Deck 8: Hypothesis Testing

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The following MINITAB output presents a 95% confidence interval. ) The following MINITAB output presents a 95% confidence interval. )  <div style=padding-top: 35px>
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A population has a standard deviation <strong>A population has a standard deviation   How large a sample must be drawn so that a  98%  confidence interval for     will have a margin of error equal to  4.2  ?</strong> A) 226 B) 126 C) 11 D) 5 <div style=padding-top: 35px> How large a sample must be drawn so that a 98% confidence interval for <strong>A population has a standard deviation   How large a sample must be drawn so that a  98%  confidence interval for     will have a margin of error equal to  4.2  ?</strong> A) 226 B) 126 C) 11 D) 5 <div style=padding-top: 35px> will have a margin of error equal to 4.2 ?

A) 226
B) 126
C) 11
D) 5
Question
The following MINITAB output presents a 95% confidence interval. ) The following MINITAB output presents a 95% confidence interval. )  <div style=padding-top: 35px>
Question
The three confidence intervals below were constructed from the same sample. ) The three confidence intervals below were constructed from the same sample. )  <div style=padding-top: 35px>
Question
<strong>  Assume the population standard deviation is   and that the population is approximat normal. Construct a  95 %  confidence interval for the mean price for all the TI-89's being sold over the internet.</strong> A)  (134.0,170.6) B)  (145.6,159.1) C)  (145.5,159.2) D)  (97.5,207.2) <div style=padding-top: 35px>
Assume the population standard deviation is <strong>  Assume the population standard deviation is   and that the population is approximat normal. Construct a  95 %  confidence interval for the mean price for all the TI-89's being sold over the internet.</strong> A)  (134.0,170.6) B)  (145.6,159.1) C)  (145.5,159.2) D)  (97.5,207.2) <div style=padding-top: 35px> and that the population is approximat normal. Construct a 95 % confidence interval for the mean price for all the TI-89's being sold over the internet.

A) (134.0,170.6)
B) (145.6,159.1)
C) (145.5,159.2)
D) (97.5,207.2)
Question
Find the level of the confidence interval that has the given critical value.1.53

A)93.7%
B)87.40%
C)12.6%
D)6.3%
Question
Find the critical value <strong>Find the critical value   needed to construct a(n)  80%  confidence interval.</strong> A)  0.84 B)  1.08 C)  1.28 D)  2.10 <div style=padding-top: 35px> needed to construct a(n) 80% confidence interval.

A) 0.84
B) 1.08
C) 1.28
D) 2.10
Question
A sample of 132 tobacco smokers who recently completed a new smoking-cessationprogram were asked to rate the effectiveness of the program on a scale of 1 to 10 A sample of 132 tobacco smokers who recently completed a new smoking-cessationprogram were asked to rate the effectiveness of the program on a scale of 1 to 10  <div style=padding-top: 35px>
Question
The following MINITAB output presents a 95% confidence interval. ) The following MINITAB output presents a 95% confidence interval. )  <div style=padding-top: 35px>
Question
A sample of size n=11 has a sample mean <strong>A sample of size  n=11  has a sample mean   and sample standard deviation  s=2.4 . Construct a  95 %  confidence interval for the population mean   </strong> A)  (14.0,17.2) B)  (15.1,16.1) C)  (14.3,16.9) D)  (14.6,16.6) <div style=padding-top: 35px> and sample standard deviation s=2.4 . Construct a 95 % confidence interval for the population mean <strong>A sample of size  n=11  has a sample mean   and sample standard deviation  s=2.4 . Construct a  95 %  confidence interval for the population mean   </strong> A)  (14.0,17.2) B)  (15.1,16.1) C)  (14.3,16.9) D)  (14.6,16.6) <div style=padding-top: 35px>

A) (14.0,17.2)
B) (15.1,16.1)
C) (14.3,16.9)
D) (14.6,16.6)
Question
A sample of 37 light bulbs had a mean lifetime of 584 hours. A 95 % confidence interval for the population mean was <strong>A sample of 37 light bulbs had a mean lifetime of 584 hours. A  95 %  confidence interval for the population mean was   Which one of the following statements is the correct interpretation of the results?</strong> A) None of these are true. B)  95 %  of the light bulbs in the sample had lifetimes between  579.2  hours and  588.8  hours C) The probability that the population mean is between  579.2  hours and  588.8  hours is  0.95 . D) We are  95 %  confident that the mean lifetime of all the bulbs in the population is between  579.2  hours and  588.8  hours. <div style=padding-top: 35px>
Which one of the following statements is the correct interpretation of the results?

