Deck 4: Dynamics: Newtons Laws of Motion

Full screen (f)
exit full mode
Question
Explain how to draw free-body diagrams.
Use Space or
up arrow
down arrow
to flip the card.
Question
According to Newton's Third Law, "action" and "reaction" forces must always act on the same object.
Question
A force exerted by an object does not influence that same object; it only influences the other object on which it is exerted.
Question
A force is required for an object to accelerate.
Question
State Newton's second law of motion.
Question
State Newton's first law of motion.
Question
A force is required to keep an object moving along a horizontal line.
Question
If no force is applied to a moving object, it will continue to move with constant speed in a straight line.
Question
Newton's First law holds in all reference frames, including inertial reference frames.
Question
The acceleration of an object does not have to be in the same direction as the net force applied to it.
Question
The acceleration of an object depends only on the net applied force.
Question
The acceleration of an object depends only on the object's mass.
Question
The normal force is always equal to the force of gravity.
Question
The force of gravity acts on an object only when it is falling.
Question
Newton's second law is valid only in inertial reference frames.
Question
The force you exert on Earth is insignificant compared to the force Earth exerts on you.
Question
Weight and normal force are action-reaction pairs.
Question
State Newton's third law of motion.
Question
When an object is at rest on the Earth, the gravitational force disappears.
Question
The mass of an object is fixed, but its weight varies from location to location.
Question
An object of weight W is in free-fall close to the surface of Earth. What is the force that the object exerts on Earth?

A)a force greater than W
B)a force less than W
C)a force equal to W
D)no force at all
E)cannot be determined without additional information
Question
The normal force is always vertical.
Question
You try to pull an object by tugging on a rope attached to the object with a force <strong>You try to pull an object by tugging on a rope attached to the object with a force   . The object does not move at all. What does this imply?</strong> A)There are no other forces acting on the object. B)The inertia of the object prevents it from accelerating. C)The object has reached its natural state of rest and can no longer be set into motion. D)The rope is not transmitting the force to the object. E)There are also one or more other forces that act on the object with a sum -   . <div style=padding-top: 35px> . The object does not move at all. What does this imply?

A)There are no other forces acting on the object.
B)The inertia of the object prevents it from accelerating.
C)The object has reached its natural state of rest and can no longer be set into motion.
D)The rope is not transmitting the force to the object.
E)There are also one or more other forces that act on the object with a sum - <strong>You try to pull an object by tugging on a rope attached to the object with a force   . The object does not move at all. What does this imply?</strong> A)There are no other forces acting on the object. B)The inertia of the object prevents it from accelerating. C)The object has reached its natural state of rest and can no longer be set into motion. D)The rope is not transmitting the force to the object. E)There are also one or more other forces that act on the object with a sum -   . <div style=padding-top: 35px> .
Question
What does the word "normal" mean in the phrase "normal force"?

A)the force that is usually exerted by a surface
B)the total force exerted by a surface
C)the component of the force exerted by a surface parallel to the surface
D)the component of the force exerted by a surface perpendicular to the surface
E)the force is due to contact between two objects.
Question
An object of mass m sits on a flat table. The Earth pulls on this object with force mg, which we will call the action force. What is the reaction force?

A)The table pushing up on the object with force mg.
B)The object pushing down on the table with force mg.
C)The table pushing down on the floor with force mg.
D)The object pulling upward on the Earth with force mg.
E)The table pulling upward on the Earth with force mg.
Question
If you exert a force F on an object, the force which the object exerts on you will

A)depend on whether or not the object is moving.
B)depend on whether or not you are moving.
C)depend on your mass.
D)depend on the object's mass.
E)always be -F.
Question
In the absence of an external force, a moving object will

A)stop immediately.
B)slow down and eventually come to a stop.
C)gradually speed up until it reaches its terminal velocity.
D)move with constant velocity in a straight line.
E)move with constant velocity in a circular orbit.
Question
A horse pulls a cart with force <strong>A horse pulls a cart with force   . As a result of this force the cart accelerates with constant acceleration. What is the magnitude of the force that the cart exerts on the horse?</strong> A)zero Newtons B)equal to the magnitude of   C)less than the magnitude of   D)more than the magnitude of   E)cannot be determined without additional information <div style=padding-top: 35px> . As a result of this force the cart accelerates with constant acceleration. What is the magnitude of the force that the cart exerts on the horse?

A)zero Newtons
B)equal to the magnitude of <strong>A horse pulls a cart with force   . As a result of this force the cart accelerates with constant acceleration. What is the magnitude of the force that the cart exerts on the horse?</strong> A)zero Newtons B)equal to the magnitude of   C)less than the magnitude of   D)more than the magnitude of   E)cannot be determined without additional information <div style=padding-top: 35px>
C)less than the magnitude of <strong>A horse pulls a cart with force   . As a result of this force the cart accelerates with constant acceleration. What is the magnitude of the force that the cart exerts on the horse?</strong> A)zero Newtons B)equal to the magnitude of   C)less than the magnitude of   D)more than the magnitude of   E)cannot be determined without additional information <div style=padding-top: 35px>
D)more than the magnitude of <strong>A horse pulls a cart with force   . As a result of this force the cart accelerates with constant acceleration. What is the magnitude of the force that the cart exerts on the horse?</strong> A)zero Newtons B)equal to the magnitude of   C)less than the magnitude of   D)more than the magnitude of   E)cannot be determined without additional information <div style=padding-top: 35px>
E)cannot be determined without additional information
Question
Two cars collide head-on. At every moment during the collision, the magnitude of the force the first car exerts on the second is exactly equal to the magnitude of the force the second car exerts on the first. This is an example of

A)Newton's first law.
B)Newton's second law.
C)Newton's third law.
D)Newton's law of gravitation.
Question
If a cord has negligible mass, the force exerted at one end is transmitted undiminished to each adjacent piece of cord along the entire length to the other end.
Question
A book rests on a level table top. Which force does Newton's third law imply is equal in magnitude but opposite in direction to the weight of the book?

A)the force of the table on the earth
B)the force of the earth on the table
C)the force of the book on the earth
D)the force of the table on the book
E)the force of the book on the table
Question
A constant net force acts on an object. Describe the motion of the object.

A)constant non-zero velocity.
B)constant non-zero acceleration.
C)increasing acceleration.
D)decreasing acceleration.
E)zero acceleration.
Question
Your bat hits the ball pitched to you with a 1500-N instantaneous force. The ball hits the bat with an instantaneous force, whose magnitude is

A)somewhat less than 1500 N.
B)somewhat greater than 1500 N.
C)exactly equal to 1500 N.
D)essentially zero.
Question
A golf club hits a golf ball with a force of 2400 N. The golf ball hits the club with a force

A)slightly less than 2400 N.
B)exactly 2400 N.
C)slightly more than 2400 N.
D)close to 0 N.
Question
You are standing in a moving bus, facing forward, and you suddenly move forward as the bus comes to an immediate stop. What force caused you to move forward?

A)force of gravity
B)normal force due to your contact with the floor of the bus
C)force due to static friction between you and the floor of the bus
D)force due to kinetic friction between you and the floor of the bus
E)no forces were responsible for your fall.
Question
A 20-ton truck collides with a 1500-lb car and causes a lot of damage to the car.

A)The force of collision on the truck is greater then the force of collision on the car.
B)The force of collision on the truck is equal to the force of collision e on the car.
C)The force of collision on the truck is smaller than the of collision force on the car.
D)The truck did not slow down during the collision.
E)The car did not slow down during the collision.
Question
An object is moving with constant velocity in a straight line. Which of the following statements is true?

A)A constant force is being applied in the direction of motion.
B)A constant force is being applied in the direction opposite of motion.
C)There are no forces acting on the object.
D)The net force on the object is zero.
E)There is no frictional force acting on the object.
Question
An ideal pulley changes the direction of the tension in a string without changing its magnitude.
Question
Action-reaction forces are

A)equal in magnitude and point in the same direction.
B)equal in magnitude but point in opposite directions.
C)unequal in magnitude but point in the same direction.
D)unequal in magnitude and point in opposite directions
Question
You ride on an elevator that is moving upward with constant speed while standing on a bathroom scale. The reading on the scale is

A)equal to your true weight, mg.
B)more than your true weight, mg.
C)less than your true weight, mg.
D)could be more or less than your true weight, mg, depending on the value of the speed.
Question
An object rests on an inclined surface. If the inclination of the surface is made steeper, what does the normal force on the object do?

A)increase
B)decrease
C)stays the same
D)The normal force is zero.
E)Cannot be determined without additional information.
Question
A block of mass M slides down a frictionless plane inclined at an angle θ with the horizontal. The normal reaction force exerted by the plane on the block is

A)Mg.
B)Mg sin θ.
C)Mg cos θ.
D)Mg tan θ.
E)zero, since the plane is frictionless.
Question
A block is pushed up a 20.0° frictionless incline with an initial speed 12.0 m/s.
(a) How high up the plane does the block slide before coming to rest?
(b) How much time does it take to return to its starting position?
Question
FIGURE 4-4 <strong>FIGURE 4-4   Two masses, m<sub>1</sub> and m<sub>2</sub>, are connected to each other as shown in Fig. 4-4. Mass m<sub>1</sub> slides without friction on the table surface. Both masses have acceleration of magnitude a as shown. How does the tension in the string compare to the weight, m<sub>2 </sub>g, of mass m<sub>2</sub>?</strong> A)The tension is equal to m<sub>2 </sub>g. B)The tension is larger than m<sub>2 </sub>g. C)The tension is smaller than m<sub>2 </sub>g. D)It depends on m<sub>1</sub> being smaller than m<sub>2</sub>. E)It depends on m<sub>1</sub> being larger than m<sub>2</sub>. <div style=padding-top: 35px>
Two masses, m1 and m2, are connected to each other as shown in Fig. 4-4. Mass m1 slides without friction on the table surface. Both masses have acceleration of magnitude a as shown. How does the tension in the string compare to the weight, m2 g, of mass m2?

