Exam 9: Large-Sample Tests of Hypotheses

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Numerical values of a test statistic for which Numerical values of a test statistic for which   is not rejected: is not rejected:

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The owner of a marina would like to believe that more than 40% of the sailboat owners use their boats more than 6 times each summer. A random sample of 70 sailboat owners showed 42 used their boats more than 6 times each summer. Test the appropriate hypotheses using a significance level of 0.005. Is there reason for the marina owner to believe more than 40% of the sailboat owners use their boats more than 6 times each summer? Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________

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3.41; 2.575; reject H0; Yes, the marina owner is correct

The p-value is usually 0.025.

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A government testing agency studies aspirin capsules to see if customers are getting cheated with capsules that contain lesser amounts of medication than advertised. Suppose the testing agent concludes the capsules contain a mean amount below the advertised level when in fact the advertised level is the true mean. Which type of error, if any, did the testing agency commit?

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If the probability of committing a Type I error for a given test is to be decreased, then for a fixed sample size n, which of the following statements is true?

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In testing In testing   vs/   the following summary statistics are found:       and   Based on these results, the null hypothesis should be rejected at the significance level   . vs/ In testing   vs/   the following summary statistics are found:       and   Based on these results, the null hypothesis should be rejected at the significance level   . the following summary statistics are found: In testing   vs/   the following summary statistics are found:       and   Based on these results, the null hypothesis should be rejected at the significance level   . In testing   vs/   the following summary statistics are found:       and   Based on these results, the null hypothesis should be rejected at the significance level   . In testing   vs/   the following summary statistics are found:       and   Based on these results, the null hypothesis should be rejected at the significance level   . and In testing   vs/   the following summary statistics are found:       and   Based on these results, the null hypothesis should be rejected at the significance level   . Based on these results, the null hypothesis should be rejected at the significance level In testing   vs/   the following summary statistics are found:       and   Based on these results, the null hypothesis should be rejected at the significance level   . .

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The public relations officer for a particular city claims the average monthly cost for childcare outside the home for a single child is $700. A potential resident is interested in whether the claim is correct. She obtains a random sample of 64 records and computes the average monthly cost of this type of childcare to be $689 with a standard deviation of $40. Perform the appropriate test of hypothesis for the potential resident using The public relations officer for a particular city claims the average monthly cost for childcare outside the home for a single child is $700. A potential resident is interested in whether the claim is correct. She obtains a random sample of 64 records and computes the average monthly cost of this type of childcare to be $689 with a standard deviation of $40. Perform the appropriate test of hypothesis for the potential resident using   = 0.01. Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________ Find the p-value for the test above. p-value = ______________ What effect, if any, would there be on the conclusion in part (a) if you changed   to 0.05? The conclusion would ______________. Find the power of the test when   is actually $685 and   = 0.05. ______________ = 0.01. Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________ Find the p-value for the test above. p-value = ______________ What effect, if any, would there be on the conclusion in part (a) if you changed The public relations officer for a particular city claims the average monthly cost for childcare outside the home for a single child is $700. A potential resident is interested in whether the claim is correct. She obtains a random sample of 64 records and computes the average monthly cost of this type of childcare to be $689 with a standard deviation of $40. Perform the appropriate test of hypothesis for the potential resident using   = 0.01. Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________ Find the p-value for the test above. p-value = ______________ What effect, if any, would there be on the conclusion in part (a) if you changed   to 0.05? The conclusion would ______________. Find the power of the test when   is actually $685 and   = 0.05. ______________ to 0.05? The conclusion would ______________. Find the power of the test when The public relations officer for a particular city claims the average monthly cost for childcare outside the home for a single child is $700. A potential resident is interested in whether the claim is correct. She obtains a random sample of 64 records and computes the average monthly cost of this type of childcare to be $689 with a standard deviation of $40. Perform the appropriate test of hypothesis for the potential resident using   = 0.01. Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________ Find the p-value for the test above. p-value = ______________ What effect, if any, would there be on the conclusion in part (a) if you changed   to 0.05? The conclusion would ______________. Find the power of the test when   is actually $685 and   = 0.05. ______________ is actually $685 and The public relations officer for a particular city claims the average monthly cost for childcare outside the home for a single child is $700. A potential resident is interested in whether the claim is correct. She obtains a random sample of 64 records and computes the average monthly cost of this type of childcare to be $689 with a standard deviation of $40. Perform the appropriate test of hypothesis for the potential resident using   = 0.01. Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ Interpretation: __________________________________________ Find the p-value for the test above. p-value = ______________ What effect, if any, would there be on the conclusion in part (a) if you changed   to 0.05? The conclusion would ______________. Find the power of the test when   is actually $685 and   = 0.05. ______________ = 0.05. ______________

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When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. If the value of the test statistic is 2.05, then the p-value is:

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When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population means, but your statistical software provides only a one-tail area of 0.156 as part of its output. The p-value for this test will be 0.078.

