Deck 7: The Normal Probability Distributions
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Deck 7: The Normal Probability Distributions
1
High temperatures in a certain city for the month of August follow a uniform distribution over the interval
to
What is the probability that a randomly selected August day has a high temperature that exceeded 
A) 0.1562
B) 0.4295
C) 0.0313
D) 0.8438



A) 0.1562
B) 0.4295
C) 0.0313
D) 0.8438
0.8438
2
Compare a graph of the normal density function with mean of 0 and standard deviation of 1 with a graph of a normal density function with mean equal to 4 and standard deviation of 1. The graphs would
A) Have the same height but one would be shifted 4 units to the right.
B) Have no horizontal displacement but one would be flatter than the other.
C) Have no horizontal displacement but one would be steeper that the other.
D) Have the same height but one would be shifter 4 units to the left.
A) Have the same height but one would be shifted 4 units to the right.
B) Have no horizontal displacement but one would be flatter than the other.
C) Have no horizontal displacement but one would be steeper that the other.
D) Have the same height but one would be shifter 4 units to the left.
Have the same height but one would be shifted 4 units to the right.
3
Compare a graph of the normal density function with mean of 0 and standard deviation of 1 with a graph of a normal density function with mean equal to 0 and standard deviation of 0.5. The graphs would
A) Have the same height but one would be shifted 4 units to the right.
B) Have no horizontal displacement but one would be flatter than the other.
C) Have no horizontal displacement but one would be steeper that the other.
D) Have the same height but one would be shifter 4 units to the left.
A) Have the same height but one would be shifted 4 units to the right.
B) Have no horizontal displacement but one would be flatter than the other.
C) Have no horizontal displacement but one would be steeper that the other.
D) Have the same height but one would be shifter 4 units to the left.
Have no horizontal displacement but one would be steeper that the other.
4
Draw a normal curve with ? = 60 and ? = 10. Label the mean and the inflection points.
A)
B)
C)
D)
A)

B)

C)

D)

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5
You are performing a study about the weight of preschoolers. A previous study found the weights to be normally distributed with a mean of 30 and a standard deviation of 4. You randomly sample 30 preschool children and find their weights to be as follows.
a) Draw a histogram to display the data. Is it reasonable to assume that the weights are normallydistributed? Why?
b) Find the mean and standard deviation of your sample.
c) Is there a high probability that the mean and standard deviation of your sample are consistentwith those found in previous studies? Explain your reasoning.

b) Find the mean and standard deviation of your sample.
c) Is there a high probability that the mean and standard deviation of your sample are consistentwith those found in previous studies? Explain your reasoning.
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6
The graph of a normal curve is given. Use the graph to identify the value of ? and ?. 
A) ? = 12, ? = 9
B) ? = 3, ? = 12
C) ? = 12, ? = 3
D) ? = 9, ? = 12

A) ? = 12, ? = 9
B) ? = 3, ? = 12
C) ? = 12, ? = 3
D) ? = 9, ? = 12
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7
Determine whether the graph can represent a normal curve. If it cannot, explain why.
-
A) The graph cannot represent a normal density function because it increases as x becomes very large or very small.
B) The graph can represent a normal density function.
C) The graph cannot represent a normal density function because it takes negative values for some values of x.
D) The graph cannot represent a normal density function because the area under the graph is greater than 1.
-

A) The graph cannot represent a normal density function because it increases as x becomes very large or very small.
B) The graph can represent a normal density function.
C) The graph cannot represent a normal density function because it takes negative values for some values of x.
D) The graph cannot represent a normal density function because the area under the graph is greater than 1.
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8
Determine whether the graph can represent a normal curve. If it cannot, explain why.
-
A) The graph cannot represent a normal density function because the area under the graph is greater than 1.
B) The graph cannot represent a normal density function because as x increases without bound, the graph takes negative values.
C) The graph cannot represent a normal density function because it has no inflection points.
D) The graph can represent a normal density function.
-

