Deck 10: One-Sample Tests of Hypothesis
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Deck 10: One-Sample Tests of Hypothesis
1
A test statistic is a value computed from sample information that is used to test the null hypothesis.
True
2
A manufacturer wants to increase the shelf life of a line of cake mixes. Past records indicate that the average shelf life of the mix is 216 days. After a revised mix has been developed, a sample of nine boxes of cake mix gave these shelf lives (in days): 215, 217, 218, 219, 216, 217, 217, 218, and 218. Using α = 0.025, has the shelf life of the cake mix increased?
A)Yes, because computed t is greater than the critical value.
B)Yes, because computed t is less than the critical value.
C)No, because computed t lies in the region of acceptance.
D)No, because 217.24 is quite close to 216.
A)Yes, because computed t is greater than the critical value.
B)Yes, because computed t is less than the critical value.
C)No, because computed t lies in the region of acceptance.
D)No, because 217.24 is quite close to 216.
Yes, because computed t is greater than the critical value.
3
A p-value is the same as a stated significance level.
False
4
An example of a hypothesis is: A person is innocent until proven guilty.
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5
A consumer products company wants to increase the absorption capacity of a sponge. Based on past data, the average sponge could absorb 3.5 ounces. After the redesign, the absorption amounts of a sample of sponges were (in ounces): 4.1, 3.7, 3.3, 3.5, 3.8, 3.9, 3.6, 3.8, 4.0, and 3.9. At the 0.01 level of significance, what is the decision rule to test if the new design increased the absorption of the sponge?
A)Reject null hypothesis if computed t is less than 2.580.
B)Reject null hypothesis if computed t is greater than 2.821.
C)Reject null hypothesis if computed z is 1.96 or larger.
D)Reject null hypothesis if computed t is less than 2.764.
A)Reject null hypothesis if computed t is less than 2.580.
B)Reject null hypothesis if computed t is greater than 2.821.
C)Reject null hypothesis if computed z is 1.96 or larger.
D)Reject null hypothesis if computed t is less than 2.764.
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6
The researcher must decide on the level of significance before formulating a decision rule and collecting sample data.
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7
Define the level of significance.
A)It is the probability of a Type II error.
B)It is the probability of a Type I error.
C)It is a z value of 1.96.
D)It is the beta error.
A)It is the probability of a Type II error.
B)It is the probability of a Type I error.
C)It is a z value of 1.96.
D)It is the beta error.
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8
For a one-tailed test with a 0.05 level of significance, the critical z statistic is 1.645, but the critical t statistic is 1.96.
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9
If the null hypothesis is µµ ≥ 200, then a two-tail test is being conducted.
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10
A null hypothesis makes a claim about a __________.
A)Population parameter
B)Sample statistic
C)Sample mean
D)Type II error
A)Population parameter
B)Sample statistic
C)Sample mean
D)Type II error
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11
An alternate hypothesis is a statement about a population parameter that is accepted when the null hypothesis is rejected.
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12
The mean length of a candy bar is 43 millimeters. There is concern that the settings of the machine cutting the bars have changed. Test the claim at the 0.02 level that there has been no change in the mean length. The alternate hypothesis is that there has been a change. Twelve bars (n = 12) were selected at random and their lengths recorded. The lengths are (in millimeters) 42, 39, 42, 45, 43, 40, 39, 41, 40, 42, 43, and 42. The mean of the sample is 41.5 and the standard deviation is 1.784. Computed t = -2.913. Has there been a statistically significant change in the mean length of the bars?
A)Yes, because the computed t lies in the rejection region.
B)No, because the information given is not complete.
C)No, because the computed t lies in the area to the right of -2.718.
D)Yes, because 43 is greater than 41.5.
A)Yes, because the computed t lies in the rejection region.
B)No, because the information given is not complete.
C)No, because the computed t lies in the area to the right of -2.718.
D)Yes, because 43 is greater than 41.5.
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13
The Greek letter used to represent the probability of a Type I error is alpha (α).
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14
Hypothesis testing is a procedure that uses sample evidence and probability theory to decide whether to reject or fail to reject a hypothesis.
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15
A p-value is a probability.
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16
If the null hypothesis is false and the researchers do not reject it, a Type I error has been made.
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17
A Type II error is the probability of rejecting the null hypothesis when it is actually true.