A)The tension is equal to m2 g.
B)The tension is larger than m2 g.
C)The tension is smaller than m2 g.
D)It depends on m1 being smaller than m2.
E)It depends on m1 being larger than m2.
Question
Two objects have masses m and 5m, respectively. They both are placed side by side on a frictionless inclined plane and allowed to slide down from rest.

A)It takes the lighter object 5 times longer to reach the bottom of the incline than the heavier.
B)It takes the lighter object 10 times longer to reach the bottom of the incline than the heavier.
C)It takes the heavier object 5 times longer to reach the bottom of the incline than the lighter.
D)It takes the heavier object 10 times longer to reach the bottom of the incline than the lighter.
E)The two objects reach the bottom of the incline at the same time.
Question
A block of mass M slides down a frictionless plane inclined at an angle θ with the horizontal. The gravitational force is directed

A)parallel to the plane in the same direction as the movement of the block.
B)parallel to the plane in the opposite direction as the movement of the block
C)perpendicular to the plane.
D)toward the center of the Earth.
E)an angle θ below the inclined plane.
Question
A block of mass M slides down a frictionless plane inclined at an angle θ with the horizontal. The normal reaction force exerted by the plane on the block is directed

A)parallel to the plane in the same direction as the movement of the block.
B)parallel to the plane in the opposite direction as the movement of the block
C)perpendicular to the plane.
D)toward the center of the Earth.
E)an angle θ above the inclined plane.
Question
Two toy cars (16 kg and 2.0 kg) are released simultaneously on an inclined plane that makes an angle of 30° with the horizontal. Make a statement which best describes their acceleration after being released.

A)The 16-kg car accelerates 8 times faster than the 2.0-kg car.
B)The 16-kg car accelerates 2 times faster than the 2.0-kg car.
C)The 2.0-kg car accelerates 8 times faster than the 16-kg car.
D)The 2.0-kg car accelerates 2 times faster than the 16-kg car.
E)Both cars accelerate at the same rate.
Question
FIGURE 4-1 <strong>FIGURE 4-1   In Fig. 4-1 the scale at left is attached to the ceiling and a mass of 1.00 kg hangs from it. It reads 9.81 N. The identical scale at the right is connected by perfect strings passing over perfect pulleys to two 1.00 kg masses hanging vertically at the end of the strings. The scale at right reads</strong> A)exactly 9.81 N. B)more than 9.81 N, but not quite twice as much. C)less than 9.81 N. D)exactly 19.62 N. E)more than 19.62 N. <div style=padding-top: 35px>
In Fig. 4-1 the scale at left is attached to the ceiling and a mass of 1.00 kg hangs from it. It reads 9.81 N. The identical scale at the right is connected by perfect strings passing over perfect pulleys to two 1.00 kg masses hanging vertically at the end of the strings. The scale at right reads

A)exactly 9.81 N.
B)more than 9.81 N, but not quite twice as much.
C)less than 9.81 N.
D)exactly 19.62 N.
E)more than 19.62 N.
Question
Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a downward acceleration less than g? Ff is the force of the floor on the person and Fg is the force of gravity on the person.

A)
<strong>Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a downward acceleration less than g? F<sub>f </sub>is the force of the floor on the person and F<sub>g </sub>is the force of gravity on the person.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B)
<strong>Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a downward acceleration less than g? F<sub>f </sub>is the force of the floor on the person and F<sub>g </sub>is the force of gravity on the person.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C)
<strong>Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a downward acceleration less than g? F<sub>f </sub>is the force of the floor on the person and F<sub>g </sub>is the force of gravity on the person.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D)
<strong>Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a downward acceleration less than g? F<sub>f </sub>is the force of the floor on the person and F<sub>g </sub>is the force of gravity on the person.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E)
<strong>Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a downward acceleration less than g? F<sub>f </sub>is the force of the floor on the person and F<sub>g </sub>is the force of gravity on the person.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
Question
You ride on an elevator that is moving with constant upward acceleration while standing on a bathroom scale. The reading on the scale is

A)equal to your true weight, mg.
B)more than your true weight, mg.
C)less than your true weight, mg.
D)could be more or less than your true weight, mg, depending on the magnitude of the acceleration.
Question
A block lies on a smooth inclined plane tilted at an angle of 35° to the horizontal.
(a) Draw the free-body diagram for the block.
(b) Determine the block's acceleration as it slides down the inclined plane.
(c) If the block started from rest 8.5 m up the incline from its base, determine the block's speed when it reaches the bottom of the incline.
(d) How long did it take the block to reach the bottom of the inclined plane?
Question
FIGURE 4-6 FIGURE 4-6   In the Atwood machine shown in Fig. 4-6, if M = 0.60 kg and m = 0.40 kg. Ignore friction and the mass of the pulley. (a) Draw free-body diagrams for mass M and mass m. (b) Calculate the magnitude of the acceleration of the system. (c) Calculate the tension in the string.<div style=padding-top: 35px>
In the Atwood machine shown in Fig. 4-6, if M = 0.60 kg and m = 0.40 kg. Ignore friction and the mass of the pulley.
(a) Draw free-body diagrams for mass M and mass m.
(b) Calculate the magnitude of the acceleration of the system.
(c) Calculate the tension in the string.
Question
A block lies on a horizontal frictionless surface. A horizontal force of 100 N is applied to the block giving rise to an acceleration of 3 m/s2.
(a) Determine the mass of the block.
(b) Calculate the distance the block will travel is the force is applied for 10 s.
(c) Calculate the speed of the block after the force has been applied for 10 s.
Question
FIGURE 4-7 FIGURE 4-7   Two boxes are connected by a cord running over a pulley as shown in Fig. 4-7. Box I of mass 8.0 kg rest on the top of the table; the coefficient of kinetic friction between box I and the table is 0.10. Box II has a mass of 15.0 kg. (a) Draw the free-body diagrams for the two boxes, identifying all of the forces acting on each of the masses. (b) Calculate the acceleration of the system. (c) Calculate the tension in the cord.<div style=padding-top: 35px>
Two boxes are connected by a cord running over a pulley as shown in Fig. 4-7. Box I of mass 8.0 kg rest on the top of the table; the coefficient of kinetic friction between box I and the table is 0.10. Box II has a mass of 15.0 kg.
(a) Draw the free-body diagrams for the two boxes, identifying all of the forces acting on each of the masses.
(b) Calculate the acceleration of the system.
(c) Calculate the tension in the cord.
Question
FIGURE 4-5 <strong>FIGURE 4-5   Two identical masses are attached by a light string that passes over a small pulley, as shown in Fig. 4-5. The table and the pulley are frictionless. The masses are moving</strong> A)with an acceleration less than g. B)at constant speed. C)with an acceleration greater than g. D)with an acceleration equal to g. E)with an acceleration that cannot be determined without additional information. <div style=padding-top: 35px>
Two identical masses are attached by a light string that passes over a small pulley, as shown in Fig. 4-5. The table and the pulley are frictionless. The masses are moving

A)with an acceleration less than g.
B)at constant speed.
C)with an acceleration greater than g.
D)with an acceleration equal to g.
E)with an acceleration that cannot be determined without additional information.
Question
FIGURE 4-3 <strong>FIGURE 4-3   A 16-kg fish is weighed with two spring scales, each of negligible weight, as shown in Fig. 4-3. What will be the readings on the scales?</strong> A)The bottom scale will read 16 kg, and the top scale will read zero. B)The sum of the two readings will be 32 kg. C)The top scale will read 16 kg, and the bottom scale will read zero. D)Each scale will show a reading greater than zero and less than 16 kg, but the sum of the two readings will be 16 kg. E)Each scale will read 8 kg. <div style=padding-top: 35px>
A 16-kg fish is weighed with two spring scales, each of negligible weight, as shown in Fig. 4-3. What will be the readings on the scales?

A)The bottom scale will read 16 kg, and the top scale will read zero.
B)The sum of the two readings will be 32 kg.
C)The top scale will read 16 kg, and the bottom scale will read zero.
D)Each scale will show a reading greater than zero and less than 16 kg, but the sum of the two readings will be 16 kg.
E)Each scale will read 8 kg.
Question
Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a constant velocity? Ff is the force of the floor on the person and Fg is the force of gravity on the person.