A) The graph cannot represent a normal density function because the area under the graph is greater than 1.
B) The graph cannot represent a normal density function because as x increases without bound, the graph takes negative values.
C) The graph cannot represent a normal density function because it has no inflection points.
D) The graph can represent a normal density function.
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9
Determine whether the graph can represent a normal curve. If it cannot, explain why.
-
A) The graph cannot represent a normal density function because it is not bell shaped.
B) The graph cannot represent a normal density function because it does not approach the horizontal axis as x increases or decreases without bound.
C) The graph cannot represent a normal density function because it has no inflection points.
D) The graph can represent a normal density function.
-

A) The graph cannot represent a normal density function because it is not bell shaped.
B) The graph cannot represent a normal density function because it does not approach the horizontal axis as x increases or decreases without bound.
C) The graph cannot represent a normal density function because it has no inflection points.
D) The graph can represent a normal density function.
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10
Determine whether the graph can represent a normal curve. If it cannot, explain why.
-
A) The graph cannot represent a normal density function because a normal density curve should approach but not reach the horizontal axis as x increases and decreases without bound.
B) The graph cannot represent a normal density function because it is bimodal.
C) The graph can represent a normal density function.
D) A and B are both true.
-

A) The graph cannot represent a normal density function because a normal density curve should approach but not reach the horizontal axis as x increases and decreases without bound.
B) The graph cannot represent a normal density function because it is bimodal.
C) The graph can represent a normal density function.
D) A and B are both true.
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11
The analytic scores on a standardized aptitude test are known to be normally distributed with mean
and standard deviation
(a) Draw a normal curve with the parameters labeled.
(b) Shade the region that represents the proportion of test takers who scored less than 725.
(c) Suppose the area under the normal curve to the left of X = 725 is 0.8413. Provide two interpretations of this result.


(b) Shade the region that represents the proportion of test takers who scored less than 725.
(c) Suppose the area under the normal curve to the left of X = 725 is 0.8413. Provide two interpretations of this result.
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12
Find the sum of the areas under the standard normal curve to the left of z = -1.25 and to the right of 
A) 0.3944
B) 0.1056
C) 0.7888
D) 0.2112

A) 0.3944
B) 0.1056
C) 0.7888
D) 0.2112
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13
Determine the area under the standard normal curve that lies between:
-z = 1 and z = 2
A) 0.1359
B) 0.8641
C) 0.000 8
D) 0.000 6
-z = 1 and z = 2
A) 0.1359
B) 0.8641
C) 0.000 8
D) 0.000 6
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14
Determine the area under the standard normal curve that lies between:
-z = 0.3 and z = 1.4
A) 0.3821
B) 0.6179
C) 0.9192
D) 0.3013
-z = 0.3 and z = 1.4
A) 0.3821
B) 0.6179
C) 0.9192
D) 0.3013
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15
Determine the area under the standard normal curve that lies between:
-z = -0.4 and z = 0.4
A) 0.5
B) 0.6554
C) 0.3446
D) 0.3108
-z = -0.4 and z = 0.4
A) 0.5
B) 0.6554
C) 0.3446
D) 0.3108
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16
Determine the area under the standard normal curve that lies between:
-z = -2 and z = -0.7
A) 0.242
B) 0.2192
C) 0.758
D) 0.0228
-z = -2 and z = -0.7
A) 0.242
B) 0.2192
C) 0.758
D) 0.0228
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17
Find the indicated probability.
-Assume that the random variable X is normally distributed, with mean
and standard deviation
Compute the probability P(X < 70).
A) 0.8944
B) 0.9015
C) 0.8849
D) 0.1056
-Assume that the random variable X is normally distributed, with mean


A) 0.8944
B) 0.9015
C) 0.8849
D) 0.1056
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18
Find the indicated probability.
-Assume that the random variable X is normally distributed, with mean
and standard deviation
Compute the probability P(X > 114).
A) 0.1977
B) 0.2420
C) 0.2119
D) 0.7881
-Assume that the random variable X is normally distributed, with mean