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18
To test the hypothesis that 55% of those families who plan to purchase a vacation residence in Florida want a condominium, the null hypothesis is π = 0.55 and the alternate is π ≠ .55. A random sample of 400 families who planned to buy a vacation residence revealed that 228 families want a condominium. What decision should be made regarding the null hypothesis using the 0.01 level of significance?
A)Do not reject it.
B)Reject it.
C)Cannot accept it or reject it based on the information given.
D)Purchase a condominium.
A)Do not reject it.
B)Reject it.
C)Cannot accept it or reject it based on the information given.
D)Purchase a condominium.
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19
The level of significance is the probability of rejecting the null hypothesis when it is actually true.
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20
Assuming that the null hypothesis is true, a p-value is the probability of observing a sample value greater than and/or less than an observed sample observation.
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21
The number of trials and the population proportion are respectively represented by what symbols?
A)p and n
B)α and β
C)z and t
D)n and π
A)p and n
B)α and β
C)z and t
D)n and π
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22
What are the critical values for a two-tailed test with a 0.01 level of significance when n is large and the population standard deviation is known?
A)Above 1.960 and below -1.960
B)Above 1.645 and below -1.645
C)Above 2.576 and below -2.576
D)Above 1.000 and below -1.000
A)Above 1.960 and below -1.960
B)Above 1.645 and below -1.645
C)Above 2.576 and below -2.576
D)Above 1.000 and below -1.000
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23
A machine is set to fill the small-size packages of M&M candies with 56 candies per bag. A sample revealed: three bags of 56, two bags of 57, one bag of 55, and two bags of 58. To test the hypothesis that the mean candies per bag is 56, how many degrees of freedom are there?
A)9
B)1
C)8
D)7
A)9
B)1
C)8
D)7
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24
What is another name for the alternate hypothesis?
A)Null hypothesis
B)Hypothesis of no difference
C)Rejected hypothesis
D)Research hypothesis
A)Null hypothesis
B)Hypothesis of no difference
C)Rejected hypothesis
D)Research hypothesis
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25
For a one-tailed hypothesis test, the critical z value of the test statistic is -2.33. Which of the following is true about the hypothesis test?
A)α = 0.05 for a lower-tailed test
B)α = 0.01 for a lower-tailed test
C)α = 0.05 for an upper-tailed test
D)α = 0.01 for an upper-tailed test
A)α = 0.05 for a lower-tailed test
B)α = 0.01 for a lower-tailed test
C)α = 0.05 for an upper-tailed test
D)α = 0.01 for an upper-tailed test
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26
Which symbol represents a test statistic used to test a hypothesis about a population mean?
A)α
B)β
C)μ
D)z
A)α
B)β
C)μ
D)z
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27
What statement do we make that determines if the null hypothesis is rejected?
A)Decision rule
B)Test statistic
C)Alternate hypothesis
D)Critical value
A)Decision rule
B)Test statistic
C)Alternate hypothesis
D)Critical value
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28
For a two-tailed test with a 0.05 significance level, where is the rejection region when n is large and the population standard deviation is known?
A)Between ±1.960
B)Between ±1.645
C)Greater than +1.960 and less than -1.960
D)Greater than +1.645 and less than -1.645
A)Between ±1.960
B)Between ±1.645
C)Greater than +1.960 and less than -1.960
D)Greater than +1.645 and less than -1.645
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29
What is a Type II error?
A)Failing to reject a false null hypothesis
B)Rejecting a false null hypothesis
C)Accepting a false alternate hypothesis
D)Rejecting a false alternate hypothesis
A)Failing to reject a false null hypothesis
B)Rejecting a false null hypothesis
C)Accepting a false alternate hypothesis
D)Rejecting a false alternate hypothesis
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30
If we reject the null hypothesis, what can we conclude subject to the probability, α?
A)Reject the null with a probability, α, of making a Type I error.
B)The alternative hypothesis is false.
C)The null hypothesis is true.
D)Both the null hypothesis and the alternative hypothesis are true.
A)Reject the null with a probability, α, of making a Type I error.
B)The alternative hypothesis is false.
C)The null hypothesis is true.
D)Both the null hypothesis and the alternative hypothesis are true.
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31
If the alternate hypothesis states that µ ≠ 4,000, where is the rejection region for the hypothesis test?
A)In both tails
B)In the lower or left tail
C)In the upper or right tail
D)In the center
A)In both tails
B)In the lower or left tail
C)In the upper or right tail
D)In the center
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32
What is the probability of making a Type II error if the null hypothesis is actually true?
