Deck 14: Additional Tests for Nominal Data: Chi-Squared Tests

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Question
Which of the following should be used if we want to conduct a two-tail test of a population proportion?

A)z-test of a population proportion.
B)Chi-squared test of a binomial experiment since z2=χ2z ^ { 2 } = \chi ^ { 2 } .
C)the chi-squared test of a contingency table.
D)z-test of a population proportion and Chi-squared test of a binomial experiment since z2=χ2z ^ { 2 } = \chi ^ { 2 } .
E)Chi-squared test of a binomial experiment since z2=χ2z ^ { 2 } = \chi ^ { 2 } and the chi-squared test of a contingency table.
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Question
If each element in a population is classified into one and only one of several categories, the population is a:

A)normal population.
B)multinomial population.
C)chi-squared population.
D)binomial population.
Question
Which of the following best describes the degrees of freedom needed in a Chi-squared test for normality?

A)Number of intervals used to test the hypothesis minus 1.
B)Number of parameters estimated minus 1.
C)Number of intervals used to test the hypothesis minus the number of parameters estimated minus 1.
D)Number of intervals used to test the hypothesis minus the number of parameters estimated minus 2.
Question
The vice-chancellor of a university collected data from students concerning the building of a new library, and classified the responses into different categories (strongly agree, agree, undecided, disagree, strongly disagree) and according to whether the student was male or female. Which of the following tests should be used to test whether responses and gender are independent?

A)Chi-squared test for goodness-of-fit.
B)Chi-squared test for normality.
C)Chi-square test of a multinomial experiment.
D)Chi-squared test of a contingency table.
Question
Which of the following may be used to determine whether data were drawn a particular distribution?

A)Chi-squared goodness-of-fit test.
B)Chi-squared test of a contingency table.
C)Z test.
D)All of these choices are correct.
Question
To determine the critical values in the chi-squared distribution table, the process requires which of the following information?

A)Degrees of freedom.
B)Probability of Type I error.
C)Probability of Type II error.
D)Degrees of freedom and Probability of Type I error.
Question
Which of the following best describes the number of degrees of freedom used in a Chi-squared test of independence if there is a contingency table with 5 rows and 3 columns?

A)7
B)8
C)15
D)10
Question
Which of the following are the degrees of freedom used in a Chi-squared test of independence between gender and mode of transport to university, if the mode of transport choices are public transport, car, bicycle or other.

A)8
B)5
C)4
D)3
Question
Of the values for a chi-squared test statistic listed below, which one is likely to lead to rejection of the null hypothesis in a goodness-of-fit test?

A)0.
B)1.
C)2.
D)40.
Question
Which of the following best describes the approach taken if the expected frequency eie _ { i } for any cell i is less than 5?

A)We must choose another sample of five or more observations.
B)We should use the normal distribution instead of the chi-squared distribution.
C)We should combine the cells such that each observed frequency fif _ { i } is 5 or more.
D)We must increase the number of degrees of freedom for the test by 5.
Question
Which of the following uses the Chi-square distribution?

A)Test of independence between two categorical variables.
B)Test of a multinomial experiment with one categorical variable.
C)Test about a single population variance with one numerical variable.
D)All of these choices are correct.
Question
A chi-squared test of a contingency table with 4 rows and 4 columns shows that the value of the test statistic is 23. Which of the following best describes the p-value for this test?

A)p-value < 0.010
B)p-value < 0.005
C)p-value > 0.10
D)0.005 < p-value < 0.01
Question
Which of the following uses a contingency table?

A)Chi-squared test of independence of two numerical variables in a population.
B)Chi-squared test of independence of two nominal variables in a sample.
C)Chi-squared test of independence of two numerical variables in a sample.
D)Chi-squared test of independence of two nominal variables in a population.
Question
Which statistical technique is appropriate when we describe a single population of nominal data with exactly two categories?

A)z-test of a population proportion.
B)Chi-squared test of a multinomial experiment.
C)Chi-squared test of a contingency table.
D)z-test of a population proportion and Chi-squared test of a multinomial experiment.
E)Chi-squared test of a multinomial experiment and Chi-squared test of a contingency table.
Question
Which of the following would be used to analyse the relationship between two categorical variables?

A)Z-test of a population proportion.
B)Chi-squared test of a binomial experiment since z2=χ2z ^ { 2 } = \chi ^ { 2 } .
C)A Chi-squared test of a binomial experiment or a Chi-squared test of a contingency table.
D)Chi-squared test of a contingency table.
E)None of these choices are correct.
Question
Which of the following best describes a Chi-squared goodness-of-fit test?

A)Two tailed test
B)Left tailed test
C)Right tailed test
D)All of these choices are correct.
Question
Which statistical technique is appropriate when we wish to analyse the relationship between two nominal variables with two or more categories?

A)Chi-squared test of a multinomial experiment.
B)Chi-squared test of a contingency table.
C)t-test of the difference between two means.
D)Z-test of the difference of two means
E)F-test of analysis of variance
Question
Which of the following may be used for hypothesis tests of nominal (categorical) data?

A)Chi-squared test of a multinomial experiment.
B)Z test of a population proportion or a Z test for the difference between two population proportions.
C)Chi-squared test of a contingency table.
D)All of these choices are correct.
Question
Which of the following is the correct decision in a goodness-of-fit test, if the calculated value of the test statistic is 20.08 and there are 10 categories, testing at 1% level of significance?

