Exam 3: The Enhanced E-R Model and Business Rules

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Creating a data model from a packaged data model requires much more skill than creating one from scratch.

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Which of the following is a generic entity type that has a relationship with one or more subtypes?

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The ________ rule specifies that each entity instance of the supertype must be a member of some subtype in the relationship.

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An entity instance of a subtype represents the same entity instance of the supertype.

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An entity cluster should focus on some area of interest to some community of users,developers or managers.

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All of the following are steps to using a packaged data model EXCEPT:

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Contrast the overlap rule to the disjoint rule.

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The ________ specifies that each entity instance of the supertype must be a member of some subtype in the relationship.

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A universal data model is a generic or template data model that can be reused as a starting point for a data modeling project.

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A supertype/subtype hierarchy is an arrangement of supertypes and subtypes where each ________ has only one ________.

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Explain why the E-R model needed to be expanded into the enhanced E-R model.

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A completeness constraint may specify that each entity of the supertype must be a member of some subtype in the relationship.

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An attribute of the supertype whose values determine the target subtype(s)is called a(n)________.

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A subtype can become a supertype if the subtype has other subtypes beneath it.

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A(n)________ is a set of one or more entity types and associated relationships grouped into a single abstract entity type.

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The overlap rule specifies that if an entity instance of the supertype is a member of one subtype,it can simultaneously be a member of two (or more)subtypes.

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An attribute of the supertype that determines the target subtype(s)is called the:

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Specialization is the reverse of generalization.

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In the figure below,which of the following are subtypes of patient? In the figure below,which of the following are subtypes of patient?

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In a supertype/subtype hierarchy,each subtype has:

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