Deck 20: The Main Group Elements
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Deck 20: The Main Group Elements
1
In the reaction of trimethyl amine with trimethyl boron,
A) the product is [N(CH3)4+][B(CH3)2-].
B) trimethyl boron is the Lewis base.
C) the product is (CH3)3N-B(CH3)3.
D) trimethyl amine is the Lewis acid.
E) no reaction occurs.
A) the product is [N(CH3)4+][B(CH3)2-].
B) trimethyl boron is the Lewis base.
C) the product is (CH3)3N-B(CH3)3.
D) trimethyl amine is the Lewis acid.
E) no reaction occurs.
the product is (CH3)3N-B(CH3)3.
2
Which of the following are Lewis acids? 
A) I, II, and III
B) II, III, and IV
C) II, IV, and V
D) II and III
E) IV and V

A) I, II, and III
B) II, III, and IV
C) II, IV, and V
D) II and III
E) IV and V
II, IV, and V
3
Which of the following are Lewis bases? 
A) I, II, and III
B) I, III, and V
C) II, IV, and V
D) I and III
E) II and IV

A) I, II, and III
B) I, III, and V
C) II, IV, and V
D) I and III
E) II and IV
I, III, and V
4
What reactants likely lead to formation of the Lewis acid-base adduct shown below? 
A) Pd2+ and Cl2
B) Pd and Cl-
C) Pd and SnCl4
D) Pd2+ and Cl-
E) PdCl2 and Sn

