
Exercise Physiology 8th Edition by Edward Howley, Scott Powers
Edition 8ISBN: 978-0078022531
Exercise Physiology 8th Edition by Edward Howley, Scott Powers
Edition 8ISBN: 978-0078022531 Exercise 2
Calculate the total amount of work performed in 5 minutes of exercise on the cycle ergometer, given the following:
Resistance on the flywheel = 25 N
Cranking speed = 60 rpm
Distance traveled per revolution = 6 meters
Resistance on the flywheel = 25 N
Cranking speed = 60 rpm
Distance traveled per revolution = 6 meters
Explanation
The following information is provided:
• Resistance on the flywheel = 25 N
• Cranking speed = 60 rpm
• Distance travelled per revolution = 6 m
• Duration of work performed = 5 min
The distance travelled per revolution is 6 m. Since the cranking speed is 60 rpm, the distance travelled in one minute is 60 × 6 = 360 m. The distance travelled in 5 minutes is 360 × 5 = 1800 meters.
Total work done = Force × distance = 25 N × 1800 m = 45,000 J or 45 kJ.
Therefore, the amount of work performed on cycle ergometer in 5 min is 45 kJ.
• Resistance on the flywheel = 25 N
• Cranking speed = 60 rpm
• Distance travelled per revolution = 6 m
• Duration of work performed = 5 min
The distance travelled per revolution is 6 m. Since the cranking speed is 60 rpm, the distance travelled in one minute is 60 × 6 = 360 m. The distance travelled in 5 minutes is 360 × 5 = 1800 meters.
Total work done = Force × distance = 25 N × 1800 m = 45,000 J or 45 kJ.
Therefore, the amount of work performed on cycle ergometer in 5 min is 45 kJ.
Exercise Physiology 8th Edition by Edward Howley, Scott Powers
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