Short Answer
A 5.0-kg block is attached to an ideal massless spring whose spring constant is 125 N/m.The block is pulled from its equilibrium position at x = 0.00 m to a position at x = +0.687 m and is released from rest.The block then executes lightly damped oscillation along the x-axis,and the damping force is proportional to the velocity.When the block first returns to x = 0.00 m,its x component of velocity is -2.0 m/s and its x component of acceleration is +5.6 m/s2.
(a)What is the magnitude of the acceleration of the block upon release at x = +0.687 m.
(b)Find the damping constant b.
Correct Answer:

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(a)17.2 m/...View Answer
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