A)
<strong>Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a constant velocity? F<sub>f </sub>is the force of the floor on the person and F<sub>g </sub>is the force of gravity on the person.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B)
<strong>Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a constant velocity? F<sub>f </sub>is the force of the floor on the person and F<sub>g </sub>is the force of gravity on the person.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C)
<strong>Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a constant velocity? F<sub>f </sub>is the force of the floor on the person and F<sub>g </sub>is the force of gravity on the person.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D)
<strong>Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a constant velocity? F<sub>f </sub>is the force of the floor on the person and F<sub>g </sub>is the force of gravity on the person.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E)
<strong>Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a constant velocity? F<sub>f </sub>is the force of the floor on the person and F<sub>g </sub>is the force of gravity on the person.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
Question
FIGURE 4-2 <strong>FIGURE 4-2   Compare the two situations shown in Fig. 4-2. On the left (A), James is holding the rope and keeping the bucket at rest. On the right (B), James ties the rope to the bucket so that it keeps the bucket at rest. In both cases the bucket contains the same quantity of water. In what case is the tension in the rope lower?</strong> A)right B)left C)It is the same in both cases. D)need more data to answer <div style=padding-top: 35px>
Compare the two situations shown in Fig. 4-2. On the left (A), James is holding the rope and keeping the bucket at rest. On the right (B), James ties the rope to the bucket so that it keeps the bucket at rest. In both cases the bucket contains the same quantity of water. In what case is the tension in the rope lower?

A)right
B)left
C)It is the same in both cases.
D)need more data to answer
Question
A student pulls a box of books on a smooth horizontal floor with a force of 100 N in a direction of 37.0° above the horizontal. The mass of the box and the books is 40.0 kg.
(a) Draw the free-body diagram for the box.
(b) Calculate the acceleration of the box.
(c) Calculate the normal force acting on the box.
Question
A 1000-kg car is driving toward the north along a straight road at a speed of 20.0 m/s. The driver applies the brakes and the car comes to a rest in a distance of 140 m. What is the constant force applied to the car to bring it to rest?

A)1.43 N north
B)7.00 × 103 N south
C)1.43 × 103 N south
D)1.43 N south
E)143 N south
Question
FIGURE 4-8 <strong>FIGURE 4-8   The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?</strong> A)7.0 N   + 2.0 N   B)1.0 N   - 5.0 N   C)3.0 N   + 4.0 N   D)-1.0 N   + 5.0 N   E)3.0 N   - 4.0 N   <div style=padding-top: 35px>
The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?

A)7.0 N <strong>FIGURE 4-8   The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?</strong> A)7.0 N   + 2.0 N   B)1.0 N   - 5.0 N   C)3.0 N   + 4.0 N   D)-1.0 N   + 5.0 N   E)3.0 N   - 4.0 N   <div style=padding-top: 35px> + 2.0 N
<strong>FIGURE 4-8   The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?</strong> A)7.0 N   + 2.0 N   B)1.0 N   - 5.0 N   C)3.0 N   + 4.0 N   D)-1.0 N   + 5.0 N   E)3.0 N   - 4.0 N   <div style=padding-top: 35px>
B)1.0 N <strong>FIGURE 4-8   The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?</strong> A)7.0 N   + 2.0 N   B)1.0 N   - 5.0 N   C)3.0 N   + 4.0 N   D)-1.0 N   + 5.0 N   E)3.0 N   - 4.0 N   <div style=padding-top: 35px> - 5.0 N
<strong>FIGURE 4-8   The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?</strong> A)7.0 N   + 2.0 N   B)1.0 N   - 5.0 N   C)3.0 N   + 4.0 N   D)-1.0 N   + 5.0 N   E)3.0 N   - 4.0 N   <div style=padding-top: 35px>
C)3.0 N <strong>FIGURE 4-8   The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?</strong> A)7.0 N   + 2.0 N   B)1.0 N   - 5.0 N   C)3.0 N   + 4.0 N   D)-1.0 N   + 5.0 N   E)3.0 N   - 4.0 N   <div style=padding-top: 35px> + 4.0 N
<strong>FIGURE 4-8   The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?</strong> A)7.0 N   + 2.0 N   B)1.0 N   - 5.0 N   C)3.0 N   + 4.0 N   D)-1.0 N   + 5.0 N   E)3.0 N   - 4.0 N   <div style=padding-top: 35px>
D)-1.0 N <strong>FIGURE 4-8   The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?</strong> A)7.0 N   + 2.0 N   B)1.0 N   - 5.0 N   C)3.0 N   + 4.0 N   D)-1.0 N   + 5.0 N   E)3.0 N   - 4.0 N   <div style=padding-top: 35px> + 5.0 N
<strong>FIGURE 4-8   The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?</strong> A)7.0 N   + 2.0 N   B)1.0 N   - 5.0 N   C)3.0 N   + 4.0 N   D)-1.0 N   + 5.0 N   E)3.0 N   - 4.0 N   <div style=padding-top: 35px>
E)3.0 N <strong>FIGURE 4-8   The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?</strong> A)7.0 N   + 2.0 N   B)1.0 N   - 5.0 N   C)3.0 N   + 4.0 N   D)-1.0 N   + 5.0 N   E)3.0 N   - 4.0 N   <div style=padding-top: 35px> - 4.0 N
<strong>FIGURE 4-8   The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?</strong> A)7.0 N   + 2.0 N   B)1.0 N   - 5.0 N   C)3.0 N   + 4.0 N   D)-1.0 N   + 5.0 N   E)3.0 N   - 4.0 N   <div style=padding-top: 35px>
Question
A 2.00-kg object moves with constant velocity 3.00 m/s toward the east. Two forces act on the object. The first is a 40.0 N force toward the west. What is the second force that acts on the object?

A)23.0 N east
B)40.0 N east
C)26.7 N east
D)46.0 N east
E)46.0 N west
Question
Three boxes rest side-by-side on a smooth, horizontal floor. Their masses are 5.0-kg, 3.0-kg, and 2.0-kg, with the 3.0-kg mass in the center. A force of 50 N pushes on the 5.0-kg mass, which pushes against the other two masses.
(a) Draw the free-body diagrams for each of the masses.
(b) What is the contact force between the 5.0-kg mass and the 3.0-kg mass?
(c) What is the contact force between the 3.0-kg and the 2.0-kg mass?
Question
Two objects push on each other. The first object has a mass 30.0 kg and it accelerates at 2.00 m/s2 toward the east. The second object has a mass 7.00 kg. If no other forces are acting on the objects, what is the acceleration of the second object?

A)4.67 m/s2 west
B)1.14 m/s2 east
C)2.00 m/s2 west
D)8.57 m/s2 west
E)4.67 m/s2 east
Question
Starting from rest, a 4.0-kg body reaches a speed of 8.0 m/s in 2.0 s. What is the net force acting on the body?

A)2.0 N
B)4.0 N
C)8.0 N
D)16 N
E)32 N
Question
Object A is acted on by only object B. The mass of object A is 20.0 kg and its acceleration is 4.00 m/s2 west. Object B is acted on by two forces, the force of object A on object B and another unknown force. If mass of object B is 40.0 kg and the acceleration of object B is 3.00 m/s2 west, what is the unknown force?

A)40 N west
B)120 N west
C)80 N east
D)200 N west
E)80 N west
Question
FIGURE 4-10 <strong>FIGURE 4-10   The three forces represented in Fig. 4-10 act on an object. What is the direction of the acceleration of the object?</strong> A)11.3° clockwise from the -x-axis B)11.3° counterclockwise from the +y-axis C)78.7° counterclockwise from the +x-axis D)11.3° clockwise from the +y-axis E)The mass of the object must be known to answer the question. <div style=padding-top: 35px>
The three forces represented in Fig. 4-10 act on an object. What is the direction of the acceleration of the object?

A)11.3° clockwise from the -x-axis
B)11.3° counterclockwise from the +y-axis
C)78.7° counterclockwise from the +x-axis
D)11.3° clockwise from the +y-axis
E)The mass of the object must be known to answer the question.
Question
Two forces act on a 4.00-kg object in a manner that the object has an acceleration 3.00 m/s2 in a direction 20.0° north of east. The first force is 15.00 N in a direction 10.0° west of north. What is the second force?

A)14.6 N in a direction 28.1° south of east
B)12.9 N in a direction 28.1° south of east
C)16.2 N in a direction 30.2° south of east
D)18.8 N in a direction 41.1° south of east
E)17.5 N in a direction 37.5° south of east
Question
The following four forces act on a 4.00 kg object: F1 = 300 N east
F2 = 700 N north
F3 = 500 N west
F4 = 600 N south
What is the acceleration of the object?

A)224 N in a direction 63.4° north of west
B)300 N in a direction 63.4° north of west
C)300 N in a direction 26.6° north of west
D)224 N in a direction 26.6° north of west
E)2100 N in a direction 26.6° north of west
Question
A person has a mass of 45 kg. How much does she weigh on the Moon, where g = 1.62 m/ s2?

A)45 N
B)73 N
C)7.4 N
D)220 N
E)440 N
Question
An astronaut weighs 99.0 N on the Moon, where the acceleration of gravity is 1.62 m/ s2. How much does she weigh on Earth?

A)16.2 N
B)61.0 N
C)99.0 N
D)600 N
E)440 N
Question
FIGURE 4-11 <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   <div style=padding-top: 35px>
The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?