A) None of these are true.
B) 95 % of the light bulbs in the sample had lifetimes between 579.2 hours and 588.8 hours
C) The probability that the population mean is between 579.2 hours and 588.8 hours is 0.95 .
D) We are 95 % confident that the mean lifetime of all the bulbs in the population is between 579.2 hours and 588.8 hours.
Question
   <div style=padding-top: 35px>    <div style=padding-top: 35px>
Question
Find the critical value <strong>Find the critical value   needed to construct a(n)  99.5%  confidence interval.</strong> A)  2.81 B)  2.53 C)  3.71 D)  2.58 <div style=padding-top: 35px> needed to construct a(n) 99.5% confidence interval.

A) 2.81
B) 2.53
C) 3.71
D) 2.58
Question
Find the critical value <strong>Find the critical value   needed to construct a confidence interval of the given level with the given sample size. Level  95 % , sample size 11</strong> A)  1.812 B)  1.960 C)  2.228 D)  2.201 <div style=padding-top: 35px> needed to construct a confidence interval of the given level with the given sample size.
Level 95 % , sample size 11

A) 1.812
B) 1.960
C) 2.228
D) 2.201
Question
A sample of size n=15 is drawn from an approximately normal population whose standard deviation is <strong>A sample of size  n=15  is drawn from an approximately normal population whose standard deviation is   The sample mean is   Construct a  90 %  confidence interval for   </strong> A)  (30.28,51.32) B)  (40.80,43.14) C)  (39.80,41.80) D)  38.46,43.14 <div style=padding-top: 35px> The sample mean is <strong>A sample of size  n=15  is drawn from an approximately normal population whose standard deviation is   The sample mean is   Construct a  90 %  confidence interval for   </strong> A)  (30.28,51.32) B)  (40.80,43.14) C)  (39.80,41.80) D)  38.46,43.14 <div style=padding-top: 35px> Construct a 90 % confidence interval for <strong>A sample of size  n=15  is drawn from an approximately normal population whose standard deviation is   The sample mean is   Construct a  90 %  confidence interval for   </strong> A)  (30.28,51.32) B)  (40.80,43.14) C)  (39.80,41.80) D)  38.46,43.14 <div style=padding-top: 35px>

A) (30.28,51.32)
B) (40.80,43.14)
C) (39.80,41.80)
D) 38.46,43.14
Question
A sample of size n=22 is drawn from a normal population. Find the critical value <strong>A sample of size  n=22  is drawn from a normal population. Find the critical value   needed to construct a  98 %  confidence interval.</strong> A)  2.326 B)  2.508 C)  2.189 D)  2.518 <div style=padding-top: 35px> needed to construct a 98 % confidence interval.

A) 2.326
B) 2.508
C) 2.189
D) 2.518
Question
A random sample of 9 TI-89 Titanium calculators being sold over the internet had the following A random sample of 9 TI-89 Titanium calculators being sold over the internet had the following  <div style=padding-top: 35px>
Question
The following MINITAB output presents a 95% confidence interval. ) The following MINITAB output presents a 95% confidence interval. )  <div style=padding-top: 35px>
Question
A sample of size n=50 is drawn from a population whose standard deviation is <strong>A sample of size  n=50  is drawn from a population whose standard deviation is   Find the margin of error for a  90 %  confidence interval for   </strong> A)  3.37 B)  0.80 C)  0.89 D)  2.05 <div style=padding-top: 35px> Find the margin of error for a 90 % confidence interval for <strong>A sample of size  n=50  is drawn from a population whose standard deviation is   Find the margin of error for a  90 %  confidence interval for   </strong> A)  3.37 B)  0.80 C)  0.89 D)  2.05 <div style=padding-top: 35px>

