Deck 12: Chemical Kinetics
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Deck 12: Chemical Kinetics
1
Consider the following rate law:
How are the exponents n and m determined?
A)by using the balanced chemical equation
B)by using the subscripts for the chemical formulas
C)by using the coefficients of the chemical formulas
D)by educated guess
E)by experiment

A)by using the balanced chemical equation
B)by using the subscripts for the chemical formulas
C)by using the coefficients of the chemical formulas
D)by educated guess
E)by experiment
by experiment
2
Consider the reaction:
At a certain instant the initial rate of disappearance of the oxygen gas is X.What is the value of the appearance of water at the same instant?
A)1.2 X
B)1.1 X
C)0.86 X
D)0.58 X
E)cannot be determined from the data

A)1.2 X
B)1.1 X
C)0.86 X
D)0.58 X
E)cannot be determined from the data
0.86 X
3
The following questions refer to the reaction between nitric oxide and hydrogen
2NO + H2 N2O + H2O
![<strong>The following questions refer to the reaction between nitric oxide and hydrogen 2NO + H<sub>2</sub> \to N<sub>2</sub>O + H<sub>2</sub>O -What is the rate law for this reaction?</strong> A)Rate = k[NO] B)Rate = k[NO]<sup>2</sup> C)Rate = k[NO]<sup>2</sup>[H<sub>2</sub>] D)Rate = k[NO][H<sub>2</sub>] E)Rate = k[N<sub>2</sub>O][H<sub>2</sub>O]](https://storage.examlex.com/TB6423/11efdc18_03f8_13df_8f65_a329fb6d5f14_TB6423_00.jpg)
-What is the rate law for this reaction?
A)Rate = k[NO]
B)Rate = k[NO]2
C)Rate = k[NO]2[H2]
D)Rate = k[NO][H2]
E)Rate = k[N2O][H2O]
2NO + H2 N2O + H2O
![<strong>The following questions refer to the reaction between nitric oxide and hydrogen 2NO + H<sub>2</sub> \to N<sub>2</sub>O + H<sub>2</sub>O -What is the rate law for this reaction?</strong> A)Rate = k[NO] B)Rate = k[NO]<sup>2</sup> C)Rate = k[NO]<sup>2</sup>[H<sub>2</sub>] D)Rate = k[NO][H<sub>2</sub>] E)Rate = k[N<sub>2</sub>O][H<sub>2</sub>O]](https://storage.examlex.com/TB6423/11efdc18_03f8_13df_8f65_a329fb6d5f14_TB6423_00.jpg)
-What is the rate law for this reaction?
A)Rate = k[NO]
B)Rate = k[NO]2
C)Rate = k[NO]2[H2]
D)Rate = k[NO][H2]
E)Rate = k[N2O][H2O]
Rate = k[NO]2[H2]
4
A general reaction written as A + 2B C + 2D is studied and yields the following data:

-What is the order of the reaction with respect to B?
A)0
B)1
C)2
D)3
E)4

-What is the order of the reaction with respect to B?
A)0
B)1
C)2
D)3
E)4
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5
A general reaction written as A + 2B C + 2D is studied and yields the following data:

-What is the order of the reaction with respect to A?
A)0
B)1
C)2
D)3
E)4

-What is the order of the reaction with respect to A?
A)0
B)1
C)2
D)3
E)4
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6
Determine the initial rate of B consumption ( [B]/ t)for the first trial?
A)8.00 10-3 mol/L·s
B)1.60 10-2 mol/L·s
C)3.20 10-2 mol/L·s
D)4.00 10-3 mol/L·s
E)none of these (A-D)
A)8.00 10-3 mol/L·s
B)1.60 10-2 mol/L·s
C)3.20 10-2 mol/L·s
D)4.00 10-3 mol/L·s
E)none of these (A-D)
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7
What is the numerical value of the rate constant?
A)0.053
B)1.19
C)2.37
D)5.63
E)none of these (A-D)
A)0.053
B)1.19
C)2.37
D)5.63
E)none of these (A-D)
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8
Determine the initial rate of C production ( [C]/ t)if [A] = 0.200 M and [B] = 0.500 M.
A)4.74 10-2 mol/L·s
B)2.37 10-1 mol/L·s
C)1.19 10-1 mol/L·s
D)8.23 10-2 mol/L·s
E)none of these (A-D)
A)4.74 10-2 mol/L·s
B)2.37 10-1 mol/L·s
C)1.19 10-1 mol/L·s
D)8.23 10-2 mol/L·s
E)none of these (A-D)
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9
The following initial rate data were found for the reaction
2MnO4- + 5H2C2O4 + 6H+ 2Mn2+ + 10CO2 + 8H2O

-What is the value of the rate constant?
A)2 105 M.s-1
B)2 105 M-2.s-1
C)200 M-1.s-1
D)200 M-2.s-1
E)2 10-4 M.s-1
2MnO4- + 5H2C2O4 + 6H+ 2Mn2+ + 10CO2 + 8H2O

-What is the value of the rate constant?
A)2 105 M.s-1
B)2 105 M-2.s-1
C)200 M-1.s-1
D)200 M-2.s-1
E)2 10-4 M.s-1
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10
Consider the following data concerning the equation:
H2O2 + 3I- + 2H+ I3- + 2H2O
![<strong>Consider the following data concerning the equation: H<sub>2</sub>O<sub>2</sub> + 3I<sup>-</sup> + 2H<sup>+</sup> \to I<sub>3</sub><sup>-</sup> + 2H<sub>2</sub>O -The rate law for this reaction is</strong> A)rate = k[H<sub>2</sub>O<sub>2</sub>][I<sup>-</sup>][H<sup>+</sup>] B)rate = k[H<sub>2</sub>O<sub>2</sub>]<sup>2</sup>[I<sup>-</sup>]<sup>2</sup>[H<sup>+</sup>]<sup>2</sup> C)rate = k[I<sup>-</sup>][H<sup>+</sup>] D)rate = k[H<sub>2</sub>O<sub>2</sub>][H<sup>+</sup>] E)rate = k[H<sub>2</sub>O<sub>2</sub>][I<sup>-</sup>]](https://storage.examlex.com/TB6423/11efdc17_782a_bd8d_8f65_af94418a678e_TB6423_00.jpg)
-The rate law for this reaction is
A)rate = k[H2O2][I-][H+]
B)rate = k[H2O2]2[I-]2[H+]2
C)rate = k[I-][H+]
D)rate = k[H2O2][H+]
E)rate = k[H2O2][I-]
H2O2 + 3I- + 2H+ I3- + 2H2O
![<strong>Consider the following data concerning the equation: H<sub>2</sub>O<sub>2</sub> + 3I<sup>-</sup> + 2H<sup>+</sup> \to I<sub>3</sub><sup>-</sup> + 2H<sub>2</sub>O -The rate law for this reaction is</strong> A)rate = k[H<sub>2</sub>O<sub>2</sub>][I<sup>-</sup>][H<sup>+</sup>] B)rate = k[H<sub>2</sub>O<sub>2</sub>]<sup>2</sup>[I<sup>-</sup>]<sup>2</sup>[H<sup>+</sup>]<sup>2</sup> C)rate = k[I<sup>-</sup>][H<sup>+</sup>] D)rate = k[H<sub>2</sub>O<sub>2</sub>][H<sup>+</sup>] E)rate = k[H<sub>2</sub>O<sub>2</sub>][I<sup>-</sup>]](https://storage.examlex.com/TB6423/11efdc17_782a_bd8d_8f65_af94418a678e_TB6423_00.jpg)
-The rate law for this reaction is
A)rate = k[H2O2][I-][H+]
B)rate = k[H2O2]2[I-]2[H+]2
C)rate = k[I-][H+]
D)rate = k[H2O2][H+]
E)rate = k[H2O2][I-]
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11
The average value for the rate constant k (without units)is
A)2710
B)2.74 104
C)137
D)108
E)none of these
A)2710
B)2.74 104
C)137
D)108
E)none of these
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12
Consider the reaction
What is the ratio of the initial rate of the appearance of water to the initial rate of disappearance of oxygen?
A)1 : 1
B)2 : 1
C)1 : 2
D)2 : 2
E)3 : 2

A)1 : 1
B)2 : 1
C)1 : 2
D)2 : 2
E)3 : 2
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13
The following data were obtained for the reaction of NO with O2.Concentrations are in molecules/cm3 and rates are in molecules/cm3.s. ![<strong>The following data were obtained for the reaction of NO with O<sub>2</sub>.Concentrations are in molecules/cm<sup>3</sup> and rates are in molecules/cm<sup>3</sup>.s. What is the rate law?</strong> A)Rate = k[NO][O<sub>2</sub>] B)Rate = k[NO][O<sub>2</sub>]<sup>2</sup> C)Rate = k[NO]<sup>2</sup>[O<sub>2</sub>] D)Rate = k[NO]<sup>2</sup> E)Rate = k[NO]<sup>2</sup>[O<sub>2</sub>]<sup>2</sup>](https://storage.examlex.com/TB6423/11efdc16_91f0_726b_8f65_6182a00a7fed_TB6423_00.jpg)
What is the rate law?
A)Rate = k[NO][O2]
B)Rate = k[NO][O2]2
C)Rate = k[NO]2[O2]
D)Rate = k[NO]2
E)Rate = k[NO]2[O2]2
![<strong>The following data were obtained for the reaction of NO with O<sub>2</sub>.Concentrations are in molecules/cm<sup>3</sup> and rates are in molecules/cm<sup>3</sup>.s. What is the rate law?</strong> A)Rate = k[NO][O<sub>2</sub>] B)Rate = k[NO][O<sub>2</sub>]<sup>2</sup> C)Rate = k[NO]<sup>2</sup>[O<sub>2</sub>] D)Rate = k[NO]<sup>2</sup> E)Rate = k[NO]<sup>2</sup>[O<sub>2</sub>]<sup>2</sup>](https://storage.examlex.com/TB6423/11efdc16_91f0_726b_8f65_6182a00a7fed_TB6423_00.jpg)
What is the rate law?
A)Rate = k[NO][O2]
B)Rate = k[NO][O2]2
C)Rate = k[NO]2[O2]
D)Rate = k[NO]2
E)Rate = k[NO]2[O2]2
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14
The balanced equation for the reaction of bromate ion with bromide ion in acidic solution is given by:
At a particular instant in time,the value of
is
mol/L s.What is the value of
in the same units?
A)
B)
C)
D)
E)




A)

B)

C)

D)

E)

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15
Consider the reaction X Y + Z Which of the following is a possible rate law?
A)Rate = k[X]
B)Rate = k[Y]
C)Rate = k[Y][Z]
D)Rate = k[X][Y]
E)Rate = k[Z]
A)Rate = k[X]
B)Rate = k[Y]
C)Rate = k[Y][Z]
D)Rate = k[X][Y]
E)Rate = k[Z]
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16
The average rate of disappearance of ozone in the reaction
is found to be
atm over a certain interval of time.What is the rate of appearance of
during this interval?
A)
atm/s
B)
atm/s
C)
atm/s
D)
atm/s
E)
atm/s



A)

B)

C)

D)

E)

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17
Two mechanisms are proposed: I.
II.
Which mechanism and which step as the rate determining step would best fit the data?
A)Mechanism I,with the first step the rate determining step.
B)Mechanism I,with the second step the rate determining step.
C)Mechanism II,with the first step rate determining.
D)Mechanism II,with the second step rate determining.
E)None of the above could be correct.


