Deck 7: Mass Stoichiometry
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Deck 7: Mass Stoichiometry
1
What is the formula mass,to the nearest whole number,for potassium nitrite,KNO2?
A) 39 amu
B) 69 amu
C) 85 amu
D) 153 amu
A) 39 amu
B) 69 amu
C) 85 amu
D) 153 amu
85 amu
2
How many moles of KF are present in 15.2 grams of KF?
A) 0.262
B) 3.82
C) 6.02
D) 882
A) 0.262
B) 3.82
C) 6.02
D) 882
0.262
3
How many moles of CO2 are present in 56.0 grams of CO2?
A) 0.786
B) 2.00
C) 0.560
D) 1.27
A) 0.786
B) 2.00
C) 0.560
D) 1.27
1.27
4
How many atoms are present in a 0.900-mole sample of gold?
A) 1.81 × 1023
B) 1.50 × 1024
C) 5.42 × 1023
D) 6.02 × 1023
A) 1.81 × 1023
B) 1.50 × 1024
C) 5.42 × 1023
D) 6.02 × 1023
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5
Lithium carbonate,Li2CO3,is commonly used to treat bipolar disorder.What is the percent by mass of carbon in this compound (to the nearest whole percent)?
A) 8%
B) 16%
C) 58%
D) 75%
A) 8%
B) 16%
C) 58%
D) 75%
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6
A skunk's spray contains the foul-smelling compound butanethiol,C4H8S.What is the percent by mass of sulfur in this compound (to the nearest whole percent)?
A) 8%
B) 36%
C) 55%
D) 75%
A) 8%
B) 36%
C) 55%
D) 75%
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7
What is the formula mass,to the nearest whole number,for sodium nitrite,NaNO2?
A) 23 amu
B) 53 amu
C) 69 amu
D) 83 amu
A) 23 amu
B) 53 amu
C) 69 amu
D) 83 amu
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8
How many molecules of carbon monoxide,CO,comprise 2.34 moles?
A) 1.41 × 1024
B) 2.57 × 1023
C) 1.69 × 1025
D) 2.15 × 1022
A) 1.41 × 1024
B) 2.57 × 1023
C) 1.69 × 1025
D) 2.15 × 1022
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9
How many atoms are present in a 0.300-mole sample of gold?
A) 4.98 × 1025
B) 1.27 × 1015
C) 1.81 × 1023
D) 6.02 × 1023
A) 4.98 × 1025
B) 1.27 × 1015
C) 1.81 × 1023
D) 6.02 × 1023
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10
How many molecules of carbon dioxide,CO2,comprise 1.22 moles?
A) 7.34 × 1023
B) 4.93 × 1023
C) 2.65 × 1025
D) 1.37 × 1022
A) 7.34 × 1023
B) 4.93 × 1023
C) 2.65 × 1025
D) 1.37 × 1022
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11
A skunk's spray contains the foul-smelling compound butanethiol,C4H8S.What is the percent by mass of carbon in this compound (to the nearest whole percent)?
A) 8%
B) 31%
C) 55%
D) 75%
A) 8%
B) 31%
C) 55%
D) 75%
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12
How many atoms are present in a 0.600-mole sample of gold?
A) 3.61 × 1023
B) 1.18 × 1015
C) 9.97 × 1025
D) 6.02 × 1023
A) 3.61 × 1023
B) 1.18 × 1015
C) 9.97 × 1025
D) 6.02 × 1023
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13
What is the mass of 1.6 × 1021 argon atoms?
A) 0.11 g
B) 0.0027 g
C) 39.4 g
D) 5.11 × 1022 g
A) 0.11 g
B) 0.0027 g
C) 39.4 g
D) 5.11 × 1022 g
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14
How many moles of CO2 are present in 88.0 grams of CO2?
A) 0.636
B) 1.42
C) 0.88
D) 2.00
A) 0.636
B) 1.42
C) 0.88
D) 2.00
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15
What is the formula mass,to the nearest whole number,for lithium nitrite,LiNO2?
A) 7 amu
B) 44 amu
C) 37 amu
D) 53 amu
A) 7 amu
B) 44 amu
C) 37 amu
D) 53 amu
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16
What is the mass of 1.5 × 1021 silicon atoms?
A) 0.0025 g
B) 4.21 × 1022 g
C) 0.070 g
D) 9.52 × 1024 g
A) 0.0025 g
B) 4.21 × 1022 g
C) 0.070 g
D) 9.52 × 1024 g
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17
What is the mass of 3.00 moles of CS2?
A) 25.4 g
B) 229 g
C) 0.0394 g
D) 1.81 × 1024 g
A) 25.4 g
B) 229 g
C) 0.0394 g
D) 1.81 × 1024 g
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18
What is the mass of 3.20 moles of KF?
