Deck 14: Oxidation and Reduction

Full screen (f)
exit full mode
Question
Given:
Li + Hg2I2 → 2LiI + 2Hg
The equation is a balanced reaction.
Refer to the reaction below for True/False Questions 13-14.
Given:
Fe + MnO4 \rightarrow Fe3+ + Mn
Use Space or
up arrow
down arrow
to flip the card.
Question
When an oxidation number of an atom is increased in the course of a redox reaction, that atom is being reduced.
Question
Given:
Mo2+ + Br2 → Mo3+ + 2Br
The equation is a balanced reaction.
Question
The phosphorous atom in H3PO4 is assigned an oxidation number of +5.
Question
The fluorine atom in HF is assigned an oxidation number of +1.
Question
If the reaction is taking place in an acidic solution, 6 moles of H2O are required on the product side to balance the equation.
Question
The sodium atom in NaOH is assigned an oxidation number of +1.
Question
If the reaction is taking place in a basic solution the balanced equation of the reaction is
7Fe + 3MnO4 \rightarrow 7Fe3+ + 3Mn + 24OH+ 12H2O.
Question
When an oxidation number of an atom is decreased in the course of a redox reaction, that atom is being oxidized.
Question
The calcium atom in Ca3(PO4)2 is assigned an oxidation number of +3.
Question
Given:
O2 + 2H2O + I2 → 4OH + 2I
The equation is a balanced reaction.
Question
The oxygen atom in O2 is assigned an oxidation number of -1.
Question
Given:
Ru2S3 + O2 → Ru2O3 + S
The coefficient of Ru2S3 is 2 in the balanced chemical equation.
Question
The value of E1/2 for the half reaction O2 + 4H+ + 4e → 2H2O is 1.23 V.
Question
Given:
Na + I2 → NaI
The coefficient of Na is 2 in the balanced chemical equation.
Question
Atoms in their elemental state are assigned an oxidation number of 0.
Question
Given:
Be + 2H+ → Be2+ + H2
The equation is a balanced reaction.
Question
The voltage of a voltaic cell based on the reaction O2 + 4H+ + 4Cl→ 2H2O + 2Cl2 is 0.15 V.
Question
The value of E1/2 for the half reaction Mn2+ + 4H2O → MnO4 + 8H+ + 5e is 1.51 V.
Question
The reaction taking place in the voltaic cell Ag+ + Fe2+ → Ag + Fe3+ is a nonspontaneous reaction.
Question
The oxidation number of the hydrogen atom in InH3 is _____.

A) +2
B) -2
C) -1
D) 0
E) -3
Refer to the reaction below for 33-34.
Given:
2RbOH + H2SO4 \rightarrow Rb2SO4 + 2H2O
Question
The reaction taking place in the voltaic cell Pb2+ + H2 → Pb + 2H+ is a spontaneous reaction.
Question
The half reaction for the electrolysis of elemental bromine is 2Br → Br2 + 2e.
Question
The oxidation number for the calcium atom in Ca3(PO4)2 is _____.

A) +4
B) +3
C) -3
D) +2
E) +6
Question
What happens to the H atom?

A) Oxidation number increases from -1 to +1
B) Oxidation number decreases from +1 to 0
C) Oxidation number remains the same at +1
D) Oxidation number decreases from -1 to 0
E) Oxidation number remains the same at +2
Refer to the reaction below for 41-43.
Given:
Mg + O2 \rightarrow MgO
Question
What happens to the oxidation number of the S atom?

A) The oxidation number remains the same at +2.
B) The oxidation number changes from 0 to +2.
C) The oxidation number remains the same at +6.
D) The oxidation number changes from -2 to +2.
E) The oxidation number remains the same at +4.
Question
Given: NH3 + HCl \rightarrow NH4Cl
Which of the following is taking place in the reaction?

