Deck 8: Microbial Genetics

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Question
Which of the following statements about bacteriocins is FALSE?

A) They can be used to identify certain bacteria.
B) The genes coding for them are on plasmids.
C) They cause food-poisoning symptoms.
D) Nisin is a bacteriocin used as a food preservative.
E) Bacteriocins kill bacteria.
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Question
Transformation is the transfer of DNA from a donor to a recipient cell

A) by a bacteriophage.
B) by cell-to-cell contact.
C) as naked DNA in solution.
D) by sexual reproduction.
E) by crossing over.
Question
DNA is constructed of

A) a single strand of nucleotides with internal hydrogen bonding.
B) two strands of identical nucleotides in a parallel configuration with hydrogen bonds between them.
C) two complementary strands of nucleotides bonded A-C and G-T.
D) two strands of nucleotides running in an antiparallel configuration.
E) None of the answers is correct.
Question
Which of the following statements is FALSE?

A) DNA replication proceeds in only one direction around the bacterial chromosome.
B) The leading strand of DNA is made continuously.
C) The lagging strand of DNA is started by an RNA primer.
D) Multiple replication forks are possible on a bacterial chromosome.
E) DNA polymerase joins nucleotides in one direction (5ʹ to 3ʹ) only.
Question
A gene is best defined as

A) a sequence of nucleotides in DNA that codes for a functional product.
B) a sequence of nucleotides in RNA that codes for a functional product.
C) any random segment of DNA.
D) the RNA product of a transcribed section of DNA.
E) three nucleotides that code for an amino acid.
Question
Genetic change in bacteria can be brought about by

A) transformation.
B) conjugation.
C) transduction.
D) mutation.
E) All of the answers are correct.
Question
Table 8.2
Codon on mRNA and corresponding amino acid
 UUA  leucine  UAA  nonsense  GCA  alanine  AAU  asparagine  AAG  lysine UGC cysteine  GUU  valine UCG,UCU serine \begin{array} { | l | l | l | l | } \hline \text { UUA } & \text { leucine } & \text { UAA } & \text { nonsense } \\\hline \text { GCA } & \text { alanine } & \text { AAU } & \text { asparagine } \\\hline \text { AAG } & \text { lysine } & \mathrm { UGC } & \text { cysteine } \\\hline \text { GUU } & \text { valine } & \mathrm { UCG } , \mathrm { UCU }& \text { serine } \\\hline\end{array}

-Refer to Table 8.2. What is the sequence of amino acids encoded by the following sequence of bases in a strand of DNA (pay attention to the polarity of the DNA here)? 3? ATTACGCTTTGC

A) Translation would stop at the first codon.
B) asparagine-arginine-lysine-alanine
C) asparagine-cysteine-valine-serine
D) leucine-arginine-lysine-alanine
E) The answer cannot be determined based on the information provided.
Question
Table 8.2
Codon on mRNA and corresponding amino acid
 UUA  leucine  UAA  nonsense  GCA  alanine  AAU  asparagine  AAG  lysine UGC cysteine  GUU  valine UCG,UCU serine \begin{array} { | l | l | l | l | } \hline \text { UUA } & \text { leucine } & \text { UAA } & \text { nonsense } \\\hline \text { GCA } & \text { alanine } & \text { AAU } & \text { asparagine } \\\hline \text { AAG } & \text { lysine } & \mathrm { UGC } & \text { cysteine } \\\hline \text { GUU } & \text { valine } & \mathrm { UCG } , \mathrm { UCU }& \text { serine } \\\hline\end{array}

-Refer to Table 8.2. If an indeterminate frameshift mutation occurred in the sequence of bases shown below, what would be the sequence of amino acids coded for? 3? ATTACGCTTTGC

A) Translation would stop at the first codon.
B) leucine-arginine-lysine-alanine
C) asparagine-cysteine-valine-serine
D) asparagine-arginine-lysine-alanine
E) The answer cannot be determined based on the information provided.
Question
The initial effect of ionizing radiation on a cell is that it causes

A) DNA to break.
B) base substitutions.
C) the formation of highly reactive ions.
D) bonding between adjacent thymines.
E) the cells to get hot.
Question
Synthesis of a repressible enzyme is stopped by the

A) substrate binding to the repressor.
B) corepressor-repressor complex binding to the operator.
C) corepressor binding to the operator.
D) allosteric transition.
E) end product binding to the promoter.
Question
Which of the following is NOT a product of transcription?

