Deck 3: The Chromosome Theory of Inheritance
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Deck 3: The Chromosome Theory of Inheritance
1
If the map distance between genes A and B is 10 map units and the map distance between genes B and C is 25 map units,what is the map distance between genes A and C?
A) 15 map units
B) 35 map units
C) either 15 map units or 35 map units,depending on the order of the genes
D) The map distance between A and C can not be predicted from these data.
E) 5 map units
A) 15 map units
B) 35 map units
C) either 15 map units or 35 map units,depending on the order of the genes
D) The map distance between A and C can not be predicted from these data.
E) 5 map units
C
2
The R/r and S/s genes are linked and 10 map units apart.In the cross Rs/rS × rs/rs what fraction of the progeny will be RS/rs?
A) 5%
B) 10%
C) 25%
D) 40%
E) 45%
A) 5%
B) 10%
C) 25%
D) 40%
E) 45%
5%
3
The pairwise map distances for four linked genes are as follows: A-B = 22 m.u. ,B-C = 7 m.u. ,C-D = 9 m.u. ,B-D = 2 m.u. ,A-D = 20 m.u. ,A-C = 29 m.u.What is the order of these four genes?
A) ABCD
B) ADBC
C) ABDC
D) BADC
E) CADB
A) ABCD
B) ADBC
C) ABDC
D) BADC
E) CADB
B
4
Which of the following processes can generate recombinant gametes?
A) Segregation of alleles in a heterozygote.
B) Crossing over between two linked heterozygous loci.
C) Independent assortment of two unlinked heterozygous loci.
D) Crossing over between two linked heterozygous loci and independent assortment of two unlinked heterozygous loci.
E) Segregation of alleles in a heterozygote,crossing over between two linked heterozygous loci and independent assortment of two unlinked heterozygous loci.
A) Segregation of alleles in a heterozygote.
B) Crossing over between two linked heterozygous loci.
C) Independent assortment of two unlinked heterozygous loci.
D) Crossing over between two linked heterozygous loci and independent assortment of two unlinked heterozygous loci.
E) Segregation of alleles in a heterozygote,crossing over between two linked heterozygous loci and independent assortment of two unlinked heterozygous loci.
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5
The map of a chromosome interval is Q-10 m.u.-R-40 m.u.-S.Which interval would likely show the higher ratio of double to single chiasmata?
A) Q-R
B) R-S
C) The ratios would be the same in the two intervals.
D) Two chiasmata never occur in the same interval.
A) Q-R
B) R-S
C) The ratios would be the same in the two intervals.
D) Two chiasmata never occur in the same interval.
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6
Suppose a three-point testcross was conducted involving the genes X,Y,and Z.If the most abundant classes are XYz and xyZ and the rarest classes are xYZ and Xyz,which gene is in the middle?
A) X
B) Y
C) Z
D) cannot be determined
E) either Z or Y
A) X
B) Y
C) Z
D) cannot be determined
E) either Z or Y
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7
In an individual with genotype Lpq/lPQ the L gene is in the middle.What would be the genotypes of the gametes produced by a double crossover surrounding the L locus?
A) LPQ and lpq
B) LpQ and lPq
C) lpQ and LPq
D) Lpq and lPQ
E) cannot be determined
A) LPQ and lpq
B) LpQ and lPq
C) lpQ and LPq
D) Lpq and lPQ
E) cannot be determined
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8
In humans,the genes for red-green colour blindness (R = normal,r = colour-blind)and haemophilia A (H = normal,h = haemophilia)are both X-linked and only 3 map units apart.Suppose a woman has four sons,and two are colour-blind but have normal blood clotting and two have haemophilia but normal colour vision.What is the probable genotype of the woman?
A) HR/hr
B) Hr/hr
C) hr/hR
D) Hr/hR
E) HR/Hr
A) HR/hr
B) Hr/hr
C) hr/hR
D) Hr/hR
E) HR/Hr
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9
Crossing over takes place in paired bivalents consisting of ______ chromatids,and involves _______ of the chromatids.
