Consider the following ANOVA table. \(\begin{array}{llll} \begin{array}{l} \text { Source } \\ \text { of Variation } \end{array} & \begin{array}{l} \text { Sum } \\ \text { of Squares } \end{array} & \begin{array}{l} \text { Degrees } \\ \text { of Freed om } \end{array} & \begin{array}{l} \text { Mean } \\ \text { Square } \end{array}&F \\ \text { Between Treatments } & 2073.6 & 4 & \\ \text { Between Blocks } & 6000 & 5 & 1200 \\ \text { Error } & & 20 & 288 \\ \text { Total } & & 29 & \end{array}\) The sum of squares due to error equals

A) 13833.6. B) 2073.6. C) 5760. D) 6000. A) 13833.6. B) 2073.6. C) 5760. D) 6000.

To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the 3 treatments.You are given the results below. \(\begin{array}{lllll} \text { Treatment } &&{\text { Observations }} \\ \text { A } & 20 & 30 & 25 & 33 \\ \text { B } & 22 & 26 & 20 & 28 \\ \mathrm{C} & 40 & 30 & 28 & 22 \end{array}\) The null hypothesis is to be tested at the 1% level of significance.The null hypothesis

A) should be rejected. B) should not be rejected. C) should be revised. D) should not be tested. A) should be rejected. B) should not be rejected. C) should be revised. D) should not be tested.

In an analysis of variance, one estimate of σ2 is based upon the differences between the treatment means and the

A) means of each sample. B) overall sample mean. C) sum of observations. D) population means. A) means of each sample. B) overall sample mean. C) sum of observations. D) population means.

To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the 3 treatments.You are given the results below. \(\begin{array}{lllll} \text { Treatment } &&{\text { Observations }} \\ \text { A } & 20 & 30 & 25 & 33 \\ \text { B } & 22 & 26 & 20 & 28 \\ \mathrm{C} & 40 & 30 & 28 & 22 \end{array}\) The mean square due to error (MSE) equals

A) 1.872. B) 5.86. C) 34. D) 36. A) 1.872. B) 5.86. C) 34. D) 36.

Consider the following information. \(\begin{array}{ll} \mathrm{SSTR}=6750 & H 0: \mu 1=\mu 2=\mu 3=\mu 4 \\ \mathrm{SSE}=8000 & H_{\mathrm{a}}: \text { At least one mean is different } \end{array}\) The test statistic to test the null hypothesis equals

A) .22. B) .84. C) 4.22. D) 4.50. A) .22. B) .84. C) 4.22. D) 4.50.

Part of an ANOVA table is shown below. \[\begin{array} { l l l l l } \text { Source of } & \text { Sum of } & \text { Degrees of } & \text { Mean } \\ \text { Variation } & \text { Squares } & \text { Freedom } & \text { Square } & F \\ \text { Between Treatments } & 64 & &&8 \\ \text { Within Treatments (Error) } & &&2 & \\ \text { TOTAL } &100 \end{array}\] The number of degrees of freedom corresponding to within-treatments is

A) 22. B) 4. C) 5. D) 18. A) 22. B) 4. C) 5. D) 18.

Part of an ANOVA table is shown below. \[\begin{array} { l l l l l } \text { Source of } & \text { Sum of } & \text { Degrees of } & \text { Mean } \\ \text { Variation } & \text { Squares } & \text { Freedom } & \text { Square } & F \\ \text { Between Treatments } & 180 & 3 & \\ \text { Within Treatments (Error) } & & & \\ \text { TOTAL } & 480 & 18 & \end{array}\] The mean square due to error (MSE) is

A) 60. B) 15. C) 18. D) 20. A) 60. B) 15. C) 18. D) 20.

