Exam 31: Gas Laws and Temperature of Mixtures

Use the gas laws to find the missing value: P₁ = 30 psia, V₁ = 15 cu in, T₁ is constant, V₂ = 23 cu in, T₂ is constant, find P₂ to the nearer hundredth psia when necessary.

The pressure of a gas depends on temperature and the volume of the gas.

Use the gas laws to find the missing value: P₁ = 10 psia, V₁ is constant, T₁ = 20° C, P₂ = 15 psia, V₂ is constant, find T₂ to the nearer hundredth degrees Celsius when necessary.

In the morning, a tank containing refrigerant R-134a as a gas is at a pressure of 59 psia. The temperature is 60° F. In the afternoon, the temperature reaches 95° F. What is the new pressure inside the tank? Round answer to the nearer hundredth psia.

Use the gas laws to find the missing value: P₁ is constant, V₁ = 10 cm³, T₁ = 38° C, P₂ is constant, T₂ = 78° C, find V₂ to the nearer hundredth cubic centimeters when necessary.

Use the gas laws to find the missing value: P₁ = 37 psig, V₁ = 8 cu in, T₁ is constant, P₂ = 49 psig, T₂ is constant, find V₂ to the nearer hundredth cubic inch when necessary.

When solving gas law problems, temperature must be converted to degrees Fahrenheit or degrees Celsius before working the problem.

A compressor takes 1.2 cu in of gas at a pressure of 14.7 psia and compresses it into a volume of 0.35 cu in. If the temperature of the gas remains the same, find the pressure of the gas in psia after it is compressed. Round the answer to the nearer hundredth psia.

Use the gas laws to find the missing value: P₁ = 24 psia, V₁ = 2 cu in, T₁ = 24° C, V₂ = 1.3 cu in, T₂ = 54° C find P₂ to the nearer hundredth psia when necessary.

Use the gas laws to find the missing value: P₁ = 16 psig, V₁ = 6 cu in, T₁ = 72° F, P₂ = 30 psig, T₂ = 62° F, find V₂ to the nearer hundredth cubic inch when necessary.