A) rRNA
B) a new strand of DNA
C) tRNA
D) mRNA
E) None of the answers are correct; all of these are products of transcription.
Question
Figure 8.2
<strong>Figure 8.2   In Figure 8.2, if base 4 is thymine, what is base 4ʹ?</strong> A) guanine B) adenine C) cytosine D) thymine E) uracil <div style=padding-top: 35px>
In Figure 8.2, if base 4 is thymine, what is base 4ʹ?

A) guanine
B) adenine
C) cytosine
D) thymine
E) uracil
Question
Table 8.2
Codon on mRNA and corresponding amino acid
 UUA  leucine  UAA  nonsense  GCA  alanine  AAU  asparagine  AAG  lysine UGC cysteine  GUU  valine UCG,UCU serine \begin{array} { | l | l | l | l | } \hline \text { UUA } & \text { leucine } & \text { UAA } & \text { nonsense } \\\hline \text { GCA } & \text { alanine } & \text { AAU } & \text { asparagine } \\\hline \text { AAG } & \text { lysine } & \mathrm { UGC } & \text { cysteine } \\\hline \text { GUU } & \text { valine } & \mathrm { UCG } , \mathrm { UCU }& \text { serine } \\\hline\end{array}

-Refer to Table 8.2 The anticodon for valine is

A) CUU.
B) GUU.
C) GTA.
D) CTT.
E) CAA.
Question
Figure 8.2
<strong>Figure 8.2   In Figure 8.2, base 2 (and ONLY the base) is covalently bound/attached to</strong> A) deoxyribose. B) phosphate. C) thymine. D) ribose. E) The answer cannot be determined based on the information provided. <div style=padding-top: 35px>
In Figure 8.2, base 2 (and ONLY the base) is covalently bound/attached to

A) deoxyribose.
B) phosphate.
C) thymine.
D) ribose.
E) The answer cannot be determined based on the information provided.
Question
Figure 8.2
<strong>Figure 8.2   In Figure 8.2, if base 4 is thymine, what is base 11ʹ (remember the complimentary configuration of bases in DNA)?</strong> A) guanine B) thymine C) adenine D) uracil E) cytosine <div style=padding-top: 35px>
In Figure 8.2, if base 4 is thymine, what is base 11ʹ (remember the complimentary configuration of bases in DNA)?

A) guanine
B) thymine
C) adenine
D) uracil
E) cytosine
Question
Table 8.2
Codon on mRNA and corresponding amino acid
 UUA  leucine  UAA  nonsense  GCA  alanine  AAU  asparagine  AAG  lysine UGC cysteine  GUU  valine UCG,UCU serine \begin{array} { | l | l | l | l | } \hline \text { UUA } & \text { leucine } & \text { UAA } & \text { nonsense } \\\hline \text { GCA } & \text { alanine } & \text { AAU } & \text { asparagine } \\\hline \text { AAG } & \text { lysine } & \mathrm { UGC } & \text { cysteine } \\\hline \text { GUU } & \text { valine } & \mathrm { UCG } , \mathrm { UCU }& \text { serine } \\\hline\end{array}

-Refer to Table 8.2. If the sequence of amino acids encoded by a strand of DNA is serine-alanine-lysine-leucine, what is the order of bases in the sense strand of DNA?

A) 3? AGACGTTTCAAT
B) 5? AGAGCTTTGAAT
C) 5? TGTGCTTTCTTA
D) 3? UGUGCAAAGUUA
E) 3? TCTCGTTTGTTA
Question
Which of the following statements regarding a bacterium that is R+ is FALSE?

A) It possesses a plasmid.
B) It is resistant to certain drugs and heavy metals.
C) R+ can be transferred to a cell of the same species.
D) R+ can be transferred to a different species.
E) It is F+.
Question
According to the operon model, for the synthesis of an inducible enzyme to occur, the

A) repressor must bind to the operator.
B) end-product must not be in excess.
C) substrate must bind to the enzyme.
D) repressor must not be synthesized.
E) substrate must bind to the repressor.
Question
Which of the following pairs is mismatched?

