Multiple Choice
The standard free energy change for a chemical reaction is +13.3 kJ.What is the equilibrium constant for the reaction at 125°C? (R = 8.31 × 10−3 kJ/K)
A) 2.8 × 10-6
B) 2.0 × 10-5
C) 4.7 × 10-3
D) 1.8 × 10-2
E) 2.1 × 102
Correct Answer:
Verified
Correct Answer:
Verified
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