A) 2;2
B) 2;4
C) 4;2
D) 4;4
E) 8;4
A) 2;2
B) 2;4
C) 4;2
D) 4;4
E) 8;4
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10
Recombination frequencies near 50 percent suggest that
A) two genes are on different chromosomes.
B) two genes lie very close together on the same chromosome.
C) two genes are on the same chromosome but lie very far apart.
D) two genes are on different chromosomes,or two genes are on the same chromosome but lie very far apart.
E) none of the choices are correct.
A) two genes are on different chromosomes.
B) two genes lie very close together on the same chromosome.
C) two genes are on the same chromosome but lie very far apart.
D) two genes are on different chromosomes,or two genes are on the same chromosome but lie very far apart.
E) none of the choices are correct.
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11
The zipper-like connection between paired homologs in early prophase is known as a
A) spindle fiber.
B) synaptic junction.
C) synaptonemal complex.
D) chiasma.
E) none of the choices are correct.
A) spindle fiber.
B) synaptic junction.
C) synaptonemal complex.
D) chiasma.
E) none of the choices are correct.
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12
The map of a chromosome interval is A-10 m.u.-B-40 m.u.-C.From the cross Abc/aBC × abc/abc,how many double crossovers would be expected out of 1000 progeny?
A) 5
B) 10
C) 20
D) 40
A) 5
B) 10
C) 20
D) 40
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13
The measured distance between genes D and E in a two-point test cross is 50 map units.What does this mean in physical terms?
A) D and E are on different pairs of chromosomes.
B) D and E are linked and exactly 50 map units apart.
C) D and E are linked and at least 50 map units apart.
D) either D and E are on different pairs of chromosomes or D and E are linked and exactly 50 map units apart.
E) either D and E are on different pairs of chromosomes or D and E are linked and at least 50 map units apart.
A) D and E are on different pairs of chromosomes.
B) D and E are linked and exactly 50 map units apart.
C) D and E are linked and at least 50 map units apart.
D) either D and E are on different pairs of chromosomes or D and E are linked and exactly 50 map units apart.
E) either D and E are on different pairs of chromosomes or D and E are linked and at least 50 map units apart.
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14
A dihybrid test cross is made between genes H and I.You wish to use the χ2 test to test the hypothesis that the H and I genes are unlinked.How many degrees of freedom would there be in this test?
A) 1
B) 2
C) 3
D) 4
E) 0
A) 1
B) 2
C) 3
D) 4
E) 0
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15
In Drosophila,singed bristles (sn)and cut wings (ct)are both caused by recessive,X-linked alleles.The wild type alleles (sn+ and ct+)are responsible for straight bristles and intact wings,respectively.A female homozygous for sn and ct+ is crossed to a sn+ct male.The F1 flies are interbred.The F2 males are distributed as follows:
What is the map distance between sn and ct?
A) 12 m.u.
B) 13 m.u.
C) 25 m.u.
D) 50 m.u.
E) 75 m.u.
What is the map distance between sn and ct?
A) 12 m.u.
B) 13 m.u.
C) 25 m.u.
D) 50 m.u.
E) 75 m.u.
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16
In Drosophila,the genes b,c,and sp are linked and in the order given,the distances being b-c = 30 m.u.and c-sp = 20 m.u.These intervals exhibit 90% interference.How many double crossovers would be recovered in a three-point cross involving b,c,and sp out of 1000 progeny?
A) 3
B) 6
C) 54
D) 60
E) 600
A) 3
B) 6
C) 54
D) 60
E) 600
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17
The T/t and S/s genes are linked and 10 map units apart.In the cross Ts/tS × ts/ts what fraction of the progeny will be Ts/ts?