A)α
B)1
C)0
D)0.05
A)α
B)1
C)0
D)0.05
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33
For an alternative hypothesis: µ > 6,700, where is the rejection region for the hypothesis test located?
A)In both tails
B)In the left or lower tail
C)In the right or upper tail
D)In the center
A)In both tails
B)In the left or lower tail
C)In the right or upper tail
D)In the center
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34
For a null hypothesis, H0: µ = 4,000, if the 1% level of significance is used and the z-test statistic is +6.00, what is our decision regarding the null hypothesis?
A)Do not reject H0.
B)Reject H0.
C)Reject H1.
D)None Apply.
A)Do not reject H0.
B)Reject H0.
C)Reject H1.
D)None Apply.
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35
If the critical z value for a hypothesis test equals 2.45, what value of the test statistic would provide the least chance of making a Type I error?
A)3.74
B)10,000
C)2.46
D)4.56
A)3.74
B)10,000
C)2.46
D)4.56
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36
Using a 5% level of significance and a sample size of 25, what is the critical t value for a null hypothesis, H0: µµ ≤ 100?
A)1.708
B)1.711
C)2.060
D)2.064
A)1.708
B)1.711
C)2.060
D)2.064
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37
A random sample of size 15 is selected from a normal population. The population standard deviation is unknown. Assume the null hypothesis indicates a two-tailed test and the researcher decided to use the 0.10 significance level. For what values of t will the null hypothesis not be rejected?
A)To the left of -1.282 or to the right of 1.282
B)To the left of -1.345 or to the right of 1.345
C)Between -1.761 and 1.761
D)To the left of -1.645 or to the right of 1.645
A)To the left of -1.282 or to the right of 1.282
B)To the left of -1.345 or to the right of 1.345
C)Between -1.761 and 1.761
D)To the left of -1.645 or to the right of 1.645
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38
To conduct a test of hypothesis with a small sample, we make an assumption that __________.
A)A larger computed value of t will be needed to reject the null hypothesis
B)The region of acceptance will be wider than for large samples
C)The confidence interval will be wider than for large samples
D)The population is normally distributed
A)A larger computed value of t will be needed to reject the null hypothesis
B)The region of acceptance will be wider than for large samples
C)The confidence interval will be wider than for large samples
D)The population is normally distributed
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39
What are the critical z-values for a two-tailed hypothesis test if α = 0.01?
A)±1.960
B)±2.326
C)±2.576
D)±1.645
A)±1.960
B)±2.326
C)±2.576
D)±1.645
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40
Which of the following is NOT one of the five steps in the hypothesis testing procedure?
A)Formulate a decision rule
B)State the null and alternate hypotheses
C)Select a level for β
D)Identify the test statistic
A)Formulate a decision rule
B)State the null and alternate hypotheses
C)Select a level for β
D)Identify the test statistic
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41
The average cost of tuition and room and board at a small private liberal arts college is reported to be $8,500 per term, but a financial administrator believes that the average cost is higher. A study conducted using 350 small liberal arts colleges showed that the average cost per term is $8,745. The population standard deviation is $1,200. Let α = 0.05. What are the null and alternative hypotheses for this study?
A)H0: µ ≤ $9,000; H1: µ > $9,000
B)H0: µ ≥ $9,000; H1: µ < $9,000
C)H0: µ ≤ $8,500; H1: µ > $8,500
D)H0: µ ≥ $8,500; H1: µ < $8,500
A)H0: µ ≤ $9,000; H1: µ > $9,000
B)H0: µ ≥ $9,000; H1: µ < $9,000
C)H0: µ ≤ $8,500; H1: µ > $8,500
D)H0: µ ≥ $8,500; H1: µ < $8,500
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42
The average cost of tuition and room and board at a small private liberal arts college is reported to be $8,500 per term, but a financial administrator believes that the average cost is higher. A study conducted using 350 small liberal arts colleges showed that the average cost per term is $8,745. The population standard deviation is $1,200. Let α = 0.05. What is the test statistic for this test?
A)±3.82
B)+0.204
C)-3.82
D)+3.82
A)±3.82
B)+0.204
C)-3.82
D)+3.82
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43
Based on the Nielsen ratings, the local CBS affiliate claims its 11 p.m. newscast reaches 41% of the viewing audience in the area. In a survey of 100 viewers, 36% indicated that they watch the late evening news on this local CBS station. What is your decision if α = 0.01?
