Deck 1: Multiple Comparison Procedures

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A one-factor fixed-effects ANOVA is performed on data for 5 groups of unequal sizes, and H0 is rejected at the .05 level of significance. Using the Scheffe' procedure, test the contrast that
A one-factor fixed-effects ANOVA is performed on data for 5 groups of unequal sizes, and H<sub>0</sub> is rejected at the .05 level of significance. Using the Scheffe' procedure, test the contrast that   at the .05 level of significance given the following information:  <div style=padding-top: 35px> at the .05 level of significance given the following information:
A one-factor fixed-effects ANOVA is performed on data for 5 groups of unequal sizes, and H<sub>0</sub> is rejected at the .05 level of significance. Using the Scheffe' procedure, test the contrast that   at the .05 level of significance given the following information:  <div style=padding-top: 35px>
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Question
A one-factor fixed-effects ANOVA is performed on data from three groups of equal size (n = 15) and equal variances, and H0 is rejected at the .05 level. The following values were computed: MSwith = 60 and the sample means are.
Yˉ.1\bar{Y}_{.1} = 25, Yˉ.2\bar{Y}_{.2} = 20, and Yˉ.3\bar{Y}_{.3} = 12. Use the Tukey HSD method to test all possible pairwise contrasts ( α\alpha = .05)
Question
Which of the following linear combinations of population means is a legitimate contrast?

A) μ\mu 1- μ\mu 2/2+ μ\mu 3/2
B) ( μ\mu 1+ μ\mu 2/2+ μ\mu 3
C) ( μ\mu 1+ μ\mu 2)+ μ\mu 3
D) μ\mu 1- μ\mu 2- μ\mu 3
Question
If J = 3, which of the following sets of contrasts is orthogonal?

A) μ\mu 1- μ\mu 2, μ\mu 1- μ\mu 3
B) μ\mu 2- μ\mu 3, μ\mu 2+ μ\mu 3
C) μ\mu 1- μ\mu 3, μ\mu 1-( μ\mu 2+ μ\mu 3)/2
D) μ\mu 1- μ\mu 3, μ\mu 2-( μ\mu 2+ μ\mu 3)/2
Question
A researcher used Fisher's LSD to test three contrasts: μ\mu 1- μ\mu 2, μ\mu 1- μ\mu 3, μ\mu 1-( μ\mu 2+ μ\mu 3)/2. Evaluate this practice.

A) This practice is problematic because Fisher's LSD is always too liberal.
B) This practice is problematic because Fisher's LSD can only be used to test simple
Contrasts.
C) This practice is problematic because the contrasts are not orthogonal.
D) I do not see any problem with this practice. It is great!
Question
In an experiment, Yˉ1\bar{Y}_{1} =10, Yˉ2\bar{Y}_{2} =20, and Yˉ3\bar{Y}_{3} =40. Tukey HSD shows that μ\mu 2- μ\mu 1 is a significant contrast. What will you find out about μ\mu 3- μ\mu 1 and μ\mu 3- μ\mu 2 if the same procedure and same α\alpha level are used?

A) Only μ\mu 3- μ\mu 1 is significant.
B) Only μ\mu 3- μ\mu 2 is significant.
C) Both contrasts are significant.
D) None of the contrasts are necessarily significant.
Question
In an experiment,? Yˉ1\bar{Y}_{1} =10, Yˉ2\bar{Y}_{2} =200, and Yˉ3\bar{Y}_{3} =4000. Which pairwise contrast will necessarily be significant