A)(6.0 N sin 28° - 5.0 N sin 22°) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   <div style=padding-top: 35px> + (6.0 N cos 28° + 5.0 N cos 22°) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   <div style=padding-top: 35px> = (8.00 kg) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   <div style=padding-top: 35px>
B)(6.0 N cos 28° + 5.0 N cos 22°) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   <div style=padding-top: 35px> + (6.0 N sin 28° + 5.0 N sin 22°) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   <div style=padding-top: 35px> = (8.00 kg) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   <div style=padding-top: 35px>
C)(6.0 N cos 28° - 5.0 N sin 22°) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   <div style=padding-top: 35px> + (6.0 N sin 28° + 5.0 N cos 22°) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   <div style=padding-top: 35px> = (8.00 kg) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   <div style=padding-top: 35px>
D)(6.0 N cos 28° - 5.0 N cos 22°) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   <div style=padding-top: 35px> + (6.0 N sin 28° + 5.0 N sin 22°) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   <div style=padding-top: 35px> = (8.00 kg) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   <div style=padding-top: 35px>
E)(6.0 N cos 28° + 5.0 N sin 22°) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   <div style=padding-top: 35px> + (6.0 N sin 28° - 5.0 N cos 22°) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   <div style=padding-top: 35px> = (8.00 kg) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   <div style=padding-top: 35px>
Question
A 1.0-kg object is moving with a constant velocity 2.0 m/s toward the north. There are two forces acting on the object. One of the forces is 2.0 N north. The other force is ________

A)1.0 N north.
B)3.0 N north.
C)2.0 N south.
D)2.0 N north.
E)0.
Question
A 1200-kg car starts from rest and accelerates with constant acceleration, traveling 200 m in 9.00 s. What is the force of the road on the car during this acceleration?

A)1.43 kN
B)3.87 kN
C)5.93 kN
D)4.82 kN
E)11.8 kN
Question
The International Space Station has a mass 1.8 × 105 kg. A 70.0-kg astronaut inside the station pushes off one wall of the station so she accelerates at 1.50 m/s2. What is the magnitude of the acceleration of the space station as the astronaut is pushing off the wall relative to an observer initially at rest relative to the space station before the push?

A)5.8 × 10-4 m/s2
B)1.50 m/s2
C)4.7 × 10-4 m/s2
D)zero
E)3.9 × 10-3 m/s2
Question
A 5.00-kg object is initially at rest. The object is acted on by a 9.00-N force toward the east for 3.00 s. No force acts on the object for the next 4.00 s. How far has the object moved during this 7.00 s interval?

A)8.10 m
B)29.7 m
C)53.6 m
D)21.7 m
E)16.2 m
Question
FIGURE 4-9 <strong>FIGURE 4-9   The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?</strong> A)(1.67 m/s<sup>2</sup>)   - (0.333 m/s<sup>2</sup>)   B)(5.00 m/s<sup>2</sup>)   + (1.00 m/s<sup>2</sup>)   C)(1.67 m/s<sup>2</sup>)   + (2.333 m/s<sup>2</sup>)   D)(15.0 m/s<sup>2</sup>)   + (3.00 m/s<sup>2</sup>)   E)(1.67 m/s<sup>2</sup>)   + (0.333 m/s<sup>2</sup>)   <div style=padding-top: 35px>
The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?

A)(1.67 m/s2) <strong>FIGURE 4-9   The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?</strong> A)(1.67 m/s<sup>2</sup>)   - (0.333 m/s<sup>2</sup>)   B)(5.00 m/s<sup>2</sup>)   + (1.00 m/s<sup>2</sup>)   C)(1.67 m/s<sup>2</sup>)   + (2.333 m/s<sup>2</sup>)   D)(15.0 m/s<sup>2</sup>)   + (3.00 m/s<sup>2</sup>)   E)(1.67 m/s<sup>2</sup>)   + (0.333 m/s<sup>2</sup>)   <div style=padding-top: 35px> - (0.333 m/s2) <strong>FIGURE 4-9   The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?</strong> A)(1.67 m/s<sup>2</sup>)   - (0.333 m/s<sup>2</sup>)   B)(5.00 m/s<sup>2</sup>)   + (1.00 m/s<sup>2</sup>)   C)(1.67 m/s<sup>2</sup>)   + (2.333 m/s<sup>2</sup>)   D)(15.0 m/s<sup>2</sup>)   + (3.00 m/s<sup>2</sup>)   E)(1.67 m/s<sup>2</sup>)   + (0.333 m/s<sup>2</sup>)   <div style=padding-top: 35px>
B)(5.00 m/s2) <strong>FIGURE 4-9   The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?</strong> A)(1.67 m/s<sup>2</sup>)   - (0.333 m/s<sup>2</sup>)   B)(5.00 m/s<sup>2</sup>)   + (1.00 m/s<sup>2</sup>)   C)(1.67 m/s<sup>2</sup>)   + (2.333 m/s<sup>2</sup>)   D)(15.0 m/s<sup>2</sup>)   + (3.00 m/s<sup>2</sup>)   E)(1.67 m/s<sup>2</sup>)   + (0.333 m/s<sup>2</sup>)   <div style=padding-top: 35px> + (1.00 m/s2) <strong>FIGURE 4-9   The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?</strong> A)(1.67 m/s<sup>2</sup>)   - (0.333 m/s<sup>2</sup>)   B)(5.00 m/s<sup>2</sup>)   + (1.00 m/s<sup>2</sup>)   C)(1.67 m/s<sup>2</sup>)   + (2.333 m/s<sup>2</sup>)   D)(15.0 m/s<sup>2</sup>)   + (3.00 m/s<sup>2</sup>)   E)(1.67 m/s<sup>2</sup>)   + (0.333 m/s<sup>2</sup>)   <div style=padding-top: 35px>
C)(1.67 m/s2) <strong>FIGURE 4-9   The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?</strong> A)(1.67 m/s<sup>2</sup>)   - (0.333 m/s<sup>2</sup>)   B)(5.00 m/s<sup>2</sup>)   + (1.00 m/s<sup>2</sup>)   C)(1.67 m/s<sup>2</sup>)   + (2.333 m/s<sup>2</sup>)   D)(15.0 m/s<sup>2</sup>)   + (3.00 m/s<sup>2</sup>)   E)(1.67 m/s<sup>2</sup>)   + (0.333 m/s<sup>2</sup>)   <div style=padding-top: 35px> + (2.333 m/s2) <strong>FIGURE 4-9   The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?</strong> A)(1.67 m/s<sup>2</sup>)   - (0.333 m/s<sup>2</sup>)   B)(5.00 m/s<sup>2</sup>)   + (1.00 m/s<sup>2</sup>)   C)(1.67 m/s<sup>2</sup>)   + (2.333 m/s<sup>2</sup>)   D)(15.0 m/s<sup>2</sup>)   + (3.00 m/s<sup>2</sup>)   E)(1.67 m/s<sup>2</sup>)   + (0.333 m/s<sup>2</sup>)   <div style=padding-top: 35px>
D)(15.0 m/s2) <strong>FIGURE 4-9   The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?</strong> A)(1.67 m/s<sup>2</sup>)   - (0.333 m/s<sup>2</sup>)   B)(5.00 m/s<sup>2</sup>)   + (1.00 m/s<sup>2</sup>)   C)(1.67 m/s<sup>2</sup>)   + (2.333 m/s<sup>2</sup>)   D)(15.0 m/s<sup>2</sup>)   + (3.00 m/s<sup>2</sup>)   E)(1.67 m/s<sup>2</sup>)   + (0.333 m/s<sup>2</sup>)   <div style=padding-top: 35px> + (3.00 m/s2) <strong>FIGURE 4-9   The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?</strong> A)(1.67 m/s<sup>2</sup>)   - (0.333 m/s<sup>2</sup>)   B)(5.00 m/s<sup>2</sup>)   + (1.00 m/s<sup>2</sup>)   C)(1.67 m/s<sup>2</sup>)   + (2.333 m/s<sup>2</sup>)   D)(15.0 m/s<sup>2</sup>)   + (3.00 m/s<sup>2</sup>)   E)(1.67 m/s<sup>2</sup>)   + (0.333 m/s<sup>2</sup>)   <div style=padding-top: 35px>
E)(1.67 m/s2) <strong>FIGURE 4-9   The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?</strong> A)(1.67 m/s<sup>2</sup>)   - (0.333 m/s<sup>2</sup>)   B)(5.00 m/s<sup>2</sup>)   + (1.00 m/s<sup>2</sup>)   C)(1.67 m/s<sup>2</sup>)   + (2.333 m/s<sup>2</sup>)   D)(15.0 m/s<sup>2</sup>)   + (3.00 m/s<sup>2</sup>)   E)(1.67 m/s<sup>2</sup>)   + (0.333 m/s<sup>2</sup>)   <div style=padding-top: 35px> + (0.333 m/s2) <strong>FIGURE 4-9   The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?</strong> A)(1.67 m/s<sup>2</sup>)   - (0.333 m/s<sup>2</sup>)   B)(5.00 m/s<sup>2</sup>)   + (1.00 m/s<sup>2</sup>)   C)(1.67 m/s<sup>2</sup>)   + (2.333 m/s<sup>2</sup>)   D)(15.0 m/s<sup>2</sup>)   + (3.00 m/s<sup>2</sup>)   E)(1.67 m/s<sup>2</sup>)   + (0.333 m/s<sup>2</sup>)   <div style=padding-top: 35px>
Question
A 7.0-kg object is acted on by two forces. One of the forces is 10.0 N acting toward the east. Which of the following forces is the other force if the acceleration of the object is 1.0 m/ s2 toward the east?

