Deck 7: The Normal Probability Distribution
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Deck 7: The Normal Probability Distribution
1
Suppose a uniform random variable can be used to describe the outcome of an experiment with the outcomesranging from 30 to 70. What is the probability that this experiment results in an outcome less than 40?
A) 0.25
B) 0.1
C) 0.31
D) 1
A) 0.25
B) 0.1
C) 0.31
D) 1
A
2

A) The graph cannot represent a normal density function because it increases as x becomes very large or very small.
B) The graph cannot represent a normal density function because it takes negative values for some values of x.
C) The graph cannot represent a normal density function because the area under the graph is greater than 1.
D) The graph can represent a normal density function.
A
3
The normal density curve is symmetric about
A) Its mean
B) The horizontal axis
C) An inflection point
D) A point located one standard deviation from the mean
A) Its mean
B) The horizontal axis
C) An inflection point
D) A point located one standard deviation from the mean
A
4
The highest point on the graph of the normal density curve is located at
A) its mean
B) an inflection point
A) its mean
B) an inflection point

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5
Suppose x is a uniform random variable with c = 30 and d = 80. Find the probability that a randomly selectedobservation is between 33 and 75.
A) 0.84
B) 0.16
C) 0.5
D) 0.8
A) 0.84
B) 0.16
C) 0.5
D) 0.8
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6
High temperatures in a certain city for the month of August follow a uniform distribution over the interval 73°Fto 103°F. Find the high temperature which 90% of the August days exceed.
A) 76°F
B) 100°F
C) 83°F
D) 103°F
A) 76°F
B) 100°F
C) 83°F
D) 103°F
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7
Suppose x is a uniform random variable with c = 10 and d = 60. Find the probability that a randomly selectedobservation exceeds 30.
A) 0.6
B) 0.4
C) 0.1
D) 0.9
A) 0.6
B) 0.4
C) 0.1
D) 0.9
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8
The diameter of ball bearings produced in a manufacturing process can be explained using a uniformdistribution over the interval 7.5 to 9.5 millimeters. What is the probability that a randomly selected ballbearing has a diameter greater than 8.6 millimeters?
A) 0.45
B) 0.9053
C) 4
D) 0.5059
A) 0.45
B) 0.9053
C) 4
D) 0.5059
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9
True or False: In a uniform probability distribution, any random variable is just as likely as any other randomvariable to occur, provided the random variables belong to the distribution.
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10
You are performing a study about the weight of preschoolers. A previous study found the weights to benormally distributed with a mean of 30 and a standard deviation of 4. You randomly sample 30 preschoolchildren and find their weights to be as follows.
a) Draw a histogram to display the data. Is it reasonable to assume that the weights are normallydistributed? Why?b) Find the mean and standard deviation of your sample.c) Is there a high probability that the mean and standard deviation of your sample are consistentwith those found in previous studies? Explain your reasoning.

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11
Compare a graph of the normal density function with mean of 0 and standard deviation of 1 with a graph of anormal density function with mean equal to 4 and standard deviation of 1. The graphs would
A) Have the same height but one would be shifted 4 units to the right.
B) Have the same height but one would be shifter 4 units to the left.
C) Have no horizontal displacement but one would be steeper that the other.
D) Have no horizontal displacement but one would be flatter than the other.
A) Have the same height but one would be shifted 4 units to the right.
B) Have the same height but one would be shifter 4 units to the left.
C) Have no horizontal displacement but one would be steeper that the other.
D) Have no horizontal displacement but one would be flatter than the other.
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12
A machine is set to pump cleanser into a process at the rate of 5 gallons per minute. Upon inspection, it islearned that the machine actually pumps cleanser at a rate described by the uniform distribution over theinterval 4.5 to 7.5 gallons per minute. Find the probability that between 5.0 gallons and 6.0 gallons are pumpedduring a randomly selected minute.
A) 0.33
B) 0.67
C) 0
D) 1
A) 0.33
B) 0.67
C) 0
D) 1
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13
A random number generator is set top generate integer random numbers between 1 and 10 inclusive followinga uniform distribution. What is the probability of the random number generator generating a 7?
A) 0.7
B) 0
C) 0.07
D) 0.5
A) 0.7
B) 0
C) 0.07
D) 0.5
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14
The graph of a normal curve is given. Use the graph to identify the value of μand σ. 

