Deck 14: Vector-Valued Functions and Motion in Space
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Deck 14: Vector-Valued Functions and Motion in Space
1


A) x = 13t, y = t, z = t
B) x = 10 + t, y = t, z = t
C) x = 10 + 13t, y = 9 + t, z = 1
D) x = 10 + 13t, y = 9 + t, z = 0
C
2
The position vector of a particle is r(t). Find the requested vector.

A) a(1) = -36i - j + 8k
B) a(1) = -9i + 8k
C) a(1) = 36i + 8k
D) a(1) = -36i + 8k

A) a(1) = -36i - j + 8k
B) a(1) = -9i + 8k
C) a(1) = 36i + 8k
D) a(1) = -36i + 8k
D
3
The position vector of a particle is r(t). Find the requested vector.


C
4
The position vector of a particle is r(t). Find the requested vector.


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5
The position vector of a particle is r(t). Find the requested vector.


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6
If r(t) is the position vector of a particle in the plane at time t, find the indicated vector.


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7
The position vector of a particle is r(t). Find the requested vector.


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8
The position vector of a particle is r(t). Find the requested vector.


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9
The vector r(t) is the position vector of a particle at time t. Find the angle between the velocity and the acceleration vectors
at time t = 0.

at time t = 0.

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10
The position vector of a particle is r(t). Find the requested vector.

A) v(3) = 46i + 81j + 6k
B) v(3) = 25i - 27j - 3k
C) v(3) = 46i - 81j - 6k
D) v(3) = 38i - 81j - 6k

A) v(3) = 46i + 81j + 6k
B) v(3) = 25i - 27j - 3k
C) v(3) = 46i - 81j - 6k
D) v(3) = 38i - 81j - 6k
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11
The position vector of a particle is r(t). Find the requested vector.


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12
If r(t) is the position vector of a particle in the plane at time t, find the indicated vector.


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13
The position vector of a particle is r(t). Find the requested vector.


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14
The vector r(t) is the position vector of a particle at time t. Find the angle between the velocity and the acceleration vectors
at time t = 0.

at time t = 0.

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15
If r(t) is the position vector of a particle in the plane at time t, find the indicated vector.
Find the acceleration vector. r(t) = (cos 4t)i + (5 sin t)j
A) a = (-4 cos 4t)i + (5 sin t)j
B) a = (-16 cos 4t)i + (-5 sin t)j
C) a = (-16 cos 4t)i + (-25 sin t)j
D) a = (16 cos 4t)i + (-5 sin t)j
Find the acceleration vector. r(t) = (cos 4t)i + (5 sin t)j
A) a = (-4 cos 4t)i + (5 sin t)j
B) a = (-16 cos 4t)i + (-5 sin t)j
C) a = (-16 cos 4t)i + (-25 sin t)j
D) a = (16 cos 4t)i + (-5 sin t)j
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16
If r(t) is the position vector of a particle in the plane at time t, find the indicated vector.
Find the velocity vector. r(t) = (cot t)i + (csc t)j
Find the velocity vector. r(t) = (cot t)i + (csc t)j

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17
The position vector of a particle is r(t). Find the requested vector.


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18
The vector r(t) is the position vector of a particle at time t. Find the angle between the velocity and the acceleration vectors
at time t = 0.

at time t = 0.

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19
If r(t) is the position vector of a particle in the plane at time t, find the indicated vector.
Find the acceleration vector. r(t) = (6 cos t)i + (9 sin t)j
A) a = (6 cos t)i + (9 sin t)j
B) a = (-6 cos t)i + (-9 sin t)j
C) a = (-6 sin t)i + (-9 cos t)j
D) a = (6 sin t)i + (9 cos t)j
Find the acceleration vector. r(t) = (6 cos t)i + (9 sin t)j
A) a = (6 cos t)i + (9 sin t)j
B) a = (-6 cos t)i + (-9 sin t)j
C) a = (-6 sin t)i + (-9 cos t)j
D) a = (6 sin t)i + (9 cos t)j
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20
The vector r(t) is the position vector of a particle at time t. Find the angle between the velocity and the acceleration vectors
at time t = 0.

at time t = 0.