A)Mechanism I,with the first step the rate determining step.
B)Mechanism I,with the second step the rate determining step.
C)Mechanism II,with the first step rate determining.
D)Mechanism II,with the second step rate determining.
E)None of the above could be correct.
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18
The following initial rate data were found for the reaction
2MnO4- + 5H2C2O4 + 6H+ 2Mn2+ + 10CO2 + 8H2O
![<strong>The following initial rate data were found for the reaction 2MnO<sub>4</sub><sup>-</sup> + 5H<sub>2</sub>C<sub>2</sub>O<sub>4</sub> + 6H<sup>+</sup> \to 2Mn<sup>2+</sup> + 10CO<sub>2</sub> + 8H<sub>2</sub>O -Which of the following is the correct rate law?</strong> A)Rate = k[MnO<sub>4</sub><sup>-</sup>]<sup>2</sup>[H<sub>2</sub>C<sub>2</sub>O<sub>4</sub>]<sup>5</sup>[H<sup>+</sup>]<sup>6</sup> B)Rate = k[MnO<sub>4</sub><sup>-</sup>]<sup>2</sup>[H<sub>2</sub>C<sub>2</sub>O<sub>4</sub>][H<sup>+</sup>] C)Rate = k[MnO<sub>4</sub><sup>-</sup>][H<sub>2</sub>C<sub>2</sub>O<sub>4</sub>][H<sup>+</sup>] D)Rate = k[MnO<sub>4</sub><sup>-</sup>]<sup>2</sup>[H<sub>2</sub>C<sub>2</sub>O<sub>4</sub>] E)Rate = k[MnO<sub>4</sub><sup>-</sup>]<sup>2</sup>[H<sub>2</sub>C<sub>2</sub>O<sub>4</sub>]<sup>2</sup>](https://storage.examlex.com/TB6423/11efdc17_af7d_2f7e_8f65_dfff33b37c4f_TB6423_00.jpg)
-Which of the following is the correct rate law?
A)Rate = k[MnO4-]2[H2C2O4]5[H+]6
B)Rate = k[MnO4-]2[H2C2O4][H+]
C)Rate = k[MnO4-][H2C2O4][H+]
D)Rate = k[MnO4-]2[H2C2O4]
E)Rate = k[MnO4-]2[H2C2O4]2
2MnO4- + 5H2C2O4 + 6H+ 2Mn2+ + 10CO2 + 8H2O
![<strong>The following initial rate data were found for the reaction 2MnO<sub>4</sub><sup>-</sup> + 5H<sub>2</sub>C<sub>2</sub>O<sub>4</sub> + 6H<sup>+</sup> \to 2Mn<sup>2+</sup> + 10CO<sub>2</sub> + 8H<sub>2</sub>O -Which of the following is the correct rate law?</strong> A)Rate = k[MnO<sub>4</sub><sup>-</sup>]<sup>2</sup>[H<sub>2</sub>C<sub>2</sub>O<sub>4</sub>]<sup>5</sup>[H<sup>+</sup>]<sup>6</sup> B)Rate = k[MnO<sub>4</sub><sup>-</sup>]<sup>2</sup>[H<sub>2</sub>C<sub>2</sub>O<sub>4</sub>][H<sup>+</sup>] C)Rate = k[MnO<sub>4</sub><sup>-</sup>][H<sub>2</sub>C<sub>2</sub>O<sub>4</sub>][H<sup>+</sup>] D)Rate = k[MnO<sub>4</sub><sup>-</sup>]<sup>2</sup>[H<sub>2</sub>C<sub>2</sub>O<sub>4</sub>] E)Rate = k[MnO<sub>4</sub><sup>-</sup>]<sup>2</sup>[H<sub>2</sub>C<sub>2</sub>O<sub>4</sub>]<sup>2</sup>](https://storage.examlex.com/TB6423/11efdc17_af7d_2f7e_8f65_dfff33b37c4f_TB6423_00.jpg)
-Which of the following is the correct rate law?
A)Rate = k[MnO4-]2[H2C2O4]5[H+]6
B)Rate = k[MnO4-]2[H2C2O4][H+]
C)Rate = k[MnO4-][H2C2O4][H+]
D)Rate = k[MnO4-]2[H2C2O4]
E)Rate = k[MnO4-]2[H2C2O4]2
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19
For the reaction
,at a particular instant in time,the rate of the reaction is 0.0223 M/s.What is the rate of change of A?
A)-0.0223 M/s
B)0.112 M/s
C)-0.112 M/s
D)-0.00446 M/s
E)0.00446 M/s

A)-0.0223 M/s
B)0.112 M/s
C)-0.112 M/s
D)-0.00446 M/s
E)0.00446 M/s
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20
A general reaction written as A + 2B C + 2D is studied and yields the following data:

-What is the overall order of the reaction?
A)0
B)1
C)2
D)3
E)4

-What is the overall order of the reaction?
A)0
B)1
C)2
D)3
E)4
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21
The kinetics of the reaction
were studied and the following results obtained,where the rate law is:
For a run where [A]0 = 1.0 10-3 M and [B]0 = 5.0 M,a plot of ln [A] versus t was found to give a straight line with slope = -5.0 10-2 s-1.
For a run where [A]0 = 1.0 10-3 M and [B]0 = 10.0 M,a plot of ln [A] versus t was found to give a straight line with slope = -7.1 10-2 s-1.
-What is the value of n?
A)0
B)0.5
C)1
D)1.5
E)2
![<strong>The kinetics of the reaction were studied and the following results obtained,where the rate law is: For a run where [A]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>3</sup> M and [B]<sub>0</sub> = 5.0 M,a plot of ln [A] versus t was found to give a straight line with slope = -5.0 \times 10<sup>-</sup><sup>2</sup> s<sup>-</sup><sup>1</sup>. For a run where [A]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>3</sup> M and [B]<sub>0</sub> = 10.0 M,a plot of ln [A] versus t was found to give a straight line with slope = -7.1 \times 10<sup>-</sup><sup>2</sup> s<sup>-</sup><sup>1</sup>. -What is the value of n?</strong> A)0 B)0.5 C)1 D)1.5 E)2](https://storage.examlex.com/TB6423/11eaa8f0_66f8_f38e_93a6_31a6fa3982fe_TB6423_11_TB6423_11_TB6423_11.jpg)
![<strong>The kinetics of the reaction were studied and the following results obtained,where the rate law is: For a run where [A]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>3</sup> M and [B]<sub>0</sub> = 5.0 M,a plot of ln [A] versus t was found to give a straight line with slope = -5.0 \times 10<sup>-</sup><sup>2</sup> s<sup>-</sup><sup>1</sup>. For a run where [A]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>3</sup> M and [B]<sub>0</sub> = 10.0 M,a plot of ln [A] versus t was found to give a straight line with slope = -7.1 \times 10<sup>-</sup><sup>2</sup> s<sup>-</sup><sup>1</sup>. -What is the value of n?</strong> A)0 B)0.5 C)1 D)1.5 E)2](https://storage.examlex.com/TB6423/11eaa8f0_66f8_f38f_93a6_512646056c97_TB6423_11_TB6423_11_TB6423_11.jpg)
For a run where [A]0 = 1.0 10-3 M and [B]0 = 10.0 M,a plot of ln [A] versus t was found to give a straight line with slope = -7.1 10-2 s-1.
-What is the value of n?
A)0
B)0.5
C)1
D)1.5
E)2
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22
The kinetics of the reaction
were studied and the following results obtained,where the rate law is:
For a run where [A]0 = 1.0 10-3 M and [B]0 = 5.0 M,a plot of ln [A] versus t was found to give a straight line with slope = -5.0 10-2 s-1.
For a run where [A]0 = 1.0 10-3 M and [B]0 = 10.0 M,a plot of ln [A] versus t was found to give a straight line with slope = -7.1 10-2 s-1.
-What is the value of m?
A)0
B)0.5
C)1
D)1.5
E)2
![<strong>The kinetics of the reaction were studied and the following results obtained,where the rate law is: For a run where [A]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>3</sup> M and [B]<sub>0</sub> = 5.0 M,a plot of ln [A] versus t was found to give a straight line with slope = -5.0 \times 10<sup>-</sup><sup>2</sup> s<sup>-</sup><sup>1</sup>. For a run where [A]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>3</sup> M and [B]<sub>0</sub> = 10.0 M,a plot of ln [A] versus t was found to give a straight line with slope = -7.1 \times 10<sup>-</sup><sup>2</sup> s<sup>-</sup><sup>1</sup>. -What is the value of m?</strong> A)0 B)0.5 C)1 D)1.5 E)2](https://storage.examlex.com/TB6423/11eaa8f0_66f8_f38e_93a6_31a6fa3982fe_TB6423_11_TB6423_11_TB6423_11.jpg)
![<strong>The kinetics of the reaction were studied and the following results obtained,where the rate law is: For a run where [A]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>3</sup> M and [B]<sub>0</sub> = 5.0 M,a plot of ln [A] versus t was found to give a straight line with slope = -5.0 \times 10<sup>-</sup><sup>2</sup> s<sup>-</sup><sup>1</sup>. For a run where [A]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>3</sup> M and [B]<sub>0</sub> = 10.0 M,a plot of ln [A] versus t was found to give a straight line with slope = -7.1 \times 10<sup>-</sup><sup>2</sup> s<sup>-</sup><sup>1</sup>. -What is the value of m?</strong> A)0 B)0.5 C)1 D)1.5 E)2](https://storage.examlex.com/TB6423/11eaa8f0_66f8_f38f_93a6_512646056c97_TB6423_11_TB6423_11_TB6423_11.jpg)
For a run where [A]0 = 1.0 10-3 M and [B]0 = 10.0 M,a plot of ln [A] versus t was found to give a straight line with slope = -7.1 10-2 s-1.
-What is the value of m?
A)0
B)0.5
C)1
D)1.5
E)2
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23
What form will the pseudo-rate law have?
A)Rate = k'[A]x
B)Rate = k'[B]y
C)Rate = k'[A]x[B]y
D)Rate = kk'[A]x
E)Rate = kk'[B]y
A)Rate = k'[A]x
B)Rate = k'[B]y
C)Rate = k'[A]x[B]y
D)Rate = kk'[A]x
E)Rate = kk'[B]y
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24
The following questions refer to the reaction between nitric oxide and hydrogen
2NO + H2 N2O + H2O