A)6.0 N east
B)3.0 N west
C)12.0 N east
D)9.0 N west
E)7.0 N west
Question
A force of 120 N is applied to an object whose mass is 30 kg. The object's acceleration is

A)3600 m/ s2.
B)150 m/ s2.
C)4.0 m/ s2.
D)2.0 m/ s2.
E)0.25 m/ s2.
Unlock Deck
Sign up to unlock the cards in this deck!
Unlock Deck
Unlock Deck
1/86
auto play flashcards
Play
simple tutorial
Full screen (f)
exit full mode
Deck 4: Dynamics: Newtons Laws of Motion
1
Explain how to draw free-body diagrams.
Choose one object, and draw an arrow to represent each force acting on it. Include every force acting on that object. Do not show forces that the chosen object exerts on other objects. To help identify each and every force that is exerted on the chosen object, ask what other objects could exert a force on it. If the problem involves more than one object, a separate free-body diagram is needed for each object.
2
According to Newton's Third Law, "action" and "reaction" forces must always act on the same object.
False
3
A force exerted by an object does not influence that same object; it only influences the other object on which it is exerted.
True
4
A force is required for an object to accelerate.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
5
State Newton's second law of motion.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
6
State Newton's first law of motion.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
7
A force is required to keep an object moving along a horizontal line.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
8
If no force is applied to a moving object, it will continue to move with constant speed in a straight line.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
9
Newton's First law holds in all reference frames, including inertial reference frames.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
10
The acceleration of an object does not have to be in the same direction as the net force applied to it.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
11
The acceleration of an object depends only on the net applied force.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
12
The acceleration of an object depends only on the object's mass.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
13
The normal force is always equal to the force of gravity.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
14
The force of gravity acts on an object only when it is falling.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
15
Newton's second law is valid only in inertial reference frames.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
16
The force you exert on Earth is insignificant compared to the force Earth exerts on you.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
17
Weight and normal force are action-reaction pairs.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
18
State Newton's third law of motion.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
19
When an object is at rest on the Earth, the gravitational force disappears.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
20
The mass of an object is fixed, but its weight varies from location to location.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
21
An object of weight W is in free-fall close to the surface of Earth. What is the force that the object exerts on Earth?

A)a force greater than W
B)a force less than W
C)a force equal to W
D)no force at all
E)cannot be determined without additional information
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
22
The normal force is always vertical.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
23
You try to pull an object by tugging on a rope attached to the object with a force <strong>You try to pull an object by tugging on a rope attached to the object with a force   . The object does not move at all. What does this imply?</strong> A)There are no other forces acting on the object. B)The inertia of the object prevents it from accelerating. C)The object has reached its natural state of rest and can no longer be set into motion. D)The rope is not transmitting the force to the object. E)There are also one or more other forces that act on the object with a sum -   . . The object does not move at all. What does this imply?

A)There are no other forces acting on the object.
B)The inertia of the object prevents it from accelerating.
C)The object has reached its natural state of rest and can no longer be set into motion.
D)The rope is not transmitting the force to the object.
E)There are also one or more other forces that act on the object with a sum - <strong>You try to pull an object by tugging on a rope attached to the object with a force   . The object does not move at all. What does this imply?</strong> A)There are no other forces acting on the object. B)The inertia of the object prevents it from accelerating. C)The object has reached its natural state of rest and can no longer be set into motion. D)The rope is not transmitting the force to the object. E)There are also one or more other forces that act on the object with a sum -   . .
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
24
What does the word "normal" mean in the phrase "normal force"?

A)the force that is usually exerted by a surface
B)the total force exerted by a surface
C)the component of the force exerted by a surface parallel to the surface
D)the component of the force exerted by a surface perpendicular to the surface
E)the force is due to contact between two objects.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
25
An object of mass m sits on a flat table. The Earth pulls on this object with force mg, which we will call the action force. What is the reaction force?

A)The table pushing up on the object with force mg.
B)The object pushing down on the table with force mg.
C)The table pushing down on the floor with force mg.
D)The object pulling upward on the Earth with force mg.
E)The table pulling upward on the Earth with force mg.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
26
If you exert a force F on an object, the force which the object exerts on you will

A)depend on whether or not the object is moving.
B)depend on whether or not you are moving.
C)depend on your mass.
D)depend on the object's mass.
E)always be -F.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
27
In the absence of an external force, a moving object will

A)stop immediately.
B)slow down and eventually come to a stop.
C)gradually speed up until it reaches its terminal velocity.
D)move with constant velocity in a straight line.
E)move with constant velocity in a circular orbit.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
28
A horse pulls a cart with force <strong>A horse pulls a cart with force   . As a result of this force the cart accelerates with constant acceleration. What is the magnitude of the force that the cart exerts on the horse?</strong> A)zero Newtons B)equal to the magnitude of   C)less than the magnitude of   D)more than the magnitude of   E)cannot be determined without additional information . As a result of this force the cart accelerates with constant acceleration. What is the magnitude of the force that the cart exerts on the horse?

A)zero Newtons
B)equal to the magnitude of <strong>A horse pulls a cart with force   . As a result of this force the cart accelerates with constant acceleration. What is the magnitude of the force that the cart exerts on the horse?</strong> A)zero Newtons B)equal to the magnitude of   C)less than the magnitude of   D)more than the magnitude of   E)cannot be determined without additional information
C)less than the magnitude of <strong>A horse pulls a cart with force   . As a result of this force the cart accelerates with constant acceleration. What is the magnitude of the force that the cart exerts on the horse?</strong> A)zero Newtons B)equal to the magnitude of   C)less than the magnitude of   D)more than the magnitude of   E)cannot be determined without additional information
D)more than the magnitude of <strong>A horse pulls a cart with force   . As a result of this force the cart accelerates with constant acceleration. What is the magnitude of the force that the cart exerts on the horse?</strong> A)zero Newtons B)equal to the magnitude of   C)less than the magnitude of   D)more than the magnitude of   E)cannot be determined without additional information
E)cannot be determined without additional information
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
29
Two cars collide head-on. At every moment during the collision, the magnitude of the force the first car exerts on the second is exactly equal to the magnitude of the force the second car exerts on the first. This is an example of

A)Newton's first law.
B)Newton's second law.
C)Newton's third law.
D)Newton's law of gravitation.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
30
If a cord has negligible mass, the force exerted at one end is transmitted undiminished to each adjacent piece of cord along the entire length to the other end.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
31
A book rests on a level table top. Which force does Newton's third law imply is equal in magnitude but opposite in direction to the weight of the book?

A)the force of the table on the earth
B)the force of the earth on the table
C)the force of the book on the earth
D)the force of the table on the book
E)the force of the book on the table
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
32
A constant net force acts on an object. Describe the motion of the object.

A)constant non-zero velocity.
B)constant non-zero acceleration.
C)increasing acceleration.
D)decreasing acceleration.
E)zero acceleration.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
33
Your bat hits the ball pitched to you with a 1500-N instantaneous force. The ball hits the bat with an instantaneous force, whose magnitude is

A)somewhat less than 1500 N.
B)somewhat greater than 1500 N.
C)exactly equal to 1500 N.
D)essentially zero.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
34
A golf club hits a golf ball with a force of 2400 N. The golf ball hits the club with a force

A)slightly less than 2400 N.
B)exactly 2400 N.
C)slightly more than 2400 N.
D)close to 0 N.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
35
You are standing in a moving bus, facing forward, and you suddenly move forward as the bus comes to an immediate stop. What force caused you to move forward?

A)force of gravity
B)normal force due to your contact with the floor of the bus
C)force due to static friction between you and the floor of the bus
D)force due to kinetic friction between you and the floor of the bus
E)no forces were responsible for your fall.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
36
A 20-ton truck collides with a 1500-lb car and causes a lot of damage to the car.

A)The force of collision on the truck is greater then the force of collision on the car.
B)The force of collision on the truck is equal to the force of collision e on the car.
C)The force of collision on the truck is smaller than the of collision force on the car.
D)The truck did not slow down during the collision.
E)The car did not slow down during the collision.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
37
An object is moving with constant velocity in a straight line. Which of the following statements is true?

A)A constant force is being applied in the direction of motion.
B)A constant force is being applied in the direction opposite of motion.
C)There are no forces acting on the object.
D)The net force on the object is zero.
E)There is no frictional force acting on the object.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
38
An ideal pulley changes the direction of the tension in a string without changing its magnitude.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
39
Action-reaction forces are

A)equal in magnitude and point in the same direction.
B)equal in magnitude but point in opposite directions.
C)unequal in magnitude but point in the same direction.
D)unequal in magnitude and point in opposite directions
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
40
You ride on an elevator that is moving upward with constant speed while standing on a bathroom scale. The reading on the scale is

A)equal to your true weight, mg.
B)more than your true weight, mg.
C)less than your true weight, mg.
D)could be more or less than your true weight, mg, depending on the value of the speed.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
41
An object rests on an inclined surface. If the inclination of the surface is made steeper, what does the normal force on the object do?

A)increase
B)decrease
C)stays the same
D)The normal force is zero.
E)Cannot be determined without additional information.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
42
A block of mass M slides down a frictionless plane inclined at an angle θ with the horizontal. The normal reaction force exerted by the plane on the block is

A)Mg.
B)Mg sin θ.
C)Mg cos θ.
D)Mg tan θ.
E)zero, since the plane is frictionless.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
43
A block is pushed up a 20.0° frictionless incline with an initial speed 12.0 m/s.
(a) How high up the plane does the block slide before coming to rest?
(b) How much time does it take to return to its starting position?
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
44
FIGURE 4-4 <strong>FIGURE 4-4   Two masses, m<sub>1</sub> and m<sub>2</sub>, are connected to each other as shown in Fig. 4-4. Mass m<sub>1</sub> slides without friction on the table surface. Both masses have acceleration of magnitude a as shown. How does the tension in the string compare to the weight, m<sub>2 </sub>g, of mass m<sub>2</sub>?</strong> A)The tension is equal to m<sub>2 </sub>g. B)The tension is larger than m<sub>2 </sub>g. C)The tension is smaller than m<sub>2 </sub>g. D)It depends on m<sub>1</sub> being smaller than m<sub>2</sub>. E)It depends on m<sub>1</sub> being larger than m<sub>2</sub>.
Two masses, m1 and m2, are connected to each other as shown in Fig. 4-4. Mass m1 slides without friction on the table surface. Both masses have acceleration of magnitude a as shown. How does the tension in the string compare to the weight, m2 g, of mass m2?

