Deck 9: Numerical Solutions of Ordinary Differential Equations

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Question
When entering the number <strong>When entering the number   into a three digit base ten calculator, the round-off error is</strong> A) 0.00143 B) 0.000143 C)   D)   E)   <div style=padding-top: 35px> into a three digit base ten calculator, the round-off error is

A) 0.00143
B) 0.000143
C) <strong>When entering the number   into a three digit base ten calculator, the round-off error is</strong> A) 0.00143 B) 0.000143 C)   D)   E)   <div style=padding-top: 35px>
D) <strong>When entering the number   into a three digit base ten calculator, the round-off error is</strong> A) 0.00143 B) 0.000143 C)   D)   E)   <div style=padding-top: 35px>
E) <strong>When entering the number   into a three digit base ten calculator, the round-off error is</strong> A) 0.00143 B) 0.000143 C)   D)   E)   <div style=padding-top: 35px>
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Question
In the previous problem, the local truncation error in <strong>In the previous problem, the local truncation error in   is</strong> A)   B)   C)   D)   E) unknown <div style=padding-top: 35px> is

A) <strong>In the previous problem, the local truncation error in   is</strong> A)   B)   C)   D)   E) unknown <div style=padding-top: 35px>
B) <strong>In the previous problem, the local truncation error in   is</strong> A)   B)   C)   D)   E) unknown <div style=padding-top: 35px>
C) <strong>In the previous problem, the local truncation error in   is</strong> A)   B)   C)   D)   E) unknown <div style=padding-top: 35px>
D) <strong>In the previous problem, the local truncation error in   is</strong> A)   B)   C)   D)   E) unknown <div style=padding-top: 35px>
E) unknown
Question
The improved Euler's method is what type of Runge-Kutta method?

A) first order
B) second order
C) third order
D) fourth order
E) It is not a Runge-Kutta method
Question
The most popular fourth order Runge-Kutta method for the solution of <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px> is

A) <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B) <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C) <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D) <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E) <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
Question
The local truncation error for the improved Euler's method is

A) <strong>The local truncation error for the improved Euler's method is</strong> A)   B)   C)   D)   E) unknown <div style=padding-top: 35px>
B) <strong>The local truncation error for the improved Euler's method is</strong> A)   B)   C)   D)   E) unknown <div style=padding-top: 35px>
C) <strong>The local truncation error for the improved Euler's method is</strong> A)   B)   C)   D)   E) unknown <div style=padding-top: 35px>
D) <strong>The local truncation error for the improved Euler's method is</strong> A)   B)   C)   D)   E) unknown <div style=padding-top: 35px>
E) unknown
Question
The standard central difference approximation of <strong>The standard central difference approximation of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px> is

A) <strong>The standard central difference approximation of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B) <strong>The standard central difference approximation of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C) <strong>The standard central difference approximation of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D) <strong>The standard central difference approximation of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E) <strong>The standard central difference approximation of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
Question
Using the Adams-Bashforth-Moulton method from the previous three problems, the solution of <strong>Using the Adams-Bashforth-Moulton method from the previous three problems, the solution of   for   with   is</strong> A) 1.5003 B) 1.4978 C) 1.4919 D) 1.4967 E) none of the above <div style=padding-top: 35px> for <strong>Using the Adams-Bashforth-Moulton method from the previous three problems, the solution of   for   with   is</strong> A) 1.5003 B) 1.4978 C) 1.4919 D) 1.4967 E) none of the above <div style=padding-top: 35px> with <strong>Using the Adams-Bashforth-Moulton method from the previous three problems, the solution of   for   with   is</strong> A) 1.5003 B) 1.4978 C) 1.4919 D) 1.4967 E) none of the above <div style=padding-top: 35px> is

A) 1.5003
B) 1.4978
C) 1.4919
D) 1.4967
E) none of the above
Question
Using the Adams-Bashforth method from the previous problem, and using the values <strong>Using the Adams-Bashforth method from the previous problem, and using the values   the solution   for   with   is</strong> A) 1.4978 B) 1.5003 C) 1.4919 D) 1.4967 E) none of the above <div style=padding-top: 35px> the solution <strong>Using the Adams-Bashforth method from the previous problem, and using the values   the solution   for   with   is</strong> A) 1.4978 B) 1.5003 C) 1.4919 D) 1.4967 E) none of the above <div style=padding-top: 35px> for <strong>Using the Adams-Bashforth method from the previous problem, and using the values   the solution   for   with   is</strong> A) 1.4978 B) 1.5003 C) 1.4919 D) 1.4967 E) none of the above <div style=padding-top: 35px> with <strong>Using the Adams-Bashforth method from the previous problem, and using the values   the solution   for   with   is</strong> A) 1.4978 B) 1.5003 C) 1.4919 D) 1.4967 E) none of the above <div style=padding-top: 35px> is

A) 1.4978
B) 1.5003
C) 1.4919
D) 1.4967
E) none of the above
Question
Using the value of <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px> from the previous problem, the Adams-Moulton corrector value for the solution of <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px> is