A) DNA gyrase - coils and twists DNA
B) transposase - insertion of DNA segments into DNA
C) DNA polymerase - makes a molecule of DNA from a DNA template
D) DNA ligase - joins segments of DNA
E) RNA polymerase - makes a molecule of RNA from an RNA template
Question
Figure 8.2
<strong>Figure 8.2   The damage caused by ultraviolet radiation is</strong> A) never repaired. B) repaired by DNA replication. C) repaired during translation. D) cut out and replaced. E) repaired during transcription. <div style=padding-top: 35px>
The damage caused by ultraviolet radiation is

A) never repaired.
B) repaired by DNA replication.
C) repaired during translation.
D) cut out and replaced.
E) repaired during transcription.
Question
Conjugation differs from reproduction because conjugation

A) transcribes DNA to RNA.
B) replicates DNA.
C) transfers DNA vertically, to new cells.
D) copies RNA to make DNA.
E) transfers DNA horizontally, to nearby cells without those cells undergoing replication.
Question
The necessary ingredients for DNA synthesis can be mixed together in a test tube. The DNA polymerase is from Thermus aquaticus, and the template is from a human cell. The DNA synthesized would be most similar to

A) human DNA.
B) human RNA.
C) T. aquaticus RNA.
D) T. aquaticus DNA.
E) a mixture of human and T. aquaticus DNA.
Question
Assume the two E.coli strains shown below are allowed to conjugate. Hfr: pro+, arg+, his+, lys+, met+, ampicillin-sensitive F-: pro-, arg-, his-, lys-, met-, ampicillin-resistant
What supplements would you add to glucose minimal salts agar to select for a recombinant cell that is lys+, arg+, amp-resistant?

A) ampicillin, proline, histidine, lysine
B) lysine, arginine
C) ampicillin, proline, histidine, methionine
D) proline, histidine, methionine
E) ampicillin, lysine, arginine
Question
The mechanism by which the presence of glucose inhibits the lac operon is

A) DNA polymerase.
B) repression.
C) catabolite repression.
D) translation.
E) induction.
Question
Figure 8.4 <strong>Figure 8.4   In Figure 8.4, the antibiotic chloramphenicol binds the 50S large subunit of a ribosome as shown (the light gray area is the large subunit, while the black shape is the drug). From this information you can conclude that chloramphenicol</strong> A) prevents translation in eukaryotes. B) prevents translation in prokaryotes. C) prevents transcription in eukaryotes. D) prevents mRNA-ribosome binding. E) prevents transcription in prokaryotes. <div style=padding-top: 35px> In Figure 8.4, the antibiotic chloramphenicol binds the 50S large subunit of a ribosome as shown (the light gray area is the large subunit, while the black shape is the drug). From this information you can conclude that chloramphenicol

A) prevents translation in eukaryotes.
B) prevents translation in prokaryotes.
C) prevents transcription in eukaryotes.
D) prevents mRNA-ribosome binding.
E) prevents transcription in prokaryotes.
Question
The cancer gene ras produces mRNA containing an extra exon that includes a number of UAA codons. Cancer cells produce ras mRNA missing this exon. This mistake most likely is due to a mistake by

A) photolyases.
B) a chemical mutagen.
C) DNA polymerase.
D) UV radiation.
E) snRNPs.
Question
Figure 8.3 - Metabolic Pathway
 Gene a Gene b Enzyme A  Enzyme B  Compound A  Compound B  Compound C \begin{array} { c c } &\text { Gene } a & \text { Gene } b \\&\downarrow & \downarrow \\&\text { Enzyme A } & \text { Enzyme B } \\&\downarrow & \downarrow \\\text { Compound A } & \rightarrow &\text { Compound B } \rightarrow \text { Compound C }\end{array}

-In Figure 8.3, if compound C reacts with the allosteric site of enzyme A, this would exemplify

A) competitive inhibition.
B) transcription.
C) feedback inhibition.
D) a mutation.
E) repression.
Question
Figure 8.3 - Metabolic Pathway
 Gene a Gene b Enzyme A  Enzyme B  Compound A  Compound B  Compound C \begin{array} { c c } &\text { Gene } a & \text { Gene } b \\&\downarrow & \downarrow \\&\text { Enzyme A } & \text { Enzyme B } \\&\downarrow & \downarrow \\\text { Compound A } & \rightarrow &\text { Compound B } \rightarrow \text { Compound C }\end{array}

