Question 1

Solve for $$x : 2 ^ { x + 1 } = 2 ^ { 3 }$$

Accepted Answer

A) x = -2 
B) x = 0 
C) x = -3 
D) x = 2 
A) x = -2 
B) x = 0 
C) x = -3 
D) x = 2

Question 2

Evaluate: e-5

Accepted Answer

A) 1 
B) -148.4131591 
C) 1.221402758 
D) 0.006737947 
A) 1 
B) -148.4131591 
C) 1.221402758 
D) 0.006737947

Question 3

The compound amount when an investment is compounded continuously is A = Peni Where A = compound amount, P = original principal, n = number of years, and i = interest rate per year. Let P = 400, I = 0.05, and n = 3, then find A.

Accepted Answer

A) $1,858.93 
B) $3717.87 
C) $929.47 
D) $464.73 
A) $1,858.93 
B) $3717.87 
C) $929.47 
D) $464.73

Question 4

The formula for finding the monthly payment for an amortized loan is:
$M = P \left[ \frac { R } { 1 - ( 1 + R ) ^ { - N } } \right]$
 where M is the monthly payment, R is the interest rate PER MONTH, and N is the number of months. Find the monthly payment on a home loan of $100,000 at 6% for 30 years.

Accepted Answer

The answer of The formula for finding the monthly payment...

Question 5

The formula for finding the amount an investment grows to if it is compounded continuously is A = Pert, A is the accumulated amount, P is the principal invested, e is the natural exponent, r is the rate per year, and t is the number of years. Find the accumulated amount A if $4,500 is compounded continuously for 6 years at 7.5% per year.

Accepted Answer

The answer of The formula for finding the amount an...

Question 6

Using the formula $A = P \left( 1 + \frac { r } { n } \right) ^ { n t }$ , find the interest on an investment of $1200, at an interest rate of 12% for 5 years, if the interest is compounded quarterly.

Accepted Answer

The answer of Using the formula \(A = P \left(...

Question 7

Solve for $$x : 3 ^ { x - 6} = \frac { 1 } { 81 }$$

Accepted Answer

A) x = 2 
B) x = 1 
C) x = -5 
D) x = -4 
A) x = 2 
B) x = 1 
C) x = -5 
D) x = -4

Question 8

A suburb city presently has a population of 100,000 people. In 25 years, what would its estimated population be if 
$P=P o{e} ^{0.02 t }?$

Accepted Answer

A) 164,872 
B) 1,318,977 
C) 329,744 
D) 659,489 
A) 164,872 
B) 1,318,977 
C) 329,744 
D) 659,489

Question 9

Evaluate: 5-1.2

Accepted Answer

A) -6 
B) 0.145 
C) -6.899 
D) 2.44 
A) -6 
B) 0.145 
C) -6.899 
D) 2.44

Question 10

Use the compound amount formula $A = P \left( 1 + \frac { r } { n } \right) ^ { n t }$ to find the accumulated amount on an investment of $\$ 1,500$ invested at an interest rate of $10 \%$ for 18 months, if the interest is compounded weekly.

Accepted Answer

A) $9,058.80 
B) $1,795.52 
C) $1,552.78 
D) $1,742.50 
A) $9,058.80 
B) $1,795.52 
C) $1,552.78 
D) $1,742.50

Question 11

Evaluate: $2 ^ { 5 }$

Accepted Answer

A)  -32 
B)  32 
C)  $\frac { - 1 } { 32 }$ 
D)  $\frac { 1 } { 32 }$ 
A)  -32 
B)  32 
C)  $\frac { - 1 } { 32 }$ 
D)  $\frac { 1 } { 32 }$

Question 12

$$e ^ { - 0.01 } =$$

Accepted Answer

A) 1.9801 
B) 0.9900 
C) 3.9602 
D) 7.9204 
A) 1.9801 
B) 0.9900 
C) 3.9602 
D) 7.9204

Question 13

Solve for $$x : 2 ^ { x - 5 } = 2 ^ { - 2 }$$

Accepted Answer

A) x = 2 
B) x = -3 
C) x = 0 
D) x = 3 
A) x = 2 
B) x = -3 
C) x = 0 
D) x = 3

Question 14

The compound amount when an investment is compounded continuously is A = Peni Where A = compound amount, P = original principal, n = # of years, and i = interest rate per year. Find the compound amount of an investment of $2,500 at an interest rate of 10% for 2 years if it is compounded continuously.