A) <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
B) <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
C) <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
D) <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
E) none of the above
Question
The Euler's method solution for <strong>The Euler's method solution for   of   using   is</strong> A) 0.14 B) 0.2 C) 0.21 D) 0.11 E) 0.12 <div style=padding-top: 35px> of <strong>The Euler's method solution for   of   using   is</strong> A) 0.14 B) 0.2 C) 0.21 D) 0.11 E) 0.12 <div style=padding-top: 35px> using <strong>The Euler's method solution for   of   using   is</strong> A) 0.14 B) 0.2 C) 0.21 D) 0.11 E) 0.12 <div style=padding-top: 35px> is

A) 0.14
B) 0.2
C) 0.21
D) 0.11
E) 0.12
Question
The Adams-Bashforth formula for finding the solution of <strong>The Adams-Bashforth formula for finding the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px> is

A) <strong>The Adams-Bashforth formula for finding the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
B) <strong>The Adams-Bashforth formula for finding the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
C) <strong>The Adams-Bashforth formula for finding the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
D) <strong>The Adams-Bashforth formula for finding the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
E) none of the above
Question
Which of the following are second order Runge-Kutta methods for the solution of <strong>Which of the following are second order Runge-Kutta methods for the solution of   ? Select all that apply.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px> ? Select all that apply.

A) <strong>Which of the following are second order Runge-Kutta methods for the solution of   ? Select all that apply.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B) <strong>Which of the following are second order Runge-Kutta methods for the solution of   ? Select all that apply.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C) <strong>Which of the following are second order Runge-Kutta methods for the solution of   ? Select all that apply.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D) <strong>Which of the following are second order Runge-Kutta methods for the solution of   ? Select all that apply.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E) <strong>Which of the following are second order Runge-Kutta methods for the solution of   ? Select all that apply.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
Question
The improved Euler's formula for solving <strong>The improved Euler's formula for solving   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px> is

A) <strong>The improved Euler's formula for solving   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B) <strong>The improved Euler's formula for solving   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C) <strong>The improved Euler's formula for solving   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D) <strong>The improved Euler's formula for solving   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E) <strong>The improved Euler's formula for solving   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
Question
The standard backward difference approximation of <strong>The standard backward difference approximation of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px> is

A) <strong>The standard backward difference approximation of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B) <strong>The standard backward difference approximation of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C) <strong>The standard backward difference approximation of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D) <strong>The standard backward difference approximation of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E) <strong>The standard backward difference approximation of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
Question
The solution of <strong>The solution of   , using the improved Euler's method with   is</strong> A) 1.2055 B) 1.21625 C) 1.24205 D) 1.226525 E) 1.235625 <div style=padding-top: 35px> , using the improved Euler's method with <strong>The solution of   , using the improved Euler's method with   is</strong> A) 1.2055 B) 1.21625 C) 1.24205 D) 1.226525 E) 1.235625 <div style=padding-top: 35px> is

A) 1.2055
B) 1.21625
C) 1.24205
D) 1.226525
E) 1.235625
Question
The solution of <strong>The solution of   , using Euler's method with   is</strong> A) 1.01 B) 1.11 C) 1.21 D) 1.22 E) 1.23 <div style=padding-top: 35px> , using Euler's method with <strong>The solution of   , using Euler's method with   is</strong> A) 1.01 B) 1.11 C) 1.21 D) 1.22 E) 1.23 <div style=padding-top: 35px> is

A) 1.01
B) 1.11
C) 1.21
D) 1.22
E) 1.23
Question
Using the notation from the text, the finite difference equation for solving the boundary value problem <strong>Using the notation from the text, the finite difference equation for solving the boundary value problem   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px> is

A) <strong>Using the notation from the text, the finite difference equation for solving the boundary value problem   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B) <strong>Using the notation from the text, the finite difference equation for solving the boundary value problem   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C) <strong>Using the notation from the text, the finite difference equation for solving the boundary value problem   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D) <strong>Using the notation from the text, the finite difference equation for solving the boundary value problem   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E) <strong>Using the notation from the text, the finite difference equation for solving the boundary value problem   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
Question
Using the method from the previous problem, the solution of <strong>Using the method from the previous problem, the solution of   with   is</strong> A) 1.222 B) 1.22 C) 1.2213 D) 1.24 E) 1.21 <div style=padding-top: 35px> with <strong>Using the method from the previous problem, the solution of   with   is</strong> A) 1.222 B) 1.22 C) 1.2213 D) 1.24 E) 1.21 <div style=padding-top: 35px> is

A) 1.222
B) 1.22
C) 1.2213
D) 1.24
E) 1.21
Question
Using the method from the previous problem, the solution of <strong>Using the method from the previous problem, the solution of   with   is</strong> A) 1.241 B) 1.242 C) 1.2422 D) 1.2426 E) 1.2428 <div style=padding-top: 35px> with <strong>Using the method from the previous problem, the solution of   with   is</strong> A) 1.241 B) 1.242 C) 1.2422 D) 1.2426 E) 1.2428 <div style=padding-top: 35px> is