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15

A) The graph cannot represent a normal density function because the graph takes negative values for some values of x.
B) The graph cannot represent a normal density function because the area under the graph is less than 1.
C) The graph cannot represent a normal density function because it is not symmetric.
D) The graph can represent a normal density function.
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16
High temperatures in a certain city for the month of August follow a uniform distribution over the interval 64°Fto 92°F. What is the probability that a randomly selected August day has a high temperature that exceeded69°F?
A) 0.8214
B) 0.1786
C) 0.4423
D) 0.0357
A) 0.8214
B) 0.1786
C) 0.4423
D) 0.0357
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17
Draw a normal curve with μ = 50 and σ = 16. Label the mean and the inflection points.
A)

B)

C)

D)
A)

B)

C)

D)

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18

A) The graph can represent a normal density function.
B) The graph cannot represent a normal density function because it has no inflection points.
C) The graph cannot represent a normal density function because as x increases without bound, the graph takes negative values.
D) The graph cannot represent a normal density function because the area under the graph is greater than 1.
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19
Approximately ____% of the area under the normal curve is between μ - 3σ and μ + 3σ.
A) 99.7
B) 68
C) 95
D) 50
A) 99.7
B) 68
C) 95
D) 50
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20
Compare a graph of the normal density function with mean of 0 and standard deviation of 1 with a graph of anormal density function with mean equal to 0 and standard deviation of 0.5. The graphs would
A) Have no horizontal displacement but one would be steeper that the other.
B) Have no horizontal displacement but one would be flatter than the other.
C) Have the same height but one would be shifted 4 units to the right.
D) Have the same height but one would be shifter 4 units to the left.
A) Have no horizontal displacement but one would be steeper that the other.
B) Have no horizontal displacement but one would be flatter than the other.
C) Have the same height but one would be shifted 4 units to the right.
D) Have the same height but one would be shifter 4 units to the left.
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21

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22
Find the area under the standard normal curve between z = 1 and z = 2.
A) 0.1359
B) 0.8413
C) 0.5398
D) 0.2139
A) 0.1359
B) 0.8413
C) 0.5398
D) 0.2139
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23
Find the area under the standard normal curve to the right of z = 1.
A) 0.1587
B) 0.8413
C) 0.1397
D) 0.5398
A) 0.1587
B) 0.8413
C) 0.1397
D) 0.5398
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24

