Deck 3: Atomic Structure and Properties
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Deck 3: Atomic Structure and Properties
1
John Dalton developed the idea that all matter was composed of solid indivisible atoms. As a result in any equation, the mass of the products is equal to the mass of ____________
reactants
2
The results of Rutherford's experiment which fired -particles at a thin metal film were? Please select all that apply.
A) All the -particles passed straight through.
B) Most of the -particles passed straight through with only minor reflections.
C) A small number of -particles were deflected through angles greater than 90°.
D) All of the -particles were deflected through angles greater than 90°.
A) All the -particles passed straight through.
B) Most of the -particles passed straight through with only minor reflections.
C) A small number of -particles were deflected through angles greater than 90°.
D) All of the -particles were deflected through angles greater than 90°.
B, C
3
The frequency of radiation used in a typical microwave oven is 1.00 1011 Hz. What is the energy of a mole of microwave photons with this frequency?
A) 39.9 J mol-1
B) 3.99 J mol-1
C) 399 J mol-1
D) 0.39 J mol-1
A) 39.9 J mol-1
B) 3.99 J mol-1
C) 399 J mol-1
D) 0.39 J mol-1
A
4
Window glass blocks out short wavelength energetic photons but allows the longer wavelength, lower energy photons in the visible and infrared region to pass through. This process means that the following statements can be paired together.
-The cancer charities advise people to stay inside during the hottest part of the day because
A) skin-damaging, short wavelength, UV radiation is most abundant during the hottest part of the day. UV radiation cannot penetrate buildings, even through the windows
B) the infrared radiation heats the molecules in the curtain and not the air molecules in the room
C) the glass lets through the visible light which the plants need for photosynthesis
D) the abundant infrared radiation passes into the greenhouse rapidly heating the air inside
-The cancer charities advise people to stay inside during the hottest part of the day because
A) skin-damaging, short wavelength, UV radiation is most abundant during the hottest part of the day. UV radiation cannot penetrate buildings, even through the windows
B) the infrared radiation heats the molecules in the curtain and not the air molecules in the room
C) the glass lets through the visible light which the plants need for photosynthesis
D) the abundant infrared radiation passes into the greenhouse rapidly heating the air inside
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5
Window glass blocks out short wavelength energetic photons but allows the longer wavelength, lower energy photons in the visible and infrared region to pass through. This process means that the following statements can be paired together.
-Closing the curtains in a house keeps the room cooler because
A) skin-damaging, short wavelength, UV radiation is most abundant during the hottest part of the day. UV radiation cannot penetrate buildings, even through the windows
B) the infrared radiation heats the molecules in the curtain and not the air molecules in the room
C) the glass lets through the visible light which the plants need for photosynthesis
D) the abundant infrared radiation passes into the greenhouse rapidly heating the air inside
-Closing the curtains in a house keeps the room cooler because
A) skin-damaging, short wavelength, UV radiation is most abundant during the hottest part of the day. UV radiation cannot penetrate buildings, even through the windows
B) the infrared radiation heats the molecules in the curtain and not the air molecules in the room
C) the glass lets through the visible light which the plants need for photosynthesis
D) the abundant infrared radiation passes into the greenhouse rapidly heating the air inside
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6
Window glass blocks out short wavelength energetic photons but allows the longer wavelength, lower energy photons in the visible and infrared region to pass through. This process means that the following statements can be paired together.
-Keen gardeners use a greenhouse to help their plants grow because
A) skin-damaging, short wavelength, UV radiation is most abundant during the hottest part of the day. UV radiation cannot penetrate buildings, even through the windows
B) the infrared radiation heats the molecules in the curtain and not the air molecules in the room
C) the glass lets through the visible light which the plants need for photosynthesis
D) the abundant infrared radiation passes into the greenhouse rapidly heating the air inside
-Keen gardeners use a greenhouse to help their plants grow because
A) skin-damaging, short wavelength, UV radiation is most abundant during the hottest part of the day. UV radiation cannot penetrate buildings, even through the windows
B) the infrared radiation heats the molecules in the curtain and not the air molecules in the room
C) the glass lets through the visible light which the plants need for photosynthesis
D) the abundant infrared radiation passes into the greenhouse rapidly heating the air inside
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7
Window glass blocks out short wavelength energetic photons but allows the longer wavelength, lower energy photons in the visible and infrared region to pass through. This process means that the following statements can be paired together.
-In high summer, plants often wither and die in a greenhouse because
A) skin-damaging, short wavelength, UV radiation is most abundant during the hottest part of the day. UV radiation cannot penetrate buildings, even through the windows
B) the infrared radiation heats the molecules in the curtain and not the air molecules in the room
C) the glass lets through the visible light which the plants need for photosynthesis
D) the abundant infrared radiation passes into the greenhouse rapidly heating the air inside
-In high summer, plants often wither and die in a greenhouse because
A) skin-damaging, short wavelength, UV radiation is most abundant during the hottest part of the day. UV radiation cannot penetrate buildings, even through the windows
B) the infrared radiation heats the molecules in the curtain and not the air molecules in the room
C) the glass lets through the visible light which the plants need for photosynthesis
D) the abundant infrared radiation passes into the greenhouse rapidly heating the air inside
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8
Given that the work function for an aluminium surface is 5.66 10-19 J, determine what wavelength of radiation will be required to eject an electron from the surface?
A) 652 nm
B) 217 nm
C) 455 nm
D) 351 nm
A) 652 nm
B) 217 nm
C) 455 nm
D) 351 nm
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9
In Thomas Young's experiment when he passed light through two closely placed slits, it gave an interference pattern. This evidence suggests that light behaves as a particle.