A) Pd2+ and Cl2
B) Pd and Cl-
C) Pd and SnCl4
D) Pd2+ and Cl-
E) PdCl2 and Sn
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5
Which statements are true about the following reaction?
PF5 + HF H+ + PF6-
I. HF is a Brønsted acid and a Lewis acid.
II. PF5 is the Lewis acid.
III. The F- ion is the Lewis base.
IV. The orbital used in bonding is a dsp3 hybrid orbital.
V. PF6-is a Lewis acid.
A) I and V
B) II and III
C) I, III and IV
D) III and V
E) I and III
PF5 + HF H+ + PF6-
I. HF is a Brønsted acid and a Lewis acid.
II. PF5 is the Lewis acid.
III. The F- ion is the Lewis base.
IV. The orbital used in bonding is a dsp3 hybrid orbital.
V. PF6-is a Lewis acid.
A) I and V
B) II and III
C) I, III and IV
D) III and V
E) I and III
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6
Identify the Lewis acid and base in the reaction of trimethyl amine with trimethyl boron.
A) Base: trimethyl amine; acid trimethyl boron
B) Base: trimethyl boron; acid trimethyl amine
C) Neither acts as an acid nor a base.
A) Base: trimethyl amine; acid trimethyl boron
B) Base: trimethyl boron; acid trimethyl amine
C) Neither acts as an acid nor a base.
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7
Which of the following groups of Lewis acids is in order of increasing hardness?
A) Cd2+, Zn2+, Ag+
B) Ag+, Zn2+ Cd2+
C) Ag+, Cd2+, Zn2+
D) Cd2+, Ag+, Zn2+
E) Zn2+, Ag+, Cd2+
A) Cd2+, Zn2+, Ag+
B) Ag+, Zn2+ Cd2+
C) Ag+, Cd2+, Zn2+
D) Cd2+, Ag+, Zn2+
E) Zn2+, Ag+, Cd2+
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8
Which of the following groups of Lewis bases is in order of decreasing hardness?
A) N(CH3)3, NH3, P(CH3)3
B) NH3, P(CH3)3, N(CH3)3
C) P(CH3)3, N(CH3)3, NH3
D) NH3, N(CH3)3, P(CH3)3
E) N(CH3)3, P(CH3)3, NH3
A) N(CH3)3, NH3, P(CH3)3
B) NH3, P(CH3)3, N(CH3)3
C) P(CH3)3, N(CH3)3, NH3
D) NH3, N(CH3)3, P(CH3)3
E) N(CH3)3, P(CH3)3, NH3
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9
The reactions of Group 13 chlorides (BCl3, AlCl3, GaCl3, InCl3) with bases are predicted well by the HSAB principle. Which of the following is the predicted order of reactivity (completeness of adduct formation) of these compounds toward P(CH2CH3)3?
A) AlCl3 < InCl3 < BCl3 < GaCl3
B) BCl3< GaCl3 < AlCl3 < InCl3
C) BCl3 < AlCl3 < GaCl3 < InCl3
D) AlCl3 < BCl3 < GaCl3 < InCl3
E) InCl3 < GaCl3 < AlCl3 < BCl3
A) AlCl3 < InCl3 < BCl3 < GaCl3
B) BCl3< GaCl3 < AlCl3 < InCl3
C) BCl3 < AlCl3 < GaCl3 < InCl3
D) AlCl3 < BCl3 < GaCl3 < InCl3
E) InCl3 < GaCl3 < AlCl3 < BCl3
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10
Identify the following as Lewis acids or bases and rank from hardest to softest: Al3+, Tl3+, Tl+.
A) bases Al3+, Tl3+, Tl+
B) acids Al3+, Tl3+, Tl+
C) acids Tl+, Tl3+, Al3+
D) bases Tl+, Tl3+, Al3+
E) acids Al3+, Tl+, Tl3+
A) bases Al3+, Tl3+, Tl+
B) acids Al3+, Tl3+, Tl+
C) acids Tl+, Tl3+, Al3+
D) bases Tl+, Tl3+, Al3+
E) acids Al3+, Tl+, Tl3+
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11
Identify the following as Lewis acids or bases and rank from hardest to softest: SbH3, PH3, PF3.
A) bases SbH3, PH3, PF3
B) acids PF3, PH3, SbH3
C) acids SbH3, PH3, PF3
D) bases PF3, PH3, SbH3
E) acids PH3, PF3, SbH3
A) bases SbH3, PH3, PF3
B) acids PF3, PH3, SbH3
C) acids SbH3, PH3, PF3
D) bases PF3, PH3, SbH3
E) acids PH3, PF3, SbH3
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12
The substances below are main group compounds that follow the hard-soft acid-base principles quite reliably:
I. Al(CH3)3
II. MgCl2
III. AlCl3
IV. LiCl
V. LiCH3
VI. Mg(CH3)2
Referring to these compounds, which of the (unbalanced) equations below is expected to proceed?
A) Al(CH3)3 + MgCl2 AlCl3 + Mg(CH3)2
B) LiCl + Al(CH3)3 LiCH3 + AlCl3
C) LiCH3 + MgCl2 LiCl + Mg(CH3)2
D) Mg(CH3)2 + LiCl LiCH3 + MgCl2
I. Al(CH3)3
II. MgCl2
III. AlCl3
IV. LiCl
V. LiCH3
VI. Mg(CH3)2
Referring to these compounds, which of the (unbalanced) equations below is expected to proceed?
A) Al(CH3)3 + MgCl2 AlCl3 + Mg(CH3)2
B) LiCl + Al(CH3)3 LiCH3 + AlCl3
C) LiCH3 + MgCl2 LiCl + Mg(CH3)2
D) Mg(CH3)2 + LiCl LiCH3 + MgCl2
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13
Potassium is found in nature most often as a chloride salt, whereas copper and mercury more often occur as the sulphides. The best explanation for this observation is
A) potassium is softer than copper or mercury.
B) the coinage metals are smaller than potassium.
C) the coinage metals prefer the +2 oxidation state.
D) potassium is less electronegative than copper.
E) the coinage metal ions are softer than potassium.
A) potassium is softer than copper or mercury.
B) the coinage metals are smaller than potassium.
C) the coinage metals prefer the +2 oxidation state.
D) potassium is less electronegative than copper.
E) the coinage metal ions are softer than potassium.
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14
Are the chlorides of Pb, Pb(II) chloride and Pb(IV) chloride solids, liquids, or gases at room temperature?
A) PbCl2: solid; PbCl4: solid
B) PbCl2: liquid; PbCl4: liquid
C) PbCl2: solid; PbCl4: liquid
D) PbCl2: liquid; PbCl4: solid
E) PbCl2: gas; PbCl4: liquid
A) PbCl2: solid; PbCl4: solid
B) PbCl2: liquid; PbCl4: liquid
C) PbCl2: solid; PbCl4: liquid
D) PbCl2: liquid; PbCl4: solid
E) PbCl2: gas; PbCl4: liquid
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15
What reasons are important for the use of Na3AlF6 in the production of aluminum?
I. The use of Na3AlF6 allows for electrolysis at lower temperature.
II. The fluoride will react with the electrodes.
III. The oxide ions combine with the fluoride ions.
IV. The fluoride is not readily oxidized.
V. The aluminum is more easily oxidized when bound to fluoride.
A) II and III
B) IV and V
C) I and V
D) I and IV
E) I, III, and V
I. The use of Na3AlF6 allows for electrolysis at lower temperature.
II. The fluoride will react with the electrodes.
III. The oxide ions combine with the fluoride ions.
IV. The fluoride is not readily oxidized.
V. The aluminum is more easily oxidized when bound to fluoride.
A) II and III
B) IV and V
C) I and V
D) I and IV
E) I, III, and V
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16
Why are heavy metals such as lead(II) and cadmium(II) toxic?
A) They can replace oxygen atoms in proteins.
B) They can bind to sulphur atoms on proteins.
C) They are hard Lewis acids.
D) They are insoluble in aqueous solution and will precipitate.
E) They form ionic compounds.
A) They can replace oxygen atoms in proteins.
B) They can bind to sulphur atoms on proteins.
C) They are hard Lewis acids.
D) They are insoluble in aqueous solution and will precipitate.
E) They form ionic compounds.
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17
Which of the following ionic species result when boric acid, H3BO3, is added to water:H3O+, H2BO3-, HBO32-, BO33-, B(OH)4-, OH-?
A) H3O+, H2BO3-,
B) H3O+, H2BO3-, HBO32-
C) H3O+, H2BO3-, HBO32-, BO33
D) H3O+, B(OH)4-
E) H3O+, OH-
A) H3O+, H2BO3-,
B) H3O+, H2BO3-, HBO32-
C) H3O+, H2BO3-, HBO32-, BO33
D) H3O+, B(OH)4-
E) H3O+, OH-
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18
Which of the following boron halides has the most -bonding?
A) BI3
B) BBr3
C) BCl3
D) BF3
E) BF4-
A) BI3
B) BBr3
C) BCl3
D) BF3
E) BF4-
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19
What is the product of the reaction of silicon-copper alloy with chlorobutane?
A)

