Exam 13: Integral Calculus

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Work the exercise. -In a certain type of specialty store, the rate of sales (in billions of dollars per year) is approximately f(x)=1.72ln(x)+16(x1)f(x)=1.72 \ln (x)+16(x \geq 1) , where x=1x=1 corresponds to the year 2001. Find the function F(x)F(x) that gives total sales between the year 2001 and year xx .

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Use the definite integral to find the area between the xx -axis and the graph of f(x)f(x) over the indicated interval. - f(x)=x2+1;[0,1]f(x)=x^{2}+1 ;[0,1]

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Use the definite integral to find the area between the xx -axis and the graph of f(x)f(x) over the indicated interval. - f(x)=2xx2;[0,2]f(x)=2 x-x^{2} ;[0,2]

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Work the exercise. -The rate of sales at a footwear outlet (in thousands of dollars per day) can be approximated by the function f(x)=8xex/7f(x)=8 x e^{-x / 7} , where xx is in days and x=0x=0 corresponds to the start of October. (a) Find the function F(x)F(x) that gives total sales since the start of October through day xx . (Hint: F(0)=0\mathrm{F}(0)=0 .) (b) Find the total sales since the start of October through x=4x=4 . Round your answer to the nearest dollar, if necessary.

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Solve the problem. -A force acts on a certain object in such a way that when the object has moved a distance of rr (in m\mathrm{m} ), the force f\mathrm{f} (in newtons) is given by f=3r2+2r\mathrm{f}=3 \mathrm{r}^{2}+2 \mathrm{r} . Find the work (in joules) done through the first four meters.

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Solve the problem. -A certain company has found that its expenditure rate per day (in hundreds of dollars) on a certain type of job is given by E(x)=6x+11\mathrm{E}^{\prime}(\mathrm{x})=6 \mathrm{x}+11 , where x\mathrm{x} is the number of days since the start of the job. Find the expenditure if the job takes 6 days.

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Find the integral. - x4(x3+12x7)dx\int x^{4}\left(x^{3}+12 x-7\right) d x

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Find the integral. - x5x6+7dx\int \frac{x^{5}}{x^{6}+7} d x

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Solve the problem. -A particle moves so that its velocity (in m/s\mathrm{m} / \mathrm{s} ) is given by v=2tet\mathrm{v}=2 \mathrm{te}^{-\mathrm{t}} , where t\mathrm{t} is the time (in seconds). Find the distance traveled between t=0\mathrm{t}=0 and t=5\mathrm{t}=5 .

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Approximate the area under the curve and above the xx -axis using nn rectangles. Let the height of each rectangle be given by the value of the function at the right side of the rectangle. - f(x)=3x22f(x)=3 x^{2}-2 from x=1x=1 to x=5;n=4x=5 ; n=4

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Find the integral. - x(1x)4dx\int \frac{x}{(1-x)^{4}} d x

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Provide the proper response. -When we define the definite integral, what is a necessary condition for the function f(x)f(x) ?

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Approximate the area under the curve and above the xx -axis using nn rectangles. Let the height of each rectangle be given by the value of the function at the right side of the rectangle. - f(x)=2x+3f(x)=2 x+3 from x=0x=0 to x=2;n=4x=2 ; n=4

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Evaluate the definite integral. - 01x(3x2+2)3dx\int_{0}^{1} \frac{x}{\left(3 x^{2}+2\right)^{3}} d x

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Find the area bounded by the given curves. - y=x3,y=x2y=x^{3}, y=x^{2}

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Solve the problem. -The current (in amperes) in an inductor of inductance L\mathrm{L} (in henries) is given by i=1 LVdt\mathrm{i}=\frac{1}{\mathrm{~L}} \int \mathrm{Vdt} , where V\mathrm{V} is the voltage (in volts) and t\mathrm{t} is the time (in seconds). Find a formula for i\mathrm{i} , if V=7t(t24)\mathrm{V}=7 \mathrm{t}\left(\mathrm{t}^{2}-4\right) .

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Solve the problem. -Find the cost function if the marginal cost function is C(x)=18x5C^{\prime}(x)=18 x-5 and the fixed cost is $3\$ 3 .

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Evaluate using integration by parts. - (2x1)ln(21x)dx\int(2 x-1) \ln (21 x) d x

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Find the integral. - te(7t2)dt\int t e^{\left(-7 t^{2}\right)} d t

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Evaluate. - (2x57x3+6)dx\int\left(2 x^{5}-7 x^{3}+6\right) d x

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