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book Business Mathematics Brief 12th Edition by Stanley Salzman ,Gary Clendenen, Charles Miller cover

Business Mathematics Brief 12th Edition by Stanley Salzman ,Gary Clendenen, Charles Miller

Edition 12ISBN: 978-0132605540
book Business Mathematics Brief 12th Edition by Stanley Salzman ,Gary Clendenen, Charles Miller cover

Business Mathematics Brief 12th Edition by Stanley Salzman ,Gary Clendenen, Charles Miller

Edition 12ISBN: 978-0132605540
Exercise 236
Solve for base in the following. Round to the nearest cent. (Hint: Original + Increase = New Value.) (See Examples.)
Using a Diagram to Understand an Increase Problem
The value of a home sold by Tom Dugally this year is $203,500, which is 10, more than last year's value. Find the value of the home last year.
SOLUTION
CASE IN POINT The phrase "10% more than last year's value," tells us that last year's value is the base and that it is the unknown. The figure below shows last year's value as 100% and this year's value which is:
(the base + 10% more than last year's value) = 110% of the base
Solve for base in the following. Round to the nearest cent. (Hint: Original + Increase = New Value.) (See Examples.)  Using a Diagram to Understand an Increase Problem  The value of a home sold by Tom Dugally this year is $203,500, which is 10, more than last year's value. Find the value of the home last year. SOLUTION  CASE IN POINT The phrase 10% more than last year's value, tells us that last year's value is the base and that it is the unknown. The figure below shows last year's value as 100% and this year's value which is: (the base + 10% more than last year's value) = 110% of the base     The diagram shows that the 10, increase is based on last year's value which is not known. It is not based on this year's value of $203,500. This year's value is last year's value plus 10, of last year's value. Use the basic percent formula to solve for base in increase problems.     Substituting in the percent formula with part = $203,500 and rate = 110, results in the following.     Quick TIP  The common error in solving an increase problem is thinking that the base is given and that the solution can be found by solving for part. Solving for B results in the following equation, which is solved for B.     So the value of the house last year was $185,000. Now check the answer.     $203,500 is 110, of $185,000. Finding Base after Two Increases      Due to increased demand for a patented process that will help analyze the DNA of mice, Biotics Genome has increased production of testing kits by 20, per year for each of the two past years. This year's production is 93,600 kits. Find the number of kits produced two years ago. SOLUTION  The two 20, increases cannot be added together since the two increases act on different bases. Solve this problem in two steps, one for each of the 20, increases. First, use a diagram to find last year's production of DNA kits.     Last year's production plus 20% of last year's production equals this year's production. So, part ( P ) = 93,600 and rate ( R ) = 120%     The number of DNA testing kits produced last year was 78,000. Use this number and knowledge that the sales volume increased 20, from 2 years ago to last year to find production 2 years ago. Quick TIP  It is important to realize that the two 20, increases cannot be added together to equal one increase of 40,. Each 20, increase is calculated on a different base.     Production two years ago added to 20, of that production equals last year's production. So, part ( P ) = 78,000 and rate ( R ) = 120% once again.     The calculator solution to this example is done by dividing in a series.     Check the answer.
The diagram shows that the 10, increase is based on last year's value which is not known. It is not based on this year's value of $203,500. This year's value is last year's value plus 10, of last year's value.
Use the basic percent formula to solve for base in increase problems.