A) 18.2 g
B) 0.055 g
C) 186 g
D) 1.93 × 1024 g
A) 18.2 g
B) 0.055 g
C) 186 g
D) 1.93 × 1024 g
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19
How many molecules of water,H2O,comprise 2.07 moles?
A) 1.25 × 1024
B) 2.91 × 1023
C) 1.08 × 1025
D) 3.34 × 1022
A) 1.25 × 1024
B) 2.91 × 1023
C) 1.08 × 1025
D) 3.34 × 1022
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20
What is the mass of 2.00 moles of CS2?
A) 38.1 g
B) 152 g
C) 0.0262 g
D) 1.20 × 1024 g
A) 38.1 g
B) 152 g
C) 0.0262 g
D) 1.20 × 1024 g
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21
Based on the following balanced equation,how many moles of O2 will be needed to react completely with of 4 moles of CH4? CH4 (g)+ 2 O2 (g) CO2 (g)+ 2 H2O (g)
A) 2
B) 4
C) 8
D) 12
A) 2
B) 4
C) 8
D) 12
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22
In this reaction,the symbol (aq)after BaCl2 means that it is: BaCl2 (aq)+ Na2CO3 (aq) BaCO3 (s)+ 2 NaCl (aq)
A) the excess reagent.
B) an ionic compound.
C) a reactant.
D) dissolved in water.
A) the excess reagent.
B) an ionic compound.
C) a reactant.
D) dissolved in water.
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23
In this reaction,BaCO3 is the: BaCl2 (aq)+ Na2CO3 (aq) BaCO3 (s)+ 2 NaCl (aq)
A) excess reagent.
B) reactant.
C) dissociated compound.
D) precipitate.
A) excess reagent.
B) reactant.
C) dissociated compound.
D) precipitate.
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24
Consider the following reaction: Fe + Br2 FeBr2
If 44.2 grams of iron react with an excess of bromine gas,what mass of FeBr2 can form?
(FeBr2 = 215.65 g/mol)
A) 171 g
B) 3.67 × 10-3 g
C) 11.4 g
D) 272 g
If 44.2 grams of iron react with an excess of bromine gas,what mass of FeBr2 can form?
(FeBr2 = 215.65 g/mol)
A) 171 g
B) 3.67 × 10-3 g
C) 11.4 g
D) 272 g
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25
Based on the following balanced equation,how many moles of H2O can form from the reaction of 6 moles of CH4? CH4 (g)+ 2 O2 (g) CO2 (g)+ 2 H2O (g)
A) 6
B) 3
C) 12
D) 18
A) 6
B) 3
C) 12
D) 18
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26
In this reaction,the limiting reagent is: 
A) Br2.
B) AlBr3.
C) Al.
D) H2O.

A) Br2.
B) AlBr3.
C) Al.
D) H2O.
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27
Based on the following balanced equation,how many moles of CO2 will be produced along with 6 moles of water? CH4 (g)+ 2 O2 (g) CO2 (g)+ 2 H2O (g)
A) 2
B) 3
C) 4
D) 8
A) 2
B) 3
C) 4
D) 8
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28
In this reaction,the symbol (aq)after ZnBr2 means that it is: ZnBr2 (aq)+ K2CO3 (aq) 2 KBr (aq)+ ZnCO3 (s)
A) the excess reagent.
B) an ionic compound.
C) a reactant.
D) dissolved in water.
A) the excess reagent.
B) an ionic compound.
C) a reactant.
D) dissolved in water.
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29
Consider the following reaction: 4 Fe + 3 O2 2 Fe2O3
If 44.2 grams of iron react with an excess of oxygen gas,what mass of Fe2O3 can form?
(Fe2O3 = 159.70 g/mol)
A) 63.2 g
B) 253 g
C) 15.5 g
D) 126 g
If 44.2 grams of iron react with an excess of oxygen gas,what mass of Fe2O3 can form?
(Fe2O3 = 159.70 g/mol)
A) 63.2 g
B) 253 g
C) 15.5 g
D) 126 g
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30
Based on the following balanced equation,how many moles of SF6 can form from the combination of 6 moles of S and 15 moles of F2? S + 3 F2 SF6
A) 5
B) 6
C) 15
D) 20
A) 5
B) 6
C) 15
D) 20
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31
Consider the following reaction: Fe + Br2 FeBr2
If 53.2 grams of iron react with an excess of bromine gas,what mass of FeBr2 can form?
(FeBr2 = 215.65 g/mol)
A) 226 g
B) 13.8 g
C) 205 g
D) 4.41 × 10-3 g
If 53.2 grams of iron react with an excess of bromine gas,what mass of FeBr2 can form?
(FeBr2 = 215.65 g/mol)
A) 226 g
B) 13.8 g
C) 205 g
D) 4.41 × 10-3 g
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32
How many molecules of water,H2O,comprise 3.64 grams?
