Deck 14: Entropy and Gibbs Energy
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Deck 14: Entropy and Gibbs Energy
1
The following substances are ordered with increasing entropy: neon gas < liquid water < a gold bar.
False
2
The entropy change for the following reaction will be negative:
C11H22O11 (s) + 12 O2 (g) → 12 CO2 (g) + 11 H2O (l)
C11H22O11 (s) + 12 O2 (g) → 12 CO2 (g) + 11 H2O (l)
False
3
The entropy change for the following reaction will be positive:
N2 (g) + 3 H2 (g) → 2 NH3 (g)
N2 (g) + 3 H2 (g) → 2 NH3 (g)
False
4
Entropy is identified with the amount of ________ in the system.
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5
Calculate the entropy change (
, J K-1 mol-1) when 1.00 mol of ethanol at its boiling point (Tb =78.45 °C) vaporizes (in the process the temperature does not change,
for ethanol is + 43.5 kJ mol-1).
A) + 124.
B) - 124.
C) + 554.
D) + 0.12.


A) + 124.
B) - 124.
C) + 554.
D) + 0.12.
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6
Calculate the entropy change (
, J K-1 mol-1) when 1.00 mol of mercury at its boiling point (Tb = 356.55 °C) vaporizes (in the process the temperature does not change,
for mercury is + 59.3 kJ mol-1).
A) - 94.
B) + 94.
C) + 166.
D) + 0.09.


A) - 94.
B) + 94.
C) + 166.
D) + 0.09.
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7
Calculate the entropy change (
, J K-1 mol-1) when 1.00 mol of methane at its melting point (Tm = - 182.05 °C) freezes (in the process the temperature does not change and
for methane is + 0.94 kJ mol-1).
A) - 10.3.
B) - 0.01.
C) + 10.3.
D) - 5.2.


A) - 10.3.
B) - 0.01.
C) + 10.3.
D) - 5.2.
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8
For water
= + 109 J K-1 mol-1 whilst
= + 22 J K-1 mol-1. The entropy change for vaporization is larger than the entropy change for fusion because it is measured at a higher temperature.


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9
Whether the total entropy change (ΔS(total)) of a process is positive, negative, or equal to zero defines whether the process is spontaneous. Match the (ΔS(total)) condition with its description.
-ΔS(total) > 0
A) spontaneous process
B) non-spontaneous process
C) process at equilibrium
-ΔS(total) > 0
A) spontaneous process
B) non-spontaneous process
C) process at equilibrium
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10
Whether the total entropy change (ΔS(total)) of a process is positive, negative, or equal to zero defines whether the process is spontaneous. Match the (ΔS(total)) condition with its description.
-ΔS(total) < 0
A) spontaneous process
B) non-spontaneous process
C) process at equilibrium
-ΔS(total) < 0
A) spontaneous process
B) non-spontaneous process
C) process at equilibrium
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11
Whether the total entropy change (ΔS(total)) of a process is positive, negative, or equal to zero defines whether the process is spontaneous. Match the (ΔS(total)) condition with its description.
-ΔS(total) = 0
A) spontaneous process
B) non-spontaneous process
C) process at equilibrium
-ΔS(total) = 0
A) spontaneous process
B) non-spontaneous process
C) process at equilibrium
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12
Calculate the change of entropy (in J K-1 mol-1) when 1 mol of methanol is heated at constant pressure from 5 °C to 35 °C, the molar heat capacity, Cp, of methanol is 81.6 J K-1 mol-1, assume that the molar heat capacity, Cp is constant over this temperature range.
A) + 8.36.
B) - 8.36.
C) - 158.79.
D) + 158.79.
A) + 8.36.
B) - 8.36.
C) - 158.79.
D) + 158.79.
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13
Calculate the change of entropy (in J K-1 mol-1) when 1 mol of ethanol is cooled at constant pressure from 25 °C to 10 °C, the molar heat capacity, Cp, of ethanol is 111.5 J K-1 mol-1 and assume that Cp is constant over this temperature range.
A) + 5.8.
B) - 5.8.
C) - 102.2.
D) + 102.2.
A) + 5.8.
B) - 5.8.
C) - 102.2.
D) + 102.2.
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14
When 1 mol of trichloromethane is heated from 5 °C to 20 °C at constant pressure, the change of entropy is + 6.00 J K-1 mol-1. When the solvent is heated further from 20 °C to 35 °C, the change in entropy will also be + 6.00 J K-1 mol-1.
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15
When 1 mol of water is heated from 10 °C to 25 °C at constant pressure, the change in entropy is + 3.89 J K-1 mol-1. When 1 mol of methanol is heated from 10 °C to 25 °C at constant pressure, the change in entropy will be smaller.
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16
At zero kelvin the entropy of a perfect crystal is ____.
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17
Calculate the standard entropy
of 1 mol of water at 20 °C and 1 bar. The molar heat capacity, Cp, of water is 75.3 J K-1 mol-1 and
is 69.9 J K-1 mol-1.
A) 69.9.
B) - 133.5.
C) 68.7.
D) 71.1.