A)The tension is equal to m2 g.
B)The tension is larger than m2 g.
C)The tension is smaller than m2 g.
D)It depends on m1 being smaller than m2.
E)It depends on m1 being larger than m2.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
45
Two objects have masses m and 5m, respectively. They both are placed side by side on a frictionless inclined plane and allowed to slide down from rest.

A)It takes the lighter object 5 times longer to reach the bottom of the incline than the heavier.
B)It takes the lighter object 10 times longer to reach the bottom of the incline than the heavier.
C)It takes the heavier object 5 times longer to reach the bottom of the incline than the lighter.
D)It takes the heavier object 10 times longer to reach the bottom of the incline than the lighter.
E)The two objects reach the bottom of the incline at the same time.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
46
A block of mass M slides down a frictionless plane inclined at an angle θ with the horizontal. The gravitational force is directed

A)parallel to the plane in the same direction as the movement of the block.
B)parallel to the plane in the opposite direction as the movement of the block
C)perpendicular to the plane.
D)toward the center of the Earth.
E)an angle θ below the inclined plane.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
47
A block of mass M slides down a frictionless plane inclined at an angle θ with the horizontal. The normal reaction force exerted by the plane on the block is directed

A)parallel to the plane in the same direction as the movement of the block.
B)parallel to the plane in the opposite direction as the movement of the block
C)perpendicular to the plane.
D)toward the center of the Earth.
E)an angle θ above the inclined plane.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
48
Two toy cars (16 kg and 2.0 kg) are released simultaneously on an inclined plane that makes an angle of 30° with the horizontal. Make a statement which best describes their acceleration after being released.

A)The 16-kg car accelerates 8 times faster than the 2.0-kg car.
B)The 16-kg car accelerates 2 times faster than the 2.0-kg car.
C)The 2.0-kg car accelerates 8 times faster than the 16-kg car.
D)The 2.0-kg car accelerates 2 times faster than the 16-kg car.
E)Both cars accelerate at the same rate.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
49
FIGURE 4-1 <strong>FIGURE 4-1   In Fig. 4-1 the scale at left is attached to the ceiling and a mass of 1.00 kg hangs from it. It reads 9.81 N. The identical scale at the right is connected by perfect strings passing over perfect pulleys to two 1.00 kg masses hanging vertically at the end of the strings. The scale at right reads</strong> A)exactly 9.81 N. B)more than 9.81 N, but not quite twice as much. C)less than 9.81 N. D)exactly 19.62 N. E)more than 19.62 N.
In Fig. 4-1 the scale at left is attached to the ceiling and a mass of 1.00 kg hangs from it. It reads 9.81 N. The identical scale at the right is connected by perfect strings passing over perfect pulleys to two 1.00 kg masses hanging vertically at the end of the strings. The scale at right reads

A)exactly 9.81 N.
B)more than 9.81 N, but not quite twice as much.
C)less than 9.81 N.
D)exactly 19.62 N.
E)more than 19.62 N.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
50
Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a downward acceleration less than g? Ff is the force of the floor on the person and Fg is the force of gravity on the person.

A)
<strong>Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a downward acceleration less than g? F<sub>f </sub>is the force of the floor on the person and F<sub>g </sub>is the force of gravity on the person.</strong> A)   B)   C)   D)   E)
B)
<strong>Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a downward acceleration less than g? F<sub>f </sub>is the force of the floor on the person and F<sub>g </sub>is the force of gravity on the person.</strong> A)   B)   C)   D)   E)
C)
<strong>Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a downward acceleration less than g? F<sub>f </sub>is the force of the floor on the person and F<sub>g </sub>is the force of gravity on the person.</strong> A)   B)   C)   D)   E)
D)
<strong>Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a downward acceleration less than g? F<sub>f </sub>is the force of the floor on the person and F<sub>g </sub>is the force of gravity on the person.</strong> A)   B)   C)   D)   E)
E)
<strong>Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a downward acceleration less than g? F<sub>f </sub>is the force of the floor on the person and F<sub>g </sub>is the force of gravity on the person.</strong> A)   B)   C)   D)   E)
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
51
You ride on an elevator that is moving with constant upward acceleration while standing on a bathroom scale. The reading on the scale is

A)equal to your true weight, mg.
B)more than your true weight, mg.
C)less than your true weight, mg.
D)could be more or less than your true weight, mg, depending on the magnitude of the acceleration.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
52
A block lies on a smooth inclined plane tilted at an angle of 35° to the horizontal.
(a) Draw the free-body diagram for the block.
(b) Determine the block's acceleration as it slides down the inclined plane.
(c) If the block started from rest 8.5 m up the incline from its base, determine the block's speed when it reaches the bottom of the incline.
(d) How long did it take the block to reach the bottom of the inclined plane?
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
53
FIGURE 4-6 FIGURE 4-6   In the Atwood machine shown in Fig. 4-6, if M = 0.60 kg and m = 0.40 kg. Ignore friction and the mass of the pulley. (a) Draw free-body diagrams for mass M and mass m. (b) Calculate the magnitude of the acceleration of the system. (c) Calculate the tension in the string.
In the Atwood machine shown in Fig. 4-6, if M = 0.60 kg and m = 0.40 kg. Ignore friction and the mass of the pulley.
(a) Draw free-body diagrams for mass M and mass m.
(b) Calculate the magnitude of the acceleration of the system.
(c) Calculate the tension in the string.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
54
A block lies on a horizontal frictionless surface. A horizontal force of 100 N is applied to the block giving rise to an acceleration of 3 m/s2.
(a) Determine the mass of the block.
(b) Calculate the distance the block will travel is the force is applied for 10 s.
(c) Calculate the speed of the block after the force has been applied for 10 s.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
55
FIGURE 4-7 FIGURE 4-7   Two boxes are connected by a cord running over a pulley as shown in Fig. 4-7. Box I of mass 8.0 kg rest on the top of the table; the coefficient of kinetic friction between box I and the table is 0.10. Box II has a mass of 15.0 kg. (a) Draw the free-body diagrams for the two boxes, identifying all of the forces acting on each of the masses. (b) Calculate the acceleration of the system. (c) Calculate the tension in the cord.
Two boxes are connected by a cord running over a pulley as shown in Fig. 4-7. Box I of mass 8.0 kg rest on the top of the table; the coefficient of kinetic friction between box I and the table is 0.10. Box II has a mass of 15.0 kg.
(a) Draw the free-body diagrams for the two boxes, identifying all of the forces acting on each of the masses.
(b) Calculate the acceleration of the system.
(c) Calculate the tension in the cord.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
56
FIGURE 4-5 <strong>FIGURE 4-5   Two identical masses are attached by a light string that passes over a small pulley, as shown in Fig. 4-5. The table and the pulley are frictionless. The masses are moving</strong> A)with an acceleration less than g. B)at constant speed. C)with an acceleration greater than g. D)with an acceleration equal to g. E)with an acceleration that cannot be determined without additional information.
Two identical masses are attached by a light string that passes over a small pulley, as shown in Fig. 4-5. The table and the pulley are frictionless. The masses are moving

A)with an acceleration less than g.
B)at constant speed.
C)with an acceleration greater than g.
D)with an acceleration equal to g.
E)with an acceleration that cannot be determined without additional information.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
57
FIGURE 4-3 <strong>FIGURE 4-3   A 16-kg fish is weighed with two spring scales, each of negligible weight, as shown in Fig. 4-3. What will be the readings on the scales?</strong> A)The bottom scale will read 16 kg, and the top scale will read zero. B)The sum of the two readings will be 32 kg. C)The top scale will read 16 kg, and the bottom scale will read zero. D)Each scale will show a reading greater than zero and less than 16 kg, but the sum of the two readings will be 16 kg. E)Each scale will read 8 kg.
A 16-kg fish is weighed with two spring scales, each of negligible weight, as shown in Fig. 4-3. What will be the readings on the scales?

A)The bottom scale will read 16 kg, and the top scale will read zero.
B)The sum of the two readings will be 32 kg.
C)The top scale will read 16 kg, and the bottom scale will read zero.
D)Each scale will show a reading greater than zero and less than 16 kg, but the sum of the two readings will be 16 kg.
E)Each scale will read 8 kg.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
58
Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a constant velocity? Ff is the force of the floor on the person and Fg is the force of gravity on the person.