Solve for base in the following. Round to the nearest cent. (Hint: Original + Increase = New Value.) (See Examples.)  Using a Diagram to Understand an Increase Problem  The value of a home sold by Tom Dugally this year is $203,500, which is 10, more than last year's value. Find the value of the home last year. SOLUTION  CASE IN POINT The phrase 10% more than last year's value, tells us that last year's value is the base and that it is the unknown. The figure below shows last year's value as 100% and this year's value which is: (the base + 10% more than last year's value) = 110% of the base     The diagram shows that the 10, increase is based on last year's value which is not known. It is not based on this year's value of $203,500. This year's value is last year's value plus 10, of last year's value. Use the basic percent formula to solve for base in increase problems.     Substituting in the percent formula with part = $203,500 and rate = 110, results in the following.     Quick TIP  The common error in solving an increase problem is thinking that the base is given and that the solution can be found by solving for part. Solving for B results in the following equation, which is solved for B.     So the value of the house last year was $185,000. Now check the answer.     $203,500 is 110, of $185,000. Finding Base after Two Increases      Due to increased demand for a patented process that will help analyze the DNA of mice, Biotics Genome has increased production of testing kits by 20, per year for each of the two past years. This year's production is 93,600 kits. Find the number of kits produced two years ago. SOLUTION  The two 20, increases cannot be added together since the two increases act on different bases. Solve this problem in two steps, one for each of the 20, increases. First, use a diagram to find last year's production of DNA kits.     Last year's production plus 20% of last year's production equals this year's production. So, part ( P ) = 93,600 and rate ( R ) = 120%     The number of DNA testing kits produced last year was 78,000. Use this number and knowledge that the sales volume increased 20, from 2 years ago to last year to find production 2 years ago. Quick TIP  It is important to realize that the two 20, increases cannot be added together to equal one increase of 40,. Each 20, increase is calculated on a different base.     Production two years ago added to 20, of that production equals last year's production. So, part ( P ) = 78,000 and rate ( R ) = 120% once again.     The calculator solution to this example is done by dividing in a series.     Check the answer.
Substituting in the percent formula with part = $203,500 and rate = 110, results in the following.
Solve for base in the following. Round to the nearest cent. (Hint: Original + Increase = New Value.) (See Examples.)  Using a Diagram to Understand an Increase Problem  The value of a home sold by Tom Dugally this year is $203,500, which is 10, more than last year's value. Find the value of the home last year. SOLUTION  CASE IN POINT The phrase 10% more than last year's value, tells us that last year's value is the base and that it is the unknown. The figure below shows last year's value as 100% and this year's value which is: (the base + 10% more than last year's value) = 110% of the base     The diagram shows that the 10, increase is based on last year's value which is not known. It is not based on this year's value of $203,500. This year's value is last year's value plus 10, of last year's value. Use the basic percent formula to solve for base in increase problems.     Substituting in the percent formula with part = $203,500 and rate = 110, results in the following.     Quick TIP  The common error in solving an increase problem is thinking that the base is given and that the solution can be found by solving for part. Solving for B results in the following equation, which is solved for B.     So the value of the house last year was $185,000. Now check the answer.     $203,500 is 110, of $185,000. Finding Base after Two Increases      Due to increased demand for a patented process that will help analyze the DNA of mice, Biotics Genome has increased production of testing kits by 20, per year for each of the two past years. This year's production is 93,600 kits. Find the number of kits produced two years ago. SOLUTION  The two 20, increases cannot be added together since the two increases act on different bases. Solve this problem in two steps, one for each of the 20, increases. First, use a diagram to find last year's production of DNA kits.     Last year's production plus 20% of last year's production equals this year's production. So, part ( P ) = 93,600 and rate ( R ) = 120%     The number of DNA testing kits produced last year was 78,000. Use this number and knowledge that the sales volume increased 20, from 2 years ago to last year to find production 2 years ago. Quick TIP  It is important to realize that the two 20, increases cannot be added together to equal one increase of 40,. Each 20, increase is calculated on a different base.     Production two years ago added to 20, of that production equals last year's production. So, part ( P ) = 78,000 and rate ( R ) = 120% once again.     The calculator solution to this example is done by dividing in a series.     Check the answer.
Quick TIP
The common error in solving an increase problem is thinking that the base is given and that the solution can be found by solving for part.
Solving for B results in the following equation, which is solved for B.
