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A Stationary Plutonium-239 Nucleus Decays into a Uranium-235 Nucleus Plus

Question 14

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A stationary plutonium-239 nucleus decays into a uranium-235 nucleus plus an alpha particle. The energy released in the process is 5.24 MeV. Given the following mass values A stationary plutonium-239 nucleus decays into a uranium-235 nucleus plus an alpha particle. The energy released in the process is 5.24 MeV. Given the following mass values He: 4.002603 u U: 235.043924 u What is the kinetic energy of the U nucleus? (1 u =931.494 MeV/c<sup>2</sup>) A) 0.0829 MeV B) 0.0837 MeV C) 0.0852 MeV D) 0.0863 MeV E) 0.0877 MeV He: 4.002603 u A stationary plutonium-239 nucleus decays into a uranium-235 nucleus plus an alpha particle. The energy released in the process is 5.24 MeV. Given the following mass values He: 4.002603 u U: 235.043924 u What is the kinetic energy of the U nucleus? (1 u =931.494 MeV/c<sup>2</sup>) A) 0.0829 MeV B) 0.0837 MeV C) 0.0852 MeV D) 0.0863 MeV E) 0.0877 MeV
U: 235.043924 u
What is the kinetic energy of the A stationary plutonium-239 nucleus decays into a uranium-235 nucleus plus an alpha particle. The energy released in the process is 5.24 MeV. Given the following mass values He: 4.002603 u U: 235.043924 u What is the kinetic energy of the U nucleus? (1 u =931.494 MeV/c<sup>2</sup>) A) 0.0829 MeV B) 0.0837 MeV C) 0.0852 MeV D) 0.0863 MeV E) 0.0877 MeV
U nucleus? (1 u =931.494 MeV/c2)


A) 0.0829 MeV
B) 0.0837 MeV
C) 0.0852 MeV
D) 0.0863 MeV
E) 0.0877 MeV

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