Multiple Choice
Given the following rate law,what will happen to the rate if the concentration of MeI is doubled and the concentration of Me3N is halved? Rate = k[Me3N][MeI]
A) It will be doubled.
B) It will not change.
C) It will decrease in half.
D) It will increase very slightly.
Correct Answer:
Verified
Correct Answer:
Verified
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