Solve for base in the following. Round to the nearest cent. (Hint: Original + Increase = New Value.) (See Examples.)  Using a Diagram to Understand an Increase Problem  The value of a home sold by Tom Dugally this year is $203,500, which is 10, more than last year's value. Find the value of the home last year. SOLUTION  CASE IN POINT The phrase 10% more than last year's value, tells us that last year's value is the base and that it is the unknown. The figure below shows last year's value as 100% and this year's value which is: (the base + 10% more than last year's value) = 110% of the base     The diagram shows that the 10, increase is based on last year's value which is not known. It is not based on this year's value of $203,500. This year's value is last year's value plus 10, of last year's value. Use the basic percent formula to solve for base in increase problems.     Substituting in the percent formula with part = $203,500 and rate = 110, results in the following.     Quick TIP  The common error in solving an increase problem is thinking that the base is given and that the solution can be found by solving for part. Solving for B results in the following equation, which is solved for B.     So the value of the house last year was $185,000. Now check the answer.     $203,500 is 110, of $185,000. Finding Base after Two Increases      Due to increased demand for a patented process that will help analyze the DNA of mice, Biotics Genome has increased production of testing kits by 20, per year for each of the two past years. This year's production is 93,600 kits. Find the number of kits produced two years ago. SOLUTION  The two 20, increases cannot be added together since the two increases act on different bases. Solve this problem in two steps, one for each of the 20, increases. First, use a diagram to find last year's production of DNA kits.     Last year's production plus 20% of last year's production equals this year's production. So, part ( P ) = 93,600 and rate ( R ) = 120%     The number of DNA testing kits produced last year was 78,000. Use this number and knowledge that the sales volume increased 20, from 2 years ago to last year to find production 2 years ago. Quick TIP  It is important to realize that the two 20, increases cannot be added together to equal one increase of 40,. Each 20, increase is calculated on a different base.     Production two years ago added to 20, of that production equals last year's production. So, part ( P ) = 78,000 and rate ( R ) = 120% once again.     The calculator solution to this example is done by dividing in a series.     Check the answer.
So the value of the house last year was $185,000. Now check the answer.
Solve for base in the following. Round to the nearest cent. (Hint: Original + Increase = New Value.) (See Examples.)  Using a Diagram to Understand an Increase Problem  The value of a home sold by Tom Dugally this year is $203,500, which is 10, more than last year's value. Find the value of the home last year. SOLUTION  CASE IN POINT The phrase 10% more than last year's value, tells us that last year's value is the base and that it is the unknown. The figure below shows last year's value as 100% and this year's value which is: (the base + 10% more than last year's value) = 110% of the base     The diagram shows that the 10, increase is based on last year's value which is not known. It is not based on this year's value of $203,500. This year's value is last year's value plus 10, of last year's value. Use the basic percent formula to solve for base in increase problems.     Substituting in the percent formula with part = $203,500 and rate = 110, results in the following.     Quick TIP  The common error in solving an increase problem is thinking that the base is given and that the solution can be found by solving for part. Solving for B results in the following equation, which is solved for B.     So the value of the house last year was $185,000. Now check the answer.     $203,500 is 110, of $185,000. Finding Base after Two Increases      Due to increased demand for a patented process that will help analyze the DNA of mice, Biotics Genome has increased production of testing kits by 20, per year for each of the two past years. This year's production is 93,600 kits. Find the number of kits produced two years ago. SOLUTION  The two 20, increases cannot be added together since the two increases act on different bases. Solve this problem in two steps, one for each of the 20, increases. First, use a diagram to find last year's production of DNA kits.     Last year's production plus 20% of last year's production equals this year's production. So, part ( P ) = 93,600 and rate ( R ) = 120%     The number of DNA testing kits produced last year was 78,000. Use this number and knowledge that the sales volume increased 20, from 2 years ago to last year to find production 2 years ago. Quick TIP  It is important to realize that the two 20, increases cannot be added together to equal one increase of 40,. Each 20, increase is calculated on a different base.     Production two years ago added to 20, of that production equals last year's production. So, part ( P ) = 78,000 and rate ( R ) = 120% once again.     The calculator solution to this example is done by dividing in a series.     Check the answer.
$203,500 is 110, of $185,000.