A) 69.9.
B) - 133.5.
C) 68.7.
D) 71.1.
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18
The standard entropy
of ethanol, at 1 bar, is 159.9 J K-1 mol-1. At 315 K, its standard entropy will be larger.

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19
The standard entropy change for the following reaction will be large and positive. CS2 (l) + 3O2 (g) → CO2 (g) + 2SO2 (g)
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20
Using data in Appendix 7, (p. 1350), calculate the standard entropy change of reaction
( in J K-1 mol-1) for the following reaction: CH4 (g) + 2 O2 (g) → CO2 (g) + 2 H2O (l)
A) + 243.0.
B) - 243.0.
C) - 107.8.
D) + 107.8.

A) + 243.0.
B) - 243.0.
C) - 107.8.
D) + 107.8.
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21
Using data in Appendix 7, (p. 1350), calculate the standard entropy change of reaction
(in J K-1 mol-1) for the following reaction:
NH3 (g) + HNO3 (l) → NH4NO3 (s)
A) - 197.
B) + 197.
C) -151.1.
D) +151.1.

NH3 (g) + HNO3 (l) → NH4NO3 (s)
A) - 197.
B) + 197.
C) -151.1.
D) +151.1.
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22
The standard entropy change,
for the following reaction is: -198.7 J K-1 mol-1.
N2 (g) + 3 H2 (g) → 2 NH3 (g) Calculate the standard entropy change of reaction
(in J K-1 mol-1) at 550 K.
A) - 226.
B) - 171.
C) + 226.
D) + 171.

N2 (g) + 3 H2 (g) → 2 NH3 (g) Calculate the standard entropy change of reaction

A) - 226.
B) - 171.
C) + 226.
D) + 171.
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23
The standard entropy change,
for the following reaction is: + 511.9 J K-1 mol-1.
C12H22O11 (s) + 12 O2 (g) → 12 CO2 (g) + 11 H2O (l) Calculate the standard entropy change of reaction
(in J K-1 mol-1) at 390 116.85 °C.
A) + 511.9.
B) + 48.3.
C) + 379.
D) + 645.

C12H22O11 (s) + 12 O2 (g) → 12 CO2 (g) + 11 H2O (l) Calculate the standard entropy change of reaction

A) + 511.9.
B) + 48.3.
C) + 379.
D) + 645.
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24
The standard entropy change,
is: - 198.7 J K-1 mol-1, for the following reaction: N2 (g) + 3 H2 (g) → 2 NH3 (g) This violates the Second Law of thermodynamics.

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25
Whether Gibbs energy change (ΔG) of a process is positive, negative, or equal to zero defines whether the process is spontaneous. Match the situation with its description.
-ΔG < 0
A) the reaction or process is spontaneous
B) the reaction or process is non-spontaneous
C) the reaction or process is at equilibrium
-ΔG < 0
A) the reaction or process is spontaneous
B) the reaction or process is non-spontaneous
C) the reaction or process is at equilibrium
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26
Whether Gibbs energy change (ΔG) of a process is positive, negative, or equal to zero defines whether the process is spontaneous. Match the situation with its description.
-ΔG > 0
A) the reaction or process is spontaneous
B) the reaction or process is non-spontaneous
C) the reaction or process is at equilibrium
-ΔG > 0
A) the reaction or process is spontaneous
B) the reaction or process is non-spontaneous
C) the reaction or process is at equilibrium
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27
Whether Gibbs energy change (ΔG) of a process is positive, negative, or equal to zero defines whether the process is spontaneous. Match the situation with its description.
-ΔG = 0
A) the reaction or process is spontaneous
B) the reaction or process is non-spontaneous
C) the reaction or process is at equilibrium
-ΔG = 0
A) the reaction or process is spontaneous
B) the reaction or process is non-spontaneous
C) the reaction or process is at equilibrium
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28
Match the reaction description and whether it is spontaneous and under which conditions
-ΔH > 0, ΔS < 0
A) Never spontaneous
B) Spontaneous on heating
C) Always spontaneous
D) Spontaneous on cooling
-ΔH > 0, ΔS < 0
A) Never spontaneous
B) Spontaneous on heating
C) Always spontaneous
D) Spontaneous on cooling
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29
Match the reaction description and whether it is spontaneous and under which conditions
-ΔH > 0, ΔS > 0
A) Never spontaneous
B) Spontaneous on heating
C) Always spontaneous
D) Spontaneous on cooling
-ΔH > 0, ΔS > 0
A) Never spontaneous
B) Spontaneous on heating
C) Always spontaneous
D) Spontaneous on cooling
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30
Match the reaction description and whether it is spontaneous and under which conditions
-ΔH < 0, ΔS > 0
A) Never spontaneous
B) Spontaneous on heating
C) Always spontaneous
D) Spontaneous on cooling
-ΔH < 0, ΔS > 0
A) Never spontaneous
B) Spontaneous on heating
C) Always spontaneous
D) Spontaneous on cooling
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31
Match the reaction description and whether it is spontaneous and under which conditions
-ΔH < 0, ΔS < 0
A) Never spontaneous
B) Spontaneous on heating
C) Always spontaneous
D) Spontaneous on cooling
-ΔH < 0, ΔS < 0
A) Never spontaneous
B) Spontaneous on heating
C) Always spontaneous
D) Spontaneous on cooling
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32
An endothermic reaction has
,
and
. Find the temperature, T(K), at which the reaction becomes spontaneous.
A) 298.
B) 783.
C) 0.78.
D) 1.28.



