Deck 18: Thermodynamics
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Deck 18: Thermodynamics
1
Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion. 4Al(s)+ 3O2(g) 2Al2O3(s)
Using the thermodynamic data provided below, calculate S° for this reaction.
A)182.3 J/K·mol
B)131.5 J/K·mol
C)-182.3 J/K·mol
D)-626.2 J/K·mol
E)-802.9 J/K·mol
Using the thermodynamic data provided below, calculate S° for this reaction.

A)182.3 J/K·mol
B)131.5 J/K·mol
C)-182.3 J/K·mol
D)-626.2 J/K·mol
E)-802.9 J/K·mol
-626.2 J/K·mol
2
Which one of the following reactions would you expect to have highest S°?
A)CH4(g)+ 2O2(g) CO2(g)+ 2H2O(g)
B)C2H2(g)+ 5/2O2(g) 2CO2(g)+ H2O(g)
C)C2H4(g)+ 3O2(g) 2CO2(g)+ 2H2O(g)
D)C2H6(g)+ 7/2O2(g) 2CO2(g)+ 3H2O(g)
A)CH4(g)+ 2O2(g) CO2(g)+ 2H2O(g)
B)C2H2(g)+ 5/2O2(g) 2CO2(g)+ H2O(g)
C)C2H4(g)+ 3O2(g) 2CO2(g)+ 2H2O(g)
D)C2H6(g)+ 7/2O2(g) 2CO2(g)+ 3H2O(g)
C2H6(g)+ 7/2O2(g) 2CO2(g)+ 3H2O(g)
3
Arrange these compounds in order of increasing standard molar entropy at 25°C: C3H8(g), C2H4(g), ZnS(s), and H2O(l).
A)ZnS(s)< H2O(l)< C3H8(g)< C2H4(g)
B)C2H4(g)< H2O(l)< C3H8(g)< NaCl(s)
C)ZnS(s)< C3H8(g)< C2H4(g)< H2O(l)
D)C3H8(g)< C2H4(g)< H2O(l)< ZnS(s)
E)ZnS(s)< H2O(l)< C2H4(g)< C3H8(g)
A)ZnS(s)< H2O(l)< C3H8(g)< C2H4(g)
B)C2H4(g)< H2O(l)< C3H8(g)< NaCl(s)
C)ZnS(s)< C3H8(g)< C2H4(g)< H2O(l)
D)C3H8(g)< C2H4(g)< H2O(l)< ZnS(s)
E)ZnS(s)< H2O(l)< C2H4(g)< C3H8(g)
ZnS(s)< H2O(l)< C2H4(g)< C3H8(g)
4
Calculate S° at 25°C for the reduction of PbO(s), 2PbO(s)+ C(s) 2Pb(s)+ CO2(g)given these absolute entropies: 
A)+198.8 J/K·mol
B)+488.0 J/K·mol
C)+353.6 J/K·mol
D)-203.3 J/K·mol
E)+203.3 J/K·mol

A)+198.8 J/K·mol
B)+488.0 J/K·mol
C)+353.6 J/K·mol
D)-203.3 J/K·mol
E)+203.3 J/K·mol
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5
Which of these species would you expect to have the highest standard entropy (S°)?
A)CH4(g)
B)C2H2(g)
C)C2H4(g)
D)C2H6(g)
E)C3H8(g)
A)CH4(g)
B)C2H2(g)
C)C2H4(g)
D)C2H6(g)
E)C3H8(g)
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6
Arrange the following substances in the order of increasing entropy at 25°C. HF(g), NaF(s), SiF4(g), SiH4(g), Al(s)
Lowest highest
A)SiF4(g)< SiH4(g)< NaF(s)< HF(g)< Al(s)
B)HF(g)< Al(s)< NaF(s)< SiF4(g)< SiH4(g)
C)Al(s)< NaF(s)< HF(g)< SiH4(g)< SiF4(g)
D)Al(s)< HF(g)< NaF(s)< SiF4(g)< SiH4(g)
E)NaF(s)< Al(s)< HF(g)< SiF4(g)< SiH4(g)
Lowest highest
A)SiF4(g)< SiH4(g)< NaF(s)< HF(g)< Al(s)
B)HF(g)< Al(s)< NaF(s)< SiF4(g)< SiH4(g)
C)Al(s)< NaF(s)< HF(g)< SiH4(g)< SiF4(g)
D)Al(s)< HF(g)< NaF(s)< SiF4(g)< SiH4(g)
E)NaF(s)< Al(s)< HF(g)< SiF4(g)< SiH4(g)
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7
Which of these species has the highest entropy (S°)at 25°C?
