Deck 9: Analytical Geometry

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Question
Three non-colinear points are given and can be connected with line segments to form a triangle. Find the perimeter of the triangle (rounded to the nearest tenth as needed) and determine if the triangle is a right triangle.
P1 = (3, 6)
P2 = (0, 6)
P3 = (7, -3)
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Question
Line segments ( <strong>Line segments (   ) and (   ) have the endpoints indicated. Use the slope formula to determine if the segments are parallel, perpendicular or simply intersect. A(-3, 4) B(5, -2) C(-4, 3) D(3, 5)</strong> A) parallel B) perpendicular C) intersect <div style=padding-top: 35px> ) and ( <strong>Line segments (   ) and (   ) have the endpoints indicated. Use the slope formula to determine if the segments are parallel, perpendicular or simply intersect. A(-3, 4) B(5, -2) C(-4, 3) D(3, 5)</strong> A) parallel B) perpendicular C) intersect <div style=padding-top: 35px> ) have the endpoints indicated. Use the slope formula to determine if the segments are parallel, perpendicular or simply intersect. A(-3, 4) B(5, -2)
C(-4, 3) D(3, 5)

A) parallel
B) perpendicular
C) intersect
Question
A theorem from elementary geometry states: If P1 and P2 are on opposite sides of a line segment and an equal distance from the endpoints, then the line through P1 and P2 is a perpendicular bisector of the segment. Verify this is true for the segment and points shown. A theorem from elementary geometry states: If P<sub>1</sub> and P<sub>2</sub> are on opposite sides of a line segment and an equal distance from the endpoints, then the line through P<sub>1</sub> and P<sub>2</sub> is a perpendicular bisector of the segment. Verify this is true for the segment and points shown.  <div style=padding-top: 35px>
Question
A theorem from elementary geometry states: If the diagonals of a quadrilateral have equal length and bisect each other, then the quadrilateral is a rectangle. Verify the points A(-1, 4), B(5, 1), C(3, -3), and D(-3, 0) are the vertices of a rectangle.
Question
Line segments ( <strong>Line segments (   ) and (   ) have the endpoints indicated. Use the slope formula to determine if the segments are parallel, perpendicular or simply intersect. A(-1, 4) B(1, -6) C(-5, 0) D(5, 2)</strong> A) parallel B) perpendicular C) intersect <div style=padding-top: 35px> ) and ( <strong>Line segments (   ) and (   ) have the endpoints indicated. Use the slope formula to determine if the segments are parallel, perpendicular or simply intersect. A(-1, 4) B(1, -6) C(-5, 0) D(5, 2)</strong> A) parallel B) perpendicular C) intersect <div style=padding-top: 35px> ) have the endpoints indicated. Use the slope formula to determine if the segments are parallel, perpendicular or simply intersect. A(-1, 4) B(1, -6)
C(-5, 0) D(5, 2)

A) parallel
B) perpendicular
C) intersect
Question
Complete the square in both x and y to write the equation in standard form. 4x2 + 16y2 + 16x - 64y + 16 = 0

A) <strong>Complete the square in both x and y to write the equation in standard form. 4x<sup>2</sup> + 16y<sup>2</sup> + 16x - 64y + 16 = 0</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>Complete the square in both x and y to write the equation in standard form. 4x<sup>2</sup> + 16y<sup>2</sup> + 16x - 64y + 16 = 0</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>Complete the square in both x and y to write the equation in standard form. 4x<sup>2</sup> + 16y<sup>2</sup> + 16x - 64y + 16 = 0</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>Complete the square in both x and y to write the equation in standard form. 4x<sup>2</sup> + 16y<sup>2</sup> + 16x - 64y + 16 = 0</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
Write the equation in standard form and identify the center and the values of a and b.
x2 + 9y2 = 36
Question
Identify the equation as that of an ellipse or a circle. 5(x - 5)2 + 5(y + 7)2 = 80.

A) ellipse
B) circle
Question
Write the equation in standard form and sketch the graph.
x2 + 9y2 = 36
Question
Graph the hyperbola. Label the vertices. <strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>

A)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
B)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
C)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
D)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
Question
Complete the square in both x and y to write the equation in standard form. Then draw a complete graph of the relation and identify all important features.
9x2 + 4y2 - 18x + 16y - 11 = 0
Question
Show the figure drawn by connecting points A(-3, 1), B(4, -5), C(5, -1), and D(-2, 5) is a parallelogram (opposite sides parallel and equal in length).
Question
Of the following four points, three are an equal distance from the point P(3, 4) and one is not. Identify which three.
Q(6, 8) R(-1, 1) S <strong>Of the following four points, three are an equal distance from the point P(3, 4) and one is not. Identify which three. Q(6, 8) R(-1, 1) S    </strong> A) Q, R, S B) Q, R, T C) Q, S, T D) R, S, T <div style=padding-top: 35px> <strong>Of the following four points, three are an equal distance from the point P(3, 4) and one is not. Identify which three. Q(6, 8) R(-1, 1) S    </strong> A) Q, R, S B) Q, R, T C) Q, S, T D) R, S, T <div style=padding-top: 35px>

A) Q, R, S
B) Q, R, T
C) Q, S, T
D) R, S, T
Question
Find two additional points that are the same (non-vertical, non-horizontal) distance from the point P(-5, 2) as S Find two additional points that are the same (non-vertical, non-horizontal) distance from the point P(-5, 2) as S   .<div style=padding-top: 35px> .
Question
Sketch the graph of the ellipse. <strong>Sketch the graph of the ellipse.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>

A)
<strong>Sketch the graph of the ellipse.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
B)
<strong>Sketch the graph of the ellipse.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
C)
<strong>Sketch the graph of the ellipse.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
D)
<strong>Sketch the graph of the ellipse.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
Question
Identify the equation as that of an ellipse or a circle. 9(x - 7)2 + 4(y + 6)2 = 36.