A) 5%
B) 10%
C) 25%
D) 40%
E) 45%
A) 5%
B) 10%
C) 25%
D) 40%
E) 45%
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18
In Drosophila,singed bristles (sn)and carnation eyes (car)are both caused by recessive,X-linked alleles.The wild-type alleles (sn+ and car+)are responsible for straight bristles and red eyes,respectively.A sn car female is mated to a sn+ car+ male and the F1 progeny are interbred.The F2 males are distributed as follows.What is the value of ?2 for a test of the hypothesis that the sn and car genes are unlinked?
A) 0.5
B) 1.0
C) 2.0
D) 0.4
E) 20
A) 0.5
B) 1.0
C) 2.0
D) 0.4
E) 20
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19
Suppose the L and M genes are on the same chromosome but separated by 100 map units.What fraction of the progeny from the cross LM/lm × lm/lm would be Lm/lm?
A) 10%
B) 25%
C) 50%
D) 75%
E) 100%
A) 10%
B) 25%
C) 50%
D) 75%
E) 100%
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20
In Drosophila,the genes y (yellow body)and car (carnation eyes)are located at opposite ends of the X chromosome.In doubly heterozygous females (y+ car+/y car),a single chiasma is observed somewhere along the X chromosome in 90% of the examined oocytes.No X chromosomes with multiple chiasmata are observed.What percentage of the male progeny from such a female would be recombinant for y and car?
A) 5%
B) 10%
C) 45%
D) 55%
E) 90%
A) 5%
B) 10%
C) 45%
D) 55%
E) 90%
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21
Which of the following is usually true of a chi-square test performed when deciding whether two genes are linked?
A) the p-value is 2
B) degrees of freedom (df)= 2
C) the minimum sample size is 1000
D) the null hypothesis is that the loci are not linked
E) degrees of freedom (df)= 4
A) the p-value is 2
B) degrees of freedom (df)= 2
C) the minimum sample size is 1000
D) the null hypothesis is that the loci are not linked
E) degrees of freedom (df)= 4
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22
Some of the larger human chromosomes typically contain multiple chiasmata during meiotic prophase.If you were to carefully study the distribution of these chiasmata,what would you find?
A) Chiasmata are randomly distributed along chromosomes.
B) All chromosome pairs have the same number of chiasmata.
C) A single chromosome pair always has the same number of chiasmata in every meiotic cell.
D) Chiasmata are spaced along a chromosome arm more regularly than would be expected by chance.
E) Chiasmata are spaced more irregularly along a chromosome arm than would be expected by chance.
A) Chiasmata are randomly distributed along chromosomes.
B) All chromosome pairs have the same number of chiasmata.
C) A single chromosome pair always has the same number of chiasmata in every meiotic cell.
D) Chiasmata are spaced along a chromosome arm more regularly than would be expected by chance.
E) Chiasmata are spaced more irregularly along a chromosome arm than would be expected by chance.
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23
Individuals heterozygous for the RB+ and RB- alleles can develop tumours as a result of
A) a mitotic crossover that leads to homozygosity for both RB+ and RB-.
B) a somatic mutation in the RB+ allele that leads to homozygosity for RB-.
C) a somatic mutation in the RB- allele that leads to homozygosity for RB+.
D) the fact that RB- is dominant to RB+.
E) either a mitotic crossover that leads to homozygosity for both RB- or a somatic mutation in the RB+ allele that leads to homozygosity for RB-.
A) a mitotic crossover that leads to homozygosity for both RB+ and RB-.
B) a somatic mutation in the RB+ allele that leads to homozygosity for RB-.
C) a somatic mutation in the RB- allele that leads to homozygosity for RB+.
D) the fact that RB- is dominant to RB+.
E) either a mitotic crossover that leads to homozygosity for both RB- or a somatic mutation in the RB+ allele that leads to homozygosity for RB-.
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24
Suppose an individual is heterozygous for a pair of alleles (e.g. ,A/a).Under what conditions would a crossover in a somatic cell of this individual lead to a clone of cells homozygous for a? (Pick the most precise answer. )
A) The crossover would have to occur between the A locus and the centromere and involve two homologous (non-sister)chromatids.
