Deck 8: Carbohydrates
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Deck 8: Carbohydrates
1
Which is true about naturally occurring monosaccharides?
A)The L-isomers predominate.
B)The D-isomers predominate.
C)The L and D-isomers occur in equal ratios.
D)The ratio of L and D-isomers varies widely depending on the source.
A)The L-isomers predominate.
B)The D-isomers predominate.
C)The L and D-isomers occur in equal ratios.
D)The ratio of L and D-isomers varies widely depending on the source.
The D-isomers predominate.
2
Which does not apply to dihydroxyacetone?
A)Ketose.
B)Triose.
C)Chiral.
D)Water-soluble.
A)Ketose.
B)Triose.
C)Chiral.
D)Water-soluble.
Chiral.
3
A saccharide is a ________.
A)lipid
B)carbohydrate
C)nucleic acid
D)protein
A)lipid
B)carbohydrate
C)nucleic acid
D)protein
carbohydrate
4
Which is not a glycoconjugate?
A)Proteoglycan.
B)Glycolipid.
C)Glycoprotein.
D)Homoglycan.
A)Proteoglycan.
B)Glycolipid.
C)Glycoprotein.
D)Homoglycan.
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5
The functional group shown is a(n)________. 
A)hemiacetal
B)hemiketal
C)acetal
D)ketal

A)hemiacetal
B)hemiketal
C)acetal
D)ketal
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6
Which structure is NOT a carbohydrate?
A)
B)
C)
D)
A)

B)

C)

D)

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7
The structure of D-arabinose is shown below.How many stereoisomers are possible for this molecule (including the one shown)? 
A)One
B)Four
C)Six
D)Eight

A)One
B)Four
C)Six
D)Eight
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8
Examine the cyclic D-monosaccharide shown below.The ring structure is the ________ and the linear form of this monosaccharide must be a(n)________. 
A)α anomer;ketose
B)β anomer;ketose
C)α anomer;aldose
D)β anomer;aldose

A)α anomer;ketose
B)β anomer;ketose
C)α anomer;aldose
D)β anomer;aldose
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9
Which is a general term indicating a carbohydrate polymer?
A)Glycan.
B)Polycarb.
C)Multimer.
D)Oligosaccharide.
A)Glycan.
B)Polycarb.
C)Multimer.
D)Oligosaccharide.
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10
Anomers can be interconverted ________.
A)by rotation about carbon-carbon bonds
B)via a linear intermediate
C)by an isotopic exchange reaction
D)None of the above.Anomers cannot be interconverted.
A)by rotation about carbon-carbon bonds
B)via a linear intermediate
C)by an isotopic exchange reaction
D)None of the above.Anomers cannot be interconverted.
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11
The intramolecular cyclization reaction of glucose in solution ________.
A)generates a chiral center
B)yields a hemiacetal
C)usually forms a pyranose
D)All of the above
A)generates a chiral center
B)yields a hemiacetal
C)usually forms a pyranose
D)All of the above
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12
Below is the structure for a cyclic D-monosaccharide.Which is the anomeric carbon atom? 
A)1
B)2
C)3
D)4
E)5

A)1
B)2
C)3
D)4
E)5
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13
In solution α-D-glucopyranose and β-D-glucopyranose ________.
A)rapidly polymerize to form a heteropolymer
B)can never exist together
C)form a racemic mixture
D)form an equilibrium mixture
A)rapidly polymerize to form a heteropolymer
B)can never exist together
C)form a racemic mixture
D)form an equilibrium mixture
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14
The Fischer projections of linear D-glucose and D-galactose are shown below.These two molecules are ________. 
A)epimers
B)enantiomers
C)anomers
D)structural (constitutional)isomers

A)epimers
B)enantiomers
C)anomers
D)structural (constitutional)isomers
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15
Which is a product of the intramolecular cyclization of D-tagatose to form a furanose? 
A)I
B)II
C)III
D)IV

A)I
B)II
C)III
D)IV
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16
The compounds α-D-fructofuranose and β-D-fructofuranose are ________.
A)enantiomers
B)mutamers
C)anomers
D)conformational isomers
A)enantiomers
B)mutamers
C)anomers
D)conformational isomers
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17
The structures of D-ribose and D-arabinose are shown below.These two molecules are ________. 
A)epimers
B)enantiomers
C)tautomers
D)anomers

A)epimers
B)enantiomers
C)tautomers
D)anomers
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18
Below is the Fischer projection of D-galactose.Which is the proper Haworth projection of β-D-galactopyranose? 
A)I
B)II
C)III
D)IV

A)I
B)II
C)III
D)IV
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19
Examine the Fischer projection below.How is this carbohydrate classified? 
A)L enantiomer;aldopentose.
B)L enantiomer;ketopentose.
C)D enantiomer;aldohexose.
D)D enantiomer;ketopentose.