A) 1.241
B) 1.242
C) 1.2422
D) 1.2426
E) 1.2428
Question
When entering the number <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px> into a three digit base ten calculator, the actual value entered is

A) <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B) <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C) <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D) <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E) <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
Question
The solution of <strong>The solution of   for   , using the Runge-Kutta method of order four, and using   , is</strong> A) 0.0909 B) 0.09999 C) 0.09099 D) 0.09899 E) 0.08899 <div style=padding-top: 35px> for <strong>The solution of   for   , using the Runge-Kutta method of order four, and using   , is</strong> A) 0.0909 B) 0.09999 C) 0.09099 D) 0.09899 E) 0.08899 <div style=padding-top: 35px> , using the Runge-Kutta method of order four, and using <strong>The solution of   for   , using the Runge-Kutta method of order four, and using   , is</strong> A) 0.0909 B) 0.09999 C) 0.09099 D) 0.09899 E) 0.08899 <div style=padding-top: 35px> , is

A) 0.0909
B) 0.09999
C) 0.09099
D) 0.09899
E) 0.08899
Question
Using the method from the previous problem, the solution of <strong>Using the method from the previous problem, the solution of   with   is</strong> A) 1.24 B) 1.241 C) 1.214 D) 1.2214 E) 1.224 <div style=padding-top: 35px> with <strong>Using the method from the previous problem, the solution of   with   is</strong> A) 1.24 B) 1.241 C) 1.214 D) 1.2214 E) 1.224 <div style=padding-top: 35px> is

A) 1.24
B) 1.241
C) 1.214
D) 1.2214
E) 1.224
Question
The Euler formula for solving the system <strong>The Euler formula for solving the system   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px> is

A) <strong>The Euler formula for solving the system   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
B) <strong>The Euler formula for solving the system   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
C) <strong>The Euler formula for solving the system   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
D) <strong>The Euler formula for solving the system   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
E) none of the above
Question
A popular second order Runge-Kutta method for the solution of <strong>A popular second order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px> is

A) <strong>A popular second order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
B) <strong>A popular second order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
C) <strong>A popular second order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
D) <strong>A popular second order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
E) none of the above
Question
The Adams-Bashforth formula for finding the solution of <strong>The Adams-Bashforth formula for finding the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px> is

A) <strong>The Adams-Bashforth formula for finding the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
B) <strong>The Adams-Bashforth formula for finding the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
C) <strong>The Adams-Bashforth formula for finding the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
D) <strong>The Adams-Bashforth formula for finding the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
E) none of the above
Question
Using the method from the previous two problems, using the values <strong>Using the method from the previous two problems, using the values   the solution of   with   is</strong> A) 1.4919 B) 1.4967 C) 1.4978 D) 1.5003 E) none of the above <div style=padding-top: 35px> the solution of <strong>Using the method from the previous two problems, using the values   the solution of   with   is</strong> A) 1.4919 B) 1.4967 C) 1.4978 D) 1.5003 E) none of the above <div style=padding-top: 35px> with <strong>Using the method from the previous two problems, using the values   the solution of   with   is</strong> A) 1.4919 B) 1.4967 C) 1.4978 D) 1.5003 E) none of the above <div style=padding-top: 35px> is

A) 1.4919
B) 1.4967
C) 1.4978
D) 1.5003
E) none of the above
Question
The solution of <strong>The solution of   , using the improved Euler's method with   is</strong> A) 1.22125 B) 1.210625 C) 1.226525 D) 1.21525 E) 1.221025 <div style=padding-top: 35px> , using the improved Euler's method with <strong>The solution of   , using the improved Euler's method with   is</strong> A) 1.22125 B) 1.210625 C) 1.226525 D) 1.21525 E) 1.221025 <div style=padding-top: 35px> is

A) 1.22125
B) 1.210625
C) 1.226525
D) 1.21525
E) 1.221025
Question
When entering the number <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px> into a three digit base ten calculator, the actual value entered is

A) <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B) <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C) <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D) <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E) <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
Question
The fourth order Runge-Kutta method for solving <strong>The fourth order Runge-Kutta method for solving   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px> is

A) <strong>The fourth order Runge-Kutta method for solving   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B) <strong>The fourth order Runge-Kutta method for solving   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C) <strong>The fourth order Runge-Kutta method for solving   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D) <strong>The fourth order Runge-Kutta method for solving   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E) <strong>The fourth order Runge-Kutta method for solving   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
Question
The problem <strong>The problem   can be written as a system of two equations as follows.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px> can be written as a system of two equations as follows.