A) ellipse
B) circle
Question
Line segments ( <strong>Line segments (   ) and (   ) have the endpoints indicated. Use the slope formula to determine if the segments are parallel, perpendicular or simply intersect. A(-4, 2) B(3, -4) C(-2, 5) D(5, -1)</strong> A) parallel B) perpendicular C) intersect <div style=padding-top: 35px> ) and ( <strong>Line segments (   ) and (   ) have the endpoints indicated. Use the slope formula to determine if the segments are parallel, perpendicular or simply intersect. A(-4, 2) B(3, -4) C(-2, 5) D(5, -1)</strong> A) parallel B) perpendicular C) intersect <div style=padding-top: 35px> ) have the endpoints indicated. Use the slope formula to determine if the segments are parallel, perpendicular or simply intersect. A(-4, 2) B(3, -4)
C(-2, 5) D(5, -1)

A) parallel
B) perpendicular
C) intersect
Question
Sketch the graph of the ellipse. Sketch the graph of the ellipse.  <div style=padding-top: 35px>
Question
Three non-colinear points are given and can be connected with line segments to form a triangle. Find the perimeter of the triangle (rounded to the nearest tenth as needed) and determine if the triangle is a right triangle. P1 = (-8, 2)
P2 = (-8, -6)
P3 = (7, 2)

A) perimeter: 33.0; right triangle
B) perimeter: 40.0; not a right triangle
C) perimeter: 40.0; right triangle
D) perimeter: 33.0; not a right triangle
Question
Graph the hyperbola. Label the vertices. <strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>

A)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
B)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
C)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
D)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
Question
Use the following to answer questions :
y = 2x2 - x - 3
Find the x- and y-intercepts (if they exist).

A) x-intercepts: <strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3 Find the x- and y-intercepts (if they exist).</strong> A) x-intercepts:   ; y-intercept: (0, 3) B) x-intercepts:   ; y-intercept: (0, -3) C) x-intercepts:   ; y-intercept: (0, -3) D) x-intercepts: none; y-intercept: (0, -3) <div style=padding-top: 35px> ; y-intercept: (0, 3)
B) x-intercepts: <strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3 Find the x- and y-intercepts (if they exist).</strong> A) x-intercepts:   ; y-intercept: (0, 3) B) x-intercepts:   ; y-intercept: (0, -3) C) x-intercepts:   ; y-intercept: (0, -3) D) x-intercepts: none; y-intercept: (0, -3) <div style=padding-top: 35px> ; y-intercept: (0, -3)
C) x-intercepts: <strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3 Find the x- and y-intercepts (if they exist).</strong> A) x-intercepts:   ; y-intercept: (0, 3) B) x-intercepts:   ; y-intercept: (0, -3) C) x-intercepts:   ; y-intercept: (0, -3) D) x-intercepts: none; y-intercept: (0, -3) <div style=padding-top: 35px> ; y-intercept: (0, -3)
D) x-intercepts: none; y-intercept: (0, -3)
Question
Classify the equation as that of a circle, ellipse, hyperbola, or none of the above. 4x2 + 9y2 - 40x - 18y = -73

A) Circle
B) Ellipse
C) Hyperbola
D) None of these
Question
Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices. <strong>Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>

A)
<strong>Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B)
<strong>Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C)
<strong>Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D)
<strong>Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.
(x - 1)2 - 9(y - 2)2 = 9
Question
Use the following to answer questions :
y = x2 - 4x + 3
Find the vertex.
Question
Graph the hyperbola. Label the vertices. Graph the hyperbola. Label the vertices.  <div style=padding-top: 35px>
Question
Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices. Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.  <div style=padding-top: 35px>
Question
For the graph given, state the location of the vertices, the equation of the transverse axis, the location of the center, and the equation of the conjugate axis. <strong>For the graph given, state the location of the vertices, the equation of the transverse axis, the location of the center, and the equation of the conjugate axis.   (Gridlines are spaced one unit apart.)</strong> A) vertices: (1, 2), (1, 4); transverse axis: x = 3; center (1, 3); conjugate axis: y = 1 B) vertices: (1, 2), (1, 4); transverse axis: y = 3; center (1, 3); conjugate axis: x = 1 C) vertices: (1, 2), (1, 4); transverse axis: x = 1; center (1, 3); conjugate axis: y = 3 D) vertices: (1, 2), (1, 4); transverse axis: y = 1; center (1, 3); conjugate axis: x = 3 <div style=padding-top: 35px> (Gridlines are spaced one unit apart.)

A) vertices: (1, 2), (1, 4); transverse axis: x = 3; center (1, 3); conjugate axis: y = 1
B) vertices: (1, 2), (1, 4); transverse axis: y = 3; center (1, 3); conjugate axis: x = 1
C) vertices: (1, 2), (1, 4); transverse axis: x = 1; center (1, 3); conjugate axis: y = 3
D) vertices: (1, 2), (1, 4); transverse axis: y = 1; center (1, 3); conjugate axis: x = 3
Question
Classify the equation as that of a circle, ellipse, hyperbola, or none of the above. 9x2 + 9y2 - 18x + 72y + 72 = 0

A) Circle
B) Ellipse
C) Hyperbola
D) None of these
Question
Classify the equation as that of a circle, ellipse, hyperbola, or none of the above. 4x2 - 7y2 = 28

A) Circle
B) Ellipse
C) Hyperbola
D) None of these
Question
Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices. <strong>Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>

A)
<strong>Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B)
<strong>Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C)
<strong>Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D)
<strong>Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
For the graph given, state
(a) the location of the vertices
(b) the equation of the transverse axis
(c) the location of the center
(d) the equation of the conjugate axis
Assume all coordinates are lattice points. For the graph given, state (a) the location of the vertices (b) the equation of the transverse axis (c) the location of the center (d) the equation of the conjugate axis Assume all coordinates are lattice points.   (Gridlines are spaced one unit apart.)<div style=padding-top: 35px> (Gridlines are spaced one unit apart.)
Question
Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.
x2 - 9y2 - 6x - 36y - 36 = 0
Question
Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices. Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.  <div style=padding-top: 35px>
Question
Graph the hyperbola. Label the vertices. <strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>

A)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
B)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
C)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
D)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
Question
Classify the equation as that of a circle, ellipse, hyperbola, or none of the above. 9x2 = -49y2 + 441

A) Circle
B) Ellipse
C) Hyperbola
D) None of these
Question
Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.
25y2 - 4x2 = 100
Question
Classify the equation as that of a circle, ellipse, hyperbola, or none of the above. 8y2 - 4 = 5x2 + 36

A) Circle
B) Ellipse
C) Hyperbola
D) None of these
Question
Classify the equation as that of a circle, ellipse, hyperbola, or none of the above. -2x2 + -2y2= -20

A) Circle
B) Ellipse
C) Hyperbola
D) None of these
Question
Use the following to answer questions :
y = x2 - 4x + 3
Find the x- and y-intercepts (if they exist).
Question
Use the following to answer questions :
x = -y2 + 6y - 8
Sketch the graph using symmetry and a few additional points.