A) The graph cannot represent a normal density function because it is not symmetric.
B) The graph cannot represent a normal density function because as x increases without bound, the graph takes negative values.
C) The graph cannot represent a normal density function because it is bimodal.
D) The graph can represent a normal density function.
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25
Find the area under the standard normal curve between z = -1.25 and z = 1.25.
A) 0.7888
B) 0.8817
C) 0.6412
D) 0.2112
A) 0.7888
B) 0.8817
C) 0.6412
D) 0.2112
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26
Find the area under the standard normal curve between z = 1.5 and z = 2.5.
A) 0.0606
B) 0.9938
C) 0.9332
D) 0.9816
A) 0.0606
B) 0.9938
C) 0.9332
D) 0.9816
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27
z = 1 and z = 2
A) 0.1359
B) 0.8641
C) 0.0006
D) 0.0008
A) 0.1359
B) 0.8641
C) 0.0006
D) 0.0008
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28
Find the area under the standard normal curve to the left of z = 1.5.
A) 0.9332
B) 0.0668
C) 0.5199
D) 0.7612
A) 0.9332
B) 0.0668
C) 0.5199
D) 0.7612
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29
True or False: The area under the normal curve drawn with regard to the population parameters is the same asthe proportion of the population that has these characteristics.
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30
Find the area under the standard normal curve between z = -1.5 and z = 2.5.
A) 0.9270
B) 0.7182
C) 0.6312
D) 0.9831
A) 0.9270
B) 0.7182
C) 0.6312
D) 0.9831
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31
The weight of 2-year old hyraxes is known to be normally distributed with meanμ = 2200 grams and standard deviation σ = 365 grams(a) Draw a normal curve with the parameters labeled.(b) Shade the region that represents the proportion of hyraxes who weighed more than 2930 grams.(c) Suppose the area under the normal curve to the left of X = 2930 is 0.0228. Provide two interpretations of thisresult.
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32
Find the area under the standard normal curve to the left of z = 1.25.
A) 0.8944
B) 0.1056
C) 0.2318
D) 0.7682
A) 0.8944
B) 0.1056
C) 0.2318
D) 0.7682
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33
Find the area under the standard normal curve between z = 0 and z = 3.
A) 0.4987
B) 0.9987
C) 0.0010
D) 0.4641
A) 0.4987
B) 0.9987
C) 0.0010
D) 0.4641
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34
Find the area under the standard normal curve to the right of z = -1.25.
A) 0.8944
B) 0.5843
C) 0.6978
D) 0.7193
A) 0.8944
B) 0.5843
C) 0.6978
D) 0.7193
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35
True or False: The area under the normal curve drawn with regard to the population parameters is the same asthe probability that a randomly selected individual of a population has these characteristics.
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36

A) The graph cannot represent a normal density function because it does not approach the horizontal axis as x increases or decreases without bound.
B) The graph cannot represent a normal density function because it is not bell shaped.
C) The graph can represent a normal density function.
D) The graph cannot represent a normal density function because it has no inflection points.
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37
Find the sum of the areas under the standard normal curve to the left of z = -1.25 and to the right of z = 1.25.
A) 0.2112
B) 0.7888
C) 0.1056
D) 0.3944
A) 0.2112
B) 0.7888
C) 0.1056
D) 0.3944
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38
True or False: The proportion of the population that has certain characteristics is the same as the probabilitythat a randomly selected individual of the population has these same characteristics.
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39