A) <strong>The problem   can be written as a system of two equations as follows.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B) <strong>The problem   can be written as a system of two equations as follows.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C) <strong>The problem   can be written as a system of two equations as follows.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D) <strong>The problem   can be written as a system of two equations as follows.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E) <strong>The problem   can be written as a system of two equations as follows.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
Question
Using the value of <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px> from the previous problem, the Adams-Moulton corrector value for the solution of <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px> is

A) <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
B) <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
C) <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
D) <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above <div style=padding-top: 35px>
E) none of the above
Question
In the previous problem, the local truncation error in <strong>In the previous problem, the local truncation error in   is</strong> A)   B)   C)   D)   E) unknown <div style=padding-top: 35px> is

A) <strong>In the previous problem, the local truncation error in   is</strong> A)   B)   C)   D)   E) unknown <div style=padding-top: 35px>
B) <strong>In the previous problem, the local truncation error in   is</strong> A)   B)   C)   D)   E) unknown <div style=padding-top: 35px>
C) <strong>In the previous problem, the local truncation error in   is</strong> A)   B)   C)   D)   E) unknown <div style=padding-top: 35px>
D) <strong>In the previous problem, the local truncation error in   is</strong> A)   B)   C)   D)   E) unknown <div style=padding-top: 35px>
E) unknown
Question
Euler's formula for solving <strong>Euler's formula for solving   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px> is

A) <strong>Euler's formula for solving   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B) <strong>Euler's formula for solving   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C) <strong>Euler's formula for solving   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D) <strong>Euler's formula for solving   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E) <strong>Euler's formula for solving   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
Question
When entering the number <strong>When entering the number   into a three digit base ten calculator, the round-off error is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px> into a three digit base ten calculator, the round-off error is

A) <strong>When entering the number   into a three digit base ten calculator, the round-off error is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B) <strong>When entering the number   into a three digit base ten calculator, the round-off error is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C) <strong>When entering the number   into a three digit base ten calculator, the round-off error is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D) <strong>When entering the number   into a three digit base ten calculator, the round-off error is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E) <strong>When entering the number   into a three digit base ten calculator, the round-off error is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
Question
Euler's method is what type of Runge-Kutta method?

A) first order
B) second order
C) third order
D) fourth order
E) It is not a Runge-Kutta method
Question
The most popular fourth order Runge-Kutta method for the solution of <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px> is

A) <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B) <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C) <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D) <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E) <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
Question
The solution of <strong>The solution of   , using Euler's method with   is</strong> A) 1.01 B) 1.1 C) 1.11 D) 1.21 E) 1.22 <div style=padding-top: 35px> , using Euler's method with <strong>The solution of   , using Euler's method with   is</strong> A) 1.01 B) 1.1 C) 1.11 D) 1.21 E) 1.22 <div style=padding-top: 35px> is

A) 1.01
B) 1.1
C) 1.11
D) 1.21
E) 1.22
Question
Using the method from the previous problem, the solution of <strong>Using the method from the previous problem, the solution of   with   is</strong> A) 1.2 B) 1.21 C) 1.214 D) 1.22 E) 1.24 <div style=padding-top: 35px> with <strong>Using the method from the previous problem, the solution of   with   is</strong> A) 1.2 B) 1.21 C) 1.214 D) 1.22 E) 1.24 <div style=padding-top: 35px> is

A) 1.2
B) 1.21
C) 1.214
D) 1.22
E) 1.24
Question
Using Euler's method on the previous problem and using a value of <strong>Using Euler's method on the previous problem and using a value of   , the solution for   is</strong> A) 0.11 B) 0.2 C) 0.21 D) 0.22 E) 0.221 <div style=padding-top: 35px> , the solution for <strong>Using Euler's method on the previous problem and using a value of   , the solution for   is</strong> A) 0.11 B) 0.2 C) 0.21 D) 0.22 E) 0.221 <div style=padding-top: 35px> is

A) 0.11
B) 0.2
C) 0.21
D) 0.22
E) 0.221
Question
The local truncation error for the improved Euler's method is

A) unknown
B) <strong>The local truncation error for the improved Euler's method is</strong> A) unknown B)   C)   D)   E)   <div style=padding-top: 35px>
C) <strong>The local truncation error for the improved Euler's method is</strong> A) unknown B)   C)   D)   E)   <div style=padding-top: 35px>
D) <strong>The local truncation error for the improved Euler's method is</strong> A) unknown B)   C)   D)   E)   <div style=padding-top: 35px>
E) <strong>The local truncation error for the improved Euler's method is</strong> A) unknown B)   C)   D)   E)   <div style=padding-top: 35px>
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Deck 9: Numerical Solutions of Ordinary Differential Equations
1
When entering the number <strong>When entering the number   into a three digit base ten calculator, the round-off error is</strong> A) 0.00143 B) 0.000143 C)   D)   E)   into a three digit base ten calculator, the round-off error is

A) 0.00143
B) 0.000143
C) <strong>When entering the number   into a three digit base ten calculator, the round-off error is</strong> A) 0.00143 B) 0.000143 C)   D)   E)
D) <strong>When entering the number   into a three digit base ten calculator, the round-off error is</strong> A) 0.00143 B) 0.000143 C)   D)   E)
E) <strong>When entering the number   into a three digit base ten calculator, the round-off error is</strong> A) 0.00143 B) 0.000143 C)   D)   E)
E
2
In the previous problem, the local truncation error in <strong>In the previous problem, the local truncation error in   is</strong> A)   B)   C)   D)   E) unknown is

A) <strong>In the previous problem, the local truncation error in   is</strong> A)   B)   C)   D)   E) unknown
B) <strong>In the previous problem, the local truncation error in   is</strong> A)   B)   C)   D)   E) unknown
C) <strong>In the previous problem, the local truncation error in   is</strong> A)   B)   C)   D)   E) unknown
D) <strong>In the previous problem, the local truncation error in   is</strong> A)   B)   C)   D)   E) unknown
E) unknown
A
3
The improved Euler's method is what type of Runge-Kutta method?