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21
Evaluate the integral.


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22
Provide an appropriate response.

A) Path (4) and Path (2)
B) Path (1)
C) Path (2) and Path (3)
D) Path (3)

A) Path (4) and Path (2)
B) Path (1)
C) Path (2) and Path (3)
D) Path (3)
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23
Evaluate the integral.


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24
Solve the initial value problem.


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25
Evaluate the integral.


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26
Provide an appropriate response.
Show that if a particle's velocity vector is always orthogonal to its acceleration vector then the particle's speed is
constant.
Show that if a particle's velocity vector is always orthogonal to its acceleration vector then the particle's speed is
constant.
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27


A) x = 10, y = -3t, z = -8 + t
B) x = 10t, y = -3, z = 1 - t
C) x = 10t, y = 3, z = 1 + t
D) x = 10t, y = -3, z = 1 - 8t
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28
Provide an appropriate response.

A) Path (2) and Path (4)
B) Path (4)
C) Path (3)
D) Path (1)

A) Path (2) and Path (4)
B) Path (4)
C) Path (3)
D) Path (1)
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29
Evaluate the integral.


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30
Evaluate the integral.


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31
Provide an appropriate response.


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32
Evaluate the integral.


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33
Evaluate the integral.


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34
Solve the initial value problem.


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35
Evaluate the integral.


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36
Provide an appropriate response.


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37
Solve the initial value problem.


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38
Solve the initial value problem.


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39
Provide an appropriate response.
The position of a particle is given by r(t) = sin 8t i + cos 3t j. Find the velocity vector for the particle.
A) cos 8t i - sin 3t j
B) 8 i + 3 j
C) 8 cos 8t i - 3 sin 3t j
D) 8 sin 8t i + 3 cos 3t j
The position of a particle is given by r(t) = sin 8t i + cos 3t j. Find the velocity vector for the particle.
A) cos 8t i - sin 3t j
B) 8 i + 3 j
C) 8 cos 8t i - 3 sin 3t j
D) 8 sin 8t i + 3 cos 3t j
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40


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41
Solve the problem. Unless stated otherwise, assume that the projectile flight is ideal, that the launch angle is measured
from the horizontal, and that the projectile is launched from the origin over a horizontal surface

A) 2 ft
B) 74.4 ft
C) 227.8 ft
D) 6.8 ft
from the horizontal, and that the projectile is launched from the origin over a horizontal surface

A) 2 ft
B) 74.4 ft
C) 227.8 ft
D) 6.8 ft
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42
Solve the problem.
At time t = 0 a particle is located at the point (4, -3, 2). It travels in a straight line to the point (6, -2, 1), has speed 2 at (4, -3, 2) and constant acceleration 6i - j - k. Find an equation for the position vector r(t) of the particle at time t.
At time t = 0 a particle is located at the point (4, -3, 2). It travels in a straight line to the point (6, -2, 1), has speed 2 at (4, -3, 2) and constant acceleration 6i - j - k. Find an equation for the position vector r(t) of the particle at time t.

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43
Solve the initial value problem.


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44
Solve the problem. Unless stated otherwise, assume that the projectile flight is ideal, that the launch angle is measured
from the horizontal, and that the projectile is launched from the origin over a horizontal surface

A) 33 sec
B) 35 sec
C) 37 sec
D) It will never get that far downrange.
from the horizontal, and that the projectile is launched from the origin over a horizontal surface

A) 33 sec
B) 35 sec
C) 37 sec
D) It will never get that far downrange.
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45
Solve the problem. Unless stated otherwise, assume that the projectile flight is ideal, that the launch angle is measured
from the horizontal, and that the projectile is launched from the origin over a horizontal surface

A) 26,749.4 m
B) 6687.3 m
C) 73.9 m
D) 65,536.0 m
from the horizontal, and that the projectile is launched from the origin over a horizontal surface

A) 26,749.4 m
B) 6687.3 m
C) 73.9 m
D) 65,536.0 m
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46
Solve the initial value problem.