A)We reject Ho because p-value < 0.01.
B)We do not reject Ho because p-value < 0.01.
C)We reject Ho because 0.01 < p-value < 0.025.
D)We do not reject Ho because 0.01 < p-value < 0.025.
Question
In a goodness-of-fit test, suppose that a sample showed that the observed frequency fif _ { i } and expected frequency eie _ { i } were equal for each cell i. Which of the following best describes the decision for the hypothesis test?

A)Reject Ho at ? of 0.05 but do not reject Ho at ? of 0.025.
B)Reject Ho at any level of ?.
C)Do not reject Ho at any level of ?.
D)Do not reject Ho at ? of 0.05 but reject Ho at ? of 0.025.
Question
In chi-squared tests, the conventional and conservative rule - known as the rule of five - is to require that the:

A)expected frequency for each cell be at least 5.
B)number of degrees of freedom for the test be at least 5.
C)each expected and observed frequency be at least 5.
D)difference between the observed and expected frequency for each cell be at least 5.
Question
Which of the following best describes the sampling distribution of the test statistic for a goodness-of-fit test with k categories?

A)Student t-distribution with k - 1 degrees of freedom.
B)Normal distribution.
C)Chi-squared distribution with k - 1 degrees of freedom.
D)Approximately Chi-squared distribution with k - 1 degrees of freedom.
Question
Which statistical technique is appropriate when we describe a single population of nominal data with two or more categories?

A)Z-test of the difference between two proportions.
B)Chi-squared test of a multinomial experiment.
C)Chi-squared test of a contingency table.
D)Z test for one proportion.
E)None of these choices are correct
Question
In a goodness-of-fit test, the null hypothesis states that the data came from a normally distributed population. The researcher estimated the population mean and population standard deviation from a sample of 500 observations. In addition, the researcher used 6 standardised intervals to test for normality. Using a 5% level of significance, the critical value for this test is:

A)11.1433.
B)9.3484.
C)7.8147.
D)9.4877.
Question
Which statistical technique is appropriate when we compare two or more populations of nominal data with two or more categories?

A)The z-test of the difference between two proportions.
B)The chi-squared test of a multinomial experiment.
C)The chi-squared test of a contingency table.
D)The z-test of the difference between two proportions and the chi-squared test of a multinomial experiment.
E)The chi-squared test of a multinomial experiment and the chi-squared test of a contingency table.
Question
In a chi-squared test of a contingency table, the value of the test statistic was χ2=12.678\chi ^ { 2 } = 12.678 , the significance level was ? = 0.05 and the degrees of freedom was 6. Thus:

A)we fail to reject the null hypothesis at ? = 0.05.
B)we reject the null hypothesis at ? = 0.05.
C)we Do not have enough evidence to accept or reject the null hypothesis at ? = 0.05.
D)we should increase the level of significance in order to reject the null hypothesis.
Question
Which of the following best describes the rejection region in a chi-squared test of independence?

A)χ2 > χ2α, (r - 2)(c −2)
B)χ2 > χ2 1−α , (r - 1)(c −1)
C)χ2 > χ2α, (r - 1)(c −1)
D)χ2 < χ2α, (r - 1)(c −1)
E)None of these choices are correct.
Question
A left-tailed area in the chi-squared distribution equals 0.975. For df = 11, the table value equals:

A)20.4831.
B)19.6751.
C)3.81575.
D)21.9200.
Question
The null hypothesis states that the sample data came from a normally distributed population. The researcher calculates the sample mean and the sample standard deviation from the data. The data arrangement consisted of seven categories. Using a 0.05 significance level, the appropriate critical value for this chi-squared test for normality is 11.0705.
Question
A chi-squared test for independence with 6 degrees of freedom results in a test statistic χ2=13.58\chi ^ { 2 } = 13.58 . Using the x2x ^ { 2 } tables, the most accurate statement that can be made about the p-value for this test is that:

A)p-value > 0.10.
B)p-value > 0.05.
C)0.05 < p-value < 0.10.
D)0.025 < p-value < 0.05.
Question
Which statistical technique is appropriate when we compare two populations of nominal data with exactly two categories?

A)The z-test of a population proportion.
B)The z-test of the difference between two proportions.
C)The chi-squared test of a contingency table.
D)The z-test of a population proportion and the z-test of the difference between two proportions.
E)The z-test of the difference between two proportions and the chi-squared test of a contingency table.
Question
The chi-squared test of a contingency table is based upon:

A)two nominal variables.
B)two numerical variables.
C)three or more nominal variables.
D)three or more numerical variables.
Question
The number of degrees of freedom in a test of a contingency table with 7 rows and 5 columns is:

A)24.
B)35.
C)30.
D)28.
Question
A test for independence is applied to a contingency table with 5 rows and 2 columns for two nominal variables. The number of degrees of freedom for this chi-squared test must be 4.
Question
Which of the following tests do not use the Chi-squared distribution?

A)Test of a contingency table.
B)Goodness-of-fit test.
C)Test for the difference between two population means.
D)All of these choices are correct.
Question
Which of the following is not a characteristic of a multinomial experiment?  

A)The experiment consists of a fixed number, n, of trials.
B)The outcome of each trial can be classified into one of two categories called success and failure.
C)The probability pip _ { i } that the outcome will fall into cell i remain constant for each trial.
D)Each trial of the experiment is independent of the other trials.
Question
Which of the following statements is not correct?