-What are the units for the rate constant for this reaction?
A)L/mol·s
B)L2/mol2·s
C)mol/L·s
D)s-2
E)L-2
2NO + H2 N2O + H2O

-What are the units for the rate constant for this reaction?
A)L/mol·s
B)L2/mol2·s
C)mol/L·s
D)s-2
E)L-2
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25
The reaction H2SeO3(aq)6I-(aq)+ 4H+(aq) 2I3-(aq)+ 3H2O(l)+ Se(s)was studied at 0°C by the method of initial rates:

-The numerical value of the rate constant is
A)5.2 105
B)2.1 102
C)4.2
D)1.9 10-6
E)none of these

-The numerical value of the rate constant is
A)5.2 105
B)2.1 102
C)4.2
D)1.9 10-6
E)none of these
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26
For the reaction
,the following data were collected:

-The order of this reaction in N2O5 is
A)0
B)1
C)2
D)3
E)none of these


-The order of this reaction in N2O5 is
A)0
B)1
C)2
D)3
E)none of these
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27
The initial rate of production of NO2 for this reaction is approximately
A)7.4 10-4 mol/L·min
B)3.2 10-4 mol/L·min
C)1.24 10-2 mol/L·min
D)1.6 10-4 mol/L·min
E)none of these
A)7.4 10-4 mol/L·min
B)3.2 10-4 mol/L·min
C)1.24 10-2 mol/L·min
D)1.6 10-4 mol/L·min
E)none of these
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28
The rate expression for a particular reaction is rate = k[A][B]2.If the initial concentration of B is increased from 0.1 M to 0.3 M,the initial rate will increase by which of the following factors?
A)2
B)6
C)12
D)3
E)9
A)2
B)6
C)12
D)3
E)9
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29
For a reaction:
,[A]0 = 4.2 M,and the first two half-lives are 56 and 28 minutes,respectively.Calculate k (without units).
A)![<strong>For a reaction: ,[A]<sub>0</sub> = 4.2 M,and the first two half-lives are 56 and 28 minutes,respectively.Calculate k (without units).</strong> A) B) C) D) E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f8_cc79_93a6_bfb744e2e388_TB6423_11.jpg)
B)![<strong>For a reaction: ,[A]<sub>0</sub> = 4.2 M,and the first two half-lives are 56 and 28 minutes,respectively.Calculate k (without units).</strong> A) B) C) D) E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f8_cc7a_93a6_57cd4d5f0f80_TB6423_11.jpg)
C)![<strong>For a reaction: ,[A]<sub>0</sub> = 4.2 M,and the first two half-lives are 56 and 28 minutes,respectively.Calculate k (without units).</strong> A) B) C) D) E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f8_cc7b_93a6_ef27f06d29e1_TB6423_11.jpg)
D)![<strong>For a reaction: ,[A]<sub>0</sub> = 4.2 M,and the first two half-lives are 56 and 28 minutes,respectively.Calculate k (without units).</strong> A) B) C) D) E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f8_cc7c_93a6_7faaee707a68_TB6423_11.jpg)
E)none of these
![<strong>For a reaction: ,[A]<sub>0</sub> = 4.2 M,and the first two half-lives are 56 and 28 minutes,respectively.Calculate k (without units).</strong> A) B) C) D) E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f8_a568_93a6_e75085a430a0_TB6423_11.jpg)
A)
![<strong>For a reaction: ,[A]<sub>0</sub> = 4.2 M,and the first two half-lives are 56 and 28 minutes,respectively.Calculate k (without units).</strong> A) B) C) D) E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f8_cc79_93a6_bfb744e2e388_TB6423_11.jpg)
B)
![<strong>For a reaction: ,[A]<sub>0</sub> = 4.2 M,and the first two half-lives are 56 and 28 minutes,respectively.Calculate k (without units).</strong> A) B) C) D) E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f8_cc7a_93a6_57cd4d5f0f80_TB6423_11.jpg)
C)
![<strong>For a reaction: ,[A]<sub>0</sub> = 4.2 M,and the first two half-lives are 56 and 28 minutes,respectively.Calculate k (without units).</strong> A) B) C) D) E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f8_cc7b_93a6_ef27f06d29e1_TB6423_11.jpg)
D)
![<strong>For a reaction: ,[A]<sub>0</sub> = 4.2 M,and the first two half-lives are 56 and 28 minutes,respectively.Calculate k (without units).</strong> A) B) C) D) E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f8_cc7c_93a6_7faaee707a68_TB6423_11.jpg)
E)none of these
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30
For which order reaction is the half-life of the reaction proportional to 1/k (k is the rate constant)?
A)zero order
B)first order
C)second order
D)all of the above
E)none of the above
A)zero order
B)first order
C)second order
D)all of the above
E)none of the above
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31
The following questions refer to the reaction between nitric oxide and hydrogen
2NO + H2 N2O + H2O

-What is the order of this reaction?
A)3
B)2
C)1
D)0
E)cannot be determined from the data
2NO + H2 N2O + H2O

-What is the order of this reaction?
A)3
B)2
C)1
D)0
E)cannot be determined from the data
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32
The half-life of this reaction is approximately
A)15 minutes
B)18 minutes
C)23 minutes
D)36 minutes
E)45 minutes
A)15 minutes
B)18 minutes
C)23 minutes
D)36 minutes
E)45 minutes
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33
The kinetics of the reaction
were studied and the following results obtained,where the rate law is:
For a run where [A]0 = 1.0 10-3 M and [B]0 = 5.0 M,a plot of ln [A] versus t was found to give a straight line with slope = -5.0 10-2 s-1.
For a run where [A]0 = 1.0 10-3 M and [B]0 = 10.0 M,a plot of ln [A] versus t was found to give a straight line with slope = -7.1 10-2 s-1.
-Calculate the value of k (ignore units).
A)22
B)10
C)50
D)1.1
E)none of these
![<strong>The kinetics of the reaction were studied and the following results obtained,where the rate law is: For a run where [A]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>3</sup> M and [B]<sub>0</sub> = 5.0 M,a plot of ln [A] versus t was found to give a straight line with slope = -5.0 \times 10<sup>-</sup><sup>2</sup> s<sup>-</sup><sup>1</sup>. For a run where [A]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>3</sup> M and [B]<sub>0</sub> = 10.0 M,a plot of ln [A] versus t was found to give a straight line with slope = -7.1 \times 10<sup>-</sup><sup>2</sup> s<sup>-</sup><sup>1</sup>. -Calculate the value of k (ignore units).</strong> A)22 B)10 C)50 D)1.1 E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f8_f38e_93a6_31a6fa3982fe_TB6423_11_TB6423_11_TB6423_11.jpg)
![<strong>The kinetics of the reaction were studied and the following results obtained,where the rate law is: For a run where [A]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>3</sup> M and [B]<sub>0</sub> = 5.0 M,a plot of ln [A] versus t was found to give a straight line with slope = -5.0 \times 10<sup>-</sup><sup>2</sup> s<sup>-</sup><sup>1</sup>. For a run where [A]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>3</sup> M and [B]<sub>0</sub> = 10.0 M,a plot of ln [A] versus t was found to give a straight line with slope = -7.1 \times 10<sup>-</sup><sup>2</sup> s<sup>-</sup><sup>1</sup>. -Calculate the value of k (ignore units).</strong> A)22 B)10 C)50 D)1.1 E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f8_f38f_93a6_512646056c97_TB6423_11_TB6423_11_TB6423_11.jpg)
For a run where [A]0 = 1.0 10-3 M and [B]0 = 10.0 M,a plot of ln [A] versus t was found to give a straight line with slope = -7.1 10-2 s-1.
-Calculate the value of k (ignore units).
A)22
B)10
C)50
D)1.1
E)none of these
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34
For a reaction:
,[A]0 = 6.0 M,and the first two half-lives are 56 and 28 minutes,respectively.Calculate [A] at t = 105.9 minutes.
A)5.7 M
B)12 M
C)0.68 M
D)0.33 M
E)none of these
![<strong>For a reaction: ,[A]<sub>0</sub> = 6.0 M,and the first two half-lives are 56 and 28 minutes,respectively.Calculate [A] at t = 105.9 minutes.</strong> A)5.7 M B)12 M C)0.68 M D)0.33 M E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f8_f38d_93a6_27a8b3d513d1_TB6423_11.jpg)
A)5.7 M
B)12 M
C)0.68 M
D)0.33 M
E)none of these
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35
The concentration of O2 at t = 10.minutes is
A)2.0 10-4 mol/L
B)0.32 10-2 mol/L
C)0.16 10-2 mol/L
D)0.64 10-2 mol/L
E)none of these
A)2.0 10-4 mol/L
B)0.32 10-2 mol/L
C)0.16 10-2 mol/L
D)0.64 10-2 mol/L
E)none of these
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36
The following data were obtained for the reaction 2A + B C where rate = [C]/ t
![<strong>The following data were obtained for the reaction 2A + B \to C where rate = \Delta [C]/ \Delta t What is the value of the rate constant?</strong> A)2.13 B)0.213 C)0.426 D)1.70 E)none of these](https://storage.examlex.com/TB6423/11efdc19_1f63_7791_8f65_29ef1e03f265_TB6423_00.jpg)
What is the value of the rate constant?
A)2.13
B)0.213
C)0.426
D)1.70
E)none of these
![<strong>The following data were obtained for the reaction 2A + B \to C where rate = \Delta [C]/ \Delta t What is the value of the rate constant?</strong> A)2.13 B)0.213 C)0.426 D)1.70 E)none of these](https://storage.examlex.com/TB6423/11efdc19_1f63_7791_8f65_29ef1e03f265_TB6423_00.jpg)
What is the value of the rate constant?
A)2.13
B)0.213
C)0.426
D)1.70
E)none of these
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37
The reaction H2SeO3(aq)6I-(aq)+ 4H+(aq) 2I3-(aq)+ 3H2O(l)+ Se(s)was studied at 0°C by the method of initial rates:
![<strong>The reaction H<sub>2</sub>SeO<sub>3</sub>(aq)6I<sup>-</sup>(aq)+ 4H<sup>+</sup>(aq) \to 2I<sub>3</sub><sup>-</sup>(aq)+ 3H<sub>2</sub>O(l)+ Se(s)was studied at 0°C by the method of initial rates: -The rate law is</strong> A)Rate = k[H<sub>2</sub>SeO<sub>3</sub>][H<sup>+</sup>][I<sup>-</sup>] B)Rate = k[H<sub>2</sub>SeO<sub>3</sub>][H<sup>+</sup>]<sup>2</sup>[I<sup>-</sup>] C)Rate = k[H<sub>2</sub>SeO<sub>3</sub>][H<sup>+</sup>][I<sup>-</sup>]<sup>2</sup> D)Rate = k[H<sub>2</sub>SeO<sub>3</sub>]<sup>2</sup>[H<sup>+</sup>][I<sup>-</sup>] E)Rate = k[H<sub>2</sub>SeO<sub>3</sub>][H<sup>+</sup>]<sup>2</sup>[I<sup>-</sup>]<sup>3</sup>](https://storage.examlex.com/TB6423/11efdc18_d91e_6c40_8f65_2376a13bb3f3_TB6423_00.jpg)
-The rate law is
A)Rate = k[H2SeO3][H+][I-]
B)Rate = k[H2SeO3][H+]2[I-]
C)Rate = k[H2SeO3][H+][I-]2
D)Rate = k[H2SeO3]2[H+][I-]
E)Rate = k[H2SeO3][H+]2[I-]3
![<strong>The reaction H<sub>2</sub>SeO<sub>3</sub>(aq)6I<sup>-</sup>(aq)+ 4H<sup>+</sup>(aq) \to 2I<sub>3</sub><sup>-</sup>(aq)+ 3H<sub>2</sub>O(l)+ Se(s)was studied at 0°C by the method of initial rates: -The rate law is</strong> A)Rate = k[H<sub>2</sub>SeO<sub>3</sub>][H<sup>+</sup>][I<sup>-</sup>] B)Rate = k[H<sub>2</sub>SeO<sub>3</sub>][H<sup>+</sup>]<sup>2</sup>[I<sup>-</sup>] C)Rate = k[H<sub>2</sub>SeO<sub>3</sub>][H<sup>+</sup>][I<sup>-</sup>]<sup>2</sup> D)Rate = k[H<sub>2</sub>SeO<sub>3</sub>]<sup>2</sup>[H<sup>+</sup>][I<sup>-</sup>] E)Rate = k[H<sub>2</sub>SeO<sub>3</sub>][H<sup>+</sup>]<sup>2</sup>[I<sup>-</sup>]<sup>3</sup>](https://storage.examlex.com/TB6423/11efdc18_d91e_6c40_8f65_2376a13bb3f3_TB6423_00.jpg)
-The rate law is
A)Rate = k[H2SeO3][H+][I-]
B)Rate = k[H2SeO3][H+]2[I-]
C)Rate = k[H2SeO3][H+][I-]2
D)Rate = k[H2SeO3]2[H+][I-]
E)Rate = k[H2SeO3][H+]2[I-]3
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38
The concentration N2O5 at 100 minutes will be approximately
A)0.03 10-2 mol/L
B)0.06 10-2 mol/L
C)0.10 10-2 mol/L
D)0.01 10-2 mol/L
E)none of these
A)0.03 10-2 mol/L
B)0.06 10-2 mol/L
C)0.10 10-2 mol/L
D)0.01 10-2 mol/L
E)none of these
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39
The following questions refer to the reaction between nitric oxide and hydrogen
2NO + H2 N2O + H2O