A)L enantiomer;aldopentose.
B)L enantiomer;ketopentose.
C)D enantiomer;aldohexose.
D)D enantiomer;ketopentose.
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20
A ribopyranose contains ________ carbon atoms while a ribofuranose has ________ carbon atoms.
A)6,5
B)6,6
C)5,6
D)5,5
A)6,5
B)6,6
C)5,6
D)5,5
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21
Which are possible conformations of a furanose molecule?
A)Envelope and twist.
B)Chair and boat.
C)Cis and trans.
D)A and B.
A)Envelope and twist.
B)Chair and boat.
C)Cis and trans.
D)A and B.
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22
If glucose supplies the anomeric carbon atom in a glycosidic link,the resulting compound is classified as a ________.
A)glycoside
B)glycan
C)glucoside
D)glucosamine
A)glycoside
B)glycan
C)glucoside
D)glucosamine
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23
Which statement is false about the sugar units in DNA?
A)They are cyclic in DNA.
B)It is a deoxy form of ribose.
C)It is an epimer of glucose.
D)It has a D-configuration.
A)They are cyclic in DNA.
B)It is a deoxy form of ribose.
C)It is an epimer of glucose.
D)It has a D-configuration.
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24
A reducing sugar is one that
A)contains a b(1→1)link.
B)has a hemiacetal group.
C)can reduce Cu2+ but not Ag+.
D)makes you lose weight.
A)contains a b(1→1)link.
B)has a hemiacetal group.
C)can reduce Cu2+ but not Ag+.
D)makes you lose weight.
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25
Ribitol is a
A)sugar phosphate.
B)deoxy sugar.
C)amino sugar.
D)sugar alcohol.
A)sugar phosphate.
B)deoxy sugar.
C)amino sugar.
D)sugar alcohol.
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26
Naturally occurring glycosides have roles in cells which include
A)building blocks of DNA.
B)chemical signals to plants.
C)food flavoring.
D)units in cell membrane structure.
E)All of the above.
A)building blocks of DNA.
B)chemical signals to plants.
C)food flavoring.
D)units in cell membrane structure.
E)All of the above.
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27
What is the name of the disaccharide shown below that is formed by joining two monomers of D-glucose? 
A)β-D-glucopyranosyl-(1→4)-β-D-glucopyranose.
B)α-D-glucopyranosyl-(1→4)-α-D-glucopyranose.
C)β-D-glucofuranosyl-(1→4)-β-D-glucofuranose.
D)α-D-glucopyranosyl-(1→3)-β-D-glucopyranose.

A)β-D-glucopyranosyl-(1→4)-β-D-glucopyranose.
B)α-D-glucopyranosyl-(1→4)-α-D-glucopyranose.
C)β-D-glucofuranosyl-(1→4)-β-D-glucofuranose.
D)α-D-glucopyranosyl-(1→3)-β-D-glucopyranose.
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28
Which classification(s)is(are)applicable to maltose? 
A)Nonreducing sugar.
B)Reducing sugar.
C)Peptidoglycan.
D)Glucoside.
E)Both B and D.