A)
<strong>Use the following to answer questions : x = -y<sup>2</sup> + 6y - 8 Sketch the graph using symmetry and a few additional points.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
B)
<strong>Use the following to answer questions : x = -y<sup>2</sup> + 6y - 8 Sketch the graph using symmetry and a few additional points.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
C)
<strong>Use the following to answer questions : x = -y<sup>2</sup> + 6y - 8 Sketch the graph using symmetry and a few additional points.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
D)
<strong>Use the following to answer questions : x = -y<sup>2</sup> + 6y - 8 Sketch the graph using symmetry and a few additional points.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
Question
Use the following to answer questions :
y = 2x2 - x - 3
Sketch the graph using symmetry and a few additional points or completing the square and shifting a parent function.

A)
<strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3 Sketch the graph using symmetry and a few additional points or completing the square and shifting a parent function.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
B)
<strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3 Sketch the graph using symmetry and a few additional points or completing the square and shifting a parent function.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
C)
<strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3 Sketch the graph using symmetry and a few additional points or completing the square and shifting a parent function.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
D)
<strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3 Sketch the graph using symmetry and a few additional points or completing the square and shifting a parent function.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
Question
Use the following to answer questions :
x = -y2 + 6y - 8
Find the x- and y-intercepts, if they exist.

A) x-intercepts: (2, 0), (4, 0); y-intercept: (0, -8)
B) x-intercept: (2, 0); y-intercepts: (0, -8), (0, 4)
C) x-intercept: (-8, 0); y-intercepts: (0, 2), (0, 4)
D) x-intercepts: none; y-intercept (0, -8)
Question
(a) Sketch x = y2 + 4y + 3 using symmetry and shifts of a basic function.
(b) Find the x- and y-intercepts (if they exist).
(c) Find the vertex.
(d) State the domain and range of the relation.
Question
(a) Sketch x = y2 - 4y using symmetry and shifts of a basic function.
(b) Find the x- and y-intercepts (if they exist).
(c) Find the vertex.
(d) State the domain and range of the relation.
Question
Use the following to answer questions :
x2 = 28y
Find the directrix.
Question
Use the following to answer questions :
y2 = 36x
Find the directrix.

A) y = -8
B) y = 8
C) x = -8
D) x = 8
Question
Use the following to answer questions :
x = y2 - 2y - 3
Find the vertex.
Question
Use the following to answer questions :
x = y2 - 2y - 3
Find the x- and y-intercepts, if they exist.
Question
Sketch x = (y - 1)2 - 4 using symmetry and shifts of a basic function.

A)
<strong>Sketch x = (y - 1)<sup>2</sup> - 4 using symmetry and shifts of a basic function.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
B)
<strong>Sketch x = (y - 1)<sup>2</sup> - 4 using symmetry and shifts of a basic function.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
C)
<strong>Sketch x = (y - 1)<sup>2</sup> - 4 using symmetry and shifts of a basic function.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
D)
<strong>Sketch x = (y - 1)<sup>2</sup> - 4 using symmetry and shifts of a basic function.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.) <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
Question
Use the following to answer questions :
x2 = 28y
Find the vertex.
Question
Use the following to answer questions :
x = -y2 + 6y - 8

-State the domain and range.

A) x \in (- \infty , 1]; y \in (- \infty , \infty )
B) x \in (- \infty , \infty ); y \in (- \infty , 3]
C) x \in [3, \infty ); y \in (- \infty , \infty )
D) x \in (- \infty , \infty ); y \in (- \infty , \infty )
Question
Find the vertex, focus, and directrix for the parabola given, then use this information to sketch a complete graph (illustrate these features).
y2 = -8x
Question
Use the following to answer questions :
y = 2x2 - x - 3
Find the vertex.

A) <strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3 Find the vertex.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3 Find the vertex.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3 Find the vertex.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3 Find the vertex.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
Use the following to answer questions :
x2 = 28y
Find the focus.
Question
Use the following to answer questions :
y2 = 36x
Find the focus.

A) (0, -6)
B) (0, -24)
C) (-6, 0)
D) (-24, 0)
Question
Use the following to answer questions :
y = 2x2 - x - 3

-State the domain and range.

A) x \in (- \infty , \infty ); y \in  <strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3  -State the domain and range.</strong> A) x  \in  (- \infty ,  \infty ); y  \in     B) x  \in    ; y  \in   (- \infty ,  \infty ) C) x  \in   (- \infty ,  \infty ); y  \in    D) x  \in   (- \infty , \infty ); y  \in  (- \infty ,  \infty ) <div style=padding-top: 35px>
B) x \in  <strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3  -State the domain and range.</strong> A) x  \in  (- \infty ,  \infty ); y  \in     B) x  \in    ; y  \in   (- \infty ,  \infty ) C) x  \in   (- \infty ,  \infty ); y  \in    D) x  \in   (- \infty , \infty ); y  \in  (- \infty ,  \infty ) <div style=padding-top: 35px>  ; y \in (- \infty , \infty )
C) x \in (- \infty , \infty ); y \in  <strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3  -State the domain and range.</strong> A) x  \in  (- \infty ,  \infty ); y  \in     B) x  \in    ; y  \in   (- \infty ,  \infty ) C) x  \in   (- \infty ,  \infty ); y  \in    D) x  \in   (- \infty , \infty ); y  \in  (- \infty ,  \infty ) <div style=padding-top: 35px>
D) x \in (- \infty , \infty ); y \in (- \infty , \infty )
Question
Use the following to answer questions :
x = -y2 + 6y - 8
Find the vertex.

A) (-80, -6)
B) (-8, 6)
C) (-35, -3)
D) (1, 3)
Question
Use the following to answer questions :
y2 = 36x
Find the vertex.