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If you wish to construct a confidence interval estimate for the difference between two population means, an increase in the sample sizes used will result in:

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A sample of size 100 selected from one population has 60 successes, and a sample of size 150 selected from a second population has 95 successes. The test statistic for testing the equality of the population proportions equal to:

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In testing In testing   vs.   a random sample of size 100 produced a sample proportion   Given these results, the test statistic value is z = -.655. vs. In testing   vs.   a random sample of size 100 produced a sample proportion   Given these results, the test statistic value is z = -.655. a random sample of size 100 produced a sample proportion In testing   vs.   a random sample of size 100 produced a sample proportion   Given these results, the test statistic value is z = -.655. Given these results, the test statistic value is z = -.655.

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A proposition tentatively advanced as possibly true is called:

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A large university claims that the average cost of housing within three miles of the campus is $6900 per school year. A high school student is preparing her budget for her freshman year at the university. She is concerned that the university's estimate is too low. Having taken AP Statistics, she decides to perform the following test of hypothesis: H0: A large university claims that the average cost of housing within three miles of the campus is $6900 per school year. A high school student is preparing her budget for her freshman year at the university. She is concerned that the university's estimate is too low. Having taken AP Statistics, she decides to perform the following test of hypothesis: H<sub>0</sub>:   = 6900 versus H<sub>a</sub>:   > 6900, where   represents the average cost of housing per year within three miles of the university. Describe the Type I error for this problem. ________________________________________________________ Describe the Type II error for this problem. ________________________________________________________ Which error has more serious consequences for the student? ________________________________________________________ = 6900 versus Ha: A large university claims that the average cost of housing within three miles of the campus is $6900 per school year. A high school student is preparing her budget for her freshman year at the university. She is concerned that the university's estimate is too low. Having taken AP Statistics, she decides to perform the following test of hypothesis: H<sub>0</sub>:   = 6900 versus H<sub>a</sub>:   > 6900, where   represents the average cost of housing per year within three miles of the university. Describe the Type I error for this problem. ________________________________________________________ Describe the Type II error for this problem. ________________________________________________________ Which error has more serious consequences for the student? ________________________________________________________ > 6900, where A large university claims that the average cost of housing within three miles of the campus is $6900 per school year. A high school student is preparing her budget for her freshman year at the university. She is concerned that the university's estimate is too low. Having taken AP Statistics, she decides to perform the following test of hypothesis: H<sub>0</sub>:   = 6900 versus H<sub>a</sub>:   > 6900, where   represents the average cost of housing per year within three miles of the university. Describe the Type I error for this problem. ________________________________________________________ Describe the Type II error for this problem. ________________________________________________________ Which error has more serious consequences for the student? ________________________________________________________ represents the average cost of housing per year within three miles of the university. Describe the Type I error for this problem. ________________________________________________________ Describe the Type II error for this problem. ________________________________________________________ Which error has more serious consequences for the student? ________________________________________________________

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In testing the hypotheses H0: p1 - p2 = 0 vs. Ha: p1 - p2 > 0, use the following statistics, where x1 and x2 represent the number of defective components found in medical instruments in the two samples. n1 = 200, x1 = 80 n2 = 400, x2 = 140 What conclusion can we draw at the 5% significance level? Test statistic = ______________ Critical Value(s) = ______________ Conclusion: ______________ What is the p-value of the test? p-value = ______________ Explain how to use the p-value to test the hypotheses. ____________________________ Estimate with 95% confidence the difference between the two population proportions. ______________

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In hypothesis testing, the statement of the null hypothesis always contain the equality sign.

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For testing the difference between two population proportions, the pooled proportion estimate should be used to compute the value of the test statistic when the:

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In testing the difference between two population means using two independent samples, we use the pooled variance in estimating the standard error of the sampling distribution of the sample mean difference In testing the difference between two population means using two independent samples, we use the pooled variance in estimating the standard error of the sampling distribution of the sample mean difference   if the populations are normal with equal variances. if the populations are normal with equal variances.

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Hypothesis testing is a systematic approach to assessing tentative beliefs about reality, which involves confronting those beliefs with evidence and deciding, in light of this evidence, whether the beliefs can be maintained as reasonable or must be discarded as untenable.

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A marketing manager wants to test the hypothesis that 90% of tennis magazine's subscribers live in their own homes. Accordingly, a simple random sample of 80 is taken from the magazine's list of subscribers. The sample turns out to contain 64 homeowners. Use a significance level of A marketing manager wants to test the hypothesis that 90% of tennis magazine's subscribers live in their own homes. Accordingly, a simple random sample of 80 is taken from the magazine's list of subscribers. The sample turns out to contain 64 homeowners. Use a significance level of   = .05. Test statistic = ______________ p-value = ______________ Conclusion: ______________ Interpretation: __________________________________________ = .05. Test statistic = ______________ p-value = ______________ Conclusion: ______________ Interpretation: __________________________________________

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