Deck 9: Molecular Geometry and Bonding Theories
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Question
Unlock Deck
Sign up to unlock the cards in this deck!
Unlock Deck
Unlock Deck
1/183
Play
Full screen (f)
Deck 9: Molecular Geometry and Bonding Theories
1
For molecules of the general formula ABn, n can be greater than four ________.
A)for any element A
B)only when A is an element from the third period or below the third period
C)only when A is boron or beryllium
D)only when A is carbon
E)only when A is Xe
A)for any element A
B)only when A is an element from the third period or below the third period
C)only when A is boron or beryllium
D)only when A is carbon
E)only when A is Xe
only when A is an element from the third period or below the third period
2
The bond angles marked a, b, and c in the molecule below are about ________, ________, and ________, respectively. 
A)90°, 90°, 90°
B)120°, 120°, 90°
C)120°, 120°, 109.5°
D)109.5°, 120°, 109.5°
E)109.5°, 90°, 120°

A)90°, 90°, 90°
B)120°, 120°, 90°
C)120°, 120°, 109.5°
D)109.5°, 120°, 109.5°
E)109.5°, 90°, 120°
109.5°, 120°, 109.5°
3
Consider the following species when answering the following questions:
(i) PCl3
(ii) CCl4
(iii) TeCl4
(iv) XeF4
(v) SF6
For which of the molecules is the molecular geometry (shape)the same as the VSEPR electron domain arrangement (electron domain geometry)?
A)(i)and (ii)
B)(i)and (iii)
C)(ii)and (v)
D)(iv)and (v)
E)(v)only
(i) PCl3
(ii) CCl4
(iii) TeCl4
(iv) XeF4
(v) SF6
For which of the molecules is the molecular geometry (shape)the same as the VSEPR electron domain arrangement (electron domain geometry)?
A)(i)and (ii)
B)(i)and (iii)
C)(ii)and (v)
D)(iv)and (v)
E)(v)only
(ii)and (v)
4
An electron domain consists of ________.
(a) a nonbonding pair of electrons
(B) a single bond
(C) a multiple bond
A)a only
B)b only
C)c only
D)a, b, and c
E)b and c
(a) a nonbonding pair of electrons
(B) a single bond
(C) a multiple bond
A)a only
B)b only
C)c only
D)a, b, and c
E)b and c
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
5
The molecular geometry consists of ________.
(a) a nonbonding pair of electrons
(b) a single bond
(c) a multiple bond
A)a only
B)b only
C)c only
D)a, b, and c
E)b and c
(a) a nonbonding pair of electrons
(b) a single bond
(c) a multiple bond
A)a only
B)b only
C)c only
D)a, b, and c
E)b and c
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
6
The electron-domain geometry and the molecular geometry of a molecule of the general formula ABn are ________.
A)never the same
B)always the same
C)sometimes the same
D)not related
E)mirror images of one another
A)never the same
B)always the same
C)sometimes the same
D)not related
E)mirror images of one another
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
7
Of the molecules below, only ________ is nonpolar.
A)BF3
B)NF3
C)IF3
D)PBr3
E)BrCl3
A)BF3
B)NF3
C)IF3
D)PBr3
E)BrCl3
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
8
The electron-domain geometry and the molecular geometry of a molecule of the general formula ABn will always be the same if ________.
A)there are no lone pairs on the central atom
B)there is more than one central atom
C)n is greater than four
D)n is less than four
E)the octet rule is obeyed
A)there are no lone pairs on the central atom
B)there is more than one central atom
C)n is greater than four
D)n is less than four
E)the octet rule is obeyed
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
9
A molecule has the formula AB3 and the central atom is in a different plane from the surrounding three atoms. Its molecular shape is ________.
A)tetrahedral
B)trigonal pyramidal
C)linear
D)T-shaped
E)bent
A)tetrahedral
B)trigonal pyramidal
C)linear
D)T-shaped
E)bent
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
10
The molecular geometry of the right-most carbon in the molecule below is ________. 
A)trigonal planar
B)trigonal bipyramidal
C)tetrahedral
D)octahedral
E)T-shaped