A)The chi-squared test of independence is a one-sample test.
B)Both variables in the chi-squared test of independence are nominal variables.
C)The chi-squared goodness-of-fit test involves two categorical variables.
D)The chi-squared distribution is skewed to the right.
Question
In a chi-squared goodness-of-fit test, if the expected frequencies eie _ { i } and the observed frequencies fif _ { i } were quite different, which of the following is the best conclusion?

A)Null hypothesis is false, and reject Ho.
B)Null hypothesis is true, and do not reject Ho.
C)Alternative hypothesis is false, reject HA.
D)Chi-squared distribution is invalid, use t-distribution instead.
Question
Which of the following statements is true for the chi-squared tests?

A)Testing for equal proportions is identical to testing for goodness-of-fit.
B)The number of degrees of freedom in a test of a contingency table with r rows and c columns is (r - 1)(c - 1).
C)The number of degrees of freedom in a goodness-of-fit test with k categories is k - 1.
D)All of these choices are correct.
Question
Which of the following statements is not correct?

A)The chi-squared distribution is symmetrical.
B)The chi-squared distribution is skewed to the right.
C)All values of the chi-squared distribution are positive.
D)The critical region for a goodness-of-fit test with k categories is <strong>Which of the following statements is not correct?</strong> A)The chi-squared distribution is symmetrical. B)The chi-squared distribution is skewed to the right. C)All values of the chi-squared distribution are positive. D)The critical region for a goodness-of-fit test with k categories is   . <div style=padding-top: 35px> .
Question
A chi-squared goodness-of-fit test can be conducted either as a two-tail test or as a one-tail test.
Question
A test for independence is applied to a contingency table with 4 rows and 4 columns for two nominal variables. The number of degrees of freedom for this test will be 9.
Question
A chi-squared test for independence with 6 degrees of freedom results in a test statistic of 13.25. Using the chi-squared table, the most accurate statement that can be made about the p-value for this test is that 0.025 < p-value < 0.05.
Question
For a chi-squared distributed random variable with 10 degrees of freedom and a level of significance of 0.025, the chi-squared value from the table is 20.5. The computed value of the test statistic is 16.857. The decision is to do not reject Ho.
Question
One type of Chi-squared goodness of fit test is a Chi-squared test for normality.
Question
A left-tailed area in the chi-squared distribution equals 0.10. For 5 degrees of freedom, the table value equals 9.23635.
Question
Whenever the expected frequency of a cell is less than 5, one remedy for this condition is to increase the size of the sample.
Question
Whenever the expected frequency of a cell is less than 5, we must increase the significance level.
Question
In a chi-squared test of independence, the value of the test statistic was x2=x ^ { 2 } = 15.652, and the critical value at α=0.025\alpha = 0.025 was 11.1433. Thus we must reject the null hypothesis at α=0.025\alpha = 0.025 .
Question
In a goodness-of-fit test, the null hypothesis states that the data came from a normally distributed population. The researcher estimated the population mean and population standard deviation from a sample of 100 observations. In addition, the researcher used 6 standardised intervals to test for normality. Using a 2.5% level of significance, the critical value for this test is 9.3484.
Question
For a chi-squared distributed random variable with 12 degrees of freedom and a level of significance of 0.05, the chi-squared value from the table is 21.0261. The computed value of the test statistics is 25.1687. This will lead us to reject the null hypothesis.
Question
In a goodness-of-fit test, the null hypothesis states that the data came from a normally distributed population. The researcher estimated the population mean and population standard deviation from a sample of 200 observations. In addition, the researcher used 5 standardised intervals to test for normality. Using a 10% level of significance, the critical value for this test is 4.60517.
Question
A left-tailed area in the chi-squared distribution equals 0.90. For 10 degrees of freedom, the table value equals 15.9871.
Question
A Chi-squared test can be used to test the equality of two population means.
Question
Whenever the expected frequency of a cell is less than 5, one possible remedy for this condition is to combine it with one or more other cells.
Question
The middle 0.95 portion of the chi-squared distribution with 9 degrees of freedom has table values of 3.32511 and 16.9190, respectively.
Question
A right-tailed area in the chi-squared distribution equals 0.01. For 4 degrees of freedom, the table value equals 13.2767.
Question
A chi-squared test for independence with 10 degrees of freedom results in a test statistic of 17.894. Using the chi-squared table, the most accurate statement that can be made about the p-value for this test is that 0.05 < p-value < 0.10.
Question
The chi-squared test of independence is a Chi-squared test of a contingency table.
Question
In chi-squared tests, the conventional and conservative rule - known as the rule of five - is to require that difference between the observed and expected frequency for each cell be at least 5.
Question
If we want to test for differences between two populations of nominal data with exactly two categories, we can employ either the z-test of p1p2p _ { 1 } - p _ { 2 } , or the chi-squared test of a contingency table. (Squaring the value of the z-statistic yields the value of the x2x ^ { 2 } -statistic.)
Question
A study of education levels of 500 voters and their political party affiliations in a particular state in Australia showed the following results. A study of education levels of 500 voters and their political party affiliations in a particular state in Australia showed the following results.   Is education level independent of political affiliation? Test at the 5% level of significance.<div style=padding-top: 35px> Is education level independent of political affiliation? Test at the 5% level of significance.
Question
Five brands of orange juice are displayed side by side in several supermarkets in a large city. It was noted that in one day, 180 customers purchased orange juice. Of these, 30 picked Brand A, 40 picked Brand B, 25 picked Brand C, 35 picked Brand D, and 50 picked brand
E.In this city, can you conclude at the 5% significance level that there is a preferred brand of orange juice?
Question
The number of degrees of freedom for a contingency table with r rows and c columns is (r 1)(c 1), provided that both r and c follow the rule of five.
