Deck 14: Analysis of Categorical Data
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Deck 14: Analysis of Categorical Data
1
All expected cell counts must equal ten in order that the chi-square approximation is valid.
False
2
The total degrees of freedom for an r x c (fixed-column) contingency table are rc + 1.
False
3
Suppose you wish to test the null hypothesis that three binomial parameters
,
, and
are equal versus the alternative hypothesis that at least two of the parameters differ. Independent random samples of 100 observations were selected from each of the populations. The data are shown in the table:
Write the null and alternative hypotheses for testing the equality of the three binomial proportions.
:
______________
Test statistic:
= ______________
What is the p-value?
______________
______________
.
There is ______________ sufficient evidence to indicate that the proportions depend upon the population from which they were drawn.






Test statistic:

What is the p-value?
______________
______________

There is ______________ sufficient evidence to indicate that the proportions depend upon the population from which they were drawn.
For all i,j; 5.0682; .0793; Do not reject; insufficient
4
If we want to perform a two-tail test for differences between two populations of nominal data with exactly two categories, we can employ either the z-test of
, or the chi-square test of homogeneity, since squaring the value of the z statistic yields the value of
statistics.


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5
To be valid, the chi-square test requires that all expected frequencies equal:
A) 30 or more
B) 30 or less
C) 30 precisely
D) both 30 or more and 30 or less
E) none of these
A) 30 or more
B) 30 or less
C) 30 precisely
D) both 30 or more and 30 or less
E) none of these
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6
When there are only 2 categories in a multinomial experiment, the experiment reduces to a binomial experiment.
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7
A study of the purchase decisions of three stock portfolio managers, A, B, C, was conducted to compare the numbers of stock purchases that resulted in profits over a time period less than or equal to 1 year. One hundred randomly selected purchases were examined for each of the managers.
Do the data provide evidence of differences among the rates of successful purchases for the three managers?
Compute
= ______________
The p-value is ______________.
Conclude that there ______________ enough information to conclude that the proportion of successful purchases will differ among the managers.

Compute

The p-value is ______________.
Conclude that there ______________ enough information to conclude that the proportion of successful purchases will differ among the managers.
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8
Numbers in a contingency table show the frequency of occurrence of all possible combinations of categories.
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9
The large-sample z tests for one and two binomial proportions are special cases of the chi-square statistic.
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10
If we want to conduct a two-tail test of a population proportion, we can employ:
A) z-test of a population proportion
B) the chi-square goodness-of-fit test since
C) the chi-square test of independence
D) z-test of a population proportion and the chi-square goodness-of-fit test since
E) z-test of a population proportion and the chi-square test of independence
A) z-test of a population proportion
B) the chi-square goodness-of-fit test since
C) the chi-square test of independence
D) z-test of a population proportion and the chi-square goodness-of-fit test since
E) z-test of a population proportion and the chi-square test of independence
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11
The chi-square technique is a statistical technique for testing the alleged independence of two qualitative variables, making inferences about the relative sizes of more than two population proportions, and conducting goodness-of-fit tests to assess the plausibility that sample data come from a population that conforms to a specified probability distribution.
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12
The following table shows the results of a study in which random samples of 200 members of each of five large unions were asked whether they are for, undecided, or against a certain piece of legislation.
Use the 0.025 level of significance to test whether the unions differ with respect to their views.
Compute
= ______________
Reject
when
> ______________.
Conclude:
The unions ______________ different views.

Compute

Reject


Conclude:
The unions ______________ different views.
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13
When either the row or column totals in a contingency table are fixed, the test of independence of classifications becomes a test of the homogeneity of cell probabilities for several multinomial experiments.
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14
Tests of homogeneity are used to compare several binomial populations.
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15
The data that result from two binomial experiment can be displayed as a two-way classification with 2 rows and 2 columns, so that the chi-square test of homogeneity can be used to compare the two binomial proportions
and
.


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16
The goodness-of-fit test is a two-way classification will cell probabilities specified in
.