-In Figure 8.3, if enzyme A is an inducible enzyme,

A) compound B would bind to enzyme A directly.
B) compound C would react with gene a directly.
C) compound C would bind to the repressor for Gene a.
D) compound A would react with enzyme B directly.
E) compound A would bind to the repressor for Gene a.
Question
The miRNAs in a cell

A) are responsible for inducing operons.
B) are a part of the eukaryotic ribosome.
C) allow different cells to produce different proteins.
D) are a part of the prokaryotic ribosome.
E) are found in prokaryotic cells.
Question
Figure 8.3 - Metabolic Pathway
 Gene a Gene b Enzyme A  Enzyme B  Compound A  Compound B  Compound C \begin{array} { c c } &\text { Gene } a & \text { Gene } b \\&\downarrow & \downarrow \\&\text { Enzyme A } & \text { Enzyme B } \\&\downarrow & \downarrow \\\text { Compound A } & \rightarrow &\text { Compound B } \rightarrow \text { Compound C }\end{array}

-In Figure 8.3, if enzyme A is a repressible enzyme, compound C would

A) bind directly to gene a.
B) bind to the corepressor for Gene a.
C) bind to RNA polymerase.
D) bind to Enzyme A.
E) always be in excess.
Question
Open-reading frames are segments of DNA in which both start and stop codons are found.
Question
Figure 8.5 <strong>Figure 8.5   In Figure 8.5, which model of the lac operon correctly shows RNA polymerase, lactose, and repressor protein when the structural genes are being transcribed?</strong> A) a B) b C) c D) d E) e <div style=padding-top: 35px> In Figure 8.5, which model of the lac operon correctly shows RNA polymerase, lactose, and repressor protein when the structural genes are being transcribed?

A) a
B) b
C) c
D) d
E) e
Question
Table 8.3 Amino Acids Encoded by the Human p53 Gene
<strong>Table 8.3 Amino Acids Encoded by the Human p53 Gene   Based on the information in Table 8.3, prostate cancer is probably the result of which kind of mutation?</strong> A) frameshift B) nonsense C) analog D) missense E) None of the answers is correct. <div style=padding-top: 35px> Based on the information in Table 8.3, prostate cancer is probably the result of which kind of mutation?

A) frameshift
B) nonsense
C) analog
D) missense
E) None of the answers is correct.
Question
Repair of damaged DNA, in some instances and mechanisms, might be viewed as a race between an endonuclease and

A) methylase.
B) primase.
C) DNA ligase.
D) DNA polymerase.
E) helicase.
Question
Recombination will always alter a cellʹs genotype.
Question
An enzyme that catalyzes the cutting and resealing of DNA, and is translated from insertion sequences, is

A) RNA polymerase.
B) DNA ligase.
C) DNA helicase.
D) transposase.
E) DNA polymerase.
Question
An enzyme that copies DNA to make a molecule of RNA is

A) RNA polymerase.
B) DNA ligase.
C) DNA helicase.
D) transposase.
E) DNA polymerase.
Question
If you knew the sequence of nucleotides within a gene, which one of the following could you determine with the most accuracy?

A) the tertiary structure of the protein
B) the primary structure of the protein
C) the quaternary structure of the protein
D) the secondary structure of the protein
E) The answer cannot be determined based on the information provided.
Question
An enzyme that makes covalent bonds between the sugar of one nucleotide and the phosphate groups in another nucleotide in DNA is

A) RNA polymerase.
B) DNA ligase
C) DNA helicase.
D) transposase.
E) DNA polymerase.
Question
Protein synthesis in eukaryotes is similar to the process in prokaryotes in that both eukaryotes and prokaryotes

A) use methionine as the ʺstartʺ amino acid.
B) require snRNPS.
C) have introns.
D) use codons to determine polypeptide sequences.
E) have exons.
Question
Bacteria typically contain multiple chromosomes.
Question
Transposition (insertion of a transposon into a DNA sequence) results in the formation of base substitution mutations in a cellʹs DNA.
Question
Cell-to-cell contact is required for transduction to occur.
Question
In the Ames test, any colonies that form on the control should be the result of spontaneous mutations.
Question
Some cells may contain multiple genomes.
Question
Mutations that are harmful to cells occur more frequently than those that benefit cells.
Question
Both base substitution and frameshift mutations can result in the formation of premature stop codons.
Question
The miRNAs in a cell inhibit protein synthesis by forming complementary bonds with rRNA.
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Deck 8: Microbial Genetics
1
Which of the following statements about bacteriocins is FALSE?