A)Nonreducing sugar.
B)Reducing sugar.
C)Peptidoglycan.
D)Glucoside.
E)Both B and D.
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29
The abbreviation for glucose is ________.
A)Glu
B)Gcs
C)Glc
D)Gluc
A)Glu
B)Gcs
C)Glc
D)Gluc
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30
A monosaccharide whose anomeric carbon atom has a glycosidic bond to an alcohol,amine or thiol is a ________.
A)glycoside
B)glycoprotein
C)heteroglycan
D)glucoconjugate
A)glycoside
B)glycoprotein
C)heteroglycan
D)glucoconjugate
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31
The chemical name for table sugar is ________ and it is a ________.
A)lactose;monosaccharide
B)lactose;disaccharide
C)sucrose;monosaccharide
D)sucrose;disaccharide
A)lactose;monosaccharide
B)lactose;disaccharide
C)sucrose;monosaccharide
D)sucrose;disaccharide
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32
Hydrolysis of maltose will yield ________.
A)glucose and galactose
B)fructose and glucose
C)glucose and mannose
D)glucose only
A)glucose and galactose
B)fructose and glucose
C)glucose and mannose
D)glucose only
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33
What type of bond links the monomers of a polysaccharide?
A)Glucotide bond.
B)Phosphate ester bond.
C)Peptide bond.
D)Glycosidic bond.
A)Glucotide bond.
B)Phosphate ester bond.
C)Peptide bond.
D)Glycosidic bond.
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34
Ribitol is a sugar alcohol that is a component of
A)vitamin C.
B)RNA.
C)FMN and FAD.
D)NAD and NADH.
E)sialic acid.
A)vitamin C.
B)RNA.
C)FMN and FAD.
D)NAD and NADH.
E)sialic acid.
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35
Monosaccharide derivatives in which an amino group replaces one of the hydroxyl groups may have important roles in
A)DNA structure.
B)intermediary metabolisms.
C)vitamin C.
D)sialic acids.
E)All of the above.
A)DNA structure.
B)intermediary metabolisms.
C)vitamin C.
D)sialic acids.
E)All of the above.
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36
The structure of a disaccharide is shown below.Which statement applies? 
A)Both rings A and B are in equilibrium with an open chain form.
B)Only ring A is in equilibrium with an open chain form.
C)Only ring B is in equilibrium with an open chain form.
D)Neither ring is in equilibrium with an open chain form.