A) 3.37
B) 0.80
C) 0.89
D) 2.05
Question
A simple random sample of kitchen toasters is to be taken to determine the mean operational lifetime in hours. Assume that the lifetimes are normally distributed with population standard deviation <strong>A simple random sample of kitchen toasters is to be taken to determine the mean operational lifetime in hours. Assume that the lifetimes are normally distributed with population standard deviation   Find the sample size needed so that a  95 %  confidence interval for the mean lifetime will have a margin of error of  4 . </strong> A) 2 B) 385 C) 189 D) 14 <div style=padding-top: 35px>
Find the sample size needed so that a 95 % confidence interval for the mean lifetime will have a margin of error of 4 .

A) 2
B) 385
C) 189
D) 14
Question
The following MINITAB output presents a confidence interval for a population mean. ) The following MINITAB output presents a confidence interval for a population mean. )  <div style=padding-top: 35px>
Question
The following display from a TI-84 Plus calculator presents a 95% confidence interval. ) The following display from a TI-84 Plus calculator presents a 95% confidence interval. )  <div style=padding-top: 35px>
Question
Find the margin of error for the given confidence level and values of x and n . x=79, n=187 , confidence level 98%

A) 0.08402
B) 0.4225
C) 0.03612
D) 0.5775
Question
The following MINITAB output presents a confidence interval for a proportion. ) The following MINITAB output presents a confidence interval for a proportion. )  <div style=padding-top: 35px>
Question
A researcher wants to construct a 98% confidence interval for the proportion ofelementary school students in Seward County who receive free or reduced-price schoollunches. A state-wide survey indicates that the proportion is 0.45. Using this estimate,what sample size is needed so that the confidence interval will have a margin of error of0.08?

A)210
B)8
C)17
D)149
Question
Twenty-three concrete blocks were sampled and tested for crushing strength in order toestimate the proportion that were sufficiently strong for a certain application. Eighteen ofthe 23 blocks were sufficiently strong. Use the small-sample method to construct a 95%confidence interval for the proportion of blocks that are sufficiently strong.

A)(0.575, 0.906)
B)(0.614, 0.951)
C)(0.562, 0.920)
D)(0.602, 0.879)
Question
The following display from a TI-84 Plus calculator presents a 99% confidence interval for a The following display from a TI-84 Plus calculator presents a 99% confidence interval for a  <div style=padding-top: 35px>
Question
In a survey of 447 registered voters, 157 of them wished to see Mayor Waffleskate loseher next election. The Waffleskate campaign claims that no more than 27% of registeredvoters wish to see her defeated. Does the 98% confidence interval for the proportionsupport this claim? (Hint: you should first construct the 98% confidence interval for theproportion of registered voters who whish to see Waffleskate defeated.)(0.299, 0.404)

A)The reasonableness of the claim cannot be determined.
B)No
C)Yes
Question
Six measurements were made of the magnesium ion concentration (in parts per million,) Six measurements were made of the magnesium ion concentration (in parts per million,)  <div style=padding-top: 35px>
Question
Find the point estimate for the given values of x and n .
x=104, n=202

A) 104
B) 0.4851
C) 0.03516
D) 0.5149
Question
Find the standard error for the given values of x and n .
x=75, n=182

A) 0.03649
B) 75
C) 0.5879
D) 0.4121
Question
A researcher wants to construct a 98% confidence interval for the proportion ofelementary school students in Seward County who receive free or reduced-price schoollunches. What sample size is needed so that the confidence interval will have a margin oferror of 0.09?

A)119
B)7
C)167
D)16
Question
Boxes of raisins are labeled as containing 22 ounces. ) Boxes of raisins are labeled as containing 22 ounces. )  <div style=padding-top: 35px>
Question
Use the given data to construct a confidence interval of the requested level.
x=114, n=228 , confidence level 90%

A) (0.446,0.554)
B) (0.410,0.590)
C) (0.467,0.533)
D) (0.458,0.542)
Question
In a survey of 314 registered voters, 156 of them wished to see Mayor Waffleskate loseher next election. Construct a 95% confidence interval for the proportion of registeredvoter who want to see Mayor Waffleskate defeated.