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10
A line from the Pfund series has the frequency 8.02 1013 Hz. What value of n2 generates this line in the spectrum?
A) 5
B) 6
C) 7
D) 8
A) 5
B) 6
C) 7
D) 8
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11
Metals and metal compounds are added to gunpowder to produce the colours given in fireworks. The intense white light produced is by the metals aluminium, magnesium and ____________
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12
An emission spectrum consists of dark lines on a bright background.
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13
An electron is travelling with a wavelength of 246 pm, what is its velocity?
A) 2.16 106 m s-1
B) 1.96 106 m s-1
C) 2.96 106 m s-1
D) 2.96 107 m s-1
A) 2.16 106 m s-1
B) 1.96 106 m s-1
C) 2.96 106 m s-1
D) 2.96 107 m s-1
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14
As objects such as electrons have wave-like properties, this property leads to uncertainties in which of the following quantities? Please select all that apply.
A) p (momentum)
B) m (mass)
C) q (position)°
D) h (Planck's constant)
A) p (momentum)
B) m (mass)
C) q (position)°
D) h (Planck's constant)
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15
Heisenberg stated that due to the wave properties of an electron, it is impossible to know their precise _________ and momentum simultaneously.
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16
It is not possible to define a region that contains the entire wavefunction.
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17
Match the type of orbital defined by the quantum numbers given in questions (a) to (d) in the left column, to the answers given in the right column.
-n equals 2, l equals 3
A) 4d orbital
B) value of n not allowed
C) 5f orbital
D) value of l not allowed for this value of n
-n equals 2, l equals 3
A) 4d orbital
B) value of n not allowed
C) 5f orbital
D) value of l not allowed for this value of n
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18
Match the type of orbital defined by the quantum numbers given in questions (a) to (d) in the left column, to the answers given in the right column.
-n equals 4, l equals 2
A) 4d orbital
B) value of n not allowed
C) 5f orbital
D) value of l not allowed for this value of n
-n equals 4, l equals 2
A) 4d orbital
B) value of n not allowed
C) 5f orbital
D) value of l not allowed for this value of n
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19
Match the type of orbital defined by the quantum numbers given in questions (a) to (d) in the left column, to the answers given in the right column.
-n equals 0, l equals 0
A) 4d orbital
B) value of n not allowed
C) 5f orbital
D) value of l not allowed for this value of n
-n equals 0, l equals 0
A) 4d orbital
B) value of n not allowed
C) 5f orbital
D) value of l not allowed for this value of n
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20
Match the type of orbital defined by the quantum numbers given in questions (a) to (d) in the left column, to the answers given in the right column.
-n equals 5, l equals 3
A) 4d orbital
B) value of n not allowed
C) 5f orbital
D) value of l not allowed for this value of n
-n equals 5, l equals 3
A) 4d orbital
B) value of n not allowed
C) 5f orbital
D) value of l not allowed for this value of n
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21
The point at which the wavefunction is zero is known as a __ ?
A) node
B) zeropoint
C) orbital
D) minimum
A) node
B) zeropoint
C) orbital
D) minimum
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22
How many orbitals are defined for the shell where n = 3?
A) 9
B) 1
C) 4
D) 16
A) 9
B) 1
C) 4
D) 16
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23
The dz2 orbital is a different shape to all the other d orbitals because it is really the combination of two orbitals, meaning there are six solutions and not five to the Schrödinger equation for n = 2.
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24
The f7 configuration has particular stability due to the _______ energy
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25
Which of the following concepts are required to determine the ground state electronic configuration of the nitrogen atom? Please select all that apply.
A) Aufbau Principle
B) Schrodinger Equation
C) Pauli Exclusion Principle
D) Hund's Rule
A) Aufbau Principle
B) Schrodinger Equation
C) Pauli Exclusion Principle
D) Hund's Rule
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26
What is the electronic configuration of the nitride, N3- ion? Is this ion paramagnetic?
A) N3- 1s2 2s2 2p6 and paramagnetic
B) N3- 1s2 2s2 2p6 and diamagnetic
C) N3- 1s2 2s2 2p5 and paramagnetic
D) N3- 1s2 2s2 2p5 and diamagnetic
A) N3- 1s2 2s2 2p6 and paramagnetic
B) N3- 1s2 2s2 2p6 and diamagnetic
C) N3- 1s2 2s2 2p5 and paramagnetic
D) N3- 1s2 2s2 2p5 and diamagnetic
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27
The anion of a non metal is smaller than the corresponding neutral species.
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28
Use Slater's rules to determine the relative sizes of N, O and F atoms.
A) F > O > N
B) N > F > O
C) F < O < N
D) O > F > N
A) F > O > N
B) N > F > O
C) F < O < N
D) O > F > N
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29
Match the first ionization enthalpy with the appropriate element of the first period.
-1402 kJ mol-1
A) N
B) Li
C) Ne
D) O
-1402 kJ mol-1
A) N
B) Li
C) Ne
D) O
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30
Match the first ionization enthalpy with the appropriate element of the first period.
-520 kJ mol-1
A) N
B) Li
C) Ne
D) O
-520 kJ mol-1
A) N
B) Li
C) Ne
D) O
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31
Match the first ionization enthalpy with the appropriate element of the first period.
-2081 kJ mol-1
A) N
B) Li
C) Ne
D) O
-2081 kJ mol-1
A) N
B) Li
C) Ne
D) O
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32
Match the first ionization enthalpy with the appropriate element of the first period.
-1314 kJ mol-1
A) N
B) Li
C) Ne
D) O
-1314 kJ mol-1
A) N
B) Li
C) Ne
D) O
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33
The ionization enthalpy of the group 1 elements _______ down the group?
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34
The half life or a radioactive element depends on the number of nuclei at the start.
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