Exam 6: Point Estimation
Exam 1: Overview and Descriptive Statistics15 Questions
Exam 2: Probability16 Questions
Exam 3: Discrete Random Variables and Probability Distributions22 Questions
Exam 4: Continuous Random Variables and Probability Distributions17 Questions
Exam 5: Joint Probability Distributions and Random Samples19 Questions
Exam 6: Point Estimation28 Questions
Exam 7: Statistical Intervals Based on a Single Sample59 Questions
Exam 8: Tests of Hypotheses Based on a Single Sample92 Questions
Exam 9: Inferences Based on Two Samples73 Questions
Exam 10: The Analysis of Variance43 Questions
Exam 11: Multifactor Analysis of Variance62 Questions
Exam 12: Simple Linear Regression and Correlation106 Questions
Exam 13: Nonlinear and Multiple Regression77 Questions
Exam 14: Goodness-Of-Fit Tests and Categorical Data Analysis40 Questions
Exam 15: Distribution-Free Procedures66 Questions
Exam 16: Quality Control Methods86 Questions
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Which of the following statements are true if is a random sample from a distribution with mean ?
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(Multiple Choice)
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Correct Answer:
D
The objective of __________ is to select a single number such as , based on sample data, that represents a sensible value (good guess) for the true value of the population parameter, such as .
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(Short Answer)
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Correct Answer:
point estimation
Which of the following statements are not always true?
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(Multiple Choice)
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Correct Answer:
A
Consider a random sample from the shifted exponential pdf
a. Obtain the maximum likelihood estimators of
b. A random sample of size
results in the values 3.12, .65, 2.56, 2.21, 5.45, 3.43, 10.40, 8.94, 17.83, and 1.31, calculate the estimates of
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The accompanying data describe flexural strength (Mpa) for concrete beams of a certain type was introduced in Example 1.2. 9.2 9.7 8.8 10.7 8.4 8.7 10.7 6.9 8.2 8.3 7.3 9.1 7.8 8.0 8.6 7.8 7.5 8.0 7.3 8.9 10.0 8.8 8.7 12.6 12.3 12.8 11.7
(Multiple Choice)
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Let be the maximum likelihood estimates (mle's) of the parameters . Then the mle of any function h( ) of these parameters is the function of the mle's. This result is known as the __________ principle.
(Short Answer)
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Consider a random sample from the pdf where (this distribution arises in particle physics). Show that is an unbiased estimator of [
Hint: First determine
![Consider a random sample X _ { 1 } , \ldots , X _ { n } from the pdf f ( x ; \theta ) = 5 ( 1 + \theta x ) \quad - 1 \leq x \leq 1 where - 1 \leq \theta \leq 1 (this distribution arises in particle physics). Show that \hat { \theta } = 3 \bar { X } is an unbiased estimator of \theta [ Hint: First determine \mu = E ( X ) = E ( \bar { X } ) . ]](https://storage.examlex.com/TB3498/11eb0e05_3e27_7293_9431_81e0fe6fba76_TB3498_11.jpg)
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Given four observed values: would result in a point estimate for that is equal to __________.
(Short Answer)
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Let represent a random sample from a Rayleigh distribution with pdf
a. It can be shown that
Use this fact to construct an unbiased estimator of
based on
(and use rules of expected value to show that it is unbiased).
b. Estimate
from the following
observations on vibratory stress of a turbine blade under specified conditions:
17.08 10.43 4.79 6.86 13.88
14.43 20.07 9.60 6.71 11.15
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An estimator that has the properties of __________ and __________ will often be regarded as an accurate estimator.
(Short Answer)
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A random sample of
a. Derive the maximum likelihood estimator of
. If
= 25 and
=5, what is the estimate?
b. Is the estimator of part (a) unbiased?
c. If
= 25 and
=5, what is the mle of the probability
that none of the next five helmets examined is flawed?
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A point estimator is said to be an __________ estimator of if for every possible value of .
(Short Answer)
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Among all estimators of parameter that are unbiased, choose the one that has minimum variance. The resulting is called the __________ of .
(Short Answer)
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Let be a random sample of size n from an exponential distribution with parameter . The moment estimator of = __________.
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The shear strength of each of ten test spot welds is determined, yielding the following data (psi): 395 379 404 370 392 365 412 418 361 378
a. Assuming that shear strength is normally distributed, estimate the true average shear strength and standard deviation of shear strength using the method of maximum likelihood.
b. Again assuming a normal distribution, estimate the strength value below which 95% of all welds will have their strengths. (Hint: What is the 95 percentile in terms of
? Now use the invariance principle.)
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