Exam 13: Experimental Design and Analysis of Variance

In a completely randomized experimental design involving five treatments, 13 observations were recorded for each of the five treatments (a total of 65 observations).Also, the design provided the following information. SSTR = 200 (Sum of Squares Due to Treatments) SST = 800 (Total Sum of Squares) The mean square due to treatments (MSTR) is

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Question 1

Correct Answer:

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C

An ANOVA procedure is used for data obtained from four populations.Four samples, each comprised of 30 observations, were taken from the four populations.The numerator and denominator (respectively) degrees of freedom for the critical value of F are

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Question 2

Correct Answer:

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D

An ANOVA procedure is used for data that was obtained from four sample groups each comprised of five observations.The degrees of freedom for the critical value of F are

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Question 3

Correct Answer:

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B

The critical F value with 6 numerator and 60 denominator degrees of freedom at α = .05 is

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Question 4

An ANOVA procedure is used for data obtained from five populations.Five samples, each comprised of 20 observations, were taken from the five populations.The numerator and denominator (respectively) degrees of freedom for the critical value of F are

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Question 5

Which of the following is not a required assumption for the analysis of variance?

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Question 6

In an analysis of variance problem if SST = 120 and SSTR = 80, then SSE is

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Question 7

Consider the following ANOVA table. Source of Variation Sum of Squares Degrees of Freed om Mean Square F Between Treatments 2073.6 4 Between Blocks 6000 5 1200 Error 20 288 Total 29 The sum of squares due to error equals

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Question 8

In factorial designs, the response produced when the treatments of one factor interact with the treatments of another in influencing the response variable is known as

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Question 9

In a completely randomized experimental design involving five treatments, 13 observations were recorded for each of the five treatments (a total of 65 observations).Also, the design provided the following information. SSTR = 200 (Sum of Squares Due to Treatments) SST = 800 (Total Sum of Squares) The number of degrees of freedom corresponding to within-treatments is

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Question 10

To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the 3 treatments.You are given the results below. Treatment Observations A 20 30 25 33 B 22 26 20 28 40 30 28 22 The null hypothesis is to be tested at the 1% level of significance.The null hypothesis

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Question 11

In a completely randomized experimental design involving five treatments, 13 observations were recorded for each of the five treatments (a total of 65 observations).The following information is provided. SSTR = 200 (Sum of Squares Due to Treatments) SST = 800 (Total Sum of Squares) If we want to determine whether or not the means of the five populations are equal, the p-value is

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Question 12

In an analysis of variance, one estimate of σ² is based upon the differences between the treatment means and the

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Question 13

A completely randomized design is useful when the experimental units are

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Question 14

To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the 3 treatments.You are given the results below. Treatment Observations A 20 30 25 33 B 22 26 20 28 40 30 28 22 The mean square due to error (MSE) equals

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Question 15

Consider the following information. =6750 H0:\mu1=\mu2=\mu3=\mu4 =8000 : At least one mean is different The test statistic to test the null hypothesis equals

(Multiple Choice)

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Question 16

In a completely randomized experimental design involving five treatments, 13 observations were recorded for each of the five treatments (a total of 65 observations).The following information is provided. SSTR = 200 (Sum of Squares Due to Treatments) SST = 800 (Total Sum of Squares) The test statistic is

(Multiple Choice)

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Question 17

Part of an ANOVA table is shown below. Source of Sum of Degrees of Mean Variation Squares Freedom Square F Between Treatments 64 8 Within Treatments (Error) 2 TOTAL 100 The number of degrees of freedom corresponding to within-treatments is

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Question 18

In testing for the equality of k population means, the number of treatments is

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Question 19

Part of an ANOVA table is shown below. Source of Sum of Degrees of Mean Variation Squares Freedom Square F Between Treatments 180 3 Within Treatments (Error) TOTAL 480 18 The mean square due to error (MSE) is

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Question 20

An ANOVA procedure is used for data obtained from four populations.Four samples, each comprised of 30 observations, were taken from the four populations.The numerator and denominator (respectively) degrees of freedom for the critical value of F are

An ANOVA procedure is used for data that was obtained from four sample groups each comprised of five observations.The degrees of freedom for the critical value of F are

The critical F value with 6 numerator and 60 denominator degrees of freedom at α = .05 is

An ANOVA procedure is used for data obtained from five populations.Five samples, each comprised of 20 observations, were taken from the five populations.The numerator and denominator (respectively) degrees of freedom for the critical value of F are

Which of the following is not a required assumption for the analysis of variance?