A) The oxidation number of the hydrogen atom increases from +3 to +4; so it is being oxidized.
B) The oxidation number of the chlorine atom decreases from 0 to +1; so it is being oxidized.
C) The oxidation number of the chlorine atom decreases from +1 to 0; so it is being reduced.
D) The oxidation number of the nitrogen atom increases from -3 to +4, so it is being oxidized.
E) The oxidation number of the nitrogen atom remains the same at -3.
Question
What happens to the oxidation number of the Rb atom?

A) The oxidation number remains the same at -2.
B) The oxidation number changes from 0 to +1.
C) The oxidation number remains the same at +1.
D) The oxidation number changes from -2 to +1.
E) The oxidation number changes from -1 to +2.
Question
Given: Fe + I2 → FeI2
Identify what is being oxidized and reduced in this redox reaction.

A) Oxidation numbers of all the atoms remain the same.
B) Fe is being reduced from 0 to -2; I is being oxidized from -1 to 0.
C) Fe is being oxidized from 0 to +1; I is being reduced from +2 to 0.
D) Fe is being reduced from 0 to -1; I is being oxidized from 0 to +2.
E) Fe is being oxidized from 0 to +2; I is being reduced from 0 to -1.
Question
If the voltage of the voltaic cell based on the reaction Cu2+ + 2I → I2 + Cu is 0.88 V, the standard reduction potential of the Cu2+ + 2e → Cu half-cell is 0.54 V.
Question
The half reaction for the electrolysis of elemental chlorine is Cl2+ + 2e → Cl2.
Question
Atoms in their elemental state are assigned an oxidation number of _____.

A) 1
B) 2
C) -2
D) 3
E) 0
Question
Given: 6H++ 2MnO4 + 5H2O2 → 2Mn+2 + 5O2 + 8H2O
Identify what is being oxidized and reduced in this redox reaction.

A) Oxidation numbers of all the atoms remain the same.
B) H is being oxidized from +6 to +8; Mn stays the same.
C) O is being oxidized from -1 to 0; Mn is being reduced from +7 to +2.
D) Mn is being oxidized from -4 to -2; O is being reduced from +6 to +5.
E) H is being oxidized from +6 to +5; Mn is being reduced from +1 to -2.
Question
The oxidation number for the fluorine atom in CaF2 is ____.

A) 0
B) -3
C) -1
D) +2
E) -2
Question
If the voltage of the voltaic cell 6I + 2NO3 + 8H+ + 6e → 2NO + 4H2O + 3I2 is 1.50 V, the standard reduction potential of the NO3 + 4H+ + 3e → NO + 2H2O half-cell reaction is -0.96 V.
Question
The oxidation number for the chlorine atom in Cl2 is _____.

A) 0
B) +3
C) +1
D) +2
E) -2
Question
Redox reactions require _____ to keep track of electrons assigned to each atom in a chemical reaction.

A) mass numbers
B) oxidation numbers
C) number of neutrons
D) magnetic quantum numbers
E) spin quantum numbers
Question
The oxidation number for the oxygen atom in BaO2 is ____.

A) -3
B) -1
C) -2
D) +2
E) 0
Question
Given: HCN + NaOH \rightarrow NaCN + H2O
Which of the following is taking place in the reaction?

A) The oxidation numbers of all the atoms remain the same.
B) The oxidation number of the nitrogen atom increases from +3 to +4.
C) The oxidation number of the nitrogen atom decreases from +4 to +3.
D) The oxidation number of the hydrogen atom decreases from +2 to +1.
E) The oxidation number of the carbon atom increases from +2 to +3.
Refer to the reaction below for 39-40.
Given:
2CH4 + 3O2 \rightarrow 2CO + 4H2O
Question
C is being _____.

A) oxidized from +3 to +4
B) oxidized from -4 to +2
C) reduced from +4 to -2
D) reduced from -1 to -2
E) reduced from -1 to -3
Question
The coefficient of O2 after balancing the equation is _____.

A) 1
B) 2
C) 5
D) 3
E) 4
Question
The coefficient of Sr after balancing the equation is _____.