A)Both rings A and B are in equilibrium with an open chain form.
B)Only ring A is in equilibrium with an open chain form.
C)Only ring B is in equilibrium with an open chain form.
D)Neither ring is in equilibrium with an open chain form.
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37
Who received a Nobel Prize in 1937 for his work on the structures of carbohydrates and the synthesis of Vitamin C?
A)Linus Pauling.
B)Walter Haworth.
C)Max Perutz.
D)Emil Fisher.
A)Linus Pauling.
B)Walter Haworth.
C)Max Perutz.
D)Emil Fisher.
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38
What distinguishes an aldonic acid from an alduronic acid?
A)The oxidation of the aldehyde group in an aldonic acid and the oxidation of the highest numbered carbon in the alduronic acid.
B)Aldonic acids are derivatives of aldoses,alduronic acids are derivatives of ketoses.
C)Aldonic acids are oxidized forms of linear monosaccharides;alduronic acids are oxidized forms of cyclic monosaccharides.
D)The two terms are synonyms and are used interchangeably.
A)The oxidation of the aldehyde group in an aldonic acid and the oxidation of the highest numbered carbon in the alduronic acid.
B)Aldonic acids are derivatives of aldoses,alduronic acids are derivatives of ketoses.
C)Aldonic acids are oxidized forms of linear monosaccharides;alduronic acids are oxidized forms of cyclic monosaccharides.
D)The two terms are synonyms and are used interchangeably.
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39
Pyranose rings are usually most stable when the ring adopts a ________ conformation with the bulkiest ring substituents in ________ positions.
A)chair;equatorial
B)chair;axial
C)boat;equatorial
D)boat;axial
A)chair;equatorial
B)chair;axial
C)boat;equatorial
D)boat;axial
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40
You have two bottles,each of which contains a white,crystalline substance.Your lab director tells you that one contains lactose and the other sucrose.Your job is to determine which bottle contains which sugar.Which procedure would you use?
A)Test both for solubility in water.Sucrose is very soluble;lactose is only minimally soluble.
B)Test for the ability to reduce Ag+.Only lactose will react.
C)Dissolve each in water and record the pH.Lactose is far more acidic than sucrose.
D)React each with bromine (Br₂)water.Only sucrose will react.
A)Test both for solubility in water.Sucrose is very soluble;lactose is only minimally soluble.
B)Test for the ability to reduce Ag+.Only lactose will react.
C)Dissolve each in water and record the pH.Lactose is far more acidic than sucrose.
D)React each with bromine (Br₂)water.Only sucrose will react.
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41
Enzymes in the human intestine which are needed to degrade plant starch into limit dextrin are
A)α-Amylase.
B)β-Amylase.
C)debranching enzymes.
D)A and B.
E)A,B,and C.
A)α-Amylase.
B)β-Amylase.
C)debranching enzymes.
D)A and B.
E)A,B,and C.
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42
Highly branched cores of amlyopectin that are resistant to hydrolysis are called ________.
A)core saccharides
B)non-reducing saccharides
C)dextran
D)limit dextrins
A)core saccharides
B)non-reducing saccharides
C)dextran
D)limit dextrins
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43
Which is a difference between maltose and cellobiose?
A)One is in cellulose and the other in starch.
B)One is linear and the other is branched.
C)The glycosidic bond is different.
D)The subunit sugars are not glucose for both.
E)All of the above.
A)One is in cellulose and the other in starch.
B)One is linear and the other is branched.
C)The glycosidic bond is different.
D)The subunit sugars are not glucose for both.
E)All of the above.
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44
The elasticity and resistance to compression of connective tissue is due to
A)the branching of the glycosaminoglycans there.
B)the glycosidic linkage to the serine of proteins in the glycosaminoglycans.
C)the carboxyl and sulfated groups in the glycosaminoglycans.
D)the rigid structure of the glycosaminoglycans.
E)All of the above.
A)the branching of the glycosaminoglycans there.
B)the glycosidic linkage to the serine of proteins in the glycosaminoglycans.
C)the carboxyl and sulfated groups in the glycosaminoglycans.
D)the rigid structure of the glycosaminoglycans.
E)All of the above.
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45
Which is not a similarity between glycogen and amylopectin?
A)They each contain about 6000 glucose residues.
B)Each has one reducing end and many nonreducing ends.
C)Each is highly branched.
D)Each has branches of similar chain length.
A)They each contain about 6000 glucose residues.
B)Each has one reducing end and many nonreducing ends.
C)Each is highly branched.
D)Each has branches of similar chain length.
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46
Humans can digest limit dextrin that is formed from dietary plant starch using
A)α-amylase.
B)β-amylase.
C)debranching enzyme.
D)A and B.
E)A,B,and C.
A)α-amylase.
B)β-amylase.
C)debranching enzyme.
D)A and B.
E)A,B,and C.
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47
The bacterial cell wall is sensitive to penicillin because it
A)blocks the linkage of the MurNAc and GlcNAc subunits.
B)blocks the pentaglycine bridge cross linkage.
C)binds to an enzyme which recognizes D-alanine-D-alanine dipeptide.
D)is not attacked by enzymes in animal cells.
E)All of the above.
A)blocks the linkage of the MurNAc and GlcNAc subunits.
B)blocks the pentaglycine bridge cross linkage.
C)binds to an enzyme which recognizes D-alanine-D-alanine dipeptide.
D)is not attacked by enzymes in animal cells.
E)All of the above.
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48
Amylase is a hydrolase that is an ________.
A)endonuclease
B)endoglycosidase
C)exonuclease
D)exoglycosidase that removes maltose
E)exoglycosidase that removes glucose monomers
A)endonuclease
B)endoglycosidase
C)exonuclease
D)exoglycosidase that removes maltose
E)exoglycosidase that removes glucose monomers
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49
Amylose differs from amylopectin in that amylose
A)has different monomers than amylopectin.
B)has more glucose residues than amylopectin.
C)is highly branched and amylopectin is not.
D)forms a helix and no branch points.
A)has different monomers than amylopectin.
B)has more glucose residues than amylopectin.
C)is highly branched and amylopectin is not.
D)forms a helix and no branch points.
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50
Polysaccharide structure can be varied by differences in
A)chain length (number of sugars in each polysaccharide).
