Deck 9: Large-Sample Tests of Hypotheses

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Question
In constructing a confidence interval estimate for the difference between two population proportions, we:

A) pool the population proportions when the populations are normally distributed
B) pool the population proportions when the population means are equal
C) pool the population proportions when they are equal
D) never pool the population proportions to construct confidence interval for
E) always pool the population proportions to construct confidence interval for
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Question
The test statistic that is used in testing The test statistic that is used in testing   vs.   is   where   .<div style=padding-top: 35px> vs. The test statistic that is used in testing   vs.   is   where   .<div style=padding-top: 35px> is The test statistic that is used in testing   vs.   is   where   .<div style=padding-top: 35px> where The test statistic that is used in testing   vs.   is   where   .<div style=padding-top: 35px> .
Question
When the necessary conditions are met, a lower tailed test is being conducted for the difference between two population proportions. If the value of the test statistic is -2.50, then the p-value is 0.0062.
Question
A sample of size 150 from population 1 has 40 successes. A sample of size 250 from population 2 has 30 successes. The value of the test statistic for testing the null hypothesis that the proportion of successes in population one exceeds the proportion of successes in population two by 0.05 is:

A) 1.645
B) 2.327
C) 1.960
D) 1.977
E) 1.772
Question
For testing the difference between two population proportions, the pooled proportion estimate should be used to compute the value of the test statistic when the:

A) populations are normally distributed
B) sample sizes are small
C) samples are independently drawn from the populations
D) null hypothesis states that the two population proportions are equal
E) populations are normally distributed and sample sizes are small
Question
If we reject the null hypothesis If we reject the null hypothesis   , we conclude that there is not enough statistical evidence to infer that the population proportions are equal.<div style=padding-top: 35px> , we conclude that there is not enough statistical evidence to infer that the population proportions are equal.
Question
In testing the null hypothesis <strong>In testing the null hypothesis   , if   is false, the test could lead to:</strong> A) a Type I error B) a Type II error C) a Type O error D) either a Type I or a Type II error E) neither a Type I nor a Type II error <div style=padding-top: 35px> , if <strong>In testing the null hypothesis   , if   is false, the test could lead to:</strong> A) a Type I error B) a Type II error C) a Type O error D) either a Type I or a Type II error E) neither a Type I nor a Type II error <div style=padding-top: 35px> is false, the test could lead to:

A) a Type I error
B) a Type II error
C) a Type O error
D) either a Type I or a Type II error
E) neither a Type I nor a Type II error
Question
When the necessary conditions are met, a two-tailed test is being conducted to test the difference between two population proportions. The two sample proportions are When the necessary conditions are met, a two-tailed test is being conducted to test the difference between two population proportions. The two sample proportions are   and   , respectively, and the standard error of the sampling distribution of   is 0.04. Then, the calculated value of the test statistic will be 1.50.<div style=padding-top: 35px> and When the necessary conditions are met, a two-tailed test is being conducted to test the difference between two population proportions. The two sample proportions are   and   , respectively, and the standard error of the sampling distribution of   is 0.04. Then, the calculated value of the test statistic will be 1.50.<div style=padding-top: 35px> , respectively, and the standard error of the sampling distribution of When the necessary conditions are met, a two-tailed test is being conducted to test the difference between two population proportions. The two sample proportions are   and   , respectively, and the standard error of the sampling distribution of   is 0.04. Then, the calculated value of the test statistic will be 1.50.<div style=padding-top: 35px> is 0.04. Then, the calculated value of the test statistic will be 1.50.
Question
In testing In testing   vs.   the test statistic value is found to be z = 1.28. The p-value of the test is approximately .1003.<div style=padding-top: 35px> vs. In testing   vs.   the test statistic value is found to be z = 1.28. The p-value of the test is approximately .1003.<div style=padding-top: 35px> the test statistic value is found to be z = 1.28. The p-value of the test is approximately .1003.
Question
A sample of size 100 selected from one population has 60 successes, and a sample of size 150 selected from a second population has 95 successes. The test statistic for testing the equality of the population proportions equal to:

A) -0.5319
B) 0.7293
C) -0.419
D) 0.2702
E) -0.3518
Question
When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. The two sample proportions are <strong>When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. The two sample proportions are   and   , and the standard error of the sampling distribution of   is 0.04. The calculated value of the test statistic will be:</strong> A) z = 0.25 B) z = 1.25 C) t = 0.25 D) t = 0.80 E) t = 1.25 <div style=padding-top: 35px> and <strong>When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. The two sample proportions are   and   , and the standard error of the sampling distribution of   is 0.04. The calculated value of the test statistic will be:</strong> A) z = 0.25 B) z = 1.25 C) t = 0.25 D) t = 0.80 E) t = 1.25 <div style=padding-top: 35px> , and the standard error of the sampling distribution of <strong>When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. The two sample proportions are   and   , and the standard error of the sampling distribution of   is 0.04. The calculated value of the test statistic will be:</strong> A) z = 0.25 B) z = 1.25 C) t = 0.25 D) t = 0.80 E) t = 1.25 <div style=padding-top: 35px> is 0.04. The calculated value of the test statistic will be:

A) z = 0.25
B) z = 1.25
C) t = 0.25
D) t = 0.80
E) t = 1.25
Question
When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. If the value of the test statistic is 2.05, then the p-value is:

A) 0.4798
B) 0.0404
C) 0.2399
D) 0.0202
E) 0.1982
Question
When the necessary conditions are met, an upper tailed test is being conducted for the difference between two population proportions. If the value of the test statistic is 2.90, then the p-value is 0.0038.
Question
When the necessary conditions are met, a two-tailed test is being conducted to test the difference between two population proportions. The two sample proportions are When the necessary conditions are met, a two-tailed test is being conducted to test the difference between two population proportions. The two sample proportions are   and   , and the standard error of the sampling distribution of   is 0.0085. The calculated value of the test statistic will be z = 3.41.<div style=padding-top: 35px> and When the necessary conditions are met, a two-tailed test is being conducted to test the difference between two population proportions. The two sample proportions are   and   , and the standard error of the sampling distribution of   is 0.0085. The calculated value of the test statistic will be z = 3.41.<div style=padding-top: 35px> , and the standard error of the sampling distribution of When the necessary conditions are met, a two-tailed test is being conducted to test the difference between two population proportions. The two sample proportions are   and   , and the standard error of the sampling distribution of   is 0.0085. The calculated value of the test statistic will be z = 3.41.<div style=padding-top: 35px> is 0.0085. The calculated value of the test statistic will be z = 3.41.
Question
When the necessary conditions are met, a lower tailed test is being conducted for the difference between two population proportions. If the value of the test statistic is -2.43, then the null hypothesis cannot be rejected at When the necessary conditions are met, a lower tailed test is being conducted for the difference between two population proportions. If the value of the test statistic is -2.43, then the null hypothesis cannot be rejected at   = 0.025.<div style=padding-top: 35px> = 0.025.
Question
Which of the following is a required condition for using the normal approximation to the binomial in testing the difference between two population proportions?