A)trigonal planar
B)trigonal bipyramidal
C)tetrahedral
D)octahedral
E)T-shaped
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
11
The central Xe atom in the XeF4 molecule has ________ unbonded electron pair(s)and ________ bonded electron pair(s)in its valence shell.
A)1, 4
B)2, 4
C)4, 0
D)4, 1
E)4, 2
A)1, 4
B)2, 4
C)4, 0
D)4, 1
E)4, 2
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
12
PCl5 has ________ electron domains and a ________ molecular arrangement.
A)6, trigonal bipyramidal
B)6, tetrahedral
C)5, square pyramidal
D)5, trigonal bipyramidal
E)6, seesaw
A)6, trigonal bipyramidal
B)6, tetrahedral
C)5, square pyramidal
D)5, trigonal bipyramidal
E)6, seesaw
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
13
The basis of the VSEPR model of molecular bonding is ________.
A)regions of electron density on an atom will organize themselves so as to maximize s-character
B)regions of electron density in the valence shell of an atom will arrange themselves so as to maximize overlap
C)atomic orbitals of the bonding atoms must overlap for a bond to form
D)electron domains in the valence shell of an atom will arrange themselves so as to minimize repulsions
E)hybrid orbitals will form as necessary to, as closely as possible, achieve spherical symmetry
A)regions of electron density on an atom will organize themselves so as to maximize s-character
B)regions of electron density in the valence shell of an atom will arrange themselves so as to maximize overlap
C)atomic orbitals of the bonding atoms must overlap for a bond to form
D)electron domains in the valence shell of an atom will arrange themselves so as to minimize repulsions
E)hybrid orbitals will form as necessary to, as closely as possible, achieve spherical symmetry
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
14
The bond angles marked a, b, and c in the molecule below are about ________, ________, and ________, respectively. 
A)109.5°, 109.5°, 109.5°
B)120°, 109.5°, 120°
C)109.5°, 109.5°, 120°
D)90°, 180°, 90°
E)109.5°, 109.5°, 90°

A)109.5°, 109.5°, 109.5°
B)120°, 109.5°, 120°
C)109.5°, 109.5°, 120°
D)90°, 180°, 90°
E)109.5°, 109.5°, 90°
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
15
Of the following species, ________ will have bond angles of 120°.
A)PH3
B)ClF3
C)NCl3
D)BCl3
E)All of these will have bond angles of 120°.
A)PH3
B)ClF3
C)NCl3
D)BCl3
E)All of these will have bond angles of 120°.
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
16
Of the molecules below, only ________ is polar.
A)CCl4
B)CH4
C)SeF4
D)SiCl4
A)CCl4
B)CH4
C)SeF4
D)SiCl4
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
17
The molecular geometry of the left-most carbon atom in the molecule below is ________. 
A)trigonal planar
B)trigonal bipyramidal
C)tetrahedral
D)octahedral
E)T-shaped

A)trigonal planar
B)trigonal bipyramidal
C)tetrahedral
D)octahedral
E)T-shaped
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
18
The electron-domain geometry of ________ is tetrahedral.
A)CBr4
B)PH3
C)CCl2Br2
D)XeF4
E)all of the above except XeF4
A)CBr4
B)PH3
C)CCl2Br2
D)XeF4
E)all of the above except XeF4
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
19
The molecular geometry of the BrO3- ion is ________.
A)trigonal pyramidal
B)trigonal planar
C)bent
D)tetrahedral
E)T-shaped
A)trigonal pyramidal
B)trigonal planar
C)bent
D)tetrahedral
E)T-shaped
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
20
In counting the electron domains around the central atom in VSEPR theory, a ________ is not included.
A)nonbonding pair of electrons
B)single covalent bond
C)core level electron pair
D)double covalent bond
E)triple covalent bond
A)nonbonding pair of electrons
B)single covalent bond
C)core level electron pair
D)double covalent bond
E)triple covalent bond
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
21
The hybridizations of bromine in BrF5 and of arsenic in AsF5 are ________ and ________, respectively.
A)sp3, sp3d
B)sp3d, sp3d2
C)sp3d, sp3
D)sp3d2, sp3d
E)sp3d2, sp3d2
A)sp3, sp3d
B)sp3d, sp3d2
C)sp3d, sp3
D)sp3d2, sp3d
E)sp3d2, sp3d2
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
22
The hybridization of the oxygen atom labeled y in the structure below is ________. The C-O-H bond angle is ________. 
A)sp, 180°
B)sp2, 109.5°
C)sp3, 109.5°
D)sp3d2, 90°
E)sp, 90°