A) (0, 0)
B) (0, -5)
C) (0, -20)
D) (-20, 0)
Question
Identify each equation in the system as that of a line, parabola, circle, ellipse, or hyperbola, and solve the system by graphing. Identify each equation in the system as that of a line, parabola, circle, ellipse, or hyperbola, and solve the system by graphing.  <div style=padding-top: 35px>
Question
Solve using elimination. <strong>Solve using elimination.  </strong> A) (4, 0), (5, -3), (-5, -3) B) (-4, 0), (5, -3), (5, -3) C) (-4, 0), (5, -3), (5, 3) D) no solutions <div style=padding-top: 35px>

A) (4, 0), (5, -3), (-5, -3)
B) (-4, 0), (5, -3), (5, -3)
C) (-4, 0), (5, -3), (5, 3)
D) no solutions
Question
List three alternate ways the point  List three alternate ways the point   can be expressed in polar coordinates using r > 0, r < 0, and  \theta   \in  [-2 \pi , 2 \pi ).<div style=padding-top: 35px>  can be expressed in polar coordinates using r > 0, r < 0, and θ\theta \in [-2 π\pi , 2 π\pi ).
Question
Plot the point Plot the point   .  <div style=padding-top: 35px> . Plot the point   .  <div style=padding-top: 35px>
Question
Solve using the method of your choice. <strong>Solve using the method of your choice.  </strong> A) (4, 5<sup>24</sup>) B) (-4, 5<sup>8</sup>) C) (4, 5<sup>24</sup>), (-4, 5<sup>8</sup>) D) (4, 5<sup>24</sup>), (-4, -5<sup>8</sup>) <div style=padding-top: 35px>

A) (4, 524)
B) (-4, 58)
C) (4, 524), (-4, 58)
D) (4, 524), (-4, -58)
Question
Solve the system of inequalities. Solve the system of inequalities.  <div style=padding-top: 35px>
Question
Convert from rectangular coordinates to polar coordinates. A diagram may help.
(8, -8)
Question
Plot the point <strong>Plot the point   .</strong> A)   B)   C)   D)   <div style=padding-top: 35px> .

A)
<strong>Plot the point   .</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B)
<strong>Plot the point   .</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C)
<strong>Plot the point   .</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D)
<strong>Plot the point   .</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
Identify each equation in the system as that of a line, parabola, circle, ellipse, or hyperbola, and solve the system by graphing. Identify each equation in the system as that of a line, parabola, circle, ellipse, or hyperbola, and solve the system by graphing.  <div style=padding-top: 35px>
Question
Express the point shown using polar coordinates with θ\theta in radians, 0 \leθ\theta < 2? and r > 0.  Express the point shown using polar coordinates with  \theta in radians, 0 \le\theta  < 2? and r > 0.  <div style=padding-top: 35px>
Question
Solve using elimination. Solve using elimination.  <div style=padding-top: 35px>
Question
Solve using substitution. [Hint: Substitute for y2 (not x).] Solve using substitution. [Hint: Substitute for y<sup>2</sup> (not x).]  <div style=padding-top: 35px>
Question
Convert from rectangular coordinates to polar coordinates. A diagram may help. <strong>Convert from rectangular coordinates to polar coordinates. A diagram may help.  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>

A) <strong>Convert from rectangular coordinates to polar coordinates. A diagram may help.  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>Convert from rectangular coordinates to polar coordinates. A diagram may help.  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>Convert from rectangular coordinates to polar coordinates. A diagram may help.  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>Convert from rectangular coordinates to polar coordinates. A diagram may help.  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
Plot the point Plot the point   .  <div style=padding-top: 35px> . Plot the point   .  <div style=padding-top: 35px>
Question
Solve using substitution. <strong>Solve using substitution.  </strong> A) (0, 5), (5, 0) B) (0, 5), (-5, 0) C) (0, -5), (5, 0) D) (0, -5), (-5, 0) <div style=padding-top: 35px>

A) (0, 5), (5, 0)
B) (0, 5), (-5, 0)
C) (0, -5), (5, 0)
D) (0, -5), (-5, 0)
Question
Solve the system of inequalities. <strong>Solve the system of inequalities.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D) Ø <div style=padding-top: 35px>

A)
<strong>Solve the system of inequalities.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D) Ø <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
B)
<strong>Solve the system of inequalities.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D) Ø <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
C)
<strong>Solve the system of inequalities.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D) Ø <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
D) Ø
Question
Solve the system of inequalities. Solve the system of inequalities.  <div style=padding-top: 35px>
Question
Solve the system of inequalities. Solve the system of inequalities.  <div style=padding-top: 35px>
Question
Solve using the method of your choice. Solve using the method of your choice.  <div style=padding-top: 35px>
Question
Solve the system of inequalities. Solve the system of inequalities.  <div style=padding-top: 35px>
Question
Solve the system of inequalities. <strong>Solve the system of inequalities.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D) Ø <div style=padding-top: 35px>

A)
<strong>Solve the system of inequalities.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D) Ø <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
B)
<strong>Solve the system of inequalities.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D) Ø <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
C)
<strong>Solve the system of inequalities.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D) Ø <div style=padding-top: 35px>
(Gridlines are spaced one unit apart.)
D) Ø
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Deck 9: Analytical Geometry
1
Three non-colinear points are given and can be connected with line segments to form a triangle. Find the perimeter of the triangle (rounded to the nearest tenth as needed) and determine if the triangle is a right triangle.
P1 = (3, 6)
P2 = (0, 6)
P3 = (7, -3)
perimeter: 24.3; not a right triangle
2
Line segments ( <strong>Line segments (   ) and (   ) have the endpoints indicated. Use the slope formula to determine if the segments are parallel, perpendicular or simply intersect. A(-3, 4) B(5, -2) C(-4, 3) D(3, 5)</strong> A) parallel B) perpendicular C) intersect ) and ( <strong>Line segments (   ) and (   ) have the endpoints indicated. Use the slope formula to determine if the segments are parallel, perpendicular or simply intersect. A(-3, 4) B(5, -2) C(-4, 3) D(3, 5)</strong> A) parallel B) perpendicular C) intersect ) have the endpoints indicated. Use the slope formula to determine if the segments are parallel, perpendicular or simply intersect. A(-3, 4) B(5, -2)
C(-4, 3) D(3, 5)

