Deck 8: Interval Estimation
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Deck 8: Interval Estimation
1
In developing an interval estimate, if the population standard deviation is unknown
A) it is impossible to develop the interval estimate.
B) the standard deviation is arrived at using the range.
C) the sample standard deviation must be used.
D) it is assumed that the population standard deviation is 1.
A) it is impossible to develop the interval estimate.
B) the standard deviation is arrived at using the range.
C) the sample standard deviation must be used.
D) it is assumed that the population standard deviation is 1.
the sample standard deviation must be used.
2
In interval estimation, as the sample size becomes larger, the interval estimate
A) becomes narrower.
B) becomes wider.
C) remains the same, because the mean is not changing.
D) gets closer to 1.96.
A) becomes narrower.
B) becomes wider.
C) remains the same, because the mean is not changing.
D) gets closer to 1.96.
becomes narrower.
3
When s is used to estimate σ, the margin of error is computed by using the
A) normal distribution.
B) t distribution.
C) mean of the sample.
D) mean of the population.
A) normal distribution.
B) t distribution.
C) mean of the sample.
D) mean of the population.
t distribution.
4
In interval estimation, the t distribution is applicable only when
A) the population has a mean of less than 30.
B) the sample standard deviation is used to estimate the population standard deviation.
C) the variance of the population is known.
D) the mean of the population is unknown.
A) the population has a mean of less than 30.
B) the sample standard deviation is used to estimate the population standard deviation.
C) the variance of the population is known.
D) the mean of the population is unknown.
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5
From a population that is not normally distributed and whose standard deviation is not known, a sample of 6 items is selected to develop an interval estimate for the mean of the population (μ).
A) The normal distribution can be used.
B) The t distribution with 5 degrees of freedom must be used.
C) The t distribution with 6 degrees of freedom must be used.
D) The sample size must be increased.
A) The normal distribution can be used.
B) The t distribution with 5 degrees of freedom must be used.
C) The t distribution with 6 degrees of freedom must be used.
D) The sample size must be increased.
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6
From a population that is normally distributed, a sample of 25 elements is selected and the standard deviation of the sample is computed.For the interval estimation of μ, the proper distribution to use is the
A) normal distribution.
B) t distribution with 25 degrees of freedom.
C) t distribution with 26 degrees of freedom.
D) t distribution with 24 degrees of freedom.
A) normal distribution.
B) t distribution with 25 degrees of freedom.
C) t distribution with 26 degrees of freedom.
D) t distribution with 24 degrees of freedom.
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7
For the interval estimation of μ when σ is known and the sample is large, the proper distribution to use is the
A) normal distribution.
B) t distribution with n degrees of freedom.
C) t distribution with n + 1 degrees of freedom.
D) t distribution with n - 1 degrees of freedom.
A) normal distribution.
B) t distribution with n degrees of freedom.
C) t distribution with n + 1 degrees of freedom.
D) t distribution with n - 1 degrees of freedom.
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8
As the sample size increases, the margin of error
A) increases.
B) decreases.
C) stays the same.
D) fluctuates depending on the mean.
A) increases.
B) decreases.
C) stays the same.
D) fluctuates depending on the mean.
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9
If we want to provide a 95% confidence interval for the mean of a population, the confidence coefficient will be
A) .485.
B) 1.96.
C) .95.
D) 1.645.
A) .485.
B) 1.96.
C) .95.
D) 1.645.
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10
From a population with a variance of 900, a sample of 225 items is selected.At 95% confidence, the margin of error is
A) 15.
B) 2.0.
C) 3.92.
D) 4.
A) 15.
B) 2.0.
C) 3.92.
D) 4.
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11
The z value for a 97.8% confidence interval estimation is
A) 2.02.
B) 1.96.
C) 2.00.
D) 2.29.
A) 2.02.
B) 1.96.
C) 2.00.
D) 2.29.