A)Fail to reject the null hypothesis.
B)Reject the null hypothesis and conclude the newscast does not reach 41% of the audience.
C)Fail to reject the alternate and conclude the newscast does not reach 41% of the audience.
D)Reject the alternate and conclude the newscast reaches about 41% of the audience.
A)Fail to reject the null hypothesis.
B)Reject the null hypothesis and conclude the newscast does not reach 41% of the audience.
C)Fail to reject the alternate and conclude the newscast does not reach 41% of the audience.
D)Reject the alternate and conclude the newscast reaches about 41% of the audience.
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44
The average cost of tuition and room and board at a small private liberal arts college is reported to be $8,500 per term, but a financial administrator believes that the average cost is higher. A study conducted using 350 small liberal arts colleges showed that the average cost per term is $8,745. The population standard deviation is $1,200. Let α = 0.05. What is the critical z value for this test?
A)+1.960
B)-1.960
C)+1.645
D)-1.645
A)+1.960
B)-1.960
C)+1.645
D)-1.645
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45
Based on the Nielsen ratings, the local CBS affiliate claims its 11 p.m. newscast reaches 41% of the viewing audience in the area. In a survey of 100 viewers, 36% indicated that they watch the late evening news on this local CBS station. What is the sample proportion?
A)0.41
B)0.36%
C)0.41%
D)0.36
A)0.41
B)0.36%
C)0.41%
D)0.36
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46
If 20 out of 50 students sampled live in a college dormitory, what is the estimated proportion of students at the University living in a dormitory?
A)0.20
B)0.40
C)0.50
D)0.60
A)0.20
B)0.40
C)0.50
D)0.60
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47
The sample proportion is defined as _________.
A)nπ
B)x/n
C)n!
D)π
A)nπ
B)x/n
C)n!
D)π
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48
Based on the Nielsen ratings, the local CBS affiliate claims its 11 p.m. newscast reaches 41% of the viewing audience in the area. In a survey of 100 viewers, 36% indicated that they watch the late evening news on this local CBS station. What is the z test statistic?
A)1.02
B)1.22
C)-1.02
D)-1.22
A)1.02
B)1.22
C)-1.02
D)-1.22
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49
The average cost of tuition and room and board at small private liberal arts colleges is reported to be $8,500 per term, but a financial administrator believes that the average cost is higher. A study conducted using 350 small liberal arts colleges showed that the average cost per term is $8,745. The population standard deviation is $1,200. Let α = 0.05. What is the p-value for this test?
A)0.0000
B)0.0124
C)0.0500
D)0.4938
A)0.0000
B)0.0124
C)0.0500
D)0.4938
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50
Based on the Nielsen ratings, the local CBS affiliate claims its 11 p.m. newscast reaches 41% of the viewing audience in the area. In a survey of 100 viewers, 36% indicated that they watch the late evening news on this local CBS station. What is the null hypothesis?
A)H0: π = 0.36
B)H0: π = 0.41
C)H0: π ≠ 0.36
D)H0: µ = 0.41
A)H0: π = 0.36
B)H0: π = 0.41
C)H0: π ≠ 0.36
D)H0: µ = 0.41
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51
It is claimed that in a bushel of peaches, less than 10% are defective. A sample of 400 peaches is examined and 50 are found to be defective. What is the alternate hypothesis for a one-sided test?
A)H1: π ≥ 0.10
B)H1: π > 0.10
C)H1: π ≤ 0.10
D)H1: π < 0.10
A)H1: π ≥ 0.10
B)H1: π > 0.10
C)H1: π ≤ 0.10
D)H1: π < 0.10
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52
An electronics retailer believes that, at most, 40% of their cell phone inventory was sold during November. The retailer surveyed 80 dealers and found that 38% of the inventory was sold. Since 38% is less than 40%, is this difference of 2 percentage points sampling error or a significant difference? Test at the 0.05 level. The computed z = -0.37.
A)The 2% is a significant difference.
B)We cannot determine if the 2% is a significant difference.
C)There is not enough information to reach a conclusion.
D)None Apply.
A)The 2% is a significant difference.
B)We cannot determine if the 2% is a significant difference.
C)There is not enough information to reach a conclusion.
D)None Apply.