B) The crossover would have to occur between the A locus and the end of the chromosome and involve two homologous (non-sister)chromatids.
C) The crossover would have to occur on the same chromosome arm as the A locus and involve two homologous (non-sister)chromatids.
D) The crossover would have to occur on the same chromosome as the A locus and involve two homologous (non-sister)chromatids.
E) The crossover would have to occur between the A locus and the centromere and involve two sister chromatids (not homologous)chromatids.
A) The crossover would have to occur between the A locus and the centromere and involve two homologous (non-sister)chromatids.
B) The crossover would have to occur between the A locus and the end of the chromosome and involve two homologous (non-sister)chromatids.
C) The crossover would have to occur on the same chromosome arm as the A locus and involve two homologous (non-sister)chromatids.
D) The crossover would have to occur on the same chromosome as the A locus and involve two homologous (non-sister)chromatids.
E) The crossover would have to occur between the A locus and the centromere and involve two sister chromatids (not homologous)chromatids.
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25
Abnormal chromosomes used by Stern and others to study crossovers are called
A) molecular markers
B) chiasmata
C) physical markers
D) genetic markers
E) non-disjunction
A) molecular markers
B) chiasmata
C) physical markers
D) genetic markers
E) non-disjunction
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26
By definition,a tester is always
A) syntenic
B) recessive
C) X-linked
D) linked
E) heterozygous
A) syntenic
B) recessive
C) X-linked
D) linked
E) heterozygous
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27
Suppose an individual is heterozygous for two linked pairs of alleles on the same chromosome arm,Ab/aB such that the A locus is closer to the centromere than the B locus.Under what conditions would a crossover in a somatic cell generate a twin spot,i.e. ,two adjacent clones of cells,one clone homozygous for a and the other clone homozygous for b?
A) The crossover would have to occur between the A locus and the centromere and involve two homologous (non-sister)chromatids.
B) The crossover would have to occur between the A locus and the B locus and involve two homologous (non-sister)chromatids.
C) The crossover would have to occur between the B locus and the end of the chromosome locus and involve two homologous (non-sister)chromatids.
D) A double crossover would have to occur,with one crossover between the A locus and the centromere and a second crossover between the A and B loci and both crossovers would have to involve two homologous (non-sister)chromatids.
E) No crossover in a somatic cell could generate a twin spot.
A) The crossover would have to occur between the A locus and the centromere and involve two homologous (non-sister)chromatids.
B) The crossover would have to occur between the A locus and the B locus and involve two homologous (non-sister)chromatids.
C) The crossover would have to occur between the B locus and the end of the chromosome locus and involve two homologous (non-sister)chromatids.
D) A double crossover would have to occur,with one crossover between the A locus and the centromere and a second crossover between the A and B loci and both crossovers would have to involve two homologous (non-sister)chromatids.
E) No crossover in a somatic cell could generate a twin spot.
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28
Recombination due to crossing over occurs only rarely in mitosis.
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29
Syntenic genes are
A) always recombinant
B) always unlinked
C) assort independently
D) always linked
E) located on the same chromosome
A) always recombinant
B) always unlinked
C) assort independently
D) always linked
E) located on the same chromosome
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30
Which of the following was useful in the identification of the gene that causes cystic fibrosis (CF)?
A) observation of independent assortment of PON and CF
B) sequencing of the complete human genome
C) identification of another trait that is often inherited with CF
D) comparison of karyotypes of affected and unaffected individuals
E) chorionic villus sampling
A) observation of independent assortment of PON and CF
B) sequencing of the complete human genome
C) identification of another trait that is often inherited with CF
D) comparison of karyotypes of affected and unaffected individuals
E) chorionic villus sampling
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31
Two genes are considered linked when F2 progeny more commonly show the recombinant genotype.