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12
The t value for a 95% confidence interval estimation with 24 degrees of freedom is
A) 1.711.
B) 2.064.
C) 2.492.
D) 2.069.
A) 1.711.
B) 2.064.
C) 2.492.
D) 2.069.
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13
In order to determine an interval for the mean of a population with unknown standard deviation, a sample of 61 items is selected.The mean of the sample is determined to be 23.The associated number of degrees of freedom for reading the t value is
A) 22.
B) 23.
C) 60.
D) 61.
A) 22.
B) 23.
C) 60.
D) 61.
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14
An estimate of a population parameter that provides an interval of values believed to contain the value of the parameter is known as the
A) confidence level.
B) interval estimate.
C) margin of error.
D) point estimate.
A) confidence level.
B) interval estimate.
C) margin of error.
D) point estimate.
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15
A 95% confidence interval for a population mean is determined to be 100 to 120.For the same data, if the confidence coefficient is reduced to .90, the confidence interval for μ
A) becomes narrower.
B) becomes wider.
C) does not change.
D) becomes 100.1 to 120.1.
A) becomes narrower.
B) becomes wider.
C) does not change.
D) becomes 100.1 to 120.1.
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16
A sample of 200 elements from a population with a known standard deviation is selected.For an interval estimation of μ, the proper distribution to use is the
A) normal distribution.
B) t distribution with 200 degrees of freedom.
C) t distribution with 201 degrees of freedom.
D) t distribution with 199 degrees of freedom.
A) normal distribution.
B) t distribution with 200 degrees of freedom.
C) t distribution with 201 degrees of freedom.
D) t distribution with 199 degrees of freedom.
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17
As the number of degrees of freedom for a t distribution increases, the difference between the t distribution and the standard normal distribution
A) becomes larger.
B) becomes smaller.
C) stays the same.
D) fluctuates.
A) becomes larger.
B) becomes smaller.
C) stays the same.
D) fluctuates.
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18
The value added to and subtracted from a point estimate in order to develop an interval estimate of the population parameter is known as the
A) confidence level.
B) margin of error.
C) parameter estimate.
D) planning value.
A) confidence level.
B) margin of error.
C) parameter estimate.
D) planning value.
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19
A population has a standard deviation of 50.A random sample of 100 items from this population is selected.The sample mean is determined to be 600.At 95% confidence, the margin of error is
A) 8.225.
B) 8.3.
C) 9.8.
D) 9.92.
A) 8.225.
B) 8.3.
C) 9.8.
D) 9.92.
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20
In an interval estimation for a proportion of a population, the value of z at 99.2% confidence is
A) 2.65.
B) 2.41.
C) 1.96.
D) 1.645.
A) 2.65.
B) 2.41.
C) 1.96.
D) 1.645.
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21
It is known that the population variance equals 484.With a .95 probability, the sample size that needs to be taken if the desired margin of error is 5 or less is
A) 190.
B) 74.
C) 189.
D) 75.
A) 190.
B) 74.
C) 189.
D) 75.
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22
The following random sample from a population whose values were normally distributed was collected. 10
12
18
16
The 80% confidence interval for μ is
A) 12.054 to 15.946.
B) 10.108 to 17.892.
C) 10.321 to 17.679.
D) 11.009 to 16.991.
12
18
16
The 80% confidence interval for μ is
A) 12.054 to 15.946.
B) 10.108 to 17.892.
C) 10.321 to 17.679.
D) 11.009 to 16.991.
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23
A random sample of 144 observations has a mean of 20, a median of 21, and a mode of 22.The population standard deviation is known to equal 4.8.The 95.44% confidence interval for the population mean is
A) 15.2 to 24.8.
B) 19.20 to 20.80.
C) 19.216 to 20.784.
D) 21.2 to 22.8.
A) 15.2 to 24.8.
B) 19.20 to 20.80.
C) 19.216 to 20.784.
D) 21.2 to 22.8.
