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∫x3−7x2+4xdx=x33−7x22+4ln⁡∣x∣+C\int \frac { x ^ { 3 } - 7 x ^ { 2 } + 4 } { x } d x = \frac { x ^ { 3 } } { 3 } - \frac { 7 x ^ { 2 } } { 2 } + 4 \ln | x | + C

Question 114

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∫x3−7x2+4xdx=x33−7x22+4ln⁡∣x∣+C\int \frac { x ^ { 3 } - 7 x ^ { 2 } + 4 } { x } d x = \frac { x ^ { 3 } } { 3 } - \frac { 7 x ^ { 2 } } { 2 } + 4 \ln | x | + C

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