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TABLE 12-14 A Perfume Manufacturer Is Trying to Choose Between 2 Magazine

Question 154

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TABLE 12-14
A perfume manufacturer is trying to choose between 2 magazine advertising layouts.An expensive layout would include a small package of the perfume.A cheaper layout would include a "scratch-and-sniff" sample of the product.The manufacturer would use the more expensive layout only if there is evidence that it would lead to a higher approval rate.The manufacturer presents the more expensive layout to 4 groups and determines the approval rating for each group.He presents the "scratch-and-sniff" layout to 5 groups and again determines the approval rating of the perfume for each group.The data are given below.Use this to test the appropriate hypotheses with the Wilcoxon Rank Sum Test with a level of significance of 0.05. TABLE 12-14 A perfume manufacturer is trying to choose between 2 magazine advertising layouts.An expensive layout would include a small package of the perfume.A cheaper layout would include a  scratch-and-sniff  sample of the product.The manufacturer would use the more expensive layout only if there is evidence that it would lead to a higher approval rate.The manufacturer presents the more expensive layout to 4 groups and determines the approval rating for each group.He presents the  scratch-and-sniff  layout to 5 groups and again determines the approval rating of the perfume for each group.The data are given below.Use this to test the appropriate hypotheses with the Wilcoxon Rank Sum Test with a level of significance of 0.05.   -Referring to Table 12-14,the hypotheses that should be used are A) H<sub>0</sub> : μ<sub>1</sub> = μ<sub>2</sub> versus H<sub>1</sub> : μ<sub>1 ≠ </sub>μ<sub>2</sub>. B) H<sub>0</sub> : μ<sub>1</sub> ≤ μ<sub>2</sub> versus H<sub>1</sub> : μ<sub>1 > </sub>μ<sub>2</sub>. C) H<sub>0</sub> : M<sub>1</sub> = M<sub>2</sub> versus H<sub>1</sub> : M<sub>1 ≠ </sub>M<sub>2</sub>. D) H<sub>0</sub> : M<sub>1</sub> ≤ M<sub>2</sub> versus H<sub>1</sub> : M<sub>1 > </sub>M<sub>2</sub>.
-Referring to Table 12-14,the hypotheses that should be used are


A) H0 : μ1 = μ2 versus H1 : μ1 ≠ μ2.
B) H0 : μ1 ≤ μ2 versus H1 : μ1 > μ2.
C) H0 : M1 = M2 versus H1 : M1 ≠ M2.
D) H0 : M1 ≤ M2 versus H1 : M1 > M2.

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