Question
The chi-squared goodness-of-fit test is usually used as a test of multinomial parameters, but it can also be used to determine whether data were drawn from any distribution.
Question
The number of degrees of freedom associated with the chi-squared test for normality is the number of intervals used minus the number of parameters estimated from the data.
Question
Last year, Brand A mobile android phones had 45% of the market, Brand B had 35% and Brand C had 20%. This year the makers of Brand C launched a heavy advertising campaign. A random sample of mobile phone stores shows that of the 10,000 android mobile phones sold, 4350 were Brand A, 3450 were Brand B, and 2200 were Brand
C.Has the market changed? Test at Last year, Brand A mobile android phones had 45% of the market, Brand B had 35% and Brand C had 20%. This year the makers of Brand C launched a heavy advertising campaign. A random sample of mobile phone stores shows that of the 10,000 android mobile phones sold, 4350 were Brand A, 3450 were Brand B, and 2200 were Brand C.Has the market changed? Test at   0.05.<div style=padding-top: 35px> 0.05.
Question
An Australian firm has been accused of engaging in prejudicial hiring practices against women who have young children, where a young child is defined to be a child less than 12 years of age. According to the most recent census, the percentages of men, women without young children and women with young children in a certain community are 72%, 10% and 18%, respectively. A random sample of 200 employees of the firm revealed that 165 were men, 14 were women without young children and 21 were women with young children. Do the data provide sufficient evidence to conclude at the 1% level of significance that the firm has been engaged in prejudicial hiring practices?
Question
When doing a Chi-squared goodness of fit test, we use Ho: The data are not normally distributed.
Question
The personnel manager of a consumer product company asked a random sample of employees how they felt about the work they were doing. The following table gives a breakdown of their responses by gender. The personnel manager of a consumer product company asked a random sample of employees how they felt about the work they were doing. The following table gives a breakdown of their responses by gender.   Do the data provide sufficient evidence to conclude that the level of job satisfaction is related to gender? Use   0.10.<div style=padding-top: 35px> Do the data provide sufficient evidence to conclude that the level of job satisfaction is related to gender? Use The personnel manager of a consumer product company asked a random sample of employees how they felt about the work they were doing. The following table gives a breakdown of their responses by gender.   Do the data provide sufficient evidence to conclude that the level of job satisfaction is related to gender? Use   0.10.<div style=padding-top: 35px> 0.10.
Question
Like that of the Student t-distribution, the shape of the chi-squared distribution depends on its number of degrees of freedom.
Question
The chi-squared test of a contingency table is used to determine if there is enough evidence to infer that two nominal variables are related, and to infer that differences exist among two or more populations of nominal variables.
Question
The following data are believed to have come from a normal probability distribution. The following data are believed to have come from a normal probability distribution.   The mean of this sample equals 26.80, and the standard deviation equals 6.378. Use the goodness-of-fit test at the 5% significance level to test this claim.<div style=padding-top: 35px> The mean of this sample equals 26.80, and the standard deviation equals 6.378. Use the goodness-of-fit test at the 5% significance level to test this claim.
Question
The area to the right of a chi-squared value is 0.01. For 8 degrees of freedom, the table value is 20.0902.
Question
A sport preference poll showed the following data for men and women: A sport preference poll showed the following data for men and women:   Using the 5% level of significance, test to determine whether sport preferences depend on gender.<div style=padding-top: 35px> Using the 5% level of significance, test to determine whether sport preferences depend on gender.
Question
At present in Australia, voting in a Federal election is compulsory for all citizens 18 years or over.
There has been some discussion to have this changed from being compulsory to voluntary.
A study was done to investigate whether there was a relationship between gender and attitude towards changing voting in Australia from compulsory to voluntary. Participants were asked "Do you agree to change voting in Australian Federal Elections from compulsory to voluntary? A table of results from the sample is given below.
At the 1% level of significance, is there a relationship between gender and attitude towards voluntary voting? At present in Australia, voting in a Federal election is compulsory for all citizens 18 years or over. There has been some discussion to have this changed from being compulsory to voluntary. A study was done to investigate whether there was a relationship between gender and attitude towards changing voting in Australia from compulsory to voluntary. Participants were asked Do you agree to change voting in Australian Federal Elections from compulsory to voluntary? A table of results from the sample is given below. At the 1% level of significance, is there a relationship between gender and attitude towards voluntary voting?  <div style=padding-top: 35px>
Question
If we want to perform a one-tail test for differences between two populations of nominal data with exactly two categories, we must employ the z-test of p1p2p _ { 1 } - p _ { 2 } .
Question
A multinomial experiment, where the outcome of each trial can be classified into one of two categories, is identical to the binomial experiment.
Question
If we want to perform a two-tail test for differences between two populations of nominal data with exactly two categories, we can employ either the z-test of p1p2p _ { 1 } - p _ { 2 } , or the chi-squared test of a contingency table. (Squaring the value of the z-statistic yields the value of the x2x ^ { 2 } -statistic.)
Question
The rule of five is used to ensure that the discrete distribution of the test statistic can be approximated by the continuous Chi-squared distribution.
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Deck 14: Additional Tests for Nominal Data: Chi-Squared Tests
1
Which of the following should be used if we want to conduct a two-tail test of a population proportion?