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32
In fruit flies,the recessive pr and cn mutations cause brown and bright-red eyes,respectively (wild-type flies have brick-red eyes).The double mutant pr cn combination has orange eyes.A female who has wild-type eyes is crossed to an orange-eyed male.Their progeny have the following distribution of eye colours:
The mother of these progeny resulted from a cross between two flies from true breeding lines.What are the genotypes of these two lines?
A) pr pr cn+ cn+ and pr+ pr+ cn cn
B) pr+ pr+ cn+ cn+ and pr pr cn cn
C) pr+ pr cn+ cn and pr pr cn cn
D) pr+ pr cn cn and pr pr cn+ cn
E) Either pr pr cn+ cn+ and pr+ pr+ cn cn or pr+ pr+ cn+ cn+ and pr pr cn cn could be true.
The mother of these progeny resulted from a cross between two flies from true breeding lines.What are the genotypes of these two lines?
A) pr pr cn+ cn+ and pr+ pr+ cn cn
B) pr+ pr+ cn+ cn+ and pr pr cn cn
C) pr+ pr cn+ cn and pr pr cn cn
D) pr+ pr cn cn and pr pr cn+ cn
E) Either pr pr cn+ cn+ and pr+ pr+ cn cn or pr+ pr+ cn+ cn+ and pr pr cn cn could be true.
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33
What happens physically during the process of crossing over?
A) Two homologous chromatids break and rejoin at random sites within each chromatid.
B) The genetic information on one chromatid is replaced by copying genetic information from a homologous chromatid without there being any physical exchange between the chromosomes.
C) Two homologous chromatids break and rejoin at precisely the same site along the chromosome so that there is no loss or gain of material on either product.
D) A segment of one chromatid is cut out and then pasted into the other chromatid.
E) It is not known what occurs during crossing over.
A) Two homologous chromatids break and rejoin at random sites within each chromatid.
B) The genetic information on one chromatid is replaced by copying genetic information from a homologous chromatid without there being any physical exchange between the chromosomes.
C) Two homologous chromatids break and rejoin at precisely the same site along the chromosome so that there is no loss or gain of material on either product.
D) A segment of one chromatid is cut out and then pasted into the other chromatid.
E) It is not known what occurs during crossing over.
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34
In fruit flies,the recessive pr and cn mutations cause brown and bright-red eyes,respectively (wild-type flies have brick-red eyes).The double mutant pr cn combination has orange eyes.A female who has wild-type eyes is crossed to an orange-eyed male.Their progeny have the following distribution of eye colours:
What is the map distance between the pr and cn genes?
A) 20 m.u.
B) 2 m.u.
C) 4 m.u.
D) 46 m.u.
E) 8 m.u.
What is the map distance between the pr and cn genes?
A) 20 m.u.
B) 2 m.u.
C) 4 m.u.
D) 46 m.u.
E) 8 m.u.
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35
Sturtevant's detailed mapping studies of the X chromosome of Drosophila established what genetic principle?
A) That genes are arranged in a linear order on the chromosomes.
B) That genes are carried on chromosomes.
C) That sex determination is controlled by the X and Y chromosomes.
D) That segregation of an allelic gene pair is accompanied by disjunction of homologous chromosomes.
E) That different pairs of chromosomes assort independently.
A) That genes are arranged in a linear order on the chromosomes.
B) That genes are carried on chromosomes.
C) That sex determination is controlled by the X and Y chromosomes.
D) That segregation of an allelic gene pair is accompanied by disjunction of homologous chromosomes.
E) That different pairs of chromosomes assort independently.
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36
Consider a pair of homologous chromosomes heterozygous for three genes (e.g.ABC/abc)during prophase I of meiosis.Let the sister chromatids of one homolog be numbered 1 and 2;and the sister chromatids of the other homolog be numbered 3 and 4.A crossover that would result in genetic recombination (e.g. ,Abc or aBC)could involve which chromatids?