A)0.450, 0.543)
B)(0.469, 0.525)
C)(0.441, 0.552)
D)(0.388, 0.605)
Question
The following MINITAB output presents a confidence interval for a population mean. ) The following MINITAB output presents a confidence interval for a population mean. )  <div style=padding-top: 35px>
Question
In a survey of 302 registered voters, 167 of them wished to see Mayor Waffleskate loseher next election. Find a point estimate for the proportion of registered voters who wishto see Mayor Waffleskate defeated.

A)0.02861
B)0.5530
C)0.4470
D)167
Question
Six measurements were made of the magnesium ion concentration (in parts per million,) Six measurements were made of the magnesium ion concentration (in parts per million,)  <div style=padding-top: 35px>
Question
The following display from a TI-84 Plus calculator presents a 99% confidence interval for a _ and The following display from a TI-84 Plus calculator presents a 99% confidence interval for a _ and  <div style=padding-top: 35px>
Question
The following MINITAB output presents a confidence interval for a population mean. ) The following MINITAB output presents a confidence interval for a population mean. )  <div style=padding-top: 35px>
Question
The following MINITAB output presents a confidence interval for a proportion. ) The following MINITAB output presents a confidence interval for a proportion. )  <div style=padding-top: 35px>
Question
Construct a 95% confidence interval for the population standard deviation <strong>Construct a  95%  confidence interval for the population standard deviation    if a sample of size 18 has standard deviation  s=20 .</strong> A)  (15.70,28.00) B)  (14.69,28.74) C)  (15.01,29.98) D)  (15.11,29.58) <div style=padding-top: 35px> if a sample of size 18 has standard deviation s=20 .

A) (15.70,28.00)
B) (14.69,28.74)
C) (15.01,29.98)
D) (15.11,29.58)
Question
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Question
Find the critical values for a 95% confidence interval using the chi-square distributionwith 14 degrees of freedom.

A)5.009, 24.736
B)5.892, 22.362
C)6.571, 23.685
D)5.629, 26.119
Question
Scores on the math SAT are normally distributed. A sample of 23 SAT scores had a standard deviation s=79 . Construct a 95 % confidence interval for the population standard deviation <strong>Scores on the math SAT are normally distributed. A sample of 23 SAT scores had a standard deviation  s=79 . Construct a  95 %  confidence interval for the population standard deviation  </strong> A)  (63.62,105.49) B)  (60.05,108.38) C)  (61.10,111.81) D)  (61.40,110.82) <div style=padding-top: 35px>

A) (63.62,105.49)
B) (60.05,108.38)
C) (61.10,111.81)
D) (61.40,110.82)
Question
Following are the heights in inches of 12 two-year-old apple trees. ) Following are the heights in inches of 12 two-year-old apple trees. )  <div style=padding-top: 35px>
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Deck 8: Hypothesis Testing
1
The following MINITAB output presents a 95% confidence interval. ) The following MINITAB output presents a 95% confidence interval. )
C
2
A population has a standard deviation <strong>A population has a standard deviation   How large a sample must be drawn so that a  98%  confidence interval for     will have a margin of error equal to  4.2  ?</strong> A) 226 B) 126 C) 11 D) 5 How large a sample must be drawn so that a 98% confidence interval for <strong>A population has a standard deviation   How large a sample must be drawn so that a  98%  confidence interval for     will have a margin of error equal to  4.2  ?</strong> A) 226 B) 126 C) 11 D) 5 will have a margin of error equal to 4.2 ?

A) 226
B) 126
C) 11
D) 5
126
3
The following MINITAB output presents a 95% confidence interval. ) The following MINITAB output presents a 95% confidence interval. )
A
4
The three confidence intervals below were constructed from the same sample. ) The three confidence intervals below were constructed from the same sample. )
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5
<strong>  Assume the population standard deviation is   and that the population is approximat normal. Construct a  95 %  confidence interval for the mean price for all the TI-89's being sold over the internet.</strong> A)  (134.0,170.6) B)  (145.6,159.1) C)  (145.5,159.2) D)  (97.5,207.2)
Assume the population standard deviation is <strong>  Assume the population standard deviation is   and that the population is approximat normal. Construct a  95 %  confidence interval for the mean price for all the TI-89's being sold over the internet.</strong> A)  (134.0,170.6) B)  (145.6,159.1) C)  (145.5,159.2) D)  (97.5,207.2) and that the population is approximat normal. Construct a 95 % confidence interval for the mean price for all the TI-89's being sold over the internet.