A)CH3OH(l)
B)CO(g)
C)MgCO3(s)
D)H2O(l)
E)Ni(s)
A)CH3OH(l)
B)CO(g)
C)MgCO3(s)
D)H2O(l)
E)Ni(s)
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8
MgCO3(s) MgO(s)+ CO2(g)
A)1 < 2 < 3
B)2 < 3 < 1
C)3 < 2 < 1
D)2 < 1 < 3
E)1 < 3 < 2
A)1 < 2 < 3
B)2 < 3 < 1
C)3 < 2 < 1
D)2 < 1 < 3
E)1 < 3 < 2
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9
Which of these species would you expect to have the lowest standard entropy (S°)?
A)CH4(g)
B)HF(g)
C)NH3(g)
D)H2O(g)
A)CH4(g)
B)HF(g)
C)NH3(g)
D)H2O(g)
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10
Which one of the following reactions would you expect to have the lowest S°?
A)CH4(g)+ 2O2(g) CO2(g)+ 2H2O(g)
B)C2H2(g)+ 5/2O2(g) 2CO2(g)+ H2O(g)
C)C2H4(g)+ O2(g) 2CO2(g)+ 2H2O(g)
D)C2H6(g)+ 7/2O2(g) 2CO2(g)+ 3H2O(g)
A)CH4(g)+ 2O2(g) CO2(g)+ 2H2O(g)
B)C2H2(g)+ 5/2O2(g) 2CO2(g)+ H2O(g)
C)C2H4(g)+ O2(g) 2CO2(g)+ 2H2O(g)
D)C2H6(g)+ 7/2O2(g) 2CO2(g)+ 3H2O(g)
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11
Calculate S° for the reaction SO2(s)+ NO2(g) SO3(g)+ NO(g).
A)53.6 J/K·mol
B)-53.6 J/K·mol
C)-22.2 J/K·mol
D)474.8 J/K·mol
E)-474.8 J/K·mol

A)53.6 J/K·mol
B)-53.6 J/K·mol
C)-22.2 J/K·mol
D)474.8 J/K·mol
E)-474.8 J/K·mol
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12
Determine S° for the reaction SO3(g)+ H2O(l) H2SO4(l). 
A)169.2 J/K·mol
B)1343.2 J/K·mol
C)-169.2 J/K·mol
D)-29.4 J/K·mol
E)29.4 J/K·mol

A)169.2 J/K·mol
B)1343.2 J/K·mol
C)-169.2 J/K·mol
D)-29.4 J/K·mol
E)29.4 J/K·mol
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13
H2O2(l) H2O(l)+ 1/2O2(g)
A)1 < 3 < 2
B)2 < 3 < 1
C)2 < 1 < 3
D)3 < 2 < 1
E)3 < 1 < 2
A)1 < 3 < 2
B)2 < 3 < 1
C)2 < 1 < 3
D)3 < 2 < 1
E)3 < 1 < 2
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14
Which of these species has the highest entropy (S°)at 25°C?
A)CO(g)
B)CH4(g)
C)NaCl(s)
D)H2O(l)
E)Fe(s)
A)CO(g)
B)CH4(g)
C)NaCl(s)
D)H2O(l)
E)Fe(s)
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15
Which of these species would you expect to have the lowest standard entropy (S°)?
A)Br2(l)
B)Cl2(g)
C)F2(g)
D)H2(g)
E)I2(s)
A)Br2(l)
B)Cl2(g)
C)F2(g)
D)H2(g)
E)I2(s)
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16
Sulfur can be separated from lead in the mineral galena, PbS(s), by "roasting" the ore in the presence of oxygen as shown in the following reaction: 2PbS(s)+ 3O2(g) 2PbO(s)+ 2SO2(g)
Calculate S° for this reaction using the thermodynamic data provided below.
A)-410 J/K·mol
B)-161.5 J/K·mol
C)-47.7 J/K·mol
D)21.8 J/K·mol
E)43.5 J/K·mol
Calculate S° for this reaction using the thermodynamic data provided below.

A)-410 J/K·mol
B)-161.5 J/K·mol
C)-47.7 J/K·mol
D)21.8 J/K·mol
E)43.5 J/K·mol
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17
The entropy change on vaporization ( Svap)of a compound or element is
A)always negative.
B)always positive.
C)sometimes is positive and sometimes is negative.
A)always negative.
B)always positive.
C)sometimes is positive and sometimes is negative.