A)
<strong>Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a constant velocity? F<sub>f </sub>is the force of the floor on the person and F<sub>g </sub>is the force of gravity on the person.</strong> A)   B)   C)   D)   E)
B)
<strong>Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a constant velocity? F<sub>f </sub>is the force of the floor on the person and F<sub>g </sub>is the force of gravity on the person.</strong> A)   B)   C)   D)   E)
C)
<strong>Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a constant velocity? F<sub>f </sub>is the force of the floor on the person and F<sub>g </sub>is the force of gravity on the person.</strong> A)   B)   C)   D)   E)
D)
<strong>Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a constant velocity? F<sub>f </sub>is the force of the floor on the person and F<sub>g </sub>is the force of gravity on the person.</strong> A)   B)   C)   D)   E)
E)
<strong>Which of the following free-body diagrams best represent the free-body diagram, with correct relative force magnitudes, of a person in an elevator that is traveling upward with a constant velocity? F<sub>f </sub>is the force of the floor on the person and F<sub>g </sub>is the force of gravity on the person.</strong> A)   B)   C)   D)   E)
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
59
FIGURE 4-2 <strong>FIGURE 4-2   Compare the two situations shown in Fig. 4-2. On the left (A), James is holding the rope and keeping the bucket at rest. On the right (B), James ties the rope to the bucket so that it keeps the bucket at rest. In both cases the bucket contains the same quantity of water. In what case is the tension in the rope lower?</strong> A)right B)left C)It is the same in both cases. D)need more data to answer
Compare the two situations shown in Fig. 4-2. On the left (A), James is holding the rope and keeping the bucket at rest. On the right (B), James ties the rope to the bucket so that it keeps the bucket at rest. In both cases the bucket contains the same quantity of water. In what case is the tension in the rope lower?

A)right
B)left
C)It is the same in both cases.
D)need more data to answer
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
60
A student pulls a box of books on a smooth horizontal floor with a force of 100 N in a direction of 37.0° above the horizontal. The mass of the box and the books is 40.0 kg.
(a) Draw the free-body diagram for the box.
(b) Calculate the acceleration of the box.
(c) Calculate the normal force acting on the box.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
61
A 1000-kg car is driving toward the north along a straight road at a speed of 20.0 m/s. The driver applies the brakes and the car comes to a rest in a distance of 140 m. What is the constant force applied to the car to bring it to rest?

A)1.43 N north
B)7.00 × 103 N south
C)1.43 × 103 N south
D)1.43 N south
E)143 N south
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
62
FIGURE 4-8 <strong>FIGURE 4-8   The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?</strong> A)7.0 N   + 2.0 N   B)1.0 N   - 5.0 N   C)3.0 N   + 4.0 N   D)-1.0 N   + 5.0 N   E)3.0 N   - 4.0 N
The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?

A)7.0 N <strong>FIGURE 4-8   The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?</strong> A)7.0 N   + 2.0 N   B)1.0 N   - 5.0 N   C)3.0 N   + 4.0 N   D)-1.0 N   + 5.0 N   E)3.0 N   - 4.0 N   + 2.0 N
<strong>FIGURE 4-8   The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?</strong> A)7.0 N   + 2.0 N   B)1.0 N   - 5.0 N   C)3.0 N   + 4.0 N   D)-1.0 N   + 5.0 N   E)3.0 N   - 4.0 N
B)1.0 N <strong>FIGURE 4-8   The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?</strong> A)7.0 N   + 2.0 N   B)1.0 N   - 5.0 N   C)3.0 N   + 4.0 N   D)-1.0 N   + 5.0 N   E)3.0 N   - 4.0 N   - 5.0 N
<strong>FIGURE 4-8   The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?</strong> A)7.0 N   + 2.0 N   B)1.0 N   - 5.0 N   C)3.0 N   + 4.0 N   D)-1.0 N   + 5.0 N   E)3.0 N   - 4.0 N
C)3.0 N <strong>FIGURE 4-8   The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?</strong> A)7.0 N   + 2.0 N   B)1.0 N   - 5.0 N   C)3.0 N   + 4.0 N   D)-1.0 N   + 5.0 N   E)3.0 N   - 4.0 N   + 4.0 N
<strong>FIGURE 4-8   The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?</strong> A)7.0 N   + 2.0 N   B)1.0 N   - 5.0 N   C)3.0 N   + 4.0 N   D)-1.0 N   + 5.0 N   E)3.0 N   - 4.0 N
D)-1.0 N <strong>FIGURE 4-8   The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?</strong> A)7.0 N   + 2.0 N   B)1.0 N   - 5.0 N   C)3.0 N   + 4.0 N   D)-1.0 N   + 5.0 N   E)3.0 N   - 4.0 N   + 5.0 N
<strong>FIGURE 4-8   The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?</strong> A)7.0 N   + 2.0 N   B)1.0 N   - 5.0 N   C)3.0 N   + 4.0 N   D)-1.0 N   + 5.0 N   E)3.0 N   - 4.0 N
E)3.0 N <strong>FIGURE 4-8   The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?</strong> A)7.0 N   + 2.0 N   B)1.0 N   - 5.0 N   C)3.0 N   + 4.0 N   D)-1.0 N   + 5.0 N   E)3.0 N   - 4.0 N   - 4.0 N
<strong>FIGURE 4-8   The three forces represented in Fig. 4-8 act on an object. What fourth force must act on the object so that the object does not accelerate?</strong> A)7.0 N   + 2.0 N   B)1.0 N   - 5.0 N   C)3.0 N   + 4.0 N   D)-1.0 N   + 5.0 N   E)3.0 N   - 4.0 N
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
63
A 2.00-kg object moves with constant velocity 3.00 m/s toward the east. Two forces act on the object. The first is a 40.0 N force toward the west. What is the second force that acts on the object?

A)23.0 N east
B)40.0 N east
C)26.7 N east
D)46.0 N east
E)46.0 N west
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
64
Three boxes rest side-by-side on a smooth, horizontal floor. Their masses are 5.0-kg, 3.0-kg, and 2.0-kg, with the 3.0-kg mass in the center. A force of 50 N pushes on the 5.0-kg mass, which pushes against the other two masses.
(a) Draw the free-body diagrams for each of the masses.
(b) What is the contact force between the 5.0-kg mass and the 3.0-kg mass?
(c) What is the contact force between the 3.0-kg and the 2.0-kg mass?
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
65
Two objects push on each other. The first object has a mass 30.0 kg and it accelerates at 2.00 m/s2 toward the east. The second object has a mass 7.00 kg. If no other forces are acting on the objects, what is the acceleration of the second object?

A)4.67 m/s2 west
B)1.14 m/s2 east
C)2.00 m/s2 west
D)8.57 m/s2 west
E)4.67 m/s2 east
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
66
Starting from rest, a 4.0-kg body reaches a speed of 8.0 m/s in 2.0 s. What is the net force acting on the body?

A)2.0 N
B)4.0 N
C)8.0 N
D)16 N
E)32 N
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
67
Object A is acted on by only object B. The mass of object A is 20.0 kg and its acceleration is 4.00 m/s2 west. Object B is acted on by two forces, the force of object A on object B and another unknown force. If mass of object B is 40.0 kg and the acceleration of object B is 3.00 m/s2 west, what is the unknown force?

A)40 N west
B)120 N west
C)80 N east
D)200 N west
E)80 N west
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
68
FIGURE 4-10 <strong>FIGURE 4-10   The three forces represented in Fig. 4-10 act on an object. What is the direction of the acceleration of the object?</strong> A)11.3° clockwise from the -x-axis B)11.3° counterclockwise from the +y-axis C)78.7° counterclockwise from the +x-axis D)11.3° clockwise from the +y-axis E)The mass of the object must be known to answer the question.
The three forces represented in Fig. 4-10 act on an object. What is the direction of the acceleration of the object?

A)11.3° clockwise from the -x-axis
B)11.3° counterclockwise from the +y-axis
C)78.7° counterclockwise from the +x-axis
D)11.3° clockwise from the +y-axis
E)The mass of the object must be known to answer the question.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
69
Two forces act on a 4.00-kg object in a manner that the object has an acceleration 3.00 m/s2 in a direction 20.0° north of east. The first force is 15.00 N in a direction 10.0° west of north. What is the second force?

A)14.6 N in a direction 28.1° south of east
B)12.9 N in a direction 28.1° south of east
C)16.2 N in a direction 30.2° south of east
D)18.8 N in a direction 41.1° south of east
E)17.5 N in a direction 37.5° south of east
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
70
The following four forces act on a 4.00 kg object: F1 = 300 N east
F2 = 700 N north
F3 = 500 N west
F4 = 600 N south
What is the acceleration of the object?

A)224 N in a direction 63.4° north of west
B)300 N in a direction 63.4° north of west
C)300 N in a direction 26.6° north of west
D)224 N in a direction 26.6° north of west
E)2100 N in a direction 26.6° north of west
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
71
A person has a mass of 45 kg. How much does she weigh on the Moon, where g = 1.62 m/ s2?

A)45 N
B)73 N
C)7.4 N
D)220 N
E)440 N
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
72
An astronaut weighs 99.0 N on the Moon, where the acceleration of gravity is 1.62 m/ s2. How much does she weigh on Earth?

A)16.2 N
B)61.0 N
C)99.0 N
D)600 N
E)440 N
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
73
FIGURE 4-11 <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)
The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?

