Deck 11: Introduction to Trigonometry

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Question
  For the right triangle   with right   , prove that   .<div style=padding-top: 35px>
For the right triangle   For the right triangle   with right   , prove that   .<div style=padding-top: 35px> with right   For the right triangle   with right   , prove that   .<div style=padding-top: 35px> , prove that   For the right triangle   with right   , prove that   .<div style=padding-top: 35px> .
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Question
  For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning.<div style=padding-top: 35px>
For the right triangle   For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning.<div style=padding-top: 35px> with right   For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning.<div style=padding-top: 35px> , prove that   For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning.<div style=padding-top: 35px> . Note that   For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning.<div style=padding-top: 35px> and   For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning.<div style=padding-top: 35px> are the same and that   For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning.<div style=padding-top: 35px> as shown in   For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning.<div style=padding-top: 35px> ; also,   For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning.<div style=padding-top: 35px> and   For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning.<div style=padding-top: 35px> have the
same meaning.
Question
  Use the drawings provided to prove the following theorem. The area of an acute triangle equals one-half the product of the lengths of two sides of a triangle and the sine of the included angle. Given: Acute   Prove:  <div style=padding-top: 35px>
Use the drawings provided to prove the following theorem.
"The area of an acute triangle equals one-half the product of the lengths of two sides of a triangle and the sine of the included angle."
Given: Acute   Use the drawings provided to prove the following theorem. The area of an acute triangle equals one-half the product of the lengths of two sides of a triangle and the sine of the included angle. Given: Acute   Prove:  <div style=padding-top: 35px> Prove:   Use the drawings provided to prove the following theorem. The area of an acute triangle equals one-half the product of the lengths of two sides of a triangle and the sine of the included angle. Given: Acute   Prove:  <div style=padding-top: 35px>
Question
  For the right triangle   with right   , prove that   .<div style=padding-top: 35px>
For the right triangle   For the right triangle   with right   , prove that   .<div style=padding-top: 35px> with right   For the right triangle   with right   , prove that   .<div style=padding-top: 35px> , prove that   For the right triangle   with right   , prove that   .<div style=padding-top: 35px> .
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Deck 11: Introduction to Trigonometry
1
  For the right triangle   with right   , prove that   .
For the right triangle   For the right triangle   with right   , prove that   . with right   For the right triangle   with right   , prove that   . , prove that   For the right triangle   with right   , prove that   . .
By definition, By definition,   ,   , and   . Then   , which can also be written   . Then   . Thus,   . , By definition,   ,   , and   . Then   , which can also be written   . Then   . Thus,   . , and By definition,   ,   , and   . Then   , which can also be written   . Then   . Thus,   . . Then By definition,   ,   , and   . Then   , which can also be written   . Then   . Thus,   . , which can also be written By definition,   ,   , and   . Then   , which can also be written   . Then   . Thus,   . . Then By definition,   ,   , and   . Then   , which can also be written   . Then   . Thus,   . . Thus, By definition,   ,   , and   . Then   , which can also be written   . Then   . Thus,   . .
2
  For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning.
For the right triangle   For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning. with right   For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning. , prove that   For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning. . Note that   For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning. and   For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning. are the same and that   For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning. as shown in   For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning. ; also,   For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning. and   For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning. have the
same meaning.
With With   and   , we see that   or   . Then   . By using the Pythagorean Theorem, we know that   . It follows that   , so   . and With   and   , we see that   or   . Then   . By using the Pythagorean Theorem, we know that   . It follows that   , so   . , we see that With   and   , we see that   or   . Then   . By using the Pythagorean Theorem, we know that   . It follows that   , so   . or With   and   , we see that   or   . Then   . By using the Pythagorean Theorem, we know that   . It follows that   , so   . .
Then With   and   , we see that   or   . Then   . By using the Pythagorean Theorem, we know that   . It follows that   , so   . . By using the Pythagorean Theorem, we know that With   and   , we see that   or   . Then   . By using the Pythagorean Theorem, we know that   . It follows that   , so   . . It follows that With   and   , we see that   or   . Then   . By using the Pythagorean Theorem, we know that   . It follows that   , so   . , so With   and   , we see that   or   . Then   . By using the Pythagorean Theorem, we know that   . It follows that   , so   . .
3
  Use the drawings provided to prove the following theorem. The area of an acute triangle equals one-half the product of the lengths of two sides of a triangle and the sine of the included angle. Given: Acute   Prove:
Use the drawings provided to prove the following theorem.
"The area of an acute triangle equals one-half the product of the lengths of two sides of a triangle and the sine of the included angle."
Given: Acute   Use the drawings provided to prove the following theorem. The area of an acute triangle equals one-half the product of the lengths of two sides of a triangle and the sine of the included angle. Given: Acute   Prove:  Prove:   Use the drawings provided to prove the following theorem. The area of an acute triangle equals one-half the product of the lengths of two sides of a triangle and the sine of the included angle. Given: Acute   Prove:
The area of The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . is given by The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . . Considering the auxiliary altitude The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . from vertex B
to side The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . , we see that The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . is a right angle. Then The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . in right triangle The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . .
From The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . , it follows that The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . . By substitution, the area formula The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . becomes The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . so we have The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . .
4
  For the right triangle   with right   , prove that   .
For the right triangle   For the right triangle   with right   , prove that   . with right   For the right triangle   with right   , prove that   . , prove that   For the right triangle   with right   , prove that   . .
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