A) μ\mu 2- μ\mu 1
B) μ\mu 3- μ\mu 1
C) μ\mu 3- μ\mu 2
D) None of the contrasts will necessarily be significant.
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Deck 1: Multiple Comparison Procedures
1
A one-factor fixed-effects ANOVA is performed on data for 5 groups of unequal sizes, and H0 is rejected at the .05 level of significance. Using the Scheffe' procedure, test the contrast that
A one-factor fixed-effects ANOVA is performed on data for 5 groups of unequal sizes, and H<sub>0</sub> is rejected at the .05 level of significance. Using the Scheffe' procedure, test the contrast that   at the .05 level of significance given the following information:  at the .05 level of significance given the following information:
A one-factor fixed-effects ANOVA is performed on data for 5 groups of unequal sizes, and H<sub>0</sub> is rejected at the .05 level of significance. Using the Scheffe' procedure, test the contrast that   at the .05 level of significance given the following information:
  Because |t| = 2 < 3.28, we fail to reject the null hypothesis and conclude that the contrast is not significant at the .05 level of significance. Because |t| = 2 < 3.28, we fail to reject the null hypothesis and conclude that the contrast is not significant at the .05 level of significance.
2
A one-factor fixed-effects ANOVA is performed on data from three groups of equal size (n = 15) and equal variances, and H0 is rejected at the .05 level. The following values were computed: MSwith = 60 and the sample means are.
Yˉ.1\bar{Y}_{.1} = 25, Yˉ.2\bar{Y}_{.2} = 20, and Yˉ.3\bar{Y}_{.3} = 12. Use the Tukey HSD method to test all possible pairwise contrasts ( α\alpha = .05)
J=3,n1=n2=n3=15;dfwith =n1+n2+n3J=42,MSwith =60;α=.05Yˉ.1=25,Yˉ.2=20,Yˉ.3=12\begin{array}{l}J=3, n_{1}=n_{2}=n_{3}=15 ; d f_{\text {with }}=n_{1}+n_{2}+n_{3}-J=42, M S_{\text {with }}=60 ; \alpha=.05 \\\bar{Y}_{.1}=25, \bar{Y}_{.2}=20, \bar{Y}_{.3}=12\end{array}
Because J=3 J=3 , there are three possible pairwise contrasts: 1 vs. 2,1 vs. 3,2 vs. 3 .
For each contrast, q=Pˉ.jPijsψ q=\frac{\bar{P}_{. j}-P_{i j}}{s_{\psi}} , where Yˉij \bar{Y}_{i j} and Yˉij \bar{Y}_{i j} are two group means to be compared.
Because standard error sΨ=Mswith n=6015=2 s \Psi=\sqrt{\frac{M s_{\text {with }}}{n}}=\sqrt{\frac{60}{15}}=2
q1=(P1Pt2sψ)=(2520)/2=2.5 q_{1}=\left(\frac{P_{-1}-P_{t 2}}{s_{\psi}}\right)=(25-20) / 2=2.5
- q2=(Ps1Psssψ)=(2512)/2=6.5 q_{2}=\left(\frac{P_{s 1}-P_{s s}}{s_{\psi}}\right)=(25-12) / 2=6.5
- q1=(P2Pssψ)=(2012)/2=4 q_{1}=\left(\frac{P_{2}-P_{s}}{s_{\psi}}\right)=(20-12) / 2=4 Using Tukey HSD, the critical values are ±\pm α\alpha qdf
(with)
, J = .05q60, 3 = ±\pm 3.40.
q1 < critical q, so μ\mu 1 - μ\mu 2 is not statistically significant at α\alpha = .05.
q2 > critical q, q3 > critical q, so μ\mu 1 - μ\mu 3, μ\mu 2 - μ\mu 3 are statistically significant at α\alpha = .05.
3
Which of the following linear combinations of population means is a legitimate contrast?

A) μ\mu 1- μ\mu 2/2+ μ\mu 3/2
B) ( μ\mu 1+ μ\mu 2/2+ μ\mu 3
C) ( μ\mu 1+ μ\mu 2)+ μ\mu 3
D) μ\mu 1- μ\mu 2- μ\mu 3
( μ\mu 1+ μ\mu 2)+ μ\mu 3
4
If J = 3, which of the following sets of contrasts is orthogonal?

A) μ\mu 1- μ\mu 2, μ\mu 1- μ\mu 3
B) μ\mu 2- μ\mu 3, μ\mu 2+ μ\mu 3
C) μ\mu 1- μ\mu 3, μ\mu 1-( μ\mu 2+ μ\mu 3)/2
D) μ\mu 1- μ\mu 3, μ\mu 2-( μ\mu 2+ μ\mu 3)/2
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5
A researcher used Fisher's LSD to test three contrasts: μ\mu 1- μ\mu 2, μ\mu 1- μ\mu 3, μ\mu 1-( μ\mu 2+ μ\mu 3)/2. Evaluate this practice.

A) This practice is problematic because Fisher's LSD is always too liberal.
B) This practice is problematic because Fisher's LSD can only be used to test simple
Contrasts.
C) This practice is problematic because the contrasts are not orthogonal.
D) I do not see any problem with this practice. It is great!
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6
In an experiment, Yˉ1\bar{Y}_{1} =10, Yˉ2\bar{Y}_{2} =20, and Yˉ3\bar{Y}_{3} =40. Tukey HSD shows that μ\mu 2- μ\mu 1 is a significant contrast. What will you find out about μ\mu 3- μ\mu 1 and μ\mu 3- μ\mu 2 if the same procedure and same α\alpha level are used?

A) Only μ\mu 3- μ\mu 1 is significant.
B) Only μ\mu 3- μ\mu 2 is significant.
C) Both contrasts are significant.
D) None of the contrasts are necessarily significant.
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7
In an experiment,? Yˉ1\bar{Y}_{1} =10, Yˉ2\bar{Y}_{2} =200, and Yˉ3\bar{Y}_{3} =4000. Which pairwise contrast will necessarily be significant

A) μ\mu 2- μ\mu 1
B) μ\mu 3- μ\mu 1
C) μ\mu 3- μ\mu 2
D) None of the contrasts will necessarily be significant.
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