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24
The sample size needed to provide a margin of error of 2 or less with a .95 probability when the population standard deviation equals 11 is
A) 10.
B) 11.
C) 116.
D) 117.
A) 10.
B) 11.
C) 116.
D) 117.
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25
The following random sample from a population whose values were normally distributed was collected. 10
8
11
11
The 95% confidence interval for μ is
A) 8.52 to 11.48.
B) 7.75 to 12.25.
C) 9.25 to 10.75.
D) 8.00 to 10.00.
8
11
11
The 95% confidence interval for μ is
A) 8.52 to 11.48.
B) 7.75 to 12.25.
C) 9.25 to 10.75.
D) 8.00 to 10.00.
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26
A random sample of 49 statistics examinations was taken.The average score, in the sample, was 84 with a variance of 12.25.The 95% confidence interval for the average examination score of the population of the examinations is
A) 80.48 to 87.52.
B) 77.40 to 86.60.
C) 82.99 to 85.01.
D) 68.00 to 100.00.
A) 80.48 to 87.52.
B) 77.40 to 86.60.
C) 82.99 to 85.01.
D) 68.00 to 100.00.
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27
In general, higher confidence levels provide
A) wider confidence intervals.
B) narrower confidence intervals.
C) a smaller standard error.
D) unbiased estimates.
A) wider confidence intervals.
B) narrower confidence intervals.
C) a smaller standard error.
D) unbiased estimates.
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28
When the level of confidence decreases, the margin of error
A) stays the same.
B) becomes smaller.
C) becomes larger.
D) becomes smaller or larger, depending on the sample mean.
A) stays the same.
B) becomes smaller.
C) becomes larger.
D) becomes smaller or larger, depending on the sample mean.
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29
When constructing a confidence interval for the population mean using the standard deviation of the sample, the degrees of freedom for the t distribution equals
A) n - 1.
B) n.
C) 2n.
D) n + 1.
A) n - 1.
B) n.
C) 2n.
D) n + 1.
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30
In a sample of 400 voters, 360 indicated they favor the incumbent governor.The 95% confidence interval of voters not favoring the incumbent is
A) .871 to .929.
B) .120 to .280.
C) .765 to .835.
D) .071 to .129.
A) .871 to .929.
B) .120 to .280.
C) .765 to .835.
D) .071 to .129.
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31
We are interested in conducting a study to determine the percentage of voters of a state would vote for the incumbent governor.What is the minimum sample size needed to estimate the population proportion with a margin of error of .05 or less at 95% confidence?
A) 200.
B) 100.
C) 58.
D) 385.
A) 200.
B) 100.
C) 58.
D) 385.
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32
In a random sample of 144 observations, = .6.The 95% confidence interval for p is
A) .52 to .68.
B) .14 to .20.
C) .55 to .65.
D) .50 to .70.
A) .52 to .68.
B) .14 to .20.
C) .55 to .65.
D) .50 to .70.
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33
In a random sample of 100 observations, = .2.The 95.44% confidence interval for p is
A) .122 to .278.
B) .164 to .236.
C) .134 to .266.
D) .120 to .280.
A) .122 to .278.
B) .164 to .236.
C) .134 to .266.
D) .120 to .280.
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34
The ability of an interval estimate to contain the value of the population parameter is described by the
A) confidence level.
B) degrees of freedom.
C) precise value of the population mean μ.
D) point estimate.
A) confidence level.
B) degrees of freedom.
C) precise value of the population mean μ.
D) point estimate.
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35
A random sample of 64 students at a university showed an average age of 25 years and a sample standard deviation of 2 years.The 98% confidence interval for the true average age of all students in the university is
A) 20.5 to 29.5.
B) 24.4 to 25.6.
C) 23.0 to 27.0.
D) 20.0 to 30.0.
A) 20.5 to 29.5.
B) 24.4 to 25.6.
C) 23.0 to 27.0.
D) 20.0 to 30.0.