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18
Mg2+(aq)+ 2OH-(aq) Mg(OH)2(s)
A)1, 2
B)1, 3
C)3, 4
D)3
E)2, 4
A)1, 2
B)1, 3
C)3, 4
D)3
E)2, 4
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19
H2O2(l) H2O(l)+ 1/2O2(g)
A)1, 2, 3, 4
B)1, 2
C)2, 3, 4
D)3, 4
E)1, 4
A)1, 2, 3, 4
B)1, 2
C)2, 3, 4
D)3, 4
E)1, 4
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20
HI has a normal boiling point of -35.4°C, and its Hvap is 21.16 kJ/mol. Calculate the molar entropy of vaporization ( Svap).
A)598 J/K·mol
B)68.6 J/K·mol
C)75.2 J/K·mol
D)0.068 J/K·mol
E)89.0 J/K·mol
A)598 J/K·mol
B)68.6 J/K·mol
C)75.2 J/K·mol
D)0.068 J/K·mol
E)89.0 J/K·mol
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21
At 1500°C the equilibrium constant for the reaction CO(g)+ 2H2(g) CH3OH(g)has the value Kp = 1.4 * 10-7. Calculate G° for this reaction at 1500°C.
A)105 kJ/mol
B)1.07 kJ/mol
C)-233 kJ/mol
D)-105 kJ/mol
E)233 kJ/mol
A)105 kJ/mol
B)1.07 kJ/mol
C)-233 kJ/mol
D)-105 kJ/mol
E)233 kJ/mol
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22
A negative sign for G indicates that, at constant T and P,
A)the reaction is exothermic.
B)the reaction is endothermic.
C)the reaction is fast.
D)the reaction is spontaneous.
E)( S) must be > 0.
A)the reaction is exothermic.
B)the reaction is endothermic.
C)the reaction is fast.
D)the reaction is spontaneous.
E)( S) must be > 0.
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23
Determine the equilibrium constant Kp at 25°C for the reaction N2(g)+ 3H2(g) 2NH3(g) [ G°f (NH3(g))= -16.6 kJ/mol].
A)1.52 * 10-6
B)6.60 * 105
C)8.28 * 10-2
D)2.60
E)13.4
A)1.52 * 10-6
B)6.60 * 105
C)8.28 * 10-2
D)2.60
E)13.4
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24
Kw for the auto-ionization of water, H2O(l) H+(aq)+ OH- (aq), is 1.0 * 10-14. What are the signs (+/-)of S° and H° for the reaction at 25°C?
A)( S°) = (+)and H° = (+)
B)( S°) = (+)and H° = (-)
C)( S°) = (-)and H° = (+)
D)( S°) = (-)and H° = (-)
A)( S°) = (+)and H° = (+)
B)( S°) = (+)and H° = (-)
C)( S°) = (-)and H° = (+)
D)( S°) = (-)and H° = (-)
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25
Sodium carbonate can be made by heating sodium bicarbonate: 2NaHCO3(s) Na2CO3(s)+ CO2(g)+ H2O(g)
Given that H° = 128.9 kJ/mol and G° = 33.1 kJ/mol at 25°C, above what minimum temperature will the reaction become spontaneous under standard state conditions?
A)0.4 K
B)3.9 K
C)321 K
D)401 K
E)525 K
Given that H° = 128.9 kJ/mol and G° = 33.1 kJ/mol at 25°C, above what minimum temperature will the reaction become spontaneous under standard state conditions?
A)0.4 K
B)3.9 K
C)321 K
D)401 K
E)525 K
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26
Calculate Kp at 298 K for the reaction SO2(g)+ NO2(g) SO3(g)+ NO(g). 
A)6.99 * 10-7
B)5.71 * 10-8
C)14.2
D)475
E)1.42 * 106

A)6.99 * 10-7
B)5.71 * 10-8
C)14.2
D)475
E)1.42 * 106
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27
The element oxygen was prepared by Joseph Priestley in 1774 by heating mercury(II)oxide: HgO(s) Hg(l)+ 1/2O2(g), H° = 90.84 kJ/mol.
Estimate the temperature at which this reaction will become spontaneous under standard state conditions.
S°(Hg)= 76.02 J/K·mol
S°(O2)= 205.0 J/K·mol
S°(HgO)= 70.29 J/K·mol
A)108 K
B)430 K
C)620 K
D)775 K
E)840 K
Estimate the temperature at which this reaction will become spontaneous under standard state conditions.
S°(Hg)= 76.02 J/K·mol
S°(O2)= 205.0 J/K·mol
S°(HgO)= 70.29 J/K·mol
A)108 K
B)430 K
C)620 K
D)775 K
E)840 K
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28
Ozone (O3)in the atmosphere can reaction with nitric oxide (NO): O3(g)+ NO(g) NO2(g)+ O2(g).