A) 1
B) 5
C) 3
D) 2
E) 4
Question
The coefficient of F2 after balancing the equation is _____.

A) 1
B) 5
C) 3
D) 2
E) 4
Question
The coefficient of PI3 after balancing the equation is _____.

A) 3
B) 5
C) 6
D) 2
E) 4
Question
The coefficient of Mg after balancing the equation is _____.

A) 1
B) 2
C) 5
D) 3
E) 4
Question
If the reaction is taking place in an acidic solution, what is the number of moles of water required on the product or reactant side to balance the redox reaction?

A) 14 moles of H2O on the reactant side
B) 14 mole2 of H2O on the product side
C) No moles of H2O
D) 7 moles of H2O on the reactant side
E) 7 moles of H2O on the product side
Question
The coefficient of H+ after balancing the equation is _____.

A) 1
B) 5
C) 3
D) 2
E) 4
Question
The coefficient of P2O5 after balancing the equation is _____.

A) 3
B) 5
C) 6
D) 2
E) 4
Question
The coefficient of MgO after balancing the equation is _____.

A) 1
B) 2
C) 5
D) 3
E) 4
Refer to the reaction below for 44-47.
Given:
P2O5 + I2 → PI3 + O2
Question
The coefficient of O2 after balancing the equation is _____.

A) 3
B) 5
C) 6
D) 2
E) 4
Refer to the reaction below for 48-51.
Given:
Sr + H+→ Sr2+ + H2
Question
If the reaction is taking place in a basic solution, what is the number of moles of water required on the product or reactant side to balance the redox reaction?

A) 7 moles of H2O on the reactant side
B) 7 moles of H2O on the product side
C) 14 moles of H2O on the reactant side
D) No moles of H2O
E) 14 moles of H2O on the product side
Question
The coefficient of Cl2 after balancing the equation is _____.

A) 2
B) 5
C) 3
D) 1
E) 4
Question
The coefficient of Sr2+ after balancing the equation is _____.

A) 1
B) 5
C) 3
D) 2
E) 4
Question
The coefficient of Au after balancing the equation is _____.

A) 1
B) 5
C) 3
D) 2
E) 4
Question
The coefficient of Au+ after balancing the equation is _____.

A) 1
B) 5
C) 3
D) 2
E) 4
Question
The coefficient of H2 after balancing the equation is _____.

A) 1
B) 5
C) 3
D) 2
E) 4
Refer to the reaction below for 52-54.
Given:
Au+ → Au + Au3+ (Hint: both half reactions will start with the same reactant.)
Question
The coefficient of Cl after balancing the equation is _____.

A) 1
B) 5
C) 3
D) 2
E) 4
Question
The coefficient of Au3+ after balancing the equation is _____.

A) 1
B) 5
C) 3
D) 2
E) 4
Refer to the reaction below for 55-58.
Given:
Cl + F2 → F + Cl2
Question
The coefficient of F after balancing the equation is _____.

A) 1
B) 2
C) 5
D) 3
E) 4
Refer to the reaction below for 59-62.
Given:
Cr2O72− + Fe → Cr3+ + Fe3+
Question
The coefficient of I2 after balancing the equation is _____.

A) 3
B) 5
C) 6
D) 2
E) 4
Question
What is the half reaction for the electrolysis of elemental nickel?

A) Ni2+ + 2e → Ni
B) Ni+ + e → Ni
C) Ni3++ 3e →Ni
D) Ni2 + 2e → 2Ni
E) 2Ni+ + 2e → Ni2
Question
What is the E of a voltaic cell based on this reaction? F2 + Pb → 2F- + Pb2+

A) 2.74 V
B) 22.7 V
C) 2.99 V
D) 0.362 V
E) 5.49 V
Question
Atoms in monatomic (i.e., one-atom) ions are assigned an oxidation number equal to their charge. Oxidation numbers are usually written with the sign first, then the magnitude, to differentiate them from charges.
Question
Briefly describe the method of balancing a redox reaction by the half reaction method.
Question
What is the E of a voltaic cell based on this reaction? MnO4 + 6H+ + H2 → Mn2+ + 4H2O

A) -1.10 V
B) +1.10 V
C) +1.51 V
D) +3.68 V
E) +1.23 V
Question
Briefly describe the rules required for assigning oxidation numbers.
Question
What is the half reaction for the electrolysis of elemental iodine?