A)z-test of a population proportion.
B)Chi-squared test of a binomial experiment since z2=χ2z ^ { 2 } = \chi ^ { 2 } .
C)the chi-squared test of a contingency table.
D)z-test of a population proportion and Chi-squared test of a binomial experiment since z2=χ2z ^ { 2 } = \chi ^ { 2 } .
E)Chi-squared test of a binomial experiment since z2=χ2z ^ { 2 } = \chi ^ { 2 } and the chi-squared test of a contingency table.
z-test of a population proportion and Chi-squared test of a binomial experiment since z2=χ2z ^ { 2 } = \chi ^ { 2 } .
2
If each element in a population is classified into one and only one of several categories, the population is a:

A)normal population.
B)multinomial population.
C)chi-squared population.
D)binomial population.
multinomial population.
3
Which of the following best describes the degrees of freedom needed in a Chi-squared test for normality?

A)Number of intervals used to test the hypothesis minus 1.
B)Number of parameters estimated minus 1.
C)Number of intervals used to test the hypothesis minus the number of parameters estimated minus 1.
D)Number of intervals used to test the hypothesis minus the number of parameters estimated minus 2.
Number of intervals used to test the hypothesis minus the number of parameters estimated minus 1.
4
The vice-chancellor of a university collected data from students concerning the building of a new library, and classified the responses into different categories (strongly agree, agree, undecided, disagree, strongly disagree) and according to whether the student was male or female. Which of the following tests should be used to test whether responses and gender are independent?

A)Chi-squared test for goodness-of-fit.
B)Chi-squared test for normality.
C)Chi-square test of a multinomial experiment.
D)Chi-squared test of a contingency table.
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5
Which of the following may be used to determine whether data were drawn a particular distribution?

A)Chi-squared goodness-of-fit test.
B)Chi-squared test of a contingency table.
C)Z test.
D)All of these choices are correct.
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6
To determine the critical values in the chi-squared distribution table, the process requires which of the following information?

A)Degrees of freedom.
B)Probability of Type I error.
C)Probability of Type II error.
D)Degrees of freedom and Probability of Type I error.
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7
Which of the following best describes the number of degrees of freedom used in a Chi-squared test of independence if there is a contingency table with 5 rows and 3 columns?

A)7
B)8
C)15
D)10
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8
Which of the following are the degrees of freedom used in a Chi-squared test of independence between gender and mode of transport to university, if the mode of transport choices are public transport, car, bicycle or other.

A)8
B)5
C)4
D)3
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9
Of the values for a chi-squared test statistic listed below, which one is likely to lead to rejection of the null hypothesis in a goodness-of-fit test?

A)0.
B)1.
C)2.
D)40.
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10
Which of the following best describes the approach taken if the expected frequency eie _ { i } for any cell i is less than 5?

A)We must choose another sample of five or more observations.
B)We should use the normal distribution instead of the chi-squared distribution.
C)We should combine the cells such that each observed frequency fif _ { i } is 5 or more.
D)We must increase the number of degrees of freedom for the test by 5.
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11
Which of the following uses the Chi-square distribution?

A)Test of independence between two categorical variables.
B)Test of a multinomial experiment with one categorical variable.
C)Test about a single population variance with one numerical variable.
D)All of these choices are correct.
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12
A chi-squared test of a contingency table with 4 rows and 4 columns shows that the value of the test statistic is 23. Which of the following best describes the p-value for this test?

A)p-value < 0.010
B)p-value < 0.005
C)p-value > 0.10
D)0.005 < p-value < 0.01
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13
Which of the following uses a contingency table?

A)Chi-squared test of independence of two numerical variables in a population.
B)Chi-squared test of independence of two nominal variables in a sample.
C)Chi-squared test of independence of two numerical variables in a sample.
D)Chi-squared test of independence of two nominal variables in a population.
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14
Which statistical technique is appropriate when we describe a single population of nominal data with exactly two categories?

A)z-test of a population proportion.
B)Chi-squared test of a multinomial experiment.
C)Chi-squared test of a contingency table.
D)z-test of a population proportion and Chi-squared test of a multinomial experiment.
E)Chi-squared test of a multinomial experiment and Chi-squared test of a contingency table.
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15
Which of the following would be used to analyse the relationship between two categorical variables?

A)Z-test of a population proportion.
B)Chi-squared test of a binomial experiment since z2=χ2z ^ { 2 } = \chi ^ { 2 } .
C)A Chi-squared test of a binomial experiment or a Chi-squared test of a contingency table.
D)Chi-squared test of a contingency table.
E)None of these choices are correct.
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16
Which of the following best describes a Chi-squared goodness-of-fit test?

A)Two tailed test
B)Left tailed test
C)Right tailed test
D)All of these choices are correct.
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17
Which statistical technique is appropriate when we wish to analyse the relationship between two nominal variables with two or more categories?

A)Chi-squared test of a multinomial experiment.
B)Chi-squared test of a contingency table.
C)t-test of the difference between two means.
D)Z-test of the difference of two means
E)F-test of analysis of variance
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18
Which of the following may be used for hypothesis tests of nominal (categorical) data?

