
College Physics 10th Edition by Raymond Serway,Chris Vuille
Edition 10ISBN: 978-1285737041
College Physics 10th Edition by Raymond Serway,Chris Vuille
Edition 10ISBN: 978-1285737041 Exercise 2
A positive charge q 1 = 2.70 C on a frictionless horizontal surface is attached to a spring of force constant k as in Figure P15.12. When a charge of q 2 = 28.60 C is placed 9.50 cm away from the positive charge, the spring stretches by 5.00 mm, reducing the distance between charges to d = 9.00 cm. Find the value of k.
Explanation
Coulomb's law states that the electro static force between the two charges is directly proportional to the charge of each particle and inversely proportional to the square of the distance between the two charges.
Here,
is the Coulomb's constant,
is the charge of the particle 1,
is the charge of the particle 2, and
is the distance between the two particles.
The number of force acts on the charge
is shown in the below figure.
The magnitude of the restoring force of the spring along the horizontal-direction is,
Here,
is force constant of the spring and
is stretched length of the spring.
The magnitude of the restoring force of the spring is balanced with the electrostatic force between the two charges.
Rewrite the equation for
.
Substitute
for
,
for
,
for
, and
for
.
Therefore, the force constant of the spring is
.





The number of force acts on the charge





The magnitude of the restoring force of the spring is balanced with the electrostatic force between the two charges.













College Physics 10th Edition by Raymond Serway,Chris Vuille
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