A) The graph can represent a normal density function.
B) The graph cannot represent a normal density function because it has no inflection points.
C) The graph cannot represent a normal density function because its maximum value is too small.
D) The graph cannot represent a normal density function because the area under the graph is less than 1.
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40
The analytic scores on a standardized aptitude test are known to be normally distributed with mean μ= 610and standard deviation σ = 115.(a) Draw a normal curve with the parameters labeled.(b) Shade the region that represents the proportion of test takers who scored less than 725.(c) Suppose the area under the normal curve to the left of X = 725 is 0.8413. Provide two interpretations of thisresult.
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41
A physical fitness association is including the mile run in its secondary-school fitness test. The time for thisevent for boys in secondary school is known to possess a normal distribution with a mean of 440 seconds and astandard deviation of 60 seconds. Find the probability that a randomly selected boy in secondary school willtake longer than 302 seconds to run the mile.
A) 0.9893
B) 0.4893
C) 0.0107
D) 0.5107
A) 0.9893
B) 0.4893
C) 0.0107
D) 0.5107
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42
The tread life of a particular brand of tire is a random variable best described by a normal distribution with amean of 60,000 miles and a standard deviation of 2900 miles. What is the probability a certain tire of this brandwill last between 53,910 miles and 54,780 miles?
A) 0.0180
B) 0.9813
C) 0.4920
D) 0.4649
A) 0.0180
B) 0.9813
C) 0.4920
D) 0.4649
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43
z = -2 and z = -0.1
A) 0.4374
B) 0.4602
C) 0.5398
D) 0.0228
A) 0.4374
B) 0.4602
C) 0.5398
D) 0.0228
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44
Assume that the random variable X is normally distributed, with mean μ = 50 and standard deviation σ = 16.Compute the probability P(6 < X < 70).
A) 0.8914
B) 0.8819
C) 0.8944
D) 0.7888
A) 0.8914
B) 0.8819
C) 0.8944
D) 0.7888
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45
The tread life of a particular brand of tire is a random variable best described by a normal distribution with amean of 60,000 miles and a standard deviation of 2900 miles. What is the probability a particular tire of thisbrand will last longer than 57,100 miles?
A) 0.8413
B) 0.1587
C) 0.2266
D) 0.7266
A) 0.8413
B) 0.1587
C) 0.2266
D) 0.7266
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46
The length of time it takes college students to find a parking spot in the library parking lot follows a normaldistribution with a mean of 3.0 minutes and a standard deviation of 1 minute. Find the probability that arandomly selected college student will find a parking spot in the library parking lot in less than 2.5 minutes.
A) 0.3085
B) 0.1915
C) 0.3551
D) 0.2674
A) 0.3085
B) 0.1915
C) 0.3551
D) 0.2674
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47
The length of time it takes college students to find a parking spot in the library parking lot follows a normaldistribution with a mean of 6.5 minutes and a standard deviation of 1 minute. Find the probability that arandomly selected college student will take between 5.0 and 7.5 minutes to find a parking spot in the librarylot.
A) 0.7745
B) 0.4938
C) 0.0919
D) 0.2255
A) 0.7745
B) 0.4938
C) 0.0919
D) 0.2255
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48
z = 0.3 and z = 1.4
A) 0.3013
B) 0.6179
C) 0.9192
D) 0.3821
A) 0.3013
B) 0.6179
C) 0.9192
D) 0.3821
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49
Assume that the random variable X is normally distributed, with mean μ = 100 and standard deviation σ = 15.Compute the probability P(X > 112).
A) 0.2119
B) 0.1977
C) 0.7881
D) 0.2420
A) 0.2119
B) 0.1977
C) 0.7881
D) 0.2420
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50
A firm believes the internal rate of return for its proposed investment can best be described by a normaldistribution with mean 36% and standard deviation 3%. What is the probability that the internal rate of returnfor the investment exceeds 42%?
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51
z = -0.7 and z = 0.7
A) 0.516
B) 0.242
C) 0.758
D) 0.5
A) 0.516
B) 0.242
C) 0.758
D) 0.5
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52
A new phone system was installed last year to help reduce the expense of personal calls that were being madeby employees. Before the new system was installed, the amount being spent on personal calls follows a normaldistribution with an average of $900 per month and a standard deviation of $50 per month. Refer to suchexpenses as PCEʹs (personal call expenses). Find the probability that a randomly selected month had a PCE thatfalls below $750.
A) 0.0013
B) 0.8333
C) 0.1667
D) 0.9987
A) 0.0013
B) 0.8333
C) 0.1667
D) 0.9987
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53
A firm believes the internal rate of return for its proposed investment can best be described by a normaldistribution with mean 26% and standard deviation 3%. What is the probability that the internal rate of returnfor the investment will be at least 21.5%?
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54
A physical fitness association is including the mile run in its secondary-school fitness test. The time for thisevent for boys in secondary school is known to possess a normal distribution with a mean of 450 seconds and astandard deviation of 50 seconds. Find the probability that a randomly selected boy in secondary school canrun the mile in less than 335 seconds.
A) 0.0107
B) 0.4893
C) 0.9893
D) 0.5107
A) 0.0107
B) 0.4893
C) 0.9893
D) 0.5107