A)Chi-squared test of a multinomial experiment.
B)Z test of a population proportion or a Z test for the difference between two population proportions.
C)Chi-squared test of a contingency table.
D)All of these choices are correct.
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19
Which of the following is the correct decision in a goodness-of-fit test, if the calculated value of the test statistic is 20.08 and there are 10 categories, testing at 1% level of significance?

A)We reject Ho because p-value < 0.01.
B)We do not reject Ho because p-value < 0.01.
C)We reject Ho because 0.01 < p-value < 0.025.
D)We do not reject Ho because 0.01 < p-value < 0.025.
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20
In a goodness-of-fit test, suppose that a sample showed that the observed frequency fif _ { i } and expected frequency eie _ { i } were equal for each cell i. Which of the following best describes the decision for the hypothesis test?

A)Reject Ho at ? of 0.05 but do not reject Ho at ? of 0.025.
B)Reject Ho at any level of ?.
C)Do not reject Ho at any level of ?.
D)Do not reject Ho at ? of 0.05 but reject Ho at ? of 0.025.
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21
In chi-squared tests, the conventional and conservative rule - known as the rule of five - is to require that the:

A)expected frequency for each cell be at least 5.
B)number of degrees of freedom for the test be at least 5.
C)each expected and observed frequency be at least 5.
D)difference between the observed and expected frequency for each cell be at least 5.
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22
Which of the following best describes the sampling distribution of the test statistic for a goodness-of-fit test with k categories?

A)Student t-distribution with k - 1 degrees of freedom.
B)Normal distribution.
C)Chi-squared distribution with k - 1 degrees of freedom.
D)Approximately Chi-squared distribution with k - 1 degrees of freedom.
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23
Which statistical technique is appropriate when we describe a single population of nominal data with two or more categories?

A)Z-test of the difference between two proportions.
B)Chi-squared test of a multinomial experiment.
C)Chi-squared test of a contingency table.
D)Z test for one proportion.
E)None of these choices are correct
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24
In a goodness-of-fit test, the null hypothesis states that the data came from a normally distributed population. The researcher estimated the population mean and population standard deviation from a sample of 500 observations. In addition, the researcher used 6 standardised intervals to test for normality. Using a 5% level of significance, the critical value for this test is:

A)11.1433.
B)9.3484.
C)7.8147.
D)9.4877.
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25
Which statistical technique is appropriate when we compare two or more populations of nominal data with two or more categories?

A)The z-test of the difference between two proportions.
B)The chi-squared test of a multinomial experiment.
C)The chi-squared test of a contingency table.
D)The z-test of the difference between two proportions and the chi-squared test of a multinomial experiment.
E)The chi-squared test of a multinomial experiment and the chi-squared test of a contingency table.
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26
In a chi-squared test of a contingency table, the value of the test statistic was χ2=12.678\chi ^ { 2 } = 12.678 , the significance level was ? = 0.05 and the degrees of freedom was 6. Thus:

A)we fail to reject the null hypothesis at ? = 0.05.
B)we reject the null hypothesis at ? = 0.05.
C)we Do not have enough evidence to accept or reject the null hypothesis at ? = 0.05.
D)we should increase the level of significance in order to reject the null hypothesis.
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27
Which of the following best describes the rejection region in a chi-squared test of independence?

A)χ2 > χ2α, (r - 2)(c −2)
B)χ2 > χ2 1−α , (r - 1)(c −1)
C)χ2 > χ2α, (r - 1)(c −1)
D)χ2 < χ2α, (r - 1)(c −1)
E)None of these choices are correct.
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28
A left-tailed area in the chi-squared distribution equals 0.975. For df = 11, the table value equals:

A)20.4831.
B)19.6751.
C)3.81575.
D)21.9200.
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29
The null hypothesis states that the sample data came from a normally distributed population. The researcher calculates the sample mean and the sample standard deviation from the data. The data arrangement consisted of seven categories. Using a 0.05 significance level, the appropriate critical value for this chi-squared test for normality is 11.0705.
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30
A chi-squared test for independence with 6 degrees of freedom results in a test statistic χ2=13.58\chi ^ { 2 } = 13.58 . Using the x2x ^ { 2 } tables, the most accurate statement that can be made about the p-value for this test is that:

A)p-value > 0.10.
B)p-value > 0.05.
C)0.05 < p-value < 0.10.
D)0.025 < p-value < 0.05.
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31
Which statistical technique is appropriate when we compare two populations of nominal data with exactly two categories?

A)The z-test of a population proportion.
B)The z-test of the difference between two proportions.
C)The chi-squared test of a contingency table.
D)The z-test of a population proportion and the z-test of the difference between two proportions.
E)The z-test of the difference between two proportions and the chi-squared test of a contingency table.
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32
The chi-squared test of a contingency table is based upon:

A)two nominal variables.
B)two numerical variables.
C)three or more nominal variables.
D)three or more numerical variables.
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33
The number of degrees of freedom in a test of a contingency table with 7 rows and 5 columns is:

A)24.
B)35.
C)30.
D)28.
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34
A test for independence is applied to a contingency table with 5 rows and 2 columns for two nominal variables. The number of degrees of freedom for this chi-squared test must be 4.
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35
Which of the following tests do not use the Chi-squared distribution?

A)Test of a contingency table.
B)Goodness-of-fit test.
C)Test for the difference between two population means.
D)All of these choices are correct.
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36
Which of the following is not a characteristic of a multinomial experiment?  

