Deck 22: Statistical Inference: Conclusion

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Question
For a sample of size 25 observations taken from a normally distributed population. The sample standard deviation is 6, a 95% confidence interval estimate for the population mean would require the use of:

A) z = 1.96
B) t = 1.711
C) z = 1.645
D) t = 2.064
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Question
A random sample of 20 observations taken from a normally distributed population revealed a sample mean of 65 and a sample variance of 16. The lower limit of a 90% confidence interval for the population mean would equal:

A) 66.546.
B) 63.454.
C) 63.812.
D) 66.188.
Question
Two independent samples of sizes 50 and 50 are randomly selected from two populations to test the difference between the population means, <strong>Two independent samples of sizes 50 and 50 are randomly selected from two populations to test the difference between the population means,   . The sampling distribution of the sample mean difference   is:</strong> A) normally distributed. B) approximately normal. C) t-distributed with 98 degrees of freedom. D) chi-squared distributed with 99 degrees of freedom. <div style=padding-top: 35px> . The sampling distribution of the sample mean difference <strong>Two independent samples of sizes 50 and 50 are randomly selected from two populations to test the difference between the population means,   . The sampling distribution of the sample mean difference   is:</strong> A) normally distributed. B) approximately normal. C) t-distributed with 98 degrees of freedom. D) chi-squared distributed with 99 degrees of freedom. <div style=padding-top: 35px> is:

A) normally distributed.
B) approximately normal.
C) t-distributed with 98 degrees of freedom.
D) chi-squared distributed with 99 degrees of freedom.
Question
A sample of size 300 had 96 successes. The lower limit of the 99% confidence interval for the population proportion is:

A) 0.3728.
B) 0.2672.
C) 0.2506.
D) 0.3894.
Question
When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. The two sample proportions are p^1\hat { p } _ { 1 } = 0.21 and p^2\hat { p } _ { 2 } = 0.15, and the standard error of the sampling distribution of are p^1\hat { p } _ { 1 } - p^2\hat { p } _ { 2 } is 0.018. The calculated value of the test statistic will be:

A) t = -3.33.
B) z = 3.33.
C) t = 3.33.
D) None of these choices are correct.
Question
When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions, but your statistical software provides only a one-tail area of 0.03 as part of its output. The p-value for this test will be:

A) 0.03
B) 0.06
C) 0.05
D) None of these choices are correct.
Question
When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions, testing at the 5% level of significance. Which of the following is the p-value for this test if the calculated z test statistic is 1.34?

A) 0.0250
B) 0.1802
C) 0.0901
D) 0.9099
Question
A random sample of size 15 taken from a normally distributed population resulted in a sample variance of 25. The upper limit of a 99% confidence interval for the population variance would be:

A) 12.868.
B) 92.032.
C) 85.896.
D) 75.100.
Question
Assuming that all necessary conditions are met, what needs to be changed in the formula <strong>Assuming that all necessary conditions are met, what needs to be changed in the formula   so that we can use it to construct a confidence interval estimate for the difference of two population means when the population variances are assumed to be equal?</strong> A) The   should be replaced by   . B) The z   should be replaced by   . C) The z   should be replaced by   . D) The   should be replaced by   . <div style=padding-top: 35px> so that we can use it to construct a confidence interval estimate for the difference of two population means when the population variances are assumed to be equal?

A) The <strong>Assuming that all necessary conditions are met, what needs to be changed in the formula   so that we can use it to construct a confidence interval estimate for the difference of two population means when the population variances are assumed to be equal?</strong> A) The   should be replaced by   . B) The z   should be replaced by   . C) The z   should be replaced by   . D) The   should be replaced by   . <div style=padding-top: 35px> should be replaced by <strong>Assuming that all necessary conditions are met, what needs to be changed in the formula   so that we can use it to construct a confidence interval estimate for the difference of two population means when the population variances are assumed to be equal?</strong> A) The   should be replaced by   . B) The z   should be replaced by   . C) The z   should be replaced by   . D) The   should be replaced by   . <div style=padding-top: 35px> .
B) The z <strong>Assuming that all necessary conditions are met, what needs to be changed in the formula   so that we can use it to construct a confidence interval estimate for the difference of two population means when the population variances are assumed to be equal?</strong> A) The   should be replaced by   . B) The z   should be replaced by   . C) The z   should be replaced by   . D) The   should be replaced by   . <div style=padding-top: 35px> should be replaced by <strong>Assuming that all necessary conditions are met, what needs to be changed in the formula   so that we can use it to construct a confidence interval estimate for the difference of two population means when the population variances are assumed to be equal?</strong> A) The   should be replaced by   . B) The z   should be replaced by   . C) The z   should be replaced by   . D) The   should be replaced by   . <div style=padding-top: 35px> .
C) The z <strong>Assuming that all necessary conditions are met, what needs to be changed in the formula   so that we can use it to construct a confidence interval estimate for the difference of two population means when the population variances are assumed to be equal?</strong> A) The   should be replaced by   . B) The z   should be replaced by   . C) The z   should be replaced by   . D) The   should be replaced by   . <div style=padding-top: 35px> should be replaced by <strong>Assuming that all necessary conditions are met, what needs to be changed in the formula   so that we can use it to construct a confidence interval estimate for the difference of two population means when the population variances are assumed to be equal?</strong> A) The   should be replaced by   . B) The z   should be replaced by   . C) The z   should be replaced by   . D) The   should be replaced by   . <div style=padding-top: 35px> .
D) The <strong>Assuming that all necessary conditions are met, what needs to be changed in the formula   so that we can use it to construct a confidence interval estimate for the difference of two population means when the population variances are assumed to be equal?</strong> A) The   should be replaced by   . B) The z   should be replaced by   . C) The z   should be replaced by   . D) The   should be replaced by   . <div style=padding-top: 35px> should be replaced by <strong>Assuming that all necessary conditions are met, what needs to be changed in the formula   so that we can use it to construct a confidence interval estimate for the difference of two population means when the population variances are assumed to be equal?</strong> A) The   should be replaced by   . B) The z   should be replaced by   . C) The z   should be replaced by   . D) The   should be replaced by   . <div style=padding-top: 35px> .
Question
In testing the null hypothesis <strong>In testing the null hypothesis   , if   is false, the test could lead to:</strong> A) Type I error. B) Type II error. C) Either a Type I or a Type II error. D) None of these choices are correct. <div style=padding-top: 35px> , if <strong>In testing the null hypothesis   , if   is false, the test could lead to:</strong> A) Type I error. B) Type II error. C) Either a Type I or a Type II error. D) None of these choices are correct. <div style=padding-top: 35px> is false, the test could lead to:

A) Type I error.
B) Type II error.
C) Either a Type I or a Type II error.
D) None of these choices are correct.
Question
In a hypothesis test for the population variance, the hypotheses are: <strong>In a hypothesis test for the population variance, the hypotheses are:   .   . If the sample size is 15 and the test is being carried out at the 5% level of significance, the null hypothesis will be rejected if:</strong> A)   . B)   . C)   . D)   . <div style=padding-top: 35px> . <strong>In a hypothesis test for the population variance, the hypotheses are:   .   . If the sample size is 15 and the test is being carried out at the 5% level of significance, the null hypothesis will be rejected if:</strong> A)   . B)   . C)   . D)   . <div style=padding-top: 35px> . If the sample size is 15 and the test is being carried out at the 5% level of significance, the null hypothesis will be rejected if:

A) <strong>In a hypothesis test for the population variance, the hypotheses are:   .   . If the sample size is 15 and the test is being carried out at the 5% level of significance, the null hypothesis will be rejected if:</strong> A)   . B)   . C)   . D)   . <div style=padding-top: 35px> .
B) <strong>In a hypothesis test for the population variance, the hypotheses are:   .   . If the sample size is 15 and the test is being carried out at the 5% level of significance, the null hypothesis will be rejected if:</strong> A)   . B)   . C)   . D)   . <div style=padding-top: 35px> .
C) <strong>In a hypothesis test for the population variance, the hypotheses are:   .   . If the sample size is 15 and the test is being carried out at the 5% level of significance, the null hypothesis will be rejected if:</strong> A)   . B)   . C)   . D)   . <div style=padding-top: 35px> .
D) <strong>In a hypothesis test for the population variance, the hypotheses are:   .   . If the sample size is 15 and the test is being carried out at the 5% level of significance, the null hypothesis will be rejected if:</strong> A)   . B)   . C)   . D)   . <div style=padding-top: 35px> .
Question
In constructing a 95% interval estimate for the ratio of two population variances, <strong>In constructing a 95% interval estimate for the ratio of two population variances,   /   , two independent samples of sizes 30 and 40 are drawn from the populations. If the sample variances are 425 and 675, then the upper confidence limit is about:</strong> A) 1.2215. B) 0.3132. C) 1.2656. D) 0.3246. <div style=padding-top: 35px> / <strong>In constructing a 95% interval estimate for the ratio of two population variances,   /   , two independent samples of sizes 30 and 40 are drawn from the populations. If the sample variances are 425 and 675, then the upper confidence limit is about:</strong> A) 1.2215. B) 0.3132. C) 1.2656. D) 0.3246. <div style=padding-top: 35px> , two independent samples of sizes 30 and 40 are drawn from the populations. If the sample variances are 425 and 675, then the upper confidence limit is about:

A) 1.2215.
B) 0.3132.
C) 1.2656.
D) 0.3246.
Question
In testing for the equality of two population variances, when the populations are normally distributed, the 5% level of significance has been used. To determine the rejection region, it will be necessary to refer to the F table corresponding to an upper-tail area of:

A) 0.950.
B) 0.050.
C) 0.025.
D) 0.100.
Question
In testing the difference between two population means for which the population variances are unknown and assumed to be equal, two independent samples are drawn from the populations. Which of the following tests is appropriate?