Finding Base after Two Increases
Solve for base in the following. Round to the nearest cent. (Hint: Original + Increase = New Value.) (See Examples.)  Using a Diagram to Understand an Increase Problem  The value of a home sold by Tom Dugally this year is $203,500, which is 10, more than last year's value. Find the value of the home last year. SOLUTION  CASE IN POINT The phrase 10% more than last year's value, tells us that last year's value is the base and that it is the unknown. The figure below shows last year's value as 100% and this year's value which is: (the base + 10% more than last year's value) = 110% of the base     The diagram shows that the 10, increase is based on last year's value which is not known. It is not based on this year's value of $203,500. This year's value is last year's value plus 10, of last year's value. Use the basic percent formula to solve for base in increase problems.     Substituting in the percent formula with part = $203,500 and rate = 110, results in the following.     Quick TIP  The common error in solving an increase problem is thinking that the base is given and that the solution can be found by solving for part. Solving for B results in the following equation, which is solved for B.     So the value of the house last year was $185,000. Now check the answer.     $203,500 is 110, of $185,000. Finding Base after Two Increases      Due to increased demand for a patented process that will help analyze the DNA of mice, Biotics Genome has increased production of testing kits by 20, per year for each of the two past years. This year's production is 93,600 kits. Find the number of kits produced two years ago. SOLUTION  The two 20, increases cannot be added together since the two increases act on different bases. Solve this problem in two steps, one for each of the 20, increases. First, use a diagram to find last year's production of DNA kits.     Last year's production plus 20% of last year's production equals this year's production. So, part ( P ) = 93,600 and rate ( R ) = 120%     The number of DNA testing kits produced last year was 78,000. Use this number and knowledge that the sales volume increased 20, from 2 years ago to last year to find production 2 years ago. Quick TIP  It is important to realize that the two 20, increases cannot be added together to equal one increase of 40,. Each 20, increase is calculated on a different base.     Production two years ago added to 20, of that production equals last year's production. So, part ( P ) = 78,000 and rate ( R ) = 120% once again.     The calculator solution to this example is done by dividing in a series.     Check the answer.
Due to increased demand for a patented process that will help analyze the DNA of mice, Biotics Genome has increased production of testing kits by 20, per year for each of the two past years. This year's production is 93,600 kits. Find the number of kits produced two years ago.
SOLUTION
The two 20, increases cannot be added together since the two increases act on different bases. Solve this problem in two steps, one for each of the 20, increases. First, use a diagram to find last year's production of DNA kits.
Solve for base in the following. Round to the nearest cent. (Hint: Original + Increase = New Value.) (See Examples.)  Using a Diagram to Understand an Increase Problem  The value of a home sold by Tom Dugally this year is $203,500, which is 10, more than last year's value. Find the value of the home last year. SOLUTION  CASE IN POINT The phrase 10% more than last year's value, tells us that last year's value is the base and that it is the unknown. The figure below shows last year's value as 100% and this year's value which is: (the base + 10% more than last year's value) = 110% of the base     The diagram shows that the 10, increase is based on last year's value which is not known. It is not based on this year's value of $203,500. This year's value is last year's value plus 10, of last year's value. Use the basic percent formula to solve for base in increase problems.     Substituting in the percent formula with part = $203,500 and rate = 110, results in the following.     Quick TIP  The common error in solving an increase problem is thinking that the base is given and that the solution can be found by solving for part. Solving for B results in the following equation, which is solved for B.     So the value of the house last year was $185,000. Now check the answer.     $203,500 is 110, of $185,000. Finding Base after Two Increases      Due to increased demand for a patented process that will help analyze the DNA of mice, Biotics Genome has increased production of testing kits by 20, per year for each of the two past years. This year's production is 93,600 kits. Find the number of kits produced two years ago. SOLUTION  The two 20, increases cannot be added together since the two increases act on different bases. Solve this problem in two steps, one for each of the 20, increases. First, use a diagram to find last year's production of DNA kits.     Last year's production plus 20% of last year's production equals this year's production. So, part ( P ) = 93,600 and rate ( R ) = 120%     The number of DNA testing kits produced last year was 78,000. Use this number and knowledge that the sales volume increased 20, from 2 years ago to last year to find production 2 years ago. Quick TIP  It is important to realize that the two 20, increases cannot be added together to equal one increase of 40,. Each 20, increase is calculated on a different base.     Production two years ago added to 20, of that production equals last year's production. So, part ( P ) = 78,000 and rate ( R ) = 120% once again.     The calculator solution to this example is done by dividing in a series.     Check the answer.