Accepted Answer

A) $3,000.00 
B) $3,053.51 
C) $4,023.59 
D) $3,025.00 
A) $3,000.00 
B) $3,053.51 
C) $4,023.59 
D) $3,025.00

Question 15

Charlie invested $2400 at an interest rate of 5% for 5 years, where it was compounded continuously. If A = Peni, calculate the accumulated amount.

Accepted Answer

A) $12,326.64 
B) $3,081.66 
C) $6,163.32 
D) $24,653.29 
A) $12,326.64 
B) $3,081.66 
C) $6,163.32 
D) $24,653.29

Question 16

The compound amount when an investment is compounded continuously is expressed by the formula A = Peni, where A is the compound amount, n is the number of years, and i is the interest rate per year. Find the compound amount of an investment of $2500 at an interest rate of 10% for 2 years if it is compounded continuously.

Accepted Answer

A) $3,000.00 
B) $3,025.00 
C) $4,023.59 
D) $3,053.51 
A) $3,000.00 
B) $3,025.00 
C) $4,023.59 
D) $3,053.51

Question 17

The compound amount when an investment is compounded continuously is expressed by the formula A = Peni, where A is the compound amount, P is the principal, n is the number of years, and i is the interest rate per year. Find the compound amount of an investment of $1,000 at an interest rate of 8% for 20 years if it is compounded continuously.

Accepted Answer

A) $4,953.03 
B) $470.00 
C) $39,810.72 
D) $4,660.96 
A) $4,953.03 
B) $470.00 
C) $39,810.72 
D) $4,660.96

Question 18

Solve for
 $x : 6 ^ { x } = \frac { 1 } { 36 }$

Accepted Answer

The answer of Solve for
 \(x : 6 ^ {...

Question 19

Solve for $$x : 2 x = \frac { 1 } { 128 }$$

Accepted Answer

A) x = -7 
B) x = 0 
C) x = -8 
D) x = 7 
A) x = -7 
B) x = 0 
C) x = -8 
D) x = 7

Question 20

Evaluate: $$2 ^ { x } = 128$$

Accepted Answer

A) x = 56 
B) x = 7 
C) x = 8 
D) x = 11.3137 
A) x = 56 
B) x = 7 
C) x = 8 
D) x = 11.3137

Solve for $x : 2 ^ { x + 1 } = 2 ^ { 3 }$

Evaluate: e-5

The compound amount when an investment is compounded continuously is A = Peni Where A = compound amount, P = original principal, n = number of years, and i = interest rate per year. Let P = 400, I = 0.05, and n = 3, then find A.

Using the formula $A = P \left( 1 + \frac { r } { n } \right) ^ { n t }$ , find the interest on an investment of $1200, at an interest rate of 12% for 5 years, if the interest is compounded quarterly.

Solve for $x : 3 ^ { x - 6} = \frac { 1 } { 81 }$

A suburb city presently has a population of 100,000 people. In 25 years, what would its estimated population be if $P=P o{e} ^{0.02 t }?$

Evaluate: 5-1.2

Use the compound amount formula $A = P \left( 1 + \frac { r } { n } \right) ^ { n t }$ to find the accumulated amount on an investment of $\$ 1,500$ invested at an interest rate of $10 \%$ for 18 months, if the interest is compounded weekly.

Evaluate: $2 ^ { 5 }$

$e ^ { - 0.01 } =$

Solve for $x : 2 ^ { x - 5 } = 2 ^ { - 2 }$

Charlie invested $2400 at an interest rate of 5% for 5 years, where it was compounded continuously. If A = Peni, calculate the accumulated amount.