A) z-test.
B) Equal-variances t-test.
C) F-test.
D) Matched pairs t-test.
Question
In constructing a 90% confidence interval estimate for the difference between the means of two normally distributed populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows: <strong>In constructing a 90% confidence interval estimate for the difference between the means of two normally distributed populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   .   ,   ,   . The lower confidence limit is:</strong> A) 30.086. B) 8.542. C) 0.914. D) 31.458. <div style=padding-top: 35px> , <strong>In constructing a 90% confidence interval estimate for the difference between the means of two normally distributed populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   .   ,   ,   . The lower confidence limit is:</strong> A) 30.086. B) 8.542. C) 0.914. D) 31.458. <div style=padding-top: 35px> , <strong>In constructing a 90% confidence interval estimate for the difference between the means of two normally distributed populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   .   ,   ,   . The lower confidence limit is:</strong> A) 30.086. B) 8.542. C) 0.914. D) 31.458. <div style=padding-top: 35px> . <strong>In constructing a 90% confidence interval estimate for the difference between the means of two normally distributed populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   .   ,   ,   . The lower confidence limit is:</strong> A) 30.086. B) 8.542. C) 0.914. D) 31.458. <div style=padding-top: 35px> , <strong>In constructing a 90% confidence interval estimate for the difference between the means of two normally distributed populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   .   ,   ,   . The lower confidence limit is:</strong> A) 30.086. B) 8.542. C) 0.914. D) 31.458. <div style=padding-top: 35px> , <strong>In constructing a 90% confidence interval estimate for the difference between the means of two normally distributed populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   .   ,   ,   . The lower confidence limit is:</strong> A) 30.086. B) 8.542. C) 0.914. D) 31.458. <div style=padding-top: 35px> . The lower confidence limit is:

A) 30.086.
B) 8.542.
C) 0.914.
D) 31.458.
Question
Two independent samples of sizes 20 and 25 are randomly selected from two normal populations with equal variances. In order to test the difference between the population means, the test statistic is:

A) a standard normal random variable.
B) approximately standard normal random variable.
C) Student t distributed with 45 degrees of freedom.
D) Student t distributed with 43 degrees of freedom.
Question
In testing the difference between two population means using two independent samples, the population standard deviations are assumed to be known and the calculated test statistic equals 1.05. If the test is upper-tail and the 10% level of significance has been specified, the conclusion should be to:

A) reject the null hypothesis.
B) not to reject the null hypothesis.
C) choose two other independent samples.
D) None of these choices are correct.
Question
Which of the following statements is correct regarding the percentile points of the F-distribution?

A) <strong>Which of the following statements is correct regarding the percentile points of the F-distribution?</strong> A)   . B)   . C)   . D)   . <div style=padding-top: 35px> .
B) <strong>Which of the following statements is correct regarding the percentile points of the F-distribution?</strong> A)   . B)   . C)   . D)   . <div style=padding-top: 35px> .
C) <strong>Which of the following statements is correct regarding the percentile points of the F-distribution?</strong> A)   . B)   . C)   . D)   . <div style=padding-top: 35px> .
D) <strong>Which of the following statements is correct regarding the percentile points of the F-distribution?</strong> A)   . B)   . C)   . D)   . <div style=padding-top: 35px> .
Question
A sample of size 200 from population 1 has 50 successes. A sample of size 200 from population 2 has 40 successes. The value of the test statistic for testing the null hypothesis that the proportion of successes in population 1 exceeds the proportion of successes in population 2 by 0.025 is:

A) 1.96.
B) 1.25.
C) 0.5998.
D) 1.20.
Question
Based on sample data, the 95% confidence interval limits for the population mean are LCL = 124.6 and UCL = 148.2. If the 5% level of significance were used in testing the hypotheses:
H0 : μ\mu = 150
H1 : μ\mu\neq 150,
The null hypothesis:

A) would not be rejected.
B) would be rejected.
C) would have to be revised.
D) There is insufficient information to decide whether to maintain or reject the null hypothesis.
Question
The pooled-variance estimator, The pooled-variance estimator,   , requires that the two population variances be equal.<div style=padding-top: 35px> , requires that the two population variances be equal.
Question
A one-tail test of the population proportion produces a test statistic z = -2.12. The p-value of the test is 0.034.
Question
In testing the hypotheses: H0 : μ\mu = 140
H1 : μ\mu \neq 140,
Suppose that we rejected the null hypothesis at α\alpha = 0.10. Then for which of the following α\alpha values do we also reject the null hypothesis?

A) 0.025
B) 0.01
C) 0.05
D) All of these choices are correct.
Question
A sample of size 125 selected from one population has 55 successes, and a sample of size 140 selected from a second population has 70 successes. The test statistic for testing the equality of the population proportions is equal to:

A) -0.060.
B) -0.977.
C) -0.940.
D) -0.472.
Question
A random sample of 30 observations is selected from a normally distributed population. The sample variance is 12. In the 90% confidence interval for the population variance, the upper limit will be:

A) 15.176.
B) 8.177.
C) 19.652.
D) 16.941.
Question
Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?

A) <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . <div style=padding-top: 35px> and <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . <div style=padding-top: 35px> .
B) <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . <div style=padding-top: 35px> and <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . <div style=padding-top: 35px> .
C) <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . <div style=padding-top: 35px> <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . <div style=padding-top: 35px> <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . <div style=padding-top: 35px> and <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . <div style=padding-top: 35px> .
D) <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . <div style=padding-top: 35px> <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . <div style=padding-top: 35px> <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . <div style=padding-top: 35px> and <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . <div style=padding-top: 35px> .
Question
When the necessary conditions are met, a one-tail test is being conducted to test the difference between two population proportions, but your statistical software provides only a two-tail area of 0.058 as part of its output. The p-value for this test will be:

A) 0.029.
B) 0.971.
C) 0.029 or 0.972, depending on whether the test is a left-tail or a right-tail test.
D) 0.058.
Question
In a hypothesis test for the population variance, the hypotheses are: <strong>In a hypothesis test for the population variance, the hypotheses are:     If the sample size is 25 and the test is being carried out at the 5% level of significance, the rejection region will be:</strong> A)   < 15.6587 or   > 33.1963. B)   <12.4011 or   >39.3641. C)   < 16.4734 or   >34.3816. D)   < 13.1197 or   <37.6525. <div style=padding-top: 35px> <strong>In a hypothesis test for the population variance, the hypotheses are:     If the sample size is 25 and the test is being carried out at the 5% level of significance, the rejection region will be:</strong> A)   < 15.6587 or   > 33.1963. B)   <12.4011 or   >39.3641. C)   < 16.4734 or   >34.3816. D)   < 13.1197 or   <37.6525. <div style=padding-top: 35px> If the sample size is 25 and the test is being carried out at the 5% level of significance, the rejection region will be:

A) <strong>In a hypothesis test for the population variance, the hypotheses are:     If the sample size is 25 and the test is being carried out at the 5% level of significance, the rejection region will be:</strong> A)   < 15.6587 or   > 33.1963. B)   <12.4011 or   >39.3641. C)   < 16.4734 or   >34.3816. D)   < 13.1197 or   <37.6525. <div style=padding-top: 35px> < 15.6587 or <strong>In a hypothesis test for the population variance, the hypotheses are:     If the sample size is 25 and the test is being carried out at the 5% level of significance, the rejection region will be:</strong> A)   < 15.6587 or   > 33.1963. B)   <12.4011 or   >39.3641. C)   < 16.4734 or   >34.3816. D)   < 13.1197 or   <37.6525. <div style=padding-top: 35px> > 33.1963.
B) <strong>In a hypothesis test for the population variance, the hypotheses are:     If the sample size is 25 and the test is being carried out at the 5% level of significance, the rejection region will be:</strong> A)   < 15.6587 or   > 33.1963. B)   <12.4011 or   >39.3641. C)   < 16.4734 or   >34.3816. D)   < 13.1197 or   <37.6525. <div style=padding-top: 35px> <12.4011 or <strong>In a hypothesis test for the population variance, the hypotheses are:     If the sample size is 25 and the test is being carried out at the 5% level of significance, the rejection region will be:</strong> A)   < 15.6587 or   > 33.1963. B)   <12.4011 or   >39.3641. C)   < 16.4734 or   >34.3816. D)   < 13.1197 or   <37.6525. <div style=padding-top: 35px> >39.3641.
C) <strong>In a hypothesis test for the population variance, the hypotheses are:     If the sample size is 25 and the test is being carried out at the 5% level of significance, the rejection region will be:</strong> A)   < 15.6587 or   > 33.1963. B)   <12.4011 or   >39.3641. C)   < 16.4734 or   >34.3816. D)   < 13.1197 or   <37.6525. <div style=padding-top: 35px> < 16.4734 or <strong>In a hypothesis test for the population variance, the hypotheses are:     If the sample size is 25 and the test is being carried out at the 5% level of significance, the rejection region will be:</strong> A)   < 15.6587 or   > 33.1963. B)   <12.4011 or   >39.3641. C)   < 16.4734 or   >34.3816. D)   < 13.1197 or   <37.6525. <div style=padding-top: 35px> >34.3816.
D) <strong>In a hypothesis test for the population variance, the hypotheses are:     If the sample size is 25 and the test is being carried out at the 5% level of significance, the rejection region will be:</strong> A)   < 15.6587 or   > 33.1963. B)   <12.4011 or   >39.3641. C)   < 16.4734 or   >34.3816. D)   < 13.1197 or   <37.6525. <div style=padding-top: 35px> < 13.1197 or <strong>In a hypothesis test for the population variance, the hypotheses are:     If the sample size is 25 and the test is being carried out at the 5% level of significance, the rejection region will be:</strong> A)   < 15.6587 or   > 33.1963. B)   <12.4011 or   >39.3641. C)   < 16.4734 or   >34.3816. D)   < 13.1197 or   <37.6525. <div style=padding-top: 35px> <37.6525.
Question
Two samples of size 30 each are independently drawn from two normal populations, where the unknown population variances are assumed to be equal. The number of degrees of freedom of the equal-variances t-test statistic is 59.
Question
Which of the following best describes a p-value?

A) A p-value is the probability of getting our population results or more extreme if the null hypothesis about the sample statistic were really true
B) A p-value is the probability of getting our sample results or more extreme if the null hypothesis about the population parameter were really true
C) A p-value is the probability of getting our sample results.
D) A p-value is the probability of getting our sample results or more extreme if the null hypothesis about the population parameter were really false
Question
When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. The two sample proportions are When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. The two sample proportions are   = 0.32 and   = 0.38, and the standard error of the sampling distribution of   is 0.046. The calculated value of the test statistic will be 1.3043.<div style=padding-top: 35px> = 0.32 and When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. The two sample proportions are   = 0.32 and   = 0.38, and the standard error of the sampling distribution of   is 0.046. The calculated value of the test statistic will be 1.3043.<div style=padding-top: 35px> = 0.38, and the standard error of the sampling distribution of When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. The two sample proportions are   = 0.32 and   = 0.38, and the standard error of the sampling distribution of   is 0.046. The calculated value of the test statistic will be 1.3043.<div style=padding-top: 35px> is 0.046. The calculated value of the test statistic will be 1.3043.
Question
Which of the following is the number of degrees of freedom associated with the t-test, when the data are gathered from a matched pairs experiment with 30 pairs?