Calculate the G° for this reaction at 25°C. ( H° = -199 kJ/mol, S° = -4.1 J/K·mol)
A)1020 kJ/mol
B)-1.22 * 103 kJ/mol
C)2.00 * 103 kJ/mol
D)-1.42 * 103 kJ/mol
E)-198 kJ/mol
Calculate the G° for this reaction at 25°C. ( H° = -199 kJ/mol, S° = -4.1 J/K·mol)
A)1020 kJ/mol
B)-1.22 * 103 kJ/mol
C)2.00 * 103 kJ/mol
D)-1.42 * 103 kJ/mol
E)-198 kJ/mol
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29
Determine the equilibrium constant (Kp)at 25°C for the reaction CO(g)+ H2O(g) CO2(g)+ H2(g) G° = -28.5 kJ/mol.
A)2.9 * 10-60
B)1.0 * 10-4
C)1.2
D)1.0 * 105
E)3.4 * 1059
A)2.9 * 10-60
B)1.0 * 10-4
C)1.2
D)1.0 * 105
E)3.4 * 1059
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30
Nitrosyl chloride (NOCl)decomposes at elevated temperatures according to the equation 2NOCl(g) 2NO(g)+ Cl2(g). Calculate Kp for this reaction at 227°C. ( H° = 81.2 kJ/mol, S° = 128 J/K·mol)
A)1.59 * 10-2
B)2.10 * 10-7
C)62.8
D)4.90 * 106
E)3.20 * 109
A)1.59 * 10-2
B)2.10 * 10-7
C)62.8
D)4.90 * 106
E)3.20 * 109
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31
For the reaction 2C(graphite)+ H2(g) C2H2(g), G°= +209.2 kJ/mol at 25°C. If P(H2)= 100. atm, and P(C2H2)= 0.10 atm, calculate G for this reaction.
A)+207.8 kJ/mol
B)+226.3 kJ/mol
C)+192.1 kJ/mol
D)+17.3 kJ/mol
E)-16.9 kJ/mol
A)+207.8 kJ/mol
B)+226.3 kJ/mol
C)+192.1 kJ/mol
D)+17.3 kJ/mol
E)-16.9 kJ/mol
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32
Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion. 4Al(s)+ 3O2(g) 2Al2O3(s)
Calculate G° for this reaction, given that G°f of aluminum oxide is -1576.4 kJ/mol.
A)-3152.8 kJ/mol
B)-1576.4 kJ/mol
C)-788.2 kJ/mol
D)1576.4 kJ/mol
E)3152.8 kJ/mol
Calculate G° for this reaction, given that G°f of aluminum oxide is -1576.4 kJ/mol.
A)-3152.8 kJ/mol
B)-1576.4 kJ/mol
C)-788.2 kJ/mol
D)1576.4 kJ/mol
E)3152.8 kJ/mol
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33
The equilibrium constant at 427°C for the reaction N2(g)+ 3H2(g) 2NH3(g)is Kp = 9.4 * 10-5. Calculate the value of G° for the reaction under these conditions.
A)-33 kJ/mol
B)-54 kJ/mol
C)54 kJ/mol
D)33 kJ/mol
E)1.3 J/mol
A)-33 kJ/mol
B)-54 kJ/mol
C)54 kJ/mol
D)33 kJ/mol
E)1.3 J/mol
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34
Calculate the equilibrium constant for the decomposition of water 2H2O(l) 2H2(g)+ O2(g)
At 25°C, given that G°f (H2O(l))= -237.2 kJ/mol.
A)0.83
B)6.3 * 10-84
C)2.5 * 10-42
D)1.6 * 1083
E)4.7 * 105
At 25°C, given that G°f (H2O(l))= -237.2 kJ/mol.
A)0.83
B)6.3 * 10-84
C)2.5 * 10-42
D)1.6 * 1083
E)4.7 * 105
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35
A spontaneous endothermic reaction always
A)causes the surroundings to get colder.
B)bursts into flame.
C)requires a spark to initiate it.
D)releases heat to the surroundings.
A)causes the surroundings to get colder.
B)bursts into flame.
C)requires a spark to initiate it.
D)releases heat to the surroundings.
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36
Calculate G° for the reaction 3NO2(g)+ H2O(l) 2HNO3(l)+ NO(g). 
A)8.7 kJ/mol
B)192 kJ/mol
C)-414 kJ/mol
D)-192 kJ/mol
E)-155 kJ/mol

A)8.7 kJ/mol
B)192 kJ/mol
C)-414 kJ/mol
D)-192 kJ/mol
E)-155 kJ/mol
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37
For the reaction H2(g)+ S(s) H2S(g), H° = -20.2 kJ/mol and S° = +43.1 J/K·mol. Which of these statements is true?