A) n1p1 ≥ 30 and n2p2 ≥ 30
B) n1p1 ≥ 5 and n2p2 ≥ 5
C) n1p1 ≥ 5 , n1(1-p1) ≥ 5 , n2p2 ≥ 5 and n2(1-p2) ≥ 5
D) n11 ≥ 5 , n1(1-p̂1) ≥ 5 , n22 ≥ 5 and n2(1-p̂2) ≥ 5
E) n1p1 ≥ 10 and n2p2 ≥ 10
Question
When the necessary conditions are met, a two-tailed test is being conducted for the difference between two population proportions. If the value of the test statistic is 1.96, then the null hypothesis is rejected at When the necessary conditions are met, a two-tailed test is being conducted for the difference between two population proportions. If the value of the test statistic is 1.96, then the null hypothesis is rejected at   = 0.10.<div style=padding-top: 35px> = 0.10.
Question
In testing In testing   vs.   using a significance level equal to .05, the critical value that will be used to conduct the test is z = 1.645.<div style=padding-top: 35px> vs. In testing   vs.   using a significance level equal to .05, the critical value that will be used to conduct the test is z = 1.645.<div style=padding-top: 35px> using a significance level equal to .05, the critical value that will be used to conduct the test is z = 1.645.
Question
When the necessary conditions are met, a two-tailed test is being conducted for the difference between two population proportions. If the value of the test statistic is -1.35, then the p-value is 0.0885.
Question
In testing In testing   vs/   the following summary statistics are found:       and   Based on these results, the null hypothesis should be rejected at the significance level   .<div style=padding-top: 35px> vs/ In testing   vs/   the following summary statistics are found:       and   Based on these results, the null hypothesis should be rejected at the significance level   .<div style=padding-top: 35px> the following summary statistics are found: In testing   vs/   the following summary statistics are found:       and   Based on these results, the null hypothesis should be rejected at the significance level   .<div style=padding-top: 35px> In testing   vs/   the following summary statistics are found:       and   Based on these results, the null hypothesis should be rejected at the significance level   .<div style=padding-top: 35px> In testing   vs/   the following summary statistics are found:       and   Based on these results, the null hypothesis should be rejected at the significance level   .<div style=padding-top: 35px> and In testing   vs/   the following summary statistics are found:       and   Based on these results, the null hypothesis should be rejected at the significance level   .<div style=padding-top: 35px> Based on these results, the null hypothesis should be rejected at the significance level In testing   vs/   the following summary statistics are found:       and   Based on these results, the null hypothesis should be rejected at the significance level   .<div style=padding-top: 35px> .
Question
In testing In testing   vs.   a random sample of size 100 produced a sample proportion   Given these results, the test statistic value is z = -.655.<div style=padding-top: 35px> vs. In testing   vs.   a random sample of size 100 produced a sample proportion   Given these results, the test statistic value is z = -.655.<div style=padding-top: 35px> a random sample of size 100 produced a sample proportion In testing   vs.   a random sample of size 100 produced a sample proportion   Given these results, the test statistic value is z = -.655.<div style=padding-top: 35px> Given these results, the test statistic value is z = -.655.
Question
In testing In testing   vs.   at   , any p-value greater than .025 will lead to a rejection of the null hypothesis.<div style=padding-top: 35px> vs. In testing   vs.   at   , any p-value greater than .025 will lead to a rejection of the null hypothesis.<div style=padding-top: 35px> at In testing   vs.   at   , any p-value greater than .025 will lead to a rejection of the null hypothesis.<div style=padding-top: 35px> , any p-value greater than .025 will lead to a rejection of the null hypothesis.
Question
If the null hypothesis If the null hypothesis   is rejected at the 0.05 level of significance, it must be rejected at the 0.01 level.<div style=padding-top: 35px> is rejected at the 0.05 level of significance, it must be rejected at the 0.01 level.
Question
A one-tailed hypothesis test of the population proportion is used when the alternative hypothesis takes the form A one-tailed hypothesis test of the population proportion is used when the alternative hypothesis takes the form   .<div style=padding-top: 35px> .
Question
In testing In testing   vs.   a random sample of size 200 produced a sample proportion   Given these results, the null hypothesis should not be rejected at   = .05.<div style=padding-top: 35px> vs. In testing   vs.   a random sample of size 200 produced a sample proportion   Given these results, the null hypothesis should not be rejected at   = .05.<div style=padding-top: 35px> a random sample of size 200 produced a sample proportion In testing   vs.   a random sample of size 200 produced a sample proportion   Given these results, the null hypothesis should not be rejected at   = .05.<div style=padding-top: 35px> Given these results, the null hypothesis should not be rejected at In testing   vs.   a random sample of size 200 produced a sample proportion   Given these results, the null hypothesis should not be rejected at   = .05.<div style=padding-top: 35px> = .05.
Question
A two-tailed hypothesis test of the population proportion takes the form A two-tailed hypothesis test of the population proportion takes the form   vs.   .<div style=padding-top: 35px> vs. A two-tailed hypothesis test of the population proportion takes the form   vs.   .<div style=padding-top: 35px> .
Question
Independent random samples of n1 = 150 and n2 = 150 sales phone calls for an insurance policy were randomly selected from binomial populations 1 and 2, respectively. Sample 1 had 80 successful sales, and sample 2 had 88 successful sales. Suppose you have no preconceived theory concerning which parameter, p1 or p2, is the larger and you wish to detect only a difference between the two parameters if one exists.
Calculate the standard error of the difference in the two sample proportions, Independent random samples of n<sub>1</sub> = 150 and n<sub>2</sub> = 150 sales phone calls for an insurance policy were randomly selected from binomial populations 1 and 2, respectively. Sample 1 had 80 successful sales, and sample 2 had 88 successful sales. Suppose you have no preconceived theory concerning which parameter, p<sub>1</sub> or p<sub>2</sub>, is the larger and you wish to detect only a difference between the two parameters if one exists. Calculate the standard error of the difference in the two sample proportions,   . Make sure to use the pooled estimate for the common value of p. ______________ Calculate the test statistic that you would use for the test above. Based on your knowledge of the standard normal distribution, is this a likely or unlikely observation, assuming that H<sub>0</sub> is true and the two population proportions are the same? Test statistic = ______________ Find the p-value for the test. Test for a significant difference in the population means at the 1% significance level. p-value = ______________ Find the rejection region when   = 0.01. Do the data provide sufficient evidence to indicate a difference in the population proportions? Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________<div style=padding-top: 35px> . Make sure to use the pooled estimate for the common value of p.
______________
Calculate the test statistic that you would use for the test above. Based on your knowledge of the standard normal distribution, is this a likely or unlikely observation, assuming that H0 is true and the two population proportions are the same?
Test statistic = ______________
Find the p-value for the test. Test for a significant difference in the population means at the 1% significance level.
p-value = ______________
Find the rejection region when Independent random samples of n<sub>1</sub> = 150 and n<sub>2</sub> = 150 sales phone calls for an insurance policy were randomly selected from binomial populations 1 and 2, respectively. Sample 1 had 80 successful sales, and sample 2 had 88 successful sales. Suppose you have no preconceived theory concerning which parameter, p<sub>1</sub> or p<sub>2</sub>, is the larger and you wish to detect only a difference between the two parameters if one exists. Calculate the standard error of the difference in the two sample proportions,   . Make sure to use the pooled estimate for the common value of p. ______________ Calculate the test statistic that you would use for the test above. Based on your knowledge of the standard normal distribution, is this a likely or unlikely observation, assuming that H<sub>0</sub> is true and the two population proportions are the same? Test statistic = ______________ Find the p-value for the test. Test for a significant difference in the population means at the 1% significance level. p-value = ______________ Find the rejection region when   = 0.01. Do the data provide sufficient evidence to indicate a difference in the population proportions? Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________<div style=padding-top: 35px> = 0.01. Do the data provide sufficient evidence to indicate a difference in the population proportions?
Critical Value(s) = ______________
Conclusion: ______________
Interpretation: __________________________________________
Question
The Environmental Protection Agency wanted to compare the proportion of plants in violation of air quality standards for two different industries: steel and utility. Two independent samples of plants were selected and monitored. The following data was recorded: The Environmental Protection Agency wanted to compare the proportion of plants in violation of air quality standards for two different industries: steel and utility. Two independent samples of plants were selected and monitored. The following data was recorded:   Test at   = 0.01 Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________<div style=padding-top: 35px> Test at The Environmental Protection Agency wanted to compare the proportion of plants in violation of air quality standards for two different industries: steel and utility. Two independent samples of plants were selected and monitored. The following data was recorded:   Test at   = 0.01 Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________<div style=padding-top: 35px> = 0.01
Test statistic = ______________
Critical Value(s) = ______________
Conclusion: ______________
Interpretation: __________________________________________
Question
A cable company in Michigan is thinking of offering its service in one of two counties; Mecosta and Newaygo. Allegedly, the proportion of households in either county ready to hook up to the cable is the same, but the company wants to test the claim. Accordingly, it takes a simple random sample in each county. In Mecosta county, 175 of 2900 households say they will join. In Newaygo county, 665 of 800 households say so.
Calculate the pooled estimate of the common proportion p.
______________
Calculate the standard error of A cable company in Michigan is thinking of offering its service in one of two counties; Mecosta and Newaygo. Allegedly, the proportion of households in either county ready to hook up to the cable is the same, but the company wants to test the claim. Accordingly, it takes a simple random sample in each county. In Mecosta county, 175 of 2900 households say they will join. In Newaygo county, 665 of 800 households say so. Calculate the pooled estimate of the common proportion p. ______________ Calculate the standard error of   . ______________ Calculate the value of the test statistic. ______________ Calculate the p-value and write your conclusion given that   = 0.05. ______________ Conclusion: ______________ Interpretation: __________________________________________ Construct 95% confidence interval for the difference in proportions of households in Mecosta and Newaygo counties who are ready to hook up to the cable. ______________ Explain how to use the 95% confidence interval to test the appropriate hypotheses at   = 0.05. __________________________________________<div style=padding-top: 35px> .
______________
Calculate the value of the test statistic.
______________
Calculate the p-value and write your conclusion given that A cable company in Michigan is thinking of offering its service in one of two counties; Mecosta and Newaygo. Allegedly, the proportion of households in either county ready to hook up to the cable is the same, but the company wants to test the claim. Accordingly, it takes a simple random sample in each county. In Mecosta county, 175 of 2900 households say they will join. In Newaygo county, 665 of 800 households say so. Calculate the pooled estimate of the common proportion p. ______________ Calculate the standard error of   . ______________ Calculate the value of the test statistic. ______________ Calculate the p-value and write your conclusion given that   = 0.05. ______________ Conclusion: ______________ Interpretation: __________________________________________ Construct 95% confidence interval for the difference in proportions of households in Mecosta and Newaygo counties who are ready to hook up to the cable. ______________ Explain how to use the 95% confidence interval to test the appropriate hypotheses at   = 0.05. __________________________________________<div style=padding-top: 35px> = 0.05.