B)

C)

D)

E) Cu metal
A)

B)

C)

D)

E) Cu metal
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20
Why is SiO2 a solid and CO2 a gas?
A) A Si atom is heavier than a C carbon.
B) Si has more electrons than C.
C) Intermolecular forces between SiO2 molecules are stronger than those between CO2 molecules.
D) It is preferable to form 4 Si - O single bonds rather than 2 Si - O double bonds.
E) SiO2 forms ionic bonds.
A) A Si atom is heavier than a C carbon.
B) Si has more electrons than C.
C) Intermolecular forces between SiO2 molecules are stronger than those between CO2 molecules.
D) It is preferable to form 4 Si - O single bonds rather than 2 Si - O double bonds.
E) SiO2 forms ionic bonds.
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21
Silicon tetrachloride has Lewis acidic characteristics, whereas carbon tetrachloride does not. What orbital is used by SiCl4 in forming adducts that gives SiCl4 this property?
A) sp2
B) sp3
C) sp2d
D) sp3d
E) sp3d2
A) sp2
B) sp3
C) sp2d
D) sp3d
E) sp3d2
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22
Arsenic oxide (As2O3) is used as a standard in oxidation-reduction titrations because it is stable and reacts very predictably. Reaction with MnO4- in acidic solution gives aqueous arsenic (H3AsO4) and Mn2+. If the coefficient of MnO4-is 4 in the balanced chemical equation of reaction, the coefficient of H3AsO4 is
A) 2.
B) 4.
C) 5.
D) 8.
E) 10.
A) 2.
B) 4.
C) 5.
D) 8.
E) 10.
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23
Neutralization of 25 ml of 0.05 M H3PO4 requires what mass of solid sodium hydroxide, NaOH?
A) 0.05 g
B) 0.15 g
C) 0.02 g
D) 0.06 g
E) 2 g
A) 0.05 g
B) 0.15 g
C) 0.02 g
D) 0.06 g
E) 2 g
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24
Which allotrope of carbon is the most thermodynamically stable?
A) diamond
B) fullerene
C) graphite
D) coke
E) carbon nanotube
A) diamond
B) fullerene
C) graphite
D) coke
E) carbon nanotube
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25
CFCs, chlorofluorocarbons, are being phased out of use as refrigerants because
A) they highly reactive producing numerous pollutants in our atmosphere.
B) they are toxic.
C) they may remain in the atmosphere for hundreds of years, but react in the upper atmosphere.
D) they are gases and hard to contain.
E) hydrochlorfluorocarbons are cheaper and more effective refrigerants.
A) they highly reactive producing numerous pollutants in our atmosphere.
B) they are toxic.
C) they may remain in the atmosphere for hundreds of years, but react in the upper atmosphere.
D) they are gases and hard to contain.
E) hydrochlorfluorocarbons are cheaper and more effective refrigerants.
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26
When SF4 acts as a Lewis base, it donates an F- ion and generates the SF3+ ion. The structure of SF3+ is
A) T-shaped.
B) trigonal planar.
C) trigonal pyramidal.
D) tetrahedral.
E) distorted trigonal bipyramidal.
A) T-shaped.
B) trigonal planar.
C) trigonal pyramidal.
D) tetrahedral.
E) distorted trigonal bipyramidal.
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27
When SF4 acts as a Lewis acid, with trimethyl amine, it forms the adduct (CH3)3N-SF4. The structure of sulphur in (CH3)3N-SF4 is a(n)
A) distorted square planar.
B) tetrahedral.
C) octahedral.
D) square pyramidal.
E) trigonal bipyramidal.
A) distorted square planar.
B) tetrahedral.
C) octahedral.
D) square pyramidal.
E) trigonal bipyramidal.
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28
In the text, it is mentioned that sulphur compounds are poison for many catalysts. How, generally, would you expect that this is possible?
A) The sulphur coats the catalyst.
B) The sulphur reacts with the metal ions of the catalyst as a hard Lewis base.
C) The sulphur reacts with the other reactants.
D) The sulphur reacts with the metal ions of the catalyst as a soft Lewis base.
E) The sulphur changes the reaction products.
A) The sulphur coats the catalyst.
B) The sulphur reacts with the metal ions of the catalyst as a hard Lewis base.
C) The sulphur reacts with the other reactants.
D) The sulphur reacts with the metal ions of the catalyst as a soft Lewis base.
E) The sulphur changes the reaction products.
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29
Which polymer is fluoride found in?
A) CFC
B) Teflon
C) PVC
D) DDT
E) chlorofluorocarbons
A) CFC
B) Teflon
C) PVC
D) DDT
E) chlorofluorocarbons
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