A) (134.0,170.6)
B) (145.6,159.1)
C) (145.5,159.2)
D) (97.5,207.2)
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6
Find the level of the confidence interval that has the given critical value.1.53

A)93.7%
B)87.40%
C)12.6%
D)6.3%
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7
Find the critical value <strong>Find the critical value   needed to construct a(n)  80%  confidence interval.</strong> A)  0.84 B)  1.08 C)  1.28 D)  2.10 needed to construct a(n) 80% confidence interval.

A) 0.84
B) 1.08
C) 1.28
D) 2.10
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8
A sample of 132 tobacco smokers who recently completed a new smoking-cessationprogram were asked to rate the effectiveness of the program on a scale of 1 to 10 A sample of 132 tobacco smokers who recently completed a new smoking-cessationprogram were asked to rate the effectiveness of the program on a scale of 1 to 10
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9
The following MINITAB output presents a 95% confidence interval. ) The following MINITAB output presents a 95% confidence interval. )
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10
A sample of size n=11 has a sample mean <strong>A sample of size  n=11  has a sample mean   and sample standard deviation  s=2.4 . Construct a  95 %  confidence interval for the population mean   </strong> A)  (14.0,17.2) B)  (15.1,16.1) C)  (14.3,16.9) D)  (14.6,16.6) and sample standard deviation s=2.4 . Construct a 95 % confidence interval for the population mean <strong>A sample of size  n=11  has a sample mean   and sample standard deviation  s=2.4 . Construct a  95 %  confidence interval for the population mean   </strong> A)  (14.0,17.2) B)  (15.1,16.1) C)  (14.3,16.9) D)  (14.6,16.6)

A) (14.0,17.2)
B) (15.1,16.1)
C) (14.3,16.9)
D) (14.6,16.6)
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11
A sample of 37 light bulbs had a mean lifetime of 584 hours. A 95 % confidence interval for the population mean was <strong>A sample of 37 light bulbs had a mean lifetime of 584 hours. A  95 %  confidence interval for the population mean was   Which one of the following statements is the correct interpretation of the results?</strong> A) None of these are true. B)  95 %  of the light bulbs in the sample had lifetimes between  579.2  hours and  588.8  hours C) The probability that the population mean is between  579.2  hours and  588.8  hours is  0.95 . D) We are  95 %  confident that the mean lifetime of all the bulbs in the population is between  579.2  hours and  588.8  hours.
Which one of the following statements is the correct interpretation of the results?

A) None of these are true.
B) 95 % of the light bulbs in the sample had lifetimes between 579.2 hours and 588.8 hours
C) The probability that the population mean is between 579.2 hours and 588.8 hours is 0.95 .
D) We are 95 % confident that the mean lifetime of all the bulbs in the population is between 579.2 hours and 588.8 hours.
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12
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13
Find the critical value <strong>Find the critical value   needed to construct a(n)  99.5%  confidence interval.</strong> A)  2.81 B)  2.53 C)  3.71 D)  2.58 needed to construct a(n) 99.5% confidence interval.

A) 2.81
B) 2.53
C) 3.71
D) 2.58
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14
Find the critical value <strong>Find the critical value   needed to construct a confidence interval of the given level with the given sample size. Level  95 % , sample size 11</strong> A)  1.812 B)  1.960 C)  2.228 D)  2.201 needed to construct a confidence interval of the given level with the given sample size.
Level 95 % , sample size 11