A)sp, 180°
B)sp2, 109.5°
C)sp3, 109.5°
D)sp3d2, 90°
E)sp, 90°
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
23
Of the following molecules, only ________ is polar.
A)BeCl2
B)BF3
C)CBr4
D)SiH2Cl2
E)Cl2
A)BeCl2
B)BF3
C)CBr4
D)SiH2Cl2
E)Cl2
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
24
The hybrid orbitals used for bonding by Xe in the unstable XeF2 molecule are ________ orbitals.
A)sp2
B)sp3
C)sp3d
D)sp3d2
E)sp
A)sp2
B)sp3
C)sp3d
D)sp3d2
E)sp
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
25
The sp3d2 atomic hybrid orbital set accommodates ________ electron domains.
A)2
B)3
C)4
D)5
E)6
A)2
B)3
C)4
D)5
E)6
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
26
For molecules with only one central atom, how many lone pairs on the central atom guarantees molecular polarity?
A)1
B)2
C)1 or 2
D)3
E)1 or 3
A)1
B)2
C)1 or 2
D)3
E)1 or 3
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
27
Of the following molecules, only ________ is polar.
A)CCl4
B)BCl3
C)NCl3
D)BeCl2
E)Cl2
A)CCl4
B)BCl3
C)NCl3
D)BeCl2
E)Cl2
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
28
The hybrid orbitals used for bonding by the sulfur atom in the SF4 molecule are ________ orbitals.
A)sp
B)sp2
C)sp3
D)sp3d
E)sp3d2
A)sp
B)sp2
C)sp3
D)sp3d
E)sp3d2
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
29
The sp2 atomic hybrid orbital set accommodates ________ electron domains.
A)2
B)3
C)4
D)5
E)6
A)2
B)3
C)4
D)5
E)6
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
30
The hybridization scheme for BeF2 is ________.
A)sp
B)sp2
C)sp3
D)sp3d
E)sp3d2
A)sp
B)sp2
C)sp3
D)sp3d
E)sp3d2
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
31
Consider the following species when answering the following questions:
(i) PCl3 (ii) CCl4 (iii) TeCl4 (iv) XeF4 (v) SF6
Which of the molecules has a see-saw shape?
A)(i)
B)(ii)
C)(iii)
D)(iv)
E)(v)
(i) PCl3 (ii) CCl4 (iii) TeCl4 (iv) XeF4 (v) SF6
Which of the molecules has a see-saw shape?
A)(i)
B)(ii)
C)(iii)
D)(iv)
E)(v)
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
32
The combination of two atomic orbitals results in the formation of ________ molecular orbitals.
A)1
B)2
C)3
D)4
E)0
A)1
B)2
C)3
D)4
E)0
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
33
Of the following, the central atom is sp3d2 hybridized only in ________.
A)PCl5
B)XeF4
C)PH3
D)Br3-
E)BeF2
A)PCl5
B)XeF4
C)PH3
D)Br3-
E)BeF2
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
34
The molecular geometry of the PF3 molecule is ________, and this molecule is ________.
A)trigonal planar, polar
B)trigonal planar, nonpolar
C)trigonal pyramidal, polar
D)trigonal pyramidal, nonpolar
E)tetrahedral, unipolar
A)trigonal planar, polar
B)trigonal planar, nonpolar
C)trigonal pyramidal, polar
D)trigonal pyramidal, nonpolar
E)tetrahedral, unipolar
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
35
The hybridizations of iodine in IF3 and IF5 are ________ and ________, respectively.
A)sp3, sp3d
B)sp3d, sp3d2
C)sp3d, sp3
D)sp3d2, sp3d
E)sp3d2, sp3d2
A)sp3, sp3d
B)sp3d, sp3d2
C)sp3d, sp3
D)sp3d2, sp3d
E)sp3d2, sp3d2
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
36
Consider the following species when answering the following questions:
(i) PCl3 (ii) CCl4 (iii) TeCl4 (iv) XeF4 (v) SF6
In which of the molecules does the central atom utilize d orbitals to form hybrid orbitals?
A)(i)and (ii)
B)(iii)only
C)(i)and (v)
D)(iii), (iv), and (v)
E)(v)only
(i) PCl3 (ii) CCl4 (iii) TeCl4 (iv) XeF4 (v) SF6
In which of the molecules does the central atom utilize d orbitals to form hybrid orbitals?
A)(i)and (ii)
B)(iii)only
C)(i)and (v)
D)(iii), (iv), and (v)
E)(v)only
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
37
The molecular geometry of the CHF3 molecule is ________, and the molecule is ________.
A)trigonal pyramidal, polar
B)tetrahedral, nonpolar
C)seesaw, nonpolar
D)tetrahedral, polar
E)seesaw, polar
A)trigonal pyramidal, polar
B)tetrahedral, nonpolar