A) They can be used to identify certain bacteria.
B) The genes coding for them are on plasmids.
C) They cause food-poisoning symptoms.
D) Nisin is a bacteriocin used as a food preservative.
E) Bacteriocins kill bacteria.
C
2
Transformation is the transfer of DNA from a donor to a recipient cell

A) by a bacteriophage.
B) by cell-to-cell contact.
C) as naked DNA in solution.
D) by sexual reproduction.
E) by crossing over.
C
3
DNA is constructed of

A) a single strand of nucleotides with internal hydrogen bonding.
B) two strands of identical nucleotides in a parallel configuration with hydrogen bonds between them.
C) two complementary strands of nucleotides bonded A-C and G-T.
D) two strands of nucleotides running in an antiparallel configuration.
E) None of the answers is correct.
D
4
Which of the following statements is FALSE?

A) DNA replication proceeds in only one direction around the bacterial chromosome.
B) The leading strand of DNA is made continuously.
C) The lagging strand of DNA is started by an RNA primer.
D) Multiple replication forks are possible on a bacterial chromosome.
E) DNA polymerase joins nucleotides in one direction (5ʹ to 3ʹ) only.
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5
A gene is best defined as

A) a sequence of nucleotides in DNA that codes for a functional product.
B) a sequence of nucleotides in RNA that codes for a functional product.
C) any random segment of DNA.
D) the RNA product of a transcribed section of DNA.
E) three nucleotides that code for an amino acid.
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6
Genetic change in bacteria can be brought about by

A) transformation.
B) conjugation.
C) transduction.
D) mutation.
E) All of the answers are correct.
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7
Table 8.2
Codon on mRNA and corresponding amino acid
 UUA  leucine  UAA  nonsense  GCA  alanine  AAU  asparagine  AAG  lysine UGC cysteine  GUU  valine UCG,UCU serine \begin{array} { | l | l | l | l | } \hline \text { UUA } & \text { leucine } & \text { UAA } & \text { nonsense } \\\hline \text { GCA } & \text { alanine } & \text { AAU } & \text { asparagine } \\\hline \text { AAG } & \text { lysine } & \mathrm { UGC } & \text { cysteine } \\\hline \text { GUU } & \text { valine } & \mathrm { UCG } , \mathrm { UCU }& \text { serine } \\\hline\end{array}

-Refer to Table 8.2. What is the sequence of amino acids encoded by the following sequence of bases in a strand of DNA (pay attention to the polarity of the DNA here)? 3? ATTACGCTTTGC

A) Translation would stop at the first codon.
B) asparagine-arginine-lysine-alanine
C) asparagine-cysteine-valine-serine
D) leucine-arginine-lysine-alanine
E) The answer cannot be determined based on the information provided.
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8
Table 8.2
Codon on mRNA and corresponding amino acid
 UUA  leucine  UAA  nonsense  GCA  alanine  AAU  asparagine  AAG  lysine UGC cysteine  GUU  valine UCG,UCU serine \begin{array} { | l | l | l | l | } \hline \text { UUA } & \text { leucine } & \text { UAA } & \text { nonsense } \\\hline \text { GCA } & \text { alanine } & \text { AAU } & \text { asparagine } \\\hline \text { AAG } & \text { lysine } & \mathrm { UGC } & \text { cysteine } \\\hline \text { GUU } & \text { valine } & \mathrm { UCG } , \mathrm { UCU }& \text { serine } \\\hline\end{array}

-Refer to Table 8.2. If an indeterminate frameshift mutation occurred in the sequence of bases shown below, what would be the sequence of amino acids coded for? 3? ATTACGCTTTGC

A) Translation would stop at the first codon.
B) leucine-arginine-lysine-alanine
C) asparagine-cysteine-valine-serine
D) asparagine-arginine-lysine-alanine
E) The answer cannot be determined based on the information provided.
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9
The initial effect of ionizing radiation on a cell is that it causes

A) DNA to break.
B) base substitutions.
C) the formation of highly reactive ions.
D) bonding between adjacent thymines.
E) the cells to get hot.
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10
Synthesis of a repressible enzyme is stopped by the

A) substrate binding to the repressor.
B) corepressor-repressor complex binding to the operator.
C) corepressor binding to the operator.
D) allosteric transition.
E) end product binding to the promoter.
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11
Which of the following is NOT a product of transcription?