A) parallel
B) perpendicular
C) intersect
intersect
3
A theorem from elementary geometry states: If P1 and P2 are on opposite sides of a line segment and an equal distance from the endpoints, then the line through P1 and P2 is a perpendicular bisector of the segment. Verify this is true for the segment and points shown. A theorem from elementary geometry states: If P<sub>1</sub> and P<sub>2</sub> are on opposite sides of a line segment and an equal distance from the endpoints, then the line through P<sub>1</sub> and P<sub>2</sub> is a perpendicular bisector of the segment. Verify this is true for the segment and points shown.
First show that the conditions of the statement are met.
Although it is evident from the graph that P1 and P2 are on opposite sides of the line segment First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . , it can be proven using the equation of the line First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . .
Find the slope of this line using the endpoints of First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . , R (-6, 7) and S (2, -5) and the slope formula: First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . and use the slope-point to find the equation of the line: First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . It can then be shown that P1(1, 3) is in the half-plane First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . : First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . and P2(-8, -3) is in the half-plane First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . : First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . and they are therefore on opposite sides of the line segment First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . .
Next, use the distance formula to show that P1(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5):
d(P1R) First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . d(P1S) First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . and that P2(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5):
d(P2R) First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . d(P2S) First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . Now show that the line First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . is a perpendicular bisector of First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . .
Use the slope formula to find the slope of the line through P1(1, 3) and P2(-8, -3):

First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . Since First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . from first step, First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . and First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . are perpendicular.
Use the point-slope formula to find the equation of First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . : First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . Find the midpoint of First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . : First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . Show First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . is on First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . : First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . Therefore First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . is a perpendicular bisector of First show that the conditions of the statement are met. Although it is evident from the graph that P<sub>1</sub> and P<sub>2</sub> are on opposite sides of the line segment   , it can be proven using the equation of the line   . Find the slope of this line using the endpoints of   , R (-6, 7) and S (2, -5) and the slope formula:   and use the slope-point to find the equation of the line:   It can then be shown that P<sub>1</sub>(1, 3) is in the half-plane   :   and P<sub>2</sub>(-8, -3) is in the half-plane   :   and they are therefore on opposite sides of the line segment   . Next, use the distance formula to show that P<sub>1</sub>(1, 3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>1</sub>R)   d(P<sub>1</sub>S)   and that P<sub>2</sub>(-8, -3) is an equal distance from the endpoints R (-6, 7) and S (2, -5): d(P<sub>2</sub>R)   d(P<sub>2</sub>S)   Now show that the line   is a perpendicular bisector of   . Use the slope formula to find the slope of the line through P<sub>1</sub>(1, 3) and P<sub>2</sub>(-8, -3):<sub> </sub> <sub> </sub>   Since   from first step,   and   are perpendicular. Use the point-slope formula to find the equation of   :   Find the midpoint of   :   Show   is on   :   Therefore   is a perpendicular bisector of   . .
4
A theorem from elementary geometry states: If the diagonals of a quadrilateral have equal length and bisect each other, then the quadrilateral is a rectangle. Verify the points A(-1, 4), B(5, 1), C(3, -3), and D(-3, 0) are the vertices of a rectangle.
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5
Line segments ( <strong>Line segments (   ) and (   ) have the endpoints indicated. Use the slope formula to determine if the segments are parallel, perpendicular or simply intersect. A(-1, 4) B(1, -6) C(-5, 0) D(5, 2)</strong> A) parallel B) perpendicular C) intersect ) and ( <strong>Line segments (   ) and (   ) have the endpoints indicated. Use the slope formula to determine if the segments are parallel, perpendicular or simply intersect. A(-1, 4) B(1, -6) C(-5, 0) D(5, 2)</strong> A) parallel B) perpendicular C) intersect ) have the endpoints indicated. Use the slope formula to determine if the segments are parallel, perpendicular or simply intersect. A(-1, 4) B(1, -6)
C(-5, 0) D(5, 2)

A) parallel
B) perpendicular
C) intersect
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6
Complete the square in both x and y to write the equation in standard form. 4x2 + 16y2 + 16x - 64y + 16 = 0

A) <strong>Complete the square in both x and y to write the equation in standard form. 4x<sup>2</sup> + 16y<sup>2</sup> + 16x - 64y + 16 = 0</strong> A)   B)   C)   D)
B) <strong>Complete the square in both x and y to write the equation in standard form. 4x<sup>2</sup> + 16y<sup>2</sup> + 16x - 64y + 16 = 0</strong> A)   B)   C)   D)
C) <strong>Complete the square in both x and y to write the equation in standard form. 4x<sup>2</sup> + 16y<sup>2</sup> + 16x - 64y + 16 = 0</strong> A)   B)   C)   D)
D) <strong>Complete the square in both x and y to write the equation in standard form. 4x<sup>2</sup> + 16y<sup>2</sup> + 16x - 64y + 16 = 0</strong> A)   B)   C)   D)
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7
Write the equation in standard form and identify the center and the values of a and b.
x2 + 9y2 = 36
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8
Identify the equation as that of an ellipse or a circle. 5(x - 5)2 + 5(y + 7)2 = 80.

A) ellipse
B) circle
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9
Write the equation in standard form and sketch the graph.
x2 + 9y2 = 36
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10
Graph the hyperbola. Label the vertices. <strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)

A)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
B)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
C)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
D)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
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11
Complete the square in both x and y to write the equation in standard form. Then draw a complete graph of the relation and identify all important features.
9x2 + 4y2 - 18x + 16y - 11 = 0
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12
Show the figure drawn by connecting points A(-3, 1), B(4, -5), C(5, -1), and D(-2, 5) is a parallelogram (opposite sides parallel and equal in length).
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13
Of the following four points, three are an equal distance from the point P(3, 4) and one is not. Identify which three.
Q(6, 8) R(-1, 1) S <strong>Of the following four points, three are an equal distance from the point P(3, 4) and one is not. Identify which three. Q(6, 8) R(-1, 1) S    </strong> A) Q, R, S B) Q, R, T C) Q, S, T D) R, S, T <strong>Of the following four points, three are an equal distance from the point P(3, 4) and one is not. Identify which three. Q(6, 8) R(-1, 1) S    </strong> A) Q, R, S B) Q, R, T C) Q, S, T D) R, S, T

A) Q, R, S
B) Q, R, T
C) Q, S, T
D) R, S, T
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14
Find two additional points that are the same (non-vertical, non-horizontal) distance from the point P(-5, 2) as S Find two additional points that are the same (non-vertical, non-horizontal) distance from the point P(-5, 2) as S   . .
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15
Sketch the graph of the ellipse. <strong>Sketch the graph of the ellipse.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)

A)
<strong>Sketch the graph of the ellipse.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
B)
<strong>Sketch the graph of the ellipse.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
C)
<strong>Sketch the graph of the ellipse.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
D)
<strong>Sketch the graph of the ellipse.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
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16
Identify the equation as that of an ellipse or a circle. 9(x - 7)2 + 4(y + 6)2 = 36.