Last year's production plus 20% of last year's production equals this year's production. So, part ( P ) = 93,600 and rate ( R ) = 120%
Solve for base in the following. Round to the nearest cent. (Hint: Original + Increase = New Value.) (See Examples.)  Using a Diagram to Understand an Increase Problem  The value of a home sold by Tom Dugally this year is $203,500, which is 10, more than last year's value. Find the value of the home last year. SOLUTION  CASE IN POINT The phrase 10% more than last year's value, tells us that last year's value is the base and that it is the unknown. The figure below shows last year's value as 100% and this year's value which is: (the base + 10% more than last year's value) = 110% of the base     The diagram shows that the 10, increase is based on last year's value which is not known. It is not based on this year's value of $203,500. This year's value is last year's value plus 10, of last year's value. Use the basic percent formula to solve for base in increase problems.     Substituting in the percent formula with part = $203,500 and rate = 110, results in the following.     Quick TIP  The common error in solving an increase problem is thinking that the base is given and that the solution can be found by solving for part. Solving for B results in the following equation, which is solved for B.     So the value of the house last year was $185,000. Now check the answer.     $203,500 is 110, of $185,000. Finding Base after Two Increases      Due to increased demand for a patented process that will help analyze the DNA of mice, Biotics Genome has increased production of testing kits by 20, per year for each of the two past years. This year's production is 93,600 kits. Find the number of kits produced two years ago. SOLUTION  The two 20, increases cannot be added together since the two increases act on different bases. Solve this problem in two steps, one for each of the 20, increases. First, use a diagram to find last year's production of DNA kits.     Last year's production plus 20% of last year's production equals this year's production. So, part ( P ) = 93,600 and rate ( R ) = 120%     The number of DNA testing kits produced last year was 78,000. Use this number and knowledge that the sales volume increased 20, from 2 years ago to last year to find production 2 years ago. Quick TIP  It is important to realize that the two 20, increases cannot be added together to equal one increase of 40,. Each 20, increase is calculated on a different base.     Production two years ago added to 20, of that production equals last year's production. So, part ( P ) = 78,000 and rate ( R ) = 120% once again.     The calculator solution to this example is done by dividing in a series.     Check the answer.
The number of DNA testing kits produced last year was 78,000. Use this number and knowledge that the sales volume increased 20, from 2 years ago to last year to find production 2 years ago.
Quick TIP
It is important to realize that the two 20, increases cannot be added together to equal one increase of 40,. Each 20, increase is calculated on a different base.
Solve for base in the following. Round to the nearest cent. (Hint: Original + Increase = New Value.) (See Examples.)  Using a Diagram to Understand an Increase Problem  The value of a home sold by Tom Dugally this year is $203,500, which is 10, more than last year's value. Find the value of the home last year. SOLUTION  CASE IN POINT The phrase 10% more than last year's value, tells us that last year's value is the base and that it is the unknown. The figure below shows last year's value as 100% and this year's value which is: (the base + 10% more than last year's value) = 110% of the base     The diagram shows that the 10, increase is based on last year's value which is not known. It is not based on this year's value of $203,500. This year's value is last year's value plus 10, of last year's value. Use the basic percent formula to solve for base in increase problems.     Substituting in the percent formula with part = $203,500 and rate = 110, results in the following.     Quick TIP  The common error in solving an increase problem is thinking that the base is given and that the solution can be found by solving for part. Solving for B results in the following equation, which is solved for B.     So the value of the house last year was $185,000. Now check the answer.     $203,500 is 110, of $185,000. Finding Base after Two Increases      Due to increased demand for a patented process that will help analyze the DNA of mice, Biotics Genome has increased production of testing kits by 20, per year for each of the two past years. This year's production is 93,600 kits. Find the number of kits produced two years ago. SOLUTION  The two 20, increases cannot be added together since the two increases act on different bases. Solve this problem in two steps, one for each of the 20, increases. First, use a diagram to find last year's production of DNA kits.     Last year's production plus 20% of last year's production equals this year's production. So, part ( P ) = 93,600 and rate ( R ) = 120%     The number of DNA testing kits produced last year was 78,000. Use this number and knowledge that the sales volume increased 20, from 2 years ago to last year to find production 2 years ago. Quick TIP  It is important to realize that the two 20, increases cannot be added together to equal one increase of 40,. Each 20, increase is calculated on a different base.     Production two years ago added to 20, of that production equals last year's production. So, part ( P ) = 78,000 and rate ( R ) = 120% once again.     The calculator solution to this example is done by dividing in a series.     Check the answer.
Production two years ago added to 20, of that production equals last year's production. So, part ( P ) = 78,000 and rate ( R ) = 120% once again.