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17
The chi-square technique has numerous applications, including:
A) testing the alleged independence of two qualitative variables
B) making inferences about the relative sizes of more than two population proportions
C) conducting a goodness-of-fit-test to determine whether data are consistent with data drawn from a particular probability distribution
D) all of these
E) none of these
A) testing the alleged independence of two qualitative variables
B) making inferences about the relative sizes of more than two population proportions
C) conducting a goodness-of-fit-test to determine whether data are consistent with data drawn from a particular probability distribution
D) all of these
E) none of these
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18
If there are more than two row categories in a contingency table with fixed c column totals, then the test of independence is equivalent to a test of the equality of c sets of multinomial proportions.
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19
If we want to conduct a one-tail test of a population proportion, we can employ:
A) z-test of a population proportion
B) the chi-square goodness-of-fit test since
C) the chi-square test of independence
D) none of these
E) all of these
A) z-test of a population proportion
B) the chi-square goodness-of-fit test since
C) the chi-square test of independence
D) none of these
E) all of these
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20
A contingency table classifies data with respect to two qualitative variables that are each divided into two or more categories.
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21
Chi-square tests of independence are always lower-tailed because a perfect fit between
and
makes
equal to zero.



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22
The chi-square test of a contingency table is used to determine if there is enough evidence to infer that two nominal variables are related, and to infer that differences exist among two or more populations of nominal variables.
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23
In a chi-square test of independence, the value of the test statistic was
15.652, and the critical value at
was 11.1433. Thus, we must reject the null hypothesis at
.



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24
A contingency table classifies data with respect to two qualitative variables that are each divided into two or more categories.
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25
Numbers in a contingency table show the frequency of occurrence of all possible combinations of categories.
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26
A chi-square test for independence is applied to a contingency table with 4 rows and 4 columns for two qualitative variables. The degrees of freedom for this test must be 9.
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27
A contingency table classifies data according to two or more categories associated with each of two qualitative variables that are statistically independent of one another.
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28
In a typical contingency-table test, we calculate each expected cell frequency as the product of row total times column total times sample size.
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29
The degrees of freedom associated with a chi-square test of independence where data are summarized in a contingency table with r rows and c columns equal the number of rows times the number of columns in the table; that is, rc.
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30
The chi-square test of independence is based upon three or more quantitative variables.
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31
A chi-square test for independence with 6 degrees of freedom results in a test statistic of 13.25. Using the chi-square table, the most accurate statement that can be made about the p-value for this test is that p-value is greater than 0.025 but smaller than 0.05.
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32
The degrees of freedom associated with a contingency-table test of independence equal the number of rows times the number of columns in the table.
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33
A chi-square test for independence with 10 degrees of freedom results in a test statistic of 17.894. Using the chi-square table, the most accurate statement that can be made about the p-value for this test is that 0.05 < p-value < 0.10.
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34
A chi-square test for independence is applied to a contingency table with 3 rows and 4 columns for two qualitative variables. The degrees of freedom for this test must be 12.
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35
To be valid, a chi-square test of independence requires that each expected frequency equal 30 or more.
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36
In a typical chi-square test of independence, we calculate each expected cell frequency (
) as the product of row total (
) times column total (
) times sample size (n).



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37
A chi-square test for independence is applied to a contingency table with 3 rows and 5 columns for two qualitative variables. The degrees of freedom for this test is 8.
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38
In a chi-square test of independence with 6 degrees of freedom and a level of significance of 0.05, the critical value from the chi-square table is 12.5916. The computed value of the test statistics is 11.264. This will lead us to reject the null hypothesis.
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39
Chi-square tests of independence are always lower-tailed because a perfect fit between
and
makes the test statistic
equal to zero.