A) I2 → 2I+ 2e
B) I2+ + 2e → I
C) 2I → I2 + 2e
D) 2I+ + 2e → I2
E) I2 + 2e → 2I
Question
Briefly enumerate the steps involved in balancing a redox reaction with an example. Assume a basic solution.
Question
Briefly describe the method of balancing a redox reaction by inspection.
Question
What is the E of a voltaic cell based on this reaction? 2Mn2+ + 8H2O + 5Sn4+ → 2MnO4- + 16H+ + 5Sn2+

A) -10.1 V
B) -1.36 V
C) +10.1 V
D) +0.227 V
E) +1.81 V
Question
If the reaction is taking place in a basic solution, the balanced equation is:

A) 14H2O + 2Cr2O72− + 2Fe \rightarrow 2Cr3+ + 14OH + 4Fe3+.
B) 14H2O + Cr2O72− + 5Fe \rightarrow 2Cr3+ + 14OH + 5Fe3+.
C) 7H2O + Cr2O72− + 2Fe \rightarrow 2Cr3+ + 14OH + 2Fe3+.
D) H2O + Cr2O72− + Fe \rightarrow Cr3+ + OH + Fe3+.
E) 7H2O + 7Cr2O72− + 7Fe \rightarrow 7Cr3+ + 14OH + 7Fe3+.
Refer to the Table 14.1 for 63-67.
Question
If the reaction is taking place in an acidic solution, the balanced equation is:

A) 2Fe + 14H+ + 2Cr2O72− → 2Fe3+ + 2Cr3+ + 2H2O.
B) Fe + H+ + Cr2O72− → Fe3+ + Cr3+ + H2O.
C) 2Fe + 14H+ + Cr2O72− → 4Fe3+ + 2Cr3+ + 28H2O.
D) 2Fe + 14H+ + Cr2O72− → 2Fe3+ + 2Cr3+ + 7H2O.
E) 4Fe + 10H+ + Cr2O72− → 3Fe3+ + Cr3+ + 7H2O.
Question
What is the E of a voltaic cell based on this reaction? 2Ce4+ + Ni → 2Ce3+ + Ni2+

A) 2.36 V
B) 2.11 V
C) 6.44 V
D) 0.403 V
E) 1.86 V
Question
Describe a voltaic cell.
Question
In compounds, fluorine is assigned a −1 oxidation number; oxygen is usually assigned a −2 oxidation number [except in peroxide compounds (where it is −1) and in binary compounds with fluorine (where it is positive)]; and hydrogen is usually assigned a +1 oxidation number [except when it exists as the hydride ion (H), in which case rule 2 prevails].
Question
In compounds, all other atoms are assigned an oxidation number so that the sum of the oxidation numbers on all the atoms in the species equals the charge on the species (which is zero if the species is neutral).
Question
What is the half reaction for the electrolysis of elemental fluorine?

A) F2+ + 2e → F
B) F+ + e → F
C) F3++ 3e →F
D) F2 → 2F + 2e
E) 2F \rightarrow F2 + 2e
Question
Define oxidation, reduction, and oxidation-reduction reactions.
Question
What is the E of a voltaic cell based on this reaction? NO3 + 4H+ + Fe2+ → NO + 2H2O + Fe3+