Solve for base in the following. Round to the nearest cent. (Hint: Original + Increase = New Value.) (See Examples.)  Using a Diagram to Understand an Increase Problem  The value of a home sold by Tom Dugally this year is $203,500, which is 10, more than last year's value. Find the value of the home last year. SOLUTION  CASE IN POINT The phrase 10% more than last year's value, tells us that last year's value is the base and that it is the unknown. The figure below shows last year's value as 100% and this year's value which is: (the base + 10% more than last year's value) = 110% of the base     The diagram shows that the 10, increase is based on last year's value which is not known. It is not based on this year's value of $203,500. This year's value is last year's value plus 10, of last year's value. Use the basic percent formula to solve for base in increase problems.     Substituting in the percent formula with part = $203,500 and rate = 110, results in the following.     Quick TIP  The common error in solving an increase problem is thinking that the base is given and that the solution can be found by solving for part. Solving for B results in the following equation, which is solved for B.     So the value of the house last year was $185,000. Now check the answer.     $203,500 is 110, of $185,000. Finding Base after Two Increases      Due to increased demand for a patented process that will help analyze the DNA of mice, Biotics Genome has increased production of testing kits by 20, per year for each of the two past years. This year's production is 93,600 kits. Find the number of kits produced two years ago. SOLUTION  The two 20, increases cannot be added together since the two increases act on different bases. Solve this problem in two steps, one for each of the 20, increases. First, use a diagram to find last year's production of DNA kits.     Last year's production plus 20% of last year's production equals this year's production. So, part ( P ) = 93,600 and rate ( R ) = 120%     The number of DNA testing kits produced last year was 78,000. Use this number and knowledge that the sales volume increased 20, from 2 years ago to last year to find production 2 years ago. Quick TIP  It is important to realize that the two 20, increases cannot be added together to equal one increase of 40,. Each 20, increase is calculated on a different base.     Production two years ago added to 20, of that production equals last year's production. So, part ( P ) = 78,000 and rate ( R ) = 120% once again.     The calculator solution to this example is done by dividing in a series.     Check the answer.
The calculator solution to this example is done by dividing in a series.
Solve for base in the following. Round to the nearest cent. (Hint: Original + Increase = New Value.) (See Examples.)  Using a Diagram to Understand an Increase Problem  The value of a home sold by Tom Dugally this year is $203,500, which is 10, more than last year's value. Find the value of the home last year. SOLUTION  CASE IN POINT The phrase 10% more than last year's value, tells us that last year's value is the base and that it is the unknown. The figure below shows last year's value as 100% and this year's value which is: (the base + 10% more than last year's value) = 110% of the base     The diagram shows that the 10, increase is based on last year's value which is not known. It is not based on this year's value of $203,500. This year's value is last year's value plus 10, of last year's value. Use the basic percent formula to solve for base in increase problems.     Substituting in the percent formula with part = $203,500 and rate = 110, results in the following.     Quick TIP  The common error in solving an increase problem is thinking that the base is given and that the solution can be found by solving for part. Solving for B results in the following equation, which is solved for B.     So the value of the house last year was $185,000. Now check the answer.     $203,500 is 110, of $185,000. Finding Base after Two Increases      Due to increased demand for a patented process that will help analyze the DNA of mice, Biotics Genome has increased production of testing kits by 20, per year for each of the two past years. This year's production is 93,600 kits. Find the number of kits produced two years ago. SOLUTION  The two 20, increases cannot be added together since the two increases act on different bases. Solve this problem in two steps, one for each of the 20, increases. First, use a diagram to find last year's production of DNA kits.     Last year's production plus 20% of last year's production equals this year's production. So, part ( P ) = 93,600 and rate ( R ) = 120%     The number of DNA testing kits produced last year was 78,000. Use this number and knowledge that the sales volume increased 20, from 2 years ago to last year to find production 2 years ago. Quick TIP  It is important to realize that the two 20, increases cannot be added together to equal one increase of 40,. Each 20, increase is calculated on a different base.     Production two years ago added to 20, of that production equals last year's production. So, part ( P ) = 78,000 and rate ( R ) = 120% once again.     The calculator solution to this example is done by dividing in a series.     Check the answer.
Check the answer.