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36
If we change a 95% confidence interval estimate to a 99% confidence interval estimate, we can expect the
A) width of the confidence interval to increase.
B) width of the confidence interval to decrease.
C) width of the confidence interval to remain the same.
D) sample size to increase.
A) width of the confidence interval to increase.
B) width of the confidence interval to decrease.
C) width of the confidence interval to remain the same.
D) sample size to increase.
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37
Using an α = .04, a confidence interval for a population proportion is determined to be .65 to .75.For the same data, if α is decreased, the confidence interval for the population proportion
A) becomes narrower.
B) becomes wider.
C) uses a zero margin of error.
D) remains the same.
A) becomes narrower.
B) becomes wider.
C) uses a zero margin of error.
D) remains the same.
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38
A random sample of 1000 people was taken.Four hundred fifty of the people in the sample favored Candidate A.The 95% confidence interval for the true proportion of people who favor Candidate A is
A) .419 to .481.
B) .40 to .50.
C) .45 to .55.
D) .424 to .476.
A) .419 to .481.
B) .40 to .50.
C) .45 to .55.
D) .424 to .476.
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39
A sample of 225 elements from a population with a standard deviation of 75 is selected.The sample mean is 180.The 95% confidence interval for μ is
A) 105 to 225.
B) 175 to 185.
C) 171.78 to 188.22.
D) 170.2 to 189.8.
A) 105 to 225.
B) 175 to 185.
C) 171.78 to 188.22.
D) 170.2 to 189.8.
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40
A machine that produces a major part for an airplane engine is monitored closely.In the past, 10% of the parts produced would be defective.With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is
A) 110.
B) 111.
C) 216.
D) 217.
A) 110.
B) 111.
C) 216.
D) 217.
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41
In order to estimate the average electric usage per month, a sample of 81 houses was selected and the electric usage was determined.Assume a population standard deviation of 450 kilowatt-hours.If the sample mean is 1858 kWh, the 95% confidence interval estimate of the population mean is
A) 1760 to 1956 kWh.
B) 1729 to 1987 kWh.
C) 1758 to 1958 kWh.
D) 1776 to 1940 kWh.
A) 1760 to 1956 kWh.
B) 1729 to 1987 kWh.
C) 1758 to 1958 kWh.
D) 1776 to 1940 kWh.
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42
From a population that is not normally distributed and whose standard deviation is not known, a sample of 50 items is selected to develop an interval estimate for µ.Which of the following statements is true?
A) The standard normal distribution can be used.
B) The t distribution with 50 degrees of freedom must be used.
C) The t distribution with 49 degrees of freedom must be used.
D) The sample size must be increased in order to develop an interval estimate.
A) The standard normal distribution can be used.
B) The t distribution with 50 degrees of freedom must be used.
C) The t distribution with 49 degrees of freedom must be used.
D) The sample size must be increased in order to develop an interval estimate.
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43
A sample of 75 information systems managers had an average hourly income of $40.75 with a standard deviation of $7.00.The value of the margin of error at 95% confidence is
A) 80.83.
B) 7.00.
C) .81.
D) 1.61.
A) 80.83.
B) 7.00.
C) .81.
D) 1.61.
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44
A random sample of 64 SAT scores of students applying for merit scholarships showed an average of 1400 with a standard deviation of 240.The t value needed to develop the 95% confidence interval for the population mean SAT score is
A) 1.96.
B) 1.998.
C) 1.645.
D) 1.28.
A) 1.96.
B) 1.998.
C) 1.645.
D) 1.28.
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45
A random sample of 64 SAT scores of students applying for merit scholarships showed an average of 1400 with a standard deviation of 240.The margin of error at 95% confidence is
A) 1.998.
B) 50.07.
C) 80.
D) 59.94.
A) 1.998.
B) 50.07.
C) 80.
D) 59.94.