B)the kind(s)of sugars in each polysaccharides.
C)the presence of branching.
D)All of the above.
A)chain length (number of sugars in each polysaccharide).
B)the kind(s)of sugars in each polysaccharides.
C)the presence of branching.
D)All of the above.
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51
Nodulation factors are ________.
A)polysaccharides that help maintain the integrity of tree bark
B)lipo-oligosaccharides that stimulate the growth of nitrogen-fixing structures in plants
C)polysaccharides used to store energy in the roots of plants
D)lipo-saccharides that are often found in tumors
A)polysaccharides that help maintain the integrity of tree bark
B)lipo-oligosaccharides that stimulate the growth of nitrogen-fixing structures in plants
C)polysaccharides used to store energy in the roots of plants
D)lipo-saccharides that are often found in tumors
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52
________ contain NeuNAc residues and sulfated sugars,and their negative charges contribute to the viscosity of mucins.
A)Proteoglycans
B)N-linked polysaccharides
C)O-linked polysaccharides
D)Hyaluronic acid
E)All of the above
A)Proteoglycans
B)N-linked polysaccharides
C)O-linked polysaccharides
D)Hyaluronic acid
E)All of the above
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53
Most of the carbohydrates on earth are produced by photosynthesis in plants.
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54
The main reasons that glycoproteins are so diverse when compared to other proteoglycans are
A)they may contain different sugars in different combinations and chain lengths.
B)β or α-glycosidic linkages may join various carbon atoms in the sugars.
C)they are found in both bacterial,plant and animal cells.
D)A and B.
E)All of the above.
A)they may contain different sugars in different combinations and chain lengths.
B)β or α-glycosidic linkages may join various carbon atoms in the sugars.
C)they are found in both bacterial,plant and animal cells.
D)A and B.
E)All of the above.
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55
Chitin is
A)found in insect and crustacean shells.
B)found in fungi cell walls.
C)composed of N-acetylglucosamine subunits.
D)composed of linear fibrils like cellulose.
E)All of the above.
A)found in insect and crustacean shells.
B)found in fungi cell walls.
C)composed of N-acetylglucosamine subunits.
D)composed of linear fibrils like cellulose.
E)All of the above.
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56
Termites and cows have bacteria in their digestive tracts that can obtain glucose from plant cellulose because they have enzymes that can attack
A)α-D-glucoside.
B)β-D-glucoside.
C)cellulose branch points.
D)hydrogen bonds in cellulose fibrils.
A)α-D-glucoside.
B)β-D-glucoside.
C)cellulose branch points.
D)hydrogen bonds in cellulose fibrils.
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57
When a sugar polymer is analyzed and found to have equal portions of reducing and non-reducing ends,it is likely that
A)it shows directionality.
B)it is linear.
C)it is branched.
D)it is branched,but not very highly.
E)some of the internal glycosidic bonds are in equilibrium with open chain forms.
A)it shows directionality.
B)it is linear.
C)it is branched.
D)it is branched,but not very highly.
E)some of the internal glycosidic bonds are in equilibrium with open chain forms.
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58
Both amylose and amylopectin molecules isolated from plant cells can contain as many as ________ glucose residues.
A)25
B)500
C)1000
D)2000
E)6000
A)25
B)500
C)1000
D)2000
E)6000
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59
The major proteoglycan in cartilage is ________.
A)hyaluronic acid
B)cellobiose
C)link protein
D)aggrecan
A)hyaluronic acid
B)cellobiose
C)link protein
D)aggrecan
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60
Cellulose is not highly branched because it
A)does not have a polysaccharide backbone.
B)does not have α(1→6)linkages.
C)does not have β(1→4)linkages.
D)is insoluble in water.
A)does not have a polysaccharide backbone.
B)does not have α(1→6)linkages.
C)does not have β(1→4)linkages.
D)is insoluble in water.
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61
The simplest aldose is the chiral molecule glyceraldehyde.
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62
Furanoses have more three-dimensional conformations than pyranoses.
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63
The chair conformation of furanoses is generally preferred to minimize steric repulsion.
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64
In solution only one anomeric form of a monosaccharide will be present.
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65
Steric strain is a major factor in determining the conformations of a monosaccharide that predominate in solution.
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66
Vitamin C is an enediol of a lactone and is vital in the synthesis of collagen.
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67
Homoglycans are used for storage,while heteroglycans are used for cell structure.
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68
Sugar alcohols do not have a carbonyl group.
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69
The ketohexoses have fewer chiral carbon atoms than the aldohexoses.
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70
All D-enantiomers of carbohydrates are dextrorotatory.
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71
DNA could be referred to as a glycoside.
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72
All carbohydrates have the empirical formula (CH₂O)n.
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73
For cattle,cellulose is a storage homoglycan.
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74
Enzymes that hydrolyze cellulose cannot hydrolyze amylopectin.
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75
Both nucleotides and nucleosides are glycosides.
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76
The main difference between structures of amylopectin and glycogen is the specific sugar subunit.
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77
The sugar derivative found in DNA is an oxidized form of ribose.
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78
The reaction between one molecule of alcohol and one molecule of aldehyde yields an acetal.
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79
α-amylases hydrolyze α(1→4)linkages and β-amylases hydrolyze β(1→4)linkages,but neither attack α1→6)linkages.
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80
Cellulose cannot be degraded in cattle.
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