A) ellipse
B) circle
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17
Line segments ( <strong>Line segments (   ) and (   ) have the endpoints indicated. Use the slope formula to determine if the segments are parallel, perpendicular or simply intersect. A(-4, 2) B(3, -4) C(-2, 5) D(5, -1)</strong> A) parallel B) perpendicular C) intersect ) and ( <strong>Line segments (   ) and (   ) have the endpoints indicated. Use the slope formula to determine if the segments are parallel, perpendicular or simply intersect. A(-4, 2) B(3, -4) C(-2, 5) D(5, -1)</strong> A) parallel B) perpendicular C) intersect ) have the endpoints indicated. Use the slope formula to determine if the segments are parallel, perpendicular or simply intersect. A(-4, 2) B(3, -4)
C(-2, 5) D(5, -1)

A) parallel
B) perpendicular
C) intersect
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18
Sketch the graph of the ellipse. Sketch the graph of the ellipse.
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19
Three non-colinear points are given and can be connected with line segments to form a triangle. Find the perimeter of the triangle (rounded to the nearest tenth as needed) and determine if the triangle is a right triangle. P1 = (-8, 2)
P2 = (-8, -6)
P3 = (7, 2)

A) perimeter: 33.0; right triangle
B) perimeter: 40.0; not a right triangle
C) perimeter: 40.0; right triangle
D) perimeter: 33.0; not a right triangle
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20
Graph the hyperbola. Label the vertices. <strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)

A)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
B)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
C)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
D)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
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21
Use the following to answer questions :
y = 2x2 - x - 3
Find the x- and y-intercepts (if they exist).

A) x-intercepts: <strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3 Find the x- and y-intercepts (if they exist).</strong> A) x-intercepts:   ; y-intercept: (0, 3) B) x-intercepts:   ; y-intercept: (0, -3) C) x-intercepts:   ; y-intercept: (0, -3) D) x-intercepts: none; y-intercept: (0, -3) ; y-intercept: (0, 3)
B) x-intercepts: <strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3 Find the x- and y-intercepts (if they exist).</strong> A) x-intercepts:   ; y-intercept: (0, 3) B) x-intercepts:   ; y-intercept: (0, -3) C) x-intercepts:   ; y-intercept: (0, -3) D) x-intercepts: none; y-intercept: (0, -3) ; y-intercept: (0, -3)
C) x-intercepts: <strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3 Find the x- and y-intercepts (if they exist).</strong> A) x-intercepts:   ; y-intercept: (0, 3) B) x-intercepts:   ; y-intercept: (0, -3) C) x-intercepts:   ; y-intercept: (0, -3) D) x-intercepts: none; y-intercept: (0, -3) ; y-intercept: (0, -3)
D) x-intercepts: none; y-intercept: (0, -3)
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22
Classify the equation as that of a circle, ellipse, hyperbola, or none of the above. 4x2 + 9y2 - 40x - 18y = -73

A) Circle
B) Ellipse
C) Hyperbola
D) None of these
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23
Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices. <strong>Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.  </strong> A)   B)   C)   D)

A)
<strong>Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.  </strong> A)   B)   C)   D)
B)
<strong>Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.  </strong> A)   B)   C)   D)
C)
<strong>Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.  </strong> A)   B)   C)   D)
D)
<strong>Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.  </strong> A)   B)   C)   D)
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24
Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.
(x - 1)2 - 9(y - 2)2 = 9
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25
Use the following to answer questions :
y = x2 - 4x + 3
Find the vertex.
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26
Graph the hyperbola. Label the vertices. Graph the hyperbola. Label the vertices.
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27
Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices. Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.
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28
For the graph given, state the location of the vertices, the equation of the transverse axis, the location of the center, and the equation of the conjugate axis. <strong>For the graph given, state the location of the vertices, the equation of the transverse axis, the location of the center, and the equation of the conjugate axis.   (Gridlines are spaced one unit apart.)</strong> A) vertices: (1, 2), (1, 4); transverse axis: x = 3; center (1, 3); conjugate axis: y = 1 B) vertices: (1, 2), (1, 4); transverse axis: y = 3; center (1, 3); conjugate axis: x = 1 C) vertices: (1, 2), (1, 4); transverse axis: x = 1; center (1, 3); conjugate axis: y = 3 D) vertices: (1, 2), (1, 4); transverse axis: y = 1; center (1, 3); conjugate axis: x = 3 (Gridlines are spaced one unit apart.)

A) vertices: (1, 2), (1, 4); transverse axis: x = 3; center (1, 3); conjugate axis: y = 1
B) vertices: (1, 2), (1, 4); transverse axis: y = 3; center (1, 3); conjugate axis: x = 1
C) vertices: (1, 2), (1, 4); transverse axis: x = 1; center (1, 3); conjugate axis: y = 3
D) vertices: (1, 2), (1, 4); transverse axis: y = 1; center (1, 3); conjugate axis: x = 3
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29
Classify the equation as that of a circle, ellipse, hyperbola, or none of the above. 9x2 + 9y2 - 18x + 72y + 72 = 0

A) Circle
B) Ellipse
C) Hyperbola
D) None of these
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30
Classify the equation as that of a circle, ellipse, hyperbola, or none of the above. 4x2 - 7y2 = 28

A) Circle
B) Ellipse
C) Hyperbola
D) None of these
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31
Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices. <strong>Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.  </strong> A)   B)   C)   D)

A)
<strong>Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.  </strong> A)   B)   C)   D)
B)
<strong>Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.  </strong> A)   B)   C)   D)
C)
<strong>Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.  </strong> A)   B)   C)   D)
D)
<strong>Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.  </strong> A)   B)   C)   D)
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32
For the graph given, state
(a) the location of the vertices
(b) the equation of the transverse axis
(c) the location of the center
(d) the equation of the conjugate axis
Assume all coordinates are lattice points. For the graph given, state (a) the location of the vertices (b) the equation of the transverse axis (c) the location of the center (d) the equation of the conjugate axis Assume all coordinates are lattice points.   (Gridlines are spaced one unit apart.) (Gridlines are spaced one unit apart.)
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33
Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.
x2 - 9y2 - 6x - 36y - 36 = 0
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34
Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices. Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.
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35
Graph the hyperbola. Label the vertices. <strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)

