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Assuming the Radius of Diatomic Molecules Is Approximately for What

Question 22

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Assuming the radius of diatomic molecules is approximately Assuming the radius of diatomic molecules is approximately for what pressure will the mean free path in room-temperature (20°C) nitrogen be 4.6 m? The Boltzmann constant is 1.38 × 10<sup>-23</sup> J/K,Avogadro's number is 6.02 × 10<sup>23</sup> molecules/mole,and the ideal gas constant is = 0.0821 L ∙ atm/mol ∙ K. A) 4.9 × 10<sup>-8</sup><sub> atm</sub> B) 6.9 × 10<sup>-8</sup><sub> atm</sub> C) 1.5 × 10<sup>-7</sup><sub> atm</sub> D) 2.2 × 10<sup>-7</sup><sub> atm</sub> for what pressure will the mean free path in room-temperature (20°C) nitrogen be 4.6 m? The Boltzmann constant is 1.38 × 10-23 J/K,Avogadro's number is 6.02 × 1023 molecules/mole,and the ideal gas constant is Assuming the radius of diatomic molecules is approximately for what pressure will the mean free path in room-temperature (20°C) nitrogen be 4.6 m? The Boltzmann constant is 1.38 × 10<sup>-23</sup> J/K,Avogadro's number is 6.02 × 10<sup>23</sup> molecules/mole,and the ideal gas constant is = 0.0821 L ∙ atm/mol ∙ K. A) 4.9 × 10<sup>-8</sup><sub> atm</sub> B) 6.9 × 10<sup>-8</sup><sub> atm</sub> C) 1.5 × 10<sup>-7</sup><sub> atm</sub> D) 2.2 × 10<sup>-7</sup><sub> atm</sub> = 0.0821 L ∙ atm/mol ∙ K.


A) 4.9 × 10-8 atm
B) 6.9 × 10-8 atm
C) 1.5 × 10-7 atm
D) 2.2 × 10-7 atm

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