A)The reaction is only spontaneous at low temperatures.
B)The reaction is spontaneous at all temperatures.
C)( G°) becomes less favorable as temperature increases.
D)The reaction is spontaneous only at high temperatures.
E)The reaction is at equilibrium at 25°C under standard conditions.
A)The reaction is only spontaneous at low temperatures.
B)The reaction is spontaneous at all temperatures.
C)( G°) becomes less favorable as temperature increases.
D)The reaction is spontaneous only at high temperatures.
E)The reaction is at equilibrium at 25°C under standard conditions.
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38
Hydrogen peroxide (H2O2)decomposes according to the equation H2O2(l) H2O(l)+ 1/2O2(g).
Calculate Kp for this reaction at 25°C. ( H° = -98.2 kJ/mol, S° = 70.1 J/K·mol)
A)1.3 * 10-21
B)20.9
C)3.46 * 1017
D)7.5 * 1020
E)8.6 * 104
Calculate Kp for this reaction at 25°C. ( H° = -98.2 kJ/mol, S° = 70.1 J/K·mol)
A)1.3 * 10-21
B)20.9
C)3.46 * 1017
D)7.5 * 1020
E)8.6 * 104
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39
The equilibrium constant for the reaction AgBr(s) Ag+(aq)+ Br- (aq)is the solubility product constant, Ksp = 7.7* 10-13 at 25°C. Calculate G for the reaction when [Ag+] = 1.0 * 10-2 M and [Br-] = 1.0 * 10-3 M. Is the reaction spontaneous or nonspontaneous at these concentrations?
A)( G) = 69.1 kJ/mol, nonspontaneous
B)( G) = -69.1 kJ/mol, spontaneous
C)( G) = 97.5 kJ/mol, spontaneous
D)( G) = 40.6 kJ/mol, nonspontaneous
E)( G) = -97.5 kJ/mol, nonspontaneous
A)( G) = 69.1 kJ/mol, nonspontaneous
B)( G) = -69.1 kJ/mol, spontaneous
C)( G) = 97.5 kJ/mol, spontaneous
D)( G) = 40.6 kJ/mol, nonspontaneous
E)( G) = -97.5 kJ/mol, nonspontaneous
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40
The normal freezing point of ammonia is -78°C. Predict the signs of H, S, and G for ammonia when it freezes at -80°C and 1 atm: NH3(l) NH3(s) H S G
A)- - 0
B)- + -
C)+ - +
D)+ + 0
E)- - -
A)- - 0
B)- + -
C)+ - +
D)+ + 0
E)- - -
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41
For the reaction CuS(s)+ H2(g) H2S(g)+ Cu(s),
G°f (CuS)= -53.6 kJ/mol
G°f (H2S)= -33.6 kJ/mol
H°f (CuS)= -53.1 kJ/mol
H°f (H2S)= -20.6 kJ/mol
Calculate the value of the equilibrium constant (Kp)at 798 K and 1 atm pressure.
G°f (CuS)= -53.6 kJ/mol
G°f (H2S)= -33.6 kJ/mol
H°f (CuS)= -53.1 kJ/mol
H°f (H2S)= -20.6 kJ/mol
Calculate the value of the equilibrium constant (Kp)at 798 K and 1 atm pressure.
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42
The reaction rates of many spontaneous reactions are actually very slow. Which of these statements is the best explanation for this observation?
A)Kp for the reaction is less than one.
B)The activation energy of the reaction is large.
C)( G°) for the reaction is positive.
D)Such reactions are endothermic.
E)The entropy change is negative.
A)Kp for the reaction is less than one.
B)The activation energy of the reaction is large.
C)( G°) for the reaction is positive.
D)Such reactions are endothermic.
E)The entropy change is negative.
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43
In the gas phase, methyl isocyanate (CH3NC)isomerizes to acetonitrile (CH3CN), H3C-N C (g) H3C-C N (g)
With H° = -89.5 kJ/mol and G° = -73.8 kJ/mol at 25°C. Find the equilibrium constant for this reaction at 100°C.
A)1.68 * 10-10
B)5.96 * 109
C)2.16 * 1010
D)4.63 * 10-11
E)8.64 * 1012
With H° = -89.5 kJ/mol and G° = -73.8 kJ/mol at 25°C. Find the equilibrium constant for this reaction at 100°C.