-What is the magnitude of the rate constant for this reaction?
A)0.66
B)4.2 10-3
C)870
D)1.9
E)300
2NO + H2 N2O + H2O

-What is the magnitude of the rate constant for this reaction?
A)0.66
B)4.2 10-3
C)870
D)1.9
E)300
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40
The reaction 2A + 5B products is second order in A and first order in B.What is the rate law for this reaction?
A)rate = k[A]2[B]5
B)rate = k[A]1[B]2
C)rate = k[A]2[B]1
D)rate = k[A]5[B]2
E)rate = k[A]2/7[B]5/7
A)rate = k[A]2[B]5
B)rate = k[A]1[B]2
C)rate = k[A]2[B]1
D)rate = k[A]5[B]2
E)rate = k[A]2/7[B]5/7
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41
The reaction
exhibits the rate law
where k = 1.0 10-5 M-1 . s-1 at 25°C.This reaction is run where the initial concentration of NOBr ([NOBr]0)is 1.00 10-1 M. The [NO] after 1.00 hour has passed is
A)3.6 10-4 M
B)9.9 10-3 M
C)9.7 10-3 M
D)1.0 10-3 M
E)none of these
![<strong>The reaction exhibits the rate law where k = 1.0 \times 10<sup>-</sup><sup>5</sup> M<sup>-</sup><sup>1</sup> . s<sup>-</sup><sup>1</sup> at 25°C.This reaction is run where the initial concentration of NOBr ([NOBr]<sub>0</sub>)is 1.00 \times 10<sup>-</sup><sup>1</sup> M. The [NO] after 1.00 hour has passed is</strong> A)3.6 \times 10<sup>-</sup><sup>4 </sup>M B)9.9 \times 10<sup>-</sup><sup>3 </sup>M C)9.7 \times 10<sup>-</sup><sup>3 </sup>M D)1.0 \times 10<sup>-</sup><sup>3 </sup>M E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66fa_0510_93a6_373fdd2fc465_TB6423_11.jpg)
![<strong>The reaction exhibits the rate law where k = 1.0 \times 10<sup>-</sup><sup>5</sup> M<sup>-</sup><sup>1</sup> . s<sup>-</sup><sup>1</sup> at 25°C.This reaction is run where the initial concentration of NOBr ([NOBr]<sub>0</sub>)is 1.00 \times 10<sup>-</sup><sup>1</sup> M. The [NO] after 1.00 hour has passed is</strong> A)3.6 \times 10<sup>-</sup><sup>4 </sup>M B)9.9 \times 10<sup>-</sup><sup>3 </sup>M C)9.7 \times 10<sup>-</sup><sup>3 </sup>M D)1.0 \times 10<sup>-</sup><sup>3 </sup>M E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66fa_0511_93a6_0b7a2668b832_TB6423_11.jpg)
A)3.6 10-4 M
B)9.9 10-3 M
C)9.7 10-3 M
D)1.0 10-3 M
E)none of these
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42
The reaction A B + C is known to be zero order in A with a rate constant of 5.0 10-2 mol/L·s at 25°C.An experiment was run at 25°C where [A]0 = 1.0 10-3 M.
-The integrated rate law is
A)[A] = kt
B)[A] - [A]0 = kt
C)![<strong>The reaction A \to B + C is known to be zero order in A with a rate constant of 5.0 \times 10<sup>-</sup><sup>2</sup> mol/L·s at 25°C.An experiment was run at 25°C where [A]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>3</sup> M. -The integrated rate law is</strong> A)[A] = kt B)[A] - [A]<sub>0</sub> = kt C) D) E)[A]<sub>0</sub> - [A] = kt](https://storage.examlex.com/TB6423/11eaa8f0_66f9_68c1_93a6_930ef06d718d_TB6423_11.jpg)
D)![<strong>The reaction A \to B + C is known to be zero order in A with a rate constant of 5.0 \times 10<sup>-</sup><sup>2</sup> mol/L·s at 25°C.An experiment was run at 25°C where [A]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>3</sup> M. -The integrated rate law is</strong> A)[A] = kt B)[A] - [A]<sub>0</sub> = kt C) D) E)[A]<sub>0</sub> - [A] = kt](https://storage.examlex.com/TB6423/11eaa8f0_66f9_68c2_93a6_d3c2eed78e79_TB6423_11.jpg)
E)[A]0 - [A] = kt
-The integrated rate law is
A)[A] = kt
B)[A] - [A]0 = kt
C)
![<strong>The reaction A \to B + C is known to be zero order in A with a rate constant of 5.0 \times 10<sup>-</sup><sup>2</sup> mol/L·s at 25°C.An experiment was run at 25°C where [A]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>3</sup> M. -The integrated rate law is</strong> A)[A] = kt B)[A] - [A]<sub>0</sub> = kt C) D) E)[A]<sub>0</sub> - [A] = kt](https://storage.examlex.com/TB6423/11eaa8f0_66f9_68c1_93a6_930ef06d718d_TB6423_11.jpg)
D)
![<strong>The reaction A \to B + C is known to be zero order in A with a rate constant of 5.0 \times 10<sup>-</sup><sup>2</sup> mol/L·s at 25°C.An experiment was run at 25°C where [A]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>3</sup> M. -The integrated rate law is</strong> A)[A] = kt B)[A] - [A]<sub>0</sub> = kt C) D) E)[A]<sub>0</sub> - [A] = kt](https://storage.examlex.com/TB6423/11eaa8f0_66f9_68c2_93a6_d3c2eed78e79_TB6423_11.jpg)
E)[A]0 - [A] = kt
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43
At a particular temperature,N2O5 decomposes according to a first-order rate law with a half-life of 3.0 s.If the initial concentration of N2O5 is 1.0 1016 molecules/cm3,what will be the concentration in molecules/cm3 after 16.1 s?
A)2.4 1014
B)3.3 101
C)1.0 1016
D)1.4 1014
E)2.3 10-1
A)2.4 1014
B)3.3 101
C)1.0 1016
D)1.4 1014
E)2.3 10-1
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44
The reaction
is known to be zero order in A with a rate constant of 5.0 10-2 mol/L s at 25°C.An experiment was run at 25°C where [A]0 = 2.0 10-3 M.After 5.0 minutes,the rate is
A)5.0 10-2 mol/L·s
B)2.5 10-2 mol/L·s
C)1.3 10-2 mol/L·s
D)2.0 10-3 mol/L·s
E)none of these
![<strong>The reaction is known to be zero order in A with a rate constant of 5.0 \times 10<sup>-</sup><sup>2</sup> mol/L s at 25°C.An experiment was run at 25°C where [A]<sub>0</sub> = 2.0 \times 10<sup>-</sup><sup>3</sup> M.After 5.0 minutes,the rate is</strong> A)5.0 \times 10<sup>-</sup><sup>2 </sup>mol/L·s B)2.5 \times 10<sup>-</sup><sup>2 </sup>mol/L·s C)1.3 \times 10<sup>-</sup><sup>2 </sup>mol/L·s D)2.0 \times 10<sup>-</sup><sup>3 </sup>mol/L·s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f9_68c3_93a6_1d16ba24d7b5_TB6423_11.jpg)
A)5.0 10-2 mol/L·s
B)2.5 10-2 mol/L·s
C)1.3 10-2 mol/L·s
D)2.0 10-3 mol/L·s
E)none of these
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45
The reaction
exhibits the rate law
where k = 1.0 10-5 M-1 s-1 at 25°C.This reaction is run where the initial concentration of NOBr ([NOBr]0)is 0.11 M.What is one half-life for this experiment?
A)
s
B)
C)
s
D)
s
E)none of these
![<strong>The reaction exhibits the rate law where k = 1.0 \times 10<sup>-</sup><sup>5</sup> M<sup>-</sup><sup>1</sup> s<sup>-</sup><sup>1</sup> at 25°C.This reaction is run where the initial concentration of NOBr ([NOBr]<sub>0</sub>)is 0.11 M.What is one half-life for this experiment?</strong> A) s B) C) s D) <sup> </sup>s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f9_b6ea_93a6_5db569d7b2bd_TB6423_11.jpg)
![<strong>The reaction exhibits the rate law where k = 1.0 \times 10<sup>-</sup><sup>5</sup> M<sup>-</sup><sup>1</sup> s<sup>-</sup><sup>1</sup> at 25°C.This reaction is run where the initial concentration of NOBr ([NOBr]<sub>0</sub>)is 0.11 M.What is one half-life for this experiment?</strong> A) s B) C) s D) <sup> </sup>s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f9_b6eb_93a6_3937b73d17e5_TB6423_11.jpg)
A)
![<strong>The reaction exhibits the rate law where k = 1.0 \times 10<sup>-</sup><sup>5</sup> M<sup>-</sup><sup>1</sup> s<sup>-</sup><sup>1</sup> at 25°C.This reaction is run where the initial concentration of NOBr ([NOBr]<sub>0</sub>)is 0.11 M.What is one half-life for this experiment?</strong> A) s B) C) s D) <sup> </sup>s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f9_b6ec_93a6_1bb0be28e809_TB6423_11.jpg)
B)
![<strong>The reaction exhibits the rate law where k = 1.0 \times 10<sup>-</sup><sup>5</sup> M<sup>-</sup><sup>1</sup> s<sup>-</sup><sup>1</sup> at 25°C.This reaction is run where the initial concentration of NOBr ([NOBr]<sub>0</sub>)is 0.11 M.What is one half-life for this experiment?</strong> A) s B) C) s D) <sup> </sup>s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f9_ddfd_93a6_a51865d5b806_TB6423_11.jpg)
C)
![<strong>The reaction exhibits the rate law where k = 1.0 \times 10<sup>-</sup><sup>5</sup> M<sup>-</sup><sup>1</sup> s<sup>-</sup><sup>1</sup> at 25°C.This reaction is run where the initial concentration of NOBr ([NOBr]<sub>0</sub>)is 0.11 M.What is one half-life for this experiment?</strong> A) s B) C) s D) <sup> </sup>s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f9_ddfe_93a6_7bcf43cf1fe1_TB6423_11.jpg)
D)
![<strong>The reaction exhibits the rate law where k = 1.0 \times 10<sup>-</sup><sup>5</sup> M<sup>-</sup><sup>1</sup> s<sup>-</sup><sup>1</sup> at 25°C.This reaction is run where the initial concentration of NOBr ([NOBr]<sub>0</sub>)is 0.11 M.What is one half-life for this experiment?</strong> A) s B) C) s D) <sup> </sup>s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f9_ddff_93a6_7327ccbf40bb_TB6423_11.jpg)
E)none of these
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46
A chemical reaction that is first order in X is observed to have a rate constant of 1.7 10-2s-1.If the initial concentration of X is 1.0 M,what is the concentration of X after 190 s?
A)25 M
B)0.68 M
C)0.24 M
D)0.96 M
E)0.040 M
A)25 M
B)0.68 M
C)0.24 M
D)0.96 M
E)0.040 M
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47
The OH· radical disproportionates according to the elementary chemical reaction
This reaction is second order in OH·.The rate constant for the reaction is 2.0 10-12 cm3/molecules at room temperature.If the initial OH concentration is 1.3 1013 molecules/cm3,what is the first half-life for the reaction?
A)3.5 1011 s
B)2.6 101 s
C)3.8 10-2 s
D)7.7 10-14 s
E)1.9 10-2 s