A) first order
B) second order
C) third order
D) fourth order
E) It is not a Runge-Kutta method
B
4
The most popular fourth order Runge-Kutta method for the solution of <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)   is

A) <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)
B) <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)
C) <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)
D) <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)
E) <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)
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5
The local truncation error for the improved Euler's method is

A) <strong>The local truncation error for the improved Euler's method is</strong> A)   B)   C)   D)   E) unknown
B) <strong>The local truncation error for the improved Euler's method is</strong> A)   B)   C)   D)   E) unknown
C) <strong>The local truncation error for the improved Euler's method is</strong> A)   B)   C)   D)   E) unknown
D) <strong>The local truncation error for the improved Euler's method is</strong> A)   B)   C)   D)   E) unknown
E) unknown
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6
The standard central difference approximation of <strong>The standard central difference approximation of   is</strong> A)   B)   C)   D)   E)   is

A) <strong>The standard central difference approximation of   is</strong> A)   B)   C)   D)   E)
B) <strong>The standard central difference approximation of   is</strong> A)   B)   C)   D)   E)
C) <strong>The standard central difference approximation of   is</strong> A)   B)   C)   D)   E)
D) <strong>The standard central difference approximation of   is</strong> A)   B)   C)   D)   E)
E) <strong>The standard central difference approximation of   is</strong> A)   B)   C)   D)   E)
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7
Using the Adams-Bashforth-Moulton method from the previous three problems, the solution of <strong>Using the Adams-Bashforth-Moulton method from the previous three problems, the solution of   for   with   is</strong> A) 1.5003 B) 1.4978 C) 1.4919 D) 1.4967 E) none of the above for <strong>Using the Adams-Bashforth-Moulton method from the previous three problems, the solution of   for   with   is</strong> A) 1.5003 B) 1.4978 C) 1.4919 D) 1.4967 E) none of the above with <strong>Using the Adams-Bashforth-Moulton method from the previous three problems, the solution of   for   with   is</strong> A) 1.5003 B) 1.4978 C) 1.4919 D) 1.4967 E) none of the above is

A) 1.5003
B) 1.4978
C) 1.4919
D) 1.4967
E) none of the above
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8
Using the Adams-Bashforth method from the previous problem, and using the values <strong>Using the Adams-Bashforth method from the previous problem, and using the values   the solution   for   with   is</strong> A) 1.4978 B) 1.5003 C) 1.4919 D) 1.4967 E) none of the above the solution <strong>Using the Adams-Bashforth method from the previous problem, and using the values   the solution   for   with   is</strong> A) 1.4978 B) 1.5003 C) 1.4919 D) 1.4967 E) none of the above for <strong>Using the Adams-Bashforth method from the previous problem, and using the values   the solution   for   with   is</strong> A) 1.4978 B) 1.5003 C) 1.4919 D) 1.4967 E) none of the above with <strong>Using the Adams-Bashforth method from the previous problem, and using the values   the solution   for   with   is</strong> A) 1.4978 B) 1.5003 C) 1.4919 D) 1.4967 E) none of the above is

A) 1.4978
B) 1.5003
C) 1.4919
D) 1.4967
E) none of the above
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9
Using the value of <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above from the previous problem, the Adams-Moulton corrector value for the solution of <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above is

A) <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above
B) <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above
C) <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above
D) <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above
E) none of the above
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10
The Euler's method solution for <strong>The Euler's method solution for   of   using   is</strong> A) 0.14 B) 0.2 C) 0.21 D) 0.11 E) 0.12 of <strong>The Euler's method solution for   of   using   is</strong> A) 0.14 B) 0.2 C) 0.21 D) 0.11 E) 0.12 using <strong>The Euler's method solution for   of   using   is</strong> A) 0.14 B) 0.2 C) 0.21 D) 0.11 E) 0.12 is

A) 0.14
B) 0.2
C) 0.21
D) 0.11
E) 0.12
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11
The Adams-Bashforth formula for finding the solution of <strong>The Adams-Bashforth formula for finding the solution of   is</strong> A)   B)   C)   D)   E) none of the above is

A) <strong>The Adams-Bashforth formula for finding the solution of   is</strong> A)   B)   C)   D)   E) none of the above
B) <strong>The Adams-Bashforth formula for finding the solution of   is</strong> A)   B)   C)   D)   E) none of the above
C) <strong>The Adams-Bashforth formula for finding the solution of   is</strong> A)   B)   C)   D)   E) none of the above
D) <strong>The Adams-Bashforth formula for finding the solution of   is</strong> A)   B)   C)   D)   E) none of the above
E) none of the above
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12
Which of the following are second order Runge-Kutta methods for the solution of <strong>Which of the following are second order Runge-Kutta methods for the solution of   ? Select all that apply.</strong> A)   B)   C)   D)   E)   ? Select all that apply.