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55
Suppose a brewery has a filling machine that fills 12 ounce bottles of beer. It is known that the amount of beerpoured by this filling machine follows a normal distribution with a mean of 13.14 onces and a standarddeviation of 0.04 ounce. Find the probability that the bottle contains more than 13.14 ounces of beer.
A) 0.5
B) 1
C) 0
D) 0.4
A) 0.5
B) 1
C) 0
D) 0.4
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56
Suppose a brewery has a filling machine that fills 12 ounce bottles of beer. It is known that the amount of beerpoured by this filling machine follows a normal distribution with a mean of 12.13 ounces and a standarddeviation of 0.04 ounce. Find the probability that the bottle contains fewer than 12.03 ounces of beer.
A) 0.0062
B) 0.4938
C) 0.9938
D) 0.5062
A) 0.0062
B) 0.4938
C) 0.9938
D) 0.5062
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57
A new phone system was installed last year to help reduce the expense of personal calls that were being madeby employees. Before the new system was installed, the amount being spent on personal calls followed anormal distribution with an average of $500 per month and a standard deviation of $50 per month. Refer tosuch expenses as PCEʹs (personal call expenses). Using the distribution above, what is the probability that arandomly selected month had a PCE of between $375.00 and $590.00?
A) 0.9579
B) 0.0421
C) 0.9999
D) 0.0001
A) 0.9579
B) 0.0421
C) 0.9999
D) 0.0001
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58
Suppose a brewery has a filling machine that fills 12 ounce bottles of beer. It is known that the amount of beerpoured by this filling machine follows a normal distribution with a mean of 12.29 ounces and a standarddeviation of 0.04 ounce. Find the probability that the bottle contains between 12.19 and 12.25 ounces.
A) 0.1525
B) 0.8351
C) 0.1649
D) 0.8475
A) 0.1525
B) 0.8351
C) 0.1649
D) 0.8475
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59
The amount of soda a dispensing machine pours into a 12 ounce can of soda follows a normal distribution witha mean of 12.48 ounces and a standard deviation of 0.32 ounce. The cans only hold 12.80 ounces of soda. Everycan that has more than 12.80 ounces of soda poured into it causes a spill and the can needs to go through aspecial cleaning process before it can be sold. What is the probability a randomly selected can will need to gothrough this process?
A) 0.1587
B) 0.3413
C) 0.8413
D) 0.6587
A) 0.1587
B) 0.3413
C) 0.8413
D) 0.6587
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60
Assume that the random variable X is normally distributed, with mean μ = 60 and standard deviation σ = 16.Compute the probability P(X < 80).
A) 0.8944
B) 0.8849
C) 0.1056
D) 0.9015
A) 0.8944
B) 0.8849
C) 0.1056
D) 0.9015
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61
Find the z-score for which the area under the standard normal curve to its right is 0.70.
A) -0.53
B) -0.98
C) -0.81
D) -0.47
A) -0.53
B) -0.98
C) -0.81
D) -0.47
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62
Given a distribution that follows a standard normal curve, what does the graph of the curve do as z increasesin the positive direction?
A) The graph of the curve approaches zero.
B) The graph of the curve approaches 1.
C) The graph of the curve approaches an inflection point.
D) The graph of the curve eventually intersects the horizontal axis.
A) The graph of the curve approaches zero.
B) The graph of the curve approaches 1.
C) The graph of the curve approaches an inflection point.
D) The graph of the curve eventually intersects the horizontal axis.
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63
Find the z-score for which the area under the standard normal curve to its left is 0.96
A) 1.75
B) 1.82
C) 1.03
D) -1.38
A) 1.75
B) 1.82
C) 1.03
D) -1.38
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64
Find the z-scores for which 98% of the distributionʹs area lies between -z and z.
A) (-2.33, 2.33)
B) (-1.645, 1.645)
C) (-1.96, 1.96)
D) (-0.99, 0.99)
A) (-2.33, 2.33)
B) (-1.645, 1.645)
C) (-1.96, 1.96)
D) (-0.99, 0.99)
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65
Determine the two z-scores that separate the middle 87.4% of the distribution from the area in the tails of thestandard normal distribution.
A) -1.53, 1.53
B) -1.39, 1.39
C) -1.46, 1.46
D) -1.45, 1.45
A) -1.53, 1.53
B) -1.39, 1.39
C) -1.46, 1.46
D) -1.45, 1.45
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66
Farmers often sell fruits and vegetables at roadside stands during the summer. One such roadside stand has adaily demand for tomatoes that is approximately normally distributed with a mean equal to 413 tomatoes perday and a standard deviation equal to 30 tomatoes per day. If there are 371 tomatoes available to be sold at theroadside stand at the beginning of a day, what is the probability that they will all be sold?
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67
For a standard normal curve, find the z-score that separates the bottom 30% from the top 70%.
A) -0.53
B) -0.98
C) -0.47
D) -0.12
A) -0.53
B) -0.98
C) -0.47
D) -0.12
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68
Find the z-score for which the area under the standard normal curve to its left is 0.40
A) -0.25
B) 0.25
C) 0.57
D) -0.57
A) -0.25
B) 0.25
C) 0.57
D) -0.57
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69
Find the z-score for which the area under the standard normal curve to its right is 0.07.
A) 1.48
B) 1.39
C) 1.26
D) 1.45
A) 1.48
B) 1.39
C) 1.26
D) 1.45
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70
Assume that the random variable X is normally distributed with mean
and standard deviation
Find the 24th percentile for X.
A) 41.48
B) 58.52
C) 42.92
D) 38.6