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53
Based on the Nielsen ratings, the local CBS affiliate claims its 11 p.m. newscast reaches 41% of the viewing audience in the area. In a survey of 100 viewers, 36% indicated that they watch the late evening news on this local CBS station. What is the p-value?
A)0.3461
B)0.1539
C)0.3078
D)0.0100
A)0.3461
B)0.1539
C)0.3078
D)0.0100
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54
Based on the Nielsen ratings, the local CBS affiliate claims its 11 p.m. newscast reaches 41% of the viewing audience in the area. In a survey of 100 viewers, 36% indicated that they watch the late evening news on this local CBS station. What is the critical value if the level of significance is 0.10?
A)-1.282
B)±1.645
C)-2.576
D)+2.576
A)-1.282
B)±1.645
C)-2.576
D)+2.576
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55
It is claimed that in a bushel of peaches, less than 10% are defective. A sample of 400 peaches is examined and 50 are found to be defective. What is the null hypothesis?
A)H0: π ≠ 0.10
B)H0: π ≥ 0.10
C)H0: π ≤ 0.10
D)H0: π < 0.10
A)H0: π ≠ 0.10
B)H0: π ≥ 0.10
C)H0: π ≤ 0.10
D)H0: π < 0.10
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56
The claim that "40% of those persons who retired from an industrial job before the age of 60 would return to work if a suitable job was available" is to be investigated at the 0.02 significance level. If 74 out of the 200 workers sampled said they would return to work, what is our decision?
A)Do not reject the null hypothesis because -0.879 lies in the region between +2.326 and -2.326.
B)Do not reject the null hypothesis because -0.879 lies in the region between +2.5760 and -2.576.
C)Reject the null hypothesis because 37% is less than 40%.
D)Do not reject the null hypothesis because 37% lies in the area between 0% and 40%.
A)Do not reject the null hypothesis because -0.879 lies in the region between +2.326 and -2.326.
B)Do not reject the null hypothesis because -0.879 lies in the region between +2.5760 and -2.576.
C)Reject the null hypothesis because 37% is less than 40%.
D)Do not reject the null hypothesis because 37% lies in the area between 0% and 40%.
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57
In hypothesis testing, what is the level of significance?
A)The risk of rejecting the null hypothesis when it is true.
B)A value symbolized by the Greek letter α.
C)A value between 0 and 1.
D)It is selected before a decision rule can be formulated.
E)All apply.
A)The risk of rejecting the null hypothesis when it is true.
B)A value symbolized by the Greek letter α.
C)A value between 0 and 1.
D)It is selected before a decision rule can be formulated.
E)All apply.
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58
Based on the Nielsen ratings, the local CBS affiliate claims its 11 p.m. newscast reaches 41% of the viewing audience in the area. In a survey of 100 viewers, 36% indicated that they watch the late evening news on this local CBS station. What is the alternate hypothesis?
A)H1: π = 0.36
B)H1: π = 0.41
C)H1: π ≠ 0.41
D)H1: µ ≠ 0.41
A)H1: π = 0.36
B)H1: π = 0.41
C)H1: π ≠ 0.41
D)H1: µ ≠ 0.41
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59
Based on the Nielsen ratings, the local CBS affiliate claims its 11 p.m. newscast reaches 41% of the viewing audience in the area. In a survey of 100 viewers, 36% indicated that they watch the late evening news on this local CBS station. What is the critical value if α = 0.01?
A)+2.576
B)+2.326
C)±2.576
D)-2.326
A)+2.576
B)+2.326
C)±2.576
D)-2.326
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60
The average cost of tuition and room and board at small private liberal arts colleges is reported to be $8,500 per term, but a financial administrator believes that the average cost is higher. A study conducted using 350 small liberal arts colleges showed that the average cost per term is $8,745. The population standard deviation is $1,200. Let α = 0.05. Based on the computed test statistic or p-value, what is our decision about the average cost?
A)Equal to $8,500
B)Greater than $8,500
C)Less than $8,500
D)Not equal to $8,500
A)Equal to $8,500
B)Greater than $8,500
C)Less than $8,500
D)Not equal to $8,500
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61
A hypothesis regarding the weight of newborn infants at a community hospital is that the mean is 6.6 pounds. A sample of seven infants is randomly selected and their weights at birth are recorded as 9.0, 7.3, 6.0, 8.8, 6.8, 8.4, and 6.6 pounds. What is the sample variance?