A) 1.22 × 1023
B) 3.95 × 1025
C) 2.98 × 1024
D) 8.22 × 1024
A) 1.22 × 1023
B) 3.95 × 1025
C) 2.98 × 1024
D) 8.22 × 1024
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33
Consider the following reaction: Fe + Br2 FeBr2
If 38.6 grams of iron react with an excess of bromine gas,what mass of FeBr2 can form?
(FeBr2 = 215.65 g/mol)
A) 149 g
B) 3.20 × 10-3 g
C) 10.0 g
D) 312 g
If 38.6 grams of iron react with an excess of bromine gas,what mass of FeBr2 can form?
(FeBr2 = 215.65 g/mol)
A) 149 g
B) 3.20 × 10-3 g
C) 10.0 g
D) 312 g
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34
How many molecules of carbon dioxide,CO2,comprise 2.55 grams?
A) 3.49 × 1022
B) 6.76 × 1025
C) 1.04 × 1025
D) 2.86 × 1023
A) 3.49 × 1022
B) 6.76 × 1025
C) 1.04 × 1025
D) 2.86 × 1023
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35
Based on the following balanced equation,how many moles of SF6 can form from the combination of 5 moles of S and 18 moles of F2? S + 3 F2 SF6
A) 6
B) 5
C) 18
D) 23
A) 6
B) 5
C) 18
D) 23
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36
In this reaction,the excess reagent is: 
A) Br2.
B) AlBr3.
C) Al.
D) H2O.

A) Br2.
B) AlBr3.
C) Al.
D) H2O.
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37
How many molecules of carbon monoxide,CO,comprise 4.82 grams?
A) 1.04 × 1023
B) 8.13 × 1025
C) 3.50 × 1024
D) 2.24 × 1022
A) 1.04 × 1023
B) 8.13 × 1025
C) 3.50 × 1024
D) 2.24 × 1022
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38
In this reaction,ZnCO3 is the: ZnBr2 (aq)+ K2CO3 (aq) 2 KBr (aq)+ ZnCO3 (s)
A) precipitate.
B) reactant.
C) dissociated compound.
D) excess reagent.
A) precipitate.
B) reactant.
C) dissociated compound.
D) excess reagent.
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39
Based on the following balanced equation,how many moles of SF6 can form from the combination of 11 moles of S and 18 moles of F2? S + 3 F2 SF6
A) 6
B) 11
C) 18
D) 29
A) 6
B) 11
C) 18
D) 29
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40
What is the mass of 1.6 × 1021 neon atoms?
A) 0.054 g
B) 0.0027 g
C) 19 g
D) 3.2 × 1022 g
A) 0.054 g
B) 0.0027 g
C) 19 g
D) 3.2 × 1022 g
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41
A chemist carries out this reaction in the laboratory using 4.31 grams of zinc and an excess of sulfur: Zn + S ZnS
From the balanced equation,she calculates that she should obtain 6.41 grams of zinc sulfide.However,she isolates only 5.01 grams of product.What is her percent yield for this reaction?
A) 67.2%
B) 86.0%
C) 78.2%
D) 128%
From the balanced equation,she calculates that she should obtain 6.41 grams of zinc sulfide.However,she isolates only 5.01 grams of product.What is her percent yield for this reaction?
A) 67.2%
B) 86.0%
C) 78.2%
D) 128%
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42
Consider the following reaction: 4 Fe + 3 O2 2 Fe2O3
If 44.2 grams of oxygen react with an excess of iron,what mass of Fe2O3 can form?
(Fe2O3 = 159.70 g/mol)
A) 147 g
B) 331 g
C) 294 g
D) 221 g
If 44.2 grams of oxygen react with an excess of iron,what mass of Fe2O3 can form?
(Fe2O3 = 159.70 g/mol)
A) 147 g
B) 331 g
C) 294 g
D) 221 g
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43
A chemist carries out this reaction in the laboratory using 4.31 grams of zinc and an excess of sulfur: Zn + S ZnS
From the balanced equation,she calculates that she should obtain 6.41 grams of zinc sulfide.However,she isolates only 5.85 grams of product.What is her percent yield for this reaction?
A) 2.1%
B) 67.2%
C) 109.6%
D) 91.3%
From the balanced equation,she calculates that she should obtain 6.41 grams of zinc sulfide.However,she isolates only 5.85 grams of product.What is her percent yield for this reaction?
A) 2.1%
B) 67.2%
C) 109.6%
D) 91.3%
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44
Consider the following reaction: 4 Fe + 3 O2 2 Fe2O3
How many grams of oxygen gas are needed to react completely with 44.2 grams of iron?
A) 19.0 g
B) 101 g
C) 12.7 g
D) 25.3 g
How many grams of oxygen gas are needed to react completely with 44.2 grams of iron?
A) 19.0 g
B) 101 g
C) 12.7 g
D) 25.3 g
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