A) 30
B) 29
C) 28
D) 59
Question
When comparing two population variances, we test H0: When comparing two population variances, we test H<sub>0</sub>:   = 0.<div style=padding-top: 35px> = 0.
Question
In testing whether the means of two normal populations are equal, summary statistics computed for two independent samples are as follows: <strong>In testing whether the means of two normal populations are equal, summary statistics computed for two independent samples are as follows:   ,   ,   .   ,   ,   . Assume that the population variances are unequal. The standard error of the sampling distribution of the sample mean difference   is equal to:</strong> A) 0.3247. B) 0.3282. C) 0.1054. D) 0.1125. <div style=padding-top: 35px> , <strong>In testing whether the means of two normal populations are equal, summary statistics computed for two independent samples are as follows:   ,   ,   .   ,   ,   . Assume that the population variances are unequal. The standard error of the sampling distribution of the sample mean difference   is equal to:</strong> A) 0.3247. B) 0.3282. C) 0.1054. D) 0.1125. <div style=padding-top: 35px> , <strong>In testing whether the means of two normal populations are equal, summary statistics computed for two independent samples are as follows:   ,   ,   .   ,   ,   . Assume that the population variances are unequal. The standard error of the sampling distribution of the sample mean difference   is equal to:</strong> A) 0.3247. B) 0.3282. C) 0.1054. D) 0.1125. <div style=padding-top: 35px> . <strong>In testing whether the means of two normal populations are equal, summary statistics computed for two independent samples are as follows:   ,   ,   .   ,   ,   . Assume that the population variances are unequal. The standard error of the sampling distribution of the sample mean difference   is equal to:</strong> A) 0.3247. B) 0.3282. C) 0.1054. D) 0.1125. <div style=padding-top: 35px> , <strong>In testing whether the means of two normal populations are equal, summary statistics computed for two independent samples are as follows:   ,   ,   .   ,   ,   . Assume that the population variances are unequal. The standard error of the sampling distribution of the sample mean difference   is equal to:</strong> A) 0.3247. B) 0.3282. C) 0.1054. D) 0.1125. <div style=padding-top: 35px> , <strong>In testing whether the means of two normal populations are equal, summary statistics computed for two independent samples are as follows:   ,   ,   .   ,   ,   . Assume that the population variances are unequal. The standard error of the sampling distribution of the sample mean difference   is equal to:</strong> A) 0.3247. B) 0.3282. C) 0.1054. D) 0.1125. <div style=padding-top: 35px> . Assume that the population variances are unequal. The standard error of the sampling distribution of the sample mean difference <strong>In testing whether the means of two normal populations are equal, summary statistics computed for two independent samples are as follows:   ,   ,   .   ,   ,   . Assume that the population variances are unequal. The standard error of the sampling distribution of the sample mean difference   is equal to:</strong> A) 0.3247. B) 0.3282. C) 0.1054. D) 0.1125. <div style=padding-top: 35px> is equal to:

A) 0.3247.
B) 0.3282.
C) 0.1054.
D) 0.1125.
Question
From a sample of 500 items, 30 were found to be defective. The point estimate of the population proportion defective will be:

A) 0.06.
B) 30.0.
C) 16.667.
D) None of these choices are correct.
Question
If we reject a null hypothesis at the 0.05 level of significance, then we must also reject it at the 0.10 level.
Question
In testing the hypotheses: <strong>In testing the hypotheses:     , at the 10% significance level, if the sample proportion is 0.56, and the standard error of the sample proportion is 0.025, the appropriate conclusion is:</strong> A) to reject   . B) not to reject   . C) to reject   . D) to reject both   and   . <div style=padding-top: 35px> <strong>In testing the hypotheses:     , at the 10% significance level, if the sample proportion is 0.56, and the standard error of the sample proportion is 0.025, the appropriate conclusion is:</strong> A) to reject   . B) not to reject   . C) to reject   . D) to reject both   and   . <div style=padding-top: 35px> , at the 10% significance level, if the sample proportion is 0.56, and the standard error of the sample proportion is 0.025, the appropriate conclusion is:

A) to reject <strong>In testing the hypotheses:     , at the 10% significance level, if the sample proportion is 0.56, and the standard error of the sample proportion is 0.025, the appropriate conclusion is:</strong> A) to reject   . B) not to reject   . C) to reject   . D) to reject both   and   . <div style=padding-top: 35px> .
B) not to reject <strong>In testing the hypotheses:     , at the 10% significance level, if the sample proportion is 0.56, and the standard error of the sample proportion is 0.025, the appropriate conclusion is:</strong> A) to reject   . B) not to reject   . C) to reject   . D) to reject both   and   . <div style=padding-top: 35px> .
C) to reject <strong>In testing the hypotheses:     , at the 10% significance level, if the sample proportion is 0.56, and the standard error of the sample proportion is 0.025, the appropriate conclusion is:</strong> A) to reject   . B) not to reject   . C) to reject   . D) to reject both   and   . <div style=padding-top: 35px> .
D) to reject both <strong>In testing the hypotheses:     , at the 10% significance level, if the sample proportion is 0.56, and the standard error of the sample proportion is 0.025, the appropriate conclusion is:</strong> A) to reject   . B) not to reject   . C) to reject   . D) to reject both   and   . <div style=padding-top: 35px> and <strong>In testing the hypotheses:     , at the 10% significance level, if the sample proportion is 0.56, and the standard error of the sample proportion is 0.025, the appropriate conclusion is:</strong> A) to reject   . B) not to reject   . C) to reject   . D) to reject both   and   . <div style=padding-top: 35px> .
Question
For a sample of 25 observations taken from a normally distributed population with standard deviation of 6, a 95% confidence interval estimate for the population mean would require the use of:

A) t = 2.064.
B) t = 1.711.
C) X2 = 39.3641.
D) z = 1.96.
Question
Suppose that a one-tail t-test is being applied to find out if the population mean is at least 80. The level of significance is 0.10 and 25 observations were sampled. The rejection region is:

A) t > 2.492
B) t > 1.711
C) t < − 2.492
D) t > 1.318
Question
Two independent samples of sizes 35 and 40 are randomly selected from two normally distributed populations. Assume that the population variances are unknown but equal. In order to test the difference between the population means, <strong>Two independent samples of sizes 35 and 40 are randomly selected from two normally distributed populations. Assume that the population variances are unknown but equal. In order to test the difference between the population means,   , the sampling distribution of the sample mean difference,   , is:</strong> A) normally distributed. B) t-distributed with 75 degrees of freedom. C) t-distributed with 73 degrees of freedom. D) F-distributed with 34 and 39 degrees of freedom. <div style=padding-top: 35px> , the sampling distribution of the sample mean difference, <strong>Two independent samples of sizes 35 and 40 are randomly selected from two normally distributed populations. Assume that the population variances are unknown but equal. In order to test the difference between the population means,   , the sampling distribution of the sample mean difference,   , is:</strong> A) normally distributed. B) t-distributed with 75 degrees of freedom. C) t-distributed with 73 degrees of freedom. D) F-distributed with 34 and 39 degrees of freedom. <div style=padding-top: 35px> , is:

A) normally distributed.
B) t-distributed with 75 degrees of freedom.
C) t-distributed with 73 degrees of freedom.
D) F-distributed with 34 and 39 degrees of freedom.
Question
If a sample has 25 observations and a 99% confidence estimate for If a sample has 25 observations and a 99% confidence estimate for   is needed, the appropriate t-score is 2.797.<div style=padding-top: 35px> is needed, the appropriate t-score is 2.797.
Question
If a sample has 12 observations and a 90% confidence estimate for µ is needed, the appropriate t-critical value from the t tables is 1.796.
Question
If a sample of size 25 is selected, the value of A for the probability P(tdf=n-1 If a sample of size 25 is selected, the value of A for the probability P(t<sub>df=n-1</sub>   A) = 0.05 is 1.708.<div style=padding-top: 35px> A) = 0.05 is 1.708.
Question
When the necessary conditions are met, a two-tail test is being conducted at When the necessary conditions are met, a two-tail test is being conducted at   = 0.025 to test H<sub>0</sub>:   = 1. The two sample variances are   = 375 and   = 625, and the sample sizes are n<sub>1</sub> = 36 and n<sub>2</sub> = 36. The calculated value of the test statistic will be F = 0.60.<div style=padding-top: 35px> = 0.025 to test
H0: When the necessary conditions are met, a two-tail test is being conducted at   = 0.025 to test H<sub>0</sub>:   = 1. The two sample variances are   = 375 and   = 625, and the sample sizes are n<sub>1</sub> = 36 and n<sub>2</sub> = 36. The calculated value of the test statistic will be F = 0.60.<div style=padding-top: 35px> = 1. The two sample variances are When the necessary conditions are met, a two-tail test is being conducted at   = 0.025 to test H<sub>0</sub>:   = 1. The two sample variances are   = 375 and   = 625, and the sample sizes are n<sub>1</sub> = 36 and n<sub>2</sub> = 36. The calculated value of the test statistic will be F = 0.60.<div style=padding-top: 35px> = 375 and When the necessary conditions are met, a two-tail test is being conducted at   = 0.025 to test H<sub>0</sub>:   = 1. The two sample variances are   = 375 and   = 625, and the sample sizes are n<sub>1</sub> = 36 and n<sub>2</sub> = 36. The calculated value of the test statistic will be F = 0.60.<div style=padding-top: 35px> = 625, and the sample sizes are
n1 = 36 and n2 = 36. The calculated value of the test statistic will be F = 0.60.
Question
We use the F-test to determine whether two population variances are equal.
Question
When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population means, but your statistical software provides only a one-tail area of 0.0327 as part of its output. The p-value for this test will be 0.0654.
Question
The equal-variances test statistic of The equal-variances test statistic of   is Student t-distributed with n<sub>1</sub> + n<sub>2</sub> - 2 degrees of freedom, provided that the two sample sizes are equal.<div style=padding-top: 35px> is Student t-distributed with n1 + n2 - 2 degrees of freedom, provided that the two sample sizes are equal.
Question
When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. If the value of the test statistic z is 1.53, then the p-value is 0.126.
Question
The number of degrees of freedom associated with the t-test, when the data are gathered from a matched pairs experiment with 8 pairs, is 14.
Question
If a null hypothesis about the population proportion p is rejected at the 0.05 level of significance, it must be rejected at the 0.01 level.
Question
The upper limit of the 89.9% confidence interval for the population proportion p, given that n = 80 and P^\hat{P} = 0.40, is 0.4898.
Question
The lower limit of the 87.4% confidence interval for the population proportion p, given that n = 250 and P^\hat{P} = 0.15, is 0.1492.
Question
If a sample of size 300 is selected, the value of A for the probability P(-A If a sample of size 300 is selected, the value of A for the probability P(-A   t<sub>df=n-1</sub>   A) = 0.90 is 1.96.<div style=padding-top: 35px> tdf=n-1 If a sample of size 300 is selected, the value of A for the probability P(-A   t<sub>df=n-1</sub>   A) = 0.90 is 1.96.<div style=padding-top: 35px> A) = 0.90 is 1.96.
Question
When the necessary conditions are met, a two-tail test is being conducted at When the necessary conditions are met, a two-tail test is being conducted at   = 0.10 to test H₀:   = 1. The two sample variances are   = 736 and   = 1024, and the sample sizes are n<sub>1</sub> = 16 and n<sub>2</sub> = 25. The rejection region is F > 2.11 or F < 0.4367.<div style=padding-top: 35px> = 0.10 to test H₀: When the necessary conditions are met, a two-tail test is being conducted at   = 0.10 to test H₀:   = 1. The two sample variances are   = 736 and   = 1024, and the sample sizes are n<sub>1</sub> = 16 and n<sub>2</sub> = 25. The rejection region is F > 2.11 or F < 0.4367.<div style=padding-top: 35px> = 1. The two sample variances are When the necessary conditions are met, a two-tail test is being conducted at   = 0.10 to test H₀:   = 1. The two sample variances are   = 736 and   = 1024, and the sample sizes are n<sub>1</sub> = 16 and n<sub>2</sub> = 25. The rejection region is F > 2.11 or F < 0.4367.<div style=padding-top: 35px> = 736 and When the necessary conditions are met, a two-tail test is being conducted at   = 0.10 to test H₀:   = 1. The two sample variances are   = 736 and   = 1024, and the sample sizes are n<sub>1</sub> = 16 and n<sub>2</sub> = 25. The rejection region is F > 2.11 or F < 0.4367.<div style=padding-top: 35px> = 1024, and the sample sizes are n1 = 16 and n2 = 25. The rejection region is F > 2.11 or F < 0.4367.
Question
If a sample has 300 observations and a 97.5% confidence estimate for p is needed, the appropriate z-score is 2.24.
Question
Descriptive statistics helps us describe and summarise data whereas inferential statistics helps us draw conclusions about populations based on samples of data.
Question
If a sample of size 28 is selected, the value of A for the probability P(-A If a sample of size 28 is selected, the value of A for the probability P(-A   t<sub>df=n-1</sub> t   A) = 0.99 is 2.771.<div style=padding-top: 35px> tdf=n-1 t If a sample of size 28 is selected, the value of A for the probability P(-A   t<sub>df=n-1</sub> t   A) = 0.99 is 2.771.<div style=padding-top: 35px> A) = 0.99 is 2.771.
Question
Both the equal-variances and unequal-variances t-test statistics of Both the equal-variances and unequal-variances t-test statistics of   require that the two populations be Student t-distributed.<div style=padding-top: 35px> require that the two populations be Student t-distributed.
Question
If a sample has 20 observations and a 95% confidence estimate for If a sample has 20 observations and a 95% confidence estimate for   is needed, the appropriate t-score is 1.729.<div style=padding-top: 35px> is needed, the appropriate t-score is 1.729.
Question
In a one-tail test, the p-value is found to be equal to 0.0456. If the test had been two-tailed, the p-value would have been 0.0912.
Question
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   Estimate a 95% confidence interval for the difference in the proportions of students who received a high distinction in semester 1 to semester 2.<div style=padding-top: 35px> Estimate a 95% confidence interval for the difference in the proportions of students who received a high distinction in semester 1 to semester 2.
Question
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   (a) Can we conclude at the 5% level of significance that semester 1 students have a higher proportion of high distinctions than semester 2 students, where a high distinction is a final mark greater than or equal to 85%? (b) Find the p-value of the test, and explain how to use it to test the hypotheses.<div style=padding-top: 35px> (a) Can we conclude at the 5% level of significance that semester 1 students have a higher proportion of high distinctions than semester 2 students, where a high distinction is a final mark greater than or equal to 85%?
(b) Find the p-value of the test, and explain how to use it to test the hypotheses.
Question
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   Estimate and interpret a 95% confidence interval for the population average final mark for semester 1 students.<div style=padding-top: 35px> Estimate and interpret a 95% confidence interval for the population average final mark for semester 1 students.
Question
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   (a) Determine whether these data are sufficient to infer at the 10% level of significance that the two population variances differ. (b) Explain the decision of your test in part (a) in the context of this question.<div style=padding-top: 35px> (a) Determine whether these data are sufficient to infer at the 10% level of significance that the two population variances differ.
(b) Explain the decision of your test in part (a) in the context of this question.
Question
The irradiation of food to destroy bacteria is an increasingly common practice. In order to determine which one of two methods of irradiation is best, a scientist took a random sample of 100 one-kilogram packages of minced meat and subjected 50 of them to irradiation method 1 and the remaining 50 to irradiation method 2. The bacteria counts were measured and the following statistics were computed. The scientist noted that the data were normally distributed. The irradiation of food to destroy bacteria is an increasingly common practice. In order to determine which one of two methods of irradiation is best, a scientist took a random sample of 100 one-kilogram packages of minced meat and subjected 50 of them to irradiation method 1 and the remaining 50 to irradiation method 2. The bacteria counts were measured and the following statistics were computed. The scientist noted that the data were normally distributed.   Estimate with 95% confidence the difference in the mean bacteria counts between method 1 and method 2.<div style=padding-top: 35px> Estimate with 95% confidence the difference in the mean bacteria counts between method 1 and method 2.
Question
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   Can we conclude at the 5% significance level that the variance of semester 2 student's final marks is greater than 150?<div style=padding-top: 35px> Can we conclude at the 5% significance level that the variance of semester 2 student's final marks is greater than 150?
Question
The sampling distributions we use for nominal (categorical) data are the Standard Normal distribution and the Chi-squared distribution.
Question
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   Estimate and interpret a 95% confidence interval for the population average final mark for semester 2 students.<div style=padding-top: 35px> Estimate and interpret a 95% confidence interval for the population average final mark for semester 2 students.
Question
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   There is a rumor going around the university that students with a higher IQ are enrolled in the semester 1 statistics course because they tend to be students enrolled in the degree with the higher entrance score for university. Can it be concluded at the 5% significance level that semester 1 students have a higher average final mark than semester 2 students? Assume that the population variances are unknown and equal.<div style=padding-top: 35px> There is a rumor going around the university that students with a higher IQ are enrolled in the semester 1 statistics course because they tend to be students enrolled in the degree with the higher entrance score for university. Can it be concluded at the 5% significance level that semester 1 students have a higher average final mark than semester 2 students? Assume that the population variances are unknown and equal.
Question
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   Estimate and interpret a 95% confidence interval for the proportion of semester 2 students that passed the course.<div style=padding-top: 35px> Estimate and interpret a 95% confidence interval for the proportion of semester 2 students that passed the course.
Question
The irradiation of food to destroy bacteria is an increasingly common practice. In order to determine which one of two methods of irradiation is best, a scientist took a random sample of 100 one-kilogram packages of minced meat and subjected 50 of them to irradiation method 1 and the remaining 50 to irradiation method 2. The bacteria counts were measured and the following statistics were computed. The scientist noted that the data were normally distributed. The irradiation of food to destroy bacteria is an increasingly common practice. In order to determine which one of two methods of irradiation is best, a scientist took a random sample of 100 one-kilogram packages of minced meat and subjected 50 of them to irradiation method 1 and the remaining 50 to irradiation method 2. The bacteria counts were measured and the following statistics were computed. The scientist noted that the data were normally distributed.   Estimate with 95% confidence the mean bacteria count with method 2.<div style=padding-top: 35px> Estimate with 95% confidence the mean bacteria count with method 2.
Question
The sampling distributions we use for numerical data are the Standard Normal distribution, the Student's t-distribution and the F distribution.
Question
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   Can we conclude at the 5% significance level that the variance of semester 1 student's final marks is greater than 150?<div style=padding-top: 35px> Can we conclude at the 5% significance level that the variance of semester 1 student's final marks is greater than 150?
Question
The irradiation of food to destroy bacteria is an increasingly common practice. In order to determine which one of two methods of irradiation is best, a scientist took a random sample of 100 one-kilogram packages of minced meat and subjected 50 of them to irradiation method 1 and the remaining 50 to irradiation method 2. The bacteria counts were measured and the following statistics were computed. The scientist noted that the data were normally distributed.  Method 1  Method 2 xˉ1=86xˉ2=98s12=324s22=841\begin{array} { | c | c | } \hline \text { Method 1 } & \text { Method 2 } \\\hline \bar { x } _ { 1 } = 86 & \bar { x } _ { 2 } = 98 \\\hline s _ { 1 } ^ { 2 } = 324 & s _ { 2 } ^ { 2 } = 841 \\\hline\end{array} Determine whether these data are sufficient to infer at the 5% significance level that the two population variances differ.
Question
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   Estimate a 95% confidence interval for the difference in final marks between semester 1 and semester 2 students in this statistics course. Assume that the population variances are unknown and equal.<div style=padding-top: 35px> Estimate a 95% confidence interval for the difference in final marks between semester 1
and semester 2 students in this statistics course. Assume that the population variances are unknown
and equal.
Question
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   (a) Can we conclude at the 5% level of significance that over 40% of students in the population scored a pass grade in semester 1, where a pass grade is 50% to 64%? (b) Find the p-value of the test and briefly explain how to use it to test the hypotheses.<div style=padding-top: 35px> (a) Can we conclude at the 5% level of significance that over 40% of students in the population scored a pass grade in semester 1, where a pass grade is 50% to 64%?
(b) Find the p-value of the test and briefly explain how to use it to test the hypotheses.
Question
The sampling distribution of the random variable of interest is the source of statistical inference.
Question
With hypothesis testing, there are only two types of errors: Type I error where we incorrectly reject Ho and Type II error where we incorrectly retain Ho.
Question
The irradiation of food to destroy bacteria is an increasingly common practice. In order to determine which one of two methods of irradiation is best, a scientist took a random sample of 100 one-kilogram packages of minced meat and subjected 50 of them to irradiation method 1 and the remaining 50 to irradiation method 2. The bacteria counts were measured and the following statistics were computed. The scientist noted that the data were normally distributed.  Method 1  Method 2 xˉ1=86xˉ2=98s12=324s22=841\begin{array} { | c | c | } \hline \text { Method 1 } & \text { Method 2 } \\\hline \bar { x } _ { 1 } = 86 & \bar { x } _ { 2 } = 98 \\\hline s _ { 1 } ^ { 2 } = 324 & s _ { 2 } ^ { 2 } = 841 \\\hline\end{array} a. Estimate with 95% confidence the ratio of the variances of the bacteria counts under the two methods, and briefly describe what the interval estimate tells you.
b. Do these results allow us to infer at the 5% significance level that there is a difference in bacteria count between methods 1 and 2?
c. Do these results allow us to infer at the 5% significance level that the mean bacteria count with method 1 is less than 95?
Question
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   Estimate and interpret a 90% confidence interval of the ratio of population variances of final student marks from semester 1 and semester 2.<div style=padding-top: 35px> Estimate and interpret a 90% confidence interval of the ratio of population variances of final student marks from semester 1 and semester 2.
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Deck 22: Statistical Inference: Conclusion
1
For a sample of size 25 observations taken from a normally distributed population. The sample standard deviation is 6, a 95% confidence interval estimate for the population mean would require the use of:

A) z = 1.96
B) t = 1.711
C) z = 1.645
D) t = 2.064
D
2
A random sample of 20 observations taken from a normally distributed population revealed a sample mean of 65 and a sample variance of 16. The lower limit of a 90% confidence interval for the population mean would equal:

A) 66.546.
B) 63.454.
C) 63.812.
D) 66.188.
B
3
Two independent samples of sizes 50 and 50 are randomly selected from two populations to test the difference between the population means, <strong>Two independent samples of sizes 50 and 50 are randomly selected from two populations to test the difference between the population means,   . The sampling distribution of the sample mean difference   is:</strong> A) normally distributed. B) approximately normal. C) t-distributed with 98 degrees of freedom. D) chi-squared distributed with 99 degrees of freedom. . The sampling distribution of the sample mean difference <strong>Two independent samples of sizes 50 and 50 are randomly selected from two populations to test the difference between the population means,   . The sampling distribution of the sample mean difference   is:</strong> A) normally distributed. B) approximately normal. C) t-distributed with 98 degrees of freedom. D) chi-squared distributed with 99 degrees of freedom. is:

A) normally distributed.
B) approximately normal.
C) t-distributed with 98 degrees of freedom.
D) chi-squared distributed with 99 degrees of freedom.
B
4
A sample of size 300 had 96 successes. The lower limit of the 99% confidence interval for the population proportion is:

A) 0.3728.
B) 0.2672.
C) 0.2506.
D) 0.3894.
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5
When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. The two sample proportions are p^1\hat { p } _ { 1 } = 0.21 and p^2\hat { p } _ { 2 } = 0.15, and the standard error of the sampling distribution of are p^1\hat { p } _ { 1 } - p^2\hat { p } _ { 2 } is 0.018. The calculated value of the test statistic will be:

A) t = -3.33.
B) z = 3.33.
C) t = 3.33.
D) None of these choices are correct.
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6
When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions, but your statistical software provides only a one-tail area of 0.03 as part of its output. The p-value for this test will be:

A) 0.03
B) 0.06
C) 0.05
D) None of these choices are correct.
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7
When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions, testing at the 5% level of significance. Which of the following is the p-value for this test if the calculated z test statistic is 1.34?

A) 0.0250
B) 0.1802
C) 0.0901
D) 0.9099
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8
A random sample of size 15 taken from a normally distributed population resulted in a sample variance of 25. The upper limit of a 99% confidence interval for the population variance would be:

A) 12.868.
B) 92.032.
C) 85.896.
D) 75.100.
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9
Assuming that all necessary conditions are met, what needs to be changed in the formula <strong>Assuming that all necessary conditions are met, what needs to be changed in the formula   so that we can use it to construct a confidence interval estimate for the difference of two population means when the population variances are assumed to be equal?</strong> A) The   should be replaced by   . B) The z   should be replaced by   . C) The z   should be replaced by   . D) The   should be replaced by   . so that we can use it to construct a confidence interval estimate for the difference of two population means when the population variances are assumed to be equal?

A) The <strong>Assuming that all necessary conditions are met, what needs to be changed in the formula   so that we can use it to construct a confidence interval estimate for the difference of two population means when the population variances are assumed to be equal?</strong> A) The   should be replaced by   . B) The z   should be replaced by   . C) The z   should be replaced by   . D) The   should be replaced by   . should be replaced by <strong>Assuming that all necessary conditions are met, what needs to be changed in the formula   so that we can use it to construct a confidence interval estimate for the difference of two population means when the population variances are assumed to be equal?</strong> A) The   should be replaced by   . B) The z   should be replaced by   . C) The z   should be replaced by   . D) The   should be replaced by   . .
B) The z <strong>Assuming that all necessary conditions are met, what needs to be changed in the formula   so that we can use it to construct a confidence interval estimate for the difference of two population means when the population variances are assumed to be equal?</strong> A) The   should be replaced by   . B) The z   should be replaced by   . C) The z   should be replaced by   . D) The   should be replaced by   . should be replaced by <strong>Assuming that all necessary conditions are met, what needs to be changed in the formula   so that we can use it to construct a confidence interval estimate for the difference of two population means when the population variances are assumed to be equal?</strong> A) The   should be replaced by   . B) The z   should be replaced by   . C) The z   should be replaced by   . D) The   should be replaced by   . .
C) The z <strong>Assuming that all necessary conditions are met, what needs to be changed in the formula   so that we can use it to construct a confidence interval estimate for the difference of two population means when the population variances are assumed to be equal?</strong> A) The   should be replaced by   . B) The z   should be replaced by   . C) The z   should be replaced by   . D) The   should be replaced by   . should be replaced by <strong>Assuming that all necessary conditions are met, what needs to be changed in the formula   so that we can use it to construct a confidence interval estimate for the difference of two population means when the population variances are assumed to be equal?</strong> A) The   should be replaced by   . B) The z   should be replaced by   . C) The z   should be replaced by   . D) The   should be replaced by   . .
D) The <strong>Assuming that all necessary conditions are met, what needs to be changed in the formula   so that we can use it to construct a confidence interval estimate for the difference of two population means when the population variances are assumed to be equal?</strong> A) The   should be replaced by   . B) The z   should be replaced by   . C) The z   should be replaced by   . D) The   should be replaced by   . should be replaced by <strong>Assuming that all necessary conditions are met, what needs to be changed in the formula   so that we can use it to construct a confidence interval estimate for the difference of two population means when the population variances are assumed to be equal?</strong> A) The   should be replaced by   . B) The z   should be replaced by   . C) The z   should be replaced by   . D) The   should be replaced by   . .
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10
In testing the null hypothesis <strong>In testing the null hypothesis   , if   is false, the test could lead to:</strong> A) Type I error. B) Type II error. C) Either a Type I or a Type II error. D) None of these choices are correct. , if <strong>In testing the null hypothesis   , if   is false, the test could lead to:</strong> A) Type I error. B) Type II error. C) Either a Type I or a Type II error. D) None of these choices are correct. is false, the test could lead to:

A) Type I error.
B) Type II error.
C) Either a Type I or a Type II error.
D) None of these choices are correct.
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11
In a hypothesis test for the population variance, the hypotheses are: <strong>In a hypothesis test for the population variance, the hypotheses are:   .   . If the sample size is 15 and the test is being carried out at the 5% level of significance, the null hypothesis will be rejected if:</strong> A)   . B)   . C)   . D)   . . <strong>In a hypothesis test for the population variance, the hypotheses are:   .   . If the sample size is 15 and the test is being carried out at the 5% level of significance, the null hypothesis will be rejected if:</strong> A)   . B)   . C)   . D)   . . If the sample size is 15 and the test is being carried out at the 5% level of significance, the null hypothesis will be rejected if:

A) <strong>In a hypothesis test for the population variance, the hypotheses are:   .   . If the sample size is 15 and the test is being carried out at the 5% level of significance, the null hypothesis will be rejected if:</strong> A)   . B)   . C)   . D)   . .
B) <strong>In a hypothesis test for the population variance, the hypotheses are:   .   . If the sample size is 15 and the test is being carried out at the 5% level of significance, the null hypothesis will be rejected if:</strong> A)   . B)   . C)   . D)   . .
C) <strong>In a hypothesis test for the population variance, the hypotheses are:   .   . If the sample size is 15 and the test is being carried out at the 5% level of significance, the null hypothesis will be rejected if:</strong> A)   . B)   . C)   . D)   . .
D) <strong>In a hypothesis test for the population variance, the hypotheses are:   .   . If the sample size is 15 and the test is being carried out at the 5% level of significance, the null hypothesis will be rejected if:</strong> A)   . B)   . C)   . D)   . .
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12
In constructing a 95% interval estimate for the ratio of two population variances, <strong>In constructing a 95% interval estimate for the ratio of two population variances,   /   , two independent samples of sizes 30 and 40 are drawn from the populations. If the sample variances are 425 and 675, then the upper confidence limit is about:</strong> A) 1.2215. B) 0.3132. C) 1.2656. D) 0.3246. / <strong>In constructing a 95% interval estimate for the ratio of two population variances,   /   , two independent samples of sizes 30 and 40 are drawn from the populations. If the sample variances are 425 and 675, then the upper confidence limit is about:</strong> A) 1.2215. B) 0.3132. C) 1.2656. D) 0.3246. , two independent samples of sizes 30 and 40 are drawn from the populations. If the sample variances are 425 and 675, then the upper confidence limit is about:

A) 1.2215.
B) 0.3132.
C) 1.2656.
D) 0.3246.
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13
In testing for the equality of two population variances, when the populations are normally distributed, the 5% level of significance has been used. To determine the rejection region, it will be necessary to refer to the F table corresponding to an upper-tail area of:

A) 0.950.
B) 0.050.
C) 0.025.
D) 0.100.
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14
In testing the difference between two population means for which the population variances are unknown and assumed to be equal, two independent samples are drawn from the populations. Which of the following tests is appropriate?