A)3.5 1011 s
B)2.6 101 s
C)3.8 10-2 s
D)7.7 10-14 s
E)1.9 10-2 s
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48
Determine the magnitude of the pseudo-rate constant (k')if the magnitude of X in the rate data is 0.00905.
A)4.3 10-3
B)1.2 10-2
C)0.86
D)0.31
E)1.81 10-3
A)4.3 10-3
B)1.2 10-2
C)0.86
D)0.31
E)1.81 10-3
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49
For the reaction A Products,successive half-lives are observed to be 10.0 min and 40.0 min.
-The reaction follows the integrated rate law
A)
B)
C)
D)
E)none of these
-The reaction follows the integrated rate law
A)

B)

C)

D)

E)none of these
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50
At a given temperature,a first-order reaction has a rate constant of 3.4 10-3 s-1.The time required for the reaction to be 44% completed is
A)4.0 min
B)1.2 min
C)20 min
D)2.8 min
E)19 min
A)4.0 min
B)1.2 min
C)20 min
D)2.8 min
E)19 min
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51
For the reaction A Products,successive half-lives are observed to be 10.0 min and 40.0 min.
-The reaction
is first order in N2O5.For this reaction at 45oC,the rate constant k = 1.0 10-5 s-1,where the rate law is defined as
For a particular experiment ([N2O5]0 = 1.0 10-3 M),calculate [N2O5] after 3.5 105 seconds.
A)3.5 M
B)1.0 10-3 M
C)3.0 10-5 M
D)0 M
E)10 M
-The reaction
![<strong>For the reaction A \to Products,successive half-lives are observed to be 10.0 min and 40.0 min. -The reaction is first order in N<sub>2</sub>O<sub>5</sub>.For this reaction at 45<sup>o</sup>C,the rate constant k = 1.0 \times 10<sup>-</sup><sup>5</sup> s<sup>-</sup><sup>1</sup>,where the rate law is defined as For a particular experiment ([N<sub>2</sub>O<sub>5</sub>]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>3 </sup>M),calculate [N<sub>2</sub>O<sub>5</sub>] after 3.5 \times 10<sup>5</sup> seconds.</strong> A)3.5 M B)1.0 \times 10<sup>-</sup><sup>3</sup> M C)3.0 \times 10<sup>-</sup><sup>5</sup> M D)0 M E)10 M](https://storage.examlex.com/TB6423/11eaa8f0_66fa_2c26_93a6_dbf7104cfd94_TB6423_11.jpg)
![<strong>For the reaction A \to Products,successive half-lives are observed to be 10.0 min and 40.0 min. -The reaction is first order in N<sub>2</sub>O<sub>5</sub>.For this reaction at 45<sup>o</sup>C,the rate constant k = 1.0 \times 10<sup>-</sup><sup>5</sup> s<sup>-</sup><sup>1</sup>,where the rate law is defined as For a particular experiment ([N<sub>2</sub>O<sub>5</sub>]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>3 </sup>M),calculate [N<sub>2</sub>O<sub>5</sub>] after 3.5 \times 10<sup>5</sup> seconds.</strong> A)3.5 M B)1.0 \times 10<sup>-</sup><sup>3</sup> M C)3.0 \times 10<sup>-</sup><sup>5</sup> M D)0 M E)10 M](https://storage.examlex.com/TB6423/11eaa8f0_66fa_2c27_93a6_750651088578_TB6423_11.jpg)
A)3.5 M
B)1.0 10-3 M
C)3.0 10-5 M
D)0 M
E)10 M
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52
Consider the reaction 3A + B + C D + E where the rate law is defined as
.
An experiment is carried out where [B]0 = [C]0 = 1.00 M and [A]0 = 1.00 10-4 M.
-The concentration of C after 10.0 minutes is
A)1.00 M
B)1.10 10-5 M
C)0.330 M
D)0.100 M
E)none of these
![<strong>Consider the reaction 3A + B + C \to D + E where the rate law is defined as . An experiment is carried out where [B]<sub>0</sub> = [C]<sub>0</sub> = 1.00 M and [A]<sub>0</sub> = 1.00 \times 10<sup>-</sup><sup>4</sup> M. -The concentration of C after 10.0 minutes is</strong> A)1.00 M B)1.10 \times 10<sup>-</sup><sup>5</sup> M C)0.330 M D)0.100 M E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66fa_5338_93a6_f9c169f1857b_TB6423_11_TB6423_11_TB6423_11_TB6423_11.jpg)
An experiment is carried out where [B]0 = [C]0 = 1.00 M and [A]0 = 1.00 10-4 M.
-The concentration of C after 10.0 minutes is
A)1.00 M
B)1.10 10-5 M
C)0.330 M
D)0.100 M
E)none of these
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53
The reaction
is known to be zero order in A with a rate constant of 5.0 10-2 mol/L s at 25°C.An experiment was run at 25°C where [A]0 =
M.The half-life for the reaction is
A)
s
B)
s
C)
s
D)
s
E)none of these
![<strong>The reaction is known to be zero order in A with a rate constant of 5.0 \times 10<sup>-</sup><sup>2</sup> mol/L s at 25°C.An experiment was run at 25°C where [A]<sub>0</sub> = <sup> </sup>M.The half-life for the reaction is</strong> A) <sup> </sup>s B) <sup> </sup>s C) s D) <sup> </sup>s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f9_8fd4_93a6_799aee19abe0_TB6423_11.jpg)
![<strong>The reaction is known to be zero order in A with a rate constant of 5.0 \times 10<sup>-</sup><sup>2</sup> mol/L s at 25°C.An experiment was run at 25°C where [A]<sub>0</sub> = <sup> </sup>M.The half-life for the reaction is</strong> A) <sup> </sup>s B) <sup> </sup>s C) s D) <sup> </sup>s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f9_8fd5_93a6_a5aa1aba3371_TB6423_11.jpg)
A)
![<strong>The reaction is known to be zero order in A with a rate constant of 5.0 \times 10<sup>-</sup><sup>2</sup> mol/L s at 25°C.An experiment was run at 25°C where [A]<sub>0</sub> = <sup> </sup>M.The half-life for the reaction is</strong> A) <sup> </sup>s B) <sup> </sup>s C) s D) <sup> </sup>s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f9_8fd6_93a6_d9d31c313310_TB6423_11.jpg)
B)
![<strong>The reaction is known to be zero order in A with a rate constant of 5.0 \times 10<sup>-</sup><sup>2</sup> mol/L s at 25°C.An experiment was run at 25°C where [A]<sub>0</sub> = <sup> </sup>M.The half-life for the reaction is</strong> A) <sup> </sup>s B) <sup> </sup>s C) s D) <sup> </sup>s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f9_8fd7_93a6_25634a2c0d08_TB6423_11.jpg)
C)
![<strong>The reaction is known to be zero order in A with a rate constant of 5.0 \times 10<sup>-</sup><sup>2</sup> mol/L s at 25°C.An experiment was run at 25°C where [A]<sub>0</sub> = <sup> </sup>M.The half-life for the reaction is</strong> A) <sup> </sup>s B) <sup> </sup>s C) s D) <sup> </sup>s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f9_b6e8_93a6_83234f34a14a_TB6423_11.jpg)
D)
![<strong>The reaction is known to be zero order in A with a rate constant of 5.0 \times 10<sup>-</sup><sup>2</sup> mol/L s at 25°C.An experiment was run at 25°C where [A]<sub>0</sub> = <sup> </sup>M.The half-life for the reaction is</strong> A) <sup> </sup>s B) <sup> </sup>s C) s D) <sup> </sup>s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66f9_b6e9_93a6_c9762cf570c4_TB6423_11.jpg)
E)none of these
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54
Consider the reaction 3A + B + C D + E where the rate law is defined as
.
An experiment is carried out where [B]0 = [C]0 = 1.00 M and [A]0 = 1.00 10-4 M.
-After 3.00 minutes,[A] = 3.26 10-5 M.The value of k is
A)6.23 10-3 L3/mol3·s
B)3.26 10-5 L3/mol3·s
C)1.15 102 L3/mol3·s
D)1.00 108 L3/mol3·s
E)none of these
![<strong>Consider the reaction 3A + B + C \to D + E where the rate law is defined as . An experiment is carried out where [B]<sub>0</sub> = [C]<sub>0</sub> = 1.00 M and [A]<sub>0</sub> = 1.00 \times 10<sup>-</sup><sup>4</sup> M. -After 3.00 minutes,[A] = 3.26 \times 10<sup>-</sup><sup>5</sup> M.The value of k is</strong> A)6.23 \times 10<sup>-</sup><sup>3</sup> L<sup>3</sup>/mol<sup>3</sup>·s B)3.26 \times 10<sup>-</sup><sup>5</sup> L<sup>3</sup>/mol<sup>3</sup>·s C)1.15 \times 10<sup>2</sup> L<sup>3</sup>/mol<sup>3</sup>·s D)1.00 \times 10<sup>8</sup> L<sup>3</sup>/mol<sup>3</sup>·s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66fa_5338_93a6_f9c169f1857b_TB6423_11_TB6423_11_TB6423_11_TB6423_11.jpg)
An experiment is carried out where [B]0 = [C]0 = 1.00 M and [A]0 = 1.00 10-4 M.
-After 3.00 minutes,[A] = 3.26 10-5 M.The value of k is
A)6.23 10-3 L3/mol3·s
B)3.26 10-5 L3/mol3·s
C)1.15 102 L3/mol3·s
D)1.00 108 L3/mol3·s
E)none of these
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55
Consider the reaction 3A + B + C D + E where the rate law is defined as
.
An experiment is carried out where [B]0 = [C]0 = 1.00 M and [A]0 = 1.00 10-4 M.
-The concentration of A after 10.0 minutes is
A)1.06 10-9 M
B)2.38 10-6 M
C)9.80 10-6 M
D)1.27 10-5 M
E)none of these
![<strong>Consider the reaction 3A + B + C \to D + E where the rate law is defined as . An experiment is carried out where [B]<sub>0</sub> = [C]<sub>0</sub> = 1.00 M and [A]<sub>0</sub> = 1.00 \times 10<sup>-</sup><sup>4</sup> M. -The concentration of A after 10.0 minutes is</strong> A)1.06 \times 10<sup>-</sup><sup>9</sup> M B)2.38 \times 10<sup>-</sup><sup>6</sup> M C)9.80 \times 10<sup>-</sup><sup>6</sup> M D)1.27 \times 10<sup>-</sup><sup>5</sup> M E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66fa_5338_93a6_f9c169f1857b_TB6423_11_TB6423_11_TB6423_11_TB6423_11.jpg)
An experiment is carried out where [B]0 = [C]0 = 1.00 M and [A]0 = 1.00 10-4 M.
-The concentration of A after 10.0 minutes is
A)1.06 10-9 M
B)2.38 10-6 M
C)9.80 10-6 M
D)1.27 10-5 M
E)none of these
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56
The reaction
is second order in A.When [A]0 = 0.100 M,the reaction is 20.0% complete in 35.9 minutes.Calculate the value of the rate constant (in L/min·mol).
A)6.96 10-2
B)5.57 10-4
C)1.57
D)1.11
E)none of these