A) +0.21 V
B) +0.77 V
C) -0.77 V
D) -0.73 V
E) +0.35 V
Question
Atoms in their elemental state are assigned an oxidation number of 0.
Unlock Deck
Sign up to unlock the cards in this deck!
Unlock Deck
Unlock Deck
1/104
auto play flashcards
Play
simple tutorial
Full screen (f)
exit full mode
Deck 14: Oxidation and Reduction
1
Given:
Li + Hg2I2 → 2LiI + 2Hg
The equation is a balanced reaction.
Refer to the reaction below for True/False Questions 13-14.
Given:
Fe + MnO4 \rightarrow Fe3+ + Mn
False
2
When an oxidation number of an atom is increased in the course of a redox reaction, that atom is being reduced.
False
3
Given:
Mo2+ + Br2 → Mo3+ + 2Br
The equation is a balanced reaction.
False
4
The phosphorous atom in H3PO4 is assigned an oxidation number of +5.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
5
The fluorine atom in HF is assigned an oxidation number of +1.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
6
If the reaction is taking place in an acidic solution, 6 moles of H2O are required on the product side to balance the equation.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
7
The sodium atom in NaOH is assigned an oxidation number of +1.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
8
If the reaction is taking place in a basic solution the balanced equation of the reaction is
7Fe + 3MnO4 \rightarrow 7Fe3+ + 3Mn + 24OH+ 12H2O.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
9
When an oxidation number of an atom is decreased in the course of a redox reaction, that atom is being oxidized.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
10
The calcium atom in Ca3(PO4)2 is assigned an oxidation number of +3.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
11
Given:
O2 + 2H2O + I2 → 4OH + 2I
The equation is a balanced reaction.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
12
The oxygen atom in O2 is assigned an oxidation number of -1.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
13
Given:
Ru2S3 + O2 → Ru2O3 + S
The coefficient of Ru2S3 is 2 in the balanced chemical equation.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
14
The value of E1/2 for the half reaction O2 + 4H+ + 4e → 2H2O is 1.23 V.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
15
Given:
Na + I2 → NaI
The coefficient of Na is 2 in the balanced chemical equation.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
16
Atoms in their elemental state are assigned an oxidation number of 0.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
17
Given:
Be + 2H+ → Be2+ + H2
The equation is a balanced reaction.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
18
The voltage of a voltaic cell based on the reaction O2 + 4H+ + 4Cl→ 2H2O + 2Cl2 is 0.15 V.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
19
The value of E1/2 for the half reaction Mn2+ + 4H2O → MnO4 + 8H+ + 5e is 1.51 V.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
20
The reaction taking place in the voltaic cell Ag+ + Fe2+ → Ag + Fe3+ is a nonspontaneous reaction.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
21
The oxidation number of the hydrogen atom in InH3 is _____.

A) +2
B) -2
C) -1
D) 0
E) -3
Refer to the reaction below for 33-34.
Given:
2RbOH + H2SO4 \rightarrow Rb2SO4 + 2H2O
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
22
The reaction taking place in the voltaic cell Pb2+ + H2 → Pb + 2H+ is a spontaneous reaction.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
23
The half reaction for the electrolysis of elemental bromine is 2Br → Br2 + 2e.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
24
The oxidation number for the calcium atom in Ca3(PO4)2 is _____.

A) +4
B) +3
C) -3
D) +2
E) +6
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
25
What happens to the H atom?

A) Oxidation number increases from -1 to +1
B) Oxidation number decreases from +1 to 0
C) Oxidation number remains the same at +1
D) Oxidation number decreases from -1 to 0
E) Oxidation number remains the same at +2
Refer to the reaction below for 41-43.
Given:
Mg + O2 \rightarrow MgO
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
26
What happens to the oxidation number of the S atom?

A) The oxidation number remains the same at +2.
B) The oxidation number changes from 0 to +2.
C) The oxidation number remains the same at +6.
D) The oxidation number changes from -2 to +2.
E) The oxidation number remains the same at +4.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
27
Given: NH3 + HCl \rightarrow NH4Cl
Which of the following is taking place in the reaction?

A) The oxidation number of the hydrogen atom increases from +3 to +4; so it is being oxidized.
B) The oxidation number of the chlorine atom decreases from 0 to +1; so it is being oxidized.
C) The oxidation number of the chlorine atom decreases from +1 to 0; so it is being reduced.
D) The oxidation number of the nitrogen atom increases from -3 to +4, so it is being oxidized.
E) The oxidation number of the nitrogen atom remains the same at -3.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
28
What happens to the oxidation number of the Rb atom?