A) z-test.
B) Equal-variances t-test.
C) F-test.
D) Matched pairs t-test.
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15
In constructing a 90% confidence interval estimate for the difference between the means of two normally distributed populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows: <strong>In constructing a 90% confidence interval estimate for the difference between the means of two normally distributed populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   .   ,   ,   . The lower confidence limit is:</strong> A) 30.086. B) 8.542. C) 0.914. D) 31.458. , <strong>In constructing a 90% confidence interval estimate for the difference between the means of two normally distributed populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   .   ,   ,   . The lower confidence limit is:</strong> A) 30.086. B) 8.542. C) 0.914. D) 31.458. , <strong>In constructing a 90% confidence interval estimate for the difference between the means of two normally distributed populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   .   ,   ,   . The lower confidence limit is:</strong> A) 30.086. B) 8.542. C) 0.914. D) 31.458. . <strong>In constructing a 90% confidence interval estimate for the difference between the means of two normally distributed populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   .   ,   ,   . The lower confidence limit is:</strong> A) 30.086. B) 8.542. C) 0.914. D) 31.458. , <strong>In constructing a 90% confidence interval estimate for the difference between the means of two normally distributed populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   .   ,   ,   . The lower confidence limit is:</strong> A) 30.086. B) 8.542. C) 0.914. D) 31.458. , <strong>In constructing a 90% confidence interval estimate for the difference between the means of two normally distributed populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   .   ,   ,   . The lower confidence limit is:</strong> A) 30.086. B) 8.542. C) 0.914. D) 31.458. . The lower confidence limit is:

A) 30.086.
B) 8.542.
C) 0.914.
D) 31.458.
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16
Two independent samples of sizes 20 and 25 are randomly selected from two normal populations with equal variances. In order to test the difference between the population means, the test statistic is:

A) a standard normal random variable.
B) approximately standard normal random variable.
C) Student t distributed with 45 degrees of freedom.
D) Student t distributed with 43 degrees of freedom.
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17
In testing the difference between two population means using two independent samples, the population standard deviations are assumed to be known and the calculated test statistic equals 1.05. If the test is upper-tail and the 10% level of significance has been specified, the conclusion should be to:

A) reject the null hypothesis.
B) not to reject the null hypothesis.
C) choose two other independent samples.
D) None of these choices are correct.
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18
Which of the following statements is correct regarding the percentile points of the F-distribution?

A) <strong>Which of the following statements is correct regarding the percentile points of the F-distribution?</strong> A)   . B)   . C)   . D)   . .
B) <strong>Which of the following statements is correct regarding the percentile points of the F-distribution?</strong> A)   . B)   . C)   . D)   . .
C) <strong>Which of the following statements is correct regarding the percentile points of the F-distribution?</strong> A)   . B)   . C)   . D)   . .
D) <strong>Which of the following statements is correct regarding the percentile points of the F-distribution?</strong> A)   . B)   . C)   . D)   . .
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19
A sample of size 200 from population 1 has 50 successes. A sample of size 200 from population 2 has 40 successes. The value of the test statistic for testing the null hypothesis that the proportion of successes in population 1 exceeds the proportion of successes in population 2 by 0.025 is:

A) 1.96.
B) 1.25.
C) 0.5998.
D) 1.20.
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20
Based on sample data, the 95% confidence interval limits for the population mean are LCL = 124.6 and UCL = 148.2. If the 5% level of significance were used in testing the hypotheses:
H0 : μ\mu = 150
H1 : μ\mu\neq 150,
The null hypothesis:

A) would not be rejected.
B) would be rejected.
C) would have to be revised.
D) There is insufficient information to decide whether to maintain or reject the null hypothesis.
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21
The pooled-variance estimator, The pooled-variance estimator,   , requires that the two population variances be equal. , requires that the two population variances be equal.
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22
A one-tail test of the population proportion produces a test statistic z = -2.12. The p-value of the test is 0.034.
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23
In testing the hypotheses: H0 : μ\mu = 140
H1 : μ\mu \neq 140,
Suppose that we rejected the null hypothesis at α\alpha = 0.10. Then for which of the following α\alpha values do we also reject the null hypothesis?

A) 0.025
B) 0.01
C) 0.05
D) All of these choices are correct.
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24
A sample of size 125 selected from one population has 55 successes, and a sample of size 140 selected from a second population has 70 successes. The test statistic for testing the equality of the population proportions is equal to:

A) -0.060.
B) -0.977.
C) -0.940.
D) -0.472.
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25
A random sample of 30 observations is selected from a normally distributed population. The sample variance is 12. In the 90% confidence interval for the population variance, the upper limit will be:

A) 15.176.
B) 8.177.
C) 19.652.
D) 16.941.
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26
Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?

A) <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . and <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . .
B) <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . and <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . .
C) <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . and <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . .
D) <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . and <strong>Which of the following is a required condition for using the normal approximation to the binomial in constructing interval estimate for the difference between two population proportions?</strong> A)   and   . B)   and   . C)       and   . D)       and   . .
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27
When the necessary conditions are met, a one-tail test is being conducted to test the difference between two population proportions, but your statistical software provides only a two-tail area of 0.058 as part of its output. The p-value for this test will be:

A) 0.029.
B) 0.971.
C) 0.029 or 0.972, depending on whether the test is a left-tail or a right-tail test.
D) 0.058.
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28
In a hypothesis test for the population variance, the hypotheses are: <strong>In a hypothesis test for the population variance, the hypotheses are:     If the sample size is 25 and the test is being carried out at the 5% level of significance, the rejection region will be:</strong> A)   < 15.6587 or   > 33.1963. B)   <12.4011 or   >39.3641. C)   < 16.4734 or   >34.3816. D)   < 13.1197 or   <37.6525. <strong>In a hypothesis test for the population variance, the hypotheses are:     If the sample size is 25 and the test is being carried out at the 5% level of significance, the rejection region will be:</strong> A)   < 15.6587 or   > 33.1963. B)   <12.4011 or   >39.3641. C)   < 16.4734 or   >34.3816. D)   < 13.1197 or   <37.6525. If the sample size is 25 and the test is being carried out at the 5% level of significance, the rejection region will be:

A) <strong>In a hypothesis test for the population variance, the hypotheses are:     If the sample size is 25 and the test is being carried out at the 5% level of significance, the rejection region will be:</strong> A)   < 15.6587 or   > 33.1963. B)   <12.4011 or   >39.3641. C)   < 16.4734 or   >34.3816. D)   < 13.1197 or   <37.6525. < 15.6587 or <strong>In a hypothesis test for the population variance, the hypotheses are:     If the sample size is 25 and the test is being carried out at the 5% level of significance, the rejection region will be:</strong> A)   < 15.6587 or   > 33.1963. B)   <12.4011 or   >39.3641. C)   < 16.4734 or   >34.3816. D)   < 13.1197 or   <37.6525. > 33.1963.
B) <strong>In a hypothesis test for the population variance, the hypotheses are:     If the sample size is 25 and the test is being carried out at the 5% level of significance, the rejection region will be:</strong> A)   < 15.6587 or   > 33.1963. B)   <12.4011 or   >39.3641. C)   < 16.4734 or   >34.3816. D)   < 13.1197 or   <37.6525. <12.4011 or <strong>In a hypothesis test for the population variance, the hypotheses are:     If the sample size is 25 and the test is being carried out at the 5% level of significance, the rejection region will be:</strong> A)   < 15.6587 or   > 33.1963. B)   <12.4011 or   >39.3641. C)   < 16.4734 or   >34.3816. D)   < 13.1197 or   <37.6525. >39.3641.
C) <strong>In a hypothesis test for the population variance, the hypotheses are:     If the sample size is 25 and the test is being carried out at the 5% level of significance, the rejection region will be:</strong> A)   < 15.6587 or   > 33.1963. B)   <12.4011 or   >39.3641. C)   < 16.4734 or   >34.3816. D)   < 13.1197 or   <37.6525. < 16.4734 or <strong>In a hypothesis test for the population variance, the hypotheses are:     If the sample size is 25 and the test is being carried out at the 5% level of significance, the rejection region will be:</strong> A)   < 15.6587 or   > 33.1963. B)   <12.4011 or   >39.3641. C)   < 16.4734 or   >34.3816. D)   < 13.1197 or   <37.6525. >34.3816.
D) <strong>In a hypothesis test for the population variance, the hypotheses are:     If the sample size is 25 and the test is being carried out at the 5% level of significance, the rejection region will be:</strong> A)   < 15.6587 or   > 33.1963. B)   <12.4011 or   >39.3641. C)   < 16.4734 or   >34.3816. D)   < 13.1197 or   <37.6525. < 13.1197 or <strong>In a hypothesis test for the population variance, the hypotheses are:     If the sample size is 25 and the test is being carried out at the 5% level of significance, the rejection region will be:</strong> A)   < 15.6587 or   > 33.1963. B)   <12.4011 or   >39.3641. C)   < 16.4734 or   >34.3816. D)   < 13.1197 or   <37.6525. <37.6525.
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29
Two samples of size 30 each are independently drawn from two normal populations, where the unknown population variances are assumed to be equal. The number of degrees of freedom of the equal-variances t-test statistic is 59.
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30
Which of the following best describes a p-value?

A) A p-value is the probability of getting our population results or more extreme if the null hypothesis about the sample statistic were really true
B) A p-value is the probability of getting our sample results or more extreme if the null hypothesis about the population parameter were really true
C) A p-value is the probability of getting our sample results.
D) A p-value is the probability of getting our sample results or more extreme if the null hypothesis about the population parameter were really false
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31
When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. The two sample proportions are When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. The two sample proportions are   = 0.32 and   = 0.38, and the standard error of the sampling distribution of   is 0.046. The calculated value of the test statistic will be 1.3043. = 0.32 and When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. The two sample proportions are   = 0.32 and   = 0.38, and the standard error of the sampling distribution of   is 0.046. The calculated value of the test statistic will be 1.3043. = 0.38, and the standard error of the sampling distribution of When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. The two sample proportions are   = 0.32 and   = 0.38, and the standard error of the sampling distribution of   is 0.046. The calculated value of the test statistic will be 1.3043. is 0.046. The calculated value of the test statistic will be 1.3043.
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32
Which of the following is the number of degrees of freedom associated with the t-test, when the data are gathered from a matched pairs experiment with 30 pairs?