A) 1.812
B) 1.960
C) 2.228
D) 2.201
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15
A sample of size n=15 is drawn from an approximately normal population whose standard deviation is <strong>A sample of size  n=15  is drawn from an approximately normal population whose standard deviation is   The sample mean is   Construct a  90 %  confidence interval for   </strong> A)  (30.28,51.32) B)  (40.80,43.14) C)  (39.80,41.80) D)  38.46,43.14 The sample mean is <strong>A sample of size  n=15  is drawn from an approximately normal population whose standard deviation is   The sample mean is   Construct a  90 %  confidence interval for   </strong> A)  (30.28,51.32) B)  (40.80,43.14) C)  (39.80,41.80) D)  38.46,43.14 Construct a 90 % confidence interval for <strong>A sample of size  n=15  is drawn from an approximately normal population whose standard deviation is   The sample mean is   Construct a  90 %  confidence interval for   </strong> A)  (30.28,51.32) B)  (40.80,43.14) C)  (39.80,41.80) D)  38.46,43.14

A) (30.28,51.32)
B) (40.80,43.14)
C) (39.80,41.80)
D) 38.46,43.14
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16
A sample of size n=22 is drawn from a normal population. Find the critical value <strong>A sample of size  n=22  is drawn from a normal population. Find the critical value   needed to construct a  98 %  confidence interval.</strong> A)  2.326 B)  2.508 C)  2.189 D)  2.518 needed to construct a 98 % confidence interval.

A) 2.326
B) 2.508
C) 2.189
D) 2.518
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17
A random sample of 9 TI-89 Titanium calculators being sold over the internet had the following A random sample of 9 TI-89 Titanium calculators being sold over the internet had the following
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18
The following MINITAB output presents a 95% confidence interval. ) The following MINITAB output presents a 95% confidence interval. )
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19
A sample of size n=50 is drawn from a population whose standard deviation is <strong>A sample of size  n=50  is drawn from a population whose standard deviation is   Find the margin of error for a  90 %  confidence interval for   </strong> A)  3.37 B)  0.80 C)  0.89 D)  2.05 Find the margin of error for a 90 % confidence interval for <strong>A sample of size  n=50  is drawn from a population whose standard deviation is   Find the margin of error for a  90 %  confidence interval for   </strong> A)  3.37 B)  0.80 C)  0.89 D)  2.05

A) 3.37
B) 0.80
C) 0.89
D) 2.05
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20
A simple random sample of kitchen toasters is to be taken to determine the mean operational lifetime in hours. Assume that the lifetimes are normally distributed with population standard deviation <strong>A simple random sample of kitchen toasters is to be taken to determine the mean operational lifetime in hours. Assume that the lifetimes are normally distributed with population standard deviation   Find the sample size needed so that a  95 %  confidence interval for the mean lifetime will have a margin of error of  4 . </strong> A) 2 B) 385 C) 189 D) 14
Find the sample size needed so that a 95 % confidence interval for the mean lifetime will have a margin of error of 4 .

A) 2
B) 385
C) 189
D) 14
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21
The following MINITAB output presents a confidence interval for a population mean. ) The following MINITAB output presents a confidence interval for a population mean. )
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22
The following display from a TI-84 Plus calculator presents a 95% confidence interval. ) The following display from a TI-84 Plus calculator presents a 95% confidence interval. )
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23
Find the margin of error for the given confidence level and values of x and n . x=79, n=187 , confidence level 98%

A) 0.08402
B) 0.4225
C) 0.03612
D) 0.5775
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24
The following MINITAB output presents a confidence interval for a proportion. ) The following MINITAB output presents a confidence interval for a proportion. )
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25
A researcher wants to construct a 98% confidence interval for the proportion ofelementary school students in Seward County who receive free or reduced-price schoollunches. A state-wide survey indicates that the proportion is 0.45. Using this estimate,what sample size is needed so that the confidence interval will have a margin of error of0.08?

A)210
B)8
C)17
D)149
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26
Twenty-three concrete blocks were sampled and tested for crushing strength in order toestimate the proportion that were sufficiently strong for a certain application. Eighteen ofthe 23 blocks were sufficiently strong. Use the small-sample method to construct a 95%confidence interval for the proportion of blocks that are sufficiently strong.