C)seesaw, nonpolar
D)tetrahedral, polar
E)seesaw, polar
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
38
The molecular geometry of the BCl3 molecule is ________, and this molecule is ________.
A)trigonal pyramidal, polar
B)trigonal pyramidal, nonpolar
C)trigonal planar, polar
D)trigonal planar, nonpolar
E)trigonal bipyramidal, polar
A)trigonal pyramidal, polar
B)trigonal pyramidal, nonpolar
C)trigonal planar, polar
D)trigonal planar, nonpolar
E)trigonal bipyramidal, polar
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
39
The hybridizations of nitrogen in NF3 and NH3 are ________ and ________, respectively.
A)sp2, sp2
B)sp, sp3
C)sp3, sp
D)sp3, sp3
E)sp2, sp3
A)sp2, sp2
B)sp, sp3
C)sp3, sp
D)sp3, sp3
E)sp2, sp3
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
40
Three monosulfur fluorides are observed: SF2, SF4, and SF6. Of these, ________ is/are polar.
A)SF2 only
B)SF2 and SF4 only
C)SF4 only
D)SF6 only
E)SF2, SF4, and SF6
A)SF2 only
B)SF2 and SF4 only
C)SF4 only
D)SF6 only
E)SF2, SF4, and SF6
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
41
Which of the following molecules or ions will exhibit delocalized bonding? SO2 SO3 SO32-
A)SO2, SO3, and SO32-
B)SO32- only
C)SO2 and SO3
D)SO3 and SO32-
E)None of the above will exhibit delocalized bonding.
A)SO2, SO3, and SO32-
B)SO32- only
C)SO2 and SO3
D)SO3 and SO32-
E)None of the above will exhibit delocalized bonding.
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
42
In a typical multiple bond, the σ bond results from overlap of ________ orbitals and the π bond(s)result from overlap of ________ orbitals.
A)hybrid, atomic
B)hybrid, hybrid
C)atomic, hybrid
D)hybrid, hybrid or atomic
E)hybrid or atomic, hybrid or atomic
A)hybrid, atomic
B)hybrid, hybrid
C)atomic, hybrid
D)hybrid, hybrid or atomic
E)hybrid or atomic, hybrid or atomic
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
43
When four atomic orbitals are mixed to form hybrid orbitals, how many hybrid orbitals are formed?
A)one
B)six
C)three
D)four
E)five
A)one
B)six
C)three
D)four
E)five
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
44
Which of the following molecules or ions will exhibit delocalized bonding? NO2- NH4+ N3-
A) NH4+ and N3-
B)NO2- only
C)NO2-, NH4+, and N3-
D)N3- only
E)NO2- and N3-
A) NH4+ and N3-
B)NO2- only
C)NO2-, NH4+, and N3-
D)N3- only
E)NO2- and N3-
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
45
A triatomic molecule cannot be linear if the hybridization of the central atoms is ________.
A)sp
B)sp2
C)sp3
D)sp2 or sp3
E)sp2d or sp3d2
A)sp
B)sp2
C)sp3
D)sp2 or sp3
E)sp2d or sp3d2
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
46
In a polyatomic molecule, "localized" bonding electrons are associated with ________.
A)one particular atom
B)two particular atoms
C)all of the atoms in the molecule
D)all of the π bonds in the molecule
E)two or more σ bonds in the molecule
A)one particular atom
B)two particular atoms
C)all of the atoms in the molecule
D)all of the π bonds in the molecule
E)two or more σ bonds in the molecule
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
47
In order to exhibit delocalized π bonding, a molecule must have ________.
A)at least two π bonds
B)at least two resonance structures
C)at least three σ bonds
D)at least four atoms
E)trigonal planar electron domain geometry
A)at least two π bonds
B)at least two resonance structures
C)at least three σ bonds
D)at least four atoms
E)trigonal planar electron domain geometry
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
48
The electron-domain geometry of the AsF5 molecule is trigonal bipyramidal. The hybrid orbitals used by the As atom for bonding are ________ orbitals.
A)sp2d2
B)sp3
C)sp3d2
D)sp3d
E)sp2
A)sp2d2
B)sp3
C)sp3d2
D)sp3d
E)sp2
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
49
The hybridization of nitrogen in the H-C
N: molecule is ________.
A)sp
B)s2p
C)s3p
D)sp2
E)sp3