A)1.68 * 10-10
B)5.96 * 109
C)2.16 * 1010
D)4.63 * 10-11
E)8.64 * 1012
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44
For the reaction HCONH2(g) NH3(g)+ CO(g), Kc = 4.84 at 400 K. If H° for this reaction is 29 kJ/mol, find Kc at 500 K.
A)5.8
B)0.17
C)27
D)0.88
E)10.3
A)5.8
B)0.17
C)27
D)0.88
E)10.3
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45
Find the temperature at which the reaction N2O4(g) 2NO2(g)will be in equilibrium when both gases are present at partial pressures of 1.00 atm. 
A)300°C
B)28°C
C)55°C
D)32°C
E)562°C

A)300°C
B)28°C
C)55°C
D)32°C
E)562°C
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46
Predict the normal boiling point of triethylborane (C6H15B)using the following data: 
A)92°C
B)-21°C
C)21°C
D)365°C
E)256°C

A)92°C
B)-21°C
C)21°C
D)365°C
E)256°C
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47
In the gas phase, formic acid forms a dimmer, 2HCOOH(g) (HCOOH)2(g). For this reaction, H° = -60.1 kJ/mol and G° = -13.9 kJ/mol at 25°C. Find the equilibrium constant (Kp)for this reaction at 75 °C.
A)8960
B)273
C)0.120
D)8.33
E)1.12 * 10-4
A)8960
B)273
C)0.120
D)8.33
E)1.12 * 10-4
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48
Using the thermodynamic data provided below, calculate the standard change in entropy when one mole of sodium sulfate is dissolved in water?
Will the solubility of sodium nitrate increase or decrease if the temperature of the system is increased?

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49
Which species will have the lowest absolute entropy at 25°C?
A)C2H5OH(l)
B)C2H2(g)
C)C3H8(g)
D)C3H7OH(l)
E)C2H6(g)
A)C2H5OH(l)
B)C2H2(g)
C)C3H8(g)
D)C3H7OH(l)
E)C2H6(g)
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50
For the reaction CuS(s)+ H2(g) H2S(g)+ Cu(s),
G°f (CuS)= -53.6 kJ/mol
G°f (H2S)= -33.6 kJ/mol
H°f (CuS)= -53.1 kJ/mol
H°f (H2S)= -20.6 kJ/mol
Will this reaction proceed spontaneously at 298 K and 1 atm pressure?
G°f (CuS)= -53.6 kJ/mol
G°f (H2S)= -33.6 kJ/mol
H°f (CuS)= -53.1 kJ/mol
H°f (H2S)= -20.6 kJ/mol
Will this reaction proceed spontaneously at 298 K and 1 atm pressure?
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51
For the reaction CuS(s)+ H2(g) H2S(g)+ Cu(s),
G°f (CuS)= -53.6 kJ/mol
G°f (H2S)= -33.6 kJ/mol
H°f (CuS)= -53.1 kJ/mol
H°f (H2S)= -20.6 kJ/mol
Calculate the value of the equilibrium constant (Kp)for this reaction at 298 K.
G°f (CuS)= -53.6 kJ/mol
G°f (H2S)= -33.6 kJ/mol
H°f (CuS)= -53.1 kJ/mol
H°f (H2S)= -20.6 kJ/mol
Calculate the value of the equilibrium constant (Kp)for this reaction at 298 K.
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52
Using the thermodynamic data provided below, calculate the standard change in entropy when one mole of sodium nitrate is dissolved in water?
Will the solubility of sodium nitrate increase or decrease if the temperature of the system is increased?

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53
Find the temperature at which Kp = 42.0 for the reaction H2(g)+ I2(g) 2HI(g). [Given: at 25°C, for H2(g), H°f = 0, S° = 131.0 J/mol·K; for I2(g), H°f = 62.26 kJ/mol, S° = 260.6 J/mol·K; for HI(g), H°f = 25.9 kJ/mol, S° = 206.3 J/mol·K; assume that H° and S° are independent of temperature.]
A)1040 K
B)168 K
C)539 K
D)1400 K
E)34,200 K
A)1040 K
B)168 K
C)539 K
D)1400 K
E)34,200 K
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54
The standard free energy of formation of gaseous hydrogen iodide is 1.30 kJ/mol at 25°C. Find Kp for the reaction H2(g)+ I2(s) 2HI(g)at this temperature.
A)7.0
B)7100
C)1.0
D)2.4
E)2.9
A)7.0
B)7100
C)1.0
D)2.4
E)2.9
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55
Find the temperature at which Kp = 4.00 for the reaction N2O4(g) 2NO2(g). [Given: at 25°C, for NO2(g), H°f = 33.85 kJ/mol, S° = 240.46 J/mol·K; for N2O4(g), H°f = 9.66 kJ/mol, S° = 304.3 J/mol·K; assume that H° and S° are independent of temperature.]