![<strong>The reaction is second order in A.When [A]<sub>0</sub> = 0.100 M,the reaction is 20.0% complete in 35.9 minutes.Calculate the value of the rate constant (in L/min·mol).</strong> A)6.96 \times 10<sup>-</sup><sup>2</sup> B)5.57 \times 10<sup>-</sup><sup>4</sup> C)1.57 D)1.11 E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66fa_7a49_93a6_775d41f201df_TB6423_11.jpg)
A)6.96 10-2
B)5.57 10-4
C)1.57
D)1.11
E)none of these
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57
What is the concentration of B after 5 10-3 sec?
A)5.0 10-5 M
B)5.0 10-4 M
C)7.5 10-4 M
D)2.5 10-4 M
E)none of these
A)5.0 10-5 M
B)5.0 10-4 M
C)7.5 10-4 M
D)2.5 10-4 M
E)none of these
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58
The reaction
is second order in A.When [A]0 = 0.100 M,the reaction is 20.0% complete in 43.2 minutes.Calculate the half-life for the reaction.
A)1.73 102 min
B)10.8 min
C)2.16 104 min
D)7.68 min
E)none of these
![<strong>The reaction is second order in A.When [A]<sub>0</sub> = 0.100 M,the reaction is 20.0% complete in 43.2 minutes.Calculate the half-life for the reaction.</strong> A)1.73 \times 10<sup>2</sup> min B)10.8 min C)2.16 \times 10<sup>4 </sup>min D)7.68 min E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66fa_7a4a_93a6_3bb66ffa0d66_TB6423_11.jpg)
A)1.73 102 min
B)10.8 min
C)2.16 104 min
D)7.68 min
E)none of these
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59
A first-order reaction is 40.0% complete at the end of 48.1 minutes.What is the value of the rate constant (in min-1)?
A)1.90 10-2
B)1.06 10-2
C)94.2
D)52.5
E)none of these
A)1.90 10-2
B)1.06 10-2
C)94.2
D)52.5
E)none of these
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60
Consider the reaction 3A + B + C D + E where the rate law is defined as
.
An experiment is carried out where [B]0 = [C]0 = 1.00 M and [A]0 = 1.00 10-4 M.
-The half-life for this experiment is
A)1.11 102 s
B)87.0 s
C)6.03 10-3 s
D)117 s
E)none of these
![<strong>Consider the reaction 3A + B + C \to D + E where the rate law is defined as . An experiment is carried out where [B]<sub>0</sub> = [C]<sub>0</sub> = 1.00 M and [A]<sub>0</sub> = 1.00 \times 10<sup>-</sup><sup>4</sup> M. -The half-life for this experiment is</strong> A)1.11 \times 10<sup>2</sup> s B)87.0 s C)6.03 \times 10<sup>-</sup><sup>3</sup> s D)117 s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66fa_5338_93a6_f9c169f1857b_TB6423_11_TB6423_11_TB6423_11_TB6423_11.jpg)
An experiment is carried out where [B]0 = [C]0 = 1.00 M and [A]0 = 1.00 10-4 M.
-The half-life for this experiment is
A)1.11 102 s
B)87.0 s
C)6.03 10-3 s
D)117 s
E)none of these
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61
Two isomers (A and B)of a given compound dimerize as follows:
Both processes are known to be second order in reactant,and k1 is known to be 0.25 L/mol·s at 25°C,where
In a particular experiment,A and B were placed in separate containers at 25°,where [A]0 = 1.0 10-2 M and [B]0 = 2.5 10-2 M.It was found that [A] = 3[B] after the reactions progressed for 3.0 minutes.
-Calculate the concentration of A2 after 3.0 minutes.
A)2.8 10-22 M
B)6.9 10-3 M
C)3.1 10-3 M
D)1.6 10-3 M
E)none of these
![<strong>Two isomers (A and B)of a given compound dimerize as follows: Both processes are known to be second order in reactant,and k<sub>1 </sub>is known to be 0.25 L/mol·s at 25°C,where <sup> </sup> In a particular experiment,A and B were placed in separate containers at 25°,where [A]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>2</sup> M and [B]<sub>0</sub> = 2.5 \times 10<sup>-</sup><sup>2</sup> M.It was found that [A] = 3[B] after the reactions progressed for 3.0 minutes. -Calculate the concentration of A<sub>2</sub> after 3.0 minutes.</strong> A)2.8 \times 10<sup>-</sup><sup>22</sup> M B)6.9 \times 10<sup>-</sup><sup>3</sup> M C)3.1 \times 10<sup>-</sup><sup>3</sup> M D)1.6 \times 10<sup>-</sup><sup>3</sup> M E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66fa_ef7e_93a6_ef2701f367bd_TB6423_11_TB6423_11.jpg)
Both processes are known to be second order in reactant,and k1 is known to be 0.25 L/mol·s at 25°C,where
![<strong>Two isomers (A and B)of a given compound dimerize as follows: Both processes are known to be second order in reactant,and k<sub>1 </sub>is known to be 0.25 L/mol·s at 25°C,where <sup> </sup> In a particular experiment,A and B were placed in separate containers at 25°,where [A]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>2</sup> M and [B]<sub>0</sub> = 2.5 \times 10<sup>-</sup><sup>2</sup> M.It was found that [A] = 3[B] after the reactions progressed for 3.0 minutes. -Calculate the concentration of A<sub>2</sub> after 3.0 minutes.</strong> A)2.8 \times 10<sup>-</sup><sup>22</sup> M B)6.9 \times 10<sup>-</sup><sup>3</sup> M C)3.1 \times 10<sup>-</sup><sup>3</sup> M D)1.6 \times 10<sup>-</sup><sup>3</sup> M E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66fa_ef7f_93a6_833870defd7a_TB6423_11_TB6423_11.jpg)
In a particular experiment,A and B were placed in separate containers at 25°,where [A]0 = 1.0 10-2 M and [B]0 = 2.5 10-2 M.It was found that [A] = 3[B] after the reactions progressed for 3.0 minutes.
-Calculate the concentration of A2 after 3.0 minutes.
A)2.8 10-22 M
B)6.9 10-3 M
C)3.1 10-3 M
D)1.6 10-3 M
E)none of these
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62
The rate law for a reaction is found to be Rate = k[A]2[B].Which of the following mechanisms gives this rate law?
I.A + B
E (fast)
E + B C + D (slow)
II.A + B
E (fast)
E + A C + D (slow)
III.A + A E (slow).
E + B C + D (fast)
A)I
B)II
C)III
D)two of these
E)none of these
I.A + B
![<strong>The rate law for a reaction is found to be Rate = k[A]<sup>2</sup>[B].Which of the following mechanisms gives this rate law? I.A + B E (fast) E + B \to C + D (slow) II.A + B E (fast) E + A \to C + D (slow) III.A + A \to E (slow). E + B \to C + D (fast)</strong> A)I B)II C)III D)two of these E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66fb_d9f0_93a6_2d00dda4c903_TB6423_11.jpg)
E + B C + D (slow)
II.A + B
![<strong>The rate law for a reaction is found to be Rate = k[A]<sup>2</sup>[B].Which of the following mechanisms gives this rate law? I.A + B E (fast) E + B \to C + D (slow) II.A + B E (fast) E + A \to C + D (slow) III.A + A \to E (slow). E + B \to C + D (fast)</strong> A)I B)II C)III D)two of these E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66fb_d9f1_93a6_97991a33df82_TB6423_11.jpg)
E + A C + D (slow)
III.A + A E (slow).
E + B C + D (fast)
A)I
B)II
C)III
D)two of these
E)none of these
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63
A particular first-order reaction has a rate constant of 0.0107 s-1.What is the half-life for this reaction?
A)1.00 s
B)64.6 s
C)93.2 s
D)0.0155 s
E)0.0107 s
A)1.00 s
B)64.6 s
C)93.2 s
D)0.0155 s
E)0.0107 s
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64
The experimental rate law for the decomposition of nitrous oxide (N2O)to N2 and O2 is Rate = k[N2O]2.Two mechanisms are proposed:
I.N2O N2 + O
N2O + O N2 + O2
II.2N2O
N4O2
N4O2 2N2 + O2
Which of the following could be a correct mechanism?
A)Mechanism I,with the first step as the rate-determining step.
B)Mechanism I,with the second step as the rate-determining step as long as the first step is a fast equilibrium step.
C)Mechanism II,with the second step as the rate-determining step if the first step is a fast equilibrium step.
D)None of the choices (A-C)could be correct.
E)At least two of the above choices (A-C)could be correct.
I.N2O N2 + O
N2O + O N2 + O2
II.2N2O
![<strong>The experimental rate law for the decomposition of nitrous oxide (N<sub>2</sub>O)to N<sub>2</sub> and O<sub>2</sub> is Rate = k[N<sub>2</sub>O]<sup>2</sup>.Two mechanisms are proposed: I.N<sub>2</sub>O \to N<sub>2</sub> + O N<sub>2</sub>O + O \to N<sub>2</sub> + O<sub>2</sub> II.2N<sub>2</sub>O N<sub>4</sub>O<sub>2</sub> N<sub>4</sub>O<sub>2</sub> \to 2N<sub>2</sub> + O<sub>2</sub> Which of the following could be a correct mechanism?</strong> A)Mechanism I,with the first step as the rate-determining step. B)Mechanism I,with the second step as the rate-determining step as long as the first step is a fast equilibrium step. C)Mechanism II,with the second step as the rate-determining step if the first step is a fast equilibrium step. D)None of the choices (A-C)could be correct. E)At least two of the above choices (A-C)could be correct.](https://storage.examlex.com/TB6423/11eaa8f0_66fc_0102_93a6_595a1f94c072_TB6423_11.jpg)
N4O2 2N2 + O2
Which of the following could be a correct mechanism?
A)Mechanism I,with the first step as the rate-determining step.
B)Mechanism I,with the second step as the rate-determining step as long as the first step is a fast equilibrium step.
C)Mechanism II,with the second step as the rate-determining step if the first step is a fast equilibrium step.
D)None of the choices (A-C)could be correct.
E)At least two of the above choices (A-C)could be correct.
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65
The radioactive nuclide
undergoes first-order decay with a half-life of 9.31 min.If a quantity of
Is produced,what fraction remains after 82.5 seconds?
A)0.113
B)0.00215
C)0.148
D)0.903
E)0.0973