A)(0.575, 0.906)
B)(0.614, 0.951)
C)(0.562, 0.920)
D)(0.602, 0.879)
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27
The following display from a TI-84 Plus calculator presents a 99% confidence interval for a The following display from a TI-84 Plus calculator presents a 99% confidence interval for a
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28
In a survey of 447 registered voters, 157 of them wished to see Mayor Waffleskate loseher next election. The Waffleskate campaign claims that no more than 27% of registeredvoters wish to see her defeated. Does the 98% confidence interval for the proportionsupport this claim? (Hint: you should first construct the 98% confidence interval for theproportion of registered voters who whish to see Waffleskate defeated.)(0.299, 0.404)

A)The reasonableness of the claim cannot be determined.
B)No
C)Yes
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29
Six measurements were made of the magnesium ion concentration (in parts per million,) Six measurements were made of the magnesium ion concentration (in parts per million,)
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30
Find the point estimate for the given values of x and n .
x=104, n=202

A) 104
B) 0.4851
C) 0.03516
D) 0.5149
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31
Find the standard error for the given values of x and n .
x=75, n=182

A) 0.03649
B) 75
C) 0.5879
D) 0.4121
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32
A researcher wants to construct a 98% confidence interval for the proportion ofelementary school students in Seward County who receive free or reduced-price schoollunches. What sample size is needed so that the confidence interval will have a margin oferror of 0.09?

A)119
B)7
C)167
D)16
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33
Boxes of raisins are labeled as containing 22 ounces. ) Boxes of raisins are labeled as containing 22 ounces. )
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34
Use the given data to construct a confidence interval of the requested level.
x=114, n=228 , confidence level 90%

A) (0.446,0.554)
B) (0.410,0.590)
C) (0.467,0.533)
D) (0.458,0.542)
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35
In a survey of 314 registered voters, 156 of them wished to see Mayor Waffleskate loseher next election. Construct a 95% confidence interval for the proportion of registeredvoter who want to see Mayor Waffleskate defeated.

A)0.450, 0.543)
B)(0.469, 0.525)
C)(0.441, 0.552)
D)(0.388, 0.605)
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36
The following MINITAB output presents a confidence interval for a population mean. ) The following MINITAB output presents a confidence interval for a population mean. )
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37
In a survey of 302 registered voters, 167 of them wished to see Mayor Waffleskate loseher next election. Find a point estimate for the proportion of registered voters who wishto see Mayor Waffleskate defeated.

A)0.02861
B)0.5530
C)0.4470
D)167
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38
Six measurements were made of the magnesium ion concentration (in parts per million,) Six measurements were made of the magnesium ion concentration (in parts per million,)
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39
The following display from a TI-84 Plus calculator presents a 99% confidence interval for a _ and The following display from a TI-84 Plus calculator presents a 99% confidence interval for a _ and
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40
The following MINITAB output presents a confidence interval for a population mean. ) The following MINITAB output presents a confidence interval for a population mean. )
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41
The following MINITAB output presents a confidence interval for a proportion. ) The following MINITAB output presents a confidence interval for a proportion. )
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42
Construct a 95% confidence interval for the population standard deviation <strong>Construct a  95%  confidence interval for the population standard deviation    if a sample of size 18 has standard deviation  s=20 .</strong> A)  (15.70,28.00) B)  (14.69,28.74) C)  (15.01,29.98) D)  (15.11,29.58) if a sample of size 18 has standard deviation s=20 .

A) (15.70,28.00)
B) (14.69,28.74)
C) (15.01,29.98)
D) (15.11,29.58)
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43
There are no testbank questions for this section.
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44
Find the critical values for a 95% confidence interval using the chi-square distributionwith 14 degrees of freedom.

A)5.009, 24.736
B)5.892, 22.362
C)6.571, 23.685
D)5.629, 26.119
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45
Scores on the math SAT are normally distributed. A sample of 23 SAT scores had a standard deviation s=79 . Construct a 95 % confidence interval for the population standard deviation <strong>Scores on the math SAT are normally distributed. A sample of 23 SAT scores had a standard deviation  s=79 . Construct a  95 %  confidence interval for the population standard deviation  </strong> A)  (63.62,105.49) B)  (60.05,108.38) C)  (61.10,111.81) D)  (61.40,110.82)

A) (63.62,105.49)
B) (60.05,108.38)
C) (61.10,111.81)
D) (61.40,110.82)
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46
Following are the heights in inches of 12 two-year-old apple trees. ) Following are the heights in inches of 12 two-year-old apple trees. )
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