A) 1 & 2 or 3 & 4
B) 1 & 3 or 2 & 4
C) 1 & 4 or 2 & 3
D) 1 & 3 or 1 & 4 or 2 & 3 or 2 & 4
E) any two of the four chromatids
A) 1 & 2 or 3 & 4
B) 1 & 3 or 2 & 4
C) 1 & 4 or 2 & 3
D) 1 & 3 or 1 & 4 or 2 & 3 or 2 & 4
E) any two of the four chromatids
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37
In fruit flies,the recessive pr and cn mutations cause brown and bright-red eyes,respectively (wild-type flies have brick-red eyes).The double mutant pr cn combination has orange eyes.A female who has wild-type eyes is crossed to an orange-eyed male.Their progeny have the following distribution of eye colours:
What is the genotype of the mother of these progeny?
A) pr cn/pr+ cn+
B) pr+ cn/pr+ cn
C) pr+ cn/pr cn+
D) pr cn+/pr cn+
E) pr cn/pr cn
What is the genotype of the mother of these progeny?
A) pr cn/pr+ cn+
B) pr+ cn/pr+ cn
C) pr+ cn/pr cn+
D) pr cn+/pr cn+
E) pr cn/pr cn
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38
Which of the following best describes a linkage map that contains a high density of genetic markers?
A) recombinant
B) saturated
C) three-point
D) random
E) sporadic
A) recombinant
B) saturated
C) three-point
D) random
E) sporadic
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39
Observation of which of the following led to the discovery of mitotic recombination?
A) twin spots
B) chromosome knobs
C) linkage mapping
D) interference
E) chiasmata
A) twin spots
B) chromosome knobs
C) linkage mapping
D) interference
E) chiasmata
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40
In fruit flies,the recessive pr and cn mutations cause brown and bright-red eyes,respectively (wild-type flies have brick-red eyes).The double mutant pr cn combination has orange eyes.A female who has wild-type eyes is crossed to an orange-eyed male.Their progeny have the following distribution of eye colours:
Which classes are the parental types?
A) wild-type and orange
B) brown and bright-red
C) wild-type and brown
D) bright-red and orange
E) There is no way to determine this.
Which classes are the parental types?
A) wild-type and orange
B) brown and bright-red
C) wild-type and brown
D) bright-red and orange
E) There is no way to determine this.
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41
C.Stern studied recombination between two homologous X chromosomes in Drosophila in which one chromosome had two cytologically visible abnormalities at opposite ends.What did he find?
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42
What is a testcross?
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43
Why does the formula for map distance between the two outside genes in a three-point testcross count the double crossovers twice whereas the formula for the distance between an outside gene and the middle gene counts the double crossovers only once?
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44
When setting up crosses to determine map distances,why do geneticists prefer to cross the hybrid individuals to individuals homozygous for the recessive alleles in the cross?
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45
Map distances between each pair of three linked genes L,M,and N are measured by two-point test crosses and determined to be: L-M = 20 cM,M-N = 25 cM,and L-N = 38 cM.Explain why the measured distance between the two farthest apart genes is not equal to the sum of the two shorter distances.
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46
In Drosophila,the genes y,f,and v are all X-linked.y f v females are crossed to wild-type males and the F1 females are test-crossed.The F2 are distributed as follows.
Calculate the coefficient of coincidence.

Calculate the coefficient of coincidence.
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47
How does Mendel's law of independent assortment relate to the concept of linkage?
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48
Chiasmata are structures of cross over between non-sister chromatids of homologous chromosomes.
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49
What are chiasmata?
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50
Genetic mapping distance calculated for a chromosome is directly related to physical distance along that chromosome.
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51
In Drosophila,the genes y,f,and v are all X-linked.y f v females are crossed to wild-type males and the F1 females are test-crossed.The F2 are distributed as follows.
Determine the linkage arrangement of these three genes and calculate the map distances.

Determine the linkage arrangement of these three genes and calculate the map distances.
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52
In Drosophila,the genes y,f,and v are all X-linked.y f v females are crossed to wild-type males and the F1 females are test-crossed.The F2 are distributed as follows.