In an analysis of variance problem if SST = 120 and SSTR = 80, then SSE is

Consider the following ANOVA table. Source of Variation Sum of Squares Degrees of Freed om Mean Square F Between Treatments 2073.6 4 Between Blocks 6000 5 1200 Error 20 288 Total 29 The sum of squares due to error equals

In factorial designs, the response produced when the treatments of one factor interact with the treatments of another in influencing the response variable is known as

In an analysis of variance, one estimate of σ² is based upon the differences between the treatment means and the

A completely randomized design is useful when the experimental units are

To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the 3 treatments.You are given the results below. Treatment Observations A 20 30 25 33 B 22 26 20 28 40 30 28 22 The mean square due to error (MSE) equals

Consider the following information. =6750 H0:\mu1=\mu2=\mu3=\mu4 =8000 : At least one mean is different The test statistic to test the null hypothesis equals

Part of an ANOVA table is shown below. Source of Sum of Degrees of Mean Variation Squares Freedom Square F Between Treatments 64 8 Within Treatments (Error) 2 TOTAL 100 The number of degrees of freedom corresponding to within-treatments is

In testing for the equality of k population means, the number of treatments is

Part of an ANOVA table is shown below. Source of Sum of Degrees of Mean Variation Squares Freedom Square F Between Treatments 180 3 Within Treatments (Error) TOTAL 480 18 The mean square due to error (MSE) is

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Exam 13: Experimental Design and Analysis of Variance

An ANOVA procedure is used for data obtained from four populations.Four samples, each comprised of 30 observations, were taken from the four populations.The numerator and denominator (respectively) degrees of freedom for the critical value of F are

An ANOVA procedure is used for data that was obtained from four sample groups each comprised of five observations.The degrees of freedom for the critical value of F are

The critical F value with 6 numerator and 60 denominator degrees of freedom at α = .05 is

An ANOVA procedure is used for data obtained from five populations.Five samples, each comprised of 20 observations, were taken from the five populations.The numerator and denominator (respectively) degrees of freedom for the critical value of F are

Which of the following is not a required assumption for the analysis of variance?

In an analysis of variance problem if SST = 120 and SSTR = 80, then SSE is

Consider the following ANOVA table. Source of Variation Sum of Squares Degrees of Freed om Mean Square F Between Treatments 2073.6 4 Between Blocks 6000 5 1200 Error 20 288 Total 29 The sum of squares due to error equals

In factorial designs, the response produced when the treatments of one factor interact with the treatments of another in influencing the response variable is known as

In an analysis of variance, one estimate of σ2 is based upon the differences between the treatment means and the

A completely randomized design is useful when the experimental units are

To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the 3 treatments.You are given the results below. Treatment Observations A 20 30 25 33 B 22 26 20 28 40 30 28 22 The mean square due to error (MSE) equals

Consider the following information. =6750 H0:\mu1=\mu2=\mu3=\mu4 =8000 : At least one mean is different The test statistic to test the null hypothesis equals

Part of an ANOVA table is shown below. Source of Sum of Degrees of Mean Variation Squares Freedom Square F Between Treatments 64 8 Within Treatments (Error) 2 TOTAL 100 The number of degrees of freedom corresponding to within-treatments is

In testing for the equality of k population means, the number of treatments is​

Part of an ANOVA table is shown below. Source of Sum of Degrees of Mean Variation Squares Freedom Square F Between Treatments 180 3 Within Treatments (Error) TOTAL 480 18 The mean square due to error (MSE) is

Data and Statistics

Descriptive Statistics: Tabulargraphical

Descriptive Statistics: Numerical

Introduction to Probability

Discrete Probability Distributions

Continuous Probability Distributions

Sampling and Sampling Distributions

Interval Estimation

Hypothesis Tests

Inference About Means and Proportions With Two Populations

Inferences About Population Variances

Comparing Multiple Proportions, Test of Independence and Goodness of Fit

Simple Linear Regression

Multiple Regression

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In an analysis of variance, one estimate of σ² is based upon the differences between the treatment means and the

In testing for the equality of k population means, the number of treatments is