A)1.177
B)6.6
C)1.385
D)7.6
A)1.177
B)6.6
C)1.385
D)7.6
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62
It is claimed that in a bushel of peaches, less than 10% are defective. A sample of 400 peaches is examined and 50 are found to be defective. What is the sample proportion?
A)0.10
B)0.125
C)40
D)0.40
A)0.10
B)0.125
C)40
D)0.40
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63
A hypothesis regarding the weight of newborn infants at a community hospital is that the mean is 6.6 pounds. A sample of seven infants is randomly selected and their weights at birth are recorded as 9.0, 7.3, 6.0, 8.8, 6.8, 8.4, and 6.6 pounds. What is the sample standard deviation?
A)1.177
B)1.188
C)1.386
D)1.090
A)1.177
B)1.188
C)1.386
D)1.090
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64
The mean annual income of certified welders is normally distributed with a mean of $50,000 and a population standard deviation of $2,000. The ship building association wishes to find out whether their welders earn more or less than $50,000 annually. The alternate hypothesis is that the mean is not $50,000. If the level of significance is 0.10, what is the decision rule?
A)Do not reject the null hypothesis if computed z lies between -1.645 and +1.645; otherwise, reject it.
B)Do not reject the null hypothesis if computed z is greater than 1.645; otherwise, reject it.
C)Do not reject the null hypothesis if computed z lies between -1.960 and +1.960; otherwise, reject it.
D)Reject the null hypothesis if computed z is below -1.960; otherwise, reject it.
A)Do not reject the null hypothesis if computed z lies between -1.645 and +1.645; otherwise, reject it.
B)Do not reject the null hypothesis if computed z is greater than 1.645; otherwise, reject it.
C)Do not reject the null hypothesis if computed z lies between -1.960 and +1.960; otherwise, reject it.
D)Reject the null hypothesis if computed z is below -1.960; otherwise, reject it.
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65
A hypothesis regarding the weight of newborn infants at a community hospital is that the mean is 6.6 pounds. A sample of seven infants is randomly selected and their weights at birth are recorded as 9.0, 7.3, 6.0, 8.8, 6.8, 8.4, and 6.6 pounds. What are the degrees of freedom?
A)7
B)8
C)6
D)6.6
A)7
B)8
C)6
D)6.6
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66
The critical t statistic for an alternative hypothesis, H1: µ > 30, a 1% level of significance, and a sample size of 8 is __________.
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67
A hypothesis regarding the weight of newborn infants at a community hospital is that the mean is 6.6 pounds. A sample of seven infants is randomly selected and their weights at birth are recorded as 9.0, 7.3, 6.0, 8.8, 6.8, 8.4, and 6.6 pounds. What is the alternate hypothesis?
A)H1: µ = 6.6
B)H1: µ ≠ 6.6
C)H1: µ ≥ 6.6
D)H1: µ > 7.6
A)H1: µ = 6.6
B)H1: µ ≠ 6.6
C)H1: µ ≥ 6.6
D)H1: µ > 7.6
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68
It is claimed that in a bushel of peaches, less than 10% are defective. A sample of 400 peaches is examined and 50 are found to be defective. What is the critical value for α = 0.025?
A)+1.960
B)±1.645
C)-1.960
D)-1.645
A)+1.960
B)±1.645
C)-1.960
D)-1.645
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69
The critical t statistic for the alternative hypothesis, H1: µ < 12, a 0.005 level of significance, and a sample size of 20 is ______.
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70
The mean annual incomes of certified welders are normally distributed with the mean of $50,000 and a standard deviation of $2,000. The ship building association wishes to find out whether their welders earn more or less than $50,000 annually. The alternate hypothesis is that the mean is not $50,000. Which of the following is the alternate hypothesis?
A)H1: π ≠ $50,000
B)H1: µ ≠ $50,000
C)H1: µ < $50,000
D)H1: µ = $50,000
A)H1: π ≠ $50,000
B)H1: µ ≠ $50,000
C)H1: µ < $50,000
D)H1: µ = $50,000
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71
A hypothesis regarding the weight of newborn infants at a community hospital is that the mean is 6.6 pounds. A sample of seven infants is randomly selected and their weights at birth are recorded as 9.0, 7.3, 6.0, 8.8, 6.8, 8.4, and 6.6 pounds. What is the decision for a statistical significant change in average weights at birth at the 5% level of significance?
A)Fail to reject the null hypothesis.
B)Reject the null hypothesis and conclude the mean is higher than 6.6 lb.