Solve for base in the following. Round to the nearest cent. (Hint: Original + Increase = New Value.) (See Examples.)  Using a Diagram to Understand an Increase Problem  The value of a home sold by Tom Dugally this year is $203,500, which is 10, more than last year's value. Find the value of the home last year. SOLUTION  CASE IN POINT The phrase 10% more than last year's value, tells us that last year's value is the base and that it is the unknown. The figure below shows last year's value as 100% and this year's value which is: (the base + 10% more than last year's value) = 110% of the base     The diagram shows that the 10, increase is based on last year's value which is not known. It is not based on this year's value of $203,500. This year's value is last year's value plus 10, of last year's value. Use the basic percent formula to solve for base in increase problems.     Substituting in the percent formula with part = $203,500 and rate = 110, results in the following.     Quick TIP  The common error in solving an increase problem is thinking that the base is given and that the solution can be found by solving for part. Solving for B results in the following equation, which is solved for B.     So the value of the house last year was $185,000. Now check the answer.     $203,500 is 110, of $185,000. Finding Base after Two Increases      Due to increased demand for a patented process that will help analyze the DNA of mice, Biotics Genome has increased production of testing kits by 20, per year for each of the two past years. This year's production is 93,600 kits. Find the number of kits produced two years ago. SOLUTION  The two 20, increases cannot be added together since the two increases act on different bases. Solve this problem in two steps, one for each of the 20, increases. First, use a diagram to find last year's production of DNA kits.     Last year's production plus 20% of last year's production equals this year's production. So, part ( P ) = 93,600 and rate ( R ) = 120%     The number of DNA testing kits produced last year was 78,000. Use this number and knowledge that the sales volume increased 20, from 2 years ago to last year to find production 2 years ago. Quick TIP  It is important to realize that the two 20, increases cannot be added together to equal one increase of 40,. Each 20, increase is calculated on a different base.     Production two years ago added to 20, of that production equals last year's production. So, part ( P ) = 78,000 and rate ( R ) = 120% once again.     The calculator solution to this example is done by dividing in a series.     Check the answer.
Solve for base in the following. Round to the nearest cent. (Hint: Original + Increase = New Value.) (See Examples.)  Using a Diagram to Understand an Increase Problem  The value of a home sold by Tom Dugally this year is $203,500, which is 10, more than last year's value. Find the value of the home last year. SOLUTION  CASE IN POINT The phrase 10% more than last year's value, tells us that last year's value is the base and that it is the unknown. The figure below shows last year's value as 100% and this year's value which is: (the base + 10% more than last year's value) = 110% of the base     The diagram shows that the 10, increase is based on last year's value which is not known. It is not based on this year's value of $203,500. This year's value is last year's value plus 10, of last year's value. Use the basic percent formula to solve for base in increase problems.     Substituting in the percent formula with part = $203,500 and rate = 110, results in the following.     Quick TIP  The common error in solving an increase problem is thinking that the base is given and that the solution can be found by solving for part. Solving for B results in the following equation, which is solved for B.     So the value of the house last year was $185,000. Now check the answer.     $203,500 is 110, of $185,000. Finding Base after Two Increases      Due to increased demand for a patented process that will help analyze the DNA of mice, Biotics Genome has increased production of testing kits by 20, per year for each of the two past years. This year's production is 93,600 kits. Find the number of kits produced two years ago. SOLUTION  The two 20, increases cannot be added together since the two increases act on different bases. Solve this problem in two steps, one for each of the 20, increases. First, use a diagram to find last year's production of DNA kits.     Last year's production plus 20% of last year's production equals this year's production. So, part ( P ) = 93,600 and rate ( R ) = 120%     The number of DNA testing kits produced last year was 78,000. Use this number and knowledge that the sales volume increased 20, from 2 years ago to last year to find production 2 years ago. Quick TIP  It is important to realize that the two 20, increases cannot be added together to equal one increase of 40,. Each 20, increase is calculated on a different base.     Production two years ago added to 20, of that production equals last year's production. So, part ( P ) = 78,000 and rate ( R ) = 120% once again.     The calculator solution to this example is done by dividing in a series.     Check the answer.
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Business Mathematics Brief 12th Edition by Stanley Salzman ,Gary Clendenen, Charles Miller
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