Exam 14: Entropy and Gibbs Energy

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The entropy change for the following reaction will be positive: N2 (g) + 3 H2 (g) → 2 NH3 (g)

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Whether the total entropy change (ΔS(total)) of a process is positive, negative, or equal to zero defines whether the process is spontaneous. Match the (ΔS(total)) condition with its description. -ΔS(total) = 0

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Match the reaction description and whether it is spontaneous and under which conditions -ΔH > 0, ΔS < 0

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A

Match the reaction description and whether it is spontaneous and under which conditions -ΔH < 0, ΔS > 0

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Calculate the entropy change ( △fusS∘\triangle_{fus} S^{∘} , J K-1 mol-1) when 1.00 mol of methane at its melting point (Tm = - 182.05 °C) freezes (in the process the temperature does not change and △fusH∘\triangle_{fus} H^{∘} for methane is + 0.94 kJ mol-1).

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The standard entropy S298∘S_{298}^{∘} of ethanol, at 1 bar, is 159.9 J K-1 mol-1. At 315 K, its standard entropy will be larger.

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Entropy is identified with the amount of ________ in the system.

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The standard entropy change for the following reaction will be large and positive. CS2 (l) + 3O2 (g) → CO2 (g) + 2SO2 (g)

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An endothermic reaction has DrH298∘=+389.5 kJ mol−1\mathrm{D}_{\mathrm{r}} \mathrm{H}_{298}^{\circ}=+389.5 \mathrm{~kJ} \mathrm{~mol}^{-1} , D1S298∘=+497.2JK−1mol−1D_{1} S_{298}^{\circ}=+497.2 \mathrm{JK}^{-1} \mathrm{mol}^{-1} and D1G298∘=+241.3 kJmol−1D_{1} G_{298}^{\circ}=+241.3 \mathrm{~kJ} m ol^{-1} . Find the temperature, T(K), at which the reaction becomes spontaneous.

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Whether the total entropy change (ΔS(total)) of a process is positive, negative, or equal to zero defines whether the process is spontaneous. Match the (ΔS(total)) condition with its description. -ΔS(total) > 0

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Using the data given below estimate the value of the Gibbs energy change of reaction at 325 K, for the following reaction: N2 (g) + 2 O2 (g) → 2 NO2 (g) () () () / 0 0 +33.2 / 191.6 205.1 240.1 / 29.1 29.4 37.2

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Whether the total entropy change (ΔS(total)) of a process is positive, negative, or equal to zero defines whether the process is spontaneous. Match the (ΔS(total)) condition with its description. -ΔS(total) < 0

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The standard entropy change, △TS298∘\triangle_{T} S_{298}^{∘} for the following reaction is: + 511.9 J K-1 mol-1. C12H22O11 (s) + 12 O2 (g) → 12 CO2 (g) + 11 H2O (l) Calculate the standard entropy change of reaction △TS∘\triangle_{T} S ^{∘} (in J K-1 mol-1) at 390 116.85 °C.

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Using ΔfG298∘\Delta _{f}G_{298}^{\circ} data given below: () () () () / -1543 0 -394.4 -237.1 Calculate the standard Gibbs energy change, ΔTG298∘\Delta _{T}G_{298}^{\circ} (kJ mol-1), for the following reaction: C12H22O11 (s) + 12 O2 (g) → 12 CO2 (g) + 11 H2O (l)

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Using ΔfG298∘\Delta_{f} G_{298}^{\circ} data given below: () () () / -137.2 0 -162.0 Calculate the standard Gibbs energy change, ΔfG298∘\Delta_{f} G_{298}^{\circ} (kJ mol-1), for the following reaction: CO (g) + 2 H2 (g) → CH3OH (g)

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Calculate the standard entropy ST∘S_{\mathrm{T}}^{∘} of 1 mol of water at 20 °C and 1 bar. The molar heat capacity, Cp, of water is 75.3 J K-1 mol-1 and S298∘S_{298}^{∘} is 69.9 J K-1 mol-1.

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Calculate the entropy change ( △vapS∘\triangle_{vap} S^{∘} , J K-1 mol-1) when 1.00 mol of ethanol at its boiling point (Tb =78.45 °C) vaporizes (in the process the temperature does not change, △vapH∘\triangle_{vap} H^{∘} for ethanol is + 43.5 kJ mol-1).

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Whether Gibbs energy change (ΔG) of a process is positive, negative, or equal to zero defines whether the process is spontaneous. Match the situation with its description. -ΔG < 0

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Using data in Appendix 7, (p. 1350), calculate the standard entropy change of reaction △TS298∘\triangle_{T} S_{298}^{∘} (in J K-1 mol-1) for the following reaction: NH3 (g) + HNO3 (l) → NH4NO3 (s)

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For water △vapS∘\triangle_{vap} S^{∘} = + 109 J K-1 mol-1 whilst △fusS∘\triangle_{fus} S^{∘} = + 22 J K-1 mol-1. The entropy change for vaporization is larger than the entropy change for fusion because it is measured at a higher temperature.

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