What Is Wrong with the Following Switch Statement

Multiple Choice

What is wrong with the following switch statement?
Int ans;
Cout <<"Type y for yes on n for no\n";
Cin >> ans;
Switch ans)
{
Case 'y':
Case 'Y': cout << "You said yes\n"; break;
Case 'n':
Case 'N': cout << "You said no\n"; break;
Default: cout <<"invalid answer\n";
}

A) ans is a int
B) break; is illegal syntax
C) nothing
D) there are no break statements on 2 cases.