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47
Solve the problem. Unless stated otherwise, assume that the projectile flight is ideal, that the launch angle is measured
from the horizontal, and that the projectile is launched from the origin over a horizontal surface

A) 14.7 m/sec
B) 11.3 m/sec
C) 128.7 m/sec
D) 3.6 m/sec
from the horizontal, and that the projectile is launched from the origin over a horizontal surface

A) 14.7 m/sec
B) 11.3 m/sec
C) 128.7 m/sec
D) 3.6 m/sec
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48
Solve the problem. Unless stated otherwise, assume that the projectile flight is ideal, that the launch angle is measured
from the horizontal, and that the projectile is launched from the origin over a horizontal surface

A) 2.1 sec
B) 1.9 sec
C) 1.0 sec
D) 4.3 sec
from the horizontal, and that the projectile is launched from the origin over a horizontal surface

A) 2.1 sec
B) 1.9 sec
C) 1.0 sec
D) 4.3 sec
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49
Solve the initial value problem.


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50
Provide an appropriate response.


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51
Solve the problem. Unless stated otherwise, assume that the projectile flight is ideal, that the launch angle is measured
from the horizontal, and that the projectile is launched from the origin over a horizontal surface
Find the muzzle speed of a gun whose maximum range is 18.8 km. Round your answer to the nearest tenth.
A) 13.6 km/sec
B) 14.1 km/sec
C) 184.2 km/sec
D) 184.7 km/sec
from the horizontal, and that the projectile is launched from the origin over a horizontal surface
Find the muzzle speed of a gun whose maximum range is 18.8 km. Round your answer to the nearest tenth.
A) 13.6 km/sec
B) 14.1 km/sec
C) 184.2 km/sec
D) 184.7 km/sec
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52
Provide an appropriate response.
Increasing the initial speed of a projectile by a factor of 6 increases its range by what factor? Assume the elevation is the same.
A) Factor of 6
B) Factor of 2.45
C) The elevation must be specified before an answer can be found.
D) Factor of 36
Increasing the initial speed of a projectile by a factor of 6 increases its range by what factor? Assume the elevation is the same.
A) Factor of 6
B) Factor of 2.45
C) The elevation must be specified before an answer can be found.
D) Factor of 36
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53
Solve the initial value problem.


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54
Solve the problem. Unless stated otherwise, assume that the projectile flight is ideal, that the launch angle is measured
from the horizontal, and that the projectile is launched from the origin over a horizontal surface

from the horizontal, and that the projectile is launched from the origin over a horizontal surface

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55
Solve the problem. Unless stated otherwise, assume that the projectile flight is ideal, that the launch angle is measured
from the horizontal, and that the projectile is launched from the origin over a horizontal surface

from the horizontal, and that the projectile is launched from the origin over a horizontal surface

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56
Solve the initial value problem.


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57
Solve the problem. Unless stated otherwise, assume that the projectile flight is ideal, that the launch angle is measured
from the horizontal, and that the projectile is launched from the origin over a horizontal surface

A) 71.0 ft
B) 84.0 ft
C) 82.0 ft
D) 78.8 ft
from the horizontal, and that the projectile is launched from the origin over a horizontal surface

A) 71.0 ft
B) 84.0 ft
C) 82.0 ft
D) 78.8 ft
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58
Provide an appropriate response.
What two angles of elevation will enable a projectile to reach a target 17 km downrange on the same level as the gun if the projectile's initial speed is 420 m/sec? Assume there is no wind resistance.
What two angles of elevation will enable a projectile to reach a target 17 km downrange on the same level as the gun if the projectile's initial speed is 420 m/sec? Assume there is no wind resistance.

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59
Provide an appropriate response.


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60
Solve the problem. Unless stated otherwise, assume that the projectile flight is ideal, that the launch angle is measured
from the horizontal, and that the projectile is launched from the origin over a horizontal surface
An ideal projectile is launched from the origin at an angle of α radians to the horizontal and an initial speed of 175 ft/sec. Find the position function r(t) for this projectile.
from the horizontal, and that the projectile is launched from the origin over a horizontal surface
An ideal projectile is launched from the origin at an angle of α radians to the horizontal and an initial speed of 175 ft/sec. Find the position function r(t) for this projectile.

