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Combustion of 493 Mg of a Hydrocarbon Gave 1549 Mg

Question 19

Multiple Choice

Combustion of 493 mg of a hydrocarbon gave 1549 mg CO2 and 633.9 mg H2O. What is the molecular formula if the molecular weight is subsequently found to be 42?


A) CO2
B) CH2
C) C6H12
D) C2H2O
E) C3H6

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