A)(6.0 N sin 28° - 5.0 N sin 22°) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   + (6.0 N cos 28° + 5.0 N cos 22°) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   = (8.00 kg) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)
B)(6.0 N cos 28° + 5.0 N cos 22°) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   + (6.0 N sin 28° + 5.0 N sin 22°) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   = (8.00 kg) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)
C)(6.0 N cos 28° - 5.0 N sin 22°) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   + (6.0 N sin 28° + 5.0 N cos 22°) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   = (8.00 kg) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)
D)(6.0 N cos 28° - 5.0 N cos 22°) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   + (6.0 N sin 28° + 5.0 N sin 22°) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   = (8.00 kg) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)
E)(6.0 N cos 28° + 5.0 N sin 22°) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   + (6.0 N sin 28° - 5.0 N cos 22°) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)   = (8.00 kg) <strong>FIGURE 4-11   The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?</strong> A)(6.0 N sin 28° - 5.0 N sin 22°)   + (6.0 N cos 28° + 5.0 N cos 22°)   = (8.00 kg)   B)(6.0 N cos 28° + 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   C)(6.0 N cos 28° - 5.0 N sin 22°)   + (6.0 N sin 28° + 5.0 N cos 22°)   = (8.00 kg)   D)(6.0 N cos 28° - 5.0 N cos 22°)   + (6.0 N sin 28° + 5.0 N sin 22°)   = (8.00 kg)   E)(6.0 N cos 28° + 5.0 N sin 22°)   + (6.0 N sin 28° - 5.0 N cos 22°)   = (8.00 kg)
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
74
A 1.0-kg object is moving with a constant velocity 2.0 m/s toward the north. There are two forces acting on the object. One of the forces is 2.0 N north. The other force is ________

A)1.0 N north.
B)3.0 N north.
C)2.0 N south.
D)2.0 N north.
E)0.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
75
A 1200-kg car starts from rest and accelerates with constant acceleration, traveling 200 m in 9.00 s. What is the force of the road on the car during this acceleration?

A)1.43 kN
B)3.87 kN
C)5.93 kN
D)4.82 kN
E)11.8 kN
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
76
The International Space Station has a mass 1.8 × 105 kg. A 70.0-kg astronaut inside the station pushes off one wall of the station so she accelerates at 1.50 m/s2. What is the magnitude of the acceleration of the space station as the astronaut is pushing off the wall relative to an observer initially at rest relative to the space station before the push?

A)5.8 × 10-4 m/s2
B)1.50 m/s2
C)4.7 × 10-4 m/s2
D)zero
E)3.9 × 10-3 m/s2
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
77
A 5.00-kg object is initially at rest. The object is acted on by a 9.00-N force toward the east for 3.00 s. No force acts on the object for the next 4.00 s. How far has the object moved during this 7.00 s interval?

A)8.10 m
B)29.7 m
C)53.6 m
D)21.7 m
E)16.2 m
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
78
FIGURE 4-9 <strong>FIGURE 4-9   The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?</strong> A)(1.67 m/s<sup>2</sup>)   - (0.333 m/s<sup>2</sup>)   B)(5.00 m/s<sup>2</sup>)   + (1.00 m/s<sup>2</sup>)   C)(1.67 m/s<sup>2</sup>)   + (2.333 m/s<sup>2</sup>)   D)(15.0 m/s<sup>2</sup>)   + (3.00 m/s<sup>2</sup>)   E)(1.67 m/s<sup>2</sup>)   + (0.333 m/s<sup>2</sup>)
The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?

A)(1.67 m/s2) <strong>FIGURE 4-9   The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?</strong> A)(1.67 m/s<sup>2</sup>)   - (0.333 m/s<sup>2</sup>)   B)(5.00 m/s<sup>2</sup>)   + (1.00 m/s<sup>2</sup>)   C)(1.67 m/s<sup>2</sup>)   + (2.333 m/s<sup>2</sup>)   D)(15.0 m/s<sup>2</sup>)   + (3.00 m/s<sup>2</sup>)   E)(1.67 m/s<sup>2</sup>)   + (0.333 m/s<sup>2</sup>)   - (0.333 m/s2) <strong>FIGURE 4-9   The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?</strong> A)(1.67 m/s<sup>2</sup>)   - (0.333 m/s<sup>2</sup>)   B)(5.00 m/s<sup>2</sup>)   + (1.00 m/s<sup>2</sup>)   C)(1.67 m/s<sup>2</sup>)   + (2.333 m/s<sup>2</sup>)   D)(15.0 m/s<sup>2</sup>)   + (3.00 m/s<sup>2</sup>)   E)(1.67 m/s<sup>2</sup>)   + (0.333 m/s<sup>2</sup>)
B)(5.00 m/s2) <strong>FIGURE 4-9   The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?</strong> A)(1.67 m/s<sup>2</sup>)   - (0.333 m/s<sup>2</sup>)   B)(5.00 m/s<sup>2</sup>)   + (1.00 m/s<sup>2</sup>)   C)(1.67 m/s<sup>2</sup>)   + (2.333 m/s<sup>2</sup>)   D)(15.0 m/s<sup>2</sup>)   + (3.00 m/s<sup>2</sup>)   E)(1.67 m/s<sup>2</sup>)   + (0.333 m/s<sup>2</sup>)   + (1.00 m/s2) <strong>FIGURE 4-9   The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?</strong> A)(1.67 m/s<sup>2</sup>)   - (0.333 m/s<sup>2</sup>)   B)(5.00 m/s<sup>2</sup>)   + (1.00 m/s<sup>2</sup>)   C)(1.67 m/s<sup>2</sup>)   + (2.333 m/s<sup>2</sup>)   D)(15.0 m/s<sup>2</sup>)   + (3.00 m/s<sup>2</sup>)   E)(1.67 m/s<sup>2</sup>)   + (0.333 m/s<sup>2</sup>)
C)(1.67 m/s2) <strong>FIGURE 4-9   The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?</strong> A)(1.67 m/s<sup>2</sup>)   - (0.333 m/s<sup>2</sup>)   B)(5.00 m/s<sup>2</sup>)   + (1.00 m/s<sup>2</sup>)   C)(1.67 m/s<sup>2</sup>)   + (2.333 m/s<sup>2</sup>)   D)(15.0 m/s<sup>2</sup>)   + (3.00 m/s<sup>2</sup>)   E)(1.67 m/s<sup>2</sup>)   + (0.333 m/s<sup>2</sup>)   + (2.333 m/s2) <strong>FIGURE 4-9   The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?</strong> A)(1.67 m/s<sup>2</sup>)   - (0.333 m/s<sup>2</sup>)   B)(5.00 m/s<sup>2</sup>)   + (1.00 m/s<sup>2</sup>)   C)(1.67 m/s<sup>2</sup>)   + (2.333 m/s<sup>2</sup>)   D)(15.0 m/s<sup>2</sup>)   + (3.00 m/s<sup>2</sup>)   E)(1.67 m/s<sup>2</sup>)   + (0.333 m/s<sup>2</sup>)
D)(15.0 m/s2) <strong>FIGURE 4-9   The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?</strong> A)(1.67 m/s<sup>2</sup>)   - (0.333 m/s<sup>2</sup>)   B)(5.00 m/s<sup>2</sup>)   + (1.00 m/s<sup>2</sup>)   C)(1.67 m/s<sup>2</sup>)   + (2.333 m/s<sup>2</sup>)   D)(15.0 m/s<sup>2</sup>)   + (3.00 m/s<sup>2</sup>)   E)(1.67 m/s<sup>2</sup>)   + (0.333 m/s<sup>2</sup>)   + (3.00 m/s2) <strong>FIGURE 4-9   The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?</strong> A)(1.67 m/s<sup>2</sup>)   - (0.333 m/s<sup>2</sup>)   B)(5.00 m/s<sup>2</sup>)   + (1.00 m/s<sup>2</sup>)   C)(1.67 m/s<sup>2</sup>)   + (2.333 m/s<sup>2</sup>)   D)(15.0 m/s<sup>2</sup>)   + (3.00 m/s<sup>2</sup>)   E)(1.67 m/s<sup>2</sup>)   + (0.333 m/s<sup>2</sup>)
E)(1.67 m/s2) <strong>FIGURE 4-9   The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?</strong> A)(1.67 m/s<sup>2</sup>)   - (0.333 m/s<sup>2</sup>)   B)(5.00 m/s<sup>2</sup>)   + (1.00 m/s<sup>2</sup>)   C)(1.67 m/s<sup>2</sup>)   + (2.333 m/s<sup>2</sup>)   D)(15.0 m/s<sup>2</sup>)   + (3.00 m/s<sup>2</sup>)   E)(1.67 m/s<sup>2</sup>)   + (0.333 m/s<sup>2</sup>)   + (0.333 m/s2) <strong>FIGURE 4-9   The two forces indicated in Fig. 4-9 act on a 3.00-kg object. What is the acceleration of the object?</strong> A)(1.67 m/s<sup>2</sup>)   - (0.333 m/s<sup>2</sup>)   B)(5.00 m/s<sup>2</sup>)   + (1.00 m/s<sup>2</sup>)   C)(1.67 m/s<sup>2</sup>)   + (2.333 m/s<sup>2</sup>)   D)(15.0 m/s<sup>2</sup>)   + (3.00 m/s<sup>2</sup>)   E)(1.67 m/s<sup>2</sup>)   + (0.333 m/s<sup>2</sup>)
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
79
A 7.0-kg object is acted on by two forces. One of the forces is 10.0 N acting toward the east. Which of the following forces is the other force if the acceleration of the object is 1.0 m/ s2 toward the east?

A)6.0 N east
B)3.0 N west
C)12.0 N east
D)9.0 N west
E)7.0 N west
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
80
A force of 120 N is applied to an object whose mass is 30 kg. The object's acceleration is

A)3600 m/ s2.
B)150 m/ s2.
C)4.0 m/ s2.
D)2.0 m/ s2.
E)0.25 m/ s2.
Unlock Deck
Unlock for access to all 86 flashcards in this deck.
Unlock Deck
k this deck
locked card icon
Unlock Deck
Unlock for access to all 86 flashcards in this deck.