A)The experiment consists of a fixed number, n, of trials.
B)The outcome of each trial can be classified into one of two categories called success and failure.
C)The probability pip _ { i } that the outcome will fall into cell i remain constant for each trial.
D)Each trial of the experiment is independent of the other trials.
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37
Which of the following statements is not correct?

A)The chi-squared test of independence is a one-sample test.
B)Both variables in the chi-squared test of independence are nominal variables.
C)The chi-squared goodness-of-fit test involves two categorical variables.
D)The chi-squared distribution is skewed to the right.
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38
In a chi-squared goodness-of-fit test, if the expected frequencies eie _ { i } and the observed frequencies fif _ { i } were quite different, which of the following is the best conclusion?

A)Null hypothesis is false, and reject Ho.
B)Null hypothesis is true, and do not reject Ho.
C)Alternative hypothesis is false, reject HA.
D)Chi-squared distribution is invalid, use t-distribution instead.
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39
Which of the following statements is true for the chi-squared tests?

A)Testing for equal proportions is identical to testing for goodness-of-fit.
B)The number of degrees of freedom in a test of a contingency table with r rows and c columns is (r - 1)(c - 1).
C)The number of degrees of freedom in a goodness-of-fit test with k categories is k - 1.
D)All of these choices are correct.
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40
Which of the following statements is not correct?