______________
Conclusion: ______________
Interpretation: __________________________________________
Construct 95% confidence interval for the difference in proportions of households in Mecosta and Newaygo counties who are ready to hook up to the cable.
______________
Explain how to use the 95% confidence interval to test the appropriate hypotheses at A cable company in Michigan is thinking of offering its service in one of two counties; Mecosta and Newaygo. Allegedly, the proportion of households in either county ready to hook up to the cable is the same, but the company wants to test the claim. Accordingly, it takes a simple random sample in each county. In Mecosta county, 175 of 2900 households say they will join. In Newaygo county, 665 of 800 households say so. Calculate the pooled estimate of the common proportion p. ______________ Calculate the standard error of   . ______________ Calculate the value of the test statistic. ______________ Calculate the p-value and write your conclusion given that   = 0.05. ______________ Conclusion: ______________ Interpretation: __________________________________________ Construct 95% confidence interval for the difference in proportions of households in Mecosta and Newaygo counties who are ready to hook up to the cable. ______________ Explain how to use the 95% confidence interval to test the appropriate hypotheses at   = 0.05. __________________________________________<div style=padding-top: 35px> = 0.05.
__________________________________________
Question
A manufacturing plant has two assembly lines for producing plastic bottles. The plant manager was concerned about whether the proportion of defective bottles differed between the two lines. Two independent random samples were selected and the following summary data computed: A manufacturing plant has two assembly lines for producing plastic bottles. The plant manager was concerned about whether the proportion of defective bottles differed between the two lines. Two independent random samples were selected and the following summary data computed:   Perform the appropriate test of hypothesis using   = 0.05. Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________<div style=padding-top: 35px> Perform the appropriate test of hypothesis using A manufacturing plant has two assembly lines for producing plastic bottles. The plant manager was concerned about whether the proportion of defective bottles differed between the two lines. Two independent random samples were selected and the following summary data computed:   Perform the appropriate test of hypothesis using   = 0.05. Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________<div style=padding-top: 35px> = 0.05.
Test statistic = ______________
Critical Value(s) = ______________
Conclusion: ______________
Interpretation: __________________________________________
Question
When testing When testing   vs.   , an increase in the sample size will result in a decrease in the probability of committing a Type I error.<div style=padding-top: 35px> vs. When testing   vs.   , an increase in the sample size will result in a decrease in the probability of committing a Type I error.<div style=padding-top: 35px> , an increase in the sample size will result in a decrease in the probability of committing a Type I error.
Question
An experiment was conducted to test the effect of a new drug on a viral infection. The infection was induced in 100 mice, and the mice were randomly split into two groups of 50. The first group, the control group, received no treatment for the infection. The second group received the drug. The proportions of survivors, An experiment was conducted to test the effect of a new drug on a viral infection. The infection was induced in 100 mice, and the mice were randomly split into two groups of 50. The first group, the control group, received no treatment for the infection. The second group received the drug. The proportions of survivors,   and   , in the two groups after a 30-day period, were found to be 0.40 and 0.64, respectively. Is there sufficient evidence to indicate that the drug is effective in treating the viral infection? Use   = 0.05. Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________ Use a 95% confidence interval to estimate the actual difference in the cure rates for the treated versus the control groups. ______________<div style=padding-top: 35px> and An experiment was conducted to test the effect of a new drug on a viral infection. The infection was induced in 100 mice, and the mice were randomly split into two groups of 50. The first group, the control group, received no treatment for the infection. The second group received the drug. The proportions of survivors,   and   , in the two groups after a 30-day period, were found to be 0.40 and 0.64, respectively. Is there sufficient evidence to indicate that the drug is effective in treating the viral infection? Use   = 0.05. Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________ Use a 95% confidence interval to estimate the actual difference in the cure rates for the treated versus the control groups. ______________<div style=padding-top: 35px> , in the two groups after a 30-day period, were found to be 0.40 and 0.64, respectively. Is there sufficient evidence to indicate that the drug is effective in treating the viral infection? Use An experiment was conducted to test the effect of a new drug on a viral infection. The infection was induced in 100 mice, and the mice were randomly split into two groups of 50. The first group, the control group, received no treatment for the infection. The second group received the drug. The proportions of survivors,   and   , in the two groups after a 30-day period, were found to be 0.40 and 0.64, respectively. Is there sufficient evidence to indicate that the drug is effective in treating the viral infection? Use   = 0.05. Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________ Use a 95% confidence interval to estimate the actual difference in the cure rates for the treated versus the control groups. ______________<div style=padding-top: 35px> = 0.05.
Test statistic = ______________
Critical Value(s) = ______________
Conclusion: ______________
Interpretation: __________________________________________
Use a 95% confidence interval to estimate the actual difference in the cure rates for the treated versus the control groups.
______________
Question
In testing the hypotheses H0: p1 - p2 = 0 vs. Ha: p1 - p2 > 0, use the following statistics, where x1 and x2 represent the number of defective components found in medical instruments in the two samples.
n1 = 200, x1 = 80
n2 = 400, x2 = 140
What conclusion can we draw at the 5% significance level?
Test statistic = ______________
Critical Value(s) = ______________
Conclusion: ______________
What is the p-value of the test?
p-value = ______________
Explain how to use the p-value to test the hypotheses.
____________________________
Estimate with 95% confidence the difference between the two population proportions.
______________
Question
Suppose in testing a hypothesis about a proportion, the p-value is computed to be 0.027. The null hypothesis should be rejected if the chosen level of significance is 0.01.
Question
In testing the hypotheses
H0: p1 - p2 = 0.10 vs.
Ha: In testing the hypotheses H<sub>0</sub>: p<sub>1</sub> - p<sub>2</sub> = 0.10 vs. H<sub>a</sub>:   . Use the following statistics, where x<sub>1</sub> and x<sub>2</sub> represent the number of Dial Soap sales in the two samples, respectively. n<sub>1</sub> = 150, x<sub>1</sub> = 72 n<sub>2</sub> = 175, x<sub>2</sub> = 70 What conclusion can we draw at the 5% significance level? Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ What is the p-value of the test? p-value = ______________ Explain how to use the p-value to test the hypotheses. ____________________________ Estimate with 95% confidence the difference between the two population proportions. ______________ Interpret and explain how to use the confidence interval to test the hypotheses. __________________________________________<div style=padding-top: 35px> .
Use the following statistics, where x1 and x2 represent the number of Dial Soap sales in the two samples, respectively.
n1 = 150, x1 = 72
n2 = 175, x2 = 70
What conclusion can we draw at the 5% significance level?
Test statistic = ______________
Critical Value(s) = ______________
Conclusion: ______________
What is the p-value of the test?
p-value = ______________
Explain how to use the p-value to test the hypotheses.
____________________________
Estimate with 95% confidence the difference between the two population proportions.
______________
Interpret and explain how to use the confidence interval to test the hypotheses.
__________________________________________
Question
In testing In testing   vs.   the level of significance must be twice as large as when testing   vs.   .<div style=padding-top: 35px> vs. In testing   vs.   the level of significance must be twice as large as when testing   vs.   .<div style=padding-top: 35px> the level of significance must be twice as large as when testing In testing   vs.   the level of significance must be twice as large as when testing   vs.   .<div style=padding-top: 35px> vs. In testing   vs.   the level of significance must be twice as large as when testing   vs.   .<div style=padding-top: 35px> .
Question
When the hypothesized proportion When the hypothesized proportion   is close to 0.50, the spread in the sampling distribution of the sample proportion   is greater than when   is close to 0.0 or 1.0.<div style=padding-top: 35px> is close to 0.50, the spread in the sampling distribution of the sample proportion When the hypothesized proportion   is close to 0.50, the spread in the sampling distribution of the sample proportion   is greater than when   is close to 0.0 or 1.0.<div style=padding-top: 35px> is greater than when When the hypothesized proportion   is close to 0.50, the spread in the sampling distribution of the sample proportion   is greater than when   is close to 0.0 or 1.0.<div style=padding-top: 35px> is close to 0.0 or 1.0.
Question
In testing In testing   vs.   the test statistic value is found to be equal to 1.20. The p-value for this test would be approximately .1151.<div style=padding-top: 35px> vs. In testing   vs.   the test statistic value is found to be equal to 1.20. The p-value for this test would be approximately .1151.<div style=padding-top: 35px> the test statistic value is found to be equal to 1.20. The p-value for this test would be approximately .1151.
Question
The campaign manager of John Kerry believes that more than 52% of the registered voters will vote in favor of Kerry. If you wish to test this claim, the appropriate null and alternative hypotheses are The campaign manager of John Kerry believes that more than 52% of the registered voters will vote in favor of Kerry. If you wish to test this claim, the appropriate null and alternative hypotheses are   vs.   .<div style=padding-top: 35px> vs. The campaign manager of John Kerry believes that more than 52% of the registered voters will vote in favor of Kerry. If you wish to test this claim, the appropriate null and alternative hypotheses are   vs.   .<div style=padding-top: 35px> .
Question
A group in favor of freezing production of nuclear weapons believes that the proportion of individuals in favor of a nuclear freeze is greater for those who have seen the movie "The Day After" (population 1) than those who have not (population 2). In an attempt to verify this belief, random samples of size 500 are obtained from the populations of interest. Among those who had seen "The Day After", 228 were in favor of a freeze. For those who had not seen the movie, 196 favored a freeze. Test using A group in favor of freezing production of nuclear weapons believes that the proportion of individuals in favor of a nuclear freeze is greater for those who have seen the movie The Day After (population 1) than those who have not (population 2). In an attempt to verify this belief, random samples of size 500 are obtained from the populations of interest. Among those who had seen The Day After, 228 were in favor of a freeze. For those who had not seen the movie, 196 favored a freeze. Test using   = 0.05. Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________<div style=padding-top: 35px> = 0.05.
Test statistic = ______________
Critical Value(s) = ______________
Conclusion: ______________
Interpretation: __________________________________________
Question
The lower limit of a confidence interval at the 95% level of confidence for the population proportion if a sample of size 200 had 40 successes is:

A) 0.2554
B) 0.1446
C) 0.2465
D) 0.1535
E) 0.3390
Question
The upper limit of the 85% confidence interval for the population proportion p, given that n = 60 and The upper limit of the 85% confidence interval for the population proportion p, given that n = 60 and   = 0.20 is 0.274.<div style=padding-top: 35px> = 0.20 is 0.274.
Question
The sampling distribution of The sampling distribution of   is approximately normal, provided that the sample size is large enough (n > 30).<div style=padding-top: 35px> is approximately normal, provided that the sample size is large enough (n > 30).
Question
In testing <strong>In testing   vs.   random sample of size 200 produced a sample proportion   Given these results, the p-value of the test is approximately:</strong> A) .4616 B) .5384 C) .0384 D) .0768 E) .2812 <div style=padding-top: 35px> vs. <strong>In testing   vs.   random sample of size 200 produced a sample proportion   Given these results, the p-value of the test is approximately:</strong> A) .4616 B) .5384 C) .0384 D) .0768 E) .2812 <div style=padding-top: 35px> random sample of size 200 produced a sample proportion <strong>In testing   vs.   random sample of size 200 produced a sample proportion   Given these results, the p-value of the test is approximately:</strong> A) .4616 B) .5384 C) .0384 D) .0768 E) .2812 <div style=padding-top: 35px> Given these results, the p-value of the test is approximately:

A) .4616
B) .5384
C) .0384
D) .0768
E) .2812
Question
In a one-tail test for the population proportion, if the null hypothesis is not rejected when the alternative hypothesis is false, a Type II error is committed.
Question
In a two-tail test for the population proportion, if the null hypothesis is rejected when the alternative hypothesis is false, a Type I error is committed.
Question
Suppose in testing a hypothesis about a proportion, the p-value is computed to be 0.038. The null hypothesis should be rejected if the chosen level of significance is 0.05.
Question
The rejection region for testing <strong>The rejection region for testing   at the 0.05 level of significance is:</strong> A) |z| < 1.28 B) |z| > 1.96 C) z > 1.645 D) z < 2.33 E) z < 2.58 <div style=padding-top: 35px> at the 0.05 level of significance is:

A) |z| < 1.28
B) |z| > 1.96
C) z > 1.645
D) z < 2.33
E) z < 2.58
Question
The lower limit of the 90% confidence interval for the population proportion p, given that n = 400 and The lower limit of the 90% confidence interval for the population proportion p, given that n = 400 and   = 0.10 is 0.1247.<div style=padding-top: 35px> = 0.10 is 0.1247.
Question
A professor of statistics refutes the claim that the proportion of Republican voters in Michigan is at most 44%. To test the claim, the hypotheses: A professor of statistics refutes the claim that the proportion of Republican voters in Michigan is at most 44%. To test the claim, the hypotheses:   ,   , should be used.<div style=padding-top: 35px> , A professor of statistics refutes the claim that the proportion of Republican voters in Michigan is at most 44%. To test the claim, the hypotheses:   ,   , should be used.<div style=padding-top: 35px> , should be used.
Question
In a hypothesis test involving the population proportion, which of the following would be an acceptable formulation?

A) H0 : p̂ = .25 vs Ha : p̂ < .25 .
B) H0 : p̂ = .25 vs Ha : p̂ > .25 .
C) H0 : p̂ = .25 vs Ha : p̂ ≠  .25 .
D) H0 : p̂ = .25 vs. Ha : p̂ < .25 and H0 : p̂ = .25 vs. Ha : p̂ > .25 are acceptable
E) none of these
Question
In testing a hypothesis about a population proportion p, the z test statistic measures how close the computed sample proportion In testing a hypothesis about a population proportion p, the z test statistic measures how close the computed sample proportion   has come to the hypothesized population parameter.<div style=padding-top: 35px> has come to the hypothesized population parameter.
Question
The use of the standard normal distribution for constructing confidence interval estimate for the population proportion p requires:

A) andare both greater than 5, wheredenotes the sample proportion
B) np and n(1 - p) are both greater than 5
C) n(p +) and n(p -) are both greater than 5
D) that the sample size is greater than 5
E) that the sample size is greater than 10
Question
Assuming that all necessary conditions are met, what needs to be changed in the formula <strong>Assuming that all necessary conditions are met, what needs to be changed in the formula   , so that we can use it to construct a confidence interval estimate for the population proportion p?</strong> A) The p̂ should be replaced by p. B) The t<sub>a</sub> should be replaced by z<sub>a</sub>. C) The t<sub>a</sub> should be replaced by t<sub>a/2</sub>. D) The t<sub>a</sub> should be replaced by z<sub>a/2</sub>. E) The p̂ should be replaced by z<sub>a/2</sub>. <div style=padding-top: 35px> , so that we can use it to construct a confidence interval estimate for the population proportion p?

A) The p̂ should be replaced by p.
B) The ta should be replaced by za.
C) The ta should be replaced by ta/2.
D) The ta should be replaced by za/2.
E) The p̂ should be replaced by za/2.
Question
Suppose in testing a hypothesis about a proportion, the z test statistic is computed to be 1.92. The null hypothesis should be rejected if the chosen level of significance is 0.01 and a two-tailed test is used.
Question
In a one-tail test about the population proportion p, the p-value is found to be equal to 0.0352. If the test had been two-tail, the p-value would have been 0.0704.
Question
A two-tailed test of the population proportion produces a test statistic z = 1.77. The p-value of the test is 0.4616.
Question
If a null hypothesis about the population proportion p is rejected at the 0.10 level of significance, it must be rejected at the 0.05 level.
Question
In selecting the sample size to estimate the population proportion p, if we have no knowledge of even the approximate values of the sample proportion <strong>In selecting the sample size to estimate the population proportion p, if we have no knowledge of even the approximate values of the sample proportion   , we:</strong> A) take another sample and estimate B) take two more samples and find the average of their C) let=0.50 D) let=0.95 E) let=0.05 <div style=padding-top: 35px> , we:

A) take another sample and estimate
B) take two more samples and find the average of their
C) let=0.50
D) let=0.95
E) let=0.05
Question
For a given data set and confidence level, the confidence interval of the population proportion p will be wider for 95% confidence than for 90% confidence.
Question
In testing the difference between two population means using two independent samples, the sampling distribution of the sample mean difference In testing the difference between two population means using two independent samples, the sampling distribution of the sample mean difference   is normal if the sample sizes are both greater than 30.<div style=padding-top: 35px> is normal if the sample sizes are both greater than 30.
Question
A survey claims that 9 out of 10 doctors recommend aspirin for their patients with headaches. To test this claim against the alternative that the actual proportion of doctors who recommend aspirin is less than 0.90, a random sample of 100 doctors' results in 83 who indicate that they recommend aspirin. The value of the test statistic in this problem is approximately equal to:

A) -1.67
B) -2.33
C) -1.86
D) -0.14
E) -2.58
Question
After calculating the sample size needed to estimate a population proportion to within 0.04, your statistics professor told you the maximum allowable error must be reduced to just .01. If the original calculation led to a sample size of 800, the sample size will now have to be:

A) 800
B) 3200
C) 12,800
D) 6400
E) 1600
Question
If you wish to test whether two populations means are the same, the appropriate null and alternative hypotheses would be: If you wish to test whether two populations means are the same, the appropriate null and alternative hypotheses would be:   vs.   .<div style=padding-top: 35px> vs. If you wish to test whether two populations means are the same, the appropriate null and alternative hypotheses would be:   vs.   .<div style=padding-top: 35px> .
Question
The z-test can be used to determine whether two population means are equal.
Question
In testing the difference between two population means using two independent samples, we use the pooled variance in estimating the standard error of the sampling distribution of the sample mean difference In testing the difference between two population means using two independent samples, we use the pooled variance in estimating the standard error of the sampling distribution of the sample mean difference   if the populations are normal with equal variances.<div style=padding-top: 35px> if the populations are normal with equal variances.
Question
In estimating the difference between two population means, the following summary statistics were found: In estimating the difference between two population means, the following summary statistics were found:           and   Based on these results, the point estimate of   is .70.<div style=padding-top: 35px> In estimating the difference between two population means, the following summary statistics were found:           and   Based on these results, the point estimate of   is .70.<div style=padding-top: 35px> In estimating the difference between two population means, the following summary statistics were found:           and   Based on these results, the point estimate of   is .70.<div style=padding-top: 35px> In estimating the difference between two population means, the following summary statistics were found:           and   Based on these results, the point estimate of   is .70.<div style=padding-top: 35px> In estimating the difference between two population means, the following summary statistics were found:           and   Based on these results, the point estimate of   is .70.<div style=padding-top: 35px> and In estimating the difference between two population means, the following summary statistics were found:           and   Based on these results, the point estimate of   is .70.<div style=padding-top: 35px> Based on these results, the point estimate of In estimating the difference between two population means, the following summary statistics were found:           and   Based on these results, the point estimate of   is .70.<div style=padding-top: 35px> is .70.
Question
The width of a confidence interval estimate for a proportion will be:

A) narrower for 99% confidence than for 95% confidence
B) wider for a sample size of 100 than for a sample size of 50
C) narrower for 90% confidence than for 95% confidence
D) narrower when the sample proportion if 0.50 than when the sample proportion is 0.20
E) none of these
Question
Which of the following would be an appropriate null hypothesis?

A) The population proportion is equal to 0.60.
B) The sample proportion is equal to 0.60.
C) The population proportion is not equal to 0.60.
D) The population proportion is greater than 0.60.
E) All of these.
Question
A political analyst in Iowa surveys a random sample of registered Democrats and compares the results with those obtained from a random sample of registered Republicans. This would be an example of two independent samples.
Question
In testing the difference between two population means using two independent samples, the population standard deviations are assumed to be known, and the calculated test statistic equals 2.75. If the test is two-tail and 5% level of significance has been specified, the conclusion should be not to reject the null hypothesis.
Question
The significance level in a hypothesis test for the difference between two population means is the same as the probability of committing a Type I error.
Question
With all other factors held constant, increasing the confidence level for a confidence interval estimate for the difference between two population means will result in a wider confidence interval estimate.
Question
Which of the following would be an appropriate alternative hypothesis?