A) <strong>Which of the following are second order Runge-Kutta methods for the solution of   ? Select all that apply.</strong> A)   B)   C)   D)   E)
B) <strong>Which of the following are second order Runge-Kutta methods for the solution of   ? Select all that apply.</strong> A)   B)   C)   D)   E)
C) <strong>Which of the following are second order Runge-Kutta methods for the solution of   ? Select all that apply.</strong> A)   B)   C)   D)   E)
D) <strong>Which of the following are second order Runge-Kutta methods for the solution of   ? Select all that apply.</strong> A)   B)   C)   D)   E)
E) <strong>Which of the following are second order Runge-Kutta methods for the solution of   ? Select all that apply.</strong> A)   B)   C)   D)   E)
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13
The improved Euler's formula for solving <strong>The improved Euler's formula for solving   is</strong> A)   B)   C)   D)   E)   is

A) <strong>The improved Euler's formula for solving   is</strong> A)   B)   C)   D)   E)
B) <strong>The improved Euler's formula for solving   is</strong> A)   B)   C)   D)   E)
C) <strong>The improved Euler's formula for solving   is</strong> A)   B)   C)   D)   E)
D) <strong>The improved Euler's formula for solving   is</strong> A)   B)   C)   D)   E)
E) <strong>The improved Euler's formula for solving   is</strong> A)   B)   C)   D)   E)
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14
The standard backward difference approximation of <strong>The standard backward difference approximation of   is</strong> A)   B)   C)   D)   E)   is

A) <strong>The standard backward difference approximation of   is</strong> A)   B)   C)   D)   E)
B) <strong>The standard backward difference approximation of   is</strong> A)   B)   C)   D)   E)
C) <strong>The standard backward difference approximation of   is</strong> A)   B)   C)   D)   E)
D) <strong>The standard backward difference approximation of   is</strong> A)   B)   C)   D)   E)
E) <strong>The standard backward difference approximation of   is</strong> A)   B)   C)   D)   E)
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15
The solution of <strong>The solution of   , using the improved Euler's method with   is</strong> A) 1.2055 B) 1.21625 C) 1.24205 D) 1.226525 E) 1.235625 , using the improved Euler's method with <strong>The solution of   , using the improved Euler's method with   is</strong> A) 1.2055 B) 1.21625 C) 1.24205 D) 1.226525 E) 1.235625 is

A) 1.2055
B) 1.21625
C) 1.24205
D) 1.226525
E) 1.235625
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16
The solution of <strong>The solution of   , using Euler's method with   is</strong> A) 1.01 B) 1.11 C) 1.21 D) 1.22 E) 1.23 , using Euler's method with <strong>The solution of   , using Euler's method with   is</strong> A) 1.01 B) 1.11 C) 1.21 D) 1.22 E) 1.23 is

A) 1.01
B) 1.11
C) 1.21
D) 1.22
E) 1.23
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17
Using the notation from the text, the finite difference equation for solving the boundary value problem <strong>Using the notation from the text, the finite difference equation for solving the boundary value problem   is</strong> A)   B)   C)   D)   E)   is

A) <strong>Using the notation from the text, the finite difference equation for solving the boundary value problem   is</strong> A)   B)   C)   D)   E)
B) <strong>Using the notation from the text, the finite difference equation for solving the boundary value problem   is</strong> A)   B)   C)   D)   E)
C) <strong>Using the notation from the text, the finite difference equation for solving the boundary value problem   is</strong> A)   B)   C)   D)   E)
D) <strong>Using the notation from the text, the finite difference equation for solving the boundary value problem   is</strong> A)   B)   C)   D)   E)
E) <strong>Using the notation from the text, the finite difference equation for solving the boundary value problem   is</strong> A)   B)   C)   D)   E)
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18
Using the method from the previous problem, the solution of <strong>Using the method from the previous problem, the solution of   with   is</strong> A) 1.222 B) 1.22 C) 1.2213 D) 1.24 E) 1.21 with <strong>Using the method from the previous problem, the solution of   with   is</strong> A) 1.222 B) 1.22 C) 1.2213 D) 1.24 E) 1.21 is

A) 1.222
B) 1.22
C) 1.2213
D) 1.24
E) 1.21
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19
Using the method from the previous problem, the solution of <strong>Using the method from the previous problem, the solution of   with   is</strong> A) 1.241 B) 1.242 C) 1.2422 D) 1.2426 E) 1.2428 with <strong>Using the method from the previous problem, the solution of   with   is</strong> A) 1.241 B) 1.242 C) 1.2422 D) 1.2426 E) 1.2428 is

A) 1.241
B) 1.242
C) 1.2422
D) 1.2426
E) 1.2428
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20
When entering the number <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)   into a three digit base ten calculator, the actual value entered is