A)sp
B)s2p
C)s3p
D)sp2
E)sp3
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
50
Valence bond theory does not address the issue of ________.
A)excited states of molecules
B)molecular shape
C)covalent bonding
D)hybridization
E)multiple bonds
A)excited states of molecules
B)molecular shape
C)covalent bonding
D)hybridization
E)multiple bonds
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
51
There are ________ σ bonds and ________ π bonds in H3C-CH2-CH
CH-CH2-C
CH.
A)14, 2
B)10, 3
C)12, 2
D)13, 2
E)16, 3


A)14, 2
B)10, 3
C)12, 2
D)13, 2
E)16, 3
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
52
The carbon-carbon σ bond in ethylene, H2C
CH2, results from the overlap of ________.
A)sp hybrid orbitals
B)sp3 hybrid orbitals
C)sp2 hybrid orbitals
D)s atomic orbitals
E)p atomic orbitals

A)sp hybrid orbitals
B)sp3 hybrid orbitals
C)sp2 hybrid orbitals
D)s atomic orbitals
E)p atomic orbitals
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
53
Consider the following species when answering the following questions:
(i) PCl3
(ii) CCl4
(iii) TeCl4
(iv) XeF4
(v) SF6
In which of the molecules is the central atom sp3d2 hybridized?
A)(i)and (ii)
B)(iii)only
C)(iii)and (iv)
D)(iv)and (v)
E)(v)only
(i) PCl3
(ii) CCl4
(iii) TeCl4
(iv) XeF4
(v) SF6
In which of the molecules is the central atom sp3d2 hybridized?
A)(i)and (ii)
B)(iii)only
C)(iii)and (iv)
D)(iv)and (v)
E)(v)only
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
54
The hybridization of the terminal carbons in the H2C
C
CH2 molecule is ________.
A)sp
B)sp2
C)sp3
D)sp3d
E)sp3d2


A)sp
B)sp2
C)sp3
D)sp3d
E)sp3d2
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
55
A typical double bond ________.
A)is stronger and shorter than a single bond
B)consists of one σ bond and one π bond
C)imparts rigidity to a molecule
D)consists of two shared electron pairs
E)All of the above answers are correct.
A)is stronger and shorter than a single bond
B)consists of one σ bond and one π bond
C)imparts rigidity to a molecule
D)consists of two shared electron pairs
E)All of the above answers are correct.
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
56
The π bond in ethylene, H2C
CH2, results from the overlap of ________.
A)sp3 hybrid orbitals
B)s atomic orbitals
C)sp hybrid orbitals
D)sp2 hybrid orbitals
E)p atomic orbitals