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46
A sample of 75 information systems managers had an average hourly income of $40.75 with a standard deviation of $7.00.The 95% confidence interval for the average hourly wage (in $) of all information system managers is
A) 38.61 to 42.89.
B) 39.40 to 42.10.
C) 39.14 to 42.36.
D) 37.54 to 43.96.
A) 38.61 to 42.89.
B) 39.40 to 42.10.
C) 39.14 to 42.36.
D) 37.54 to 43.96.
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47
A sample of 75 information systems managers had an average hourly income of $40.75 with a standard deviation of $7.00.The standard error of the mean is
A) 80.83.
B) 7.0.
C) .8083.
D) 1.611.
A) 80.83.
B) 7.0.
C) .8083.
D) 1.611.
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48
In order to estimate the average electric usage per month, a sample of 81 houses was selected and the electric usage was determined.Assume a population standard deviation of 450 kilowatt-hours.At 95% confidence, the size of the margin of error is
A) 1.96.
B) 50.00.
C) 98.00.
D) 42.00.
A) 1.96.
B) 50.00.
C) 98.00.
D) 42.00.
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49
The manager of a grocery store has taken a random sample of 100 customers.The average length of time it took these 100 customers to check out was 3 minutes.It is known that the standard deviation of the population of checkout times is 1 minute.The standard error of the mean equals
A) .001.
B) .010.
C) .100.
D) 1.000.
A) .001.
B) .010.
C) .100.
D) 1.000.
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50
In order to estimate the average time spent per student on the computer terminals at a local university, data were collected for a sample of 81 business students over a one-week period.Assume the population standard deviation is 1.8 hours.If the sample mean is 9 hours, then the 95% confidence interval is
A) 7.04 to 10.96 hours.
B) 7.36 to 10.64 hours.
C) 7.80 to 10.20 hours.
D) 8.61 to 9.39 hours.
A) 7.04 to 10.96 hours.
B) 7.36 to 10.64 hours.
C) 7.80 to 10.20 hours.
D) 8.61 to 9.39 hours.
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51
The manager of a grocery store has taken a random sample of 100 customers.The average length of time it took these 100 customers to check out was 3 minutes.It is known that the standard deviation of the population of checkout times is 1 minute.With a .95 probability, the sample mean will provide a margin of error of
A) 1.96.
B) .10.
C) .196.
D) 1.64.
A) 1.96.
B) .10.
C) .196.
D) 1.64.
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52
In order to estimate the average electric usage per month, a sample of 81 houses was selected and the electric usage was determined.Assume a population standard deviation of 450 kilowatt-hours.The standard error of the mean is
A) 450.
B) 81.
C) 500.
D) 50.
A) 450.
B) 81.
C) 500.
D) 50.
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53
A random sample of 25 employees of a local company has been taken.A 95% confidence interval estimate for the mean systolic blood pressure for all employees of the company is 123 to 139.Which of the following statements is valid?
A) 95% of the sample of employees has a systolic blood pressure between 123 and 139.
B) If the sampling procedure were repeated many times, 95% of the resulting confidence intervals would contain the population mean systolic blood pressure.
C) 95% of the population of employees has a systolic blood pressure between 123 and 139.
D) If the sampling procedure were repeated many times, 95% of the sample means would be between 123 and 139.
A) 95% of the sample of employees has a systolic blood pressure between 123 and 139.
B) If the sampling procedure were repeated many times, 95% of the resulting confidence intervals would contain the population mean systolic blood pressure.
C) 95% of the population of employees has a systolic blood pressure between 123 and 139.
D) If the sampling procedure were repeated many times, 95% of the sample means would be between 123 and 139.
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54
A sample of 75 information systems managers had an average hourly income of $40.75 with a standard deviation of $7.00.If we want to determine a 95% confidence interval for the average hourly income of the population, the value of t is
A) 1.96.
B) 1.645.
C) 1.28.
D) 1.993.
A) 1.96.
B) 1.645.
C) 1.28.