A)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
B)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
C)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
D)
<strong>Graph the hyperbola. Label the vertices.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
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36
Classify the equation as that of a circle, ellipse, hyperbola, or none of the above. 9x2 = -49y2 + 441

A) Circle
B) Ellipse
C) Hyperbola
D) None of these
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37
Sketch a complete graph of the equation, including asymptotes. Be sure to identify the center and vertices.
25y2 - 4x2 = 100
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38
Classify the equation as that of a circle, ellipse, hyperbola, or none of the above. 8y2 - 4 = 5x2 + 36

A) Circle
B) Ellipse
C) Hyperbola
D) None of these
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39
Classify the equation as that of a circle, ellipse, hyperbola, or none of the above. -2x2 + -2y2= -20

A) Circle
B) Ellipse
C) Hyperbola
D) None of these
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40
Use the following to answer questions :
y = x2 - 4x + 3
Find the x- and y-intercepts (if they exist).
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41
Use the following to answer questions :
x = -y2 + 6y - 8
Sketch the graph using symmetry and a few additional points.

A)
<strong>Use the following to answer questions : x = -y<sup>2</sup> + 6y - 8 Sketch the graph using symmetry and a few additional points.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
B)
<strong>Use the following to answer questions : x = -y<sup>2</sup> + 6y - 8 Sketch the graph using symmetry and a few additional points.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
C)
<strong>Use the following to answer questions : x = -y<sup>2</sup> + 6y - 8 Sketch the graph using symmetry and a few additional points.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
D)
<strong>Use the following to answer questions : x = -y<sup>2</sup> + 6y - 8 Sketch the graph using symmetry and a few additional points.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
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42
Use the following to answer questions :
y = 2x2 - x - 3
Sketch the graph using symmetry and a few additional points or completing the square and shifting a parent function.

A)
<strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3 Sketch the graph using symmetry and a few additional points or completing the square and shifting a parent function.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
B)
<strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3 Sketch the graph using symmetry and a few additional points or completing the square and shifting a parent function.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
C)
<strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3 Sketch the graph using symmetry and a few additional points or completing the square and shifting a parent function.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
D)
<strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3 Sketch the graph using symmetry and a few additional points or completing the square and shifting a parent function.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
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43
Use the following to answer questions :
x = -y2 + 6y - 8
Find the x- and y-intercepts, if they exist.

A) x-intercepts: (2, 0), (4, 0); y-intercept: (0, -8)
B) x-intercept: (2, 0); y-intercepts: (0, -8), (0, 4)
C) x-intercept: (-8, 0); y-intercepts: (0, 2), (0, 4)
D) x-intercepts: none; y-intercept (0, -8)
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44
(a) Sketch x = y2 + 4y + 3 using symmetry and shifts of a basic function.
(b) Find the x- and y-intercepts (if they exist).
(c) Find the vertex.
(d) State the domain and range of the relation.
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45
(a) Sketch x = y2 - 4y using symmetry and shifts of a basic function.
(b) Find the x- and y-intercepts (if they exist).
(c) Find the vertex.
(d) State the domain and range of the relation.
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46
Use the following to answer questions :
x2 = 28y
Find the directrix.
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47
Use the following to answer questions :
y2 = 36x
Find the directrix.

A) y = -8
B) y = 8
C) x = -8
D) x = 8
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48
Use the following to answer questions :
x = y2 - 2y - 3
Find the vertex.
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49
Use the following to answer questions :
x = y2 - 2y - 3
Find the x- and y-intercepts, if they exist.
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50
Sketch x = (y - 1)2 - 4 using symmetry and shifts of a basic function.

A)
<strong>Sketch x = (y - 1)<sup>2</sup> - 4 using symmetry and shifts of a basic function.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
B)
<strong>Sketch x = (y - 1)<sup>2</sup> - 4 using symmetry and shifts of a basic function.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
C)
<strong>Sketch x = (y - 1)<sup>2</sup> - 4 using symmetry and shifts of a basic function.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
D)
<strong>Sketch x = (y - 1)<sup>2</sup> - 4 using symmetry and shifts of a basic function.</strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D)   (Gridlines are spaced one unit apart.)
(Gridlines are spaced one unit apart.)
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51
Use the following to answer questions :
x2 = 28y
Find the vertex.
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52
Use the following to answer questions :
x = -y2 + 6y - 8

-State the domain and range.

A) x \in (- \infty , 1]; y \in (- \infty , \infty )
B) x \in (- \infty , \infty ); y \in (- \infty , 3]
C) x \in [3, \infty ); y \in (- \infty , \infty )
D) x \in (- \infty , \infty ); y \in (- \infty , \infty )
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53
Find the vertex, focus, and directrix for the parabola given, then use this information to sketch a complete graph (illustrate these features).
y2 = -8x
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54
Use the following to answer questions :
y = 2x2 - x - 3
Find the vertex.

A) <strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3 Find the vertex.</strong> A)   B)   C)   D)
B) <strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3 Find the vertex.</strong> A)   B)   C)   D)
C) <strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3 Find the vertex.</strong> A)   B)   C)   D)
D) <strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3 Find the vertex.</strong> A)   B)   C)   D)
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55
Use the following to answer questions :
x2 = 28y
Find the focus.
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56
Use the following to answer questions :
y2 = 36x
Find the focus.

A) (0, -6)
B) (0, -24)
C) (-6, 0)
D) (-24, 0)
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57
Use the following to answer questions :
y = 2x2 - x - 3

-State the domain and range.