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40
To be valid, a chi-square test of independence requires that the expected frequency for each cell in the contingency table equal 10 or more.
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41
Consider a cell in a contingency table. Given the cell's row total of 200, the cell's column total of 75, and a sample size of 1,000, the cell's expected frequency:
A) equals 10
B) equals 15
C) equals 20
D) equals 25
E) cannot possibly be determined without additional information
A) equals 10
B) equals 15
C) equals 20
D) equals 25
E) cannot possibly be determined without additional information
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42
In a chi-square test of independence, the value of the test statistic was
= 9.572, and the critical value at
was 11.1433. Thus,
A) we fail to reject the null hypothesis at
B) we reject the null hypothesis at
C) we don't have enough evidence to accept or reject the null hypothesis at
D) we should decrease the level of significance in order to reject the null hypothesis
E) none of these


A) we fail to reject the null hypothesis at
B) we reject the null hypothesis at
C) we don't have enough evidence to accept or reject the null hypothesis at
D) we should decrease the level of significance in order to reject the null hypothesis
E) none of these
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43
The number of degrees of freedom for a contingency table with 6 rows and 6 columns is:
A) 36
B) 25
C) 12
D) 6
E) 0
A) 36
B) 25
C) 12
D) 6
E) 0
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44
A market research study was conducted to compare three different brands of car oil. The results of the study are summarized below.
Use the accompanying MINITAB output and
= 0.005 to determine whether the brand of oil is independent of opinion.
Compute
= ______________
Reject
when
> ______________.
Conclude that the two variables are ______________.


Compute

Reject


Conclude that the two variables are ______________.
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45
The president of a state university collected data from students concerning building a new library, and classified the responses into different categories (strongly agree, agree, undecided, disagree, strongly disagree) and according to whether the student was male or female. To determine whether the data provide sufficient evidence to indicate that the responses depend upon gender, the most appropriate test is:
A) chi-square goodness-of-fit test
B) chi-square test of a contingency table (test of independence)
C) chi-square test of normality
D) none of these
E) all of these
A) chi-square goodness-of-fit test
B) chi-square test of a contingency table (test of independence)
C) chi-square test of normality
D) none of these
E) all of these
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46
A chi-square test of a contingency table with 4 rows and 5 columns shows that the value of the test statistic is 22.18. The most accurate statement that can be made about the p-value for this test is that:
A) p-value is greater than 0.05
B) p-value is smaller than 0.025
C) p-value is greater than 0.025 but smaller than 0.05
D) p-value is greater than 0.10
E) Not enough information is given to determine the p- value.
A) p-value is greater than 0.05
B) p-value is smaller than 0.025
C) p-value is greater than 0.025 but smaller than 0.05
D) p-value is greater than 0.10
E) Not enough information is given to determine the p- value.
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47
Which statistical technique is appropriate when we wish to analyze the relationship between two qualitative variables with two or more categories?
A) The chi-square test of a multinomial experiment.
B) The chi-square test of a contingency table.
C) The t-test of the difference between two means.
D) The z test of the difference between two proportions.
E) None of these.
A) The chi-square test of a multinomial experiment.
B) The chi-square test of a contingency table.
C) The t-test of the difference between two means.
D) The z test of the difference between two proportions.
E) None of these.
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48
A contingency table:
A) classifies data with respect to two qualitative variables
B) divides each variable into two or more categories
C) contains numbers that show the frequency of occurrence of all possible combinations of categories
D) all of these
E) none of these
A) classifies data with respect to two qualitative variables
B) divides each variable into two or more categories
C) contains numbers that show the frequency of occurrence of all possible combinations of categories
D) all of these
E) none of these
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49
Contingency tables are used in:
A) testing independence of two samples
B) testing dependence in matched pairs
C) testing independence of two populations
D) describing a single population
E) testing independence of two quantitative variables in a population
A) testing independence of two samples
B) testing dependence in matched pairs
C) testing independence of two populations
D) describing a single population
E) testing independence of two quantitative variables in a population
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50
A pollster was interested in determining whether three television dramas are equally preferable among men and women. The following data was recorded:
Compute
= ______________
Reject
when
> ______________.
Conclude that the preference of television drama is ______________ the viewer's gender.