A)sp3 hybrid orbitals
B)s atomic orbitals
C)sp hybrid orbitals
D)sp2 hybrid orbitals
E)p atomic orbitals
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
57
A typical double bond consists of ________.
A)three sigma bonds
B)three pi bonds
C)one sigma and two pi bonds
D)one sigma and one pi bond
E)three ionic bonds
A)three sigma bonds
B)three pi bonds
C)one sigma and two pi bonds
D)one sigma and one pi bond
E)three ionic bonds
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
58
________ hybrid orbitals are used for bonding by Xe in the XeF4 molecule.
A)sp2
B)sp3
C)sp3d
D)sp3d2
E)sp
A)sp2
B)sp3
C)sp3d
D)sp3d2
E)sp
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
59
The N-N bond in HNNH consists of ________.
A)one σ bond and one π bond
B)one σ bond and two π bonds
C)two σ bonds and one π bond
D)two σ bonds and two π bonds
E)one σ bond and no π bonds
A)one σ bond and one π bond
B)one σ bond and two π bonds
C)two σ bonds and one π bond
D)two σ bonds and two π bonds
E)one σ bond and no π bonds
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
60
A typical triple bond ________.
A)consists of one σ bond and two π bonds
B)consists of three shared electrons
C)consists of two σ bonds and one π bond
D)consists of six shared electron pairs
E)is longer than a single bond
A)consists of one σ bond and two π bonds
B)consists of three shared electrons
C)consists of two σ bonds and one π bond
D)consists of six shared electron pairs
E)is longer than a single bond
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
61
Based on molecular orbital theory, the bond order of the N-N bond in the N22+ ion is ________.
A)0
B)3
C)1
D)2
E)1/2
A)0
B)3
C)1
D)2
E)1/2
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
62
Based on molecular orbital theory, the bond order of the Be-Be bond in the Be2 molecule is ________.
A)0
B)1
C)2
D)3
E)4
A)0
B)1
C)2
D)3
E)4
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
63
An antibonding π orbital contains a maximum of ________ electrons.
A)1
B)2
C)4
D)6
E)8
A)1
B)2
C)4
D)6
E)8
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
64
The Lewis structure of carbon dioxide is given below. The hybridization of the carbon atom in carbon dioxide is ________. 
A)sp3
B)sp2
C)sp
D)sp2d
E)sp2d2

A)sp3
B)sp2
C)sp
D)sp2d
E)sp2d2
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
65
A molecular orbital can accommodate a maximum of ________ electron(s).
A)1
B)2
C)4
D)6
E)12
A)1
B)2
C)4
D)6
E)12
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
66
Based on molecular orbital theory, the bond order of the H-H bond in the H2+ ion is ________.
A)0
B)1/2
C)1
D)3/2
E)2
A)0
B)1/2
C)1
D)3/2
E)2
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
67
The hybridization of carbon in the H-C
N: molecule is ________.
A)sp2
B)s2p
C)s3p
D)sp
E)sp3