A) rRNA
B) a new strand of DNA
C) tRNA
D) mRNA
E) None of the answers are correct; all of these are products of transcription.
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12
Figure 8.2
<strong>Figure 8.2   In Figure 8.2, if base 4 is thymine, what is base 4ʹ?</strong> A) guanine B) adenine C) cytosine D) thymine E) uracil
In Figure 8.2, if base 4 is thymine, what is base 4ʹ?

A) guanine
B) adenine
C) cytosine
D) thymine
E) uracil
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13
Table 8.2
Codon on mRNA and corresponding amino acid
 UUA  leucine  UAA  nonsense  GCA  alanine  AAU  asparagine  AAG  lysine UGC cysteine  GUU  valine UCG,UCU serine \begin{array} { | l | l | l | l | } \hline \text { UUA } & \text { leucine } & \text { UAA } & \text { nonsense } \\\hline \text { GCA } & \text { alanine } & \text { AAU } & \text { asparagine } \\\hline \text { AAG } & \text { lysine } & \mathrm { UGC } & \text { cysteine } \\\hline \text { GUU } & \text { valine } & \mathrm { UCG } , \mathrm { UCU }& \text { serine } \\\hline\end{array}

-Refer to Table 8.2 The anticodon for valine is

A) CUU.
B) GUU.
C) GTA.
D) CTT.
E) CAA.
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14
Figure 8.2
<strong>Figure 8.2   In Figure 8.2, base 2 (and ONLY the base) is covalently bound/attached to</strong> A) deoxyribose. B) phosphate. C) thymine. D) ribose. E) The answer cannot be determined based on the information provided.
In Figure 8.2, base 2 (and ONLY the base) is covalently bound/attached to

A) deoxyribose.
B) phosphate.
C) thymine.
D) ribose.
E) The answer cannot be determined based on the information provided.
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15
Figure 8.2
<strong>Figure 8.2   In Figure 8.2, if base 4 is thymine, what is base 11ʹ (remember the complimentary configuration of bases in DNA)?</strong> A) guanine B) thymine C) adenine D) uracil E) cytosine
In Figure 8.2, if base 4 is thymine, what is base 11ʹ (remember the complimentary configuration of bases in DNA)?

A) guanine
B) thymine
C) adenine
D) uracil
E) cytosine
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16
Table 8.2
Codon on mRNA and corresponding amino acid
 UUA  leucine  UAA  nonsense  GCA  alanine  AAU  asparagine  AAG  lysine UGC cysteine  GUU  valine UCG,UCU serine \begin{array} { | l | l | l | l | } \hline \text { UUA } & \text { leucine } & \text { UAA } & \text { nonsense } \\\hline \text { GCA } & \text { alanine } & \text { AAU } & \text { asparagine } \\\hline \text { AAG } & \text { lysine } & \mathrm { UGC } & \text { cysteine } \\\hline \text { GUU } & \text { valine } & \mathrm { UCG } , \mathrm { UCU }& \text { serine } \\\hline\end{array}

-Refer to Table 8.2. If the sequence of amino acids encoded by a strand of DNA is serine-alanine-lysine-leucine, what is the order of bases in the sense strand of DNA?

A) 3? AGACGTTTCAAT
B) 5? AGAGCTTTGAAT
C) 5? TGTGCTTTCTTA
D) 3? UGUGCAAAGUUA
E) 3? TCTCGTTTGTTA
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17
Which of the following statements regarding a bacterium that is R+ is FALSE?

A) It possesses a plasmid.
B) It is resistant to certain drugs and heavy metals.
C) R+ can be transferred to a cell of the same species.
D) R+ can be transferred to a different species.
E) It is F+.
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18
According to the operon model, for the synthesis of an inducible enzyme to occur, the

A) repressor must bind to the operator.
B) end-product must not be in excess.
C) substrate must bind to the enzyme.
D) repressor must not be synthesized.
E) substrate must bind to the repressor.
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19
Which of the following pairs is mismatched?