Is produced,what fraction remains after 82.5 seconds?
A)0.113
B)0.00215
C)0.148
D)0.903
E)0.0973
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66
Determine the molecularity of the following elementary reaction: O3 O2 + O.
A)unimolecular
B)bimolecular
C)termolecular
D)quadmolecular
E)molecularity cannot be determined
A)unimolecular
B)bimolecular
C)termolecular
D)quadmolecular
E)molecularity cannot be determined
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67
Of what use is it to find a rate law for a reaction?
A)We can use the rate law to directly determine coefficients in the balanced equation.
B)From the rate law we can evaluate potential reaction mechanisms.
C)The rate law gives us a good indication of the thermodynamic stability of the products.
D)The rate law can lead us to determine the equilibrium constant for the reaction.
E)None of these.
A)We can use the rate law to directly determine coefficients in the balanced equation.
B)From the rate law we can evaluate potential reaction mechanisms.
C)The rate law gives us a good indication of the thermodynamic stability of the products.
D)The rate law can lead us to determine the equilibrium constant for the reaction.
E)None of these.
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68
The reaction A products is first order.If the initial concentration of A is 0.528 M and,after 16.3 seconds have elapsed,the concentration of A has fallen to 0.0122 M,what is the rate constant of the reaction?
A)0.231 s-1
B)0.0425 s-1
C)0.0316 s-1
D)4.91 s-1
E)0.0613 s-1
A)0.231 s-1
B)0.0425 s-1
C)0.0316 s-1
D)4.91 s-1
E)0.0613 s-1
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69
The reaction A products is second order.If the initial concentration of A is 0.436 M and,after 52.8 seconds have elapsed,the concentration of A has fallen to 0.0476 M,what is the rate constant of the reaction?
A)0.0419 M-1 s-1
B)0.354 M-1 s-1
C)0.0131 M-1 s-1
D)0.00736 M-1 s-1
E)0.0189 M-1 s-1
A)0.0419 M-1 s-1
B)0.354 M-1 s-1
C)0.0131 M-1 s-1
D)0.00736 M-1 s-1
E)0.0189 M-1 s-1
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70
The decomposition of N2O5(g)to NO2(g)and O2(g)obeys first-order kinetics.Assuming the form of the rate law is:
Where k = 3.4 10-5 s-1 at 25°C,what is the initial rate of reaction at 25°C where [N2O5]0 = 8.2 10-2 M?
A)
mol/L·s
B)
mol/L·s
C)
mol/L·s
D)
mol/L·s
E)none of these
![<strong>The decomposition of N<sub>2</sub>O<sub>5</sub>(g)to NO<sub>2</sub>(g)and O<sub>2</sub>(g)obeys first-order kinetics.Assuming the form of the rate law is: <sup> </sup> <sup> </sup> Where k = 3.4 \times 10<sup>-</sup><sup>5</sup> s<sup>-</sup><sup>1</sup> at 25°C,what is the initial rate of reaction at 25°C where [N<sub>2</sub>O<sub>5</sub>]<sub>0</sub> = 8.2 \times 10<sup>-</sup><sup>2</sup> M?</strong> A) mol/L·s B) mol/L·s C) <sup> </sup>mol/L·s D) mol/L·s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66fb_1692_93a6_45218845056e_TB6423_11.jpg)
Where k = 3.4 10-5 s-1 at 25°C,what is the initial rate of reaction at 25°C where [N2O5]0 = 8.2 10-2 M?
A)
![<strong>The decomposition of N<sub>2</sub>O<sub>5</sub>(g)to NO<sub>2</sub>(g)and O<sub>2</sub>(g)obeys first-order kinetics.Assuming the form of the rate law is: <sup> </sup> <sup> </sup> Where k = 3.4 \times 10<sup>-</sup><sup>5</sup> s<sup>-</sup><sup>1</sup> at 25°C,what is the initial rate of reaction at 25°C where [N<sub>2</sub>O<sub>5</sub>]<sub>0</sub> = 8.2 \times 10<sup>-</sup><sup>2</sup> M?</strong> A) mol/L·s B) mol/L·s C) <sup> </sup>mol/L·s D) mol/L·s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66fb_3da3_93a6_7b5708d4ccf1_TB6423_11.jpg)
B)
![<strong>The decomposition of N<sub>2</sub>O<sub>5</sub>(g)to NO<sub>2</sub>(g)and O<sub>2</sub>(g)obeys first-order kinetics.Assuming the form of the rate law is: <sup> </sup> <sup> </sup> Where k = 3.4 \times 10<sup>-</sup><sup>5</sup> s<sup>-</sup><sup>1</sup> at 25°C,what is the initial rate of reaction at 25°C where [N<sub>2</sub>O<sub>5</sub>]<sub>0</sub> = 8.2 \times 10<sup>-</sup><sup>2</sup> M?</strong> A) mol/L·s B) mol/L·s C) <sup> </sup>mol/L·s D) mol/L·s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66fb_3da4_93a6_ade05276a406_TB6423_11.jpg)
C)
![<strong>The decomposition of N<sub>2</sub>O<sub>5</sub>(g)to NO<sub>2</sub>(g)and O<sub>2</sub>(g)obeys first-order kinetics.Assuming the form of the rate law is: <sup> </sup> <sup> </sup> Where k = 3.4 \times 10<sup>-</sup><sup>5</sup> s<sup>-</sup><sup>1</sup> at 25°C,what is the initial rate of reaction at 25°C where [N<sub>2</sub>O<sub>5</sub>]<sub>0</sub> = 8.2 \times 10<sup>-</sup><sup>2</sup> M?</strong> A) mol/L·s B) mol/L·s C) <sup> </sup>mol/L·s D) mol/L·s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66fb_3da5_93a6_e9fc09ca3539_TB6423_11.jpg)
D)
![<strong>The decomposition of N<sub>2</sub>O<sub>5</sub>(g)to NO<sub>2</sub>(g)and O<sub>2</sub>(g)obeys first-order kinetics.Assuming the form of the rate law is: <sup> </sup> <sup> </sup> Where k = 3.4 \times 10<sup>-</sup><sup>5</sup> s<sup>-</sup><sup>1</sup> at 25°C,what is the initial rate of reaction at 25°C where [N<sub>2</sub>O<sub>5</sub>]<sub>0</sub> = 8.2 \times 10<sup>-</sup><sup>2</sup> M?</strong> A) mol/L·s B) mol/L·s C) <sup> </sup>mol/L·s D) mol/L·s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66fb_3da6_93a6_7be9bf06ac01_TB6423_11.jpg)
E)none of these
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71
If the reaction 2HI H2 + I2 is second order,which of the following will yield a linear plot?
A)log [HI] vs time
B)1/[HI] vs time
C)[HI] vs time
D)ln [HI] vs time
E)None of these.
A)log [HI] vs time
B)1/[HI] vs time
C)[HI] vs time
D)ln [HI] vs time
E)None of these.
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72
The elementary chemical reaction O + ClO Cl + O2 is made pseudo-first order in oxygen atoms by using a large excess of ClO radicals.The rate constant for the reaction is 2.7 cm3/molecule.s.If the initial concentration of ClO is 1.0 1011 molecules/cm3,how long will it take for the oxygen atoms to decrease to 10.% of their initial concentration?
A)1.2 s
B)0.039 s
C)0.26 s
D)0.85 s
E)2.6 s
A)1.2 s
B)0.039 s
C)0.26 s
D)0.85 s
E)2.6 s
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73
Two isomers (A and B)of a given compound dimerize as follows:
Both processes are known to be second order in reactant,and k1 is known to be 0.25 L/mol·s at 25°C,where
In a particular experiment,A and B were placed in separate containers at 25°,where [A]0 = 1.0 10-2 M and [B]0 = 2.5 10-2 M.It was found that [A] = 3[B] after the reactions progressed for 3.0 minutes.
-Calculate the value of
where
A)2.2 L/mol·s
B)0.75 L/mol·s
C)1.9 L/mol·s
D)0.21 L/mol·s
E)none of these
![<strong>Two isomers (A and B)of a given compound dimerize as follows: Both processes are known to be second order in reactant,and k<sub>1 </sub>is known to be 0.25 L/mol·s at 25°C,where <sup> </sup> In a particular experiment,A and B were placed in separate containers at 25°,where [A]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>2</sup> M and [B]<sub>0</sub> = 2.5 \times 10<sup>-</sup><sup>2</sup> M.It was found that [A] = 3[B] after the reactions progressed for 3.0 minutes. -Calculate the value of where <sup> </sup> <sup> </sup> <sup> </sup></strong> A)2.2 L/mol·s B)0.75 L/mol·s C)1.9 L/mol·s D)0.21 L/mol·s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66fa_ef7e_93a6_ef2701f367bd_TB6423_11_TB6423_11.jpg)
Both processes are known to be second order in reactant,and k1 is known to be 0.25 L/mol·s at 25°C,where
![<strong>Two isomers (A and B)of a given compound dimerize as follows: Both processes are known to be second order in reactant,and k<sub>1 </sub>is known to be 0.25 L/mol·s at 25°C,where <sup> </sup> In a particular experiment,A and B were placed in separate containers at 25°,where [A]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>2</sup> M and [B]<sub>0</sub> = 2.5 \times 10<sup>-</sup><sup>2</sup> M.It was found that [A] = 3[B] after the reactions progressed for 3.0 minutes. -Calculate the value of where <sup> </sup> <sup> </sup> <sup> </sup></strong> A)2.2 L/mol·s B)0.75 L/mol·s C)1.9 L/mol·s D)0.21 L/mol·s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66fa_ef7f_93a6_833870defd7a_TB6423_11_TB6423_11.jpg)
In a particular experiment,A and B were placed in separate containers at 25°,where [A]0 = 1.0 10-2 M and [B]0 = 2.5 10-2 M.It was found that [A] = 3[B] after the reactions progressed for 3.0 minutes.
-Calculate the value of
![<strong>Two isomers (A and B)of a given compound dimerize as follows: Both processes are known to be second order in reactant,and k<sub>1 </sub>is known to be 0.25 L/mol·s at 25°C,where <sup> </sup> In a particular experiment,A and B were placed in separate containers at 25°,where [A]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>2</sup> M and [B]<sub>0</sub> = 2.5 \times 10<sup>-</sup><sup>2</sup> M.It was found that [A] = 3[B] after the reactions progressed for 3.0 minutes. -Calculate the value of where <sup> </sup> <sup> </sup> <sup> </sup></strong> A)2.2 L/mol·s B)0.75 L/mol·s C)1.9 L/mol·s D)0.21 L/mol·s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66fb_1690_93a6_c38983a9d3ff_TB6423_11.jpg)
![<strong>Two isomers (A and B)of a given compound dimerize as follows: Both processes are known to be second order in reactant,and k<sub>1 </sub>is known to be 0.25 L/mol·s at 25°C,where <sup> </sup> In a particular experiment,A and B were placed in separate containers at 25°,where [A]<sub>0</sub> = 1.0 \times 10<sup>-</sup><sup>2</sup> M and [B]<sub>0</sub> = 2.5 \times 10<sup>-</sup><sup>2</sup> M.It was found that [A] = 3[B] after the reactions progressed for 3.0 minutes. -Calculate the value of where <sup> </sup> <sup> </sup> <sup> </sup></strong> A)2.2 L/mol·s B)0.75 L/mol·s C)1.9 L/mol·s D)0.21 L/mol·s E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66fb_1691_93a6_4b1dac189960_TB6423_11.jpg)
A)2.2 L/mol·s
B)0.75 L/mol·s
C)1.9 L/mol·s
D)0.21 L/mol·s
E)none of these
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74
Consider the reaction 2O3(g) 3O2(g).The following mechanism is proposed: O3
O2 + O
O3 + O 2O2
If we assume the second step of the mechanism is the rate determining step and the first step is a fast equilibrium step,which of the following rate laws is predicted by this mechanism?
A)rate = k[O3]
B)rate = k[O3]2[O2]
C)rate = k[O3]2[O2]-1
D)rate = k[O3]2
E)none of these
![<strong>Consider the reaction 2O<sub>3</sub>(g) \to 3O<sub>2</sub>(g).The following mechanism is proposed: O<sub>3</sub> O<sub>2</sub> + O O<sub>3</sub> + O \to 2O<sub>2</sub> If we assume the second step of the mechanism is the rate determining step and the first step is a fast equilibrium step,which of the following rate laws is predicted by this mechanism?</strong> A)rate = k[O<sub>3</sub>] B)rate = k[O<sub>3</sub>]<sup>2</sup>[O<sub>2</sub>] C)rate = k[O<sub>3</sub>]<sup>2</sup>[O<sub>2</sub>]<sup>-</sup><sup>1</sup> D)rate = k[O<sub>3</sub>]<sup>2</sup> E)none of these](https://storage.examlex.com/TB6423/11eaa8f0_66fc_2813_93a6_4df398e411e2_TB6423_11.jpg)
O3 + O 2O2
If we assume the second step of the mechanism is the rate determining step and the first step is a fast equilibrium step,which of the following rate laws is predicted by this mechanism?
A)rate = k[O3]
B)rate = k[O3]2[O2]
C)rate = k[O3]2[O2]-1
D)rate = k[O3]2
E)none of these
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75
The decomposition of ozone may occur through the two-step mechanism shown:
The oxygen atom is considered to be a(n)
A)reactant
B)product
C)catalyst
D)reaction intermediate
E)activated complex