A) The oxidation number remains the same at -2.
B) The oxidation number changes from 0 to +1.
C) The oxidation number remains the same at +1.
D) The oxidation number changes from -2 to +1.
E) The oxidation number changes from -1 to +2.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
29
Given: Fe + I2 → FeI2
Identify what is being oxidized and reduced in this redox reaction.

A) Oxidation numbers of all the atoms remain the same.
B) Fe is being reduced from 0 to -2; I is being oxidized from -1 to 0.
C) Fe is being oxidized from 0 to +1; I is being reduced from +2 to 0.
D) Fe is being reduced from 0 to -1; I is being oxidized from 0 to +2.
E) Fe is being oxidized from 0 to +2; I is being reduced from 0 to -1.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
30
If the voltage of the voltaic cell based on the reaction Cu2+ + 2I → I2 + Cu is 0.88 V, the standard reduction potential of the Cu2+ + 2e → Cu half-cell is 0.54 V.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
31
The half reaction for the electrolysis of elemental chlorine is Cl2+ + 2e → Cl2.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
32
Atoms in their elemental state are assigned an oxidation number of _____.

A) 1
B) 2
C) -2
D) 3
E) 0
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
33
Given: 6H++ 2MnO4 + 5H2O2 → 2Mn+2 + 5O2 + 8H2O
Identify what is being oxidized and reduced in this redox reaction.

A) Oxidation numbers of all the atoms remain the same.
B) H is being oxidized from +6 to +8; Mn stays the same.
C) O is being oxidized from -1 to 0; Mn is being reduced from +7 to +2.
D) Mn is being oxidized from -4 to -2; O is being reduced from +6 to +5.
E) H is being oxidized from +6 to +5; Mn is being reduced from +1 to -2.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
34
The oxidation number for the fluorine atom in CaF2 is ____.

A) 0
B) -3
C) -1
D) +2
E) -2
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
35
If the voltage of the voltaic cell 6I + 2NO3 + 8H+ + 6e → 2NO + 4H2O + 3I2 is 1.50 V, the standard reduction potential of the NO3 + 4H+ + 3e → NO + 2H2O half-cell reaction is -0.96 V.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
36
The oxidation number for the chlorine atom in Cl2 is _____.

A) 0
B) +3
C) +1
D) +2
E) -2
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
37
Redox reactions require _____ to keep track of electrons assigned to each atom in a chemical reaction.

A) mass numbers
B) oxidation numbers
C) number of neutrons
D) magnetic quantum numbers
E) spin quantum numbers
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
38
The oxidation number for the oxygen atom in BaO2 is ____.

A) -3
B) -1
C) -2
D) +2
E) 0
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
39
Given: HCN + NaOH \rightarrow NaCN + H2O
Which of the following is taking place in the reaction?

A) The oxidation numbers of all the atoms remain the same.
B) The oxidation number of the nitrogen atom increases from +3 to +4.
C) The oxidation number of the nitrogen atom decreases from +4 to +3.
D) The oxidation number of the hydrogen atom decreases from +2 to +1.
E) The oxidation number of the carbon atom increases from +2 to +3.
Refer to the reaction below for 39-40.
Given:
2CH4 + 3O2 \rightarrow 2CO + 4H2O
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
40
C is being _____.

A) oxidized from +3 to +4
B) oxidized from -4 to +2
C) reduced from +4 to -2
D) reduced from -1 to -2
E) reduced from -1 to -3
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
41
The coefficient of O2 after balancing the equation is _____.

A) 1
B) 2
C) 5
D) 3
E) 4
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
42
The coefficient of Sr after balancing the equation is _____.

A) 1
B) 5
C) 3
D) 2
E) 4
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
43
The coefficient of F2 after balancing the equation is _____.