A) DNA gyrase - coils and twists DNA
B) transposase - insertion of DNA segments into DNA
C) DNA polymerase - makes a molecule of DNA from a DNA template
D) DNA ligase - joins segments of DNA
E) RNA polymerase - makes a molecule of RNA from an RNA template
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20
Figure 8.2
<strong>Figure 8.2   The damage caused by ultraviolet radiation is</strong> A) never repaired. B) repaired by DNA replication. C) repaired during translation. D) cut out and replaced. E) repaired during transcription.
The damage caused by ultraviolet radiation is

A) never repaired.
B) repaired by DNA replication.
C) repaired during translation.
D) cut out and replaced.
E) repaired during transcription.
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21
Conjugation differs from reproduction because conjugation

A) transcribes DNA to RNA.
B) replicates DNA.
C) transfers DNA vertically, to new cells.
D) copies RNA to make DNA.
E) transfers DNA horizontally, to nearby cells without those cells undergoing replication.
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22
The necessary ingredients for DNA synthesis can be mixed together in a test tube. The DNA polymerase is from Thermus aquaticus, and the template is from a human cell. The DNA synthesized would be most similar to

A) human DNA.
B) human RNA.
C) T. aquaticus RNA.
D) T. aquaticus DNA.
E) a mixture of human and T. aquaticus DNA.
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23
Assume the two E.coli strains shown below are allowed to conjugate. Hfr: pro+, arg+, his+, lys+, met+, ampicillin-sensitive F-: pro-, arg-, his-, lys-, met-, ampicillin-resistant
What supplements would you add to glucose minimal salts agar to select for a recombinant cell that is lys+, arg+, amp-resistant?

A) ampicillin, proline, histidine, lysine
B) lysine, arginine
C) ampicillin, proline, histidine, methionine
D) proline, histidine, methionine
E) ampicillin, lysine, arginine
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24
The mechanism by which the presence of glucose inhibits the lac operon is

A) DNA polymerase.
B) repression.
C) catabolite repression.
D) translation.
E) induction.
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25
Figure 8.4 <strong>Figure 8.4   In Figure 8.4, the antibiotic chloramphenicol binds the 50S large subunit of a ribosome as shown (the light gray area is the large subunit, while the black shape is the drug). From this information you can conclude that chloramphenicol</strong> A) prevents translation in eukaryotes. B) prevents translation in prokaryotes. C) prevents transcription in eukaryotes. D) prevents mRNA-ribosome binding. E) prevents transcription in prokaryotes. In Figure 8.4, the antibiotic chloramphenicol binds the 50S large subunit of a ribosome as shown (the light gray area is the large subunit, while the black shape is the drug). From this information you can conclude that chloramphenicol

A) prevents translation in eukaryotes.
B) prevents translation in prokaryotes.
C) prevents transcription in eukaryotes.
D) prevents mRNA-ribosome binding.
E) prevents transcription in prokaryotes.
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26
The cancer gene ras produces mRNA containing an extra exon that includes a number of UAA codons. Cancer cells produce ras mRNA missing this exon. This mistake most likely is due to a mistake by

A) photolyases.
B) a chemical mutagen.
C) DNA polymerase.
D) UV radiation.
E) snRNPs.
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27
Figure 8.3 - Metabolic Pathway
 Gene a Gene b Enzyme A  Enzyme B  Compound A  Compound B  Compound C \begin{array} { c c } &\text { Gene } a & \text { Gene } b \\&\downarrow & \downarrow \\&\text { Enzyme A } & \text { Enzyme B } \\&\downarrow & \downarrow \\\text { Compound A } & \rightarrow &\text { Compound B } \rightarrow \text { Compound C }\end{array}

-In Figure 8.3, if compound C reacts with the allosteric site of enzyme A, this would exemplify

A) competitive inhibition.
B) transcription.
C) feedback inhibition.
D) a mutation.
E) repression.
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28
Figure 8.3 - Metabolic Pathway
 Gene a Gene b Enzyme A  Enzyme B  Compound A  Compound B  Compound C \begin{array} { c c } &\text { Gene } a & \text { Gene } b \\&\downarrow & \downarrow \\&\text { Enzyme A } & \text { Enzyme B } \\&\downarrow & \downarrow \\\text { Compound A } & \rightarrow &\text { Compound B } \rightarrow \text { Compound C }\end{array}