A) 30
B) 29
C) 28
D) 59
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33
When comparing two population variances, we test H0: When comparing two population variances, we test H<sub>0</sub>:   = 0. = 0.
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34
In testing whether the means of two normal populations are equal, summary statistics computed for two independent samples are as follows: <strong>In testing whether the means of two normal populations are equal, summary statistics computed for two independent samples are as follows:   ,   ,   .   ,   ,   . Assume that the population variances are unequal. The standard error of the sampling distribution of the sample mean difference   is equal to:</strong> A) 0.3247. B) 0.3282. C) 0.1054. D) 0.1125. , <strong>In testing whether the means of two normal populations are equal, summary statistics computed for two independent samples are as follows:   ,   ,   .   ,   ,   . Assume that the population variances are unequal. The standard error of the sampling distribution of the sample mean difference   is equal to:</strong> A) 0.3247. B) 0.3282. C) 0.1054. D) 0.1125. , <strong>In testing whether the means of two normal populations are equal, summary statistics computed for two independent samples are as follows:   ,   ,   .   ,   ,   . Assume that the population variances are unequal. The standard error of the sampling distribution of the sample mean difference   is equal to:</strong> A) 0.3247. B) 0.3282. C) 0.1054. D) 0.1125. . <strong>In testing whether the means of two normal populations are equal, summary statistics computed for two independent samples are as follows:   ,   ,   .   ,   ,   . Assume that the population variances are unequal. The standard error of the sampling distribution of the sample mean difference   is equal to:</strong> A) 0.3247. B) 0.3282. C) 0.1054. D) 0.1125. , <strong>In testing whether the means of two normal populations are equal, summary statistics computed for two independent samples are as follows:   ,   ,   .   ,   ,   . Assume that the population variances are unequal. The standard error of the sampling distribution of the sample mean difference   is equal to:</strong> A) 0.3247. B) 0.3282. C) 0.1054. D) 0.1125. , <strong>In testing whether the means of two normal populations are equal, summary statistics computed for two independent samples are as follows:   ,   ,   .   ,   ,   . Assume that the population variances are unequal. The standard error of the sampling distribution of the sample mean difference   is equal to:</strong> A) 0.3247. B) 0.3282. C) 0.1054. D) 0.1125. . Assume that the population variances are unequal. The standard error of the sampling distribution of the sample mean difference <strong>In testing whether the means of two normal populations are equal, summary statistics computed for two independent samples are as follows:   ,   ,   .   ,   ,   . Assume that the population variances are unequal. The standard error of the sampling distribution of the sample mean difference   is equal to:</strong> A) 0.3247. B) 0.3282. C) 0.1054. D) 0.1125. is equal to:

A) 0.3247.
B) 0.3282.
C) 0.1054.
D) 0.1125.
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35
From a sample of 500 items, 30 were found to be defective. The point estimate of the population proportion defective will be:

A) 0.06.
B) 30.0.
C) 16.667.
D) None of these choices are correct.
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36
If we reject a null hypothesis at the 0.05 level of significance, then we must also reject it at the 0.10 level.
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37
In testing the hypotheses: <strong>In testing the hypotheses:     , at the 10% significance level, if the sample proportion is 0.56, and the standard error of the sample proportion is 0.025, the appropriate conclusion is:</strong> A) to reject   . B) not to reject   . C) to reject   . D) to reject both   and   . <strong>In testing the hypotheses:     , at the 10% significance level, if the sample proportion is 0.56, and the standard error of the sample proportion is 0.025, the appropriate conclusion is:</strong> A) to reject   . B) not to reject   . C) to reject   . D) to reject both   and   . , at the 10% significance level, if the sample proportion is 0.56, and the standard error of the sample proportion is 0.025, the appropriate conclusion is:

A) to reject <strong>In testing the hypotheses:     , at the 10% significance level, if the sample proportion is 0.56, and the standard error of the sample proportion is 0.025, the appropriate conclusion is:</strong> A) to reject   . B) not to reject   . C) to reject   . D) to reject both   and   . .
B) not to reject <strong>In testing the hypotheses:     , at the 10% significance level, if the sample proportion is 0.56, and the standard error of the sample proportion is 0.025, the appropriate conclusion is:</strong> A) to reject   . B) not to reject   . C) to reject   . D) to reject both   and   . .
C) to reject <strong>In testing the hypotheses:     , at the 10% significance level, if the sample proportion is 0.56, and the standard error of the sample proportion is 0.025, the appropriate conclusion is:</strong> A) to reject   . B) not to reject   . C) to reject   . D) to reject both   and   . .
D) to reject both <strong>In testing the hypotheses:     , at the 10% significance level, if the sample proportion is 0.56, and the standard error of the sample proportion is 0.025, the appropriate conclusion is:</strong> A) to reject   . B) not to reject   . C) to reject   . D) to reject both   and   . and <strong>In testing the hypotheses:     , at the 10% significance level, if the sample proportion is 0.56, and the standard error of the sample proportion is 0.025, the appropriate conclusion is:</strong> A) to reject   . B) not to reject   . C) to reject   . D) to reject both   and   . .
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38
For a sample of 25 observations taken from a normally distributed population with standard deviation of 6, a 95% confidence interval estimate for the population mean would require the use of:

A) t = 2.064.
B) t = 1.711.
C) X2 = 39.3641.
D) z = 1.96.
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39
Suppose that a one-tail t-test is being applied to find out if the population mean is at least 80. The level of significance is 0.10 and 25 observations were sampled. The rejection region is:

A) t > 2.492
B) t > 1.711
C) t < − 2.492
D) t > 1.318
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40
Two independent samples of sizes 35 and 40 are randomly selected from two normally distributed populations. Assume that the population variances are unknown but equal. In order to test the difference between the population means, <strong>Two independent samples of sizes 35 and 40 are randomly selected from two normally distributed populations. Assume that the population variances are unknown but equal. In order to test the difference between the population means,   , the sampling distribution of the sample mean difference,   , is:</strong> A) normally distributed. B) t-distributed with 75 degrees of freedom. C) t-distributed with 73 degrees of freedom. D) F-distributed with 34 and 39 degrees of freedom. , the sampling distribution of the sample mean difference, <strong>Two independent samples of sizes 35 and 40 are randomly selected from two normally distributed populations. Assume that the population variances are unknown but equal. In order to test the difference between the population means,   , the sampling distribution of the sample mean difference,   , is:</strong> A) normally distributed. B) t-distributed with 75 degrees of freedom. C) t-distributed with 73 degrees of freedom. D) F-distributed with 34 and 39 degrees of freedom. , is:

A) normally distributed.
B) t-distributed with 75 degrees of freedom.
C) t-distributed with 73 degrees of freedom.
D) F-distributed with 34 and 39 degrees of freedom.
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41
If a sample has 25 observations and a 99% confidence estimate for If a sample has 25 observations and a 99% confidence estimate for   is needed, the appropriate t-score is 2.797. is needed, the appropriate t-score is 2.797.
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42
If a sample has 12 observations and a 90% confidence estimate for µ is needed, the appropriate t-critical value from the t tables is 1.796.
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43
If a sample of size 25 is selected, the value of A for the probability P(tdf=n-1 If a sample of size 25 is selected, the value of A for the probability P(t<sub>df=n-1</sub>   A) = 0.05 is 1.708. A) = 0.05 is 1.708.
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44
When the necessary conditions are met, a two-tail test is being conducted at When the necessary conditions are met, a two-tail test is being conducted at   = 0.025 to test H<sub>0</sub>:   = 1. The two sample variances are   = 375 and   = 625, and the sample sizes are n<sub>1</sub> = 36 and n<sub>2</sub> = 36. The calculated value of the test statistic will be F = 0.60. = 0.025 to test
H0: When the necessary conditions are met, a two-tail test is being conducted at   = 0.025 to test H<sub>0</sub>:   = 1. The two sample variances are   = 375 and   = 625, and the sample sizes are n<sub>1</sub> = 36 and n<sub>2</sub> = 36. The calculated value of the test statistic will be F = 0.60. = 1. The two sample variances are When the necessary conditions are met, a two-tail test is being conducted at   = 0.025 to test H<sub>0</sub>:   = 1. The two sample variances are   = 375 and   = 625, and the sample sizes are n<sub>1</sub> = 36 and n<sub>2</sub> = 36. The calculated value of the test statistic will be F = 0.60. = 375 and When the necessary conditions are met, a two-tail test is being conducted at   = 0.025 to test H<sub>0</sub>:   = 1. The two sample variances are   = 375 and   = 625, and the sample sizes are n<sub>1</sub> = 36 and n<sub>2</sub> = 36. The calculated value of the test statistic will be F = 0.60. = 625, and the sample sizes are
n1 = 36 and n2 = 36. The calculated value of the test statistic will be F = 0.60.
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45
We use the F-test to determine whether two population variances are equal.
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46
When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population means, but your statistical software provides only a one-tail area of 0.0327 as part of its output. The p-value for this test will be 0.0654.
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47
The equal-variances test statistic of The equal-variances test statistic of   is Student t-distributed with n<sub>1</sub> + n<sub>2</sub> - 2 degrees of freedom, provided that the two sample sizes are equal. is Student t-distributed with n1 + n2 - 2 degrees of freedom, provided that the two sample sizes are equal.
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48
When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. If the value of the test statistic z is 1.53, then the p-value is 0.126.
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49
The number of degrees of freedom associated with the t-test, when the data are gathered from a matched pairs experiment with 8 pairs, is 14.
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50
If a null hypothesis about the population proportion p is rejected at the 0.05 level of significance, it must be rejected at the 0.01 level.
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51
The upper limit of the 89.9% confidence interval for the population proportion p, given that n = 80 and P^\hat{P} = 0.40, is 0.4898.
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52
The lower limit of the 87.4% confidence interval for the population proportion p, given that n = 250 and P^\hat{P} = 0.15, is 0.1492.
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53
If a sample of size 300 is selected, the value of A for the probability P(-A If a sample of size 300 is selected, the value of A for the probability P(-A   t<sub>df=n-1</sub>   A) = 0.90 is 1.96. tdf=n-1 If a sample of size 300 is selected, the value of A for the probability P(-A   t<sub>df=n-1</sub>   A) = 0.90 is 1.96. A) = 0.90 is 1.96.
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54
When the necessary conditions are met, a two-tail test is being conducted at When the necessary conditions are met, a two-tail test is being conducted at   = 0.10 to test H₀:   = 1. The two sample variances are   = 736 and   = 1024, and the sample sizes are n<sub>1</sub> = 16 and n<sub>2</sub> = 25. The rejection region is F > 2.11 or F < 0.4367. = 0.10 to test H₀: When the necessary conditions are met, a two-tail test is being conducted at   = 0.10 to test H₀:   = 1. The two sample variances are   = 736 and   = 1024, and the sample sizes are n<sub>1</sub> = 16 and n<sub>2</sub> = 25. The rejection region is F > 2.11 or F < 0.4367. = 1. The two sample variances are When the necessary conditions are met, a two-tail test is being conducted at   = 0.10 to test H₀:   = 1. The two sample variances are   = 736 and   = 1024, and the sample sizes are n<sub>1</sub> = 16 and n<sub>2</sub> = 25. The rejection region is F > 2.11 or F < 0.4367. = 736 and When the necessary conditions are met, a two-tail test is being conducted at   = 0.10 to test H₀:   = 1. The two sample variances are   = 736 and   = 1024, and the sample sizes are n<sub>1</sub> = 16 and n<sub>2</sub> = 25. The rejection region is F > 2.11 or F < 0.4367. = 1024, and the sample sizes are n1 = 16 and n2 = 25. The rejection region is F > 2.11 or F < 0.4367.
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55
If a sample has 300 observations and a 97.5% confidence estimate for p is needed, the appropriate z-score is 2.24.
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56
Descriptive statistics helps us describe and summarise data whereas inferential statistics helps us draw conclusions about populations based on samples of data.
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57
If a sample of size 28 is selected, the value of A for the probability P(-A If a sample of size 28 is selected, the value of A for the probability P(-A   t<sub>df=n-1</sub> t   A) = 0.99 is 2.771. tdf=n-1 t If a sample of size 28 is selected, the value of A for the probability P(-A   t<sub>df=n-1</sub> t   A) = 0.99 is 2.771. A) = 0.99 is 2.771.
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58
Both the equal-variances and unequal-variances t-test statistics of Both the equal-variances and unequal-variances t-test statistics of   require that the two populations be Student t-distributed. require that the two populations be Student t-distributed.
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59
If a sample has 20 observations and a 95% confidence estimate for If a sample has 20 observations and a 95% confidence estimate for   is needed, the appropriate t-score is 1.729. is needed, the appropriate t-score is 1.729.
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60
In a one-tail test, the p-value is found to be equal to 0.0456. If the test had been two-tailed, the p-value would have been 0.0912.
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61
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   Estimate a 95% confidence interval for the difference in the proportions of students who received a high distinction in semester 1 to semester 2. Estimate a 95% confidence interval for the difference in the proportions of students who received a high distinction in semester 1 to semester 2.
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62
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   (a) Can we conclude at the 5% level of significance that semester 1 students have a higher proportion of high distinctions than semester 2 students, where a high distinction is a final mark greater than or equal to 85%? (b) Find the p-value of the test, and explain how to use it to test the hypotheses. (a) Can we conclude at the 5% level of significance that semester 1 students have a higher proportion of high distinctions than semester 2 students, where a high distinction is a final mark greater than or equal to 85%?
(b) Find the p-value of the test, and explain how to use it to test the hypotheses.
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63
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   Estimate and interpret a 95% confidence interval for the population average final mark for semester 1 students. Estimate and interpret a 95% confidence interval for the population average final mark for semester 1 students.
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64
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   (a) Determine whether these data are sufficient to infer at the 10% level of significance that the two population variances differ. (b) Explain the decision of your test in part (a) in the context of this question. (a) Determine whether these data are sufficient to infer at the 10% level of significance that the two population variances differ.
(b) Explain the decision of your test in part (a) in the context of this question.
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65
The irradiation of food to destroy bacteria is an increasingly common practice. In order to determine which one of two methods of irradiation is best, a scientist took a random sample of 100 one-kilogram packages of minced meat and subjected 50 of them to irradiation method 1 and the remaining 50 to irradiation method 2. The bacteria counts were measured and the following statistics were computed. The scientist noted that the data were normally distributed. The irradiation of food to destroy bacteria is an increasingly common practice. In order to determine which one of two methods of irradiation is best, a scientist took a random sample of 100 one-kilogram packages of minced meat and subjected 50 of them to irradiation method 1 and the remaining 50 to irradiation method 2. The bacteria counts were measured and the following statistics were computed. The scientist noted that the data were normally distributed.   Estimate with 95% confidence the difference in the mean bacteria counts between method 1 and method 2. Estimate with 95% confidence the difference in the mean bacteria counts between method 1 and method 2.
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66
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   Can we conclude at the 5% significance level that the variance of semester 2 student's final marks is greater than 150? Can we conclude at the 5% significance level that the variance of semester 2 student's final marks is greater than 150?
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67
The sampling distributions we use for nominal (categorical) data are the Standard Normal distribution and the Chi-squared distribution.
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68
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   Estimate and interpret a 95% confidence interval for the population average final mark for semester 2 students. Estimate and interpret a 95% confidence interval for the population average final mark for semester 2 students.
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69
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   There is a rumor going around the university that students with a higher IQ are enrolled in the semester 1 statistics course because they tend to be students enrolled in the degree with the higher entrance score for university. Can it be concluded at the 5% significance level that semester 1 students have a higher average final mark than semester 2 students? Assume that the population variances are unknown and equal. There is a rumor going around the university that students with a higher IQ are enrolled in the semester 1 statistics course because they tend to be students enrolled in the degree with the higher entrance score for university. Can it be concluded at the 5% significance level that semester 1 students have a higher average final mark than semester 2 students? Assume that the population variances are unknown and equal.
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70
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   Estimate and interpret a 95% confidence interval for the proportion of semester 2 students that passed the course. Estimate and interpret a 95% confidence interval for the proportion of semester 2 students that passed the course.
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71
The irradiation of food to destroy bacteria is an increasingly common practice. In order to determine which one of two methods of irradiation is best, a scientist took a random sample of 100 one-kilogram packages of minced meat and subjected 50 of them to irradiation method 1 and the remaining 50 to irradiation method 2. The bacteria counts were measured and the following statistics were computed. The scientist noted that the data were normally distributed. The irradiation of food to destroy bacteria is an increasingly common practice. In order to determine which one of two methods of irradiation is best, a scientist took a random sample of 100 one-kilogram packages of minced meat and subjected 50 of them to irradiation method 1 and the remaining 50 to irradiation method 2. The bacteria counts were measured and the following statistics were computed. The scientist noted that the data were normally distributed.   Estimate with 95% confidence the mean bacteria count with method 2. Estimate with 95% confidence the mean bacteria count with method 2.
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72
The sampling distributions we use for numerical data are the Standard Normal distribution, the Student's t-distribution and the F distribution.
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73
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   Can we conclude at the 5% significance level that the variance of semester 1 student's final marks is greater than 150? Can we conclude at the 5% significance level that the variance of semester 1 student's final marks is greater than 150?
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74
The irradiation of food to destroy bacteria is an increasingly common practice. In order to determine which one of two methods of irradiation is best, a scientist took a random sample of 100 one-kilogram packages of minced meat and subjected 50 of them to irradiation method 1 and the remaining 50 to irradiation method 2. The bacteria counts were measured and the following statistics were computed. The scientist noted that the data were normally distributed.  Method 1  Method 2 xˉ1=86xˉ2=98s12=324s22=841\begin{array} { | c | c | } \hline \text { Method 1 } & \text { Method 2 } \\\hline \bar { x } _ { 1 } = 86 & \bar { x } _ { 2 } = 98 \\\hline s _ { 1 } ^ { 2 } = 324 & s _ { 2 } ^ { 2 } = 841 \\\hline\end{array} Determine whether these data are sufficient to infer at the 5% significance level that the two population variances differ.
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75
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   Estimate a 95% confidence interval for the difference in final marks between semester 1 and semester 2 students in this statistics course. Assume that the population variances are unknown and equal. Estimate a 95% confidence interval for the difference in final marks between semester 1
and semester 2 students in this statistics course. Assume that the population variances are unknown
and equal.
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76
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   (a) Can we conclude at the 5% level of significance that over 40% of students in the population scored a pass grade in semester 1, where a pass grade is 50% to 64%? (b) Find the p-value of the test and briefly explain how to use it to test the hypotheses. (a) Can we conclude at the 5% level of significance that over 40% of students in the population scored a pass grade in semester 1, where a pass grade is 50% to 64%?
(b) Find the p-value of the test and briefly explain how to use it to test the hypotheses.
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77
The sampling distribution of the random variable of interest is the source of statistical inference.
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78
With hypothesis testing, there are only two types of errors: Type I error where we incorrectly reject Ho and Type II error where we incorrectly retain Ho.
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79
The irradiation of food to destroy bacteria is an increasingly common practice. In order to determine which one of two methods of irradiation is best, a scientist took a random sample of 100 one-kilogram packages of minced meat and subjected 50 of them to irradiation method 1 and the remaining 50 to irradiation method 2. The bacteria counts were measured and the following statistics were computed. The scientist noted that the data were normally distributed.  Method 1  Method 2 xˉ1=86xˉ2=98s12=324s22=841\begin{array} { | c | c | } \hline \text { Method 1 } & \text { Method 2 } \\\hline \bar { x } _ { 1 } = 86 & \bar { x } _ { 2 } = 98 \\\hline s _ { 1 } ^ { 2 } = 324 & s _ { 2 } ^ { 2 } = 841 \\\hline\end{array} a. Estimate with 95% confidence the ratio of the variances of the bacteria counts under the two methods, and briefly describe what the interval estimate tells you.
b. Do these results allow us to infer at the 5% significance level that there is a difference in bacteria count between methods 1 and 2?
c. Do these results allow us to infer at the 5% significance level that the mean bacteria count with method 1 is less than 95?
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80
A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample.
Assume that student final marks are normally distributed in each semester. A statistics course at a large university is taught in each semester. A student has noticed that the students in semester 1 and semester 2 are enrolled in different degrees. To investigate, the student takes a random sample of 25 students from semester 1 and 25 students from semester 2 and records their final marks (%) provided in the table below. Excel was used to generate descriptive statistics on each sample. Assume that student final marks are normally distributed in each semester.   Estimate and interpret a 90% confidence interval of the ratio of population variances of final student marks from semester 1 and semester 2. Estimate and interpret a 90% confidence interval of the ratio of population variances of final student marks from semester 1 and semester 2.
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Unlock Deck
Unlock for access to all 103 flashcards in this deck.