A Uniform Rod of Mass M = 1 $\theta$ = 40 $\degree$

Multiple Choice

A uniform rod of mass M = 1.2 kg and length L = 0.80 m,lying on a frictionless horizontal plane,is free to pivot about a vertical axis through one end,as shown.The moment of inertia of the rod about this axis is given by (1/3) ML².If a force (F = 5.0 N, $\theta$ = 40 $\degree$ ) acts as shown,what is the resulting angular acceleration about the pivot point?

A) 16 rad/s²
B) 12 rad/s²
C) 14 rad/s²
D) 10 rad/s²
E) 33 rad/s²