A)sp2
B)s2p
C)s3p
D)sp
E)sp3
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
68
According to MO theory, overlap of two s atomic orbitals produces ________.
A)one bonding molecular orbital and one hybrid orbital
B)two bonding molecular orbitals
C)two bonding molecular orbitals and two antibonding molecular orbitals
D)two bonding molecular orbitals and one antibonding molecular orbital
E)one bonding molecular orbital and one antibonding molecular orbital
A)one bonding molecular orbital and one hybrid orbital
B)two bonding molecular orbitals
C)two bonding molecular orbitals and two antibonding molecular orbitals
D)two bonding molecular orbitals and one antibonding molecular orbital
E)one bonding molecular orbital and one antibonding molecular orbital
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
69
In comparing the same two atoms bonded together, the ________ the bond order, the ________ the bond length, and the ________ the bond energy.
A)greater, shorter, greater
B)greater, greater, greater
C)greater, longer, greater
D)greater, greater, smaller
E)smaller, greater, greater
A)greater, shorter, greater
B)greater, greater, greater
C)greater, longer, greater
D)greater, greater, smaller
E)smaller, greater, greater
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
70
Molecular Orbital theory correctly predicts paramagnetism of oxygen gas, O2. This is because ________.
A)the bond order in O2 can be shown to be equal to 2.
B)there are more electrons in the bonding orbitals than in the antibonding orbitals.
C)the energy of the π2p MOs is higher than that of the σ2p MO
D)there are two unpaired electrons in the MO electron configuration of O2
E)the O-O bond distance is relatively short
A)the bond order in O2 can be shown to be equal to 2.
B)there are more electrons in the bonding orbitals than in the antibonding orbitals.
C)the energy of the π2p MOs is higher than that of the σ2p MO
D)there are two unpaired electrons in the MO electron configuration of O2
E)the O-O bond distance is relatively short
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
71
Based on molecular orbital theory, the bond orders of the H-H bonds in H2, H2+, and H2- are ________, respectively
A)1, 0, and 0
B)1, 1/2, and 0
C)1, 0, and 1/2
D)1, 1/2, and 1/2
E)1, 2, and 0
A)1, 0, and 0
B)1, 1/2, and 0
C)1, 0, and 1/2
D)1, 1/2, and 1/2
E)1, 2, and 0
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
72
The hybridization of the oxygen atom labeled x in the structure below is ________. 
A)sp
B)sp2
C)sp3
D)sp3d
E)sp3d2

A)sp
B)sp2
C)sp3
D)sp3d
E)sp3d2
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
73
Based on molecular orbital theory, the only molecule in the list below that has unpaired electrons is ________.
A)C2
B)N2
C)F2
D)O2
E)Li2
A)C2
B)N2
C)F2
D)O2
E)Li2
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
74
Molecular Orbital theory correctly predicts diamagnetism of fluorine gas, F2. This is because ________.
A)the bond order in F2 can be shown to be equal to 1.
B)there are more electrons in the bonding orbitals than in the antibonding orbitals.
C)all electrons in the MO electron configuration of F2 are paired.
D)the energy of the π2pMOs is higher than that of the σ2p MO
E)the F-F bond enthalpy is very low
A)the bond order in F2 can be shown to be equal to 1.
B)there are more electrons in the bonding orbitals than in the antibonding orbitals.
C)all electrons in the MO electron configuration of F2 are paired.
D)the energy of the π2pMOs is higher than that of the σ2p MO
E)the F-F bond enthalpy is very low
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
75
Electrons in ________ bonds remain localized between two atoms. Electrons in ________ bonds can become delocalized between more than two atoms.
A)pi, sigma
B)sigma, pi
C)pi, pi
D)sigma, sigma
E)ionic, sigma
A)pi, sigma
B)sigma, pi
C)pi, pi
D)sigma, sigma
E)ionic, sigma
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
76
In comparing the same two atoms bonded together, the ________ the bond order, the ________ the bond length, and the ________ the bond energy.
A)greater, shorter, greater
B)greater, greater, greater
C)greater, longer, greater
D)smaller, longer, smaller
E)smaller, greater, greater
A)greater, shorter, greater
B)greater, greater, greater
C)greater, longer, greater
D)smaller, longer, smaller
E)smaller, greater, greater
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
77
The bond order of any molecule containing equal numbers of bonding and antibonding electrons is ________.
A)0
B)1
C)2
D)3
E)1/2
A)0
B)1
C)2
D)3
E)1/2
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
78
Based on molecular orbital theory, there is/are ________ unpaired electron(s)in the OF+ ion.
A)0
B)3
C)1
D)2
E)1/2
A)0
B)3
C)1
D)2
E)1/2
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
79
Structural changes around a double bond in the ________ portion of the rhodopsin molecule trigger the chemical reactions that result in vision.
A)protein
B)opsin
C)retinal
D)cones
E)rods
A)protein
B)opsin
C)retinal
D)cones
E)rods
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck
80
The hybridization of the carbon atom labeled x in the molecule below is ________. 
A)sp
B)sp2
C)sp3
D)sp3d
E)sp3d2

A)sp
B)sp2
C)sp3
D)sp3d
E)sp3d2
Unlock Deck
Unlock for access to all 183 flashcards in this deck.
Unlock Deck
k this deck