A) The population proportion is less than 0.65.
B) The sample proportion is less than 0.65.
C) The population proportion is equal to 0.65.
D) The sample proportion is equal to 0.65.
E) The population proportion is less than 0.65 and the sample proportion is equal to 0.65.
Question
If we reject the null hypothesis If we reject the null hypothesis   at the 0.01 level of significance, then we must also reject it at the 0.05 level.<div style=padding-top: 35px> at the 0.01 level of significance, then we must also reject it at the 0.05 level.
Question
From a sample of 400 items, 14 are found to be defective. The point estimate of the population proportion defective will be:

A) 14
B) 0.035
C) 28.57
D) 0.05
E) 0.26
Question
Independent samples are those for which the selection process for one is not related to the selection process for the other.
Question
Increasing the size of the samples in a study to estimate the difference between two population means will increase the probability of committing a Type I error that a decision maker can have regarding the interval estimate.
Question
In estimating the difference between two population means, if a 90% confidence interval includes zero, then we can be 90% certain that the difference between the two population means is zero.
Question
In estimating the difference between two population means, the estimate for the standard deviation of the sampling distribution of In estimating the difference between two population means, the estimate for the standard deviation of the sampling distribution of   is found by taking the square root of the sum of the two sample variances.<div style=padding-top: 35px> is found by taking the square root of the sum of the two sample variances.
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Deck 9: Large-Sample Tests of Hypotheses
1
In constructing a confidence interval estimate for the difference between two population proportions, we:

A) pool the population proportions when the populations are normally distributed
B) pool the population proportions when the population means are equal
C) pool the population proportions when they are equal
D) never pool the population proportions to construct confidence interval for
E) always pool the population proportions to construct confidence interval for
never pool the population proportions to construct confidence interval for
2
The test statistic that is used in testing The test statistic that is used in testing   vs.   is   where   . vs. The test statistic that is used in testing   vs.   is   where   . is The test statistic that is used in testing   vs.   is   where   . where The test statistic that is used in testing   vs.   is   where   . .
False
3
When the necessary conditions are met, a lower tailed test is being conducted for the difference between two population proportions. If the value of the test statistic is -2.50, then the p-value is 0.0062.
True
4
A sample of size 150 from population 1 has 40 successes. A sample of size 250 from population 2 has 30 successes. The value of the test statistic for testing the null hypothesis that the proportion of successes in population one exceeds the proportion of successes in population two by 0.05 is:

A) 1.645
B) 2.327
C) 1.960
D) 1.977
E) 1.772
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5
For testing the difference between two population proportions, the pooled proportion estimate should be used to compute the value of the test statistic when the:

A) populations are normally distributed
B) sample sizes are small
C) samples are independently drawn from the populations
D) null hypothesis states that the two population proportions are equal
E) populations are normally distributed and sample sizes are small
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6
If we reject the null hypothesis If we reject the null hypothesis   , we conclude that there is not enough statistical evidence to infer that the population proportions are equal. , we conclude that there is not enough statistical evidence to infer that the population proportions are equal.
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7
In testing the null hypothesis <strong>In testing the null hypothesis   , if   is false, the test could lead to:</strong> A) a Type I error B) a Type II error C) a Type O error D) either a Type I or a Type II error E) neither a Type I nor a Type II error , if <strong>In testing the null hypothesis   , if   is false, the test could lead to:</strong> A) a Type I error B) a Type II error C) a Type O error D) either a Type I or a Type II error E) neither a Type I nor a Type II error is false, the test could lead to:

A) a Type I error
B) a Type II error
C) a Type O error
D) either a Type I or a Type II error
E) neither a Type I nor a Type II error
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8
When the necessary conditions are met, a two-tailed test is being conducted to test the difference between two population proportions. The two sample proportions are When the necessary conditions are met, a two-tailed test is being conducted to test the difference between two population proportions. The two sample proportions are   and   , respectively, and the standard error of the sampling distribution of   is 0.04. Then, the calculated value of the test statistic will be 1.50. and When the necessary conditions are met, a two-tailed test is being conducted to test the difference between two population proportions. The two sample proportions are   and   , respectively, and the standard error of the sampling distribution of   is 0.04. Then, the calculated value of the test statistic will be 1.50. , respectively, and the standard error of the sampling distribution of When the necessary conditions are met, a two-tailed test is being conducted to test the difference between two population proportions. The two sample proportions are   and   , respectively, and the standard error of the sampling distribution of   is 0.04. Then, the calculated value of the test statistic will be 1.50. is 0.04. Then, the calculated value of the test statistic will be 1.50.
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9
In testing In testing   vs.   the test statistic value is found to be z = 1.28. The p-value of the test is approximately .1003. vs. In testing   vs.   the test statistic value is found to be z = 1.28. The p-value of the test is approximately .1003. the test statistic value is found to be z = 1.28. The p-value of the test is approximately .1003.
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10
A sample of size 100 selected from one population has 60 successes, and a sample of size 150 selected from a second population has 95 successes. The test statistic for testing the equality of the population proportions equal to:

A) -0.5319
B) 0.7293
C) -0.419
D) 0.2702
E) -0.3518
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11
When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. The two sample proportions are <strong>When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. The two sample proportions are   and   , and the standard error of the sampling distribution of   is 0.04. The calculated value of the test statistic will be:</strong> A) z = 0.25 B) z = 1.25 C) t = 0.25 D) t = 0.80 E) t = 1.25 and <strong>When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. The two sample proportions are   and   , and the standard error of the sampling distribution of   is 0.04. The calculated value of the test statistic will be:</strong> A) z = 0.25 B) z = 1.25 C) t = 0.25 D) t = 0.80 E) t = 1.25 , and the standard error of the sampling distribution of <strong>When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. The two sample proportions are   and   , and the standard error of the sampling distribution of   is 0.04. The calculated value of the test statistic will be:</strong> A) z = 0.25 B) z = 1.25 C) t = 0.25 D) t = 0.80 E) t = 1.25 is 0.04. The calculated value of the test statistic will be:

A) z = 0.25
B) z = 1.25
C) t = 0.25
D) t = 0.80
E) t = 1.25
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12
When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. If the value of the test statistic is 2.05, then the p-value is:

A) 0.4798
B) 0.0404
C) 0.2399
D) 0.0202
E) 0.1982
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13
When the necessary conditions are met, an upper tailed test is being conducted for the difference between two population proportions. If the value of the test statistic is 2.90, then the p-value is 0.0038.
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14
When the necessary conditions are met, a two-tailed test is being conducted to test the difference between two population proportions. The two sample proportions are When the necessary conditions are met, a two-tailed test is being conducted to test the difference between two population proportions. The two sample proportions are   and   , and the standard error of the sampling distribution of   is 0.0085. The calculated value of the test statistic will be z = 3.41. and When the necessary conditions are met, a two-tailed test is being conducted to test the difference between two population proportions. The two sample proportions are   and   , and the standard error of the sampling distribution of   is 0.0085. The calculated value of the test statistic will be z = 3.41. , and the standard error of the sampling distribution of When the necessary conditions are met, a two-tailed test is being conducted to test the difference between two population proportions. The two sample proportions are   and   , and the standard error of the sampling distribution of   is 0.0085. The calculated value of the test statistic will be z = 3.41. is 0.0085. The calculated value of the test statistic will be z = 3.41.
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15
When the necessary conditions are met, a lower tailed test is being conducted for the difference between two population proportions. If the value of the test statistic is -2.43, then the null hypothesis cannot be rejected at When the necessary conditions are met, a lower tailed test is being conducted for the difference between two population proportions. If the value of the test statistic is -2.43, then the null hypothesis cannot be rejected at   = 0.025. = 0.025.
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16
Which of the following is a required condition for using the normal approximation to the binomial in testing the difference between two population proportions?

