Exam 8: An Introduction to Algebra

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Simplify the following algebraic expression and express your answer using positive exponents only. (a1v2)7\left( a ^ { - 1 } v ^ { - 2 } \right) ^ { 7 }

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For a 49-mile trip, Stacy paid the taxi driver $23.00. If $2 was a tip, how much was the fare? $__________

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Use the division or the multiplication property of equality to solve 28a=2,07228 a = 2,072 . What is the result? a=a = __________

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Simplify the expression.  (3x5c4)3\left( 3 x ^ { 5 } c ^ { 4 } \right) ^ { 3 }

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Identify the like terms from the list below and add them. 16x,6,14b,20x- 16 x , - 6,14 b , - 20 x

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Use an algebraic approach to solve the problem. Find three consecutive integers whose sum is 48.

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Use a property of equality to solve the equation. Then check the result. a4=67a - 4 = 67 a= __________

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Write the following statement as a mathematical expression. Three is less than twenty-three.

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Simplify and complete the expression. 5( y - 7) + 8 y = 5 y +      - 35 =      - 35

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Simplify the expression by combining like terms. 12 a + (-12 a )

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In the expression 410- 4 ^ { - 10 } , what is the base and the exponent?

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Find the product. (6b5)(5b6)\left( 6 b ^ { 5 } \right) \left( 5 b ^ { 6 } \right)

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Identify the terms of the expression. 5d27d+8d+55 d ^ { 2 } - 7 d + 8 - d + 5

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Use an equation to solve the problem. The average price of homes in one neighborhood decreased 8 % since last year, a drop of $5,800 . What was the average price of a home last year?

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What is 2c3(4c2)5c22 c ^ { 3 } \left( 4 c ^ { 2 } \right) 5 c ^ { 2 }  rewritten using only one exponent?

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Let y=5y = 5 and z=1z = 1 . Write the phrase as an algebraic expression, and evaluate it. yy minus ZZ

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Use an equation to solve the problem. A sport jacket that sells for $180 has a markup of $90. Find the wholesale price.

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Simplify the expression.  (3s3)3\left( 3 s ^ { 3 } \right) ^ { 3 }

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Solve the equation. 5(t1)+3(t3)=2(t1)+11(t+3)5 ( t - 1 ) + 3 ( t - 3 ) = - 2 ( t - 1 ) + 11 ( t + 3 )

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Evaluate the following expression for the given value of the variable. z1010z\frac { z - 10 } { 10 - z }  for z=8z = 8

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