Reject


Conclude that the preference of television drama is ______________ the viewer's gender.
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51
A chi-square test of independence is applied to a contingency table with 4 rows and 5 columns for two qualitative variables. The degrees of freedom for this test will be:
A) 20
B) 16
C) 15
D) 12
E) 9
A) 20
B) 16
C) 15
D) 12
E) 9
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52
A chi-square test of independence with 10 degrees of freedom results in a test statistic of 19.25. Using the chi-square table, the most accurate statement that can be made about the p-value for this test is that:
A) p-value < 0.025
B) 0.025 < p-value < 0.05
C) 0.05 < p-value < 0.10
D) 0.10 < p-value < 0.20
E) p-value > 0.2
A) p-value < 0.025
B) 0.025 < p-value < 0.05
C) 0.05 < p-value < 0.10
D) 0.10 < p-value < 0.20
E) p-value > 0.2
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53
The owner of Fit Forever Health Club is considering adding an indoor swimming pool to his facility. The manager decided to take a survey to determine whether member opinion about the addition of a pool was independent of the age of the member. Two hundred members were selected at random and asked to state their opinion. The following data was recorded:
What is
?
______________
What is the p-value associated with the test?
______________
Conclude that member's opinion concerning the addition of an indoor pool is ______________ the member's age.


______________
What is the p-value associated with the test?
______________
Conclude that member's opinion concerning the addition of an indoor pool is ______________ the member's age.
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54
Which of the following statements about a goodness-of-fit test is false?
A) It determines the likelihood that sample data have been generated from a population that conforms to a specified type of probability distribution.
B) It compares the entire shapes of two (discrete or continuous) probability distributions: one describing known population data and the other one describing hypothetical sample data.
C) The aim of the test might be limited to identifying only the family to which the underlying distribution belongs.
D) The aim of the test might be limited to identifying only the family to which the underlying distribution belongs or it might go further, seeking even to identify a particular member of that family.
E) None of these.
A) It determines the likelihood that sample data have been generated from a population that conforms to a specified type of probability distribution.
B) It compares the entire shapes of two (discrete or continuous) probability distributions: one describing known population data and the other one describing hypothetical sample data.
C) The aim of the test might be limited to identifying only the family to which the underlying distribution belongs.
D) The aim of the test might be limited to identifying only the family to which the underlying distribution belongs or it might go further, seeking even to identify a particular member of that family.
E) None of these.
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55
Which of the following statements about the chi-square distribution is false?
A) A different chi-square distribution exists for each possible number of degrees of freedom.
B) Because the chi-square random variable is a sum of squared deviations, negative values are impossible.
C) All values range between zero and one.
D) All chi-square distributions are skewed to the right.
E) All of these.
A) A different chi-square distribution exists for each possible number of degrees of freedom.
B) Because the chi-square random variable is a sum of squared deviations, negative values are impossible.
C) All values range between zero and one.
D) All chi-square distributions are skewed to the right.
E) All of these.
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56
The chi-square test of independence is based upon:
A) two qualitative variables
B) two quantitative variables
C) three or more qualitative variables
D) three or more quantitative variables
E) a quantitative and a qualitative variable
A) two qualitative variables
B) two quantitative variables
C) three or more qualitative variables
D) three or more quantitative variables
E) a quantitative and a qualitative variable
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57
Which of the following statements about a contingency table test is false?
A) The nature of the sampling distribution of chi-square depends on the number of degrees of freedom associated with the problem under investigation.
B) The degrees of freedom are found as (r - 2)(c - 2), where r represents number of rows and c represents number of columns.
C) The contingency table must have a minimum of 2 rows and 2 columns.
D) All of these.
E) None of these.
A) The nature of the sampling distribution of chi-square depends on the number of degrees of freedom associated with the problem under investigation.
B) The degrees of freedom are found as (r - 2)(c - 2), where r represents number of rows and c represents number of columns.
C) The contingency table must have a minimum of 2 rows and 2 columns.
D) All of these.
E) None of these.
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58
A contingency table test with 4 rows and 30 degrees of freedom implies that the table must have:
A) 7 columns
B) 9 columns
C) 11 columns
D) 13 columns
E) 15 columns
A) 7 columns
B) 9 columns
C) 11 columns
D) 13 columns
E) 15 columns
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59
The chi-square test of a contingency table is based upon:
A) two qualitative variables
B) two quantitative variables
C) three or more qualitative variables
D) three or more quantitative variables
E) all of these
A) two qualitative variables
B) two quantitative variables
C) three or more qualitative variables
D) three or more quantitative variables
E) all of these
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60
A contingency table test with 4 rows and 15 degrees of freedom implies:
A) 5 columns
B) 6 columns
C) 9 columns
D) 11 columns
E) 60 columns
A) 5 columns
B) 6 columns
C) 9 columns
D) 11 columns
E) 60 columns
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61
A sport preference poll showed the following data for men and women:
Use the 5% level of significance and test to determine whether sport preferences depend on gender.
= ______________
Critical Value = ______________
Conclusion: ______________
Sport preferences ______________ on gender.


