Deck 57: Heat Loss Vs Radiator Size

Question 1

A double glass window is 4' 0" * 5' 0". The outside temperature is 30 ° F and the inside temperature is 68 ° . How much heat is lost through the window?. Heat loss = constant * temperature difference * area (sq ft) Constant = .65 for window

A) 494 Btu
B) 1494 Btu
C) 94 Btu
D) 500 Btu

Answer 1

494 Btu

Question 2

A single glass window is 4' 0" * 5' 0". The outside temperature is 0 ° F and the inside temperature is 70 ° F. How much heat is lost through the window?. Heat loss = constant * temperature difference * area (sq ft) Constant = 1.13 for window

A) 1482 BTU
B) 1682 BTU
C) 1582 BTU
D) 1572 BTU

Answer 2

1582 BTU

Question 3

Determine the ceiling area for a dining room 11'0" * 11'0" * 8'0".Round to a whole number.

A) 121 sq ft
B) 120 sq ft
C) 125 sq ft
D) 124.12 sq ft

Answer 3

121 sq ft

Question 4

A double glass window is 10' 0" * 6' 0". The outside temperature is 0 ° F and the inside temperature is 70 ° . How much heat is lost through the window?. Heat loss = constant * temperature difference * area (sq ft) Constant = .65 for window

A) 2,700 Btu
B) 2,730 Btu
C) 2,731 Btu
D) 2,738 Btu

Question 5

Determine the Btu loss for a dining room 998 sq ft.Temperature difference is 60 ° F.Constant is .014.Round to a whole number.

A) 838 Btu
B) 838.12 Btu
C) 858 Btu
D) 848 Btu

Question 6

Determine the Btu heat loss for the ceiling area for a dining room 11'0" * 11'0" * 8'0".Constant is 0.05.Temperature difference is 25 ° F.Round to a whole number.

A) 151 Btu
B) 155 Btu
C) 152 Btu
D) 151.25 Btu

Question 7

A single glass window is 8' 0" * 5' 0". The outside temperature is 50 ° F and the inside temperature is 68 ° . How much heat is lost through the window?. Heat loss = constant * temperature difference * area (sq ft) Constant = 1.13 for window

A) 813.6 Btu
B) 813 Btu
C) 815.8 Btu
D) 789.4 Btu

Question 8

Determine the volume for a dining room 11' 2" * 11' 2" * 8' 0".Round to a whole number.

A) 998.16 cu ft
B) 998 cu ft
C) 999 cu ft
D) 997 cu ft