A) 1
B) 5
C) 3
D) 2
E) 4
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
44
The coefficient of PI3 after balancing the equation is _____.

A) 3
B) 5
C) 6
D) 2
E) 4
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
45
The coefficient of Mg after balancing the equation is _____.

A) 1
B) 2
C) 5
D) 3
E) 4
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
46
If the reaction is taking place in an acidic solution, what is the number of moles of water required on the product or reactant side to balance the redox reaction?

A) 14 moles of H2O on the reactant side
B) 14 mole2 of H2O on the product side
C) No moles of H2O
D) 7 moles of H2O on the reactant side
E) 7 moles of H2O on the product side
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
47
The coefficient of H+ after balancing the equation is _____.

A) 1
B) 5
C) 3
D) 2
E) 4
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
48
The coefficient of P2O5 after balancing the equation is _____.

A) 3
B) 5
C) 6
D) 2
E) 4
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
49
The coefficient of MgO after balancing the equation is _____.

A) 1
B) 2
C) 5
D) 3
E) 4
Refer to the reaction below for 44-47.
Given:
P2O5 + I2 → PI3 + O2
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
50
The coefficient of O2 after balancing the equation is _____.

A) 3
B) 5
C) 6
D) 2
E) 4
Refer to the reaction below for 48-51.
Given:
Sr + H+→ Sr2+ + H2
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
51
If the reaction is taking place in a basic solution, what is the number of moles of water required on the product or reactant side to balance the redox reaction?

A) 7 moles of H2O on the reactant side
B) 7 moles of H2O on the product side
C) 14 moles of H2O on the reactant side
D) No moles of H2O
E) 14 moles of H2O on the product side
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
52
The coefficient of Cl2 after balancing the equation is _____.

A) 2
B) 5
C) 3
D) 1
E) 4
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
53
The coefficient of Sr2+ after balancing the equation is _____.

A) 1
B) 5
C) 3
D) 2
E) 4
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
54
The coefficient of Au after balancing the equation is _____.

A) 1
B) 5
C) 3
D) 2
E) 4
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
55
The coefficient of Au+ after balancing the equation is _____.

A) 1
B) 5
C) 3
D) 2
E) 4
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
56
The coefficient of H2 after balancing the equation is _____.

A) 1
B) 5
C) 3
D) 2
E) 4
Refer to the reaction below for 52-54.
Given:
Au+ → Au + Au3+ (Hint: both half reactions will start with the same reactant.)
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
57
The coefficient of Cl after balancing the equation is _____.

A) 1
B) 5
C) 3
D) 2
E) 4
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
58
The coefficient of Au3+ after balancing the equation is _____.

A) 1
B) 5
C) 3
D) 2
E) 4
Refer to the reaction below for 55-58.
Given:
Cl + F2 → F + Cl2
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
59
The coefficient of F after balancing the equation is _____.

A) 1
B) 2
C) 5
D) 3
E) 4
Refer to the reaction below for 59-62.
Given:
Cr2O72− + Fe → Cr3+ + Fe3+
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
60
The coefficient of I2 after balancing the equation is _____.

A) 3
B) 5
C) 6
D) 2
E) 4
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
61
What is the half reaction for the electrolysis of elemental nickel?

A) Ni2+ + 2e → Ni
B) Ni+ + e → Ni
C) Ni3++ 3e →Ni
D) Ni2 + 2e → 2Ni
E) 2Ni+ + 2e → Ni2
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
62
What is the E of a voltaic cell based on this reaction? F2 + Pb → 2F- + Pb2+

A) 2.74 V
B) 22.7 V
C) 2.99 V
D) 0.362 V
E) 5.49 V
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
63
Atoms in monatomic (i.e., one-atom) ions are assigned an oxidation number equal to their charge. Oxidation numbers are usually written with the sign first, then the magnitude, to differentiate them from charges.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
64
Briefly describe the method of balancing a redox reaction by the half reaction method.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
65
What is the E of a voltaic cell based on this reaction? MnO4 + 6H+ + H2 → Mn2+ + 4H2O

A) -1.10 V
B) +1.10 V
C) +1.51 V
D) +3.68 V
E) +1.23 V
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
66
Briefly describe the rules required for assigning oxidation numbers.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
67
What is the half reaction for the electrolysis of elemental iodine?