A)197 °C
B)56 °C
C)36 °C
D)79 °C
E)476°C
A)197 °C
B)56 °C
C)36 °C
D)79 °C
E)476°C
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56
The solubility product constant at 25°C for AgI(s)in water has the value 8.3 * 10-17. Calculate Grxn at 25°C for the process AgI(s) Ag+(aq)+ I- (aq)where [Ag+] = 9.1 * 10-9 and [I-] = 9.1 * 10-9.
A)+4.4 kJ/mol
B)+91.7 kJ/mol
C)0.0 kJ/mol
D)-91.7 kJ/mol
E)-4.4 kJ/mol
A)+4.4 kJ/mol
B)+91.7 kJ/mol
C)0.0 kJ/mol
D)-91.7 kJ/mol
E)-4.4 kJ/mol
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57
For the reaction CuS(s)+ H2(g) H2S(g)+ Cu(s),
G°f (CuS)= -53.6 kJ/mol
G°f (H2S)= -33.6 kJ/mol
H°f (CuS)= -53.1 kJ/mol
H°f (H2S)= -20.6 kJ/mol
Calculate G at 798 K and 1 atm pressure (assume S° and H° do not change with temperature).
G°f (CuS)= -53.6 kJ/mol
G°f (H2S)= -33.6 kJ/mol
H°f (CuS)= -53.1 kJ/mol
H°f (H2S)= -20.6 kJ/mol
Calculate G at 798 K and 1 atm pressure (assume S° and H° do not change with temperature).
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58
A sample of solid naphthalene is introduced into an evacuated flask. Use the data below to calculate the equilibrium vapor pressure of naphthalene (C10H8)in the flask at 35°C. 
A)890. mmHg
B)0.21 mmHg
C)696 mmHg
D)0.086 mmHg
E)833 mmHg

A)890. mmHg
B)0.21 mmHg
C)696 mmHg
D)0.086 mmHg
E)833 mmHg
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59
Which species will have the greatest absolute entropy at 25°C?
A)Ne(g)
B)C2H2(g)
C)H2O(l)
D)C2H5OH(l)
E)C4H10(g)
A)Ne(g)
B)C2H2(g)
C)H2O(l)
D)C2H5OH(l)
E)C4H10(g)
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60
Calculate G° for the combustion of ethanol vapor, C2H5OH(g), at 750°C in oxygen to form carbon dioxide and water vapor. The following data is valid at 25°C: 
A)-1407 kJ/mol
B)-2151 kJ/mol
C)-1307 kJ/mol
D)-4486 kJ/mol
E)-1377 kJ/mol

A)-1407 kJ/mol
B)-2151 kJ/mol
C)-1307 kJ/mol
D)-4486 kJ/mol
E)-1377 kJ/mol
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61
For the reaction 3H2(g)+ N2(g) 2NH3(g), Kc = 9.0 at 350°C. What is the value of G at this temperature when 1.0 mol NH3, 5.0 mol N2, and 5.0 mol H2 are mixed in a 2.5 L reactor?
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62
Is the reaction SiO2(s)+ Pb(s) PbO2(s)+ Si(s)spontaneous?
G°f (PbO2)= -217 kJ/mol
G°f (SiO2)= -856 kJ/mol
G°f (PbO2)= -217 kJ/mol
G°f (SiO2)= -856 kJ/mol
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63
Predict the sign of S for the process Ni(s, 50°C) Ni(s, 25°C).
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64
Assuming S° and H° do not vary with temperature, at what temperature will the reaction shown below become spontaneous?
C(s)+ H2O(g) H2(g)+ CO(s)( S° = 133.6 J/K·mol; H° = 131.3 kJ/mol)
C(s)+ H2O(g) H2(g)+ CO(s)( S° = 133.6 J/K·mol; H° = 131.3 kJ/mol)
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65
Predict the sign of S for the reaction O2(g) 2O(g).
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66
For the reaction SbCl5(g) SbCl3(g)+ Cl2(g),
G°f (SbCl5)= -334.34 kJ/mol
G°f (SbCl3)= -301.25 kJ/mol
H°f (SbCl5)= -394.34 kJ/mol
H°f (SbCl3)= -313.80 kJ/mol
Calculate G at 800 K and 1 atm pressure (assume S° and H° do not change with temperature).
G°f (SbCl5)= -334.34 kJ/mol
G°f (SbCl3)= -301.25 kJ/mol
H°f (SbCl5)= -394.34 kJ/mol
H°f (SbCl3)= -313.80 kJ/mol
Calculate G at 800 K and 1 atm pressure (assume S° and H° do not change with temperature).