A) 0.1977
B) 0.2420
C) 0.2119
D) 0.7881
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19
Find the indicated probability.
-Assume that the random variable X is normally distributed, with mean
and standard deviation
Compute the probability P( 38 < X < 70).
A) 0.8944
B) 0.8914
C) 0.8819
D) 0.7888
-Assume that the random variable X is normally distributed, with mean


A) 0.8944
B) 0.8914
C) 0.8819
D) 0.7888
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20
The amount of soda a dispensing machine pours into a 12 ounce can of soda follows a normal distribution with a mean of 12.36 ounces and a standard deviation of 0.24 ounce. The cans only hold 12.60 ounces of soda. Every can that has more than 12.60 ounces of soda poured into it causes a spill and the can needs to go through a special cleaning process before it can be sold. What is the probability a randomly selected can will need to go through this process?
A) 0.1587
B) 0.8413
C) 0.6587
D) 0.3413
A) 0.1587
B) 0.8413
C) 0.6587
D) 0.3413
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21
Find the indicated z-score.
-Find the z-score for which the area under the standard normal curve to its left is 0.96
A) -1.38
B) 1.82
C) 1.75
D) 1.03
-Find the z-score for which the area under the standard normal curve to its left is 0.96
A) -1.38
B) 1.82
C) 1.75
D) 1.03
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22
Find the indicated z-score.
-Find the z-score for which the area under the standard normal curve to its left is 0.40
A) 0.57
B) -0.25
C) -0.57
D) 0.25
-Find the z-score for which the area under the standard normal curve to its left is 0.40
A) 0.57
B) -0.25
C) -0.57
D) 0.25
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23
Find the indicated z-score.
-Find the z-score for which the area under the standard normal curve to its left is 0.09.
A) -1.45
B) -1.39
C) -1.34
D) -1.26
-Find the z-score for which the area under the standard normal curve to its left is 0.09.
A) -1.45
B) -1.39
C) -1.34
D) -1.26
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24
Find the indicated z-score.
-Find the z-score for which the area under the standard normal curve to its left is 0.04.
A) -1.48
B) -1.89
C) -1.63
D) -1.75
-Find the z-score for which the area under the standard normal curve to its left is 0.04.
A) -1.48
B) -1.89
C) -1.63
D) -1.75
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25
Find the indicated z-score.
-Find the z-score for which the area under the standard normal curve to its left is 0.70.
A) 0.81
B) 0.53
C) 0.98
D) 0.47
-Find the z-score for which the area under the standard normal curve to its left is 0.70.
A) 0.81
B) 0.53
C) 0.98
D) 0.47
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26
Find the indicated z-score.
-Find the z-score for which the area under the standard normal curve to its right is 0.70.
A) -0.53
B) -0.81
C) -0.47
D) -0.98
-Find the z-score for which the area under the standard normal curve to its right is 0.70.
A) -0.53
B) -0.81
C) -0.47
D) -0.98
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27
Find the indicated z-score.
-Find the z-score having area 0.86 to its right under the standard normal curve; that is, find
.
A) 0.5557
B) 1.08
C) -1.08
D) 0.8051
-Find the z-score having area 0.86 to its right under the standard normal curve; that is, find