A) 41.48
B) 58.52
C) 42.92
D) 38.6
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71
Determine the two z-scores that separate the middle 96% of the distribution from the area in the tails of thestandard normal distribution.
A) -2.05 and 2.05
B) -1.75 and 1.75
C) 0 and 2.05
D) -2.33 and 2.33
A) -2.05 and 2.05
B) -1.75 and 1.75
C) 0 and 2.05
D) -2.33 and 2.33
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72
z0.05
A) 1.645
B) -1.645
C) 0.52
D) 1.75
A) 1.645
B) -1.645
C) 0.52
D) 1.75
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73
Find the z-score for which the area under the standard normal curve to its right is 0.09.
A) 1.34
B) 1.39
C) 1.26
D) 1.45
A) 1.34
B) 1.39
C) 1.26
D) 1.45
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74
Find the z-score having area 0.86 to its right under the standard normal curve; that is, find z 0.86 .
A) -1.08
B) 1.08
C) 0.8051
D) 0.5557
A) -1.08
B) 1.08
C) 0.8051
D) 0.5557
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75
For a standard normal curve, find the z-score that separates the bottom 90% from the top 10%.
A) 1.28
B) 0.28
C) 1.52
D) 2.81
A) 1.28
B) 0.28
C) 1.52
D) 2.81
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76
Find the z-score for which the area under the standard normal curve to its left is 0.04.
A) -1.75
B) -1.89
C) -1.48
D) -1.63
A) -1.75
B) -1.89
C) -1.48
D) -1.63
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77
Find the z-score for which the area under the standard normal curve to its left is 0.09.
A) -1.34
B) -1.39
C) -1.26
D) -1.45
A) -1.34
B) -1.39
C) -1.26
D) -1.45
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78
For a standard normal curve, find the z-score that separates the bottom 70% from the top 30%.
A) 0.53
B) 0.98
C) 0.47
D) 0.12
A) 0.53
B) 0.98
C) 0.47
D) 0.12
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79
Find the z-score for which the area under the standard normal curve to its left is 0.70.
A) 0.53
B) 0.98
C) 0.81
D) 0.47
A) 0.53
B) 0.98
C) 0.81
D) 0.47
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80
Find the z-scores for which 90% of the distributionʹs area lies between -z and z.
A) (-1.645, 1.645)
B) (-2.33, 2.33)
C) (-1.96, 1.96)
D) (-0.99, 0.99)
A) (-1.645, 1.645)
B) (-2.33, 2.33)
C) (-1.96, 1.96)
D) (-0.99, 0.99)
Unlock Deck
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