Critical Value = ______________
Conclusion: ______________
Sport preferences ______________ on gender.
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62
Is there a difference in the spending patterns of high school seniors depending on their gender? A study to investigate this question focused on 196 employed high school seniors. Students were asked to classify the amount of their earnings that they spent on their car during a given month:
A portion of the Minitab printout is given here.
Use the printout to analyze the relationship between spending patterns and gender.
What is
?
______________
What is the p-value?
______________
Conclude that there ______________ sufficient evidence to indicate a difference in spending patterns between males and females.


What is

______________
What is the p-value?
______________
Conclude that there ______________ sufficient evidence to indicate a difference in spending patterns between males and females.
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63
A chi-square goodness-of-fit test with 3 degrees of freedom results in a test statistic of 6.789. Using the chi-square table, the most accurate statement that can be made about the p-value for this test is that 0.05 < p-value < 0.10.
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64
The number of Americans who visit fast-food restaurants regularly has grown steadily over the last decade. For this reason, marketing experts are interested in the demographics of fast-food customers. Is a customer's preference for a fast- food chain affected by the age of the customer? If so, advertising might need to target a particular age group. Suppose a random sample of 400 fast-food customers aged 16 and older was selected, and their favorite fast-food restaurants along with their age groups were recorded, as shown in the table:
Use an appropriate method to determine whether or not a customer's fast-food preference is dependent on age.
Compute
:
______________
What is the p-value?
______________
Conclude that there ______________ a dependence between age group and favorite fast food restaurant.
Write a short paragraph presenting your statistical conclusions and their practical implications for marketing experts.
________________________________________________________

Compute

______________
What is the p-value?
______________
Conclude that there ______________ a dependence between age group and favorite fast food restaurant.
Write a short paragraph presenting your statistical conclusions and their practical implications for marketing experts.
________________________________________________________
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65
A marketing research professor at Ferris State University conducted a survey to determine whether mode of transportation to the university and the person's position at the university were independent. The following data was recorded:
Perform the appropriate test of hypothesis using
= 0.10.
Compute
= ______________
Reject
when
> ______________.
Conclude that the mode of transportation to the university and person's position at the university are ______________.


Compute

Reject


Conclude that the mode of transportation to the university and person's position at the university are ______________.
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66
All chi-square distributions are skewed to the right and their means equal the associated degrees of freedom.
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67
Because the chi-square random variable is a sum of squares, it cannot take on negative values.
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68
A study of educational levels of 500 voters and their political party affiliations in a southern state in the USA showed the following results:
Use the 1% level of significance and test to see if party affiliation is independent of the educational level of the voters.
= ______________
Critical Value = ______________
Conclusion: ______________
Political party affiliation ______________ on the educational level of the voters.


Critical Value = ______________
Conclusion: ______________
Political party affiliation ______________ on the educational level of the voters.
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69
Whenever the expected frequency of a cell is less than 5, one remedy for this condition is to increase the significance level.
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70
An experiment was conducted to investigate the effect of general hospital experience on the attitudes of physicians toward lower-class people. A random sample of 50 physicians who had just completed 4 weeks of service in a general hospital were categorized according to their concern for lower-class people before and after their general hospital experience. The data are shown in the table.
Do the data provide sufficient evidence to indicate a change in "concern" after the general hospital experience?
Compute
= ______________
Give a range for the p-value. ______________
Conclude that there is ______________ enough evidence to indicate a change in concern due to the general hospital experience.