-In Figure 8.3, if enzyme A is an inducible enzyme,

A) compound B would bind to enzyme A directly.
B) compound C would react with gene a directly.
C) compound C would bind to the repressor for Gene a.
D) compound A would react with enzyme B directly.
E) compound A would bind to the repressor for Gene a.
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29
The miRNAs in a cell

A) are responsible for inducing operons.
B) are a part of the eukaryotic ribosome.
C) allow different cells to produce different proteins.
D) are a part of the prokaryotic ribosome.
E) are found in prokaryotic cells.
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30
Figure 8.3 - Metabolic Pathway
 Gene a Gene b Enzyme A  Enzyme B  Compound A  Compound B  Compound C \begin{array} { c c } &\text { Gene } a & \text { Gene } b \\&\downarrow & \downarrow \\&\text { Enzyme A } & \text { Enzyme B } \\&\downarrow & \downarrow \\\text { Compound A } & \rightarrow &\text { Compound B } \rightarrow \text { Compound C }\end{array}

-In Figure 8.3, if enzyme A is a repressible enzyme, compound C would

A) bind directly to gene a.
B) bind to the corepressor for Gene a.
C) bind to RNA polymerase.
D) bind to Enzyme A.
E) always be in excess.
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31
Open-reading frames are segments of DNA in which both start and stop codons are found.
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32
Figure 8.5 <strong>Figure 8.5   In Figure 8.5, which model of the lac operon correctly shows RNA polymerase, lactose, and repressor protein when the structural genes are being transcribed?</strong> A) a B) b C) c D) d E) e In Figure 8.5, which model of the lac operon correctly shows RNA polymerase, lactose, and repressor protein when the structural genes are being transcribed?

A) a
B) b
C) c
D) d
E) e
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33
Table 8.3 Amino Acids Encoded by the Human p53 Gene
<strong>Table 8.3 Amino Acids Encoded by the Human p53 Gene   Based on the information in Table 8.3, prostate cancer is probably the result of which kind of mutation?</strong> A) frameshift B) nonsense C) analog D) missense E) None of the answers is correct. Based on the information in Table 8.3, prostate cancer is probably the result of which kind of mutation?

A) frameshift
B) nonsense
C) analog
D) missense
E) None of the answers is correct.
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34
Repair of damaged DNA, in some instances and mechanisms, might be viewed as a race between an endonuclease and

A) methylase.
B) primase.
C) DNA ligase.
D) DNA polymerase.
E) helicase.
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35
Recombination will always alter a cellʹs genotype.
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36
An enzyme that catalyzes the cutting and resealing of DNA, and is translated from insertion sequences, is

A) RNA polymerase.
B) DNA ligase.
C) DNA helicase.
D) transposase.
E) DNA polymerase.
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37
An enzyme that copies DNA to make a molecule of RNA is

A) RNA polymerase.
B) DNA ligase.
C) DNA helicase.
D) transposase.
E) DNA polymerase.
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38
If you knew the sequence of nucleotides within a gene, which one of the following could you determine with the most accuracy?

A) the tertiary structure of the protein
B) the primary structure of the protein
C) the quaternary structure of the protein
D) the secondary structure of the protein
E) The answer cannot be determined based on the information provided.
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39
An enzyme that makes covalent bonds between the sugar of one nucleotide and the phosphate groups in another nucleotide in DNA is

A) RNA polymerase.
B) DNA ligase
C) DNA helicase.
D) transposase.
E) DNA polymerase.
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40
Protein synthesis in eukaryotes is similar to the process in prokaryotes in that both eukaryotes and prokaryotes

A) use methionine as the ʺstartʺ amino acid.
B) require snRNPS.
C) have introns.
D) use codons to determine polypeptide sequences.
E) have exons.
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41
Bacteria typically contain multiple chromosomes.
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42
Transposition (insertion of a transposon into a DNA sequence) results in the formation of base substitution mutations in a cellʹs DNA.
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43
Cell-to-cell contact is required for transduction to occur.
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44
In the Ames test, any colonies that form on the control should be the result of spontaneous mutations.
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45
Some cells may contain multiple genomes.
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46
Mutations that are harmful to cells occur more frequently than those that benefit cells.
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47
Both base substitution and frameshift mutations can result in the formation of premature stop codons.
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48
The miRNAs in a cell inhibit protein synthesis by forming complementary bonds with rRNA.
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