A) 298.
B) 783.
C) 0.78.
D) 1.28.
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33
Using
and
data given below:

Calculate the standard Gibbs energy change,
(kJ mol-1), for the following reaction:
2 NH3 (g) → N2 (g) + 3 H2 (g)
A) + 151.
B) - 151.
C) + 33.
D) - 59.



Calculate the standard Gibbs energy change,

2 NH3 (g) → N2 (g) + 3 H2 (g)
A) + 151.
B) - 151.
C) + 33.
D) - 59.
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34
Using
and
data given below:
Calculate the standard Gibbs energy change,
(kJ mol-1), for the following reaction:
CH4 (g) + 2 O2 (g) → CO2 (g) + 2 H2O (l)
A) - 818.
B) + 71.5.
C) + 963.
D) - 963.




CH4 (g) + 2 O2 (g) → CO2 (g) + 2 H2O (l)
A) - 818.
B) + 71.5.
C) + 963.
D) - 963.
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35
Using
data given below:

Calculate the standard Gibbs energy change,
(kJ mol-1), for the following reaction:
CO (g) + 2 H2 (g) → CH3OH (g)
A) - 299.2.
B) + 299.2.
C) + 24.8.
D) - 24.8.


Calculate the standard Gibbs energy change,

CO (g) + 2 H2 (g) → CH3OH (g)
A) - 299.2.
B) + 299.2.
C) + 24.8.
D) - 24.8.
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36
Using
data given below:
calculate the standard Gibbs energy change,
(kJ mol-1), for the following reaction:
CO2 (g) + CH4 (g) → CH3CO2H (l)
A) - 835.1
B) - 55.3.
C) + 835.1.
D) + 55.3.



CO2 (g) + CH4 (g) → CH3CO2H (l)
A) - 835.1
B) - 55.3.
C) + 835.1.
D) + 55.3.
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37
Using
data given below:

Calculate the standard Gibbs energy change,
(kJ mol-1), for the following reaction:
C12H22O11 (s) + 12 O2 (g) → 12 CO2 (g) + 11 H2O (l)
A) + 911.5.
B) - 5797.9.
C) + 5797.9.
D) - 911.5.


Calculate the standard Gibbs energy change,

C12H22O11 (s) + 12 O2 (g) → 12 CO2 (g) + 11 H2O (l)
A) + 911.5.
B) - 5797.9.
C) + 5797.9.
D) - 911.5.
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38
An endothermic reaction with a positive entropy change will become spontaneous on cooling.
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39
Using the data given below estimate the value of the Gibbs energy change of reaction (kJ mol-1) at 310 K, for the following reaction:
CH3CH2OH (l) + O2 (g) → CH3CO2H (l) + H2O (l)

A) - 450.2
B) - 451.8.
C) -41.7.
D) -533.8.
CH3CH2OH (l) + O2 (g) → CH3CO2H (l) + H2O (l)

A) - 450.2
B) - 451.8.
C) -41.7.
D) -533.8.
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40
Using the data given below estimate the value of the Gibbs energy change of reaction at 325 K, for the following reaction:
N2 (g) + 2 O2 (g) → 2 NO2 (g)

A) + 26.1.
B) + 105.9.
C) + 102.6.
D) + 40.
N2 (g) + 2 O2 (g) → 2 NO2 (g)

A) + 26.1.
B) + 105.9.
C) + 102.6.
D) + 40.
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