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67
For the reaction SbCl5(g) SbCl3(g)+ Cl2(g),
G°f (SbCl5)= -334.34 kJ/mol
G°f (SbCl3)= -301.25 kJ/mol
H°f (SbCl5)= -394.34 kJ/mol
H°f (SbCl3)= -313.80 kJ/mol
Calculate the value of the equilibrium constant (Kp)at 800 K and 1 atm pressure.
G°f (SbCl5)= -334.34 kJ/mol
G°f (SbCl3)= -301.25 kJ/mol
H°f (SbCl5)= -394.34 kJ/mol
H°f (SbCl3)= -313.80 kJ/mol
Calculate the value of the equilibrium constant (Kp)at 800 K and 1 atm pressure.
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68
For the reaction SbCl5(g) SbCl3(g)+ Cl2(g),
G°f (SbCl5)= -334.34 kJ/mol
G°f (SbCl3)= -301.25 kJ/mol
H°f (SbCl5)= -394.34 kJ/mol
H°f (SbCl3)= -313.80 kJ/mol
Calculate the value of the equilibrium constant (Kp)for this reaction at 298 K.
G°f (SbCl5)= -334.34 kJ/mol
G°f (SbCl3)= -301.25 kJ/mol
H°f (SbCl5)= -394.34 kJ/mol
H°f (SbCl3)= -313.80 kJ/mol
Calculate the value of the equilibrium constant (Kp)for this reaction at 298 K.
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69
For a certain reaction, G° = 87 kJ/mol, H° = 100 kJ/mol at STP. At what temperature, in K, is the reaction in equilibrium, assuming that S° and H° are temperature-independent?
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70
What is the free energy change for the reaction SiO2(s)+ Pb(s) PbO2(s)+ Si(s)?
G°f (PbO2)= -217 kJ/mol
G°f (SiO2)= -856 kJ/mol
G°f (PbO2)= -217 kJ/mol
G°f (SiO2)= -856 kJ/mol
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71
Rubidium has a heat of vaporization of 69.0 kJ/mol at its boiling point (686°C). Calculate S for this process, Rb(l) Rb(g), at 1 atm and 686°C.
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72
The following reaction is nonspontaneous at 25°C:
Cu2O(s) 2Cu(s)+ 1/2O2(g), G° = 141 kJ/mol
If S° = 75.8 J/K·mol, what is the lowest temperature at which the reaction will be spontaneous?
Cu2O(s) 2Cu(s)+ 1/2O2(g), G° = 141 kJ/mol
If S° = 75.8 J/K·mol, what is the lowest temperature at which the reaction will be spontaneous?
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73
For the reaction 3H2(g)+ N2(g) 2NH3(g), Kc = 9.0 at 350°C. Calculate G° at 350°C.
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74
The heat of vaporization of water is 2.27 kJ/g. What is Svap per mole at the normal boiling point?
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75
Predict the sign of S for the process N2(g, 10 atm) N2(g, 1atm).
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76
For the reaction 3H2(g)+ N2(g) 2NH3(g), Kc = 9.0 at 350°C. In what direction does this reaction proceed at 350°C under standard state conditions?
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77
For the reaction SbCl5(g) SbCl3(g)+ Cl2(g),
G°f (SbCl5)= -334.34 kJ/mol
G°f (SbCl3)= -301.25 kJ/mol
H°f (SbCl5)= -394.34 kJ/mol
H°f (SbCl3)= -313.80 kJ/mol
Will this reaction proceed spontaneously at 298 K and 1 atm pressure?
G°f (SbCl5)= -334.34 kJ/mol
G°f (SbCl3)= -301.25 kJ/mol
H°f (SbCl5)= -394.34 kJ/mol
H°f (SbCl3)= -313.80 kJ/mol
Will this reaction proceed spontaneously at 298 K and 1 atm pressure?
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78
Predict the sign of S for the reaction 6CO2(g)+ 6H2O(g) C6H12O6(g)+ 6O2(g).
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79
Calculate the free energy of formation of NaBr(s)given the following information:
NaBr(s) Na(s)+ 1/2Br2(l), G° = 349 kJ/mol
NaBr(s) Na(s)+ 1/2Br2(l), G° = 349 kJ/mol
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80
The free energy of formation of nitric oxide, NO, at 1000 K (roughly the temperature in an automobile engine during ignition)is about 78 kJ/mol. Calculate the equilibrium constant Kp for the reaction N2(g)+ O2(g) 2NO(g)at this temperature.
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