Solve for $x : 6 ^ { x } = \frac { 1 } { 36 }$

Solve for $x : 2 x = \frac { 1 } { 128 }$

Evaluate: $2 ^ { x } = 128$

Review of Basic Concepts

Review of Fractions

Percents

Measurement

Signed Numbers and Powers of 10

Statistics

Linear Equations and Inequalities

Formulas, Proportion, and Variation

Linear Equations, Functions, and Inequalities in Two Variables

Systems of Linear Equations

Powers and Polynomials

Roots and Radicals

Factoring

Rational Expressions, Equations, and Inequalities

Quadratic and Other Nonlinear Equations and Inequalities

Geometry

Triangles

Right-Triangle Trigonometry

Trigonometry With Any Angle

Filters

Exam 16: Exponential and Logarithmic Equations

Solve for x:2x+1=23x : 2 ^ { x + 1 } = 2 ^ { 3 }x:2x+1=23

Evaluate: e-5

The compound amount when an investment is compounded continuously is A = Peni Where A = compound amount, P = original principal, n = number of years, and i = interest rate per year. Let P = 400, I = 0.05, and n = 3, then find A.

Using the formula A=P(1+rn)ntA = P \left( 1 + \frac { r } { n } \right) ^ { n t }A=P(1+nr​)nt , find the interest on an investment of $1200, at an interest rate of 12% for 5 years, if the interest is compounded quarterly.

Solve for x:3x−6=181x : 3 ^ { x - 6} = \frac { 1 } { 81 }x:3x−6=811​

A suburb city presently has a population of 100,000 people. In 25 years, what would its estimated population be if P=Poe0.02t?P=P o{e} ^{0.02 t }?P=Poe0.02t?

Evaluate: 5-1.2

Use the compound amount formula A=P(1+rn)ntA = P \left( 1 + \frac { r } { n } \right) ^ { n t }A=P(1+nr​)nt to find the accumulated amount on an investment of $1,500\$ 1,500$1,500 invested at an interest rate of 10%10 \%10% for 18 months, if the interest is compounded weekly.

Evaluate: 252 ^ { 5 }25

e−0.01=e ^ { - 0.01 } =e−0.01=

Solve for x:2x−5=2−2x : 2 ^ { x - 5 } = 2 ^ { - 2 }x:2x−5=2−2

Charlie invested $2400 at an interest rate of 5% for 5 years, where it was compounded continuously. If A = Peni, calculate the accumulated amount.

Solve for x:6x=136x : 6 ^ { x } = \frac { 1 } { 36 }x:6x=361​

Solve for x:2x=1128x : 2 x = \frac { 1 } { 128 }x:2x=1281​

Evaluate: 2x=1282 ^ { x } = 1282x=128

Review of Basic Concepts

Review of Fractions

Percents

Measurement

Signed Numbers and Powers of 10

Statistics

Linear Equations and Inequalities

Formulas, Proportion, and Variation

Linear Equations, Functions, and Inequalities in Two Variables

Systems of Linear Equations

Powers and Polynomials

Roots and Radicals

Factoring

Rational Expressions, Equations, and Inequalities

Quadratic and Other Nonlinear Equations and Inequalities

Geometry

Triangles

Right-Triangle Trigonometry

Trigonometry With Any Angle

Filters

Solve for $x : 2 ^ { x + 1 } = 2 ^ { 3 }$

Using the formula $A = P \left( 1 + \frac { r } { n } \right) ^ { n t }$ , find the interest on an investment of $1200, at an interest rate of 12% for 5 years, if the interest is compounded quarterly.

Solve for $x : 3 ^ { x - 6} = \frac { 1 } { 81 }$

A suburb city presently has a population of 100,000 people. In 25 years, what would its estimated population be if $P=P o{e} ^{0.02 t }?$

Use the compound amount formula $A = P \left( 1 + \frac { r } { n } \right) ^ { n t }$ to find the accumulated amount on an investment of $\$ 1,500$ invested at an interest rate of $10 \%$ for 18 months, if the interest is compounded weekly.

Evaluate: $2 ^ { 5 }$

$e ^ { - 0.01 } =$

Solve for $x : 2 ^ { x - 5 } = 2 ^ { - 2 }$

Solve for $x : 6 ^ { x } = \frac { 1 } { 36 }$

Solve for $x : 2 x = \frac { 1 } { 128 }$

Evaluate: $2 ^ { x } = 128$