State what a coefficient of coincidence of 0.5 would mean.

State what a coefficient of coincidence of 0.5 would mean.
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53
When mapping three genes,why do geneticists prefer to do one three-point cross rather than three two-point crosses? Give two reasons.
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54
What use is genetic mapping? Give one example where it has been of value to society.
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55
When considering the chi-square test,a p value of 0.05 is often considered significant but it is actually an arbitrary assignment of significance.
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56
Chromosomal interference is not uniform and may significantly vary within a region of a single chromosome.
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57
Females heterozygous for the recessive second chromosome mutations pn,px,and sp are mated to a male homozygous for all three mutations.The offspring are as follows:
What is the genotype of the females that gave rise to these progeny?

What is the genotype of the females that gave rise to these progeny?
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58
Three-point crosses are more tedious and less accurate than two-point crosses.
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59
Chiasmata can be seen through a light microscope and are sites of recombination.
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60
Genes chained together by linkage relationships are known collectively as a linkage group.
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61
Females heterozygous for the recessive second chromosome mutations pn,px,and sp are mated to a male homozygous for all three mutations.The offspring are as follows:
Using the two-point cross method,what are the distances between these three genes?

Using the two-point cross method,what are the distances between these three genes?
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62
Females heterozygous for the recessive second chromosome mutations pn,px,and sp are mated to a male homozygous for all three mutations.The offspring are as follows:
Using the three-point cross method,determine which gene is in the middle (which has to be flipped).

Using the three-point cross method,determine which gene is in the middle (which has to be flipped).
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63
In peas,tall (T)is dominant to short (t),red flowers (R)is dominant to white flowers (r),and wide leaves (W)is dominant to narrow leaves (w).A tall,red,wide-leaved plant is crossed to a short,white,narrow-leaved plant and the progeny are as follows:
What is the genotype of the tall,red,wide-leaved parent?

What is the genotype of the tall,red,wide-leaved parent?
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64
In peas,tall (T)is dominant to short (t),red flowers (R)is dominant to white flowers (r),and wide leaves (W)is dominant to narrow leaves (w).A tall,red,wide-leaved plant is crossed to a short,white,narrow-leaved plant and the progeny are as follows:
Give the linkage arrangements.

Give the linkage arrangements.
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65
A dihybrid test cross is made between the genes C and D with the following results.Calculate ?2 to test the hypothesis that the C and D genes are unlinked.

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66
Suppose the map for a particular human chromosome interval is: a-1-b-1-c-1-d-1-e-1-f,where the numbers indicate map distances.
In a man heterozygous for all six genes,what fraction of his sperm would be recombinant in the a-f interval?
In a man heterozygous for all six genes,what fraction of his sperm would be recombinant in the a-f interval?
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67
Suppose the map for a particular human chromosome interval is: a-1-b-1-c-1-d-1-e-1-f,where the numbers indicate map distances.
In a man of the genotype ABCDEF/abcdef,what event would give rise to a sperm with the genotype abcdeF?
In a man of the genotype ABCDEF/abcdef,what event would give rise to a sperm with the genotype abcdeF?
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68
Females heterozygous for the recessive second chromosome mutations pn,px,and sp are mated to a male homozygous for all three mutations.The offspring are as follows:
Calculate the coefficient of coincidence and comment on its meaning.

Calculate the coefficient of coincidence and comment on its meaning.
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69
Females heterozygous for the recessive second chromosome mutations pn,px,and sp are mated to a male homozygous for all three mutations.The offspring are as follows:
Which method provides more confidence as to the correct order of the genes?

Which method provides more confidence as to the correct order of the genes?
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70
A female mouse from a true-breeding wild-type strain was crossed to a male mouse with apricot eyes (ap)and grey body (gy).The F1 mice were wild-type for both traits.When the F1 were interbred,the F2 were distributed as follows (200 total):
Explain these results.

Explain these results.
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