D) 1.993.
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55
A random sample of 64 SAT scores of students applying for merit scholarships showed an average of 1400 with a standard deviation of 240.The 95% confidence interval for the population mean SAT score is
A) 1340.06 to 1459.94.
B) 1341.20 to 1458.80.
C) 1349.93 to 1450.07.
D) 1320.32 to 1479.68.
A) 1340.06 to 1459.94.
B) 1341.20 to 1458.80.
C) 1349.93 to 1450.07.
D) 1320.32 to 1479.68.
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56
The manager of a grocery store has taken a random sample of 100 customers.The average length of time it took these 100 customers to check out was 3 minutes.It is known that the standard deviation of the population of checkout times is 1 minute.The 95% confidence interval for the true average checkout time (in minutes) is
A) 2.5 to 3.5.
B) 1.36 to 4.64.
C) 1 to 5.
D) 2.804 to 3.196.
A) 2.5 to 3.5.
B) 1.36 to 4.64.
C) 1 to 5.
D) 2.804 to 3.196.
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57
In order to estimate the average time spent per student on the computer terminals at a local university, data were collected for a sample of 81 business students over a one-week period.Assume the population standard deviation is 1.8 hours.With a .95 probability, the margin of error is approximately
A) .39.
B) 1.96.
C) .20.
D) 1.64.
A) .39.
B) 1.96.
C) .20.
D) 1.64.
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58
A random sample of 64 SAT scores of students applying for merit scholarships showed an average of 1400 with a standard deviation of 240.If we want to provide a 95% confidence interval for the population mean SAT score, the degrees of freedom for reading the t value is
A) 60.
B) 61.
C) 62.
D) 63.
A) 60.
B) 61.
C) 62.
D) 63.
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59
We can use the normal distribution to make confidence interval estimates for the population proportion, p, when
A) np > 5.
B) n(1 - p) > 5.
C) p has a normal distribution.
D) both np > 5 and n(1 - p) > 5.
A) np > 5.
B) n(1 - p) > 5.
C) p has a normal distribution.
D) both np > 5 and n(1 - p) > 5.
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60
In order to estimate the average time spent per student on the computer terminals at a local university, data were collected for a sample of 81 business students over a one-week period.Assume the population standard deviation is 1.8 hours.The standard error of the mean is
A) 7.50.
B) .39.
C) 2.00.
D) .20.
A) 7.50.
B) .39.
C) 2.00.
D) .20.
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61
To compute the necessary sample size for an interval estimate of a population proportion, all of the following procedures are recommended when p is unknown except
A) use the sample proportion from a previous study.
B) use the sample proportion from a preliminary sample.
C) use 1.0 as an estimate.
D) use judgment or a best guess.
A) use the sample proportion from a previous study.
B) use the sample proportion from a preliminary sample.
C) use 1.0 as an estimate.
D) use judgment or a best guess.
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62
The t distribution should be used whenever
A) the sample size is less than 30.
B) the sample standard deviation is used to estimate the population standard deviation.
C) the population is not normally distributed.
D) the population standard deviation is known.
A) the sample size is less than 30.
B) the sample standard deviation is used to estimate the population standard deviation.
C) the population is not normally distributed.
D) the population standard deviation is known.
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63
The margin of error in an interval estimate of the population mean is a function of all of the following except
A) α.
B) sample mean.
C) sample size.
D) variability of the population.
A) α.
B) sample mean.
C) sample size.
D) variability of the population.
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64
The t distribution is a family of similar probability distributions, with each individual distribution depending on a parameter known as the
A) finite correction factor.
B) sample size.
C) degrees of freedom.
D) standard deviation.
A) finite correction factor.
B) sample size.
C) degrees of freedom.
D) standard deviation.
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65
The degrees of freedom associated with a t distribution are a function of the
A) area in the upper tail.
B) sample standard deviation.
C) confidence coefficient.
D) sample size.