A) n1p1 ≥ 30 and n2p2 ≥ 30
B) n1p1 ≥ 5 and n2p2 ≥ 5
C) n1p1 ≥ 5 , n1(1-p1) ≥ 5 , n2p2 ≥ 5 and n2(1-p2) ≥ 5
D) n11 ≥ 5 , n1(1-p̂1) ≥ 5 , n22 ≥ 5 and n2(1-p̂2) ≥ 5
E) n1p1 ≥ 10 and n2p2 ≥ 10
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17
When the necessary conditions are met, a two-tailed test is being conducted for the difference between two population proportions. If the value of the test statistic is 1.96, then the null hypothesis is rejected at When the necessary conditions are met, a two-tailed test is being conducted for the difference between two population proportions. If the value of the test statistic is 1.96, then the null hypothesis is rejected at   = 0.10. = 0.10.
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18
In testing In testing   vs.   using a significance level equal to .05, the critical value that will be used to conduct the test is z = 1.645. vs. In testing   vs.   using a significance level equal to .05, the critical value that will be used to conduct the test is z = 1.645. using a significance level equal to .05, the critical value that will be used to conduct the test is z = 1.645.
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19
When the necessary conditions are met, a two-tailed test is being conducted for the difference between two population proportions. If the value of the test statistic is -1.35, then the p-value is 0.0885.
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20
In testing In testing   vs/   the following summary statistics are found:       and   Based on these results, the null hypothesis should be rejected at the significance level   . vs/ In testing   vs/   the following summary statistics are found:       and   Based on these results, the null hypothesis should be rejected at the significance level   . the following summary statistics are found: In testing   vs/   the following summary statistics are found:       and   Based on these results, the null hypothesis should be rejected at the significance level   . In testing   vs/   the following summary statistics are found:       and   Based on these results, the null hypothesis should be rejected at the significance level   . In testing   vs/   the following summary statistics are found:       and   Based on these results, the null hypothesis should be rejected at the significance level   . and In testing   vs/   the following summary statistics are found:       and   Based on these results, the null hypothesis should be rejected at the significance level   . Based on these results, the null hypothesis should be rejected at the significance level In testing   vs/   the following summary statistics are found:       and   Based on these results, the null hypothesis should be rejected at the significance level   . .
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21
In testing In testing   vs.   a random sample of size 100 produced a sample proportion   Given these results, the test statistic value is z = -.655. vs. In testing   vs.   a random sample of size 100 produced a sample proportion   Given these results, the test statistic value is z = -.655. a random sample of size 100 produced a sample proportion In testing   vs.   a random sample of size 100 produced a sample proportion   Given these results, the test statistic value is z = -.655. Given these results, the test statistic value is z = -.655.
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22
In testing In testing   vs.   at   , any p-value greater than .025 will lead to a rejection of the null hypothesis. vs. In testing   vs.   at   , any p-value greater than .025 will lead to a rejection of the null hypothesis. at In testing   vs.   at   , any p-value greater than .025 will lead to a rejection of the null hypothesis. , any p-value greater than .025 will lead to a rejection of the null hypothesis.
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23
If the null hypothesis If the null hypothesis   is rejected at the 0.05 level of significance, it must be rejected at the 0.01 level. is rejected at the 0.05 level of significance, it must be rejected at the 0.01 level.
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24
A one-tailed hypothesis test of the population proportion is used when the alternative hypothesis takes the form A one-tailed hypothesis test of the population proportion is used when the alternative hypothesis takes the form   . .
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25
In testing In testing   vs.   a random sample of size 200 produced a sample proportion   Given these results, the null hypothesis should not be rejected at   = .05. vs. In testing   vs.   a random sample of size 200 produced a sample proportion   Given these results, the null hypothesis should not be rejected at   = .05. a random sample of size 200 produced a sample proportion In testing   vs.   a random sample of size 200 produced a sample proportion   Given these results, the null hypothesis should not be rejected at   = .05. Given these results, the null hypothesis should not be rejected at In testing   vs.   a random sample of size 200 produced a sample proportion   Given these results, the null hypothesis should not be rejected at   = .05. = .05.
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26
A two-tailed hypothesis test of the population proportion takes the form A two-tailed hypothesis test of the population proportion takes the form   vs.   . vs. A two-tailed hypothesis test of the population proportion takes the form   vs.   . .
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27
Independent random samples of n1 = 150 and n2 = 150 sales phone calls for an insurance policy were randomly selected from binomial populations 1 and 2, respectively. Sample 1 had 80 successful sales, and sample 2 had 88 successful sales. Suppose you have no preconceived theory concerning which parameter, p1 or p2, is the larger and you wish to detect only a difference between the two parameters if one exists.
Calculate the standard error of the difference in the two sample proportions, Independent random samples of n<sub>1</sub> = 150 and n<sub>2</sub> = 150 sales phone calls for an insurance policy were randomly selected from binomial populations 1 and 2, respectively. Sample 1 had 80 successful sales, and sample 2 had 88 successful sales. Suppose you have no preconceived theory concerning which parameter, p<sub>1</sub> or p<sub>2</sub>, is the larger and you wish to detect only a difference between the two parameters if one exists. Calculate the standard error of the difference in the two sample proportions,   . Make sure to use the pooled estimate for the common value of p. ______________ Calculate the test statistic that you would use for the test above. Based on your knowledge of the standard normal distribution, is this a likely or unlikely observation, assuming that H<sub>0</sub> is true and the two population proportions are the same? Test statistic = ______________ Find the p-value for the test. Test for a significant difference in the population means at the 1% significance level. p-value = ______________ Find the rejection region when   = 0.01. Do the data provide sufficient evidence to indicate a difference in the population proportions? Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________ . Make sure to use the pooled estimate for the common value of p.
______________
Calculate the test statistic that you would use for the test above. Based on your knowledge of the standard normal distribution, is this a likely or unlikely observation, assuming that H0 is true and the two population proportions are the same?
Test statistic = ______________
Find the p-value for the test. Test for a significant difference in the population means at the 1% significance level.
p-value = ______________
Find the rejection region when Independent random samples of n<sub>1</sub> = 150 and n<sub>2</sub> = 150 sales phone calls for an insurance policy were randomly selected from binomial populations 1 and 2, respectively. Sample 1 had 80 successful sales, and sample 2 had 88 successful sales. Suppose you have no preconceived theory concerning which parameter, p<sub>1</sub> or p<sub>2</sub>, is the larger and you wish to detect only a difference between the two parameters if one exists. Calculate the standard error of the difference in the two sample proportions,   . Make sure to use the pooled estimate for the common value of p. ______________ Calculate the test statistic that you would use for the test above. Based on your knowledge of the standard normal distribution, is this a likely or unlikely observation, assuming that H<sub>0</sub> is true and the two population proportions are the same? Test statistic = ______________ Find the p-value for the test. Test for a significant difference in the population means at the 1% significance level. p-value = ______________ Find the rejection region when   = 0.01. Do the data provide sufficient evidence to indicate a difference in the population proportions? Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________ = 0.01. Do the data provide sufficient evidence to indicate a difference in the population proportions?
Critical Value(s) = ______________
Conclusion: ______________
Interpretation: __________________________________________
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28
The Environmental Protection Agency wanted to compare the proportion of plants in violation of air quality standards for two different industries: steel and utility. Two independent samples of plants were selected and monitored. The following data was recorded: The Environmental Protection Agency wanted to compare the proportion of plants in violation of air quality standards for two different industries: steel and utility. Two independent samples of plants were selected and monitored. The following data was recorded:   Test at   = 0.01 Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________ Test at The Environmental Protection Agency wanted to compare the proportion of plants in violation of air quality standards for two different industries: steel and utility. Two independent samples of plants were selected and monitored. The following data was recorded:   Test at   = 0.01 Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________ = 0.01
Test statistic = ______________
Critical Value(s) = ______________
Conclusion: ______________
Interpretation: __________________________________________
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29
A cable company in Michigan is thinking of offering its service in one of two counties; Mecosta and Newaygo. Allegedly, the proportion of households in either county ready to hook up to the cable is the same, but the company wants to test the claim. Accordingly, it takes a simple random sample in each county. In Mecosta county, 175 of 2900 households say they will join. In Newaygo county, 665 of 800 households say so.
Calculate the pooled estimate of the common proportion p.
______________
Calculate the standard error of A cable company in Michigan is thinking of offering its service in one of two counties; Mecosta and Newaygo. Allegedly, the proportion of households in either county ready to hook up to the cable is the same, but the company wants to test the claim. Accordingly, it takes a simple random sample in each county. In Mecosta county, 175 of 2900 households say they will join. In Newaygo county, 665 of 800 households say so. Calculate the pooled estimate of the common proportion p. ______________ Calculate the standard error of   . ______________ Calculate the value of the test statistic. ______________ Calculate the p-value and write your conclusion given that   = 0.05. ______________ Conclusion: ______________ Interpretation: __________________________________________ Construct 95% confidence interval for the difference in proportions of households in Mecosta and Newaygo counties who are ready to hook up to the cable. ______________ Explain how to use the 95% confidence interval to test the appropriate hypotheses at   = 0.05. __________________________________________ .
______________
Calculate the value of the test statistic.
______________
Calculate the p-value and write your conclusion given that A cable company in Michigan is thinking of offering its service in one of two counties; Mecosta and Newaygo. Allegedly, the proportion of households in either county ready to hook up to the cable is the same, but the company wants to test the claim. Accordingly, it takes a simple random sample in each county. In Mecosta county, 175 of 2900 households say they will join. In Newaygo county, 665 of 800 households say so. Calculate the pooled estimate of the common proportion p. ______________ Calculate the standard error of   . ______________ Calculate the value of the test statistic. ______________ Calculate the p-value and write your conclusion given that   = 0.05. ______________ Conclusion: ______________ Interpretation: __________________________________________ Construct 95% confidence interval for the difference in proportions of households in Mecosta and Newaygo counties who are ready to hook up to the cable. ______________ Explain how to use the 95% confidence interval to test the appropriate hypotheses at   = 0.05. __________________________________________ = 0.05.
______________
Conclusion: ______________
Interpretation: __________________________________________
Construct 95% confidence interval for the difference in proportions of households in Mecosta and Newaygo counties who are ready to hook up to the cable.
______________
Explain how to use the 95% confidence interval to test the appropriate hypotheses at A cable company in Michigan is thinking of offering its service in one of two counties; Mecosta and Newaygo. Allegedly, the proportion of households in either county ready to hook up to the cable is the same, but the company wants to test the claim. Accordingly, it takes a simple random sample in each county. In Mecosta county, 175 of 2900 households say they will join. In Newaygo county, 665 of 800 households say so. Calculate the pooled estimate of the common proportion p. ______________ Calculate the standard error of   . ______________ Calculate the value of the test statistic. ______________ Calculate the p-value and write your conclusion given that   = 0.05. ______________ Conclusion: ______________ Interpretation: __________________________________________ Construct 95% confidence interval for the difference in proportions of households in Mecosta and Newaygo counties who are ready to hook up to the cable. ______________ Explain how to use the 95% confidence interval to test the appropriate hypotheses at   = 0.05. __________________________________________ = 0.05.
__________________________________________
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30
A manufacturing plant has two assembly lines for producing plastic bottles. The plant manager was concerned about whether the proportion of defective bottles differed between the two lines. Two independent random samples were selected and the following summary data computed: A manufacturing plant has two assembly lines for producing plastic bottles. The plant manager was concerned about whether the proportion of defective bottles differed between the two lines. Two independent random samples were selected and the following summary data computed:   Perform the appropriate test of hypothesis using   = 0.05. Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________ Perform the appropriate test of hypothesis using A manufacturing plant has two assembly lines for producing plastic bottles. The plant manager was concerned about whether the proportion of defective bottles differed between the two lines. Two independent random samples were selected and the following summary data computed:   Perform the appropriate test of hypothesis using   = 0.05. Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________ = 0.05.
Test statistic = ______________
Critical Value(s) = ______________
Conclusion: ______________
Interpretation: __________________________________________
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31
When testing When testing   vs.   , an increase in the sample size will result in a decrease in the probability of committing a Type I error. vs. When testing   vs.   , an increase in the sample size will result in a decrease in the probability of committing a Type I error. , an increase in the sample size will result in a decrease in the probability of committing a Type I error.
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32
An experiment was conducted to test the effect of a new drug on a viral infection. The infection was induced in 100 mice, and the mice were randomly split into two groups of 50. The first group, the control group, received no treatment for the infection. The second group received the drug. The proportions of survivors, An experiment was conducted to test the effect of a new drug on a viral infection. The infection was induced in 100 mice, and the mice were randomly split into two groups of 50. The first group, the control group, received no treatment for the infection. The second group received the drug. The proportions of survivors,   and   , in the two groups after a 30-day period, were found to be 0.40 and 0.64, respectively. Is there sufficient evidence to indicate that the drug is effective in treating the viral infection? Use   = 0.05. Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________ Use a 95% confidence interval to estimate the actual difference in the cure rates for the treated versus the control groups. ______________ and An experiment was conducted to test the effect of a new drug on a viral infection. The infection was induced in 100 mice, and the mice were randomly split into two groups of 50. The first group, the control group, received no treatment for the infection. The second group received the drug. The proportions of survivors,   and   , in the two groups after a 30-day period, were found to be 0.40 and 0.64, respectively. Is there sufficient evidence to indicate that the drug is effective in treating the viral infection? Use   = 0.05. Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________ Use a 95% confidence interval to estimate the actual difference in the cure rates for the treated versus the control groups. ______________ , in the two groups after a 30-day period, were found to be 0.40 and 0.64, respectively. Is there sufficient evidence to indicate that the drug is effective in treating the viral infection? Use An experiment was conducted to test the effect of a new drug on a viral infection. The infection was induced in 100 mice, and the mice were randomly split into two groups of 50. The first group, the control group, received no treatment for the infection. The second group received the drug. The proportions of survivors,   and   , in the two groups after a 30-day period, were found to be 0.40 and 0.64, respectively. Is there sufficient evidence to indicate that the drug is effective in treating the viral infection? Use   = 0.05. Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________ Use a 95% confidence interval to estimate the actual difference in the cure rates for the treated versus the control groups. ______________ = 0.05.
Test statistic = ______________
Critical Value(s) = ______________
Conclusion: ______________
Interpretation: __________________________________________
Use a 95% confidence interval to estimate the actual difference in the cure rates for the treated versus the control groups.
______________
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33
In testing the hypotheses H0: p1 - p2 = 0 vs. Ha: p1 - p2 > 0, use the following statistics, where x1 and x2 represent the number of defective components found in medical instruments in the two samples.
n1 = 200, x1 = 80
n2 = 400, x2 = 140
What conclusion can we draw at the 5% significance level?
Test statistic = ______________
Critical Value(s) = ______________
Conclusion: ______________
What is the p-value of the test?
p-value = ______________
Explain how to use the p-value to test the hypotheses.
____________________________
Estimate with 95% confidence the difference between the two population proportions.
______________
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34
Suppose in testing a hypothesis about a proportion, the p-value is computed to be 0.027. The null hypothesis should be rejected if the chosen level of significance is 0.01.
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35
In testing the hypotheses
H0: p1 - p2 = 0.10 vs.
Ha: In testing the hypotheses H<sub>0</sub>: p<sub>1</sub> - p<sub>2</sub> = 0.10 vs. H<sub>a</sub>:   . Use the following statistics, where x<sub>1</sub> and x<sub>2</sub> represent the number of Dial Soap sales in the two samples, respectively. n<sub>1</sub> = 150, x<sub>1</sub> = 72 n<sub>2</sub> = 175, x<sub>2</sub> = 70 What conclusion can we draw at the 5% significance level? Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ What is the p-value of the test? p-value = ______________ Explain how to use the p-value to test the hypotheses. ____________________________ Estimate with 95% confidence the difference between the two population proportions. ______________ Interpret and explain how to use the confidence interval to test the hypotheses. __________________________________________ .
Use the following statistics, where x1 and x2 represent the number of Dial Soap sales in the two samples, respectively.
n1 = 150, x1 = 72
n2 = 175, x2 = 70
What conclusion can we draw at the 5% significance level?
Test statistic = ______________
Critical Value(s) = ______________
Conclusion: ______________
What is the p-value of the test?
p-value = ______________
Explain how to use the p-value to test the hypotheses.
____________________________
Estimate with 95% confidence the difference between the two population proportions.
______________
Interpret and explain how to use the confidence interval to test the hypotheses.
__________________________________________
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36
In testing In testing   vs.   the level of significance must be twice as large as when testing   vs.   . vs. In testing   vs.   the level of significance must be twice as large as when testing   vs.   . the level of significance must be twice as large as when testing In testing   vs.   the level of significance must be twice as large as when testing   vs.   . vs. In testing   vs.   the level of significance must be twice as large as when testing   vs.   . .
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37
When the hypothesized proportion When the hypothesized proportion   is close to 0.50, the spread in the sampling distribution of the sample proportion   is greater than when   is close to 0.0 or 1.0. is close to 0.50, the spread in the sampling distribution of the sample proportion When the hypothesized proportion   is close to 0.50, the spread in the sampling distribution of the sample proportion   is greater than when   is close to 0.0 or 1.0. is greater than when When the hypothesized proportion   is close to 0.50, the spread in the sampling distribution of the sample proportion   is greater than when   is close to 0.0 or 1.0. is close to 0.0 or 1.0.
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38
In testing In testing   vs.   the test statistic value is found to be equal to 1.20. The p-value for this test would be approximately .1151. vs. In testing   vs.   the test statistic value is found to be equal to 1.20. The p-value for this test would be approximately .1151. the test statistic value is found to be equal to 1.20. The p-value for this test would be approximately .1151.
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39
The campaign manager of John Kerry believes that more than 52% of the registered voters will vote in favor of Kerry. If you wish to test this claim, the appropriate null and alternative hypotheses are The campaign manager of John Kerry believes that more than 52% of the registered voters will vote in favor of Kerry. If you wish to test this claim, the appropriate null and alternative hypotheses are   vs.   . vs. The campaign manager of John Kerry believes that more than 52% of the registered voters will vote in favor of Kerry. If you wish to test this claim, the appropriate null and alternative hypotheses are   vs.   . .
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40
A group in favor of freezing production of nuclear weapons believes that the proportion of individuals in favor of a nuclear freeze is greater for those who have seen the movie "The Day After" (population 1) than those who have not (population 2). In an attempt to verify this belief, random samples of size 500 are obtained from the populations of interest. Among those who had seen "The Day After", 228 were in favor of a freeze. For those who had not seen the movie, 196 favored a freeze. Test using A group in favor of freezing production of nuclear weapons believes that the proportion of individuals in favor of a nuclear freeze is greater for those who have seen the movie The Day After (population 1) than those who have not (population 2). In an attempt to verify this belief, random samples of size 500 are obtained from the populations of interest. Among those who had seen The Day After, 228 were in favor of a freeze. For those who had not seen the movie, 196 favored a freeze. Test using   = 0.05. Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________ = 0.05.
Test statistic = ______________
Critical Value(s) = ______________
Conclusion: ______________
Interpretation: __________________________________________
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41
The lower limit of a confidence interval at the 95% level of confidence for the population proportion if a sample of size 200 had 40 successes is:

A) 0.2554
B) 0.1446
C) 0.2465
D) 0.1535
E) 0.3390
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42
The upper limit of the 85% confidence interval for the population proportion p, given that n = 60 and The upper limit of the 85% confidence interval for the population proportion p, given that n = 60 and   = 0.20 is 0.274. = 0.20 is 0.274.
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43
The sampling distribution of The sampling distribution of   is approximately normal, provided that the sample size is large enough (n > 30). is approximately normal, provided that the sample size is large enough (n > 30).
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44
In testing <strong>In testing   vs.   random sample of size 200 produced a sample proportion   Given these results, the p-value of the test is approximately:</strong> A) .4616 B) .5384 C) .0384 D) .0768 E) .2812 vs. <strong>In testing   vs.   random sample of size 200 produced a sample proportion   Given these results, the p-value of the test is approximately:</strong> A) .4616 B) .5384 C) .0384 D) .0768 E) .2812 random sample of size 200 produced a sample proportion <strong>In testing   vs.   random sample of size 200 produced a sample proportion   Given these results, the p-value of the test is approximately:</strong> A) .4616 B) .5384 C) .0384 D) .0768 E) .2812 Given these results, the p-value of the test is approximately:

A) .4616
B) .5384
C) .0384
D) .0768
E) .2812
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45
In a one-tail test for the population proportion, if the null hypothesis is not rejected when the alternative hypothesis is false, a Type II error is committed.
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46
In a two-tail test for the population proportion, if the null hypothesis is rejected when the alternative hypothesis is false, a Type I error is committed.
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47
Suppose in testing a hypothesis about a proportion, the p-value is computed to be 0.038. The null hypothesis should be rejected if the chosen level of significance is 0.05.
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48
The rejection region for testing <strong>The rejection region for testing   at the 0.05 level of significance is:</strong> A) |z| < 1.28 B) |z| > 1.96 C) z > 1.645 D) z < 2.33 E) z < 2.58 at the 0.05 level of significance is:

A) |z| < 1.28
B) |z| > 1.96
C) z > 1.645
D) z < 2.33
E) z < 2.58
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49
The lower limit of the 90% confidence interval for the population proportion p, given that n = 400 and The lower limit of the 90% confidence interval for the population proportion p, given that n = 400 and   = 0.10 is 0.1247. = 0.10 is 0.1247.
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50
A professor of statistics refutes the claim that the proportion of Republican voters in Michigan is at most 44%. To test the claim, the hypotheses: A professor of statistics refutes the claim that the proportion of Republican voters in Michigan is at most 44%. To test the claim, the hypotheses:   ,   , should be used. , A professor of statistics refutes the claim that the proportion of Republican voters in Michigan is at most 44%. To test the claim, the hypotheses:   ,   , should be used. , should be used.
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51
In a hypothesis test involving the population proportion, which of the following would be an acceptable formulation?

A) H0 : p̂ = .25 vs Ha : p̂ < .25 .
B) H0 : p̂ = .25 vs Ha : p̂ > .25 .
C) H0 : p̂ = .25 vs Ha : p̂ ≠  .25 .
D) H0 : p̂ = .25 vs. Ha : p̂ < .25 and H0 : p̂ = .25 vs. Ha : p̂ > .25 are acceptable
E) none of these
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52
In testing a hypothesis about a population proportion p, the z test statistic measures how close the computed sample proportion In testing a hypothesis about a population proportion p, the z test statistic measures how close the computed sample proportion   has come to the hypothesized population parameter. has come to the hypothesized population parameter.
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53
The use of the standard normal distribution for constructing confidence interval estimate for the population proportion p requires:

A) andare both greater than 5, wheredenotes the sample proportion
B) np and n(1 - p) are both greater than 5
C) n(p +) and n(p -) are both greater than 5
D) that the sample size is greater than 5
E) that the sample size is greater than 10
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54
Assuming that all necessary conditions are met, what needs to be changed in the formula <strong>Assuming that all necessary conditions are met, what needs to be changed in the formula   , so that we can use it to construct a confidence interval estimate for the population proportion p?</strong> A) The p̂ should be replaced by p. B) The t<sub>a</sub> should be replaced by z<sub>a</sub>. C) The t<sub>a</sub> should be replaced by t<sub>a/2</sub>. D) The t<sub>a</sub> should be replaced by z<sub>a/2</sub>. E) The p̂ should be replaced by z<sub>a/2</sub>. , so that we can use it to construct a confidence interval estimate for the population proportion p?

A) The p̂ should be replaced by p.
B) The ta should be replaced by za.
C) The ta should be replaced by ta/2.
D) The ta should be replaced by za/2.
E) The p̂ should be replaced by za/2.
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55
Suppose in testing a hypothesis about a proportion, the z test statistic is computed to be 1.92. The null hypothesis should be rejected if the chosen level of significance is 0.01 and a two-tailed test is used.
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56
In a one-tail test about the population proportion p, the p-value is found to be equal to 0.0352. If the test had been two-tail, the p-value would have been 0.0704.
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57
A two-tailed test of the population proportion produces a test statistic z = 1.77. The p-value of the test is 0.4616.
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58
If a null hypothesis about the population proportion p is rejected at the 0.10 level of significance, it must be rejected at the 0.05 level.
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59
In selecting the sample size to estimate the population proportion p, if we have no knowledge of even the approximate values of the sample proportion <strong>In selecting the sample size to estimate the population proportion p, if we have no knowledge of even the approximate values of the sample proportion   , we:</strong> A) take another sample and estimate B) take two more samples and find the average of their C) let=0.50 D) let=0.95 E) let=0.05 , we:

A) take another sample and estimate
B) take two more samples and find the average of their
C) let=0.50
D) let=0.95
E) let=0.05
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60
For a given data set and confidence level, the confidence interval of the population proportion p will be wider for 95% confidence than for 90% confidence.
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61
In testing the difference between two population means using two independent samples, the sampling distribution of the sample mean difference In testing the difference between two population means using two independent samples, the sampling distribution of the sample mean difference   is normal if the sample sizes are both greater than 30. is normal if the sample sizes are both greater than 30.
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62
A survey claims that 9 out of 10 doctors recommend aspirin for their patients with headaches. To test this claim against the alternative that the actual proportion of doctors who recommend aspirin is less than 0.90, a random sample of 100 doctors' results in 83 who indicate that they recommend aspirin. The value of the test statistic in this problem is approximately equal to:

A) -1.67
B) -2.33
C) -1.86
D) -0.14
E) -2.58
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63
After calculating the sample size needed to estimate a population proportion to within 0.04, your statistics professor told you the maximum allowable error must be reduced to just .01. If the original calculation led to a sample size of 800, the sample size will now have to be:

A) 800
B) 3200
C) 12,800
D) 6400
E) 1600
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64
If you wish to test whether two populations means are the same, the appropriate null and alternative hypotheses would be: If you wish to test whether two populations means are the same, the appropriate null and alternative hypotheses would be:   vs.   . vs. If you wish to test whether two populations means are the same, the appropriate null and alternative hypotheses would be:   vs.   . .
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65
The z-test can be used to determine whether two population means are equal.
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66
In testing the difference between two population means using two independent samples, we use the pooled variance in estimating the standard error of the sampling distribution of the sample mean difference In testing the difference between two population means using two independent samples, we use the pooled variance in estimating the standard error of the sampling distribution of the sample mean difference   if the populations are normal with equal variances. if the populations are normal with equal variances.
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67
In estimating the difference between two population means, the following summary statistics were found: In estimating the difference between two population means, the following summary statistics were found:           and   Based on these results, the point estimate of   is .70. In estimating the difference between two population means, the following summary statistics were found:           and   Based on these results, the point estimate of   is .70. In estimating the difference between two population means, the following summary statistics were found:           and   Based on these results, the point estimate of   is .70. In estimating the difference between two population means, the following summary statistics were found:           and   Based on these results, the point estimate of   is .70. In estimating the difference between two population means, the following summary statistics were found:           and   Based on these results, the point estimate of   is .70. and In estimating the difference between two population means, the following summary statistics were found:           and   Based on these results, the point estimate of   is .70. Based on these results, the point estimate of In estimating the difference between two population means, the following summary statistics were found:           and   Based on these results, the point estimate of   is .70. is .70.
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68
The width of a confidence interval estimate for a proportion will be:

A) narrower for 99% confidence than for 95% confidence
B) wider for a sample size of 100 than for a sample size of 50
C) narrower for 90% confidence than for 95% confidence
D) narrower when the sample proportion if 0.50 than when the sample proportion is 0.20
E) none of these
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69
Which of the following would be an appropriate null hypothesis?

A) The population proportion is equal to 0.60.
B) The sample proportion is equal to 0.60.
C) The population proportion is not equal to 0.60.
D) The population proportion is greater than 0.60.
E) All of these.
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70
A political analyst in Iowa surveys a random sample of registered Democrats and compares the results with those obtained from a random sample of registered Republicans. This would be an example of two independent samples.
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71
In testing the difference between two population means using two independent samples, the population standard deviations are assumed to be known, and the calculated test statistic equals 2.75. If the test is two-tail and 5% level of significance has been specified, the conclusion should be not to reject the null hypothesis.
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72
The significance level in a hypothesis test for the difference between two population means is the same as the probability of committing a Type I error.
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73
With all other factors held constant, increasing the confidence level for a confidence interval estimate for the difference between two population means will result in a wider confidence interval estimate.
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74
Which of the following would be an appropriate alternative hypothesis?

A) The population proportion is less than 0.65.
B) The sample proportion is less than 0.65.
C) The population proportion is equal to 0.65.
D) The sample proportion is equal to 0.65.
E) The population proportion is less than 0.65 and the sample proportion is equal to 0.65.
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75
If we reject the null hypothesis If we reject the null hypothesis   at the 0.01 level of significance, then we must also reject it at the 0.05 level. at the 0.01 level of significance, then we must also reject it at the 0.05 level.
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76
From a sample of 400 items, 14 are found to be defective. The point estimate of the population proportion defective will be:

A) 14
B) 0.035
C) 28.57
D) 0.05
E) 0.26
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77
Independent samples are those for which the selection process for one is not related to the selection process for the other.
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78
Increasing the size of the samples in a study to estimate the difference between two population means will increase the probability of committing a Type I error that a decision maker can have regarding the interval estimate.
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79
In estimating the difference between two population means, if a 90% confidence interval includes zero, then we can be 90% certain that the difference between the two population means is zero.
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80
In estimating the difference between two population means, the estimate for the standard deviation of the sampling distribution of In estimating the difference between two population means, the estimate for the standard deviation of the sampling distribution of   is found by taking the square root of the sum of the two sample variances. is found by taking the square root of the sum of the two sample variances.
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