A)reactant
B)product
C)catalyst
D)reaction intermediate
E)activated complex
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76
The reaction
obeys the rate law:
at 500.K. If the initial concentration of NO2 is 1.00 M,how long will it take for the [NO2] to decrease to 35.8% of its initial value?
A)45.9 s
B)73 s
C)128 s
D)
s
E)cannot be determined from this data
![<strong>The reaction obeys the rate law: at 500.K. If the initial concentration of NO<sub>2</sub> is 1.00 M,how long will it take for the [NO<sub>2</sub>] to decrease to 35.8% of its initial value?</strong> A)45.9 s B)73 s C)128 s D) s E)cannot be determined from this data](https://storage.examlex.com/TB6423/11eaa8f0_66fb_8bcc_93a6_5f30d36235d9_TB6423_11.jpg)
![<strong>The reaction obeys the rate law: at 500.K. If the initial concentration of NO<sub>2</sub> is 1.00 M,how long will it take for the [NO<sub>2</sub>] to decrease to 35.8% of its initial value?</strong> A)45.9 s B)73 s C)128 s D) s E)cannot be determined from this data](https://storage.examlex.com/TB6423/11eaa8f0_66fb_8bcd_93a6_755131e7040c_TB6423_11.jpg)
A)45.9 s
B)73 s
C)128 s
D)
![<strong>The reaction obeys the rate law: at 500.K. If the initial concentration of NO<sub>2</sub> is 1.00 M,how long will it take for the [NO<sub>2</sub>] to decrease to 35.8% of its initial value?</strong> A)45.9 s B)73 s C)128 s D) s E)cannot be determined from this data](https://storage.examlex.com/TB6423/11eaa8f0_66fb_8bce_93a6_e5a3da7a77ef_TB6423_11.jpg)
E)cannot be determined from this data
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77
The decomposition of N2O5(g)to NO2(g)and O2(g)obeys first-order kinetics.Assuming the form of the rate law is:
Where k = 5.4 10-5 s-1 at 25°C,what is the half-life for the reaction described?
A)
s
B)
s
C)
s
D)
s
E)none of these

Where k = 5.4 10-5 s-1 at 25°C,what is the half-life for the reaction described?
A)

B)

C)

D)

E)none of these
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78
In 6 M HCl,the complex ion Ru(NH3)63+ decomposes to a variety of products.The reaction is first order in Ru(NH3)63+ and has a half-life of 14 hours at 25°C.Under these conditions,how long will it take for the [Ru(NH3)63+] to decrease to 23.5% of its initial value?
A)5.4 hours
B)9.7 hours
C)3.3 hours
D)14 hours
E)29 hours
A)5.4 hours
B)9.7 hours
C)3.3 hours
D)14 hours
E)29 hours
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79
The reaction 3NO N2O + NO2 is found to obey the rate law,Rate = k[NO]2.If the first half-life of the reaction is found to be 2.0 s,what is the length of the fourth half-life?
A)2.0 s
B)4.0 s
C)8.0 s
D)12.0 s
E)16.0 s
A)2.0 s
B)4.0 s
C)8.0 s
D)12.0 s
E)16.0 s
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80
Consider a reaction of the type aA Products in which the rate law is found to be rate = k[A]3 (yes,a termolecular reaction is improbable but possible).If the first half-life of the reaction is found to be 40 seconds,what is the time for the second half-life?
A)10 seconds
B)20 seconds
C)80 seconds
D)160 seconds
E)320 seconds
A)10 seconds
B)20 seconds
C)80 seconds
D)160 seconds
E)320 seconds
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