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61
Calculate the arc length of the indicated portion of the curve r(t).

A) -1089
B) -99
C) 121
D) 1331

A) -1089
B) -99
C) 121
D) 1331
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62
Find the unit tangent vector of the given curve.

A) T = (5 sin 9t)i - (5 cos 9t)j
B) T = (sin 9t)i - (cos 9t)j
C) T = (135 sin 9t)i -(135 cos 9t)j
D) T = (5 cos 9t)i - (5 sin 9t)j

A) T = (5 sin 9t)i - (5 cos 9t)j
B) T = (sin 9t)i - (cos 9t)j
C) T = (135 sin 9t)i -(135 cos 9t)j
D) T = (5 cos 9t)i - (5 sin 9t)j
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63
Calculate the arc length of the indicated portion of the curve r(t).

A) -35
B) 45
C) -175
D) 225

A) -35
B) 45
C) -175
D) 225
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64
Provide an appropriate response.

A) Maximum height = 3.48 feet;
B) Maximum height = 0.21 feet; time to maximum height = 0.05 sec time to maximum height = -0.21 sec
C) Maximum height = 3.51 feet;
D) Maximum height = 8.71 feet; time to maximum height = 0.02 sec time to maximum height = 0.74 sec

A) Maximum height = 3.48 feet;
B) Maximum height = 0.21 feet; time to maximum height = 0.05 sec time to maximum height = -0.21 sec
C) Maximum height = 3.51 feet;
D) Maximum height = 8.71 feet; time to maximum height = 0.02 sec time to maximum height = 0.74 sec
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65
Calculate the arc length of the indicated portion of the curve r(t).

A) 9
B) 45
C) 27
D) 15

A) 9
B) 45
C) 27
D) 15
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66
Calculate the arc length of the indicated portion of the curve r(t).

A) 112
B) 56
C) 119
D) 238

A) 112
B) 56
C) 119
D) 238
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67
Calculate the arc length of the indicated portion of the curve r(t).

A) 270
B) 558
C) 450
D) 297

A) 270
B) 558
C) 450
D) 297
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68
Provide an appropriate response.


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69
Calculate the arc length of the indicated portion of the curve r(t).


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70
Provide an appropriate response.


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71
Find the unit tangent vector of the given curve.
r(t) = (7t cos t - 7 sin t)j + (7t sin t + 7 cos t)k
r(t) = (7t cos t - 7 sin t)j + (7t sin t + 7 cos t)k

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72
Calculate the arc length of the indicated portion of the curve r(t).

A) 300
B) 4500
C) 18,000
D) 1200

A) 300
B) 4500
C) 18,000
D) 1200
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73
Provide an appropriate response.


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74
Provide an appropriate response.

A) Flight time = 3.97 sec; range = 424.4 feet
B) Flight time = 3.74 sec; range = 413.5 feet
C) Flight time = 2.82 sec; range = 393.5 feet
D) Flight time = 3.62 sec; range = 402.2 feet

A) Flight time = 3.97 sec; range = 424.4 feet
B) Flight time = 3.74 sec; range = 413.5 feet
C) Flight time = 2.82 sec; range = 393.5 feet
D) Flight time = 3.62 sec; range = 402.2 feet
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75
Find the unit tangent vector of the given curve.
r(t) = (10 - 2t)i + (2t - 3)j + (10 + t)k
r(t) = (10 - 2t)i + (2t - 3)j + (10 + t)k

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76
Find the unit tangent vector of the given curve.


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77
Calculate the arc length of the indicated portion of the curve r(t).

A) 1
B) 3
C) 0
D) 6

A) 1
B) 3
C) 0
D) 6
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78
Find the unit tangent vector of the given curve.


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79
Provide an appropriate response.


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80
Find the unit tangent vector of the given curve.


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