A)The chi-squared distribution is symmetrical.
B)The chi-squared distribution is skewed to the right.
C)All values of the chi-squared distribution are positive.
D)The critical region for a goodness-of-fit test with k categories is <strong>Which of the following statements is not correct?</strong> A)The chi-squared distribution is symmetrical. B)The chi-squared distribution is skewed to the right. C)All values of the chi-squared distribution are positive. D)The critical region for a goodness-of-fit test with k categories is   . .
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41
A chi-squared goodness-of-fit test can be conducted either as a two-tail test or as a one-tail test.
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42
A test for independence is applied to a contingency table with 4 rows and 4 columns for two nominal variables. The number of degrees of freedom for this test will be 9.
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43
A chi-squared test for independence with 6 degrees of freedom results in a test statistic of 13.25. Using the chi-squared table, the most accurate statement that can be made about the p-value for this test is that 0.025 < p-value < 0.05.
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44
For a chi-squared distributed random variable with 10 degrees of freedom and a level of significance of 0.025, the chi-squared value from the table is 20.5. The computed value of the test statistic is 16.857. The decision is to do not reject Ho.
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45
One type of Chi-squared goodness of fit test is a Chi-squared test for normality.
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46
A left-tailed area in the chi-squared distribution equals 0.10. For 5 degrees of freedom, the table value equals 9.23635.
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47
Whenever the expected frequency of a cell is less than 5, one remedy for this condition is to increase the size of the sample.
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48
Whenever the expected frequency of a cell is less than 5, we must increase the significance level.
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49
In a chi-squared test of independence, the value of the test statistic was x2=x ^ { 2 } = 15.652, and the critical value at α=0.025\alpha = 0.025 was 11.1433. Thus we must reject the null hypothesis at α=0.025\alpha = 0.025 .
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50
In a goodness-of-fit test, the null hypothesis states that the data came from a normally distributed population. The researcher estimated the population mean and population standard deviation from a sample of 100 observations. In addition, the researcher used 6 standardised intervals to test for normality. Using a 2.5% level of significance, the critical value for this test is 9.3484.
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51
For a chi-squared distributed random variable with 12 degrees of freedom and a level of significance of 0.05, the chi-squared value from the table is 21.0261. The computed value of the test statistics is 25.1687. This will lead us to reject the null hypothesis.
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52
In a goodness-of-fit test, the null hypothesis states that the data came from a normally distributed population. The researcher estimated the population mean and population standard deviation from a sample of 200 observations. In addition, the researcher used 5 standardised intervals to test for normality. Using a 10% level of significance, the critical value for this test is 4.60517.
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53
A left-tailed area in the chi-squared distribution equals 0.90. For 10 degrees of freedom, the table value equals 15.9871.
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54
A Chi-squared test can be used to test the equality of two population means.
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55
Whenever the expected frequency of a cell is less than 5, one possible remedy for this condition is to combine it with one or more other cells.
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56
The middle 0.95 portion of the chi-squared distribution with 9 degrees of freedom has table values of 3.32511 and 16.9190, respectively.
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57
A right-tailed area in the chi-squared distribution equals 0.01. For 4 degrees of freedom, the table value equals 13.2767.
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58
A chi-squared test for independence with 10 degrees of freedom results in a test statistic of 17.894. Using the chi-squared table, the most accurate statement that can be made about the p-value for this test is that 0.05 < p-value < 0.10.
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59
The chi-squared test of independence is a Chi-squared test of a contingency table.
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60
In chi-squared tests, the conventional and conservative rule - known as the rule of five - is to require that difference between the observed and expected frequency for each cell be at least 5.
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61
If we want to test for differences between two populations of nominal data with exactly two categories, we can employ either the z-test of p1p2p _ { 1 } - p _ { 2 } , or the chi-squared test of a contingency table. (Squaring the value of the z-statistic yields the value of the x2x ^ { 2 } -statistic.)
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62
A study of education levels of 500 voters and their political party affiliations in a particular state in Australia showed the following results. A study of education levels of 500 voters and their political party affiliations in a particular state in Australia showed the following results.   Is education level independent of political affiliation? Test at the 5% level of significance. Is education level independent of political affiliation? Test at the 5% level of significance.
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63
Five brands of orange juice are displayed side by side in several supermarkets in a large city. It was noted that in one day, 180 customers purchased orange juice. Of these, 30 picked Brand A, 40 picked Brand B, 25 picked Brand C, 35 picked Brand D, and 50 picked brand
E.In this city, can you conclude at the 5% significance level that there is a preferred brand of orange juice?
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64
The number of degrees of freedom for a contingency table with r rows and c columns is (r 1)(c 1), provided that both r and c follow the rule of five.
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65
The chi-squared goodness-of-fit test is usually used as a test of multinomial parameters, but it can also be used to determine whether data were drawn from any distribution.
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66
The number of degrees of freedom associated with the chi-squared test for normality is the number of intervals used minus the number of parameters estimated from the data.
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67
Last year, Brand A mobile android phones had 45% of the market, Brand B had 35% and Brand C had 20%. This year the makers of Brand C launched a heavy advertising campaign. A random sample of mobile phone stores shows that of the 10,000 android mobile phones sold, 4350 were Brand A, 3450 were Brand B, and 2200 were Brand
C.Has the market changed? Test at Last year, Brand A mobile android phones had 45% of the market, Brand B had 35% and Brand C had 20%. This year the makers of Brand C launched a heavy advertising campaign. A random sample of mobile phone stores shows that of the 10,000 android mobile phones sold, 4350 were Brand A, 3450 were Brand B, and 2200 were Brand C.Has the market changed? Test at   0.05. 0.05.
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68
An Australian firm has been accused of engaging in prejudicial hiring practices against women who have young children, where a young child is defined to be a child less than 12 years of age. According to the most recent census, the percentages of men, women without young children and women with young children in a certain community are 72%, 10% and 18%, respectively. A random sample of 200 employees of the firm revealed that 165 were men, 14 were women without young children and 21 were women with young children. Do the data provide sufficient evidence to conclude at the 1% level of significance that the firm has been engaged in prejudicial hiring practices?
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69
When doing a Chi-squared goodness of fit test, we use Ho: The data are not normally distributed.
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70
The personnel manager of a consumer product company asked a random sample of employees how they felt about the work they were doing. The following table gives a breakdown of their responses by gender. The personnel manager of a consumer product company asked a random sample of employees how they felt about the work they were doing. The following table gives a breakdown of their responses by gender.   Do the data provide sufficient evidence to conclude that the level of job satisfaction is related to gender? Use   0.10. Do the data provide sufficient evidence to conclude that the level of job satisfaction is related to gender? Use The personnel manager of a consumer product company asked a random sample of employees how they felt about the work they were doing. The following table gives a breakdown of their responses by gender.   Do the data provide sufficient evidence to conclude that the level of job satisfaction is related to gender? Use   0.10. 0.10.
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71
Like that of the Student t-distribution, the shape of the chi-squared distribution depends on its number of degrees of freedom.
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72
The chi-squared test of a contingency table is used to determine if there is enough evidence to infer that two nominal variables are related, and to infer that differences exist among two or more populations of nominal variables.
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73
The following data are believed to have come from a normal probability distribution. The following data are believed to have come from a normal probability distribution.   The mean of this sample equals 26.80, and the standard deviation equals 6.378. Use the goodness-of-fit test at the 5% significance level to test this claim. The mean of this sample equals 26.80, and the standard deviation equals 6.378. Use the goodness-of-fit test at the 5% significance level to test this claim.
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74
The area to the right of a chi-squared value is 0.01. For 8 degrees of freedom, the table value is 20.0902.
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75
A sport preference poll showed the following data for men and women: A sport preference poll showed the following data for men and women:   Using the 5% level of significance, test to determine whether sport preferences depend on gender. Using the 5% level of significance, test to determine whether sport preferences depend on gender.
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76
At present in Australia, voting in a Federal election is compulsory for all citizens 18 years or over.
There has been some discussion to have this changed from being compulsory to voluntary.
A study was done to investigate whether there was a relationship between gender and attitude towards changing voting in Australia from compulsory to voluntary. Participants were asked "Do you agree to change voting in Australian Federal Elections from compulsory to voluntary? A table of results from the sample is given below.
At the 1% level of significance, is there a relationship between gender and attitude towards voluntary voting? At present in Australia, voting in a Federal election is compulsory for all citizens 18 years or over. There has been some discussion to have this changed from being compulsory to voluntary. A study was done to investigate whether there was a relationship between gender and attitude towards changing voting in Australia from compulsory to voluntary. Participants were asked Do you agree to change voting in Australian Federal Elections from compulsory to voluntary? A table of results from the sample is given below. At the 1% level of significance, is there a relationship between gender and attitude towards voluntary voting?
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77
If we want to perform a one-tail test for differences between two populations of nominal data with exactly two categories, we must employ the z-test of p1p2p _ { 1 } - p _ { 2 } .
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78
A multinomial experiment, where the outcome of each trial can be classified into one of two categories, is identical to the binomial experiment.
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79
If we want to perform a two-tail test for differences between two populations of nominal data with exactly two categories, we can employ either the z-test of p1p2p _ { 1 } - p _ { 2 } , or the chi-squared test of a contingency table. (Squaring the value of the z-statistic yields the value of the x2x ^ { 2 } -statistic.)
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80
The rule of five is used to ensure that the discrete distribution of the test statistic can be approximated by the continuous Chi-squared distribution.
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