A) 0.5557
B) 1.08
C) -1.08
D) 0.8051
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28
Find the indicated z-score.
-Determine the two z-scores that separate the middle 87.4% of the distribution from the area in the tails of the standard normal distribution.
A) -1.53, 1.53
B) -1.45, 1.45
C) -1.39, 1.39
D) -1.46, 1.46
-Determine the two z-scores that separate the middle 87.4% of the distribution from the area in the tails of the standard normal distribution.
A) -1.53, 1.53
B) -1.45, 1.45
C) -1.39, 1.39
D) -1.46, 1.46
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29
Find the indicated z-score.
-Determine the two z-scores that separate the middle 96% of the distribution from the area in the tails of the standard normal distribution.
A) -1.75 and 1.75
B) 0 and 2.05
C) -2.05 and 2.05
D) -2.33 and 2.33
-Determine the two z-scores that separate the middle 96% of the distribution from the area in the tails of the standard normal distribution.
A) -1.75 and 1.75
B) 0 and 2.05
C) -2.05 and 2.05
D) -2.33 and 2.33
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30
Find the indicated z-score.
-Find the z-scores for which 90% of the distribution's area lies between -z and z.
A) (-0.99, 0.99)
B) (-1.645, 1.645)
C) (-2.33, 2.33)
D) (-1.96, 1.96)
-Find the z-scores for which 90% of the distribution's area lies between -z and z.
A) (-0.99, 0.99)
B) (-1.645, 1.645)
C) (-2.33, 2.33)
D) (-1.96, 1.96)
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31
Find the indicated z-score.
-Find the z-scores for which 98% of the distribution's area lies between -z and z.
A) (-2.33, 2.33)
B) (-1.645, 1.645)
C) (-0.99, 0.99)
D) (-1.96, 1.96)
-Find the z-scores for which 98% of the distribution's area lies between -z and z.
A) (-2.33, 2.33)
B) (-1.645, 1.645)
C) (-0.99, 0.99)
D) (-1.96, 1.96)
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32
Find the value of. 
-
A) 1.13
B) 0.55
C) 1.08
D) -1.13

-

A) 1.13
B) 0.55
C) 1.08
D) -1.13
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33
Find the indicated percentile.
-Assume that the random variable X is normally distributed with mean
and standard deviation
Find the 55th percentile for X.
A) 48.96
B) 51.04
C) 55.68
D) 52.8
-Assume that the random variable X is normally distributed with mean


A) 48.96
B) 51.04
C) 55.68
D) 52.8
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34
The amount of soda a dispensing machine pours into a 12 ounce can of soda follows a normal distribution with a standard deviation of 0.06 ounce. Every can that has more than 12.15 ounces of soda poured into it causes a spill and the can needs to go through a special cleaning process before it can be sold. What is the mean amount of soda the machine should dispense if the company wants to limit the percentage that need to be cleaned because of spillage to 3%?
A) 12.0198 oz
B) 12.2628 oz
C) 12.2802 oz
D) 12.0372 oz
A) 12.0198 oz
B) 12.2628 oz
C) 12.2802 oz
D) 12.0372 oz
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35
A brewery has a beer dispensing machine that dispenses beer into the company's 12 ounce bottles. The distribution for the amount of beer dispensed by the machine follows a normal distribution with a standard deviation of 0.14 ounce. The company can control the mean amount of beer dispensed by the machine. What value of the mean should the company use if it wants to guarantee that 98.5% of the bottles contain at least 12 ounces (the amount on the label)? Round to the nearest thousandth.
A) 12.304 oz
B) 12.002 oz
C) 12.340 oz
D) 12.001 oz
A) 12.304 oz
B) 12.002 oz
C) 12.340 oz
D) 12.001 oz
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36
Use a normal probability plot to asses whether the sample data could have come from a population that is normally distributed.
-An industrial psychologist conducted an experiment in which 40 employees that were identified as "chronically tardy" by their managers were divided into two groups of size 20. Group 1 participated in the new "It's Great to be Awake!" program, while Group 2 had their pay pay docked. The following data represent the number of minutes that employees in Group 1 were late for work after participating in the program.
A) not normally distributed
B) normally distributed
-An industrial psychologist conducted an experiment in which 40 employees that were identified as "chronically tardy" by their managers were divided into two groups of size 20. Group 1 participated in the new "It's Great to be Awake!" program, while Group 2 had their pay pay docked. The following data represent the number of minutes that employees in Group 1 were late for work after participating in the program.

A) not normally distributed
B) normally distributed
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