A) <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)
B) <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)
C) <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)
D) <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)
E) <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)
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21
The solution of <strong>The solution of   for   , using the Runge-Kutta method of order four, and using   , is</strong> A) 0.0909 B) 0.09999 C) 0.09099 D) 0.09899 E) 0.08899 for <strong>The solution of   for   , using the Runge-Kutta method of order four, and using   , is</strong> A) 0.0909 B) 0.09999 C) 0.09099 D) 0.09899 E) 0.08899 , using the Runge-Kutta method of order four, and using <strong>The solution of   for   , using the Runge-Kutta method of order four, and using   , is</strong> A) 0.0909 B) 0.09999 C) 0.09099 D) 0.09899 E) 0.08899 , is

A) 0.0909
B) 0.09999
C) 0.09099
D) 0.09899
E) 0.08899
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22
Using the method from the previous problem, the solution of <strong>Using the method from the previous problem, the solution of   with   is</strong> A) 1.24 B) 1.241 C) 1.214 D) 1.2214 E) 1.224 with <strong>Using the method from the previous problem, the solution of   with   is</strong> A) 1.24 B) 1.241 C) 1.214 D) 1.2214 E) 1.224 is

A) 1.24
B) 1.241
C) 1.214
D) 1.2214
E) 1.224
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23
The Euler formula for solving the system <strong>The Euler formula for solving the system   is</strong> A)   B)   C)   D)   E) none of the above is

A) <strong>The Euler formula for solving the system   is</strong> A)   B)   C)   D)   E) none of the above
B) <strong>The Euler formula for solving the system   is</strong> A)   B)   C)   D)   E) none of the above
C) <strong>The Euler formula for solving the system   is</strong> A)   B)   C)   D)   E) none of the above
D) <strong>The Euler formula for solving the system   is</strong> A)   B)   C)   D)   E) none of the above
E) none of the above
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24
A popular second order Runge-Kutta method for the solution of <strong>A popular second order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E) none of the above is

A) <strong>A popular second order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E) none of the above
B) <strong>A popular second order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E) none of the above
C) <strong>A popular second order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E) none of the above
D) <strong>A popular second order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E) none of the above
E) none of the above
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25
The Adams-Bashforth formula for finding the solution of <strong>The Adams-Bashforth formula for finding the solution of   is</strong> A)   B)   C)   D)   E) none of the above is

A) <strong>The Adams-Bashforth formula for finding the solution of   is</strong> A)   B)   C)   D)   E) none of the above
B) <strong>The Adams-Bashforth formula for finding the solution of   is</strong> A)   B)   C)   D)   E) none of the above
C) <strong>The Adams-Bashforth formula for finding the solution of   is</strong> A)   B)   C)   D)   E) none of the above
D) <strong>The Adams-Bashforth formula for finding the solution of   is</strong> A)   B)   C)   D)   E) none of the above
E) none of the above
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26
Using the method from the previous two problems, using the values <strong>Using the method from the previous two problems, using the values   the solution of   with   is</strong> A) 1.4919 B) 1.4967 C) 1.4978 D) 1.5003 E) none of the above the solution of <strong>Using the method from the previous two problems, using the values   the solution of   with   is</strong> A) 1.4919 B) 1.4967 C) 1.4978 D) 1.5003 E) none of the above with <strong>Using the method from the previous two problems, using the values   the solution of   with   is</strong> A) 1.4919 B) 1.4967 C) 1.4978 D) 1.5003 E) none of the above is

A) 1.4919
B) 1.4967
C) 1.4978
D) 1.5003
E) none of the above
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27
The solution of <strong>The solution of   , using the improved Euler's method with   is</strong> A) 1.22125 B) 1.210625 C) 1.226525 D) 1.21525 E) 1.221025 , using the improved Euler's method with <strong>The solution of   , using the improved Euler's method with   is</strong> A) 1.22125 B) 1.210625 C) 1.226525 D) 1.21525 E) 1.221025 is

A) 1.22125
B) 1.210625
C) 1.226525
D) 1.21525
E) 1.221025
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28
When entering the number <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)   into a three digit base ten calculator, the actual value entered is

A) <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)
B) <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)
C) <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)
D) <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)
E) <strong>When entering the number   into a three digit base ten calculator, the actual value entered is</strong> A)   B)   C)   D)   E)
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29
The fourth order Runge-Kutta method for solving <strong>The fourth order Runge-Kutta method for solving   is</strong> A)   B)   C)   D)   E)   is

A) <strong>The fourth order Runge-Kutta method for solving   is</strong> A)   B)   C)   D)   E)
B) <strong>The fourth order Runge-Kutta method for solving   is</strong> A)   B)   C)   D)   E)
C) <strong>The fourth order Runge-Kutta method for solving   is</strong> A)   B)   C)   D)   E)
D) <strong>The fourth order Runge-Kutta method for solving   is</strong> A)   B)   C)   D)   E)
E) <strong>The fourth order Runge-Kutta method for solving   is</strong> A)   B)   C)   D)   E)
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30
The problem <strong>The problem   can be written as a system of two equations as follows.</strong> A)   B)   C)   D)   E)   can be written as a system of two equations as follows.