C)Reject the null hypothesis and conclude the mean is lower than 6.6 lb.
D)Cannot calculate because the population standard deviation is unknown.
A)Fail to reject the null hypothesis.
B)Reject the null hypothesis and conclude the mean is higher than 6.6 lb.
C)Reject the null hypothesis and conclude the mean is lower than 6.6 lb.
D)Cannot calculate because the population standard deviation is unknown.
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72
A hypothesis regarding the weight of newborn infants at a community hospital is that the mean is 6.6 pounds. A sample of seven infants is randomly selected and their weights at birth are recorded as 9.0, 7.3, 6.0, 8.8, 6.8, 8.4, and 6.6 pounds. The null hypothesis is ______.
A)H0: µ = 6.6
B)H0: µ ≥ 6.6
C)H0: µ > 7.6
D)H0: µ ≤ 7.6
A)H0: µ = 6.6
B)H0: µ ≥ 6.6
C)H0: µ > 7.6
D)H0: µ ≤ 7.6
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73
It is claimed that in a bushel of peaches, less than 10% are defective. A sample of 400 peaches is examined and 50 are found to be defective. What is the p-value?
A)0.0250
B)0.4525
C)0.9525
D)0.0500
A)0.0250
B)0.4525
C)0.9525
D)0.0500
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74
The mean annual incomes of certified welders are normally distributed with the mean of $50,000 and a standard deviation of $2,000. The ship building association wishes to find out whether their welders earn more or less than $50,000 annually. The alternate hypothesis is that the mean is not $50,000. If the level of significance is 0.10, what is the critical value?
A)+1.645
B)-1.282
C)±1.282
D)±1.645
A)+1.645
B)-1.282
C)±1.282
D)±1.645
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75
A hypothesis regarding the weight of newborn infants at a community hospital is that the mean is 6.6 pounds. A sample of seven infants is randomly selected and their weights at birth are recorded as 9.0, 7.3, 6.0, 8.8, 6.8, 8.4, and 6.6 pounds. If α = 0.05, what is the critical t value?
A)-2.365
B)±1.96
C)±2.365
D)±2.447
A)-2.365
B)±1.96
C)±2.365
D)±2.447
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76
As the sample size increases, the curve of the t-distribution approaches the _____________________________.
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77
A hypothesis regarding the weight of newborn infants at a community hospital is that the mean is 6.6 pounds. A sample of seven infants is randomly selected and their weights at birth are recorded as 9.0, 7.3, 6.0, 8.8, 6.8, 8.4, and 6.6 pounds. What is the sample mean?
A)6.6
B)7.6
C)1.177
D)2.447
A)6.6
B)7.6
C)1.177
D)2.447
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78
It is claimed that in a bushel of peaches, less than 10% are defective. A sample of 400 peaches is examined and 50 are found to be defective. If α = 0.025, what will be the decision?
A)Accept the null.
B)Reject the null and conclude the defects are not greater than 10%.
C)Reject the null and conclude the defects are greater than 10%.
D)Fail to reject the null.
A)Accept the null.
B)Reject the null and conclude the defects are not greater than 10%.
C)Reject the null and conclude the defects are greater than 10%.
D)Fail to reject the null.
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79
It is claimed that in a bushel of peaches, less than 10% are defective. A sample of 400 peaches is examined and 50 are found to be defective. What is the z-test statistic?
A)+0.125
B)+0.278
C)-1.645
D)+1.667
A)+0.125
B)+0.278
C)-1.645
D)+1.667
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80
The mean weight of newborn infants at a community hospital is 6.6 pounds. A sample of seven infants is randomly selected and their weights at birth are recorded as 9.0, 7.3, 6.0, 8.8, 6.8, 8.4, and 6.6 pounds. Does the sample data show a significant increase in the average birthrate at a 5% level of significance?
A)Fail to reject the null hypothesis and conclude the mean is 6.6 lb.
B)Reject the null hypothesis and conclude the mean is lower than 6.6 lb.
C)Reject the null hypothesis and conclude the mean is greater than 6.6 lb.
D)Cannot calculate because the population standard deviation is unknown.
A)Fail to reject the null hypothesis and conclude the mean is 6.6 lb.
B)Reject the null hypothesis and conclude the mean is lower than 6.6 lb.
C)Reject the null hypothesis and conclude the mean is greater than 6.6 lb.
D)Cannot calculate because the population standard deviation is unknown.
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