A) area in the upper tail.
B) sample standard deviation.
C) confidence coefficient.
D) sample size.
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66
The probability that the interval estimation procedure will generate an interval that does not contain the actual value of the population parameter being estimated is the
A) proportion estimate.
B) margin of error.
C) confidence coefficient.
D) same as α.
A) proportion estimate.
B) margin of error.
C) confidence coefficient.
D) same as α.
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67
To compute the necessary sample size for an interval estimate of a population mean, all of the following procedures are recommended when σ is unknown except
A) use the estimated σ from a previous study.
B) use the sample standard deviation from a preliminary sample.
C) use judgment or a best guess.
D) use .5 as an estimate.
A) use the estimated σ from a previous study.
B) use the sample standard deviation from a preliminary sample.
C) use judgment or a best guess.
D) use .5 as an estimate.
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68
The level of significance α
A) can be any positive value.
B) is always a negative value.
C) is (1 - confidence coefficient).
D) can be any value between -1.96 to 1.96.
A) can be any positive value.
B) is always a negative value.
C) is (1 - confidence coefficient).
D) can be any value between -1.96 to 1.96.
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69
We are interested in conducting a study in order to determine the percentage of voters in a city who would vote for the incumbent mayor.What is the minimum sample size needed to estimate the population proportion with a margin of error not exceeding 4% at 95% confidence?
A) 625
B) 626
C) 600
D) 601
A) 625
B) 626
C) 600
D) 601
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70
We can reduce the margin of error in an interval estimate of p by doing any of the following except
A) increasing the sample size.
B) increasing the planning value p* to .5.
C) increasing α.
D) reducing the confidence coefficient.
A) increasing the sample size.
B) increasing the planning value p* to .5.
C) increasing α.
D) reducing the confidence coefficient.
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71
As the degrees of freedom increase, the t distribution approaches the
A) uniform distribution.
B) normal distribution.
C) exponential distribution.
D) p distribution.
A) uniform distribution.
B) normal distribution.
C) exponential distribution.
D) p distribution.
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72
It is known that the population variance (σ2) is 144.At 95% confidence, what sample size should be taken so that the margin of error does not exceed 5?
A) 22
B) 23
C) 24
D) 25
A) 22
B) 23
C) 24
D) 25
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73
The sample size that guarantees the estimate of a population proportion satisfying the margin of error requirement is computed using a planning value of p equal to
A) .01.
B) .50.
C) .51.
D) .99.
A) .01.
B) .50.
C) .51.
D) .99.
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74
The mean of the t distribution is
A) 0.
B) .5.
C) 1.
D) problem specific.
A) 0.
B) .5.
C) 1.
D) problem specific.
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75
The use of the normal probability distribution as an approximation of the sampling distribution of is based on the condition that both np and n(1 - p) equal or exceed?
A) .05.
B) 5.
C) 10.
D) 30.
A) .05.
B) 5.
C) 10.
D) 30.
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76
To compute the minimum sample size for an interval estimate of
, we must first determine all of the following except?
A) desired margin of error.
B) confidence level.
C) population standard deviation.
D) degrees of freedom.

A) desired margin of error.
B) confidence level.
C) population standard deviation.
D) degrees of freedom.
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77
For a given confidence level and when σ is known, the margin of error in a confidence interval estimate
A) varies from sample to sample of the same size.
B) is the same for all samples of the same size.
C) increases as the sample size increases.
D) is independent of sample size.
A) varies from sample to sample of the same size.
B) is the same for all samples of the same size.
C) increases as the sample size increases.
D) is independent of sample size.
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78
The general form of an interval estimate of a population mean or a population proportion is the _____ plus and minus the _____.
A) population mean, standard error
B) population proportion, standard error
C) point estimate, margin of error
D) planning value, confidence coefficient
A) population mean, standard error
B) population proportion, standard error
C) point estimate, margin of error
D) planning value, confidence coefficient
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