A) x \in (- \infty , \infty ); y \in  <strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3  -State the domain and range.</strong> A) x  \in  (- \infty ,  \infty ); y  \in     B) x  \in    ; y  \in   (- \infty ,  \infty ) C) x  \in   (- \infty ,  \infty ); y  \in    D) x  \in   (- \infty , \infty ); y  \in  (- \infty ,  \infty )
B) x \in  <strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3  -State the domain and range.</strong> A) x  \in  (- \infty ,  \infty ); y  \in     B) x  \in    ; y  \in   (- \infty ,  \infty ) C) x  \in   (- \infty ,  \infty ); y  \in    D) x  \in   (- \infty , \infty ); y  \in  (- \infty ,  \infty )  ; y \in (- \infty , \infty )
C) x \in (- \infty , \infty ); y \in  <strong>Use the following to answer questions : y = 2x<sup>2</sup> - x - 3  -State the domain and range.</strong> A) x  \in  (- \infty ,  \infty ); y  \in     B) x  \in    ; y  \in   (- \infty ,  \infty ) C) x  \in   (- \infty ,  \infty ); y  \in    D) x  \in   (- \infty , \infty ); y  \in  (- \infty ,  \infty )
D) x \in (- \infty , \infty ); y \in (- \infty , \infty )
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58
Use the following to answer questions :
x = -y2 + 6y - 8
Find the vertex.

A) (-80, -6)
B) (-8, 6)
C) (-35, -3)
D) (1, 3)
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59
Use the following to answer questions :
y2 = 36x
Find the vertex.

A) (0, 0)
B) (0, -5)
C) (0, -20)
D) (-20, 0)
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60
Identify each equation in the system as that of a line, parabola, circle, ellipse, or hyperbola, and solve the system by graphing. Identify each equation in the system as that of a line, parabola, circle, ellipse, or hyperbola, and solve the system by graphing.
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61
Solve using elimination. <strong>Solve using elimination.  </strong> A) (4, 0), (5, -3), (-5, -3) B) (-4, 0), (5, -3), (5, -3) C) (-4, 0), (5, -3), (5, 3) D) no solutions

A) (4, 0), (5, -3), (-5, -3)
B) (-4, 0), (5, -3), (5, -3)
C) (-4, 0), (5, -3), (5, 3)
D) no solutions
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62
List three alternate ways the point  List three alternate ways the point   can be expressed in polar coordinates using r > 0, r < 0, and  \theta   \in  [-2 \pi , 2 \pi ). can be expressed in polar coordinates using r > 0, r < 0, and θ\theta \in [-2 π\pi , 2 π\pi ).
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63
Plot the point Plot the point   .  . Plot the point   .
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64
Solve using the method of your choice. <strong>Solve using the method of your choice.  </strong> A) (4, 5<sup>24</sup>) B) (-4, 5<sup>8</sup>) C) (4, 5<sup>24</sup>), (-4, 5<sup>8</sup>) D) (4, 5<sup>24</sup>), (-4, -5<sup>8</sup>)

A) (4, 524)
B) (-4, 58)
C) (4, 524), (-4, 58)
D) (4, 524), (-4, -58)
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65
Solve the system of inequalities. Solve the system of inequalities.
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66
Convert from rectangular coordinates to polar coordinates. A diagram may help.
(8, -8)
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67
Plot the point <strong>Plot the point   .</strong> A)   B)   C)   D)   .

A)
<strong>Plot the point   .</strong> A)   B)   C)   D)
B)
<strong>Plot the point   .</strong> A)   B)   C)   D)
C)
<strong>Plot the point   .</strong> A)   B)   C)   D)
D)
<strong>Plot the point   .</strong> A)   B)   C)   D)
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68
Identify each equation in the system as that of a line, parabola, circle, ellipse, or hyperbola, and solve the system by graphing. Identify each equation in the system as that of a line, parabola, circle, ellipse, or hyperbola, and solve the system by graphing.
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69
Express the point shown using polar coordinates with θ\theta in radians, 0 \leθ\theta < 2? and r > 0.  Express the point shown using polar coordinates with  \theta in radians, 0 \le\theta  < 2? and r > 0.
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70
Solve using elimination. Solve using elimination.
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71
Solve using substitution. [Hint: Substitute for y2 (not x).] Solve using substitution. [Hint: Substitute for y<sup>2</sup> (not x).]
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72
Convert from rectangular coordinates to polar coordinates. A diagram may help. <strong>Convert from rectangular coordinates to polar coordinates. A diagram may help.  </strong> A)   B)   C)   D)

A) <strong>Convert from rectangular coordinates to polar coordinates. A diagram may help.  </strong> A)   B)   C)   D)
B) <strong>Convert from rectangular coordinates to polar coordinates. A diagram may help.  </strong> A)   B)   C)   D)
C) <strong>Convert from rectangular coordinates to polar coordinates. A diagram may help.  </strong> A)   B)   C)   D)
D) <strong>Convert from rectangular coordinates to polar coordinates. A diagram may help.  </strong> A)   B)   C)   D)
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73
Plot the point Plot the point   .  . Plot the point   .
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74
Solve using substitution. <strong>Solve using substitution.  </strong> A) (0, 5), (5, 0) B) (0, 5), (-5, 0) C) (0, -5), (5, 0) D) (0, -5), (-5, 0)

A) (0, 5), (5, 0)
B) (0, 5), (-5, 0)
C) (0, -5), (5, 0)
D) (0, -5), (-5, 0)
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75
Solve the system of inequalities. <strong>Solve the system of inequalities.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D) Ø

A)
<strong>Solve the system of inequalities.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D) Ø
(Gridlines are spaced one unit apart.)
B)
<strong>Solve the system of inequalities.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D) Ø
(Gridlines are spaced one unit apart.)
C)
<strong>Solve the system of inequalities.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D) Ø
(Gridlines are spaced one unit apart.)
D) Ø
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76
Solve the system of inequalities. Solve the system of inequalities.
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77
Solve the system of inequalities. Solve the system of inequalities.
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78
Solve using the method of your choice. Solve using the method of your choice.
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79
Solve the system of inequalities. Solve the system of inequalities.
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80
Solve the system of inequalities. <strong>Solve the system of inequalities.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D) Ø

A)
<strong>Solve the system of inequalities.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D) Ø
(Gridlines are spaced one unit apart.)
B)
<strong>Solve the system of inequalities.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D) Ø
(Gridlines are spaced one unit apart.)
C)
<strong>Solve the system of inequalities.  </strong> A)   (Gridlines are spaced one unit apart.) B)   (Gridlines are spaced one unit apart.) C)   (Gridlines are spaced one unit apart.) D) Ø
(Gridlines are spaced one unit apart.)
D) Ø
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