A) <strong>The problem   can be written as a system of two equations as follows.</strong> A)   B)   C)   D)   E)
B) <strong>The problem   can be written as a system of two equations as follows.</strong> A)   B)   C)   D)   E)
C) <strong>The problem   can be written as a system of two equations as follows.</strong> A)   B)   C)   D)   E)
D) <strong>The problem   can be written as a system of two equations as follows.</strong> A)   B)   C)   D)   E)
E) <strong>The problem   can be written as a system of two equations as follows.</strong> A)   B)   C)   D)   E)
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31
Using the value of <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above from the previous problem, the Adams-Moulton corrector value for the solution of <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above is

A) <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above
B) <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above
C) <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above
D) <strong>Using the value of   from the previous problem, the Adams-Moulton corrector value for the solution of   is</strong> A)   B)   C)   D)   E) none of the above
E) none of the above
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32
In the previous problem, the local truncation error in <strong>In the previous problem, the local truncation error in   is</strong> A)   B)   C)   D)   E) unknown is

A) <strong>In the previous problem, the local truncation error in   is</strong> A)   B)   C)   D)   E) unknown
B) <strong>In the previous problem, the local truncation error in   is</strong> A)   B)   C)   D)   E) unknown
C) <strong>In the previous problem, the local truncation error in   is</strong> A)   B)   C)   D)   E) unknown
D) <strong>In the previous problem, the local truncation error in   is</strong> A)   B)   C)   D)   E) unknown
E) unknown
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33
Euler's formula for solving <strong>Euler's formula for solving   is</strong> A)   B)   C)   D)   E)   is

A) <strong>Euler's formula for solving   is</strong> A)   B)   C)   D)   E)
B) <strong>Euler's formula for solving   is</strong> A)   B)   C)   D)   E)
C) <strong>Euler's formula for solving   is</strong> A)   B)   C)   D)   E)
D) <strong>Euler's formula for solving   is</strong> A)   B)   C)   D)   E)
E) <strong>Euler's formula for solving   is</strong> A)   B)   C)   D)   E)
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34
When entering the number <strong>When entering the number   into a three digit base ten calculator, the round-off error is</strong> A)   B)   C)   D)   E)   into a three digit base ten calculator, the round-off error is

A) <strong>When entering the number   into a three digit base ten calculator, the round-off error is</strong> A)   B)   C)   D)   E)
B) <strong>When entering the number   into a three digit base ten calculator, the round-off error is</strong> A)   B)   C)   D)   E)
C) <strong>When entering the number   into a three digit base ten calculator, the round-off error is</strong> A)   B)   C)   D)   E)
D) <strong>When entering the number   into a three digit base ten calculator, the round-off error is</strong> A)   B)   C)   D)   E)
E) <strong>When entering the number   into a three digit base ten calculator, the round-off error is</strong> A)   B)   C)   D)   E)
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35
Euler's method is what type of Runge-Kutta method?

A) first order
B) second order
C) third order
D) fourth order
E) It is not a Runge-Kutta method
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36
The most popular fourth order Runge-Kutta method for the solution of <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)   is

A) <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)
B) <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)
C) <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)
D) <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)
E) <strong>The most popular fourth order Runge-Kutta method for the solution of   is</strong> A)   B)   C)   D)   E)
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37
The solution of <strong>The solution of   , using Euler's method with   is</strong> A) 1.01 B) 1.1 C) 1.11 D) 1.21 E) 1.22 , using Euler's method with <strong>The solution of   , using Euler's method with   is</strong> A) 1.01 B) 1.1 C) 1.11 D) 1.21 E) 1.22 is

A) 1.01
B) 1.1
C) 1.11
D) 1.21
E) 1.22
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38
Using the method from the previous problem, the solution of <strong>Using the method from the previous problem, the solution of   with   is</strong> A) 1.2 B) 1.21 C) 1.214 D) 1.22 E) 1.24 with <strong>Using the method from the previous problem, the solution of   with   is</strong> A) 1.2 B) 1.21 C) 1.214 D) 1.22 E) 1.24 is

A) 1.2
B) 1.21
C) 1.214
D) 1.22
E) 1.24
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39
Using Euler's method on the previous problem and using a value of <strong>Using Euler's method on the previous problem and using a value of   , the solution for   is</strong> A) 0.11 B) 0.2 C) 0.21 D) 0.22 E) 0.221 , the solution for <strong>Using Euler's method on the previous problem and using a value of   , the solution for   is</strong> A) 0.11 B) 0.2 C) 0.21 D) 0.22 E) 0.221 is

A) 0.11
B) 0.2
C) 0.21
D) 0.22
E) 0.221
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40
The local truncation error for the improved Euler's method is

A) unknown
B) <strong>The local truncation error for the improved Euler's method is</strong> A) unknown B)   C)   D)   E)
C) <strong>The local truncation error for the improved Euler's method is</strong> A) unknown B)   C)   D)   E)
D) <strong>The local truncation error for the improved Euler's method is</strong> A) unknown B)   C)   D)   E)
E) <strong>The local truncation error for the improved Euler's method is</strong> A) unknown B)   C)   D)   E)
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