Compute

Give a range for the p-value. ______________
Conclude that there is ______________ enough evidence to indicate a change in concern due to the general hospital experience.
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71
A large carpet store wishes to determine if the brand of carpet purchased is related to the purchaser's family income. As a sampling frame, they mailed a survey to people who have a store credit card. Five hundred customers returned the survey and the results follow:
At the 5% level of significance, can you conclude that the brand of carpet purchased is related to the purchaser's family income?
Test statistic = ______________
Critical Value = ______________
Conclusion: ______________
We can conclude that the brand of carpet purchased ______________ related to the purchaser's family income.

Test statistic = ______________
Critical Value = ______________
Conclusion: ______________
We can conclude that the brand of carpet purchased ______________ related to the purchaser's family income.
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72
A major insurance firm interviewed a random sample of 1200 college students to find out the type of life insurance preferred, if any. The results follow:
Is there evidence that life insurance preference of male students is different than that of female students? Test using the 5% level of significance.
Test statistic = ______________
Critical Value = ______________
Conclusion: ______________
Life insurance preference ______________ on gender.

Test statistic = ______________
Critical Value = ______________
Conclusion: ______________
Life insurance preference ______________ on gender.
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73
A survey of 500 respondents produced these cell counts in a 2
3 contingency table:
If you wish to test the null hypothesis of "independence" - that the probability that a response falls in any one row is independent of the column it falls in - and you plan to use a chi-square test, how many degrees of freedom will be associated with the
statistic?
df = ______________
Compute
: = ______________
Reject
when
> ______________.
Conclude that there ______________ reason to expect a dependence between rows and columns.
Find the approximate p-value for the test.
The p-value ______________ .10



df = ______________
Compute

Reject


Conclude that there ______________ reason to expect a dependence between rows and columns.
Find the approximate p-value for the test.
The p-value ______________ .10
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74
The personnel manager of a consumer products company asked a random sample of employees how they felt about the work they were doing. The following table gives a breakdown of their responses by age.
Is there sufficient evidence to conclude that the level of job satisfaction is related to age? Use
= 0.10.
What is
?
______________
Critical Value = ______________
Conclusion: ______________
Job satisfaction ______________ related to age.


What is

______________
Critical Value = ______________
Conclusion: ______________
Job satisfaction ______________ related to age.
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75
The degrees of freedom associated with a goodness-of-fit test equal the number of rows times the number of columns in the table.
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76
The personnel manager of a consumer product company asked a random sample of employees how they felt about the work they were doing. The following table gives a breakdown of their responses by gender.
Do the data provide sufficient evidence to conclude that the level of job satisfaction is related to gender? Conduct the test at the 0.10 level of significance.
Test statistic = ______________
Critical Value(s) = ______________
Conclusion: ______________
The data provide ______________ evidence to conclude that the level of job satisfaction is related to gender.

Test statistic = ______________
Critical Value(s) = ______________
Conclusion: ______________
The data provide ______________ evidence to conclude that the level of job satisfaction is related to gender.
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77
A right-tailed area in the chi-square distribution equals 0.05. For 6 degrees of freedom the table value equals 12.5916.
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78
A goodness-of-fit test determines the likelihood that sample data have been generated from a population that conforms to a specified type of probability distribution.
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79
A chi-square goodness-of-fit test is always conducted as a two-tail test.
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80
A study was conducted to determine whether opinion concerning the addition of seat belts in school buses is independent of the population density in which a person resides. The following data was recorded:
Use the following output generated using Minitab to answer the questions below.
What is
?
______________
What is the p-value associated with the test?
______________
Conclude that opinion concerning the addition of seat belts to school buses is ______________ the population density where the person resides.



______________
What is the p-value associated with the test?
______________
Conclude that opinion concerning the addition of seat belts to school buses is ______________ the population density where the person resides.
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