Deck 2: Forces, Moments, Resultants

Question 1

resultant moment vector at point O in Problem 2.2 is (in N ∙ m) :

Answer 1

A

Question 2

Problem 2.7, the perpendicular distance d (in.) from force to line AC is:
(A) 1.7
(B) 2.1
(C) 1.2
(D) 3.3

Answer 2

A

Question 3

Forces and couples are applied to ABCDE as shown in the figure. All turns of ABCDE are 90º angles . The statically equivalent moment at A ( for the force2couple system is (in N ∙ m) :

Answer 3

C

Question 4

resultant force (in newtons) for the force system shown in the figure is:

Question 5

Bracket ADO is acted on by forces F and T and couple M (see figure). Assume that F 5 8 N, T 5 9 N and M 5 12 N ∙ m. Joint coordinates are in meters.
The resultant force vector (in newtons) is:

Question 6

Force is applied at D along line DB and couple is perpendicular to plane ABC. Assume magnitudes F 5 20 lb and couple M 5 50 in-lb. The moment

Question 7

Three couples of equal magnitude e applied as shown. A single couple (in N ∙ m) that is statically equivalent to the three couples is: Equilibrium of rigid bodies; static friction

Question 8

distributed loading on beam ABCD is to be replaced by a statically equivalent set of forces. The mag- nitude and location of the statically equivalent force on beam segment AB are:

(A) 575 lb, 4.1 ft
(B) 638 lb, 4.2 ft
(C) 740 lb, 3.9 ft
(D) 428 lb, 4.4 ft

Question 9

Problem 2.7, the moment of force

Question 10

bracket ABCDEF, each y-direction force acts at the center of the bar segment to which it is applied (see figure). All turns of ABCDEF are 90º angles. The resultant moment at for this parallel force system
Is (in N ∙ m) :