A) I2 → 2I+ 2e
B) I2+ + 2e → I
C) 2I → I2 + 2e
D) 2I+ + 2e → I2
E) I2 + 2e → 2I
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
68
Briefly enumerate the steps involved in balancing a redox reaction with an example. Assume a basic solution.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
69
Briefly describe the method of balancing a redox reaction by inspection.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
70
What is the E of a voltaic cell based on this reaction? 2Mn2+ + 8H2O + 5Sn4+ → 2MnO4- + 16H+ + 5Sn2+

A) -10.1 V
B) -1.36 V
C) +10.1 V
D) +0.227 V
E) +1.81 V
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
71
If the reaction is taking place in a basic solution, the balanced equation is:

A) 14H2O + 2Cr2O72− + 2Fe \rightarrow 2Cr3+ + 14OH + 4Fe3+.
B) 14H2O + Cr2O72− + 5Fe \rightarrow 2Cr3+ + 14OH + 5Fe3+.
C) 7H2O + Cr2O72− + 2Fe \rightarrow 2Cr3+ + 14OH + 2Fe3+.
D) H2O + Cr2O72− + Fe \rightarrow Cr3+ + OH + Fe3+.
E) 7H2O + 7Cr2O72− + 7Fe \rightarrow 7Cr3+ + 14OH + 7Fe3+.
Refer to the Table 14.1 for 63-67.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
72
If the reaction is taking place in an acidic solution, the balanced equation is:

A) 2Fe + 14H+ + 2Cr2O72− → 2Fe3+ + 2Cr3+ + 2H2O.
B) Fe + H+ + Cr2O72− → Fe3+ + Cr3+ + H2O.
C) 2Fe + 14H+ + Cr2O72− → 4Fe3+ + 2Cr3+ + 28H2O.
D) 2Fe + 14H+ + Cr2O72− → 2Fe3+ + 2Cr3+ + 7H2O.
E) 4Fe + 10H+ + Cr2O72− → 3Fe3+ + Cr3+ + 7H2O.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
73
What is the E of a voltaic cell based on this reaction? 2Ce4+ + Ni → 2Ce3+ + Ni2+

A) 2.36 V
B) 2.11 V
C) 6.44 V
D) 0.403 V
E) 1.86 V
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
74
Describe a voltaic cell.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
75
In compounds, fluorine is assigned a −1 oxidation number; oxygen is usually assigned a −2 oxidation number [except in peroxide compounds (where it is −1) and in binary compounds with fluorine (where it is positive)]; and hydrogen is usually assigned a +1 oxidation number [except when it exists as the hydride ion (H), in which case rule 2 prevails].
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
76
In compounds, all other atoms are assigned an oxidation number so that the sum of the oxidation numbers on all the atoms in the species equals the charge on the species (which is zero if the species is neutral).
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
77
What is the half reaction for the electrolysis of elemental fluorine?

A) F2+ + 2e → F
B) F+ + e → F
C) F3++ 3e →F
D) F2 → 2F + 2e
E) 2F \rightarrow F2 + 2e
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
78
Define oxidation, reduction, and oxidation-reduction reactions.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
79
What is the E of a voltaic cell based on this reaction? NO3 + 4H+ + Fe2+ → NO + 2H2O + Fe3+

A) +0.21 V
B) +0.77 V
C) -0.77 V
D) -0.73 V
E) +0.35 V
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
80
Atoms in their elemental state are assigned an oxidation number of 0.
Unlock Deck
Unlock for access to all 104 flashcards in this deck.
Unlock Deck
k this deck
locked card icon
Unlock Deck
Unlock for access to all 104 flashcards in this deck.